Explain two scenarios where a large truck can have the same momentum as a small car.

Answers

Answer 1

The momentum, p, of any object having mass m and the velocity v is

\(p=mv\cdots(i)\)

Let \(M_L\) and \(M_S\) be the masses of the large truck and the car respectively, and \(V_L\) and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck \(= M_LV_L\)

and the momentum of the small car \(= M_SV_S\).

If the large truck has the same momentum as a small car, then the condition is

\(M_LV_L=M_SV_S\cdots(ii)\)

The equation (ii) can be rearranged as

\(\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}\)

So, the first scenario:

\(\frac {M_L}{M_S}=\frac {V_S}{V_L}\)

\(\Rhghtarrow M_L:M_S=V_S:V_L\)

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\(\frac{M_L}{V_S}=\frac{M_S}{V_L}\)

\(\Rhghtarrow M_L:V_S= M_S:V_L\)

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.


Related Questions

A cheetah can run at a maximum speed 95.2 km/h and a gazelle can run at a maximum speed of 79.9 km/h. If both animals are running at full speed, with the gazelle 53.1 m ahead, how long before the cheetah catches its prey? Answer in units of s. (Part 1)

The cheetah can maintain its maximum speed for only 7.5 s.
What is the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape? (After 7.5 s the speed of cheetah is less than that of the gazelle.)
Answer in units of m. (Part 2)

Answers

1 ) The cheetah catches its prey after 277 m

2 ) The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is 31.5 m

Let the velocity of cheetah be Vc and that of gazelle be Vg.

Vc = 95.2 km / h

Vg = 79.9 km / h

Since they both travel for same amount of time,

Tc = Tg

dc / Vc = dc / Vg

( 0.0531 + x ) / 95.2 = x / 79.9

95.2 x = 4.24 + 79.9 x

15.3 x = 4.24

x = 0.277 km

x = 277 m

Distance travelled by cheetah in 7.5 seconds = 26.4 m / s * 7.5 s

Distance travelled by cheetah in 7.5 seconds = 198 m

Distance travelled by gazelle in 7.5 seconds = 22.2 m / s * 7.5 s

Distance travelled by gazelle in 7.5 seconds = 166.5 m

Distance that the gazelle need be ahead of cheetah to escape = 198 - 166.5 = 31.5 m

Therefore,

1 ) The cheetah catches its prey after 277 m

2 ) The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is 31.5 m

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An object of mass(0.8kg) is attached to massless string of length (2.0),and swung with a tangential velocity of (3.0m/s) what is the tension in the string?

Answers

Answer:

3.6 N

Explanation:

The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.

The formula is :

T= mv²/r ------where T is tension

m= mass of object =0.8 kg

v= velocity of object {tangential velocity} = 3.0 m/s

r= length of string = 2m

Applying the formula with real values;

T= mv²/r

T= {0.8 * 3²} / 2

T= { 7.2}/2 = 3.6 N

What are the latitude and longitude coordinates for Location C? 1) 50N, 68S 2) 50N, 68W 3) 50S, 68E 4) 50S, 68W Which is farther- the distance between Location B and the Equator or the distance between Location C and the Equator? 1) Location B and the Equator 2) Location C and the Equator 3) Locations B and C are the same distance from the Equator 4) Cannot discern from the information provided

Answers

The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.

Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.

However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.

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. a horse on a merry go round is 7 m from the center and travels at 10km/hr. what is its angular speed? brainly

Answers

The angular speed of the horse that which is 7 m from the cenetr of a merry go round is 252 m/s.

What is angular speed?

Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.

To calculate the angular speed of the horse, we use the formula below.

Formula:

ω = v/r................... Equation 1

Where:

ω = Angular speedv = Linear speed = 10 km/hr = (10×3600/1000) m/s = 36 m/sr = Radius of the circular part = 7m

Substitute these values into equation 1

ω = 36×7ω = 252 m/s

Hence, the angular speed of the horse is 252 m/s.

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What does a filled-in circle mean on a pedigree?

Answers

The circle of the family tree symbol represents a female individual. Individuals are the main component of a family tree chart.

A pedigree chart is a graph showing the prevalence and incidence of a particular gene or organism and its ancestors from one generation to the next (most commonly humans, show dogs, and horses race). The Family Tree presents family information in an easy-to-read chart. We could simply call it a "family tree". The genealogy uses a standardized set of symbols, with squares representing males and circles representing females. Building the family tree is the story of the family, and as memories fade, details about previous generations can become uncertain.

