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A 0.100 m long solenoid has a radius of 0.050 m and 1.50 x 10^4 turns. The current in the solenoid changes at a rate of 6.0 A/s. A conducting loop of radius 0.0200 m is placed at the center of the solenoid with its axis the same as that of the solenoid.
a.) What is the magnetic flux through the small loop when the current through the solenoid is 2.50 A?
b.) What is the induced emf in the loop?

Here, the slope of the graph is negative and constant.

Hence, acceleration is constant and is in opposite direction to its motion.

So, The object whose motion is represented by this graph is moving with constant acceleration.

Motion is defined in physics as the phenomenon through which an object changes its location with respect to time. Motion is mathematically characterized in terms of displacement, distance, velocity, acceleration, speed, and frame of reference to an observer, with the change in position of the body relative to that frame measured as time passes. Kinematics is the branch of physics that studies forces and their effects on motion, whereas dynamics is the branch that studies forces and their effects on motion.

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Answer:

A) 140 k

b ) 5.22 *10^3 J

c) 2910 Pa

Explanation:

Volume of Monatomic ideal gas = 1.20 m^3

heat added ( Q ) = 5.22*10^3 J

number of moles  (n)  = 3

A ) calculate the change in temp of the gas

since the volume of gas is constant no work is said to be done

heat capacity of an Ideal monoatomic gas ( Q ) = n.(3/2).RΔT

make ΔT subject of the equation

ΔT = Q / n.(3/2).R

    = (5.22*10^3 ) / 3( 3/2 ) * (8.3144 J/mol.k )

    = 140 K

B) Calculate the change in its internal energy

ΔU = Q  this is because no work is done

therefore the change in internal energy = 5.22 * 10^3 J

C ) calculate the change in pressure

applying ideal gas equation

P = nRT/V

therefore ; Δ P = ( n*R*ΔT/V )

                        = ( 3 * 8.3144 * 140 ) / 1.20

                        = 2910 Pa

A) The change in the temperature of the gas is; ΔT = 139.5 K

B) The change in internal energy of the gas is; ΔU = 5.22 × 10³ J

C) The change in pressure of the gas is; ΔP = 2899.5 Pa

We are given;

Volume of Monatomic ideal gas; V = 1.2 m³

Amount of heat added; Q = 5.22 × 10³ J

number of moles; n = 3

A) To calculate the change in temperature of the monatomic idea gas, we will use formula;

Q = ³/₂nRΔT

Where R is a constant = 8.314 J/mol.K

ΔT is the change in temperature

Making ΔT the subject of the formula;

ΔT = ²/₃(Q/(nR))

ΔT = ²/₃(5.22 × 10³)/(3 × 8.314)

ΔT = 139.5 K

B) Due to the fact that no work was done, then from first law of thermodynamics, we can say that;  

ΔU = Q

Thus;

change in internal energy; ΔU = 5.22 × 10³ J

C) The change in pressure will be calculated from the formula;

ΔP = (n*R*ΔT)/V

ΔP = (3 * 8.314 * 139.5)/1.2

ΔP = 2899.5 Pa

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Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Answer:

bye bye

Explanation:

Answer: Or please call again to see if they reached the phone yet.

Explanation: It always stops ringing right before someone gets to there phone so call again in 2 minutes. :3

Air speed in terms of the difference in the liquid levels in that tube is 68.85 m/s.

The density rho of the liquid in the U-tube is 810 kg/m³.

The density of air is 1.14 kg/m³.

What is Bernoulli's equation?

The conservation of energy concept as it applies to flowing fluids is stated by the Bernoulli equation. The reduction of fluid pressure in locations where the flow velocity is increased is the qualitative characteristic that is typically referred to as the "Bernoulli effect." Although this reduction of pressure in a flow route restriction may appear contradictory, it becomes less so if you think of pressure as energy density. Kinetic energy must rise at the expense of pressure energy in the high-velocity flow through the restriction.

We know.

Bernoulli's equation = P1 + hρg + \(\frac{1}{2}\)ρ(a) v1² = P2 + hρg + \(\frac{1}{2}\)ρv2²

Now, P is same : v2 will be 0.

\(\frac{1}{2}\)ρ(a)v1² = hρg

v1 = \(\sqrt{(2hrhog)/rho(a)}\)

Given,

h = 34cm = 0.34 m

rho, ρ = 810 kg/m³

ρ (a) = 1.14 kg/m³

v1 = v = \(\sqrt{2 X 0.34 X 810 X 9.81/1.14}\) = 68.85 m/s

Hence, v = 68.85 m/s

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Answer:

The value of g is  \(g =76.2 m/s^2\)

Explanation:

From the question we are told that

     The mass of the weight is \(m = 1.30 kg\)

      The spring  constant  \(k = 1.73 g/m = 1.73 *10^{-3} \ kg/m\)

       The second harmonic frequency is \(f = 100 \ Hz\)

       The number of oscillation is \(N = 200\)

        The time taken is  \(t = 315 \ s\)

Generally the frequency is  mathematically represented as

           \(f = \frac{v}{\lambda}\)

At second harmonic frequency the length of the string vibrating is equal to  the wavelength of the wave generated

         \(l = \lambda\)

Noe from the question the vibrating string is just half of the length of the main string so

Let assume the length of the main string is  \(L\)

So      \(l = \frac{L}{2}\)

The velocity of the vibrating string is mathematically represented as

             \(v = \sqrt{\frac{T}{\mu} }\)

Where T is the tension on the string which can be mathematically represented as

             \(T = mg\)

So  

           \(v = \sqrt{\frac{mg}{k} }\)

Then

          \(f = \frac{v}{\frac{L}{2} }\)

=>       \(v = \frac{fL }{2}\)

=>      \(\sqrt{\frac{mg}{k} } = \frac{fL}{2}\)

=>        \(g = \frac{f^2 L^2 \mu}{4m}\)

substituting values

             \(g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2\)

              \(g = 3.326 m^{-1} s^{-2} L^2\)

Generally the period of oscillation is mathematically represented as

       \(T_p = 2 \pi \sqrt{\frac{L}{g} }\)

=>   \(L = \frac{T^2 g}{4 \pi ^2}\)

   The period can be mathematically evaluated as

                \(T_p = \frac{t}{N}\)

 substituting values

             \(T_p = \frac{315}{200}\)

             \(T_p = 1.575 \ s\)

Therefore

          \(L = \frac{1.575^2 * g }{4 \pi ^2}\)

           \(L = 0.0628 ^2 g\)

so

      \(g = 3.326 m^{-1} s^{-2} L^2\)

substituting for L

        \(g = 3.326 ((0.0628) g)^2\)

=>    \(g = \frac{1}{(3.326)* (0.0628)^2}\)

       \(g =76.2 m/s^2\)

(a) Velocity with which the mug leaves the counter is approximately 5.02 m/s.

(b) The direction of velocity of mug just before it hits the floor is downwards, since mug is falling under influence of gravity.

Velocity is a quantity that designates how fast and also in what direction a certain point is moving.

(a) As we know, PE = m g h

\(\mathrm{PE = mgh }\)

\(\mathrm{= (m)(9.81 m/s^2)(1.36 m) }\)

= 13.4mJ

\(\mathrm{KE =\frac{1}{2} mv^2}\)

PE = KE

\(\mathrm{mgh = \frac{1}{2}mv^2}\)

\(\mathrm{v = \sqrt{2gh}}\)

\(\mathrm{v = \sqrt{2 \times 9.81 \times 1.36 m}}\)

v = 5.02 m/s

Therefore, the velocity with which the mug leaves the counter is approximately 5.02 m/s.

(b) The direction of the velocity of mug just before it hits the floor is downwards, since mug is falling under the influence of gravity. Velocity vector has a vertical component that points downwards and horizontal component that is parallel to counter.

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Answer:

A goal keepee catering the ball in time is answer

Anaerobic transmission is when you touch a contaminated surface is a false statement.

Anaerobic organisms are the living things that can survive and grow where there is no oxygen in the surrounding environment so we can conclude that Anaerobic transmission is when you touch a contaminated surface is a false statement.

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Answer:

B. Electrons are transferred from the fur to the plastic rod.

Explanation:

Triboelectricity or friction charging refers to the ability of materials to gain or lose electrons as a result of rubbing them against something. This phenomenon has been observed in the case of rubbing plastic rod against fur, or glass rod against silk.

In the context of rubbing plastic rod against fur, what happens is that the fur which has an excess of charges loses electrons to the plastic rod. This makes the plastic rod to become positively charged, and the fur, negatively charged.

Answer:

Period becomes 1/3 of the original

Explanation:

Period = 1/f      if f becomes 3f   then period becomes 1/3 of the original

An egg is attached to a parachute and dropped from a height of 16 meters, after hitting the ground the egg will crack. Hence, option A is correct.

A moving object's speed and orientation vary over time at a certain rate, which is known as acceleration. An object or location is considered to be accelerated when it moves more quickly or more slowly in a straight path.

A circle's motion increases despite its constant speed because its direction is always changing. For all other motions, by and also to acceleration is used.

Because of its magnitude and direction, it is a vector quantity.

As per the given information in the question,

The egg is attached to a parachute.

The dropping height of the egg is 16 m.

The given velocity is 0.8 m/s.

When the egg will strike the ground with minimal velocity doesn't matter it will break anyway because the out shell of the egg is very smooth or soft and every soft strike will lead to the breaking of the egg.

Then the egg will crack after hitting the ground.

Hence, option A is correct.

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Work = (force) x (distance)

Your force was not enough to move the building, so the distance is zero.

Work = (your force) x (zero)

Work = zero

The angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.

When a light ray travels from rarer medium to a denser medium, the refracted ray tends to move towards the normal. So angle of refraction < angle of incidence. When a light ray travels from denser medium to a rarer medium, the refracted ray tends to move away from the normal. So angle of refraction > angle of incidence.

Glass is denser than air. So the angle of refraction will be higher for air than the angle of refraction of glass. So, when the medium is changed from air to glass, the angle of refraction will decrease.

Therefore, the angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.

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Answer:

The net magnetic flux through any closed surface must always be zero.

As we know,

F= ma

Here,

applied force(f)= mass × acceleration

=80kg×3m/s2

=240kgm/s2

=240N

the mass of the body 2 is {eq}5.804\;{\rm{kg}} {/eq}.

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.

Answer:

C) radio → infrared → ultraviolet → gamma

Explanation:

It Increases left to right therefore it decreases right to left

Answer:

the time taken t is 9.25 minutes

Explanation:

Given the data in the question;

The initial charge on the supercapacitor = 2.1 × 10³ mV = 2.1 V

now, every minute, the charge lost is 9.9 %  

so we need to find the time for which the charge drops below 800 mV or 0.8 V

to get the time, we can use the formula for compound interest in basic mathematics;

A = P × ( (1 - r/100 )ⁿ

where A IS 0.8, P is 2.1, r is 9.9

so we substitute

0.8 = 2.1 × ( 1 - 0.099 )ⁿ

0.8/2.1 = 0.901ⁿ

0.901ⁿ = 0.381

n = 9.25 minutes

Therefore, the time taken t is 9.25 minutes

Based on linear velocity, size of impulse, and force required to stop them, the automobiles are ranked from largest to smallest in size.

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

As fast-acting force or "impact" is referred to as "impulse," impulse may be described as "the abrupt force operating on an item for a brief period of time."

Force (F), Impulse (J) and linear momentum (P) are related as

P = mu

where m = mass

           u = initial velocity

J = ΔP = m (v - u)

Impulse is the change in momentum as we know.

J = F.t

Therefore, P ∝ J ∝ F

Thus, it follows that the force and impulse required to stop each automobile are precisely proportional to its linear momentum.

The Red car's linear momentum is computed as;

P = 1000 x 10 = 10, 000 kg.m/s

The Yellow car's linear momentum is computed as;

P = 2,000 x 5 = 10,000 kg.m/s

The Blue car's linear momentum is computed as;

P = 500 x 20 = 10,000 kg.m/s

The Light blue car's linear momentum is computed as;

P = 1,000 x 20 = 20,000 kgm/s

The Purple car's linear momentum is computed as;

P = 4,000 x 5 = 20,000 kg.m/s

Therefore the rankin of the automobiles will be

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

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The complete question is;

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part B Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them.

Given,

The coordinate plane with two points M and N.

The coordinates of the point N is (7,2)

The coordinates of point M is (7,-3)

From the figure, point N is in the 1st quadrant and point M is in the 4th quadrant. Thus 1st option is not correct.

The y-coordinate of point N is 2 and that of point M is -3. Thus option 3 is not correct either.

The c-coordinate of the point N is 7 and that of M is 7 too.

Thus the correct answer is option 2

The 99% confidence interval for the average maximum HP for the experimental engine is (610.12, 689.88).

To calculate the confidence interval for the experimental engines' average maximum HP, we can use the following formula:

To find the z-score for α=0.01, we can refer to a standard normal distribution table or use a calculator. The z-score is approximately 2.58.

Substituting the given values into the formula, we get:

CI = 650 ± 2.58*(60/√25) CI = 650 ± 30.96

Rounding to two decimal places, the confidence interval for the experimental engines' average maximum HP is:

CI = [619.04 HP, 680.96 HP]

Therefore, we can say with 99% confidence that the true average maximum HP for the experimental engines falls between 619.04 HP and 680.96 HP. Thus, we can conclude that the experimental engines' average maximum HP is likely to be within this range. However, note that this range does not include the manufacturer's claimed maximum HP of 630 HP, which may indicate that the engines are performing below expectations.

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When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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We can use the conservation of momentum to solve both problems:

Conservation of momentum:

0 = m1(v1') + m2(v2')

where m1 = 50 kg, v2' = 3 m/s, and m2 = 80 kg. We can solve for v1' to get:

v1' = -(m2/m1) v2'

v1' = -(80 kg/50 kg) (3 m/s) = -4.8 m/s

Therefore, the 50 kg swimmer moves away from the raft with a velocity of -4.8 m/s.

Conservation of momentum:

m1(v1) + m2(v2) = m1(v1') + m2(v2')

where m1 = 90 kg, v1 = 6 m/s, m2 = 60 kg, and v1' = 4 m/s. We can solve for v2 to get:

v2 = (m1v1 + m2v2 - m1v1') / m2

v2 = (90 kg)(6 m/s) + (60 kg)(2 m/s) - (90 kg)(4 m/s) / 60 kg

v2 = -1 m/s

Therefore, the velocity of the 60 kg player after the collision is -1 m/s, which means they are moving in the opposite direction to the 90 kg player.

Answer:

Explanation:

As you throw a book upward, two types of energy are given to the book:

Kinetic Energy: The book gains kinetic energy as it speeds up while you throw it upwards.

Potential Energy: The book gains potential energy as it moves upward against gravity.

The energy to throw the book comes from the food we eat, which provides the body with potential energy in the form of glucose. This glucose is broken down in the cells of our body, and the energy released is used to perform physical activities like throwing a book upwards.

The energy transformation involved in this process is the conversion of potential energy stored in the glucose molecule into kinetic energy of the body and ultimately into potential energy of the book. The energy transformation is an example of the Law of Conservation of Energy, which states that energy cannot be created or destroyed but can only be transformed from one form to another.

Answer:

d = 114.95 m

Explanation:

Givens:

a = 7.6 m/s^2

t = 5.5 s

v_i = 0 m/s

a = (v_f-v_i)/t

7.6 m/s^2 = (v_f-0 m/s)/5.5 s

v_f = (7.6 m/s^2)*(5.5 s)

v_f = 41.8 m/s

d = [(v_f+v_i)/2]*t

d = [(41.8 m/s)/2]*5.5 s

d = 114.95 m