Explain the difference between the reactants and
products of a chemical reaction.
MP

In order to prepare the solution required by this question, we would employ the use of 375mg of protein.

Here we are given the ratio of protein to solution that we wish to achieve. Said ratio is 15mg/ml. This means that there should be 15mg of protein for every ml of solution. Since we have 25ml of the solution, we can multiply these values to reach our answer of 375mg of protein.

Therefore, we can confirm that In order to prepare the solution required by this question, we would employ the use of 375mg of protein.

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Answer:

19

Explanation:

Here,

[Ar] = Argon = atomic no. = 18

4s1 = 1 electron

so 18 + 1 = 19

19 = Potassium (K)

Answer:

\(2.64\text{ L}\)

Explanation:

Assuming that the helium is at standard temperature and pressure (STP), we can use the molar volume of an ideal gas at STP (22.4L) to solve for its volume.

\(\text{Volume} = (\text{number of moles}) \cdot (\text{molar volume at STP})\)

\(V = (0.118\text{ mol}) \cdot (22.4 \text{ L/mol})\)

\(\boxed{V = 2.64\text{ L}}\)

Note that we rounded to 3 significant figures because that is how many significant figures were given by the measurement of helium (0.118 mol).

Answer:

23.3 grams

Explanation:

First we'll need the balanced equation for this equation.

2H₂ + O₂ → 2H₂O

This shows us that we need one mole of O₂ to produce two moles of water.

Now we need to convert grams to moles.

There is 18.01528 g for every mole of water

26.2/18.01528 = 1.454321

There 1.454321 moles of water produced

Remember that two moles of water are produced from a gram of O₂

1.454321/2 = 0.72716

0.72716 moles of O₂ were used

Now convert moles back to grams. There are 31.998 g for every mole of O₂

31.998 x 0.72716 = 23.2677

23.2677 grams of oxygen were used

Answer:

B

Explanation:

Smaller pieces results in a larger surface area, therefore the answer is beaker B.

Answer:

c) H2O and HSO4-

Explanation:

The dehydration of 2-methylcyclohexanol occurs in the presence of H2SO4. Recall that acids are proton donors in solution; the equilibrium shown below is then set up,

H2SO4(aq)  +  H2O(l) ⇄H3O^+(aq) + HSO4^-(aq)

The species H2O and HSO4- are two proton acceptors in the system. According to the Brownstead- Lowry definition, a base is a proton acceptor in solution.

Hence H2O and HSO4- are bases present in the dehydration of 2-methylcyclohexanol.

Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

Answer:

All fungi are Eukaryotic

Explanation:

A fungus is any member of the group of eukaryotic organisms that includes microorganisms such as yeasts and molds, as well as the more familiar mushrooms. These organisms are classified as a kingdom, which is separate from the other eukaryotic life kingdoms of plants and animals.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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Approximately 631.5 liters of dry air at 25°C and 750 torr would need to be processed to produce 150 liters of liquid \(O_2\) -183°C.

To solve this problem, we need to consider the ideal gas law and the molar volume of gases.

First, we can calculate the number of moles of oxygen in 150 L of liquid \(O_2\) at -183°C. To do this, we divide the mass of liquid oxygen by its molar mass:

Mass of liquid oxygen = volume of liquid oxygen * density of liquid oxygen = 150 L * 1.14 g/mL = 171 g

Molar mass of oxygen (O2) = 32 g/mol

Number of moles of oxygen = mass of oxygen / molar mass of oxygen = 171 g / 32 g/mol ≈ 5.34 mol

Since the mole fraction of oxygen in dry air is given as 0.21, we can calculate the total moles of dry air needed to produce 5.34 mol of oxygen:

Moles of dry air = moles of oxygen / mole fraction of oxygen = 5.34 mol / 0.21 ≈ 25.43 mol

Now, we can use the ideal gas law to calculate the volume of dry air at 25°C and 750 torr (convert to atm) that corresponds to 25.43 mol:

PV = nRT

P = 750 torr * (1 atm / 760 torr) ≈ 0.987 atm

V = volume of dry air (unknown)

n = 25.43 mol

R = 0.0821 L·atm/(mol·K)

T = 25°C + 273.15 = 298.15 K

Solving for V:

V = nRT / P = (25.43 mol)(0.0821 L·atm/(mol·K))(298.15 K) / 0.987 atm ≈ 631.5 L

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We can see here that the best fuel is the one that produces the most heat per unit mass. In this case, the fuel that produces the most heat per unit mass is methanol.

