explain what happens to the heat energy that is absorbed during this time while the temperature does not change.

Answers

Answer 1

Heat is absorbed during the phase change, but the temperature does not change because the heat is used to "unsettle" the interparticle interactions. There is no change in the kinetic energy of the particles, and thus no change in temperature.

What is heat?

The movement of kinetic energy from one media to another, or from an energy source to a medium or an object, is referred to as heat. Energy can be transferred in three ways: radiation, conduction, and convection.

The calorie (cal) is the standard unit of heat in the International System of Units (SI), and it is defined as the amount of energy transfer required to raise the temperature of one gramme of pure liquid water by one degree Celsius if the water temperature is greater than the freezing point but less than the boiling point.

Heat conduction occurs when two material medium or objects come into direct touch and one of them has a higher temperature than the other. Because temperatures tend to equalise, heat conduction consists of a transfer of kinetic energy from the warmer to the colder medium. A chilly human body being immersed in a hot bath is one example.

Convection heat arises when the motion of a liquid or gas transports energy from a warmer to a cooler zone. Convection is demonstrated by the tendency of warm air to ascend and cool air to fall, so equalising the air temperature inside a room with a hot stove.

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Related Questions

Which Property is an example of a chemical property?

A.The ability to Burn
B. The ability to melt
C. The ability to dissolve
D.The ability to Evaporate

Answers

A, The ability to burn
Because when you burn something, you cant unburn it, making it a chemical reaction. A physical reaction is a reaction that can be undone, such as mixing sand and rocks, or sand and metal shavings


Which image illustrates the bouncing of a light wave off of a surface?
A
B
с
D
A. A
B. B
C. C

Which image illustrates the bouncing of a light wave off of a surface?ABDA. AB. BC. C

Answers

Answer:

The answer is A good luck :P

Answer:

A

Explanation:

The light Bounces off because it is reflecting off glass or anything else

s the statement, "You run faster than I do," qualitative or quantitative?

Answers

Answer:

qualitative, its an expression, not specific #'s

Explanation:

It is Qualitative

What is Qualitative or Quantitative?

Quantitative : Data is number based , countable or measurable

Qualitative : Data is interpretation based , descriptive and relating to language

Since , the statement given in question does not in include any kind of number or measurable quantity and its just an descriptive and relating to language . It is Qualitative

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FILL THE BLANK.
the energy density of most enteral formulas is between _____.

Answers

The energy density of most enteral formulas is between 1.0 and 2.0 kilocalories per milliliter (kcal/mL).

The energy density of enteral formulas refers to the amount of calories (energy) contained within a given volume of the formula. Enteral formulas are specially designed liquid nutrition products used for individuals who are unable to consume food orally or have difficulty absorbing nutrients from solid food.

The energy density of most enteral formulas typically falls within the range of 1.0 to 2.0 kilocalories per milliliter (kcal/mL). This range allows for flexibility in meeting individual energy needs based on factors such as age, medical condition, and nutritional requirements.

Enteral formulas with lower energy density, such as 1.0 kcal/mL, are often used for individuals who require a lower calorie intake or have specific dietary restrictions. These formulas may be recommended for those with certain gastrointestinal disorders or conditions where a slower rate of nutrient delivery is desired.

On the other hand, enteral formulas with higher energy density, such as 1.5 or 2.0 kcal/mL, are utilized when higher calorie requirements need to be met within a smaller volume. These formulas may be beneficial for individuals with increased energy needs, such as those recovering from surgery, trauma, or severe malnutrition.

It's important to note that the energy density of enteral formulas can vary among different brands and types of products. Additionally, the choice of an enteral formula and its energy density should be made under the guidance of a healthcare professional or registered dietitian, considering the specific nutritional needs of the individual.

Hence, The energy density of most enteral formulas is between 1.0 and 2.0 kilocalories per milliliter (kcal/mL).

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Rhyolite forms as lava cools very quickly, forming holes.
Sometimes gems can form within the holes. The image
shows fire opal within rhyolite.
Which type of rock is rhyolite?
A. Intrusive igneous
B. Extrusive igneous
C. Metamorphic
D. Sedimentary
PREVIOUS

Rhyolite forms as lava cools very quickly, forming holes.Sometimes gems can form within the holes. The

Answers

Answer:

B. Extrusive igneous

Explanation:

Its B

two equally charged particles are held 3.2x10-3 m apart and then released from rest. the initial acceleration of the first particle is observed to be 7.0 m/s2 and that of the second to be 9.0m/s2 . if the mass of the first particle is 6.3 x 10-7 kg, what are (a) the mass of the second particle and (b) the magnitude

Answers

The mass and magnitude of the second particle are calculated below.