Diamonds are used if the gender of the person is unknown. Individuals with associated phenotypes are indicated by solid (dark) symbols. Heterozygotes, when identifiable, are indicated by shaded dots in symbols or half-filled symbols.

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A recipe gives the instructions below.

After browning the meat, pour off the fat from the pan.
To further reduce fat, use a strainer.

What type of separation methods are described in the recipe?

decantation and screening
distillation and screening
decantation and centrifugation
distillation and filtration

Answers

Answer: decantation and screening

Explanation:

Answer:

it is A

Explanation:

the person above me helped

Two charges are separated by 1.68 cm. Object A has a charge of 5.0 μ C , while object B has a charge of 7.0 μ C . What is the force on Object A?

Answers

Answer:

The force on Object A = 1116.07 N

Explanation:

The separation between the two charges, d = 1.68 cm

d = 1.68/100 m

d = 0.0168 m

The charge on object A

\(\begin{gathered} q_A=5.0\mu C \\ q_A=5\times10^{-6}C \end{gathered}\)

The charge on object B

\(\begin{gathered} q_B=7.0\mu C \\ q_B=7\times10^{-6}C \end{gathered}\)

The electric constant

\(k=9\times10^9Nm^2C^{-2}\)

The force on on the charge A is calculated as shown below:

\(\begin{gathered} F_A=\frac{kq_Aq_B}{d^2} \\ F_A=\frac{9\times10^9\times5\times10^{-6}\times7\times10^{-6}}{0.0168^2} \\ F_A=\frac{0.315}{0.00028224} \\ F_A=1116.07N \end{gathered}\)

The force on Object A = 1116.07 N

In an experiment, Erin holds two conductive objects. Object A has a charge of –4.81 × 10–7 C, and object B has a charge of 6.41 × 10–7 C. She touches the objects together.
1. Roughly how many more electrons are there than protons in object A before the two objects come in contact?
2. Roughly how many more protons are there than electrons in object B before the two objects come in contact?
3. After Erin touches the objects together, what is the net charge on each object?

Answers

1. there are roughly 3 × 10^12 more electrons than protons in object A before the two objects come in contact.

2.  there are roughly 4 × 10^12 more protons than electrons in object B before the two objects come in contact.

3.  the net charge on object A after touching is -4.81 × 10^-7 C, and the net charge on object B is +4.81 × 10^-7 C.

What is an electron?

The electron is described as a subatomic particle with a negative one elementary electric charge.

We divide the charge by the charge of one electron to get the number of  electrons are there than protons in object A before the two objects come in contact:

excess electrons = charge on object A / charge of one electron

= -4.81 × 10^-7 C / -1.602 × 10^-19 C

3 × 10^12 electrons

2.

we divide the charge by the charge of one proton to get protons that are there than electrons in object B before the two objects come in contact:

excess protons = charge on object B / charge of one proton

= 6.41 × 10^-7 C / 1.602 × 10^-19 C

4 × 10^12 protons

3.

charge on object A + charge on object B = 0

-4.81 × 10^-7 C + charge on object B = 0

charge on object B = 4.81 × 10^-7 C

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!!! i'll give brainliest to whoever can answer this for me !!!

you have to match the letters in the picture to the list of energy types

!!! i'll give brainliest to whoever can answer this for me !!!you have to match the letters in the picture

Answers

Answer:

you have to match the letters in the picture to the list of energy types

when light travelling in a certain medium falls on the surface of another medium, a part of it turns back in the same medium. this phenomenon is called group of answer choices diffraction dispersion reflection refraction acoustics

Answers

When light travels in a certain medium and falls on the surface of another medium a part of it turns back in the same medium This phenomenon is called Reflection.

A wavefront may alter its course at an interface between two different media and return to the first medium, a phenomenon known as reflection. Common examples are the reflection of light, sound, and water waves.

Reflection of light refers to the occurrence where light strikes an item and bounces back off its surface. Examples: using a flat mirror to reflect. by a spherical mirror's reflection. There are essentially two types of reflection that apply to light. While diffuse reflection is caused by rough surfaces that tend to reflect light in all directions, specular reflection is described as light reflected off a smooth surface at a specific angle.

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What is force? Do systems have inputs, outputs, do they have both, do they have one, do they have the other, what are the systems.

Answers

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Systems always have inputs and outputs.

Explanation:

Resistance in metals increases with increasing temperature according to the equation, rho (T) rhoₒ(1 + α (T-Tₒ)) where α is the temperature coefficient of resistivity and rhoₒ is the resistivity at temperature Tₒ For a particular wire α = 5.5 x 10⁻³ 1/°C and the resistivity and is rhoₒ = 4.5x 10.7 Ω·m at Tₒ = 229 °C
Part (a) Input an expression for the temperature T₂ at which the resistance of a wire will be twice as high as as at Tₒ.
T₂ = _________
Part (b) What is this temperature, in degrees Celcius?
Part (c) If the wire is L = 1 m long with a radius of r = 1 cm, what is its resistance R, in Ω, at 2 Tₒ?

Answers

(a) T₂ = Tₒ + (2ρₒ - ρₒ) / (αρₒ), (b) Substitute values to find T₂ in °C, (c) Use R = ρ(T) * (L / A) to find resistance R at 2Tₒ.

Part (a) To find the temperature T₂ at which the resistance of the wire will be twice as high as at Tₒ, we can set up the equation:

2ρₒ(1 + α(T₂ - Tₒ)) = ρₒ(1 + α(T - Tₒ))

By simplifying and cancelling ρₒ on both sides, we get:

2(1 + α(T₂ - Tₒ)) = 1 + α(T - Tₒ)

Expanding and rearranging the equation, we have:

2αT₂ - 2αTₒ + 2 = αT - αTₒ

2αT₂ = αT + (2αTₒ - αTₒ - 2)

2αT₂ = αT + αTₒ - 2αTₒ + αTₒ - 2

2αT₂ = αT - αTₒ - 2

Dividing both sides by 2α, we obtain:

T₂ = (αT - αTₒ - 2) / (2α)

Part (b) To find the temperature T₂ in degrees Celsius, we substitute the given values:

T₂ = (5.5x10⁻³T - 5.5x10⁻³(229) - 2) / (2x5.5x10⁻³)

T₂ = (5.5x10⁻³T - 1.2595 - 2) / (11x10⁻³)

T₂ = (5.5x10⁻³T - 3.2595) / (11x10⁻³)

Part (c) To find the resistance R at 2Tₒ, we use the formula for resistance:

R = (ρL) / A

where ρ is the resistivity, L is the length, and A is the cross-sectional area. Given the wire length L = 1 m and the radius r = 1 cm (which is equal to 0.01 m), we can calculate the cross-sectional area A:

A = πr² = π(0.01)² = 0.0001π m²

Substituting the given resistivity ρₒ = 4.5x10⁻⁷ Ω·m at Tₒ = 229 °C, we can calculate the resistance R at 2Tₒ:

R = (ρL) / A = (4.5x10⁻⁷)(1) / (0.0001π) = 0.045 / π Ω

Therefore, the resistance R at 2Tₒ is approximately 0.045 / π Ω.

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(c) Identify the forces acting on your hand. (Select all that apply.) book on hand hand on book floor on hand earth on hand'

Answers

Both the force of "Hand on the book" and the force of "Earth on the book" are directed upward. The ground and the book are being drawn in toward the hand. As a result, the forces pulling on the hands are "Book on hand" and "Earth on hand."

Gravity, usually referred to as gravitation, is the unchanging force of attraction that binds everything together in physics. Being the weakest known force in nature, it has minimal effect on defining the inherent properties of everyday objects.

The force "Hand on the book" is directed upward, and the force "Earth on the book" is directed downward. The hand is being pulled toward the book and the earth.

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PLEASE HELP...How much power is done when you exert 30J of Work over 5 seconds?​

Answers

May Help:

In classical physics terms, you do work on an object when you exert a ... to do work (follow the kinetic and potential energy links for a more in ... runs twice as powerfully as the runner that finishes in 5 hours. The unit of power is joules per second or J/s when work is measured in joules and time in seconds.

