Answer:
Dynamic Stretching
Explanation:
Dynamic Stretching: Dynamic stretches are controlled movements that prepare your muscles, ligaments and other soft tissues for performance and safety.
You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N
Answer:
85.2 N
Explanation:
You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.
WeightYour weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...
W = k(M/r²) = 710 N
W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N
Your weight would be 82.5 N.
Question 6 of 10
In which three ways does the pattern seen on the screen during a double-slit
experiment support the wave model of light?
A. All of the light that enters the slits passes through them.
I B. There are bands of dimmer light.
C. There are bands of brighter light.
I D. The light bends around the edges of the slit.
Answer:
Explanation:
a speed swimmer love to race around the parks pine which is 25m around if she can swim 20 laps in 7200s what is her average speed?
Answer:
the average speed of the swimmer is 0.069 m/s.
Explanation:
Given;
complete distance around the park pine, d = 25 m
total lap completed, = 20 laps
time of laps completion, t = 7200 s
The total distance completed by the swimmer = 20 x 25 = 500 m
The average speed of the swimmer = distance / time
= (500 m) / (7200 s)
= 0.069 m/s.
Therefore, the average speed of the swimmer is 0.069 m/s.
The decomposition of dinitrogen pentoxide is described by the reaction: 2N2O5(g)→4NO2(g)+O2(g). If O2 is being formed at a rate of 2.40 mol/min, what is the rate at which N2O5 is being used up?
Answer:
4.80 mol N2O5/min
Explanation:
The balanced equation tells us that 2 moles of N2O5 are required for every 1 mole of O2. Therefore:
(2.40 mol O2/min)*(2 mol N2O5/mol O2) = 4.80 mol N2O5/min
a high schooler who lives on the "5th" floor of an apartment complex dropped his phone off the balcony. If the balcony is 18.75 m above the ground, determine the time required for the phone to reach the ground'
Answer:
1.38 s
Explanation:
Use the free falling formula
T = √(L)/ g
T = √18.75/9.8
T = 1.38 s
Somebody help!?
13. The graph below represents the speed of a car vs. time. Circle the letter(s) with the lowest acceleration.
What is the acceleration? How do you know?
Answer:
acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Explanation:
Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .
Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?
Answer:
80 Percent
Explanation:
E=energy output/energy input×100
E=8000/10000×100
E=0.8×100
E=80 percent.
Mark brianliest if my answer suit your question
If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.
What is Work?Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.
Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.
As per the data provided in the question,
Total input energy = 10,000 J
Total output energy = 8,000 J
Then, the efficiency (η) of the machine will be,
η = (output energy/input energy) × 100
η = 8000/10000 × 100
η = 80%.
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a cylinder of gas floats in a large tank of water what kind of process is this
The process of a gas cylinder floating in a large tank of water is an example of an equilibrium process.
The gas cylinder floating in a large tank of water represents a state of equilibrium. In this scenario, the gas cylinder is immersed in the water, and the forces acting on it are in balance.
When the gas cylinder is placed in the water, it experiences an upward buoyant force due to the displacement of water by the cylinder. This buoyant force is equal to the weight of the water displaced by the cylinder. According to Archimedes' principle, this buoyant force is equal to the weight of the gas cylinder itself.
Simultaneously, the gas cylinder experiences a downward gravitational force due to its own weight. For the cylinder to float, these two forces must be equal.
As a result, the floating gas cylinder represents an equilibrium state, where the buoyant force and the gravitational force are balanced. This equilibrium occurs because the density of the gas in the cylinder is lower than the density of the water, allowing it to displace a volume of water that is equal to its own weight.
Therefore, the process of a gas cylinder floating in a large tank of water is an example of an equilibrium process where the upward buoyant force equals the downward gravitational force.
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Each of the gears a and b has a mass of 675 g and has a radius of gyration of 40 mm, while gear c has a mass of 3. 6 kg and a radius of gyration of 100 mm. Assume that kinetic friction in the bearings of gears a, b, and c produces couples of constant magnitude 0. 15 n·m, 0. 15 n·m, and 0. 3 n·m, respectively. Knowing that the initial angular velocity of gear c is 2000 rpm, determine the time required for the system to come to rest.