The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.

Distance between the charges, r = 3.2 × \(10^{-3}\)m

initial acceleration of first particle, \(a_{1}\) = 7m / \(s^{2}\)

Initial acceleration of second particle, \(a_{2}\) = 9.0m / \(s^{2}\)

Mass of first particle, \(m_{1}\) = 6.3 × \(10^{-7}\)kg

Mas of second particle, m₂ = ?

a) Since, \(F_{1}=F_{2}\)

∴ \(m_{1}a_{1} = m_{2}a_{2}\)

mass of second particle-\(m_{2}\) =\(\frac{m_{1}\times a_{1}}{a_{2}}\)

= \(\frac{6.3\times10^{-7}\times7.0}{9.0}\)

=4.9 × \(10^{-7}\)Kg

b)As, \(F_{1} = F_{2}\)

       = \(\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}\) = \(m_{1}a_{1}\)

       = 6.3 × \(10^{-7} \times\) 7.0

       = 44.1 × \(10^{-7}\)

∴ q = 7.1 × \(10^{-11}\)C.

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what is the process where dna can change in many ways?

Answers

Answer:

process of recombination

Explanation:

this process happens when 2 molecules of DNA exchange pieces of their genetic material with each other

one way to monitor global warming is to measure the average temperature of the ocean. researchers are doing this by measuring the time it takes sound pulses to travel underwater over large distances. at a depth of 1000 m, where ocean temperatures hold steady near 4∘c, the average sound speed is 1480m/s. it's known from laboratory measurements that the sound speed increases 4.0m/s for every 1.0∘c increase in temperature. in one experiment, where sounds generated near california are detected in the south pacific, the sound waves travel 7700 km .

Answers

The smallest change in average temperature that can be measured is 0.0475°C

Calculation

Average sound speed in deep sea = v=1480m/s

from California to south pacific, sound waves travel 7.7 x \(10^{6}\) m distance

smallest time change detected = 1s

The time required for the sound wave to travel the given distance without any change in temperature can be calculated as

t =x/v

=7.7 x \(10^{6}\) / 1480

=5202 s

The new time required for the waves,

t1 = t -\(\delta t\) =5202-1 =5201s

Now we have to calculate the new sound speed.

v1 = x/t1 = \(\frac{7.7 *10^6}{5202}\) =1480.19 m/s

so change in the speed of sound

\(\delta v = v1 - v\)

= 1480.19 - 1480 = 0.19 m/s

Then it is given that

\(\delta v\) = (4 m/s/°C) \(\delta T\)(°C)

Formulating,

0.19 m/s = (4 m/s/°C) \(\delta T\)(°C)

\(\delta T\) = 0.19/4

=0.0475°C

Thus, the smallest change in temperature is 0.0475°C

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1. The mass of the Earth is 81 times the mass of the Moon. Using Newton's Law of Gravity, what would the effect of gravitation be if the mass of the Moon were increased by four times and the distance between Earth and
the Moon were cut in half?

1. The mass of the Earth is 81 times the mass of the Moon. Using Newton's Law of Gravity, what would

Answers

Answer:

8 × the gravitational attraction

Explanation:

Hope this helps. :)

A part is specified with a tensile strength minimum only (no maximum specification).


It has a Cp = 1. 2. Please determine the reject rate. RR = _______________


1. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 2. Please determine the reject rate. RR = _______________


2. A part is specified with a tensile strength 2 sided specifications.


It has a Cp = 0. 7. Please determine the reject rate. RR = _______________


3. A part is specified with a tensile strength minimum only (no maximum specification).


It has a Cp = 1. Please determine the reject rate. RR = _______________


4. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.


It has a Cpk = 1. 3. Please determine the reject rate. RR = _______________


5. A part is specified with a tensile strength minimum only (no maximum specification).


It has a Cp = 1. 2. Please determine the reject rate. RR = _______________


6. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 1. Please determine the reject rate. RR = _______________


7. A part is specified with a tensile strength 2 sided specifications.


It has a Cp = 0. 6. Please determine the reject rate. RR = _______________


8. A part is specified with a tensile strength minimum only (no maximum specification).


It has a Cp = 1. 25. Please determine the reject rate. RR = _______________


9. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.


