explain how sodium chloride is formed​

Answer:

True

Explanation:

Higher temperature will have greater volumes so the density will be less.

Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

INFORMATION:

We know that:

- pure water boils at 99.8 degrees celcius

And we must calculate the expected elevated boiling point of a solution of 2.50g of CaCl2, in 50.0mL (i.e., 50.0g) of H2O

STEP BY STEP EXPLANATION:

To calculate it, we need to use that:

Boiling point of solution = boiling point of pure solvent + boiling point elevation (ΔTb)

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation.

Where,

- i is the Van’t Hoff factor

- Kb is the ebullioscopic constant

- m is the molality of the solute

From given information, we know that:

- i = 3

Now, the ebullioscopic constant (Kb) is often expressed in terms of °C * kg * mol^-1. The value of Kb for water is 0.512.

So, kb = 0.512 °C * kg * mol^-1

Then, we must calculate the molality

So, m = 0.45 mol/kg

Replacing the values in the formula for ΔTb

Finally, the expected elevated boiling point of the solution would be

ANSWER:

The expected elevated boiling point of the solution is 100.49 °C

Answer:

0.086

Explanation:

got it on acellus

The mass of the dry solute recovered from the given data is 0.086 g.  Option C

To determine the mass of the dry solute recovered, we need to subtract the mass of the boat from the mass of the boat with the dry solute.

Given the data provided:

Boat Mass: 0.730 g

Boat + Solution: 0.929 g

Boat + Dry: 0.816 g

To find the mass of the dry solute, we subtract the boat mass from the boat + dry mass:

Mass of Dry Solute = (Boat + Dry) - (Boat Mass)

Mass of Dry Solute = 0.816 g - 0.730 g

Mass of Dry Solute = 0.086 g

Therefore, the correct answer is c) 0.086 g.

The mass of the dry solute recovered from the given data is 0.086 g. It is important to note that the mass of the dry solute is obtained by subtracting the mass of the boat from the mass of the boat with the dry solute, as the boat mass represents the weight of the empty boat or container used in the experiment.

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5 valence electrons are provided by nitrogen to make the lewis structure of NH₃

The nitrogen atom provide 5 electrons and each of the three hydrogen atoms has 1 electron. So the total number of electrons for ammonia will therefore be 8.

In the Lewis structure of ammonia, Nitrogen is present in center and the three hydrogen atoms are present and bonded at sides of nitrogen as indicated in image  Nitrogen also has a lone pair above it that is the reason why ammonia act as a Lewis base. Ammonia has tetrahedral geometry due to four pairs of electrons .

The lone pair makes space for itself by pushing the three hydrogen atoms together a little and the H-N-H bond angles are slightly less (106.6°) than the ideal tetrahedral angle of 109.5°.

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The new molarity after dilution is approximately 6.375.

The amount of a solution is gauged by its molarity. It is described as the quantity of solute in a solution measured in moles per liter. M represents molarity in a symbol.

The dilution equation is as follows:

\(M^1V^1 = M^2V^2\)

Where

Substituting the given values, we get:

\(M^1 = 4.5 MV^1 = 1.7 LV^2 = 1.2 LM^2 = ?\)

Using the equation for dilution, we can solve for M2:

\(M^1V^1 = M^2V^2\)

4.5 M × 1.7 L =\(M^2\) × 1.2 L

7.65 = 1.2\(M^2\)

\(M^2\) = 7.65 / 1.2

\(M^2\)= 6.375 M

Therefore, the new molarity after dilution is approximately 6.375.

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Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

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Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

The net ionic equations of the reactions are;

3Mn^3+(aq) + 4PO4^3-(aq) ----> Mn3(PO4)4(s)

Pd^2+(aq)  +  S^2-(aq) ----> PdS(s)

A net ionic equation is a chemical equation that shows only the species that participate in a reaction and contribute to the formation of a product or the consumption of a reactant.

It excludes any spectator ions that do not undergo a chemical change. In other words, it shows the actual chemical species that are involved in the reaction.

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We can define a quantity called the equilibrium constant \(K_{c}\) based on the concentrations of all the different reaction species at equilibrium, which is also sometimes written as \(K_{eq}\) or K.

Because the equilibrium constant describes the molar concentrations, at equilibrium for a specific temperature, the c in the subscript stands for concentration \(\frac{mol}{L}\).

At equilibrium, the equilibrium constant can tell us whether the reaction has a higher concentration of products or reactants. We can also use \(K_{c}\) to see if the reaction has already reached equilibrium.

If any of the reactants or products are gases, the equilibrium constant can also be expressed in terms of the partial pressure of the gases. We typically use that value as \(K_{p}\) to distinguish it from the equilibrium constant when using molar concentrations \(K_{c}\).

