Eurostar is a high speed rail service that connects London to Paris. The distance from London to the English Channel Tunnel is 108. 0 km. The English Channel Tunnel is 50. 5 km long. The distance from the English Channel Tunnel to Paris is 316. 0 km. The train travels at a maximum speed of 300 km/hr except within the English Channel Tunnel, where a reduced speed of 160 km/hr is required for safety reasons. A. How long does the journey from London to Paris take? Give you answer in s. B. If the resistance between the train and the track at maximum speed is 120 kN and air resistance adds an additional 20. 5 kN (Note: Power = force x velocity), what is the power in horsepower required to power the engine?

Answer:

commercial freezing

Explanation:

smaller ice crystals are formed this causes less damage to cell membranes so the quality is less effected

Answer:

c +5

Explanation:

we have difference in energy =

2.18x10⁻¹⁸ x z² / n²

now n = 1

amount of energy absorbed Δdelta = 7.84×10−17 J

7.84×10⁻¹⁷ = 2.18x10⁻¹⁸ x z²

we divide through by 2.18x10⁻¹⁸

z² = 7.84×10⁻¹⁷ / 2.18x10⁻¹⁸

z² = 35.9633

z = √35.9633

z = 5.9969

≈ 6

charge = atomic number 6 - number of electrons available in the element 1

= 6-1 = 5

from the calculations above, the charge of the one electron specie would be c +5

Connect the multimeter's positive (red) probe first to the collector, then the emitter, then the multimeter's negative (often a black probe) probe to the base output.

A reading between 500 and 1500 Ohms indicates the transistor is operating properly. For proper test results, remove the transistor from the circuit. Connect the multimeter's positive lead to the transistor's BASE (B). Connect the negative meter lead to the transistor's EMITTER (E). The meter should display a voltage drop between 0.45V and 0.9V if the NPN transistor is functioning properly. Testing the junction resistance of a transistor will show leakage, shorts, and openings. GAIN TEST FOR TRANSISTOR. Using an ohmmeter, a simple transistor gain test can be performed.

Learn more about transistor here-

https://brainly.com/question/29892962

#SPJ4

To calculate the mean of all numeric variables in the HELPrct data from the mosaicData package, we can use the colMeans() function in R. This function calculates the mean of each column in a data frame.

However, it only works on numeric columns, so we need to first remove any non-numeric columns or missing values.
To do this, we can use the select_if() function from the dplyr package to only select columns that are numeric. Then, we can use the na.omit() function to remove any rows with missing values. Finally, we can use the colMeans() function to calculate the mean of each column.
Here's the code:
library(mosaicData)
library(dplyr)
# Select only numeric columns
numeric_cols <- select_if(HELPrct, is.numeric)
# Remove rows with missing values
numeric_cols <- na.omit(numeric_cols)
# Calculate column means
means <- colMeans(numeric_cols)
# Print the result
print(means)
This will give us the mean of each numeric column in the HELPrct data, excluding any missing values.

For more such questions on variables visit:

https://brainly.com/question/30317504

#SPJ11

inhalation is the most common way for chemical to enter the body

The Z value will be  400 units.

As given Annual demand (D)=1000 units, Carrying cost (H)=$10 per unit, set up cost (S)=$400.

As per the production order model formula will be:

\sqrt{2}D*S/H[1-d/p]} .

d for week=1000/50

                =20. p per day

                =40 units/7 days.

                =5.71

d per day = 20/7

               =2.85

Therefore on applying all these:\sqrt{}2*1000*400/10[1-2.85/5.7.

on solving this we will get 400 Units

Therefore, The best batch size for this item is 400 units.

To learn more about Z value visit:

https://brainly.com/question/13399886

#SPJ1

Answer:

The answer is below

Explanation:

Given that:

\(k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m\)

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

\(V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s\)

c) The load torque is given as:

\(T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm\)

A hunter is raising his game off the ground in a game bag using the setup shown, the elevation of the bottom of the bag above the ground is 1.30 m (5 m - (-5 m) - 1 m).