Q11: A mercury manometer is connected to a container that holds alcohol and traps some gas, as shown in the figure. knowing the demsity of mercury is 13 600 kg/m³, the density of alcohol is 750 kg/m³, the acceleration due to gravity is 10 m/s². and the atmospheric pressure is 76 cmHg. what is the pressure at the bottom of the container ?​

Answers

The following equation can be used to determine the pressure at the bottom of the container:

\(P_b_o_t_t_o_m = P_a_t_m + p_m_e_r_c_u_r_y_g_h\)

where

h is the height difference between the two arms of the manometer (in m),

g is the acceleration due to gravity (in m/s2),

\(P_a_t_m\) is the atmospheric pressure (in Pa), and

\(p_H_g\) is the density of mercury (kg/m3) In).

To find the height difference h, we need to use the density difference between mercury and alcohol. We can write:

ρ_mercury * g * h = ρ_alcohol * g * h'

where

ρ_alcohol is the density of alcohol (in kg/m³) and

h' is the height difference between the mercury level and the alcohol level in the arm of the manometer that is in contact with the alcohol.

Solving for h, we get:

h = (ρ_alcohol / ρ_mercury) * h'

Therefore, the first equation can be used to determine the pressure at the bottom of the container once we know h.

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The mass of each loaf of bread produced by a bakery follows a normal distribution with the mean of 400g and standard deviation of 18g. Find the probability that a loaf of bread chosen at random will have a mass of more than 450g.

Answers

The probability that a loaf of bread chosen at random will have a mass of more than 450g is 0.0026 or 0.26%.

The probability that a loaf of bread chosen at random will have a mass of more than 450g is found by first standardizing the random variable, using the standard normal distribution. We can then use the standard normal table or calculator to find the area to the right of the standardized value. The standardized random variable can be found using the formula

Z = (X - μ) / σ,

where X is the given value, μ is the mean, and σ is the standard deviation.

Substituting the given values, we get:

Z = (450 - 400) / 18 = 2.78

Using the standard normal table or calculator, we can find the area to the right of 2.78. This area represents the probability that a loaf of bread chosen at random will have a mass of more than 450g.

Using a standard normal table or calculator, we find that this area is 0.0026 or 0.26%.

Hence, the probability that a loaf of bread chosen at random will have a mass of more than 450g is 0.0026 or 0.26%.

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Please select the best answer from the choices provided


A
B
C
D

Please select the best answer from the choices providedABCD

Answers

D hi hi hi hi hi hi g u hudiikekoow the answer is D

Answer:

D hope this helps plz mark brainliest

Explanation:

For a sled sliding down a frictionless slope with a constant inclination, the acceleration of the sled is?

Answers

The acceleration of the sled is, the acceleration is equal to the acceleration of gravity multiplied by the sine of the angle for a frictionless incline of degree.

How fast is an inclined plane without friction moving?The acceleration is equal to the acceleration of gravity multiplied by the sine of the angle for a frictionless incline of degree.The measure of the force applied by any surface is its acceleration. The motion is stopped on the frictionless surface by the friction force, which is meant to do so. Acceleration on frictionless surfaces is equal to zero since the net forces acting on the body are eliminated.The sine of the incline angle, (), determines how quickly something accelerates. The angle of inclination equals 90° when sin is equal to 1. It's the same as falling freely. The slope of the acceleration vs sin graph can then be used to calculate the acceleration during free fall.  

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A solenoid with a length of 6.5 cm and 200 loops is carrying 5 A of current. What is the
strength of the magnetic field at the center of the solenoid? Label the north and south pole of
the solenoid.

Answers

The strength of the magnetic field at the center of the solenoid is 0.006 T

Magnetic field calculation.

The strength of the magnetic field at the center of a solenoid is given by:

B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.

In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:

n = 200 / 0.065 m = 3076.92 turns/m

The current flowing through the solenoid is 5 A.

The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.

Therefore, the magnetic field strength at the center of the solenoid is:

B = μ₀ * n * I

= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A

= 0.006 T

So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.

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you push a block of 50kg with a force of 400 N over a distance of 8m. How much kinetic energy does the box gain?

Answers

Answer:

The box gains 3200 J of kinect energy.

Explanation:

What is kinect energy?

Kinect energy is the energy of an object has because of its motion. Almost anything that has mass and it's in motion has kinect energy. Examples:

wind;throwing a footbal;driving a car;lauching a rocket;etc.

What is the work energy theorem?

Also known as the principle of work and kinect energy, it states that the work done by all forces acting upon an object equals the change of its kinect energy.

For example, if you pull a box, then you're exerting a force on it and it moves forward. Since the box has mass and it's in motion, you have changed its kinect energy.

Solution:

Write the data down:

\(\bullet \quad \mathsf{m=50\,kg}\\\\\bullet \quad \mathsf{F=400\,N}\\\\\bullet \quad \mathsf{d=8\,m}\)

Apply work energy theorem:

\(\mathsf{W}= \Delta\mathsf{K}\)

The amount work done equals the change of kinect energy:

\(\mathsf{W}=\mathsf{K-K_o}\)

Since the block is at rest at the beginning, so it has zero initial kinect energy:

\(\mathsf{W}=\mathsf{K-0}\\\\\\\mathsf{W}=\mathsf{K}\)

Now, apply the formula for work to the left hand side of the equation:

\(\mathsf{F\cdot d}=\mathsf{K}\\\\\\\mathsf{400\cdot 8}=\mathsf{K}\\\\\\\therefore \boxed{\mathsf{K=3200\,J}}\)

Conclusion: the box has gained 3200 J of kinect energy.

Happy studying!

Brainly Team

you push a block of 50kg with a force of 400 N over a distance of 8m. How much kinetic energy does the

Which famous inventor invented the telephone?

Thomas Edison

Benjamin Franklin

Alexander Graham Bell

Nikola Tesla

Answers

Answer:

Alexander Graham Bell

Hope this helps :)

Alexander Graham Bell

hope this helps

Packing material such as packing peanuts or bubble wrap are used to reduce theforce on items when a box is dropped during shipping. Which is the best explanationfor why the force is reduced?The packing material makes the object fall slower and impact the ground withless force..The packing material allows the contents of a box to move more freely.The packing material cushions the contents and increases the time of impactwhen the box strikes the ground.The packing material increases the mass of the box reducing the impact whenthe box strikes the ground.

Packing material such as packing peanuts or bubble wrap are used to reduce theforce on items when a box

Answers

The correct choice is the third option.

This comes from the fact that the packing material cushions the impacts of the content in case of a fall.

consider what happens to the two spoons. choose the terms that correctly complete the sentences. the metal in the spoon is an excellent conductor , which means that it choose... heat well. on the other hand, wood is an excellent choose... , which means that it easily choose... heat.

Answers

The metal in the spoon is an excellent conductor is correct sentences.

Conductors are the elements or materials that allow electricity to pass through them. They conduct electricity because they allow for simple electron passage between atoms inside of them. Conductors also allow heat or light to be transferred between sources. People, the earth, metals, and living things are all examples of conductors. We occasionally get electric shocks as a result. Additionally an excellent conductor of electricity is the human body. Therefore, it provides an unimpeded conduit for the electricity to travel from wire to body.

Conductors are made easy for current to pass through by the presence of free electrons on their surface. The capacity of conductors to carry electricity is based on this.

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How long would it take you too run the 100m sprint if from rest you accelerate at 2m/s/s for the whole race?

Answers

Answer:

10 s

Explanation:

Given:

Δx = 100 m

v₀ = 0 m/s

a = 2 m/s²

Find: t

Δx = v₀ t + ½ at²

100 m = (0 m/s) t + ½ (2 m/s²) t²

t = 10 s

a person hums into the top of a well and finds that the standing waves are established at frequencies of 54, 90, and 126 hz. the frequency of 54 hz is not necessarily the fundamental frequency. the speed of sound is 343 m/sec. how deep is the well?

Answers

To determine the depth of the well, we can use the relationship between the wavelength of the sound wave and the depth of the well. The standing wave pattern in the well is created by the interference between the sound wave emitted by the person and the reflected wave from the bottom of the well. The depth of the well is approximately 3.18 meters.

The formula for the wavelength of a standing wave in a closed pipe (like a well) is:

λ = 2L/n

Where:

λ is the wavelength

L is the length of the pipe (depth of the well)

n is the harmonic number (1 for the fundamental frequency, 2 for the second harmonic, 3 for the third harmonic, and so on)

In this case, we have three standing waves with frequencies of 54 Hz, 90 Hz, and 126 Hz. We need to find the fundamental frequency (first harmonic) among these three frequencies.

To find the fundamental frequency, we need to determine the harmonic number (n) for the frequency of 54 Hz. We can do this by comparing it with the harmonic numbers of the other frequencies.