It has a Cpk = 0. 8. Please determine the reject rate. RR = _______________

Answers

To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.

1. RR = 0.27%

2. RR = 16.03%

3. RR = 0%

4. RR = 0.003%

5. RR = 0.27%

6. RR = 2.28%

7. RR = 29.93%

8. RR = 0%

9. RR = 5.87%

Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.

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A car advertisement states that a certain car can accelerate from rest to 140 m/s in 7 seconds. Find the car’s average acceleration.

Answers

Answer:

20 m/s

Explanation:

Bc Accelerations formula is V/T (velocity over time).

with this you can plug in the velocity witch is just speed with direction over time witch looks like this 140 m/s / 7 s.

and when you calculate acceleration= 20 m/s

Plz give brainliest:-)

A 60.0 kg runner is moving at 6.00 m/s and speeds up to 9.00 m/s. the runner’s change in kinetic energy is 1,350 j. how much work was done? –2,430 j –1,350 j 1,350 j 2,430 j

Answers

The work done is 1350. Option C is correct. The work-energy theorem is applied to a given problem.

What is the work-energy theorem?

From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.

\(\rm W_{net}=K_f-K_i \\\\ \rm W_{net}=\frac{1}{2}mv_f^2-\frac{1}{2} mv_i^2 \\\\ W_{net}=\frac{1}{2} m(v_f^2-v_i^2)}\)

Substitute the given value;

\(\rm W_{net}=\frac{1}{2} \times 60 \times (9.00^2-6.00^2)} \\\\ W_{net}=1350 \ J\)

The work done is 1350 J.

Hence option C is correct.

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Answer:

C on edge

Explanation:

1,350 J

If a spaceship approaches you at 0.5c, and a light on the spaceship is turned on pointing in your direction, how fast will the light be traveling when it reaches you?

Answers

Answer:

I'm pretty sure the speed of light is a constant so I my hypothesis is that the light will be travelling at *c*

What is the density of a piece of metal with a mass of 48g and a volume of 6 cm3

Answers

Answer:

A mineral has a volume of 6 mL and a mass of 12g.

Explanation:

Was this right?

A gas occupies 500mL at a temperature of 20 degrees Celsius. What is the volume at 150 degrees Celsius? ​

Answers

Answer: 3750 ML

Explanation:

​Two college students push a broken down, 711 kg car to a mechanic. If the first student pushes with a force of 638 N and the second student pushes with a force of 573 N, what is the magnitude of acceleration of the car?

Answers

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) .

Acceleration is the rate of change of velocity with respect to time.

Also it is the capacity of the vehicle to gain speed.

Mass of the car = 711 kg

Force exerted by the Student 1 = \(F_1\) =  638 N

Force exerted by the Student 2 = \(F_2\) =  573 N

Total force exerted on the car = F  = \(F_1\) + \(F_2\)

F = 638 + 573

F = 1,211 N

As we know that, Force is the product of mass and acceleration i.e.

F = m * a

\(a = \frac{F}{m}\)

a = \(\frac{1211}{711}\)

a = 1.70 \(m/s^{2}\)

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) to push it to a car mechanic.

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Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.

Answers

radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.

The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.

We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.

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what force can stop a 1400kg truck accelerating at 7.5m/s2? URGENT PLZZ

Answers

Answer:

10500 N

Explanation:

F = m*a=1400*7.5N=10500N

A solar eclipse may occur when:

A. when the moon is 3rd quarter phase
B. when the moon is full
C. when the moon is at 1st quarter phase
D. when the moon is new

Answers

D. When the moon is new

when placing all fingers and the palm in contact with the object being lifted, you are using which of the following? question 1 options: a) vise grip b) lock grip c) power lift d) power grip

Answers

I use a power lift when all of my fingers and my palm are in contact with the object I'm lifting.

What posture should your hand be in during a power lift?

Put your hand on the side of the object that is farthest away from you. It should be on the same side of your body as your forward foot. The most popular technique for good lifting is this lift. When there is sufficient space to adopt a wide stance and the object is small enough to be straddled, utilise the basic lift. 7.

How are your palms positioned when employing the power grip?

