Evaluate 2x-y for x=3 and y= -2
A. 10
B. 14
C. 18
D. 20

Answer:

C

Step-by-step explanation:

Substitute x = -1 into    \(f(x)=-\sqrt[3]{x-7}+3\) :

\(f(x)=-\sqrt[3]{-1-7}+3=-\sqrt[3]{-8}+3=2+3=5\)

Substitute x = 7 into    \(f(x)=-\sqrt[3]{x-7}+3\) :

\(f(x)=-\sqrt[3]{7-7}+3=-\sqrt[3]{0}+3=0+3=3\)

Answer:

y=-4/5+8/5, or y= -.8+1.6

Step-by-step explanation:

Slope intercept form-

y=mx+b

y=-4/5+8/5

Step-by-step explanation:

2(2x - 6) + 2(x + 3) = 26

4x - 12 + 2x + 6 = 26

4x + 2x -12 + 6 = 26

6x - 6 = 26

6x = 26 + 6

6x = 32

x =32/6

x = 5.3333

Answer:

Step-by-step explanation:

2(2x -6) + 2(x + 3) = 26

4x - 12 + 2x + 6 = 26

6x - 6 = 26

6x = 32

x = 32/6= 16/3

Answer:

amoung us

Step-by-step explanation:

Answer:

among us

Step-by-step explanation:

Answer:300

Step-by-step explanation:

Answer:

answer is 300

hope it helps

plz mark as brainliest

Answer:

y= 3/2x + 1

Step-by-step explanation:

slope intercept form is y=mx+b. the m is the slope and the b is the y intercept. the y intercept is 1, where it crosses the y axis. the slope is 3/2 because from the y intercept which is 1, you go up 3 and over 2 right.

Answer:i don't know really im just another student and i'm just doing this for the points my guy so don't be mad if you get a bad response

Step-by-step explanation:

1. I have no idea

Step-by-step explanation:

v = u + at

v-u = at

a = (v -u)/t

When t = 4, u=10, v=50

a = (50-10)/4

a= 40/4

a = 10

300 must be subtracted from the product of 25 and 23 to equal 275.

To do dilatation a triangle by a scale factor of k, we have to multiply the x and y-value of each triangle point by k.

A coordinate plane is a system that graphs and describes the position of points and lines. It consists of horizontal (x) and vertical (y) axes.

We can perform dilatation for a point or line in a coordinate plane system based on specific criteria.

Dilation is a form of image transformation that produces a new image, which is larger, or smaller, based on a certain scale factor. The new image is the same in shape, but different in size.

The rule of dilatation:

\(D_{k}\)(x,y) = (kx, ky)

where \(D_{k}\) is the point of the new image and k is the scale factor.

When we want to dilate a triangle ABC, the result can be found by multiplying its original points with the scale factor.

For example:

Triangle ABC (-2,2), (-2,3), (1,2) is dilated by a scale factor of 2. The new triangle A'B'C' will be A’(-4,4), B’ (-4,6), and C’ (2,4).

Thus, to dilate a triangle by a scale factor of k, we have to multiply the x and y-value of each triangle point by k.

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Answer:

0.9

Step-by-step explanation:

1.2/4 is 0.3.   and 0.9/3 is 0.3. so... yeah

The perimeter of triangle GHI is determined as 112.

The perimeter of triangle GHI is determined by calculating the distance round the triangle GHI.

The given parameters include;

length GI = 52

length KI = length LI = 15

Length GL = GI - LI

GL = 52 - 15

GL = 37

Length GJ = GL = 37

Length GH = GJ + JH

GH = 37 + 4

GH = 41

Length HI is calculated as;

HI = HK + KI

HK = HJ = 4

HI = 4 + 15

HI = 19

The perimeter of triangle GHI is calculated as;

P = GI + GH + HI

P = 52 + 41 + 19

P = 112

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Answer:

The equation of a vertical line in the graph, which is parallel to y-axis is x = a. The slope of a vertical line is infinity or undefined as it has no y-intercept and the denominator in the slope formula is zero.

Step-by-step explanation:

a) The set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.

To find the set of values of k for which the line and curve meet at two distinct points, we need to solve the equation:

x^2 - kx + 2 = 3kx - 2k

Rearranging, we get:

x^2 - (3k + k)x + 2k + 2 = 0

For the line and curve to meet at two distinct points, this equation must have two distinct real roots. This means that the discriminant of the quadratic equation must be greater than zero:

(3k + k)^2 - 4(2k + 2) > 0

Simplifying, we get:

5k^2 - 8k - 8 > 0

Using the quadratic formula, we can find the roots of this inequality:

\(k < (-(-8) - \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = -2/5\\ or\\ k > (-(-8)) + \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = 2\)

Therefore, the set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.

b) To find the two values of k for which the line is a tangent to the curve, we need to find the values of k for which the line is parallel to the tangent to the curve at the point of intersection. For m to be the slope of the tangent at the point of intersection, we need to have:

2x - 4 = m

3k = m

Substituting the first equation into the second, we get:

3k = 2x - 4

Solving for x, we get:

x = (3/2)k + (2/3)

Substituting this value of x into the equation of the curve, we get:

y = ((3/2)k + (2/3))^2 - k((3/2)k + (2/3)) + 2

Simplifying, we get:

y = (9/4)k^2 + (8/9) - (5/3)k

For this equation to have a double root, the discriminant must be zero:

(-5/3)^2 - 4(9/4)(8/9) = 0

Simplifying, we get:

25/9 - 8/3 = 0

Therefore, the constant term is 8/3. Solving for k, we get:

(9/4)k^2 - (5/3)k + 8/3 = 0

Using the quadratic formula, we get:

\(k = (-(-5/3) ± \sqrt{((-5/3)^2 - 4(9/4)(8/3)))} / (2(9/4)) = -1/3 \\or \\k= 4/3\)

Therefore, the two values of k for which the line is a tangent to the curve are k = -1/3 and k = 4/3. To show that the two tangents meet on the x-axis, we can find the x-coordinate of the point of intersection:

For k = -1/3, the x-coordinate is x = (3/2)(-1/3) + (2/3) = 1

For k = 4/3, the x-coordinate is x = (3/2)(4/3) + (2/3) = 3

Therefore, the two tangents meet on the x-axis at x = 2.

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In a sample of 28 participants, suppose we conduct an analysis of regression with one predictor variable. If Fobt= 4.28, then the decision for this test at a .05 level of significance is there is not enough information to answer this question, option C.

To determine the decision for a regression analysis with one predictor variable at a 0.05 level of significance, we need to compare the observed F-statistic (Fobt) with the critical F-value.

Since the degrees of freedom for the numerator is 1 and the degrees of freedom for the denominator is 26 (28 participants - 2 parameters estimated), we can find the critical F-value from the F-distribution table or using statistical software.

Let's assume that the critical F-value at a 0.05 level of significance for this test is Fcrit.

If Fobt > Fcrit, then we reject the null hypothesis and conclude that X significantly predicts Y.

If Fobt ≤ Fcrit, then we fail to reject the null hypothesis and conclude that X does not significantly predict Y.

Since the information about the critical F-value is not provided, we cannot determine the decision for this test at a 0.05 level of significance. Therefore, the correct answer is C) There is not enough information to answer this question.

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Answer:

The first one is - 5 and the other is - 40

Spherical harmonics are an integral part of quantum mechanics. They describe the shape of the orbitals, which electrons occupy in atoms. Moreover, the spherical harmonics provide the angular distribution of a wave in spherical coordinates. In 3D, the spherical harmonics can be written as:

Ylm(θ, φ) = √(2l + 1)/(4π) * √[(l - m)!/(l + m)!] * Plm(cosθ) * e^(imφ)

Here, l and m are known as the angular quantum numbers. They define the shape and orientation of the orbital. Plm(cosθ) represents the associated Legendre polynomial, and e^(imφ) is the exponential function. The spherical harmonics have various forms, including:

Y1,1 = -Y1,-1 = 1/2 √(3/2π) sinθe^(iφ)

Y1,0 = 1/2 √(3/π)cosθ

Y2,2 = 1/4 √(15/2π)sin²θe^(2iφ)

Y2,1 = -Y2,-1 = 1/2 √(15/2π)sinθcosφ

Y2,0 = 1/4 √(5/π)(3cos²θ-1)

Y0,0 = 1/√(4π)

The spherical harmonics have various applications in physics, including quantum mechanics, electrodynamics, and acoustics. They play a crucial role in understanding the symmetry of various systems. Hence, the spherical harmonics are an essential mathematical tool in modern physics. Thus, this is how one can show another form for spherical harmonics.

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Answer:

f(x) = -x^2 is a downward parabola.

Step-by-step explanation:

The f(x) = x^2 graph is a parabola pointing up. Therefore, f(x) = -x^2 is a downward parabola.

The equation of the line in point-slope form is:

y - 8 = 3(x + 6) or y - 2 = 3(x + 8).

The equation, y - b = m(x - a), represents the equation of a line in point-slope form, where:

Given two points, (-8, 2) and (-6, 8), find the slope (m) of the line that passes through the two points:

Slope (m) = change in y / change in x = (8 - 2)/(-6 -(-8))

Slope (m) = 6/2

Slope (m) = 3

Substitute m = 3 and (-6, 8) into y - b = m(x - a):

y - 8 = 3(x - (-6))

y - 8 = 3(x + 6)

Or substitute m = 3 and (-8, 2) into y - b = m(x - a):

y - 2 = 3(x - (-8))

y - 2 = 3(x + 8)

Therefore, the equation of the line in point-slope form is:

y - 8 = 3(x + 6) or y - 2 = 3(x + 8).

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Answer: 75% off the original price.

Step-by-step explanation:Say an item is $100.  50% off $100 is of coarse $50.

Now 50% off that price is $25.

So the new price is now $25 which is 75% off.

Answer:

c. 75%

Step-by-step explanation:

just took the test

brainliest pls?

Answer:

1/2 + 1/3 = 3/6 + 2/6 = 5/6

5/6 roughly equals to 0.8

The answer is C

Which of the following best estmates the sum: 1/2 + 1/3

Answer: C) 0.8

Based on the differential equation a) Solving the DE subject to P(0) = P0 will yield P = ((kP0 - h)e^(kt) + h)/k. b) For the three cases given (P0 > h/k, P0 = h/k, P0 = 0), the behavior of the population P(t) is will be population will grow without bound, the population will remain constant, and the population will decrease and approach zero as t approaches infinity respectively. c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. At T = (1/k)ln(-h/(kP0 - h)) the fish population will go extinct.

(a) To solve the differential equation (dP/dt) = kP - h subject to P(0) = P0, we need to separate the variables and integrate both sides:

(dP/dt) = kP - h

dP/(kP - h) = dt

∫dP/(kP - h) = ∫dt

ln|kP - h| = kt + C

kP - h = e^(kt + C)

P = (e^(kt + C) + h)/k

Using the initial condition P(0) = P0, we can solve for C:

P0 = (e^(k*0 + C) + h)/k

P0 = (e^C + h)/k

e^C = kP0 - h

C = ln(kP0 - h)

Substituting back into the equation for P, we get:

P = (e^(kt + ln(kP0 - h)) + h)/k

P = ((kP0 - h)e^(kt) + h)/k

This is the solution to the differential equation subject to the initial condition P(0) = P0.

(b) The behavior of the population P(t) for increasing time depends on the initial condition P0:

- If P0 > h/k, then the term (kP0 - h)e^(kt) will be positive and will increase exponentially as t increases, so the population will grow without bound.

- If P0 = h/k, then the term (kP0 - h)e^(kt) will be zero and the population will remain constant at P = h/k for all time.

- If P0 < h/k, then the term (kP0 - h)e^(kt) will be negative and will decrease exponentially as t increases, so the population will decrease and approach zero as t approaches infinity.

(c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. From the equation for P, we can see that this will happen if and only if P0 < h/k:

P(T) = ((kP0 - h)e^(kT) + h)/k = 0

(kP0 - h)e^(kT) = -h

e^(kT) = -h/(kP0 - h)

Since the exponential function is always positive, this equation has no solution for P0 > h/k or P0 = h/k. However, if P0 < h/k, then the term (kP0 - h) is negative and the equation has a solution:

kT = ln(-h/(kP0 - h))

T = (1/k)ln(-h/(kP0 - h))

This is the time at which the fish population will go extinct.

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Answer:

there will be 8 rows

the number of photographs in each row is 8

Answer:

A. 80

Step-by-step explanation:

2 is corresponding to 6 and 6 is vertical with 7. Making them all congruent. And since we know 7 is 80 degrees then there is your answer. Hope that helped :))

Answer:

- 36

Step-by-step explanation:

First evaluate g(18), then substitute the value obtained into h(x), then substitute the value obtained here into f(x).

g(18) = \(\sqrt{2(18)}\) = \(\sqrt{36}\) = 6, then

h(6) = | 4(6) | - 12 = | 24 | - 12 = 24 - 12 = 12, then

f(12) = - 3(12) = - 36

23.4587 hectares is equal to 2,529,708.3512 square survey feet. 23.4587 hectares is equal to 57.9965 acres. 23.4587 hectares is equal to 0.9272 square Gunter's Chains.

Given: 23.4587 ha

To convert 23.4587 hectares to square survey feet, acres and square Gunter's Chains Conversions:

1 Hectare = 107639.1041671 Square Survey Feet

1 Hectare = 2.47105381 Acres

1 Hectare = 0.0395369 Square Gunter's Chains

To convert 23.4587 hectares to square survey feet, multiply by the conversion factor.

23.4587 ha × 107639.1041671 square survey feet/ha = 2529708.3512 square survey feet

Therefore, 23.4587 hectares is equal to 2,529,708.3512 square survey feet.

To convert 23.4587 hectares to acres, multiply by the conversion factor.

23.4587 ha × 2.47105381 acres/ha = 57.9965 acres

Therefore, 23.4587 hectares is equal to 57.9965 acres.

To convert 23.4587 hectares to square Gunter's Chains, multiply by the conversion factor.

23.4587 ha × 0.0395369 square Gunter's Chains/ha = 0.9272 square Gunter's Chains

Therefore, 23.4587 hectares is equal to 0.9272 square Gunter's Chains.

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The 90% confidence interval for the average speed of all the cars passing through the intersection is (41.29, 42.71) miles per hour.

To calculate the confidence interval, we can use the formula:

Confidence interval = Sample mean ± (Critical value * Standard error)

Given that the sample mean is 42 miles per hour and the standard deviation is 4.2 miles per hour, we need to determine the critical value and the standard error.

Since we have a sample size of 85, we can use the t-distribution with (n-1) degrees of freedom to find the critical value. With a 90% confidence level, the corresponding critical value for a two-tailed test is approximately 1.66.

The standard error is calculated as the standard deviation divided by the square root of the sample size:

Standard error = (Standard deviation) / √(Sample size)

Standard error = 4.2 / √85 ≈ 0.456

Now we can plug in the values into the confidence interval formula:

Confidence interval = 42 ± (1.66 * 0.456)

Confidence interval ≈ (41.29, 42.71)

Therefore, the 90% confidence interval for the average speed of all the cars passing through the intersection is (41.29, 42.71) miles per hour.

Based on the given data and calculations, we can conclude that with 90% confidence, the average speed of all the cars passing through the intersection falls within the range of 41.29 to 42.71 miles per hour.

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