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The sorted order of the given chemical species by reducing power is:

Na(s)

Al(s)

Br(aq)

Ag(s)

To determine reducing power the Therefore, the sorted order of the given chemical species by reducing power is:

Na(s)

Al(s)

Br(aq)

Ag(s) of chemical species, we need to consider their ability to undergo oxidation, which involves losing electrons. The species that can readily donate electrons are strong reducing agents and have high reducing power. Let's analyze each species:

Br(aq) (Bromide ion in aqueous solution):

Bromide ion can be oxidized to bromine (Br2) or other higher oxidation states. It acts as a reducing agent by donating electrons to substances with higher reduction potentials.

Na(s) (Sodium metal):

Sodium metal is a strong reducing agent. It can easily donate electrons to other species in chemical reactions, leading to oxidation of sodium to sodium ions (Na+).

Al(s) (Aluminum metal):

Aluminum metal is also a strong reducing agent. It readily donates electrons in reactions, resulting in oxidation of aluminum to aluminum ions (Al3+).

Ag(s) (Silver metal):

Silver metal is not a strong reducing agent compared to sodium and aluminum. It has a relatively higher reduction potential and is less likely to donate electrons in reactions.

Based on the analysis, we can sort the species in terms of reducing power from highest to lowest:

Highest reducing power: Na(s) > Al(s) > Br(aq) > Ag(s)

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The new volume of the balloon at 17°C and 0.8 atm is approximately 434.5 mL.

The combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law.

It is expressed as:

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)

Given that:

Plug the given values into the combined gas law formula and solve for the final volume.

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\P_1V_1T_2 = P_2V_2T_1\\\\V_2 = \frac{P_1V_1T_2}{P_2T_1} \\\\V_2 = \frac{1.0atm\ *\ 350mL\ * \ 290.15K}{0.8atm\ *\ 292.15K } \\\\V_2 = 434.5\ mL\)

Therefore, the final volume is approximately 434.5 mL.

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The molecular formula for a compound that contains 69. 5% oxygen and 30. 5% nitrogen is N204.

The molecular formula expresses the number of atoms of each element in one chemical molecule.

The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.

The empirical formula is used to derive the Molecular Formula when the molar mass value is known.

n = empirical formula molar mass/mass

The molecular formula is frequently the same as or an exact multiple of an empirical formula.

Moles of oxygen = 69.5/16 = 4.34

Moles of nitrogen = 30.5/14 = 2.18

Ratio of moles of N and 0 = 2.18:4.34

Empirical formula = NO2

Molecular formula = (NO2)n

where n= Molecular mass/Empirical mass = 92/46 = 2

Therefore, the formula of the compound is N204.

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Answer:

I forgot dude sorry so sorry

Answer:

255 grams of ammonia

Explanation:

To solve this problem, we need to use the balanced chemical equation for the reaction between ammonia and water:

NH3 + H2O → NH4+ + OH-

From this equation, we can see that one molecule of ammonia reacts with one molecule of water to produce one hydroxide ion (OH-) and one ammonium ion (NH4+). Therefore, we need the same number of molecules of ammonia as water to form the products.

So, if we have 9.09X^23 molecules of water, we need the same number of molecules of ammonia:

9.09X^23 molecules of NH3

To calculate the mass of ammonia required, we need to use the molar mass of ammonia, which is approximately 17 g/mol:

1 mol of NH3 = 17 g

To convert the number of molecules of NH3 to grams, we need to use Avogadro's number:

1 mol = 6.022 × 10^23 molecules

Therefore, the mass of ammonia required is:

9.09X^23 molecules of NH3 * (1 mol/6.022 × 10^23 molecules) * 17 g/mol

= 2.55 × 10^2 g or 255 grams (rounded to two significant figures)

So, we need 255 grams of ammonia to form 9.09X^23 molecules of water.

The Statement "All colors are transmitted through the drink except for blue which is absorbed by the drink." is correct on what happens to a light as it passes through a blue drink.

Light is a form of electromagnetic radiation that is visible to the human eye. It is a type of energy that travels through space in the form of waves and does not require a medium to propagate. Light is produced by the movement of charged particles and travels at a constant speed of about 299,792,458 meters per second in a vacuum.

When light passes through a blue drink, the liquid absorbs the blue portion of the spectrum and allows the other colors to pass through. This is because the blue pigment in the drink selectively absorbs the blue portion of the spectrum, which is why we perceive the liquid as blue. The other colors in the visible spectrum are transmitted through the drink and are not affected.

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Answer:

473 °C

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 200 mL

Initial temperature (T1) = 100 °C

Final volume (V2) = 400 mL

Final temperature (T2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T (°C) + 273

Initial temperature (T1) = 100 °C

Initial temperature (T1) = 100 °C + 273 = 373 K

Next, we shall determine the final temperature of the water as follow:

Initial volume (V1) = 200 mL

Initial temperature (T1) = 373 K

Final volume (V2) = 400 mL

Final temperature (T2) =..?

V1/T1 = V2/T2

200/373 = 400/T2

Cross multiply

200 × T2 = 373 × 400

200 × T2 = 149200

Divide both side by 200

T2 = 149200/200

T2 = 746 K

Finally, we shall convert 746 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 746 K

T(°C) = 746 – 273

T(°C) = 473 °C

Therefore, the temperature of the second sample when it starts to boil is 473 °C

Answer:

facta you from the same thing as you from the samel

Answer:

The first one

The process of dissolving frees the electrons in the solution to move.

Explanation:

Answer:

what grade is this for and i think ik what the answer is

Explanation:

The arrangements of the molecules of a solid, liquid and gas  as follows

1. Solid: In this state of matter, the particles are closely bonded to each other. This means that they are closely packed in a system and the arrangement is regular. The intermolecular space between the particles is minimum.

2. Liquid: In this state of matter, the particles are not so closely packed. The arrangement between the particles is not regular. The intermolecular spacing between the particles is more than solid but less than gaseous state.

3. Gases: In this state of matter, the particles are very far away from each other and the arrangement is not regular. The intermolecular spacing between the particles is very much in case of gases.

The solid, liquid, and gaseous phases of matter are the three basic states of matter.

Every item we encounter every day—from ice cream to chairs to water is composed of matter. Based on intermolecular forces and the arrangement of the particles, matter can be divided into distinct states such as solid, liquid, and gas. By altering specific environmental variables, these three types of matter can change their state of matter (increasing or decreasing pressure and temperature, for instance). For instance, raising the temperature will cause ice to melt from a solid state.

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The concentration of HF(g) in the equilibrium system under these conditions is approximately 0.041 M.

To determine the concentration of HF(g) in the equilibrium system, we can use the equilibrium constant expression and the given concentrations of H2(g) and F2(g).

The equilibrium constant expression for the given reaction is:

K = [HF(g)]^2 / ([H2(g)] * [F2(g)])

We are given that the equilibrium constant (K) has a value of 2.1 × 10^3 and the concentrations of H2(g) and F2(g) are both 0.0059 M.

Substituting the given values into the equilibrium constant expression:

2.1 × 10^3 = [HF(g)]^2 / (0.0059 M * 0.0059 M)

Simplifying the expression:

[HF(g)]^2 = 2.1 × 10^3 * (0.0059 M)^2

Taking the square root of both sides to isolate [HF(g)]:

[HF(g)] = √(2.1 × 10^3 * (0.0059 M)^2)

Calculating this expression, we find:

[HF(g)] ≈ 0.041 M

Therefore, the concentration of HF(g) in the equilibrium system under these conditions is approximately 0.041 M.

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Answer:

This is because oxygen requires two electrons to gain stability, while hydrogen has only one olectron, therefore two hydrogen atoms are required

Answer:

Structural formula

Explanation:

Structural formulas are usually represented as such.

If the pH of a solution is one and it is diluted by 1*10^3 times, the pH of the resulting solution will be 4.

The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the concentration of hydrogen ions in the solution.

When a solution is diluted by a factor of 10, its pH increases or decreases by 1 depending on whether it is an acidic or basic solution, respectively. In this case, the solution has been diluted by a factor of 1*10^3, which means that its pH will increase by 3 units. Therefore, the pH of the resulting solution will be 4 (pH of the original solution + 3).

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Answer:

I'm sorry, but I cannot see the observations or the data table you mentioned in your question. However, I can still provide you with some general guidance on how to approach the calculations and answer the questions based on the given information.

4. To calculate the concentration of the NaOH solution, you need to know the mass of NaOH used and the volume of the solution. The formula to calculate concentration is:

Concentration (in mol/L) = (Mass of NaOH (in grams) / molar mass of NaOH) / Volume of solution (in L)

Make sure to convert the mass of NaOH to moles by dividing it by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).

5. The balanced equation for the neutralization reaction between NaOH and HCl is:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

(aq) represents an aqueous solution, and (l) represents a liquid.

6a. To calculate the average concentration of HCl in the sample from site B, you need to know the volumes and concentrations of the NaOH and HCl solutions used in the titration. Use the formula:

Concentration of HCl (in mol/L) = (Volume of NaOH solution (in L) * Concentration of NaOH (in mol/L)) / Volume of HCl solution (in L)

Multiply the volume of NaOH solution used by its concentration to find the amount of NaOH used. Then, divide this amount by the volume of HCl solution used to find the concentration of HCl.

6b. To determine the pH of the water at site B, you need to know the concentration of HCl from the previous calculation. The pH can be calculated using the formula:

pH = -log10[H+]

Since HCl is a strong acid, it dissociates completely into H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl. Take the negative logarithm (base 10) of the H+ concentration to find the pH.

To check if the water is safe, compare the calculated pH value to the range provided (pH 4.5-7.5). If the pH falls within this range, the water is considered safe for plant and animal reproduction in an aquatic environment.

6c. Use a similar calculation as in 6a to determine the average concentration of HCl in the sample from site C.

6d. Use the concentration of HCl from 6c to calculate the pH using the formula in 6b. Follow the same procedure to check if the water is safe based on the pH range.

7. To find the most current pH value for the Grand River, you can search for the latest data from reliable sources such as environmental agencies, research institutions, or government websites. Compare this pH value to the pH values obtained in the experiment to assess the difference between them.

Remember, without the specific data and observations, the calculations and comparisons provided here are only general guidelines. It's important to use the actual data from your experiment to obtain accurate results and conclusions.

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The molarity of the HCl solution is 0.376 M.

To find the molarity of the HCl solution, we need to use the balanced chemical equation for the reaction between calcium hydroxide and hydrochloric acid:

Ca(OH)2 + 2HCl → CaCl2 + 2H2O

From the equation, we can see that 1 mole of Ca(OH)2 reacts with 2 moles of HCl. We can calculate the number of moles of Ca(OH)2 from its mass and molar mass:

moles of Ca(OH)2 = mass / molar mass = 2.10 g / 74.10 g/mol = 0.0284 mol

Since 151 mL of HCl solution completely neutralized the Ca(OH)2, we can use the balanced equation to calculate the number of moles of HCl:

moles of HCl = 2 x moles of Ca(OH)2 = 2 x 0.0284 mol = 0.0568 mol

Now we can calculate the molarity of the HCl solution:

Molarity = moles of solute / volume of solution in liters

Volume of solution = 151 mL = 0.151 L

Molarity = 0.0568 mol / 0.151 L = 0.376 M

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20gm of hydrogen will have highest number of hydrogen atoms.

We know that 1 mole of substance contains atoms equal to Avogadro number i.e.  \(6.022*10^{23}\)

As molar mass of hydrogen is 1gm there 1 mole of hydrogen contains 1gm of hydrogen and \(6.022*10^{23}\) hydrogen atoms

If we take 1020 hydrogen atoms then it is very less than \(6.022*10^{23}\) hydrogen atoms.

In 100gm of substance if hydrogen is 2% by mass i.e. we have 2gm of hydrogen atom  which means 2 mole of hydrogen atoms

Mass of 1 mole of water is 18gm

Thus 100 gm of water have 5.55 moles of water

In 1 mole of water we have 2 grams of hydrogen

Therefore 5.55 moles of water contains 11.11gm of water i.e. 11.11 mole of water

11.11gm of water = \(11.11* 6.022 * 10^{23}\) atoms

In 20gm of hydrogen we have 20 mole of hydrogen

               i.e. \(20* 6.022 * 10^{23}\)

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The IUPAC names of the following organic compounds are correct with the given naming conventions:A. Pent-3-eneB. Prop-1-en-2-yneC. 1-methylpropaneD. All are incorrect - This is the incorrect option because all the given options have correct IUPAC names of the organic compounds. Hence, option D is incorrect.

The International Union of Pure and Applied Chemistry (IUPAC) is an organization that establishes a set of rules for the naming of chemical compounds. This is done to make sure that all scientists in the world use the same names for the same compounds. Therefore, the names should be unique and unambiguous. The IUPAC name of a compound provides information about its molecular structure, functional groups, and substituents. Some of the examples are given below:A. Pent-3-ene - It is a five-carbon molecule with a double bond between the third and fourth carbons. Hence, the name of the compound is pent-3-ene.B. Prop-1-en-2-yne - It is a three-carbon molecule with a triple bond between the first and second carbons and a double bond between the second and third carbons. Hence, the name of the compound is prop-1-en-2-yne.C. 1-methylpropane - It is a three-carbon molecule with one methyl group attached to the first carbon. Hence, the name of the compound is 1-methylpropane.

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Answer:

A. Atoms gain, lose, or share electrons to achieve a full valence shell

Explanation:

The octet rule is best explained as the process in which atoms lose or gain or share electrons to achieve a full valence shell.

Therefore, the octet rule is attained when atoms gain full valence configuration.