Each hand should be inserted under the handle with the palm facing up and the thumb pointing upward for a power grip. Never attempt to lift a stretcher or palm facing down over the handle of the backboard.

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a) Why does the amplitude of a compound motor action potential (CMAP) change when stimulus intensity was increased?
b) The minimum voltage needed to evoke a CMAP differed a small amount between the stimulus sites. Why? (Proximal = 21.34 mV ; Distal = 22.56 mV)
c) The experimental conduction velocity of the ulnar nerve (NCV) is 30 m/s, but in young healthy adults, it is about 60 m/sec. How does the conduction velocity you calculated compare with this value? If your value differs, what is one plausible explanation for this deviation from the literature value? You should explain how a specific error condition could have lead to the deviation from the expected value.

Answers

a) The amplitude of a Compound Motor Action Potential (CMAP) changes when stimulus intensity is increased because higher stimulus intensity leads to the recruitment of more motor units.

Motor units are the functional units of muscle contraction, consisting of a motor neuron and the muscle fibers it innervates. When a stimulus is applied to a muscle, initially only a small number of motor units are activated. As the stimulus intensity increases, more motor units are recruited, resulting in a larger overall muscle response and a higher CMAP amplitude.

The small difference in the minimum voltage needed to evoke a CMAP between the stimulus sites may be due to variations in nerve fiber excitability and electrode placement. Nerve fibers may have different thresholds for activation, and the location and positioning of the stimulating electrode can influence the effective stimulus intensity at different sites along the nerve pathway. These factors can contribute to slight variations in the minimum voltage required to elicit a CMAP response.

The calculated conduction velocity of the ulnar nerve may differ from the literature value of 60 m/s due to several reasons. One plausible explanation is the presence of a conduction block or nerve injury along the ulnar nerve pathway. A conduction block occurs when there is interruption or impairment of nerve conduction, resulting in a slower conduction velocity. This can be caused by nerve compression, inflammation, demyelination, or other pathological conditions.

If such a conduction block exists in the ulnar nerve of the subject being tested, it could lead to a deviation from the expected conduction velocity and a lower calculated value. Further diagnostic tests, such as nerve conduction studies or imaging, could help identify and evaluate the underlying cause of the deviation.

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you are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.8 × 107 m and its rotation period to be 22.3 hours. you have previously determined that the planet orbits 3.2 × 1011 m from its star with a period of 402 earth days. once on the surface you find that the acceleration due to gravity is 37.8 m/s2. what are the mass of (a) the planet and (b) the star? (g

Answers

The mass of the planet and star is \(2.4 *10^{25}\) kg and \(1.2 * 10^{31}\) kg respectively.

Acceleration due to gravity is the force experienced per unit mass of an object due to gravitational force and it is given by:

\(a = \frac{GM_{planet} }{r^{2} }\)

\(19.5 =\frac{6.67 * 10^{-11} * M_{planet} }{(0.9 * 10^{7}) ^{2} }\)

\(M_{planet} = 2.4 * 10^{25}\) kg

Now this planet orbits a star and so we can use Kepler's Third Law to find the mass of the star.

\(T^{2} = \frac{4\pi ^{2} }{GM_{star} } r^{3}\)

T = 402 earth days = 60 x 60 x 24 x 402 = 34732800 seconds

\(34732800^{2} = \frac{4\pi ^{2} }{6.67 * 10^{-11} M_{star} } (2.9 * 10^{11}) ^{3}\)

\(M_{star} = 1.2 * 10^{31}\) kg

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The mass of the star of the distant solar system is 82 * 10²² kg and the mass of the planet of the distant solar system is 8.58 * 10²⁵ kg

g = G M / r

g = Acceleration due to gravity

G = Gravitational constant

M = Mass of star

r = Distance between both bodies

g = 63.6 m / s²

G = 6.67 * 10⁻¹¹ N m² / kg²

r = 8.6 * 10¹¹ m

Ms = 63.6 * 8.6 * 10¹¹ / ( 6.67 * 10⁻¹¹ )

Ms = 82 * 10²² kg

F = G M m / r²

F = m g

Equating,

m g = G M m / r²

Mp = g r² / G

Mp = 63.6 * ( 1.8 * 10⁷ / 2 )² / 6.67 * 10⁻¹¹

Mp = 8.58 * 10²⁵ kg

Therefore the mass will be equal to 8.58 * 10²⁵ kg

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Please help u guys acellus sucks

Please help u guys acellus sucks

Answers

Answer:

6.0cm

Explanation:

Given

focal length = 15.0cm

object distance = 10.0cm

Required

Image distance v

Using the formula

1/f = 1/u + 1/v

1/15 = 1/10+1/v

1/v = 1/15 + 1/10

1/v = 2+3/30

1/v = 5/30

v = 30/5

v = 6.0cm

Hence the image distance is 6.0cm

Answer:

6.0 (2 sig figs)

Explanation:

Is it General Physics? I had it and passed the Final Exam with an A in the beginning of July!

An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.​

Answers

I suggest that the students move forward with option A.

Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.

To find a solution to the issue of the marble not landing on the launch pad consistently, I suggest the students follow a systematic approach in their design process. Option D, testing all of the above funnels and then constructing a funnel with the best design elements from each, would be the most comprehensive and effective approach.

By testing funnels of different sizes, materials, and openings, the students can gather valuable data and insights about how each factor affects the marble's trajectory. This will help them identify the key design elements that contribute to successful landing on the launch pad.

Once the students have tested the various funnels, they can analyze the results and determine which design elements worked best in terms of directing the marble accurately. By combining these successful elements, they can then construct a new funnel that incorporates the best features from each tested funnel. This iterative approach allows them to refine their design and increase the chances of achieving consistent and reliable results.

Therefore, option D provides a comprehensive method for the students to explore different design possibilities, gather data, and ultimately create an improved funnel design.

4. A foam cooler of negligible mass contains 1.75 kg of water Ice from a refrigerator at -15°C, is then added to the water in the cooler. When thermal equilibrium has been reached, the total mass of ice in the cooler is
0.778 kg. Assuming no heat exchange with the surroundings, what mass of ice was added? For water, Le-334 x 10 J/kg, and for ice, c-2100 J/(kg-K).
1.8 kg
O 1.1 kg
O 07
O
0.7 kg
0.9 kg

Answers

The mass of ice that was added is 1.11 kg. So the answer is 1.1 kg (option O 1.1 kg).

To solve this problem, we can use the principle of energy conservation. The heat gained by the ice will be equal to the heat lost by the water.

The heat gained by the ice can be calculated using the formula:

Q_ice = m_ice * c_ice * ΔT_ice

Where:

Q_ice = heat gained by the ice

m_ice = mass of ice added

c_ice = specific heat capacity of ice (2100 J/(kg-K))

ΔT_ice = change in temperature of the ice (from -15°C to 0°C)

The heat lost by the water can be calculated using the formula:

Q_water = m_water * L_water

Where:

Q_water = heat lost by the water

m_water = mass of water in the cooler

L_water = latent heat of fusion of water (334 x 10^3 J/kg)

Since there is no heat exchange with the surroundings, the heat gained by the ice is equal to the heat lost by the water:

Q_ice = Q_water

m_ice * c_ice * ΔT_ice = m_water * L_water

Substituting the known values:

m_ice * 2100 * (0 - (-15)) = 1.75 * 334 * 10^3

Simplifying the equation:

m_ice * 2100 * 15 = 1.75 * 334 * 10^3

m_ice = (1.75 * 334 * 10^3) / (2100 * 15)

m_ice ≈ 1.11 kg

Therefore, the mass of ice that was added is approximately 1.11 kg. So the answer is 1.1 kg (option O 1.1 kg).

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The __________ is located under the forebrain and midbrain. A. forebrain B. midbrain C. hindbrain D. brainstem

Answers

Answer is the hind brain

The brainstem is located under the forebrain and midbrain. Therefore option D is correct.

The brainstem is located under both the forebrain and midbrain. It is a vital component of the central nervous system that connects the brain to the spinal cord and controls many essential functions such as breathing, heart rate, and digestion.

It consists of three main regions: the medulla oblongata, pons, and midbrain. The forebrain, midbrain, and hindbrain together constitute the major divisions of the brain.

The hindbrain is positioned below the midbrain and includes structures like the cerebellum, pons, and medulla oblongata.

The brainstem, specifically its lower regions, is responsible for relaying information between the brain and the rest of the body while regulating critical bodily functions.

Therefore option D is correct.

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Why does weight change depending
on location?

