Examine the equation and the graph, each of which represent a different linear function.

Function A: y=7x−2

Function B:

The graph of a line that contains points (0, 2), (1, 1), and (2, 0).




What is the difference between the initial values for these two functions?
Responses

0

−2

22

4

Answer:

0.5

Step-by-step explanation:

-1 + 3[(10-12)³÷(-16)]

Step 1: (10 - 12)³ — Bracket

(-2)³ = -8

Step 2: -8 ÷ (-16) — Division

-8/-16

= 1/2

Step 3: 3(1/2) — Multiplication

= 3/2

Step 4: 1 + 3/2 — Addition

= 0.5

You can also type it straight into the calculator to confirm.

The correct statement is: b. The uncertainty will be larger in Study 1 than in Study 2.

This is because Study 2 used a larger random sample (100 cigarettes) compared to Study 1 (10 cigarettes), resulting in a more accurate estimate of the mean nicotine content and reduced uncertainty.

The uncertainty will be larger in study 1 than in study 2. This is because the sample size in study 1 is smaller than in study 2, which means there is more variability in the estimates due to the smaller sample size. In general, larger sample sizes lead to more precise estimates with less uncertainty.

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Datos:

Oferta:

Demanda:

Para encontrar el precio de equilibrio iguala las ecuaciones de oferta y demanda:

El precio de equilibrio lo encuentras resolviendo la ecuación arriba para p(precio):

1.

2. Para dejar los terminos con la variable p de un lado de la ecuacion resta 100p en los dos lados de la ecuacion:

The statement "TRUE" is the answer to the question "TRUE or FALSE: residuals measure the vertical distance between two observations of the response variable.

Residuals are the difference between the predicted value and the actual value. It's also referred to as the deviation. The error or deviation of an observation (sample) is computed with a residual in statistical analysis. The residual is the deviation of an observation (sample) from the prediction value or the mean value of a sample.In a linear regression, the residual is the vertical distance between the actual and predicted values.

The vertical distance between the actual and predicted values is used to compute the deviation (error) of the observation. Therefore, the statement "TRUE" is correct because residuals measure the vertical distance between two observations of the response variable.

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Answer:

79-22=8h

Step-by-step explanation:

hope this helps!

Answer:

As a fraction 0.13 (13 repeating) is 1399

Step-by-step explanation:

0.13 = 13/99

338 students went on the field trip.

Given:

Four-ninth of the total participants rode a large bus, and the rest rode a smaller bus.

156 people rode the larger bus.

Let x be the total participants.

4/9 x = 156

multiply by 9 on both sides

4*9/9 x = 156*9

4x = 156*9

4x = 1404

divide by 4 on both sides

4x/4 = 1404/4

x = 1404/4

x = 351.

number of students = total participants - adult chaperones.

= 351 -13

= 338 students

Therefore 338 students went on the field trip.

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The probability that a player will be asked a math question and then a music question is 0.03125

The size of the sections are given as:

Music = 0.5

Sport = 0.5

Others = 1

So, the total size is:

Total = 0.5 + 0.5 + 1 + 1 + 1

Evaluate

Total = 4

The probability of asking a math question is:

P(Math) = 1/4 = 0.25

The probability of asking a music question is:

P(Music) = 0.5/4 = 0.125

The required probability is:

P(Math and Music) = P(Math) * P(Music)

This gives

P(Math and Music) = 0.25 * 0.125

Evaluate

P(Math and Music) = 0.03125

Hence, the probability that a player will be asked a math question and then a music question is 0.03125

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To clear the old codes in the garage door and reprogram it access the doors motor and reprogram the remote afterwards.

Most individuals do not consider the garage door opener remote control to be a particularly valuable feature unless something goes wrong. Using the remote, the garage door can be opened from the outside.

You can unlock it by entering a PIN on the keypad outside the garage. The PIN can be activated or deactivated when you enter a personal identification number.

The door code may occasionally need to be changed. This has a number of advantages, such as improving security or getting access to your garage when you forget the code.

You could be considering how to modify the garage door code. You might try to do it yourself or ask a professional for help.

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Answer:

no point of intersection

Step-by-step explanation:

y=x-8

y=x^2-2x-3

Answer:

C) y = 1/2x - 3

Step-by-step explanation:

y - \(y_{1\\}\) = m(x - \(x_{1}\))

y - (-1) = 1/2(x - 4)

y + 1 = 1/2x - 2

y = 1/2x - 3

Answer:

Scalene

Step-by-step explanation:

All three sides are unequal from each other and are different lengths

Answer:

6/5

Step-by-step explanation:

-3/5-(-2/15)+5/6

-3/5+2/15+5/6

=-3+2×5/15 + 5/6. (taking lcm)

=-3+6/15+5/6

=3/15+5/6

=3+5×3/15 (taking lcm)

=18/15

=6/5

Answer:

Step-by-step explanation:

-3/5-(-2/15)+5/6

=-3/3+2/15(take lcm of 3 and 15)+5/6

=-3*3+2*1/15+5/6

=-9+2/15+5/6

=-7/15+5/6(take lcm of 15 and 6)

=-7*2+5*5/30

=-14+25/30

=11/30

=11/30

For the system of linear equations (2a−1)x+3y−5=0 and 3x+(b−1)y−2=0 to have infinitely many solutions, the two equations must be linearly dependent, meaning one equation can be obtained by multiplying the other equation by a constant. This can be achieved when the ratios of the coefficients of x, y, and constants in the two equations are equal, except for a scalar multiple. Therefore, setting (2a-1)/3 = -2/(b-1) = -5/2, we get a = -1/2 and b = 9.

To find the values of a and b such that the system of linear equations (2a−1)x+3y−5=0 and 3x+(b−1)y−2=0 has infinitely many solutions, we need to find the condition under which the two equations are linearly dependent.

If the two equations are linearly dependent, it means that one equation can be obtained by multiplying the other equation by a constant. Mathematically, this can be represented as:

k(2a−1)x + k(3y) − k(5) = 0 where k is a non-zero constant

and 3x + (b−1)y − 2 = 0

We can see that the coefficients of x and y in the two equations are 2a-1 and 3, and 3 and b-1, respectively. For the equations to be linearly dependent, the ratios of these coefficients must be equal, except for a scalar multiple. In other words:

(2a-1)/3 = (b-1)/(-2) = k where k is a non-zero constant

We can solve for k by setting any two ratios equal to each other. Let's set the first ratio equal to the second ratio:

(2a-1)/3 = (b-1)/(-2)

Cross-multiplying, we get:

-4a + 2 = 3b - 3

Simplifying, we get:

-4a + 3b = 5

Next, let's set the first ratio equal to the third ratio:

(2a-1)/3 = -5/2

Cross-multiplying, we get:

4a - 2 = -15

Simplifying, we get:

4a = -13

Solving for a, we get:

a = -13/4

Substituting this value of a into the equation -4a + 3b = 5, we get:

-4(-13/4) + 3b = 5

Simplifying, we get:

13 + 3b = 5

Solving for b, we get:

b = 9

Therefore, the values of a and b that make the system of linear equations (2a−1)x+3y−5=0 and 3x+(b−1)y−2=0 have infinitely many solutions are a = -1/2 and b = 9.

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A reference tool that is used to determine how the fiber is to be orientated for a particular ply of fabric is called a lay plan or lay direction.

A lay plan is a detailed diagram that shows the orientation of fibers in each layer of a fabric, and it is used as a guide for the manufacturing process. The lay plan indicates the direction in which the fibers should be oriented in each layer of the fabric, which is essential for achieving the desired strength, stretch, and durability of the final product.

The lay plan is also used to ensure that the fibers are aligned in the same direction in each layer, which helps to prevent warping or other issues that can occur during manufacturing.

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To find the Laplace transform of 6e^-3t - 2 + 2^(1-8), we can use the linearity property of the Laplace transform.

First, we can find the Laplace transform of each term separately using the Laplace transform table.

L{6e^-3t} = 6/(s+3)

L{2} = 2/s

L{2^(1-8)} = 2^(-7) * 1/s

Then, we can use the linearity property to add the Laplace transforms of each term:

L{6e^-3t - 2 + 2^(1-8)} = L{6e^-3t} - L{2} + L{2^(1-8)}

= 6/(s+3) - 2/s + 2^(-7)/s

= (6s - 2s + 2^(-7))/(s(s+3))

= (4s + 2^(-7))/(s(s+3))

Therefore, the Laplace transform of 6e^-3t - 2 + 2^(1-8) is (4s + 2^(-7))/(s(s+3)).
Hi there! To solve this problem using the Laplace transform table and linearity property, we need to find the Laplace transforms of each term individually and then combine them according to the given expression. So, let's compute the Laplace transforms:

Given expression: 6e^(-3t) - 2 + 2t^(-8)

1. L{6e^(-3t)}
Using the Laplace transform table, we have L{e^(at)} = 1/(s-a). In this case, a = -3. Therefore,
L{6e^(-3t)} = 6/(s+3)

2. L{-2}
Since the Laplace transform of a constant is L{c} = c/s, we have:
L{-2} = -2/s

3. L{2t^(-8)}
Unfortunately, the expression "2t^(-8)" is not well-defined as it represents division by t^8, which is undefined for t=0. Please recheck the given expression or provide more context to help you better.

Finally, assuming the correct expression is 6e^(-3t) - 2, the combined Laplace transform would be:

L{6e^(-3t) - 2} = 6/(s+3) - 2/s

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Answer:

if you mean to the tens place, then its 5,940

Step-by-step explanation:

Answer:

5940

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

log sqrt5  (25) = y

we know that loga (b) = c  can be rewritten as  a^c = b

sqrt(5) ^ y = 25

Rewriting sqrt(5) as 5^1/2  and 25 as  5^2

5^1/2 ^ y = 5^2

we know a^b^c = a^ (b*c)

5 ^ 1/2y = 5^2

1/2y = 2

y = 4

\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)

let's solve ~

Perimeter of the composite figure :

Perimeter of rectangle + circumference of semi circle - common side.

Perimeter of rectangle :

\(\qquad \tt \dashrightarrow \:2(4 + 12)\)

\(\qquad \tt \dashrightarrow \:2(16)\)

\(\qquad \tt \dashrightarrow \:32 \: \: ft {}^{} \)

Circumference of Semicircle :

\(\qquad \tt \dashrightarrow \:\pi r\)

\(\qquad \tt \dashrightarrow \:3.14 \times 2\)

\(\qquad \tt \dashrightarrow \:6.28 \: ft\)

Length of common side = 4 feet

So, perimeter of composite figure :

\(\qquad \tt \dashrightarrow \:32 + 6.28 - 4\)

\(\qquad \tt \dashrightarrow \:34.28 \: ft\)

So, the percentage of data values represented on a box plot that falls between the lower quartile and the upper quartile is 50%.

In a box plot, the lower quartile (Q1) represents the 25th percentile, and the upper quartile (Q3) represents the 75th percentile. The interquartile range (IQR) is the range between the lower quartile and the upper quartile. To determine the percentage of data values that fall between the lower quartile and the upper quartile, we need to consider the IQR.

The IQR represents the middle 50% of the data. Therefore, the percentage of data values between the lower quartile and the upper quartile is 50%. In other words, half of the data values are within the IQR range, while the remaining 50% are outside this range, including the lower 25% below the lower quartile and the upper 25% above the upper quartile.

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An algebraic expression which represents this word description "8 divided by the sum of 7 and v" is 8/(7 + v).

In Mathematics, a quotient can be defined as a mathematical expression that is simply used to represent the division of a number by another number.

In order to translate this word problem into algebraic equation, we would assign a variable to the unknown number and then translate the word problem into algebraic equation as follows:

Let the variable v represent the unknown number.

Translating the word problem into an algebraic equation, we have the following;

Quotient = 8/(7 + v)

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The value of x is -1 4/5 i.e, Therefore, the correct option is A

Define Algebraic Expression

The concept of algebraic expressions is the use of letters or alphabets to represent numbers without providing their precise values. We learned how to express an unknown value using letters like x, y, and z in the fundamentals of algebra. Here, we refer to these letters as variables. Variables and constants can both be used in an algebraic expression. A coefficient is any value that is added before a variable and then multiplied by it. In mathematics, an expression that incorporates variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.).

Given expression,

-2/9 x=2/5

Isolate the variable, x

x = (2 * 9) / ( 5 * -2)

x = - (9/5) or -1 4/5

Hence, the value of x is -1 4/5 i.e, option(A)

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The equation Ant can use to determine the total cost (y) for any large pizza, regardless of the number of toppings ordered (x), is y = 12 + 0.50x.

The equation is formed by considering the base cost of a large cheese pizza, which is $12. Each additional topping adds $0.50 to the total cost.

The variable x represents the number of toppings ordered, and y represents the total cost of the pizza. Multiplying the number of toppings (x) by the cost per topping ($0.50) gives the additional cost of the toppings.

By adding the base cost of the large cheese pizza ($12) to the additional cost of the toppings (0.50x), we obtain the equation y = 12 + 0.50x. This equation allows Ant to calculate the total cost for any large pizza based on the number of toppings chosen.

For example, if a customer orders 3 toppings, substituting x = 3 into the equation gives y = 12 + 0.50 * 3 = 12 + 1.50 = $13.50. Hence, the total cost for a large pizza with 3 toppings would be $13.50.

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Step-by-step explanation:

she sell 5piece out of 6 per hour

for 36 hour, she sell:

5 × 36 = 180piece of pie

one pie is cut to 6 piece

180/6 = 30pie

Let f(x) = 3x³ / (x - 5)At what x-values is f′(x) zero or undefined?To find the first derivative of f(x), we apply the quotient rule and simplify:f′(x) = (9x² - 45x²) / (x - 5)²The numerator is equal to zero only when 9x² - 45 = 0, which is equivalent to x² = 5.

Thus, f′(x) is zero when x = ±√5.The denominator (x - 5)² is zero only when x = 5. Therefore, f′(x) is undefined when x = 5.The values of x for which f′(x) is zero or undefined are x = -√5, 5, and √5. Thus, the answer is: x = -√5, 5, √5On what interval(s) is f(x) increasing?We find the critical values of f(x) by solving the inequality f′(x) > 0. We create a sign chart to determine the intervals on which f(x) is increasing and decreasing:x-√55√5x5+√5f′(x)+--+--f(x)↓↑↓↑↓Thus, f(x) is increasing on the intervals (-∞, -√5) U (√5, 5) and decreasing on the interval (-√5, √5) U (5, ∞).

Thus, the answer is: f(x) is increasing for x in (-∞, -√5) U (√5, 5) On what interval(s) is f(x) decreasing?We find the critical values of f(x) by solving the inequality f′(x) < 0. We create a sign chart to determine the intervals on which f(x) is increasing and decreasing Thus, f(x) is increasing on the intervals and decreasing on the interval (-√5, √5) U (5, ∞). Thus, the answer is: f(x) is decreasing for x in (-√5, √5) U (5, ∞).

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Answer:

L= 90, M=53, K=37

Step-by-step explanation:

Tilt your phone/computer to the right, and you'll see the 90° angle for L. Now you're left with two more, and just compare which angle is bigger, K or M. M is bigger, so you apply the bigger number out of the you got which is 53. Now no doubts, K is 37.

There are 87 possible outcomes that contain at least three heads when a coin is flipped 9 times.

When a coin is flipped nine times, there are 512 possible outcomes, or 29. Using the equation:

P (At least one head) = 1 - 0.5n,

where n is the total number of flips, we can determine the number of outcomes that contain at least three heads.

Therefore, P (At least three heads) = 1 - P (No heads) - P (One head) - P (Two heads)

= 1 - (0.5)⁹ - 9(0.5)⁹ + 36(0.5)⁹

= 0.1718751.

The formula used to calculate the number of possible outcomes that contain at least three heads is C(9,3) + C(9,4) + C(9,5) + C(9,6) + C(9,7) + C(9,8) + C(9,9),

where C(n,r) denotes the variety of options for selecting item(s) r from a set of item(s) n.

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Answer:

y=1

x=5/2

Step-by-step explanation:

4x-9y=1

(2x+y=-5)-2

4x-9y=1

-4x-2y=10

_________

-11y=11

y=-1

4x-9y=1

4x-9(1)=1

4x=10

x=10/4

x=5/2