Let's calculate the harmonic numbers for the frequencies of 90 Hz and 126 Hz:

Now, let's find the harmonic number (n) for the frequency of 54 Hz:

n = (\(v_{sound}\)) / (2L) = (343 m/s) / (2L)

Since we don't know the harmonic number for 54 Hz, we'll assume it as the fundamental frequency (n = 1) and find the corresponding length of the well (L).

Using the formula for the wavelength, we have:

λ = 2L/n

For the assumed fundamental frequency (n = 1) of 54 Hz:

λ = 2L/1

The speed of sound (\(v_{sound}\) ) is given as 343 m/s. The wavelength (λ) can be calculated using the formula:

λ = \(v_{sound}\)/ f

Where:

f is the frequency

For the assumed fundamental frequency (54 Hz):

λ = (343 m/s) / (54 Hz)

Now, we can equate the two expressions for λ and solve for L (the depth of the well):

2L = (343 m/s) / (54 Hz)

L = ((343 m/s) / (54 Hz)) / 2

L = 3.18 m

Therefore, the depth of the well is approximately 3.18 meters.

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What is the S.I Unit of electric flux?

Answers

Answer:

Volt metre (Vm)

or Newton/Coulomb x (Metre)^2       (N/C x m^2)

HEY CAN ANYONE PLS ANSWER DIS!

HEY CAN ANYONE PLS ANSWER DIS!

Answers

Answer:

sodium chloride

Explanation:

which is the correct statement regarding the work and impulse required to move a box on the floor i) from 2v to 3v; and ii) from 3v to 4v? a box is shown on a horizontal surface. which is the correct statement regarding the work and impulse required to move a box on the floor i) from 2v to 3v; and ii) from 3v to 4v? a box is shown on a horizontal surface. case i requires more work, but i and ii require the same amount of impulse; case i requires less impulse, but i and ii require the same amount of work; case i requires less work, but i and ii require the same amount of impulse; case i requires more impulse, but i and ii require the same amount of work; the two cases require the same amount of work and impulse;

Answers

The correct statement regarding the work and impulse required to move a box on the floor from 2v to 3v and from 3v to 4v is Case i requires less work, but i and ii require the same amount of impulse.

W = ΔKE

W = Work done

ΔKE = Change in Kinetic energy

ΔKE = 1 / 2 m ( v2 - v1 )²

J = m Δv

J = Impulse

m = Mass

Δv = Change in velocity

For ( i ),

W = 1 / 2 m ( ( 3 v )² - ( 2 v )² )

W = 1 / 2 m ( 9 v² - 4 v² )

W = 2.5 m v²

J = m ( 3 v - 2 v )

J = m v

For ( ii ),

W = 1 / 2 m ( ( 4 v )² - ( 3 v )² )

W = 1 / 2 m ( 16 v² - 9 v² )

W = 3.5 m v²

J = m ( 4 v - 3 v )

J = m v

Therefore,

i ) W1 < W2

ii ) J1 = J2

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In the equation for specific heat capacity, temperature is measured using the units degrees __________.

Answers

Answer kelvin

Explanation:

Use the table below to answer the questions.
Measured Values for a Stamp's Length
Student 1 Student 2 Student 3
Trial 1 2.60 cm 2.70 cm 2.75 cm
Trial 2 2.72 cm 2.69 cm 2.74 cm
Trial 3 2.65 cm 2.71 cm 2.64 cm
Average 2.66 cm 2.70 cm 2.71 cm

Three students measured the length of a stamp whose accepted length is 2.71 cm. Based on the table, which statement is true?
Multiple choice question.

A)
Student 3 is both precise and accurate.

B)
Student 2 is both precise and accurate.

C)
Student 1 is more accurate than Student 3.

D)
Student 2 is less precise than Student 1.

Answers

Student three because it says 2.71

Three students measured the length of a stamp whose accepted length is 2.71 cm, on the basis of the table student 2 is both precise and accurate, therefore the correct answer is option B.

What is a unit of measurement?

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The degree to which a measurement is accurate in relation to its true value. The degree to which the same results are produced by repeated measurements under the same circumstances is known as precision.

Thus, according to the chart, student 2 is both exact and accurate, hence the proper response is option B. Three students measured the length of a stamp, and the approved length is 2.71 cm.

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