Answers

Answer:

gravity

Explanation:

gravity pulls you down so for example you will weigh more on earth than on the moon because earths gravitational pull is greater.

show the positioning of an objective lens and eye piece of the following devices with respect to their focal length . example d=fo-fe and number of lens in the device
1. simple microscopic (magnifying glass)
2. compound microscope
3. astronomical telescope
4. galilean telescope
5. prismatic binoculars ​

Answers

1. Simple Microscope (Magnifying Glass): Objective lens = N/A, Eyepiece = N/A (Single Lens)

2. Compound Microscope: Objective lens = Closer, Eyepiece = Farther

3. Astronomical Telescope: Objective lens = Closer, Eyepiece = Farther

4. Galilean Telescope: Objective lens = Closer, Eyepiece = Farther

5. Prismatic Binoculars: Objective lens = Closer, Eyepiece = Farther

Simple Microscope (Magnifying Glass):

In a simple microscope or magnifying glass, there is only one lens, which serves as both the objective lens and the eyepiece. The lens is convex and typically has a short focal length. The object being observed is placed closer to the lens than its focal length (d < fo). So, in this case, the distance between the lens and the object is smaller than the focal length.

Compound Microscope:

A compound microscope consists of two lenses: the objective lens and the eyepiece. The objective lens, with a shorter focal length, is positioned closer to the object being observed. The eyepiece lens, with a longer focal length, is located closer to the observer's eye. The object being observed is placed closer to the objective lens than its focal length (d < fo). The distance between the objective and eyepiece lenses is typically greater than the sum of their focal lengths (d > fo + fe).

Astronomical Telescope:

In an astronomical telescope, the objective lens is positioned closer to the object being observed, such as celestial bodies. The objective lens has a longer focal length compared to the eyepiece lens. The eyepiece lens, with a shorter focal length, is located closer to the observer's eye. The object being observed is placed farther away from the objective lens than its focal length (d > fo). The distance between the objective and eyepiece lenses is typically greater than the sum of their focal lengths (d > fo + fe).

Galilean Telescope:

A Galilean telescope has a convex objective lens and a concave eyepiece lens. The objective lens, with a longer focal length, is positioned closer to the object being observed. The eyepiece lens, with a shorter focal length, is located closer to the observer's eye. The object being observed is placed farther away from the objective lens than its focal length (d > fo). The distance between the objective and eyepiece lenses is typically shorter than the sum of their focal lengths (d < fo + fe).

Prismatic Binoculars:

Prismatic binoculars use multiple lenses and prisms to provide a magnified view. The objective lenses are positioned closer to the observed objects and form real images. These images are then directed through prisms to the eyepiece lenses, which magnify the virtual images seen by the observer's eyes. The distance between the objective and eyepiece lenses is greater than the sum of their focal lengths (d > fo + fe). Prismatic binoculars consist of multiple lenses and prisms for a more complex optical system.

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for the series circuit in the previous part, change the resistance of the bottom resistor to 20 ωω . what is the voltage across this 20- ωω resistor?

Answers

In a series circuit, the total resistance is the sum of all individual resistances. So, if the bottom resistor is changed to 20 ω, the total resistance of the circuit will increase.

The voltage across the resistor can be found using Ohm's law, which states that voltage (V) is equal to the current (I) times the resistance (R), or V=IR.

Assuming a constant current flow through the circuit, the voltage across the 20 ω resistor can be found by using the total resistance of the circuit. Let's say the total resistance is 100 ω. If the current through the circuit is 1A, then using Ohm's law, the voltage across the 20 ω resistor would be V=IR=1A x 20 ω = 20V.

Therefore, if the resistance of the bottom resistor in a series circuit is changed to 20 ω, the voltage across it will depend on the total resistance and current of the circuit. In the example above, the voltage across the 20 ω resistor would be 20V.

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Please answer, No links please, i need a real answer!
The table shows the mass and melting point of some substances.
Melting Point of Substances
Mass Melting Point of Tin Melting Point of Lead
(kg)
(°C)
(°C)
1
W
Y
N
232
327
Part 1: What will be the values of W and Y for 1 kg of each substance?
Part 2: Explain your answer for Part 1.

Please answer, No links please, i need a real answer! The table shows the mass and melting point of some

Answers

Answer:

W= 116  Y= 163

Explanation:

This is because the cutting the mass in half would make it half of the temp of the mass 1 kg higher.

Answer: W=116 Y=163

Explanation:

We have to divide 2 by 232 and 327

232/2= 116    327/2=163

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