To solve this problem, we can use the equations of motion for uniformly accelerated motion and the kinematic equations for constant acceleration.

First, let's find the position function of the bag as a function of time. The acceleration of the bag is given by:

a = 0.5 - 0.05x

We can integrate this expression to obtain the velocity function:

v = ∫(0.5 - 0.05x) dt = 0.5t - 0.025x^2 + C1

where C1 is the constant of integration, which we can determine from the initial conditions. At t = 0 and x = 0, we have v = 0, so:

0 = 0 + 0 + C1

C1 = 0

Therefore, the velocity function is:

v = 0.5t - 0.025x^2

We can now integrate this expression to obtain the position function:

x = ∫(0.5t - 0.025x^2) dt = 0.25t^2 - 0.00833x^3 + C2

where C2 is the constant of integration, which we can determine from the initial conditions. At t = 0 and x = 0, we have x = 2, so:

2 = 0 + 0 + C2

C2 = 2

Therefore, the position function is:

x = 0.25t^2 - 0.00833x^3 + 2

Next, let's find the tension in the cable as a function of position. The weight of the bag is given by:

W = mg

where m is the mass of the bag and g is the acceleration due to gravity. The tension in the cable is equal to the weight of the bag plus the force required to accelerate it:

T = W + ma

Substituting for W and a, we have:

T = mg + m(0.5 - 0.05x)

T = m(0.5 - 0.05x + g)

Using the given values, we have:

m = 10 kg

g = 9.8 m/s^2

Therefore, the tension in the cable is:

T = 10(0.5 - 0.05x + 9.8) = 103 - 5x

Finally, let's use the position function and the tension function to find the elevation of the bottom of the bag and the upward velocity of the bag when the hunter is 2 meters to the left (i.e., when x = -2).

The elevation of the bottom of the bag above the ground is given by:

y = 5 - (9 - x) - 1 = -3 + x

At x = -2, we have:

y = -3 + (-2) = -5 m

Therefore, the elevation of the bottom of the bag above the ground is 1.30 m (5 m - (-5 m) - 1 m).

The upward velocity of the bag is given by:

v = (T - mg)/m

Substituting for T and m, we have:

v = (103 - 5x - 98)/10

At x = -2, we have:

v = (103 - 5(-2) - 98)/10 = 0.372 m/s

Therefore, the upward velocity of the bag when the hunter is 2 meters to the left is 0.372 m/s.

For more details regarding velocity, visit:

https://brainly.com/question/17127206

#SPJ1

Answer:

142.825 m³/sec

Explanation:

Let the discharge of this stream = Q1

200g/L = 200x10³mg/L

Q2 = 200x10³ ppm

C1 = 10

C2 = 0.025

Qmix * Cmix = c1Q1 + c2Q2

(Q1+0.025)45 = 10xQ1 + 0.025*200x10³

45Q1 + 1.125 = 10Q1 + 5000

45Q1 -10Q1 = 5000 - 1.125

35q1 = 4998.875

Q1 = 4998.875/35

Q2 = 142.825 m³/sec

142.825 m³/sec is therefore the estimated discharge from the stream.

Cause and Effect Diagram (also known as Fishbone Diagram):

When analyzing the failure of the coffee maker using a Cause and Effect Diagram, we can identify various potential causes leading to the issue of no coffee being supplied. The main categories of causes and their subcategories can be represented as follows:

1. Equipment:

  - Faulty on/off switch

  - Malfunctioning heating element

  - Clogged water filter

2. Materials:

  - Low-quality coffee beans

  - Insufficient water supply

3. Process:

  - Improper coffee ground measurement

  - Incorrect brewing temperature

  - Inadequate brewing time

4. People:

  - User error in operating the coffee maker

  - Lack of maintenance and cleaning

Root Cause Analysis:

To perform a Root Cause Analysis for the failure of no coffee being supplied, we delve deeper into identifying the underlying root cause(s). This involves a systematic investigation to identify the primary reason(s) leading to the failure. The analysis may include techniques such as 5 Whys, Fault Tree Analysis, or Failure Mode and Effects Analysis (FMEA).