Fuel is a substance that is used to produce energy through combustion or other chemical reactions. It is commonly utilized to power various forms of transportation, generate heat or electricity, and operate machinery and appliances.

The results of the experiment are shown below:

Fuel            Mass (g)      Heat produced (J)       Heat per gram (J/g)

Methanol 1.0                          350                   350

Ethanol         1.0                          250                   250

Propane         1.0                          200                   200

Butane         1.0                          150                            150

Pentane         1.0                          100                            100

It is important to note that the results of this experiment are only a measure of the heat produced by the fuels.

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If tadpoles are hatched in stagnant water then they have got a lower survival rate than those hatched in churned & aerated water because the sitting water is higher. Testable via experimenting with tadpoles in unique settings.

Eggs generally hatch in 2-3 weeks, however, this time varies based totally on water temperature. One egg is seen whereas the other embryos are very advanced and are probably near hatching. four. The larval degree tadpole level.

A filter-out, however, can lessen the number of water adjustments in order to be needed. The clear-out must not be so robust that it creates too much current— tadpoles are terrible swimmers. make certain the tadpoles may not be up into the clear out and that they don't should swim constantly.

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If a reaction has a negative ΔG and a positive ΔS, the reaction will be spontaneous at all temperatures.

If a reaction is spontaneous at all temperatures, it implies that the reaction will occur without the need for any external intervention, such as the addition of energy. For a reaction to be spontaneous, it must satisfy the criteria of thermodynamic favorability, which is determined by the change in Gibbs free energy (ΔG) associated with the reaction.

The relationship between ΔG, temperature (T), and the equilibrium constant (K) of a reaction is described by the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

To ensure spontaneity at all temperatures, two conditions must be met:

ΔG must be negative: A negative ΔG indicates a thermodynamically favorable reaction, meaning the products have a lower Gibbs free energy than the reactants. If ΔG is negative, the reaction will proceed spontaneously in the forward direction.

ΔS must be positive: A positive ΔS signifies an increase in the overall entropy of the system. Higher entropy means more disorder, and spontaneous reactions often involve an increase in randomness. When ΔS is positive, it can compensate for the enthalpic term, ΔH, allowing the reaction to proceed spontaneously.

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By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Answer:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Explanation:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Answer: =378.94000053g

Explanation:

I think that explains it

Answer:

d) Evaporation.

Explanation:

The process that converts a solid directly to gas is called Sublimation.

Answer: Well, the volume of the copper is (63.4 - 40.0) * mL = 23.4 * mL

Explanation:

Do you agree? The copper displaces the given volume of water.

Now  ρ Cu =  8.90  ⋅  g  ⋅  c m 3  OR  ρ Cu  =  8.90  ⋅  g  ⋅  m L − 1, i.e.  1 ⋅  m L  ≡  1  ⋅  c m 3

But by definition,  ρ  density  =  mass  volume

And thus  mass  =  ρ  ×  volume  =  8.90  ⋅  g  ⋅  m  L  −  1  ×  23.4  ⋅  m  L

= 208.3 * G

Which example is a liquid at room temperature?

answer : bromine.

Answer:

bromine is liquid at room temperature ️....

So, the mass of each metal in the 70.5 g mixture is: Magnesium: 39.1 g and Silver: 31.4 g.

A reaction, in chemistry, refers to a process in which one or more substances are transformed into new substances with different physical and/or chemical properties. Chemical reactions involve the breaking and forming of chemical bonds between atoms or molecules, resulting in the rearrangement of atoms to create new substances. In a chemical reaction, the reactants are the starting materials that undergo the chemical change, while the products are the substances that are formed as a result of the reaction. The chemical equation represents the reactants and products of a chemical reaction and is balanced to show the conservation of mass and the law of conservation of energy.

Here,

The balanced chemical equation for the reaction between magnesium and silver nitrate is:

Mg + 2AgNO3 → 2Ag + Mg(NO3)2

From the equation, we can see that 1 mole of magnesium reacts with 2 moles of silver nitrate to produce 2 moles of silver and 1 mole of magnesium nitrate.

First, we need to calculate how much silver was produced in the reaction. From the equation, we can see that 1 mole of magnesium produces 2 moles of silver, so:

1 mol Mg = 2 mol Ag

The molar mass of magnesium is 24.31 g/mol, so the number of moles of magnesium in the sample is:

=17.6 g Mg / 24.31 g/mol

= 0.724 mol Mg

Since 1 mole of magnesium produces 2 moles of silver, the number of moles of silver produced in the reaction is:

=0.724 mol Mg × 2 mol Ag / 1 mol Mg

= 1.448 mol Ag

The molar mass of silver is 107.87 g/mol, so the mass of silver produced in the reaction is:

=1.448 mol Ag × 107.87 g/mol

= 156.0 g Ag

Now, we can calculate the mass of magnesium that reacted in the reaction:

=17.6 g Mg × (156.0 g Ag / 70.5 g total metal)

= 39.1 g Mg

Therefore, the mass of silver in the 70.5 g mixture is:

=70.5 g total metal - 39.1 g Mg

= 31.4 g Ag

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The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.

Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.

Balanced reaction equation

2CH₄(g)⇌C₂H₂(g)+3H₂(g)

The initial concentration of the CH₄ = 0.093 M

The equilibrium concentration of the H = 0.017 M

Equilibrium constant = ?

Let's make the ice table

2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)

0.093 M 0 0

-2x +x +3x

0.093-2x x 0.017 M

3x = 0.017 M

Therefore, x =0.017 M /3 = 0.00567 M

Therefore, the equilibrium concentration of CH₄ =

0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M

Equilibrium concentration of the C₂H₄ = x = 0.00567 M

Let's write the equilibrium constant expression

Kc= [C₂H₄[H2]³/[CH₄]²

Let's put the values in the formula

Kc= [0.00567][0.017]³/[0.0817]²

Kc= 4.17 x 10⁻⁶

Therefore, the equilibrium constant is 4.17 x 10⁻⁶.

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer:

2.5 g

Explanation:

The balanced chemical equation for the reaction is:

CH4 + 2O2 → CO2 + 2H2O

From the equation, we can see that for every 1 mole of methane reacted, 2 moles of water are produced. Therefore, we need to first calculate the number of methane and oxygen moles in the reaction mixture.

The molar mass of methane is 16.04 g/mol, so the number of moles of methane present is:

2.41 g / 16.04 g/mol = 0.15 mol

The molar mass of oxygen is 32.00 g/mol, so the number of moles of oxygen present is:

4.6 g / 32.00 g/mol = 0.14 mol

We can see insufficient oxygen to react completely with all of the methane, so oxygen is the limiting reagent. To determine the maximum amount of water that can be produced, we need to use the number of moles of oxygen to calculate the number of moles of water produced and then convert that to a mass using the molar mass of water.

The balanced equation shows that 2 moles of water are produced for every 2 moles of oxygen. Therefore, the number of moles of water produced is:

0.14 mol O2 × (2 mol H2O / 2 mol O2) = 0.14 mol H2O

The molar mass of water is 18.02 g/mol, so the mass of water produced is:

0.14 mol H2O × 18.02 g/mol = 2.53 g

Rounding to 2 significant digits, the maximum mass of water that could be produced is 2.5 g.

In a spectrophotometer, both absorbance and transmítanse indicate the amount of light passing through a sample. A high absorbance corresponds to a low transmittance.

What is absorbance?

It is a measure of a substance's ability to absorb light of a specific wavelength. It is equivalent to the reciprocal of the logarithm of the transmittance. The amount of light absorbed by a solution, also known as optical density.

What is Transmittance?

It is the proportion of light energy falling on a body to light energy transmitted through it. In other words, it is the proportion of light flowing through to light incident on the sample, whereas the reflectance is the proportion of light reflected to light incident.

In a spectrophotometer, both absorbance and transmittance indicate the amount of light passing through a sample. A high absorbance corresponds to a low transmittance.

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The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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