If the mass bigger and the acceleration faster, the force is bigger(F = ma). The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force(p=mc) The gravity can affect the resultant force as weight when the object launch.
sorry if there's any grammar mistake
Convert from standard form to scientific notation:
0.00000013
A)1.3 x 10-7
B)13 x 108
C)1.3 x 107
D)13 x 10-8
Which word identifies the shaking that results from movement under Earth’s surface? earthquake fault plate stress
Answer: Earthquake
Explanation:
An earthquake is the ground shaking caused by a sudden slip on a fault. Stresses in the earth's outer layer push the sides of the fault together. Stress builds up and the rocks slip suddenly, releasing energy in waves that travel through the earth's crust and cause the shaking that we feel during an earthquake.
Answer:The word earthquake identifies the shaking that results from movement under Earth's surface.
explanation: What is earthquake?
An earthquake is an intense shaking of Earth’s surface. The shaking is caused by movements in Earth’s outermost layer.When tectonic plates move, it also causes movements at the faults. An earthquake is the sudden movement of Earth’s crust at a fault line.
alpha and beta rays origin is same
Answer:
Alpha particles carry a positive charge, beta particles carry a negative charge, and gamma rays are neutral. An alpha particle is made up of two protons and two neutrons bound together. Beta particles are high energy electrons. Gamma rays are waves of electromagnetic energy, or photons.
Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km
The weight of an astronaut plus his space suit on the Moon is only 310 N. How much (in N) do they weigh on Earth
Explanation:
Gravity on the Moon is 1/6 th of Earths gravity
weight on earth=310 N ×6
=1860 N
Please help in 5 mintues
A piece of chess game called master
a. king
b. queen
c. rook
d. bishop
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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I need help on this question!
Answer:
All of these
Explanation:
Have a great day!
Answer:
D
Explanation:
this is because the EMS is arranged according to all these factors, the most dangerous waves are the smallest
Explain the difference between an element and a compound. Give an example of each in your discussion.
Elements are pure substances made up of only one type of atom, while compounds are substances made up of two or more different elements that are chemically bonded together.
The difference between an element and a compoundAn element is a pure substance that consists of only one type of atom. Each element has a unique atomic structure and characteristic properties, such as melting point, boiling point, and reactivity. Elements are organized in the periodic table based on their atomic number, which represents the number of protons in the nucleus of an atom.
An example of an element is oxygen (O), which is a gas that makes up about 21% of the Earth's atmosphere. Oxygen is a diatomic element, which means it exists as two atoms that are chemically bonded together. Oxygen has the atomic number 8, which means it has 8 protons in its nucleus.
On the other hand, a compound is a substance that is composed of two or more different elements that are chemically bonded together. The atoms in a compound are held together by chemical bonds, such as covalent or ionic bonds, which give the compound its unique properties
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Two narrow slits spaced 100 microns apart are exposed to light of 600 nm. At what angle does the first minimum (dark space) occur in the interference pattern
Answer:
The angle is \(\theta = 0.1719^o\)
Explanation:
From the question we are told that
The distance of separation is \(d = 100 * 10^{-6} \ m\)
The wavelength of light is \(\lambda = 600 nm = 600 *10^{-9} \ m\)
Generally the condition for destructive interference is mathematically represented as
\(dsin(\theta ) =[m + \frac{1}{2} ]\lambda\)
Here m is the order of maxima, first minimum (dark space) m = 0
So
\(100 *10^{-6 } * sin(\theta ) =[0 + \frac{1}{2} ]600 *10^{-9}\)
=> \(\theta = sin^{-1} [0.003]\)
=> \(\theta = 0.1719^o\)
two physical quantities that change with temperature
Answer:
i think this is wat u want
A force of x Newtons is applied at an angle of x degrees above the horizontal to
a mass of x kg which sits on an incline of angle x degrees. The coefficient
of friction between the mass and the incline is x. For a sufficient applied force so
that the mass moves upward , the net force is given by the expression
F_net = F * cos(α + β) - m * g * sin(β) - u * N
Note:
F_net = net force
F = applied force
α = angle of the applied force
β = angle that the mass sits on
m = mass
g = gravity
u = coefficient of friction between the mass and the incline
N = normal force of the object
Determine the expression to find the angle of the applied force (α).
Show all work/steps.
Hello,
I hope you and your family are doing well!
To find the angle of the applied force (α), you can rearrange the equation for the net force to solve for α. The equation for the net force is:
F_net = F * cos(α + β) - m * g * sin(β) - u * N
To solve for α, you can start by isolating the term containing α. You can do this by subtracting the other terms from both sides of the equation, which gives you:
F_net - F * cos(β) + m * g * sin(β) + u * N = F * cos(α + β)
Then, you can divide both sides of the equation by F * cos(β) to get:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α + β)
Next, you can use the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) to rewrite the right side of the equation:
[F_net - F * cos(β) + m * g * sin(β) + u * N] / (F * cos(β)) = cos(α)cos(β) - sin(α)sin(β)
Finally, you can rearrange this equation to solve for α:
α = atan2(sin(α) * cos(β) + cos(α) * sin(β), cos(α) * cos(β) - sin(α) * sin(β))
This equation gives the angle of the applied force (α) in terms of the other variables in the equation for the net force.
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Happy Holidays!
2. A car is traveling with a velocity of 40 m/s and has a mass of 1,120 kg. Calculate the kinetic energy.
Answer:
896,000 J
Explanation:
m = 1,120 kg
v = 40 m/s
kinetic energy = mv^2/2 = 1,120 * 40^2/2= 896,000 J
For an atom's electrons, how many energy sub levels are present in the principal energy level n=4?
A. 4
B. 9
C. 10
D. 16
E. 32
Answer:
the principal energy level is d because electrons are 2 times more
What does volume measure name two different units that might be used to measure volume
Answer:
Volume measures liquid
Explanation:
Volume can be measured in meters and centimeters
I drop a meterstick, and my reaction time is 0.2 seconds. How far does the meterstick travel
before I catch it?
The distance formula used for a falling object is y = 1/2gt^2 where g is gravity which is 9.80m/s^2 and t is the time it falls ( reaction time).
Y = 1/2(9.8)0.2^2
Y = 0.196
It travels 0.196 meters
1c. Using a metric (SI) measuring tape or ruler:
Measure the length L, width Wand height H of the shoebox shaped object and record
them in centimeters plus millimeters. Transform them to decimal format.
height H
Dimensions of shoebox shaped object measured with ruler
Format
length L
width W
In centimeters and
millimeters
28 cm and 6 mm 19 cm and 1 mm
In decimal
centimeters format
(show your work)
9 cm and 5 mm
Lo
Answer:
Format ______Length ______width ___ height
cm and mm _26cm 6mm _19cm 1mm_9cm 5mm
Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm
Explanation:
Dimension of shoebox shaped object :
Format ______Length ______width ___ height
cm and mm _26cm 6mm _19cm 1mm_9cm 5mm
Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm
Recall:
1mm = 0.1cm
For the length :
26cm + 6mm = 26cm+(6*0.1) = 26 + 0.6 = 26.6cm
Width:
19cm + 1mm = 19cm+(1*0.1) = 19 + 0.1 = 19.1cm
Height:
9cm + 5mm = 9cm+(5*0.1) = 9 + 0.5 = 9.5cm
HELP I NEED IT NOW PLEASE
Please help with these MCQs.
1. Filter absorbs __________________.
- only primary coloured lights
- only secondary coloured lights
- only tertiary coloured lights
- all colors of white light
2. The light that has passed through a filter, is always ______________.
- dim
- bright
- sharp
- blur
1. Filter absorbs all colors of white light.
2. The light that has passed through a filter, is always dim.
Which colors are being absorbed by the filter?The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.
Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.
Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.
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What is the result of (3.60 m ✕ 1.50 m)/0.50 m with the proper number of significant figures? (Enter your answer in m.) answer in: m
Given:
\(\frac{3.60\text{ }m\text{ }\times1.50\text{ m}}{0.50\text{ m}}\)Let's find the result.
To find the result, let's first simplify the numerator:
\(\begin{gathered} \frac{3.60\text{ m }\times1.50\text{ m}}{0.50\text{ m}} \\ \\ =\frac{5.40\text{ m}^2}{0.50\text{ m}} \end{gathered}\)Solving further:
\(=10.80\)Therefore, the result is 10.80 m.
ANSWER:
10.8 m
mechanical advantage describes how simple machines can___________
a. increase the amount of work being done.
b. change the total amount of work that is done
c. allow you to use less force to do the same amount of work
d. allow you to use more force to do the same amount of work
Answer:
The correct answer is c) allow you to use less force to do the same amount of work.
1. we know that the total amount of heat that flows out of the sample and into the water at a specific time is given byLaTeX: Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)Q=mscs(Ts,i−Ts), whereLaTeX: T_sTs is the temperature of the sample at a specific time and, again,LaTeX: T_{s,i}Ts,i is the initial temperature of the sample (at time 0). To simplify the math, we may neglect the heat leak term here to say that this is roughly the same amount of heat the flows into the water, soLaTeX: Q=m_wc_w\left(T_w-T_{w,i}\right)Q=mwcw(Tw−Tw,i), whereLaTeX: T_wTw is the temperature of the water at this same specific time andLaTeX: T_{w,i}Tw,i is the initial temperature of the water.
In the lab, we will measure both the sample and water temperatures as a function of time, but the important quantity is the difference between these temperatures since this is what drives the heat flow between the center of the sample and the water. Using the above equations (solving for the temperatures of the sample and the water bath at a particular time), we can find the relationship between the total amount of heat flow and the difference in the temperatures of the center of the sample and water at some moment in time. This yields _________________________________.
sample and water at some moment in time. This yields _________________________________.
Group of answer choices
Option D: the link between the total heat flow and the temperature difference between the sample's Centre and the water at a specific time.
\(Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)\)
\(T_s\right =(T_{s,i}-T_s\right))\)
\(Q=m_wc_w\left(T_w-T_{w,i}\right)\)
\(Q=m_wc_w\left(T_w-T_{w,i}\right)\)
\(T_{diff} =(T_{s}-T_w\right))\)
= \(T_{s,i} -\frac{Q}{m_{s}C_{s}} -(T_{w,i}\right +\frac{Q}{m_{s}C_{s}} )\)
=\((T_{s,i} - T_{w,i} )-Q(\frac{1}{m_{s}C_{s}} +\frac{1}{m_{w}C_{w}})\)
Specific time refers to a precise moment in time, often denoted by a particular time and date. It can be expressed in different ways depending on the context, such as using a 24-hour clock or the AM/PM system. Specific time is essential for scheduling events, meetings, and appointments, and for coordinating activities across different time zones. It is also crucial for time-sensitive activities such as transportation, where schedules must be coordinated down to the minute. The concept of specific time is used in many fields, including science, technology, business, and everyday life. In modern times, technologies such as smartphones and computers have made it easier than ever to track and coordinate specific times across the globe.
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The complete question is:
1. we know that the total amount of heat that flows out of the sample and into the water at a specific time is given by LaTeX: \(Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)Q=mscs(Ts,i−Ts)\), where LaTeX: \(T_sTs\) is the temperature of the sample at a specific time and, again, LaTeX: \(T_{s,i}Ts,i\)is the initial temperature of the sample (at time 0). To simplify the math, we may neglect the heat leak term here to say that this is roughly the same amount of heat the flows into the water, so LaTeX: \(Q=m_wc_w\left(T_w-T_{w,i}\right)Q=mwcw(Tw−Tw,i)\), where LaTeX:\(T_wTw\) is the temperature of the water at this same specific time and LaTeX: is the initial temperature of the water.
In the lab, we will measure both the sample and water temperatures as a function of time, but the important quantity is the difference between these temperatures since this is what drives the heat flow between the center of the sample and the water. Using the above equations (solving for the temperatures of the sample and the water bath at a particular time), we can find the relationship between the total amount of heat flow and the difference in the temperatures of the center of the sample and water at some moment in time. This yields _________________________________.
sample and water at some moment in time. This yields _________________________________.
Group of answer choices
A. \(T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q\)
B \(T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q\)
C.\(T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q\)
D. \(T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q\)
Express the number of significant figures or digits for the following number: 18470
there are four significant figures for 18470
the last digit is a zero and zeroes are not counted in significant figures so there are four significant figures
hope this helps and sorry for any mistakes :))
No no no no. no no no no
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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1. An object was launched from the ground to the top of a building at a
distance of 65 m from its foot on a horizontal plane at an angle of 60
degrees. Using SOHCAHTOA, find the height of the building the
projectile was launched to from the ground.
Using SOH,CAH,TOA, we can calculate the height of the building by taking the sine of the launch angle (60°) and the distance traveled (65 m). The height of the building is 56.9 m.
What is SOH,CAH,TOA?SOH,CAH,TOA stands for Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. This is a set of trigonometric ratios that can be used to solve for angles and lengths of sides of a right triangle. It is used when the angle and length of two sides of a right triangle are known, but the length of the third side needs to be calculated.
Calculation using SOH, CAH, TOA
The distance from the ground to the top of the building is 65 m and the angle is 60 degrees. the height (h) of the building.has to be found
Using the trigonometric ratio of Sine, calculate the height of the building:
Sin(60°) = Opposite/Hypotenuse
h/65 = sin(60°)
h = 65sin(60°)
h = 65(0.866)
h = 56.59 m
Therefore, the height of the building the projectile was launched to from the ground is 56.59 m.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table as in Fig. 11–5. The mass is pulled so that the spring is stretched 0.250-m from the equilibrium point, and released from rest.
Determine:
(a) the spring stiffness constant k.
The spring constant k based on the information is 12.0 N/m.
How to calculate the valueFrom the information, a spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table.
The spring constant k is the force required to stretch or compress the spring by a unit distance. In this case, the spring is stretched by 0.294 m when a 0.360 kg mass is suspended from it.
This means that the force exerted by the spring is equal to the weight of the mass, which is 0.360 kg x 9.8 m/s^2 = 3.53 N.
Therefore, the spring constant k is:
= 3.53 N/0.294 m
= 12.0 N/m.
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In a particular crash test, an automobile of mass 1577 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 17 m/s and 1.5 m/s, respectively. If the collision lasts for 0.18 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s.
Answer:
Ft=24,443.5 kgm/s
Explanation:
Step one
Given data
Mass of automobile m=1577kg
Initial Velocity u=17m/s
Final Velocity v=1.5m/s
Time t=0.18s
Step two
From the impulse and momentum equation
Ft=mΔv
Substitute
Ft=1577*(17-1.5)
Ft=1577*15.5
Ft=24,443.5 kgm/s
A ball is thrown so that its speed increases by 20 m/s in 10 seconds. What is the ball’s acceleration?
Answer: a= 2 m/s²
Explanation: acceleration = change of speed/ time = 20 m/s / 10 s