explain the moral dilemma antigone faces. what is the essence of any moral dilemma? what are the moral and legal consequences of her choice?

The letters "NM" on the outside of Romex wire stand for "Non-Metallic".

Romex is a type of electrical wiring that is commonly used in residential construction. It is a brand name for a specific type of cable that contains multiple wires inside a sheathing. The sheathing is made of a non-metallic material, which is why the wire is referred to as "non-metallic". The use of non-metallic sheathing provides insulation and protection for the wires inside, as well as making it easier to handle and install.

NM wire is commonly used for interior wiring applications, such as lighting and outlets. It is important to note that the use of electrical wiring should always be done by a licensed electrician and should meet local building codes and safety standards. So therefore The letters "NM" on the outside of Romex wire stand for Non-Metallic.

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Answer:

Negative 3

Explanation:

Bc scientific notation is the zeros either ahead or behind the actual numbers

Answer:

-3

Explanation:

Answer:

6.15 km/h

Explanation:

distance/time

Answer:

1.5 g/cm

3

Let d be the density of fluid.

So , Initial reading of balance, F

1

=30dg N

After the level reaches 50cm

3

Final reading of balance , F

2

=50dg N

Given that difference between final and initial reading is 30g

i.e, F

2

−F

1

=30 g

⟹50dg−30dg=30g

⟹20dg=30g

⟹d=

20g

30g

⟹d=1.5g/cm

3

So, density of fluid is 1.5g/cm

3

This statement suggests that the ice undergoes a phase change from solid to liquid, indicating heat transfer.

All of the ice will melt, and the final temperature of the mixture will be 10°C.

If the surroundings were at a lower temperature than the ice, heat would flow from the ice to the surroundings, causing the ice to freeze instead of melt.

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Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec

Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

\(x = x_{o}+v_{o,x} \cdot t\)

\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}\)

Where:

\(x_{o}\), \(y_{o}\) - Initial horizontal and vertical position of the projectile, measured in meters.

\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical speed of the projectile, measured in meters per second.

\(t\) - Time, measured in seconds.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(x\), \(y\) - Current horizontal and vertical position of the projectile, measured in meters.

Given that \(x_{o} = 0\,m\), \(y_{o} = 80\,m\), \(v_{o,x} = 360\,\frac{m}{s}\), \(v_{o,y} = 0\,\frac{m}{s}\) and \(g = -9.807\,\frac{m}{s^{2}}\), the kinematic equations are, respectively:

\(x = 360\cdot t\)

\(y = 80-4.094\cdot t^{2}\)

(a) If \(y = 0\,m\), the time taken for the projectile to reach the water is:

\(80 - 4.094\cdot t^{2} = 0\)

\(t = \sqrt{\frac{80}{4.094} }\,s\)

\(t \approx 4.420\,s\)

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If \(t \approx 4.420\,s\), the horizontal scope of the projectile is:

\(x = 360\cdot (4.420)\)

\(x = 1591.2\,m\)

The horizontal scope of the projectile is 1591.2 meters.

(c) If \(t = 2\,s\), the height that remains to descend is:

\(y = 80-4.094\cdot (2)^{2}\)

\(y = 63.624\,m\)

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

The light of wavelength 447 nm from a He-Ne laser passes through the circular aperture and  observed on the screen 2.0 m behind the aperture. The diameter of the aperture is  8.2 × 10⁻⁶ m.

The expression is as follows :

Diameter, D = 2.44 × d × λ / D'

Where

λ = wavelength = 447 × 10⁻⁹  m

d = 2 m

D' = 26.6 cm = 0.266 m

D = 2.44 × d × λ / D'

D = ( 2.44 × 447 × 10⁻⁹  × 2 ) / 0.266

D = 8.2 × 10⁻⁶ m

Thus , the diameter of the aperture is  8.2 × 10⁻⁶ m.

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Answer:

Sink

Explanation:

The normal density of water is 1 g/cm3.  Since the rock has a higher density of 1.72g/cm3, it will sink in water.

Answer:

Photoelectric Effect

Explanation:

Photoelectric Effect is a phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation.

The internal conflict in the passage is about how Maggie feels about Dee's arrival. Maggie is feeling insecure about her scars and how Dee will react to her seeing her.

The correct answer to this question is option B.

Maggie is self-conscious of her appearance due to the burns on her skin. Her scars resulted from a house fire in which she was injured while trying to save some family heirloom quilts. On the other hand, Dee is confident and proud of her African heritage.

She changed her name to Wangero, saying that Dee no longer represents her real personality. Dee has also gained a formal education, moved to a big city, and embraced new ideas while rejecting her past, which has left Maggie feeling left behind in rural life.

In conclusion, the passage's internal conflict is Maggie's insecurity about her scars and how her sister Dee will react to seeing her.

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Answer:

1) q₃ is approximately -7.58 nC

2) The direction of the net force on 'q₃' is the negative '-' direction

3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

Explanation:

1) The force, 'F', between two charged spheres is given as follows;

\(F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}\)

The net force acting on the point charge, 'q₃', is given as follows;

\(F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}\)

By substituting the given values, we have;

\(F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}\)

\(3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}\)

\(\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}\)

K = 9 × 10⁹ N·m²·C⁻²

\(\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC\)

q₃ ≈ -7.58 nC

2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin

The net force's direction on q₃ will be in the '-' direction

3) For zero net force, we have;

The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m

Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1

By substitution, we have;

\(0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)\)

\(\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}\)

From which we have;

\(\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}\)

(r₁)²×4.10 = 2.20 × (0.57 - r₁)²

From the above equation, we have;

95,000·r₁²+ 125,400·r₁-35739 = 0

Solving, using a graphing calculator we get;

r₁ ≈ 0.241 or r₁ ≈ -1.561

Where, 'r₁', is measured from 'q₂', therefore, we have;

r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881

Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero

Answer and Explanation:

distance will be 2×3.14 (pie)×r

displacement will be 2r (diameter)

the motion is uniform circular motion as the object is moving in a circular path with uniform motion

Answer:

distance= pi*r=π×r²

displacement=2r

Answer: The force of gravity

Answer:Chemical energy

Explanation:, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic.

Answer:

Hope this helps

Explanation:

Chemical energy, Energy stored in the bonds of chemical compounds Chemical energy may be released during a chemical reaction, often in the form of heat such reactions are exothermic. The chemical energy in food us converted by the body into mechanical energy and heat .

Answer:

$10 a g

Explanation:

Answer:

As The mass of the beach ball is having lowest magnitude when compared with the other balls given so when apply the same magnitude of force to all the balls then the beach ball due to its lighternessand also its inertia of rest would not resist the force so much so when you apply the force to this ball it would starts to roll and covers the maximum diatance whwn compared with the other ball only in the condition when same magnitude of force applied.Thats this ball would do more work than the other ball.The mass also influences the velocity carried by the body and also the kinetic energy possessed by the body. More the force applied more the distance it would cover

Hope it helps

The far point of the eye is approximately 1.54 meters.

To find the far point of an eye follow these steps:

1. Determine the focal length of the lens: The optical power (P) of a lens is the inverse of its focal length (f) in meters. So, P = 1/f or f = 1/P.

2. Calculate the focal length: Given the optical power of -0.65 D, the focal length can be calculated as f = 1/-0.65 ≈ -1.54 meters. A negative sign indicates that the lens is a diverging lens, which is commonly prescribed for myopia or nearsightedness.

3. Find the far point: For a person with myopia, the far point is the distance at which they can see clearly without any corrective lenses. The far point can be found using the lens formula, which is 1/f = 1/u + 1/v, where 'f' is the focal length, 'u' is the object distance (distance of the object from the lens), and 'v' is the image distance (distance of the image formed from the lens).

Since the far point is the maximum distance at which the person can see clearly without corrective lenses, the image formed by the lens should be at infinity (v = ∞). So the formula becomes:

1/f = 1/u + 1/∞
1/f = 1/u

4. Calculate the object distance (u): Since we know the focal length (f), we can calculate the object distance (u) using the formula:

u = 1/(1/f) = 1/(1/-1.54) ≈ -1.54 meters

So, the far point of the eye is approximately 1.54 meters. Note that the negative sign indicates that the far point is a virtual point located behind the lens.

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Answer: the thing that brings you life- h2o- idrk the question but if this helps your welcome ^-^have a good day

Explanation:

Answer:

B. chromosphere

Explanation:

Immediately above the Sun's photosphere is the _______, which is the Sun's lower atmosphere. A. core B. chromosphere C. corona D. solar wind

The Answer to the question: The sun emits electromagnetic waves at many frequencies, but mostly in the infrared, visible, and ultraviolet spectrums. What kind of energy is this?  Is......     radiant

The energy emitted by sun in the form of electromagnetic waves is the radiant energy. So, the second option is correct.

Electromagnetic wave is defined as the waves that are formed as a result of the vibrations between electric and magnetic fields.

Here,

The sun emits electromagnetic waves at many frequencies, but mostly in the infrared, visible and ultraviolet spectrums.

The energy from the sun that reaches are in the form of solar radiations. These solar radiations carry a large amount of energy and are a part of electromagnetic energy spectrum.

The solar radiation consists of  radiations of 40% at the wavelengths of infrared, 50% at the wavelength of visible light and 10% at the wavelength of ultraviolet waves.

The ultraviolet radiations has an important role in the formation of earth's upper atmosphere.

These radiations are responsible for the heating and temperature effects on the earth.

Hence,

The energy emitted by sun in the form of electromagnetic waves is the radiant energy.

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A bowling ball of mass 7.25 kg and radius 10.8 cm rolls without slipping down a lane at 3.10 m/s. Then the total mechanical kinetic energy of a bowling ball is 48.8 J.

Given that, mass = 7.25 kg

Radius = 10.8 cm = 10.8/100 m = 0.108 m

Velocity = 3.1 m/s

The total mechanical kinetic energy is nothing but the sum of kinetic energy due to rotation and kinetic energy due to translation. It can be written as

KE = 1/2* m* v² + 1/2* I*ω²

where, I is the moment of inertia of the bowling ball about its centre

ω is the angular velocity

As the ball is in rotation, v = r * ω

And I = 2/5 * m * r²

So, the total mechanical kinetic energy is

KE = 1/2* m* v² + 1/2* I*ω² = 1/2* m* v² + 1/5* m * v²

⇒ 7/10 m * v² = 7/10 * 7.25 * 3.1² = 48.77 J ≈ 48.8 J

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Answer:

Explanation:

Given: q₁ = q₂,

F= 10 N,

distance between two charges, r = 30000 m.

We have, \(F = \frac{q_{1} q_{2} }{4\pi Er^{2} }\)

Hence, \(q_{1} q_{2} =F * 4\pi *E *r^{2}\)

E (epsilon) =\(8.85 * 10^{-12} C^{2} /Nm\)

Substituting the values, we have,

\(q_{1} q_{2} = 1 C\)

Hence \(q_{1} = q_{2} = 0.5 C\)

Answer:

B.) decreased attention span

Explanation:

took the test and got 100%