9.87 seconds
The time required for this system to come to rest is equal to 9.87 seconds.
We have the following data:
Mass of gear A = 675 g to kg = 0.675 kg.
Radius of gear A = 40 mm to m = 0.04 m.
Mass of gear C = 3.6 kg.
Radius of gear C = 100 mm to m = 0.1 m.
How can I calculate the time needed?
We would need to figure out the moment of inertia for gears A and C in order to compute the time needed for this system to come to rest.
Mathematically, the following formula can be used to determine the moment of inertia for a gear:
I = mr²
Where:
m is the mass.
r is the radius.
We have, For gear A:
I = mr²
I = 0.675 × 0.04²
I = 0.675 × 0.0016
I = 1.08 × 10⁻³ kg·m².
We have, For gear C:
I = mr²
I = 3.6 × 0.1²
I = 3.6 × 0.01
I = 0.036 kg·m².
The initial angular velocity of gear C would therefore be converted as follows from rotations per minute (rpm) to radians per second (rad/s):
ωc₁ = 2000 × 2π/60
ωc₁ = 4000π/60
ωc₁ = 209.44 rad/s.
Also, the initial angular velocity of gears A and B is given by:
ωA₁ = ωB₁ = rc/rA × (ωc₁)
ωA₁ = ωB₁ = 0.15/0.06 × (209.44)
ωA₁ = ωB₁ = 2.5 × (209.44)
ωA₁ = ωB₁ = 523.60 rad/s.
Taking the moment about A, we have:
I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0
On Substituting the given parameters into the formula, we have;
(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0
0.15t - 0.06∫F_{AC}dt = 0.56549 ----->equation 1.
Similarly, the moment about B is given by:
0.15t - 0.06∫F_{BC}dt = 0.56549 ------>equation 2.
Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt
Adding eqn. 1 & eqn. 2, we have:
0.3t - 0.06x = (0.56549) × 2
0.3t - 0.06x = 1.13098 ------>equation 3.
Taking the moment about A, we have:
Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0
0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0
0.3t + 0.15x = 7.5398 ------->equation 4.
Solving eqn. 3 and eqn. 4 simultaneously, we have:
x = 30.5 Ns.
Time, t = 9.87 seconds.
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if a dog ages 7 years for 1 human year, what would be the relative velocity, if these relative clocks were phrased kinematically (ie. using the lorentz time dilation transformation formula)?
The relative velocity between the dog and the human is very close to the speed of light, which is not surprising given the simplifying assumptions we've made. In reality, the dog's aging process is determined by biological factors rather than relativistic effects, so the Lorentz time dilation formula is not directly applicable.
The Lorentz time dilation formula relates the time interval between two events in one frame of reference to the time interval between the same events in a different frame of reference that is moving at a constant velocity relative to the first frame.
We can use the Lorentz time dilation formula to relate the time interval between these events in the dog's frame of reference (Δt) to the time interval between the same events in the human's frame of reference (Δt'):
Δt' = Δt / √(1 - v²/c²)
Here, v is the relative velocity between the dog and the human, c is the speed of light, and we've set the units so that Δt and Δt' are both measured in years.
We want to solve for v, so we can rearrange the formula as follows:
v = c √(1 - (Δt/Δt')²)
Substituting the values we've assumed, we get:
v = c √(1 - (10/70)²) ≈ 0.99999999999996c
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A wheel is formed from a hoop of mass 4.3 kgand three equally spaced spokes, each of mass0.15 kg. The hoop’s radius is the length0.67 m of each spoke.
The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².
The given parameters;
mass of the hoop, M = 43. kgmass of each spoke, m = 0.15 kgradius of the hoop, r = 0.67 mThe moment of inertial of the wheel is calculated as follows;
\(I = I_{hoop} + 3I_{spoke}\\\\I = MR^2\ + \ 3(\frac{1}{3} mL^2)\\\\I = (4.3 \times 0.67^2) \ + \ (0.15 \times 0.67^2)\\\\I = 2.0 \ kgm^2\)
Thus, the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².
"Your question is not complete, it seems to be missing the following information";
find the moment of inertial of the wheel about an axis through its center and perpendicular to the plane of the wheel.
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A student puts a beaker of boiling water where it touches a block of ice.
Which two statements are true?
A. Thermal energy will move from the boiling water to the ice.
B. Thermal energy will move from the air to the ice.
O c. Thermal energy will move from the air to the boiling water.
D. Thermal energy will move from the ice to the air.
O
Answer:
Option (A).
Explanation:
When a hot and a cold objects come in thermal contact with each other,exchange of heat takes place between them until thermal equilibrium is reached.
In this process thermal energy flows from high temperature to low.
Therefore, when a beaker of boiling water comes in touch with a block of ice,
Thermal energy starts flowing from boiling water to block of ice until equilibrium is established.
Option (A) will be the answer.
what would be a reasonable unit to measure the length of a rice grain?
A reasonable unit to measure the length of a rice grain is millimeters (mm).
Rice grains are relatively small, and millimeters provide a suitable level of precision for measuring their length. Using millimeters allows for more accurate measurements and consistency in assessing the size of rice grains. Various tools, such as calipers or rulers with millimeter markings, can be used to measure the length of rice grains.
This unit is commonly used in scientific studies, culinary applications, and quality control assessments of rice. It provides a practical and standardized way to quantify the length of rice grains, aiding in research, production, and cooking processes.
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what is the wavelength range of photons that produce 40-kev electrons in compton scattering?
The wavelength range of photons that produce 40-keV electrons in Compton scattering is approximately 0.031 nanometers to 0.035 nanometers.
In Compton scattering, a photon collides with an electron, causing the photon to lose energy and change direction. The amount of energy lost by the photon is determined by the angle of scattering and the initial energy of the photon.
The maximum energy that can be transferred to the electron is equal to the energy of the incident photon minus the energy of the scattered photon.
To calculate the wavelength range of photons that produce 40-keV electrons in Compton scattering, we can use the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Rearranging the equation, we get λ = hc/E.
For a 40-keV electron, the energy of the incident photon can be calculated by subtracting the rest mass energy of the electron from the total energy: E = 40 keV + 511 keV = 551 keV. Using the above equation, we can calculate the wavelength range to be approximately 0.031 nm to 0.035 nm.
This range falls within the X-ray region of the electromagnetic spectrum and is commonly used in medical imaging and material analysis.
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Emily drives her car
293.8 km with a
constant speed of
82 km/h and another
194.4 km with a
constant speed of
48 km/h. How much
time in total does she
take to travel these
distances?
Answer:
Since there is already an answer i will try to go more into depth about how it was solved.
Explanation:
Using the basic equation S=d/t, where S is speed is in km/hr, d is distance in km, and t is time in hours, we can plug in the two separate pairs of known variables.
Pair 1:
S=d/t
82km/hr=293.8km/t
t=3.583hr
Pair 2:
S=d/t
48km/hr=194.4km/t
t=4.05hr
since the question is asking us for the total time, we can add these two together.
3.583hr+4.050hr=7.633hr
So she has traveled for a total of 7.633 hours
Hope this helps you understand the question a little more!
A rocket travels vertically at a speed of 1200 km/h. The rocket is tracked through a telescope by an observer located 16km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min after lift-off. Round your answer to the nearest hundredth rad/hr
Answer:
w = 0.01 t⁻² rad/h
Explanation:
Let's use trigonometry to find the elevation angle of the telescope, we assume that the rocket remains fixed in the telescope.
tan θ = CO / CA
the adjacent leg is CA = 16 km = 16 10³ m
Let's use kinematics to find the height of the rocket
v = y / t
y = v t
this height is equal to the opposite leg
CO = v t
we substitute
tan θ = vt / 16
tan θ = 1200/16 t
tan θ = 75 t
θ = tan⁻¹ ( 75 t )
speed is defined by
w = dθ/dt
w = \(\frac{1}{1 + (75 t)^2} \ 75\)
as time increases we can neglect the 1 of the denominator
w = 1/75 t²
w = 0.0133 t⁻²
Using three significant figures
w = 0.01 t⁻² rad/h
for this answer the time must be given in hours
Miranda drives her car clockwise around a circular track of radius 25 m. She
completes 13 laps around the track in 5 minutes. Find Miranda's total distance
traveled
A balloon’s internal pressure has increased, but the balloon has not changed in size. What must have happened to the external pressure for this to be true? Assume that elastic recoil is negligible. A balloon's internal pressure has increased, but the balloon has not changed in size. What must have happened to the external pressure for this to be true? Assume that elastic recoil is negligible. The outside pressure has increased the same amount as the inside pressure The outside pressure has increased more than the inside pressure. The outside pressure has remained the same The outside pressure has decreased.
The outside pressure has increased the same amount as the inside pressure.
When the internal pressure of a balloon increases but the balloon does not change in size, it implies that the external pressure acting on the balloon must have increased by the same amount as the internal pressure. This balance of pressures prevents the balloon from expanding or contracting.
By Newton's third law of motion, for every action, there is an equal and opposite reaction. In the case of the balloon, the increase in internal pressure exerts a force on the walls of the balloon. The external pressure must match this force to maintain equilibrium and prevent any change in the size of the balloon.
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it is important to know the difference between atoms
Answer:
yes
hope this will help you
What is the relationship between acceleration and time alt) for the model rocket (u(t) = at3 + ßt + y, where a = -3.0 m/s4, B = 36m/s², and y = 1.0m/s)? ► View Available Hint(s) a(t) = at? +B+ a(t) = cit? + C2 with the constants ci and c2 unknown because not enough information has been provided a(t) = 3at? +B a(t) = ß a(t) =
The relationship between acceleration and time for the model rocket is given by the function a(t) = -9.0 m/s⁴t² + 36 m/s².
The relationship between acceleration and time for the model rocket can be found by taking the derivative of the given velocity function u(t) with respect to time t. The velocity function is u(t) = at³ + ßt + y, where a = -3.0 m/s⁴, ß = 36 m/s², and y = 1.0 m/s.
Step 1: Find the derivative of u(t) with respect to time t.
The derivative of at³ with respect to t is 3at².
The derivative of ßt with respect to t is ß.
The derivative of y with respect to t is 0.
Step 2: Combine the derivatives to get the acceleration function a(t).
a(t) = 3at² + ß
Step 3: Substitute the given values of a, ß, and y into the acceleration function.
a(t) = 3(-3.0 m/s⁴)t² + 36 m/s²
a(t) = -9.0 m/s⁴t² + 36 m/s²
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two bodies of equal mass are separated by a distance r. if you double the distance between them the new gravitational force will be
1/4 of the old gravity influence would remain.
Newton's universal principle of gravitation states that the attracting force among any two components is equal to the square of the length that separates them and equal to the ratio of their masses.
Gravitational pull is the term for something like the pressure which the planet exerts upon the object. Illustrations of movement caused by gravitational influence include the downward force of flow of water, the downward movement liquid flowing water, and the upward motion of a ball when it is tossed. Every two mass-containing items are attracted to one another by the gravitational force.
Since the force of gravity rarely aims to push masses apart, it is referred to as appealing since it constantly seeks to draw them towards.
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True Or False: The Quantities Di And D0 Are Measured From The Focal Point Of A Lens Or Mirror. True False
The quantities di and d0 are measured from the focal point of a lens or mirror. The given statement is true.
What is a focal point?A focal point is a point on the axis of a mirror or lens to which light rays are focused. It is where parallel rays converge after being reflected or refracted.The quantities di and d0 are measured from the focal point of a lens or mirror.
What is meant by quantities di and d0?In the study of lenses and mirrors, di is the distance of the image from the lens, and d0 is the distance of the object from the lens. These quantities are measured from the lens's or mirror's focal point, depending on whether it is a converging or diverging lens or mirror.
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which scan examines the current security, in a passive method?
The scan that examines the current security in a passive method is called a Vulnerability Assessment (VA) scan.
A Vulnerability Assessment scan is a process of identifying and assessing vulnerabilities within a system, network, or application. It is typically performed using automated tools that scan the target environment for known vulnerabilities, configuration weaknesses, and security holes. Unlike active scanning techniques that actively probe the system and may generate network traffic, a VA scan operates in a passive manner, observing the system without actively interacting with it.
During a Vulnerability Assessment scan, the automated tool examines the target environment by analyzing network traffic, configurations, system logs, and other sources of information to identify potential vulnerabilities. It compares the collected data against a database of known vulnerabilities and security weaknesses to determine if any matches exist.
The passive nature of a VA scan makes it non-intrusive, as it does not generate additional traffic or perform active actions that could potentially impact the system's performance or stability. It allows organizations to assess their current security posture, identify vulnerabilities, and prioritize remediation efforts without disrupting the normal operation of the environment.
The results of a Vulnerability Assessment scan provide insights into the security weaknesses present in the system, enabling organizations to take appropriate measures to address and mitigate those vulnerabilities. This may include applying security patches, reconfiguring systems, updating software versions, or implementing additional security controls to protect against potential threats.
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find the volume of the given solid. bounded by the planes z = x, y = x, x + y = 9 and z = 0
The volume of the given solid is:
V = ∭(D) dx dy dz = (1/2) * 9/2 * 9/2 = 81/8
What is the method to find the volume?To find the volume of the solid, we can use the triple integral. Since the solid is bounded by the planes z = x, y = x, x + y = 9, and z = 0, we can write the integral as:
V = ∭(D) dV = ∭(D) dx dy dz
where D is the region bounded by the given planes.
To set up the triple integral, we need to determine the bounds for the variables x, y, and z. Since the solid is bounded by the planes z = x, x + y = 9, and y = x, we can express z in terms of x and y. We have:
z = x
Since x + y = 9, we can also express y in terms of x:
y = 9 - x
Substituting this expression for y into the equation for z, we get:
z = x = x
Therefore, the bounds for x are 0 ≤ x ≤ 9/2. The bounds for y are 0 ≤ y ≤ 9 - x, and the bounds for z are 0 ≤ z ≤ x.
Using these bounds, we can set up the triple integral as follows:
V = ∭(D) dx dy dz = ∫x=0 to x=9/2 ∫y=0 to y=9-x ∫z=0 to z=x 1 dz dy dx
Evaluating this integral, we find that the volume of the solid is:
V = ∭(D) dx dy dz = (1/2) * 9/2 * 9/2 = 81/8
Therefore, the volume of the solid is 81/8.
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The most common form of lightning strike from a cloud to the ground involves negative charge moving from the cloud to the ground. Just before a lightning strike,
Just before a lightning strike, a negative charge within the cloud creates a stepped leader, which moves towards the ground. As it approaches, the ground's positive charge forms an upward streamer. When the stepped leader and upward streamer connect, a powerful electrical discharge occurs, creating the lightning strike from the cloud to the ground.
Just before a lightning strike, the negative charge within the cloud separates from the positive charge, creating an electric field. This electric field becomes strong enough to ionize the air molecules between the cloud and the ground, creating a conductive path for the negative charge to travel to the positively charged ground. This is what causes the lightning bolt to shoot down from the cloud to the ground, resulting in a lightning strike.
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i will give u brainliest!
Answer:
True
Explanation:
idk
consider the titration of 100.0 ml of 0.200 m acetic acid (ka by 0.100 m koh. calculate the ph of the result- ing solution after the following volumes of koh have been added.
Answer: The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
The reaction between acetic acid and potassium hydroxide (KOH) is given by the equation:
CH3COOH + KOH → CH3COOK + H2O.
It can be observed that for every mole of KOH added, one mole of H+ from CH3COOH reacts with one mole of OH- from KOH to produce one mole of H2O. Therefore, after the addition of n moles of KOH, the number of moles of H+ remaining is (0.200 - n) moles (since 0.200 M is the initial concentration of acetic acid). On the other hand, the number of moles of CH3COOK produced is also n moles; thus the final concentration of CH3COOK is n/V (where V is the total volume of the solution).
The reaction produces a salt (CH3COOK), which is neutral. Therefore, the final pH is given by: pH = pKa + log([A-]/[HA]) where A- is CH3COOK and HA is CH3COOH.
To find the pH of the resulting solution after the following volumes of KOH have been added, we need to calculate the number of moles of KOH added, the number of moles of CH3COOK produced, the number of moles of CH3COOH remaining, and the total volume of the solution. Then we can use the Henderson-Hasselbalch equation above to find the pH.
Here are the calculations: Initial number of moles of CH3COOH = M × V = 0.200 × 0.100 = 0.020 moles. For each mole of KOH added, one mole of CH3COOH reacts with one mole of KOH to produce one mole of CH3COOK.Number of moles of KOH added Volume of KOH added (mL)Moles of KOH added0.02 0.00 (initial) 0.000.02 10.10 0.010.02 20.20 0.020.02 30.30 0.030.02 40.40 0.040.02 50.50 0.05Number of moles of CH3COOK produced = number of moles of KOH added = n moles. Concentration of CH3COOK produced = n/V = n/(Vinitial + V added) = n/(0.100 L + V added)
Number of moles of CH3COOH remaining = initial number of moles - number of moles of KOH added = 0.020 - n moles. Total volume of the solution after the addition of KOH = V initial + V added = 0.100 L + V added. We can then use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA])where A- is CH3COOK and HA is CH3COOH.pKa of acetic acid = 4.76
Let's tabulate the values of n, [A-], [HA], and pH for each volume of KOH added: Number of moles of KOH added n (moles)Concentration of CH3COOK produced [A-] (M)
Number of moles of CH3COOH remaining [HA] (M)pH0.000.000.020.76 (initial)0.010.010.019.84 0.020.020.018.98 0.030.030.018.20 0.040.040.017.49 0.050.050.016.85.
The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
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what is the best defintion of efficency
Answer: Efficiency signifies a peak level of performance that uses the least amount of inputs to achieve the highest amount of output.
Explanation: It minimizes the waste of resources such as physical materials, energy, and time while accomplishing the desired output.
Answer:
The efficiency of a simple machine is defined as the ratio of useful work done by the machine ( output work) to the total work out into the machine ( input work).
Explanation:
EfficiencyIf a machine overcomes a load ' L ' and the distance travelled by the load is 'Ld' , the work done by the load is L× LD. It is also called output work or useful work.
Therefore, \( \boxed{Output \: work \: = L \: \times \: Ld}\)
Likewise, The effort applied to overcome the load is 'E' and the distance covered by effort is 'Ed' , the work done by effort is E × Ed. It is also called input work.
Therefore, \( \boxed{Input \: work = E \times Ed}\)
The efficiency of a simple machine is defined as the ratio of output work to the input work .
Therefore, \( \boxed{Efficiency ( η)= \frac{outpt \: work}{input \: work} \times 100\%}\)
Efficiency is expressed in percentage. It is a ratio of two works. A machine is never 100% efficient. It is because no machine is friction free and due to friction, some of the input energy is wastes in the form of heat energy.
\( \mathrm{Hope \: I \: helped!}\)
\( \mathrm{Best \: regards!}\)
4.
Which wave diffracts the most when encountering an obstacle?
O a surface wave
O a wave with the longest wavelength
O a longitudinal wave
O a wave with the highest amplitude
Answer:
Answer is a wave with the longest wavelength.
Explanation:
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I’m confuse like which two types of fields vibrate in light wave
Electromagnetic waves consists of alternate electrical and magnetic fields.
Light is a electromagnetic wave. Hence in light wave, electrical and magnetic fields vibrate.