Answer:
Explanation:
The equation must be balanced on both sides to show the law of conservation of mass. So, as long as it is equaled, the law is shown.
If gas has a pressure of 954 atm and temp of 728 k and the temp changes to 951 k what is the new pressure ?
We have a change of pressure and temperature. To solve and find the new pressure we will assume that the volume and moles of the gas remain constant, therefore we can apply Gay-Lussac's law which tells us:
\(\frac{P_1}{T_1}=\frac{P_2}{T_2}\)Where,
P1 is the initial pressure of the gas, 954atm
T1 is the temperature of the gas, 728K
T2 is the final temperature, 951K
P2 is the final pressure, =?
We clear P2 and replace the known data:
\(\begin{gathered} P_2=\frac{P_1}{T_1}\times T_2 \\ P_2=\frac{954atm}{728K}\times951K=1246atm \end{gathered}\)Answer: The new pressure will be 1246atm
An aqueous potassium carbonate solution is made by dissolving 7.32 moles of K2CO3 in sufficient water so that the final volume of the solution is 4.80 L . Calculate the molarity of the K2CO3 solution.
According to the concept of molar concentration, molarity of the solution is 1.525 M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
In the given problem, by substituting values in mentioned formula related to moles we get,7.32/4.80=1.525 M.
Thus , the molarity of solution is 1.525 M.
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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."
Here are possible words that can be made from this jumbled word:
Sky: Referring to the atmosphere above the Earth.
Zig: Describing a series of sharp turns or angles.
Text: Referring to written or printed words.
Six: The number following five and preceding seven.
It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.
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HELPPPPP (100 POINTS)
Assume that the water stream is replaced by a stream of CCl4. Predict what would happen in each case.
a. charged acetate strip:
b. charged vinyl strip:
c. Explain your predictions.
Answer:c
Explanation:c
After the square has been drawn and the genotypes have been placed, what is the next step for determining probability
After the Punnett square has been drawn and the genotypes ratio is identified. The next step is to identify the Phenotypic ratio.
What is Punnett square?The Punnett square can be defined as a square diagram that is utilized to find the genotypes of a particular breeding experiment. The diagram of the Punnet square can be used by biologists to determine the probability of an offspring having a definite genotype.
The Punnett square can be defined as a tabular summary of combinations of paternal alleles with maternal alleles. These tables can be used to find the genotypical probabilities of the offspring of a single trait.
The Punnett square is a visual representation in which Phenotypes can be predicted with at least better-than-chance accuracy. But the phenotype can appear for a given genotype and may be influenced by other factors.
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A 17.6 g sample of magnesium reacts with excess silver nitrate to produce silver metal and magnesium nitrate. The reaction is stopped before all of the magnesium metal has reacted. A total of 70.5 g of solid metal is present. Calculate the mass of each metal in the 70.5 g mixture.
So, the mass of each metal in the 70.5 g mixture is: Magnesium: 39.1 g and Silver: 31.4 g.
What is reaction?A reaction, in chemistry, refers to a process in which one or more substances are transformed into new substances with different physical and/or chemical properties. Chemical reactions involve the breaking and forming of chemical bonds between atoms or molecules, resulting in the rearrangement of atoms to create new substances. In a chemical reaction, the reactants are the starting materials that undergo the chemical change, while the products are the substances that are formed as a result of the reaction. The chemical equation represents the reactants and products of a chemical reaction and is balanced to show the conservation of mass and the law of conservation of energy.
Here,
The balanced chemical equation for the reaction between magnesium and silver nitrate is:
Mg + 2AgNO3 → 2Ag + Mg(NO3)2
From the equation, we can see that 1 mole of magnesium reacts with 2 moles of silver nitrate to produce 2 moles of silver and 1 mole of magnesium nitrate.
First, we need to calculate how much silver was produced in the reaction. From the equation, we can see that 1 mole of magnesium produces 2 moles of silver, so:
1 mol Mg = 2 mol Ag
The molar mass of magnesium is 24.31 g/mol, so the number of moles of magnesium in the sample is:
=17.6 g Mg / 24.31 g/mol
= 0.724 mol Mg
Since 1 mole of magnesium produces 2 moles of silver, the number of moles of silver produced in the reaction is:
=0.724 mol Mg × 2 mol Ag / 1 mol Mg
= 1.448 mol Ag
The molar mass of silver is 107.87 g/mol, so the mass of silver produced in the reaction is:
=1.448 mol Ag × 107.87 g/mol
= 156.0 g Ag
Now, we can calculate the mass of magnesium that reacted in the reaction:
=17.6 g Mg × (156.0 g Ag / 70.5 g total metal)
= 39.1 g Mg
Therefore, the mass of silver in the 70.5 g mixture is:
=70.5 g total metal - 39.1 g Mg
= 31.4 g Ag
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Is the chemical equation CH4 +202 + 2H2O + CO2 balanced?
A. No Oxygen is unbalanced
B. Yes all elements are blanaced
C. No Hydrogen is unbalanced
Answer:
I think C
Explanation:
because hydrogen on the right side only have two while on the left side it have 4
Answer:
The answer is A. No Oxygen is Unbalanced
Explanation:
I took the test. You got this.
What is the shape of the hypothetical molecule XY3
Answer:
Trigonal planar
Explanation:
If a hypothetical molecule XY3 has three electron domains as shown and no lone pairs, the molecule will be trigonal planar in shape.
From the valence shell electron pair repulsion theory, the shape of molecules is dependent on the number of electron domains in a molecule and weather those electron pairs are lone pairs or bond pairs.
Since lone pairs cause more repulsion and take up more space around the central atom than bond pairs, bond pairs cause the bond angle and molecular geometry to deviate from that predicted on the basis of the valence shell electron pair repulsion theory.
Finally, remember that in a molecule, electron pairs are placed as far apart in space as possible to minimize repulsion.
How many grams of K are in 3.14 mol of K4C?
Answer:
122.768662
Explanation:
Yolanda is focusing on eccentric contractions during her workout today. How is this MOST likely demonstrated in her workout?
8. What does the term 'sustainable mean? *
Answer:
something that can be maintained over a period of time
Answer:
a balance between meeting today's needs.......
Explanation:
What volume in mL of 0.3000 M NaCl solution is required to produce 0.1950 moles of NaCl
To calculate the volume of 0.3000 M NaCl solution that is required to produce 0.1950 moles of NaCl, we can use the formula: moles = Molarity x Volume
We can rearrange the formula to solve for Volume as follows:Volume = Moles/ Molarity Now, we can substitute the given values and solve for Volume:Volume = 0.1950 moles/0.3000 MVolume = 0.65 L or 650 mLTherefore, the volume of 0.3000 M NaCl solution that is required to produce 0.1950 moles of NaCl is 650 mLFor such more question on moles
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Calculate the numerical value of Kc for
the following reaction if the equilibrium
mixture contains 0.0450 M PCI 3, 0.116
M Cl₂, and 25.8 M PCI 5.
PC 3 (g) + Cl₂ (g) ⇒ PCI5 (g)
(the 5 in PCl is a subscript)
The numerical value of Kc for the given reaction, with the equilibrium mixture containing 0.0450 M PCl3, 0.116 M Cl2, and 25.8 M PCl5, is approximately 4942.03.
To calculate the numerical value of Kc for the given reaction, we need to set up an expression for the equilibrium constant using the concentrations of the species involved.
The balanced equation for the reaction is:
PCl3 (g) + Cl2 (g) ⇌ PCl5 (g)
The equilibrium constant expression, Kc, is given by:
Kc = [PCI5] / ([PCl3] * [Cl2])
Given the equilibrium concentrations:
[PCl3] = 0.0450 M
[Cl2] = 0.116 M
[PCI5] = 25.8 M
Substituting these values into the equilibrium constant expression, we have:
Kc = (25.8 M) / ((0.0450 M) * (0.116 M))
Calculating Kc:
Kc = 25.8 M / (0.00522 M^2)
Kc = 4942.03
Therefore, the numerical value of Kc for the given reaction, with the equilibrium mixture containing 0.0450 M PCl3, 0.116 M Cl2, and 25.8 M PCl5, is approximately 4942.03.
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Write the equation for the equilibrium constant (K) of the reaction studied in this exercise.
2C04 2- (ag) + 2Ht (ag) = CI20, 2- (ag) + H20(1)
The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])
In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.
The reaction being studied involves the following species:
\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)
In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.
It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.
Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.
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How long does it take for a car driving at 10m/s to move 200m?
A.
0.05 seconds
B.
2 seconds
C.
20 seconds
D.
2000 seconds
The time taken by the car driving at 10m/s to move 200m is 20 seconds. The speed of car is 10m/s. Thus option C is correct.
What is speed?Speed is defined as a measurement of the length of time it takes for an object to travel a certain distance.
The SI unit of speed is m/s, and speed is defined as the ratio of distance to time.
A change in speed is an example of acceleration because it is a change in velocity. Acceleration could be for positive or negative. Deceleration is another name for negative acceleration.
There are four types of speed.
Uniform speedVariable speedAverage speedInstantaneous speedSpeed can be expressed as
Speed = Distance / Time
Given, Distance = 200 m
Time = 10 m/s
Speed = 200m / 10m/s
= 20 seconds
Thus, the time taken by the car driving at 10m/s to move 200m is 20 seconds. The speed of car is 10m/s. Thus option C is correct.