Example of a potential root cause identified through analysis:

Root Cause: Faulty on/off switch

Further analysis may involve determining why the on/off switch is faulty, such as a manufacturing defect, electrical wiring issue, or wear and tear.

It's important to note that the above examples are not an exhaustive analysis but demonstrate how a Cause and Effect Diagram and Root Cause Analysis can be applied to understand the failure of the coffee maker in terms of causes and underlying root cause(s).

Learn more about systematic investigation  here:

https://brainly.com/question/33510083

#SPJ11

Answer:

The temperature of the outer wall surface will be closer to the temperature of the surrounding air.

Explanation

Since the outer wall has a convective heat transfer coefficient that is 3 time the one in the inner surface due to the wind, the outer wall will have a temperature closer to the surrounding air's temperature because the heat that flows from the warmer inner room wall will be rapidly conducted away from the surface of the outer wall by the prevailing wind, leaving it with a reduced temperature that will be closer to the temperature of the surrounding air.

The thing that happens when a capacitor is connected to a DC source is that Capacitors charge up until the voltage across the capacitor is equal to the externally applied voltage when they are linked across a direct current DC supply voltage.

Capacitors slowly charge in a DC circuit until the charging voltage of the capacitor is equal to the supply voltage. The capacitor will not permit any extra charges to travel through it after it has been fully charged.

Note that the link between a capacitor and voltage and current can be summarized as follows: the capacitance and the rate of rise or fall of the voltage determine how much current flows through a capacitor. A strong positive current will be produced through a capacitor if the voltage across the capacitor rises quickly.

Learn more about capacitor from

https://brainly.com/question/14883923
#SPJ1

The minimum safety power that is safely dissipated using a transistor of height 0.4cm and diameter 0.06cm is 0.04665

\(\pi DL +\frac{\pi }{4} D^2\\\\Area = 3.14 * 0.6*0.4+\frac{3.14}{4} *0.6^2\)

D = diameter = 0.6cm

Length = height = 0.4cm

Area = 1.0367cm²

hA (Ts - Tair)

30 * 1.0367 x 10⁻⁴(70-55)

= 0.04665

The minimum safety power that is safely dissipated is 0.04665W

Read more on energy here: https://brainly.com/question/13881533

The equivalent to the man command generally provides info

Info is a shortened form of the word information. It is all about the facts about something or someone that are provided or learned and exemplified by a specific arrangement.

Information regarding sessions, processes and Remote Desktop Session Host servers can be seen in the reference article for the query commands.

The database objects can be searched for with the query command. During a search, it evaluates a query expression. Any query clause from query-related options and query_string argument can make up the query expression.

Your question is incomplete, but most probably your whole question was:

What equivalent to the 'man' command generally provides an easier-to-read description of the queried command and contains links to other related information?

a. who

b. man help

c. man -descriptive

d. info

learn more about the information here:https://brainly.com/question/24621985

#SPJ4

Answer:

\(\mathbf{F_{AB} = 13785.06 N }\)

\(\mathbf{F_{AC} = -5062.38 N }\)

\(\mathbf{F_{AD} = -5062.38 N }\)

Explanation:

From the given information:

Let calculate the position vector of AB, AC, and AD

To start with AB; in order to calculate the position vector of AB ; we have:

\(r_{AB}^{\to} = r _{OA}^{\to} - r_{OB}^{\to} \\ \\ r_{AB}^{\to} = (2.6 \ \hat i + 2.6 \ \hat j - 2.2 \ \hat k ) - ( 1.5 \ \hat i + \ 1. 5 \hat j ) \\ \\ r_{AB}^{\to} = ( 2.6 \ \hat i - 1.5 \ \hat i + 2.6 \ \hat j - 1.5 \ \hat j - 2.2 \ \hat k) \\ \\ r_{AB}^{\to} = (1.1 \ \hat i + 1.1 \ \hat j - 2.2 \ \hat k ) m\)

To calculate the position vector of AC; we have:

\(r_{AC}^{\to} = r _{OA}^{\to} - r_{OC}^{\to} \\ \\ r_{AC}^{\to} = (2.6 \ \hat i + 2.6 \ \hat j - 2.2 \ \hat k ) - ( 2\ \hat i + \ \hat j - 1.2 \ \hat k) \\ \\ r_{AC}^{\to} = ( 2.6 \ \hat i - 2\ \hat i + 2.6 \ \hat j - \ \hat j - 2.2 \ \hat k + 1.2 \ \hat k) \\ \\ r_{AC}^{\to} = (0.6 \ \hat i + 1.6 \ \hat j - \ \hat k ) m\)

To calculate the position vector of AD ; we have:

\(r_{AD}^{\to} = r _{OA}^{\to} - r_{OD}^{\to} \\ \\ r_{AC}^{\to} = (2.6 \ \hat i + 2.6 \ \hat j - 2.2 \ \hat k ) - ( \hat i + \ 2 \hat j - 1.2 \ \hat k) \\ \\ r_{AD}^{\to} = ( 2.6 \ \hat i - \hat i + 2.6 \ \hat j - 2 \ \hat j - 2.2 \ \hat k + 1.2 \ \hat k) \\ \\ r_{AD}^{\to} = (1.6 \ \hat i + 0.6 \ \hat j - \ \hat k ) m\)

However; let's calculate the force in AB, AC and AD in their respective unit vector form;

To start with unit vector AB by using the following expression; we have:

\(F_{AB}^{\to} = F_{AB} \dfrac{ r _{AB}^{\to} }{|r_{AB}^{\to}} \\ \\ \\ F_{AB}^{\to} = F_{AB} \dfrac{(1.1 \ \hat i + 1.1 \ \hat j - 2.2 \ \hat k ) }{\sqrt{ (1.1)^2 + (1.1)^2 + (-2.2 )^2 }} \\ \\ \\ F_{AB}^{\to} = F_{AB} \dfrac{(1.1 \ \hat i + 1.1 \ \hat j - 2.2 \ \hat k ) }{ \sqrt{7.26}} \\ \\ \\ F_{AB}^{\to} = F_{AB} \dfrac{(1.1 \ \hat i + 1.1 \ \hat j - 2.2 \ \hat k ) }{ 2.6944} \\ \\ \\ F_{AB}^{\to} = F_{AB} (0.408 \ \hat i+ 0.408 \ \hat j - 0.8165 \ \hat k ) N\\\)

The force AC in unit vector form is ;

\(F_{AC}^{\to} = F_{AC} \dfrac{ r _{AC}^{\to} }{|r_{AC}^{\to}} \\ \\ \\ F_{AC}^{\to} = F_{AC} \dfrac{(0.6 \ \hat i + 1.6 \ \hat j - \ \hat k ) }{\sqrt{ (0.6)^2 + (1.6)^2 + (-1 )^2 }} \\ \\ \\ F_{AC}^{\to} = F_{AC} \dfrac{(0.6 \ \hat i + 1.6 \ \hat j - \ \hat k ) }{ \sqrt{3.92}} \\ \\ \\ F_{AC}^{\to} = F_{AC} \dfrac{(0.6 \ \hat i + 1.6 \ \hat j - \ \hat k ) }{1.9798} \\ \\ \\ F_{AC}^{\to} = F_{AC} (0.303 \ \hat i+ 0.808 \ \hat j - 0.505 \ \hat k ) N\\\)

The force AD in unit vector form is ;

\(F_{AD}^{\to} = F_{AD} \dfrac{ r _{AD}^{\to} }{|r_{AD}^{\to}|} \\ \\ \\ F_{AD}^{\to} = F_{AD} \dfrac{(1.6 \ \hat i + 0.6 \ \hat j - \ \hat k ) }{\sqrt{ (1.6)^2 + (0.6)^2 + (-1 )^2 }} \\ \\ \\ F_{AD}^{\to} = F_{AD} \dfrac{(1.6 \ \hat i + 0.6 \ \hat j - \ \hat k ) }{ \sqrt{3.92}} \\ \\ \\ F_{AD}^{\to} = F_{AD} \dfrac{(1.6 \ \hat i + 0.6 \ \hat j - \ \hat k ) }{1.9798} \\ \\ \\ F_{AD}^{\to} = F_{AD} (0.808 \ \hat i+ 0.303 \ \hat j - 0.505 \ \hat k ) N\\\)

Similarly ; the weight of the lunar Module is:

W = mg

where;

mass = 13500 kg

acceleration due to gravity=  1.82 m/s²

W = 13500 × 1.82

W = 24,570 N

Also. we known that the load is shared by four landing gears; Thus, the vertical reaction force exerted by the ground on each landing gear can be expressed as:

\(R =\dfrac{W}{4}\)

\(R =\dfrac{24,570}{4}\)

R = 6142.5 N

Now; the reaction force at point A in unit vector form is :

\(R^{\to} = Rk^{\to} \\ \\ R^{\to} = (6142.5 \ k ^{\to}) \ N\)

Using the force equilibrium at the meeting point of the coordinates at A.

\(\sum F^{\to} = 0\)

\(F_{AB}^{\to} +F_{AC}^{\to} + F_{AD}^{\to} + R^{\to} =0\)

\([F_{AB} (0.408 \ \hat i + 0.408 \ \hat j - 0.8165 \ \hat k ) N + F_{AC} (0.303 \ \hat i + 0.808 \ \hat j - 0.505 \ \hat k ) N + F_{AD} (0.808 \ \hat i + 0.303 \ \hat j - 0.505 \ \hat k) N + (6142.5 \ k^ \to ) ]\)

\(= [ ( 0.408 F_{AB} +0.303 F_{AC} + 0.808F_{AD}) \hat i + (0.408 F_{AB}+0.808F_{AC}+0.303F_{AD}) \hat j + (-0.8165 F_{AB} -0.505F_{AC} -0.505 F_{AD} +6142.5 ) k ^ \to ] = 0\)

From above; we need to relate and equate each coefficients i.e i ,j, and \(k ^ \to\) on both sides ; so, we can re-write that above as;

\(0.408 F_{AB} +0.303 F_{AC} + 0.808F_{AD}) =0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ --- (1) \\ \\ 0.408 F_{AB}+0.808F_{AC}+0.303F_{AD}) =0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ --- (2) \\ \\ -0.8165 F_{AB} -0.505F_{AC} -0.505 F_{AD} +6142.5 = 0 --- (3)\)

Making rearrangement and solving by elimination method;

\(\mathbf{F_{AB} = 13785.06 N }\)

\(\mathbf{F_{AC} = -5062.38 N }\)

\(\mathbf{F_{AD} = -5062.38 N }\)

The force vector of each member, depends on the magnitude of the

force and the unit vector of the member.

Responses:

The force supported by the members are;

Resolving the given members into unit vectors gives;

\(\hat u_{AB} = \mathbf{\dfrac{(2.6 - 1.5) \cdot \hat i + (2.6 - 1.5)\cdot \hat j + (-2.2)\cdot \hat k }{\sqrt{(2.6- 1.5)^2 + (2.6 - 1.5)^2 + (-2.2)^2}}}\)\(\dfrac{(2.6 - 1.5) \cdot \hat i + (2.6 - 1.5)\cdot \hat j + (-2.2)\cdot \hat k }{\sqrt{(2.6- 1.5)^2 + (2.6 - 1.5)^2 + (-2.2)^2}}= 0.40825 \cdot \hat i + 0.40825\cdot \hat j - 0.81625\cdot \hat k\)

Similarly, we have;

\(\hat u_{AC} =\mathbf{ \dfrac{(2.6 - 2) \cdot \hat i + (2.6 - 1)\cdot \hat j + (-2.2+1.2)\cdot \hat k }{\sqrt{(2.6- 2)^2 + (2.6 - 1)^2 + (-2.2+1.2)^2}}}\)

\(\dfrac{(2.6 - 2) \cdot \hat i + (2.6 - 1)\cdot \hat j + (-2.2+1.2)\cdot \hat k }{\sqrt{(2.6- 2)^2 + (2.6 - 1)^2 + (-2.2+1.2)^2}} =\dfrac{0.6\cdot \hat i +1.6\cdot \hat j -1\cdot \hat k }{\sqrt{0.6^2 + 1.6^2 + (-1.)^2}}\)

\(\dfrac{0.6\cdot \hat i +1.6\cdot \hat j -1\cdot \hat k }{\sqrt{0.6^2 + 1.6^2 + (-1.)^2}}= 0.303046\cdot \hat i + 0.80812\cdot \hat j - 0.50508\cdot \hat k\)

\(\hat u_{AD} =\mathbf{ \dfrac{(2.6 - 1) \cdot \hat i + (2.6 -2)\cdot \hat j + (-2.2 + 1.2)\cdot \hat k }{\sqrt{(2.6-1)^2 + (2.6 -2))^2 + (-2.2 + 1.2)^2}}}\)

\(\hat u_{AD} =\mathbf{0.80812\cdot \hat i+ 0.303046\cdot \hat j - 0.50508\cdot \hat k}\)

The forces are therefore;

\(\vec F_{AB} =\mathbf{ F_{AB} \cdot \left ( 0.40825 \cdot \hat i + 0.40825\cdot \hat j - 0.81625\cdot \hat k \right)}\)

\(\vec F_{AC} =\mathbf{ F_{AC} \cdot \left (0.303046\cdot \hat i + 0.80812\cdot \hat j - 0.50508\cdot \hat k\right)}\)

\(\vec F_{AD} = \mathbf{F_{AD} \cdot \left (0.80812\cdot \hat i+ 0.303046\cdot \hat j - 0.50508\cdot \hat k\right)}\)

\(Weight \ on \ the \ assembly = \dfrac{13,500 \, kg \times 1.82 \, m/s^2}{4} = 6,142.5 \, \hat k N\)

Which gives;

\(\mathbf{0.40825 \cdot \hat i \cdot F_{AB}}\) + \(0.303046\cdot \hat i \cdot F_{AC}\) + \(0.80812\cdot \hat i \cdot F_{AD}\) = 0

\(0.40825 \cdot \hat j \cdot F_{AB}\) + \(0.80812\cdot \hat j \cdot F_{AC}\) + \(0.303046 \cdot \hat j \cdot F_{AD}\left\) = 0

\(-0.81625\cdot \hat k \cdot F_{AB}\) - \(0.50508\cdot \hat k \cdot F_{AC}\) - \(0.50508\cdot \hat k \cdot F_{AD}\) +  \(\mathbf{6,142.5 \, \hat k}\) = 0

Which gives;

\(-0.81625\cdot \hat k \cdot F_{AB}\) - \(0.50508\cdot \hat k \cdot F_{AC}\) - \(0.50508\cdot \hat k \cdot F_{AD}\) =  \(-6,142.5 \, \hat k\)

Solving gives;

Learn more about unit vectors here:

https://brainly.com/question/13289984

https://brainly.com/question/18703034

Answer:

25 V, 50V, 75V respectively.

I hope it will be useful.

The number of commutator bars for a 4-pole, 2-layer, DC lap winding with 20 slots and one conductor per layer exists 20

Lap Winding is one kind of winding with two layers, and it is used in electric machines. Every coil in the engine is allied in series with the one nearby coil to it. The applications of lap winding mainly contain low voltage as well as high current devices.

Advantages of Lap Winding

The advantages of lap windings contain: This winding is necessarily needed for large current applications because it has more parallel paths. It is suited for low voltage and high current generators.

To learn more about Lap Winding, refer

https://brainly.com/question/14980223

#SPJ9

Active Filters:

Active filters are made by using the active components i.e operational amplifiers.

Passive Filters:

Passive filters are made by using passive components i.e capacitor, resistor, and inductor.

Active High Pass Filter:

An active high pass filter is shown in attachment. When the input with the high frequency is applied then the capacitive reactance will be low and signal will pass. When input frequency will be low capacitive reactance will be high. So, It will not allow to pass the Signal.

Designing:

The cuttoff frequency of this filter is given below:  

                                      \(f = 1/2\pi RC\)

It is always known the cutoff frequency of the required filter. Hence, by supposing R we can find the C for this active high pass filter.

Gain:

As this is non-inverting amplifier so, its gain will be

                                       \(A = 1+ Ri/Rf\)    

Answer:

up up down down

Explanation:

left right left right b a select start

Answer:

The minimum thickness t of the wall is 0.00446 mm

Explanation:

Solution

Given that

Pressure =670kPa = 0.670

σ allowable normal stress = 150 MPa

Inner diameter = 2mm

Steel = A516 grade 60

Now,

Since the hoop stress is twice the longitudinal stress, the cylindrical tank is more likely to fail from the hoop stress.

Thus

σ allowable = σₙ = pμ/t

=p (d/2)

150 MPa =0.670MPa * 2/2/t

=0.67/t

t=0.67/150

t =0.00446 mm

Answer:

D

Explanation:

Got it wrong so i could answer

Technologies such as bronze working first arrive in china through pastoralist nomad migrations in the Mongolian steppes.

China's culture was very different from what we conceive of today during the Bronze Age. The typical individual ate bread instead of rice and drank beer instead of tea. The ruler's influence stemmed from his kinship with the dead and his capacity to appease the gods for the sake of his people. Priests would write queries on animal bones and heat them until they cracked to discover what these beings desired. They would determine what the spirits and the ancestors desired by interpreting the fracture pattern. In order to appease them, sacrifices of wine and grains were frequently made, but in times of dire need, the Shang Dynasty kings would also offer up people and animals. As the Bronze Age progressed, the Zhou Dynasty kings phased out the practice of human sacrifice.

Learn more about Bronze age:

https://brainly.com/question/1463925

#SPJ4

Complete question is:

How did technologies such as bronze working first arrive in China?

a. Through pastoralist nomad migrations in the Mongolian steppes

b. Through shipping lanes from the Korean peninsula

c. Through indigenous invention in the Yangshao culture

d. Through the overland caravan routes from the Indus Valley

Answer:

1. Rounding numbers.

2. Imperfection of the instruments used.

3. Environment where the experiment was made.

4. Human error.

Answer:

I don't know ask my dad he would

Explanation:

but I can't ask him because he went to get milk and forgot to come back

b. false Meter loading refers to inaccurate readings due to the meter's resistance being in series with the component being tested, not in parallel.

When a meter is connected in series with a component, the meter's internal resistance creates a voltage drop that affects the measurement of the component's voltage or current.

The internal resistance of a meter forms a voltage divider with the component's resistance, causing a voltage drop across the meter itself. This voltage drop reduces the voltage or current being measured, leading to inaccurate readings. The extent of the error depends on the relative magnitudes of the meter's internal resistance and the component's resistance.

To minimize meter loading and obtain more accurate readings, meters with high input impedance (low internal resistance) are used. These high-impedance meters minimize the voltage drop across the meter and have minimal impact on the circuit being measured.

Learn more about inaccurate here

https://brainly.com/question/30365701

#SPJ11

The charged sphere pushes against the line of charge with a force of 0.0181 N.

The product of the magnitudes of the charges and the square of the distance between them determines the magnitude of the electrostatic force F between two point charges, q1 and q2, and vice versa. While opposing charges attract one another, like charges repel one another.

Apply the electrostatic force law of Coulomb.

F = (kq1q2)/r²

where;

Charge is q1. 1.26 nC = 6.3 n C/m x 0.2 m

F = (9 x 109 x 1.26 x 109 x 4 x 106)/q2

= charge 2 = -4 C

r = distance between the charges = 5 cm

= 0.05 m (0.05)²

F = 0.0181 N

To learn more about magnitudes refer to:

https://brainly.com/question/24468862

#SPJ4

Answer: Increase in minimills

Explanation: