See below.
The following are the guidelines for creating ray diagrams for the generation of an image by a concave mirror:
Rule 1: If the incident ray is parallel to the major axis, the reflected ray will pass through the concave mirror's focus.
The reflected ray is parallel to the principal axis if the incident ray passes through the focus of the concave mirror.
Rule 3: If the incident ray passes through the concave mirror's center of curvature, the reflected ray follows the same path.
Hope this helps!
a wave having a wavelength of 4.7 meters and an amplitude of 2.5 meters travels a distance of 28 meters in 7 seconds. determine the frequency and period of the wave
Answer:
T(Period) = 1.33sf(Frequency) = 0.75Hz (cycles/second)Explanation:
Given:λ = 4.0mAmplitude = 25md = 24ms = 8.0sRequired:f = ?T = ?Analysis:v = λff =N/tT = 1/fv = d/tSolve:v = d/t = 24/8.0 → v = 3.0m/sv =λf → f = v/λ = 3.0/4.0 → f = 0.75HzT = 1/f = 1/0.75 → T = 1.33sHopes this helps. Mark as brainlest plz!A
person shoves an ice cube off a table. Which of the following acts on the ice cube after it leave
the table but before it hits the floor?
Answer:
friction I would guess? you didnt leave any options.
Explanation:
A house painter uses the chair and pulley arrangement of the figure to lift himself up the side of a house. The painter's mass is 68kg and the chair's mass is 8.0kg .
With what force must he pull down on the rope in order to accelerate upward at 0.20m/s2 ?
The house painter must pull down on the rope with a force of 15.2 N to accelerate upward at 0.20 m/s².
Mass of the painter, m = 68 kg
Mass of the chair, M = 8.0 kg
Acceleration, a = 0.20 m/s²
The tension in a rope in such an arrangement is,
T = (m + M) x a
Substituting the given values ,
T = (m + M) x a
T = (68 kg + 8.0 kg) x 0.20 m/s²
= 15.2 N
Therefore, the house painter must pull down on the rope with a force of 15.2 N to accelerate upward at 0.20 m/s².
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A golf ball of mass 0.045 kg is hit off the tee at a speed of 34m/s . The golf club was in contact with the ball for 3.50*10^-3s .
Find the impulse imparted to the golf ball.??
Find the average force exerted on the ball by the golf club.??
Express your answer to two significant figures and include the appropriate units.
The average force exerted on the ball by the golf club is 490 N.
Thus, F = p/t = 0.49 * 10³ N = 490 N.
Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.
A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.
This is because bowling balls are larger in mass than ping-pong balls.
Thus, The average force exerted on the ball by the golf club is 490 N.
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You drive a bumper car into another bumper car whose driver has a much larger body mass than you do. Who experiences more of a jolt, you or the other driver?
Answer:
both drivers experience the same force. just with different "results"
Explanation:
Answer:
You do
Explanation:
Momentum is mass*velocity. So Newton's 3rd law equal and opposite reaction. Because you weigh less you will have more force act on you than the driver who weighs more.
A girl, standing 150m in front of a tall building, fires a shot using a starting pistol. A boy, standing
350 m from the girl
, hears two bangs 1s apart.
June 200
my
PATI
gid
boy
47
150 m
350 m
From this information, what is the speed of sound in air?
A 300 m/s
B 350 m/s
D 650 m/s
C 500 m/s
Answer:
I believe 650 or C
Explanation:
plz mark brainnlyist :)
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
Which describes the greatest amount of ice cream?
a 3-N bowl of ice cream on the moon a
3-N bowl of ice cream on Jupiter a
3-N bowl of ice cream on Earth's surface a
3-N bowl at the bottom of an Earth ocean
We must know that the gravity acceleration on Jupyter is g = 24.79 m/s² , on the Earth g = 9.8 m/s² and on the moon 1.62 m/s².
The weigh of an object is given by:
P = mg
Solving for m:
m = P/g
We see that for the same weight, if gravity is less, then the amount of mass is greater, because they are inversely proportional. So we conclude that the answer is:
a 3-N bowl of ice cream on the moonOn arrival at a vehicle collision, you observe a small fire in the engine compartment. A bystander is attempting to smother the fire with a jacket as you approach with an A-B-C extinguisher from your ambulance. Which of the following is the best method of extinguishing the fire?
a. Sweep the nozzle of the extinguisher left and right using short bursts until you are out of extinguishing agent.
b. Aim at the base of the fire and use short bursts until the fire is out.
c. Close the hood to contain the fire within the engine compartment.
d. Aim the nozzle to the side of the fire and, with a sweeping motion, push the fire at its base
Answer:
Aim at the base of the fire and use short bursts until the fire is out.
Explanation:
Fire extinguishers use CO2 (Carbondioxide) as the extinguishing agent. This is because CO2 is denser than air, and does not support combustion.
Aiming at the base of the fire causes the CO2 to fall on the base of the fire, where the source of the fire is, trapping it, and preventing it from further reacting with air in a combustion reaction. Also, the short burst creates a strong wind that forces the flame to blow out.
Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x Distance 0 J 15 J 30 J 60 J.
Answer:
15 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 30 × 0.5 = 15
We have the final answer as
15 JHope this helps you
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
WORK DONE:The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
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Which is NOT one of the four principals of Dalton’s atomic theory?
A. Atoms of one element are identical while atoms of different elements are different
B. Electrons orbit the nucleus in energy levels
C. Elements are made of particular called atoms
Answer:
Your answer would be letter B. Electrons orbit the nucleus in energy level.
Explanation:
Hope it helps..
Just correct me if I'm wrong, okay?
But ur welcome!!
(;ŏ﹏ŏ)(◕ᴗ◕✿)
Answer:
B
Explanation:
Dalton's 4 principles did not involve discussion of the electrons or their orbits.
Calculate the inductance of a flat wire loop of radius r. assume the wire has a radius r= 0.010r, and that the contribution to the inductance from the magnetic field inside the wire is negligible?
The inductance of the flat wire loop is given by: L = μ₀N²πr²/2
To calculate the inductance of a flat wire loop of radius r, we can use the formula for the inductance of a circular loop, which is given by L = μ₀N²A/2R, where μ₀ is the permeability of free space, N is the number of turns, A is the area enclosed by the loop, and R is the mean radius of the loop.
In this case, we are assuming that the contribution to the inductance from the magnetic field inside the wire is negligible. This means that we can treat the wire as if it were hollow and only consider the magnetic field outside the wire.
Given that the wire has a radius r = 0.010r, we can determine the mean radius of the loop by subtracting the inner radius of the wire from the outer radius of the loop. The mean radius is therefore r - 0.010r = 0.990r.
Since the wire is flat, the area enclosed by the loop is simply the area of a circle with radius 0.990r, which is A = π(0.990r)².
Now we can plug the given values into the formula for inductance and calculate the result.
L = μ₀N²A/2R
= μ₀N²π(0.990r)²/2(0.990r)
Simplifying the equation, we find that the inductance of the flat wire loop is given by:
L = μ₀N²πr²/2
In conclusion, the expression μ₀N²πr²/2 represents the inductance of the flat wire loop with a radius r, considering the wire's radius as 0.010r and neglecting the contribution to inductance from the magnetic field inside the wire.
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The table below shows some common animals and their hearing range in Hertz (Hz). Animal Hearing Range in Rate of Vibrations per Seconds (Hz) : Human: 20–20,000 Bat: 2,000–110,000 Elephant: 16–12,000 Dolphin: 90–105,000 Chicken: 125–2,000 Which animal has a hearing range most similar to that of a Human? *
A. Bat
B. Chicken
C. Dolphin
D. Elephant
Answer:
D
Explanation:
If you list and compare, the elephants hearing range is the closest to a humans.
Humans: 20-20,000
Elephant: 16-12,000
While the others are either too much more or less than a humans.
Bat: 2,000-110,000
Dolphin: 90-105,000
Chicken: 125-2,000
-4.3 light years what is the value of the 3??
Answer:
A light-year is a unit of distance. It is the distance that light can travel in one year. Light moves at a velocity of about 300,000 kilometers (km) each second. So in one year, it can travel about 10 trillion km. More p recisely, one light-year is equal to 9,500,000,000,000 kilometers
Two helium isotopes fuse to form beryllium, as shown below. The mass of beryllium is 2.73 x 107 kg less than the combined mass of the two helium atoms. How much energy was produced during this reaction? The speed of light is 3 x 108 m/s. Show your work. Use E = mc².
3/2He+ 4/2He → 7/4Be
A chemical element with the symbol Be and atomic number 4 is known as beryllium. Beryllium is a solid at room temperature and is categorized as an alkaline earth metal. The molar mass of beryllium (atomic number 4) is 9.012 g/mol. Accordingly, if all 6.22x1023 Beryllium atoms were put together in a mole, they would weigh 9.012g on a triple beam balance.
Explain about the mass of beryllium?
The atomic mass unit serves as the unit of measurement for mass (amu). A mass unit of an atom is 1.66 x 10-24 gram. The mass of one nucleon, which can be either a single proton or neutron, is roughly equal to one unified atomic mass unit, which is numerically equivalent to 1 g/mol.
In the aircraft industry in particular, beryllium is employed in gears and cogs. A silvery-white metal is beryllium. It has a low density and is relatively soft. Gyroscopes, springs, electrical contacts, spot-welding electrodes, and non-sparking tools all use beryllium in alloys with copper or nickel.
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Which potatoes when peeled produce the most peelings?
A. 10 kg of large potatoes
B. 10 kg of small potatoes
C. They both produce the same amount
Assuming that both types of potatoes have the same skin-to-flesh ratio, 10 kg of small potatoes would produce more peelings than 10 kg of large potatoes.
This is because small potatoes have a higher surface area-to-volume ratio than large potatoes, so there is more skin per unit weight. As a result, more peelings would be produced when peeling small potatoes compared to large potatoes.
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The intensity of sound is measured on the decibel scale, db. The equation db=10logi represents the decibel level, where i is the ratio of the sound to the human hearing threshold. A noise registers a decibel level of 29. Which equation could be used to find how many times greater the noise is than the human hearing threshold?.
The noise level is I=1029 I=log2 times over the threshold of human hearing.
How is dB measured?Logarithmic scales are used to measure decibels. This is a method of accounting for or measuring an exponentially growing quantity. For instance, every 10 dB increase in decibels corresponds to a 10-fold increase in sound pressure level (SPL).
What is the formula for sound frequency?The formula for sound speed is vw=f, where f is sound frequency and is sound wavelength. The distance between adjacent, identical wave components, such as between adjacent compressions, determines a sound's wavelength.
What is frequency measured in?The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.
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88) A giant star radiates energy at the rate of 3.0 × 1030 W, and its surface temperature has been measured to be 3000 K. Assuming that it is a perfect emitter, what is the radius of this star?(σ = 5.67 × 10-8 W/m2 ∙ K4)
A) 7.8 × 1010 m
B) 8.7 × 1010 m
C) 1.4 × 1010 m
D) 1.9 × 1011 m
E) 2.3 × 1011 m
According to the question the radius of the star is 8.7 × 10¹⁰ m..
What is radius?Radius is a term used to describe the distance from the center of a circle to any point on its circumference. It is also the length of a line segment extending from the center of a circle to any point on its circumference. The radius is an important tool in geometry, allowing for calculations of area and circumference of a circle, as well as the measurement of angles and arcs.
The Stefan-Boltzmann Law states that the total energy emitted by a blackbody radiator is proportional to the fourth power of its temperature.
E = σT⁴
We can rearrange this equation to solve for the radius of the star.
R² = E / (4πσT⁴)
Plugging in the given values, we get:
R² = (3.0 × 1030 W) / (4π × 5.67 × 10-8 W/m² ∙ K4 × 3000 K)
R² = 8.7 × 1010 m
Therefore, the radius of the star is 8.7 × 10¹⁰ m.
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If equipment draws a current of 300 amperes, what is the approximate opening time of the ocpd?
The approximate opening time of the Overcurrent Protection Device (OCPD) can be determined based on the current drawn by the equipment. However, to provide a more accurate answer, we need to know the type of OCPD being used.
Assuming that the OCPD is a standard circuit breaker, the opening time can vary depending on the specific breaker. Generally, circuit breakers have a time-current characteristic curve that defines their tripping time based on the magnitude of the current.
To determine the approximate opening time, we can refer to the manufacturer's data or standard time-current curves. These curves provide a graphical representation of the tripping time for different current values.
For example, if we assume that the circuit breaker has a tripping time of 0.1 seconds at 100 amperes, we can estimate the opening time for a current of 300 amperes by interpolating between the provided data points.
Using linear interpolation, we can calculate the approximate opening time as follows:
- The time difference between 100 amperes and 300 amperes is 200 amperes.
- The time difference between 0.1 seconds and the unknown opening time is t seconds.
- The ratio of the current difference to the time difference is constant: 200 amperes / 0.1 seconds = 300 amperes / t seconds.
- Solving for t, we get t = (0.1 seconds) * (300 amperes / 200 amperes) = 0.15 seconds.
Therefore, based on this estimation, the approximate opening time of the OCPD for a current draw of 300 amperes is 0.15 seconds.
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two tiny spheres of mass 5.30 mg carry charges of equal magnitude, 62.0 nc , but opposite sign. they are tied to the same ceiling hook by light strings of length 0.530 m. when a horizontal uniform electric field e that is directed to the left is turned on, the spheres hang at rest with the angle θ between the strings equal to 58.0∘
To solve this problem, we can use the concept of electrostatic equilibrium, where the electric force on the charged spheres is balanced by the force of gravity and tension in the strings.
Where q is the charge on each sphere and E is the magnitude of the electric field. Since the charges on the spheres are equal in magnitude but opposite in sign, the electric forces will have the same magnitude but opposite directions.In equilibrium, the electric force on each sphere and the gravitational force are balanced by the tension in the strings. Thus, we can set up the following equations,Evaluating this expression will give you the magnitude of the electric field (E).
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Calculate the discharge, in ft3/min, m3/min, and million-gallon/day (MGD) of the stream (10,000-mile long) according to the given measurement: cross sectional, width and depth of 1-mile and 80-ft, respectively, and at the stream-velocity of 9-ft/min.
The discharge of the stream is approximately 3,801,600 ft³/min, 107,701.6 m³/min, and 0.508 MGD.
To calculate the discharge of the stream, we can use the formula:
Discharge = Cross-sectional area × Velocity
First, let's calculate the cross-sectional area:
Cross-sectional area = Width × Depth
Given that the width is 1 mile (5280 ft) and the depth is 80 ft, we have:
Cross-sectional area = 5280 ft × 80 ft = 422,400 ft²
Next, we need to convert the velocity from ft/min to ft³/min. Since the velocity is given as 9 ft/min, the discharge velocity is equal to the cross-sectional area multiplied by the velocity:
Discharge velocity = Cross-sectional area × Velocity = 422,400 ft² × 9 ft/min = 3,801,600 ft³/min
To convert the discharge to other units, we can use the following conversions:
1 m³ = 35.3147 ft³
1 million gallons = 3,068.88 acre-feet
Now, let's perform the conversions:
Discharge in m³/min = Discharge velocity / 35.3147 = 3,801,600 ft³/min / 35.3147 = 107,701.6 m³/min
Discharge in million-gallon/day (MGD) = (Discharge velocity / 7.481) / 1,000,000 = (3,801,600 ft³/min / 7.481) / 1,000,000 = 0.508 MGD
Therefore, the discharge of the stream is approximately 3,801,600 ft³/min, 107,701.6 m³/min, and 0.508 MGD.
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Please help ASAP -multiple choice- will give brainliest
Answer:
C. An article written by a scientist
Explanation:
Research-based original articles written by a scientist can act as a primary source of information. Textbooks, dictionaries and encyclopedias are generally classified as secondary sources and are rarely primary sources.
Can someone please help me?
Answer: C
Explanation: I been there before trust meh...
How are particles in liquids, solids, and gases the same? How are they different?
Answer:
Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
Explanation:
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What is Einstein’s equation ?
He has derived a lot of equations but the most common one is E=mc^2
(Energy=Mass×Speed of light squared)
John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s
The horizontal component of the velocity is equal to: D. 15 m/s.
Given the following data:
Velocity = 30 m/sAngle = 60°To determine the horizontal component of the velocity:
The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.
Mathematically, the horizontal component of velocity is given by the formula:
\(V_x = Vcos(\theta)\)
Substituting the given parameters into the formula, we have;
\(\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5\)
Horizontal component, Vx = 15 m/s
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Answer the following question after observing the given diagram.
(a) Ehich type of simple machije is it?
(b) Find the velocity ratio , mechanical advantage and efficiency of the machine?
(a) The type of simple machine given in image is wheel and axle.
(b.i) The velocity ratio of the machine is 5.
(b.ii) The mechanical advantage of the machine is 4.
(b.iii) The efficiency of the simple machine is 80%.
What type of simple machine is in the image?(a) The type of simple machine given in image is know as the wheel and axle, as we can see the wheel with bigger and axle with smaller radius.
(b.i) The velocity ratio of the machine is calculated by applying the following formula;
V.R = R/r
V.R = 20 cm / 4 cm
V.R = 5
(b.ii) The mechanical advantage of the machine is calculated as follows;
M.A = Load / Effort
M.A = 200 N / 50 N
M.A = 4
(b.iii) The efficiency of the simple machine is calculated as follows;
E = M.A / V.R x 100%
E = 4 / 5 x 100%
E = 80%
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100 point question!! A driver begins to brake when her car is traveling at 15.0 m/s, and the car comes to a stop 4.0 s later. How much farther does the car go after the driver begins to brake, assuming constant acceleration?
Answer:
30 m
Explanation:
Let's list out the known variables that we are given in this question.
v₀ = 15 m/sv = 0 m/s t = 4 sWe are trying to solve for displacement in the x-direction.
Δx = ?Find which constant acceleration equation contains all 4 of these variables.
\(\displaystyle \triangle x = \Big (\frac{v+v_0}{2} \Big ) t\)Plug the known values into the equation and solve for delta x.
\(\displaystyle \triangle x = \Big (\frac{0+15}{2} \Big ) \cdot 4\) \(\displaystyle \triangle x = \Big (\frac{15}{2} \Big ) \cdot 4\) \(\displaystyle \triangle x =\frac{60}{2}\) \(\triangle x = 30\)The car goes 30 m after the driver begins to brake.
Answer:
the answer should be 30 m
Explanation:
have a good day
When palladium-102, 102/ 46Pd, undergoes β+ decay, the daughter nucleus contains When palladium-102, undergoes decay, the daughter nucleus contains
47 protons and 36 neutrons.
45 protons and 57 neutrons.
55 protons and 47 neutrons.
57 protons and 45 neutrons.
When palladium-102, 102/46Pd, undergoes β+ decay, the daughter nucleus contains 47 protons and 36 neutrons, which is ruthenium-102, 102/47Ru.
The decay equation for this process is:
102/46Pd -> 102/47Ru + β+ + νe
During the decay, a proton in the palladium-102 nucleus undergoes a transformation, changing its charge from positive to neutral. This is accompanied by the emission of a positron, which is a positively charged electron, and a neutrino, which is a neutral subatomic particle.
The resulting daughter nucleus, ruthenium-102, has 47 protons, reflecting the increase in proton count due to the conversion, and 36 neutrons, maintaining the overall mass number of 102. This β+ decay process plays a significant role in nuclear physics and radioactive decay, contributing to the understanding of fundamental particles and the stability of atomic nuclei. Hence, the correct option is 47 protons and 36 neutrons.
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if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
Answer:
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