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A fly hits a windshield of a truck. The truck exerts a force on the fly, and
the fly exerts an equal and opposite force back on the windshield.
A. Newton’s first law
B. Newton’s second law
C. Newton’s third law
Answer:
A fly hits a windshield of a truck.
Explanation:
newton's first law
think about an inflated balloon and a small bag of marbles that is half its size . which one has more volume explain
The object with more volume is the inflated balloon
Explanation:
Volume is about how much space an object or material occupies; in this context, if the inflated balloon has the double size of the bag of marbles then the balloon has more volume because this is occupying more space.
Moreover, the volume should not be confused with other factors such as mass or weight because it is likely the marbles weight more but this does not imply the marbles have more volume. Also, the balloon contains gas and gases tend to expand and occupy more space, which does not occur with solids such as marbles because these have a defined volume.
Write two half‑reactions to describe each of these metal displacement reactions. Include phase symbols.
Mg(s)+CoBr2(aq)⟶MgBr2(aq)+Co(s)
oxidation half‑reaction:
reduction half‑reaction:
Cu(s)+2AuCl(aq)⟶CuCl2(aq)+2Au(s)
oxidation half‑reaction:
reduction half‑reaction:
In redox reactions, an oxidation half reaction shows the oxusetoon occurring while the reduction half reaction shows the reduction occurring in the overall reaction.
What are redox reactions?Redox reactions are reactions in which oxidation and reduction reactions occur together to the same extent.
A redox reaction can be split into two half oxidation and reduction reactions.
The half reactions of the given reactions are shown below:
Overall reaction;
\(A. Mg(s) + CoBr_2(aq) ⟶ MgBr_2(aq) + Co(s) \\ \)
Oxidation half reaction:
\(Mg (s) ---> Mg ^{2+}(aq)\)
Reduction half reaction:
\(Co^{2+} (aq) ---> Co (s)\)
B. Overall reaction
\(Cu(s) + 2AuCl(aq) ⟶ CuCl_2(aq) + 2Au(s) \\ \)
Oxidation half reaction:
\(Cu(s) ---> Cu^{2+}(aq)\)
Reduction half reaction:
\(2Au^{+}(aq) ---> 2 Au (s)\)
Therefore, redox equations can be spilt into oxidation and reduction half reactions.
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An atom has the electron configuration of 1s22s22p5 how many electrons are in that atom
Answer:
There are \(9\) electrons in this atom.
Explanation:
Electron configuration of this atom: \(1s^2\, 2s^2\, 2p^5\).
The electron orbitals of an atom are denoted as \(1s\), \(2s\), \(2p\), \(3s\), \(3p\), etc. At any given time, an electron in this atom is located in exactly one orbital.
The electron configuration of an atom gives the number of electrons in each orbitals of this atom.
For example, in this atom, the superscript "\(2\)" on the right of "\(1s\)" means that there are two electrons in the \(1s\!\) orbital of this atom. Hence, \(1s^2\, 2s^2\, 2p^5\) would translate to:
The \(1s\) orbital of this atom contains \(2\) electrons.The \(2s\) orbital of this atom contains \(2\) electrons.The \(2p\) orbitals of this atom contain \(5\) electrons.Hence, there would be \(2 + 2 + 5 = 9\) electrons in total in this atom.
What frequency corresponds to an absorption line at 527 nm? A. 5.69 x 1014 Hz B. 3.77 x 10¹4 Hz C. 1.76 x 10¹4 Hz D. 6.71 10¹4 Hz
Taking into account the definition of wavelength, frecuency and propagation speed, the correct answer is option A.: The frequency corresponding to an absorption line at 527 nm is 5.69×10¹⁴ Hz
WavelengthWavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
FrequencyFrequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Propagation speedThe propagation speed is the speed with which the wave propagates in the medium.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.
Frequency in this caseIn this case, you know:
v= 3×10⁸ m/sf= ?λ= 527 nm= 527×10⁻⁹ m (1 nm= 1×10⁻⁹ m)Replacing in the definition of propagation speed:
3×10⁸ m/s= f× 527×10⁻⁹ m
Solving:
f= 3×10⁸ m/s ÷ 527×10⁻⁹ m
f= 5.69×10¹⁴ Hz
In summary, the correct answer is option A.: The frequency corresponding to an absorption line at 527 nm is 5.69×10¹⁴ Hz
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5.712 grams = kilograms
Answer:
0.005712
Explanation:
5.712 grams = 0.005712 kilograms
Answer:
It would be 0.005712
Explanation:
79.1,3-Butadiene molecule contains how many sigma and pi bond
3 sigma and 3 pieee
okok kkk
Net ionic equation for potassium sulfide and magnesium iodide
The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.
To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.
Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):
K2S -> 2K+ + S2-
Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):
MgI2 -> Mg2+ + 2I-
Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):
K+ + I- -> KI
Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):
Mg2+ + S2- -> MgS
Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:
2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS
To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).
Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:
S2- + Mg2+ -> MgS
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ANSWER ASAP FORF BRAINLIEST!!!!!
For this and the following two questions, determine the density of a substance (in g/dL) of a sample with a mass of 8.3 x 10-1 dag and a volume of 4.10 mL. What is the right-most significant figure after performing the calculation in scientific notation?
The density of a substance (in g/dL) of a sample with a mass of 8.3 x 10-¹ dag and a volume of 4.10 mL is 202.44g/dL.
How to calculate density?The density of a substance is the measure of the mass of matter contained by a unit volume.
The density of a substance can be calculated by dividing the mass of the substance by its volume.
According to this question, a substance with a mass of 8.3 x 10-¹ dag has a volume of 4.10 mL. The density can be calculated as follows:
1 dag = 10g0.83 dag = 8.3g 1 millilitre = 0.01 decilitre4.10millitre = 0.041 deciliterDensity = 8.3g ÷ 0.041dL
Density = 202.44g/dL
Therefore, the density of a substance (in g/dL) of a sample with a mass of 8.3 x 10-¹ dag and a volume of 4.10 mL is 202.44g/dL.
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the specific heat capacity of titanium is 0.523j/g c what is the heat capacity of 2.3g of titanium
Answer:
1.2029 J/g.°C
Explanation:
Given data:
Specific heat capacity of titanium = 0.523 J/g.°C
Specific heat capacity of 2.3 gram of titanium = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
1 g of titanium have 0.523 J/g.°C specific heat capacity
2.3 × 0.523 J/g.°C
1.2029 J/g.°C
If a watershed suddenly receives a great deal of rainfall, what will happen to its wetlands and rivers?
Answer:
Depending on the actual amount of water, it's going to overfill.
Explanation:
If your watershed is already one that has a lot of water and is always filled, it's likely that your wetlands and rivers will start to overfill, causing a form of flooding.
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I hope this helps!
-No one
A weather balloon with a volume of 171 L is launched at 20.0°C at sea level, where the atmospheric pressure is 1.00 atm. The balloon
rises to an altitude of 2.00 x 104 m, where atmospheric pressure is 61.0 mmHg and the temperature is 210.0 K. What is the volume of
the balloon at 2.00 × 104 m?
Volume of the balloon at 2.00 × 10⁴ m is 1.52x10³ L
Volume is the three dimensional qualities that is used to measure capacity of solid shape and atmospheric pressure is the air around you has weight and it weighs down everything it touches is called atmospheric pressure
Here given data is
Pi = 1.0 atmosphere = absolute atmospheric pressure
P f = 61.0 mm Hg = atmospheric pressure
= 61.0/760 atmosphere
= 0.0802 atmosphere
Vi = 171 L
T i = 20.0°C = 20+273 = 293 K
T f = 210 K
We have to find volume of the balloon at 2.00 ×10⁴ m =?
Then the formula is
Pi × Vi/T i = P f × V f/T f
1 atm×171 L/293 K = 0.0802× V f/210K
V f = 1.52x10³ L
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In terms of energy, when atoms chemically bond to form a stable compound:_____.
A. Energy is released.
B. Energy can either be released or consumed depending upon the bond formed.
C. Energy is transferred from one atom to another.
D. Energy is consumed.
Answer:
A. Energy is released
Explanation:
Energy is only released when chemical bonds are formed.
. 2.514g Ca, 1.004g O empirical formula
The empirical formula of the given compound is \(CaO\).
A chemical compound's empirical formula in chemistry is the simplest whole number ratio of atoms within a molecule.
Given:
Mass of Ca = 2.514g
Mass of O = 1.004g
Molar mass of Ca = 40.078g/mol
Molar mass of O = 15.999g/mol
To find:
Empirical formula = ?
Formula:
Empirical formula = Moles of Ca : Moles of O
Calculations:
No. of moles of Ca = 2.514 / 40.078
n of Ca = 0.06273 moles
No. of moles of O = 1.004 / 15.999
n of O = 0.06275 moles
Divide both by the lowest no. of moles
n of Ca : n of O = 1 : 1
Empirical formula = \(CaO\)
Result:
\(CaO\) is the empirical formula of the compound.
The complete question is:
In an experiment, a 2.514 g sample of calcium was heated in a pure stream of oxygen, and was found to increase in mass by 1.004 g. Calculate the empirical formula for the given compound.
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What are colloidal suspensions?
Answer:
The term colloidal suspension refers unambiguously to the overall mixture (although a narrower sense of the word suspension is distinguished from colloids by larger particle size). A colloid has a dispersed phase (the suspended particles) and a continuous phase (the medium of suspension).
Explanation: