If someone now told you that the derivative (slope of the tangent line to the graph) of f(x)f(x) at x=1x=1 was −1/n2−1/n2 for some integer nn. We can expect n to be 1.
For h = 0.1:
f(1 + h) - f(1)/h = [f(1.1) - f(1)]/0.1
= [(1/1.1) - 5 - (1/1 - 5)]/0.1
= [-3.1818181818181818181818181818182]/0.1
= -31.818181818181818181818181818182
For h = 0.01:
f(1 + h) - f(1)/h = [f(1.01) - f(1)]/0.01
= [(1/1.01) - 5 - (1/1 - 5)]/0.01
= [-31.818181818181818181818181818182]/0.01
= -3181.8181818181818181818181818182
For h = -0.01:
f(1 + h) - f(1)/h = [f(0.99) - f(1)]/(-0.01)
= [(1/0.99) - 5 - (1/1 - 5)]/(-0.01)
= [-31.818181818181818181818181818182]/(-0.01)
= 3181.8181818181818181818181818182
For h = -0.1:
f(1 + h) - f(1)/h = [f(0.9) - f(1)]/(-0.1)
= [(1/0.9) - 5 - (1/1 - 5)]/(-0.1)
= [-3.1818181818181818181818181818182]/(-0.1)
= 31.818181818181818181818181818182
The derivative of f(x) at x=1 is -1/n^2 for some integer n.
The derivative of f(x) is given by f'(x) = -1/x^2.
So, f'(1) = -1/1^2 = -1.
Comparing this with -1/n^2, we can expect n to be 1.
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Please help me with this.
Write the expression 8x^2y + 3xy^2 - 2xy - x^2y + 3xy - 5xy^2 in simplest form.
Then, answer the following questions using complete sentences:
a. How many terms are in the simplified expression?
b. How many of the terms in the simplified expression are positive?
Answer:
\(7x^{2} y-2xy^2+xy\)
Three terms.
Two terms are positive.
Step-by-step explanation:
\(8x^2y + 3xy^2 - 2xy - x^2y + 3xy - 5xy^2\)
Group like terms
\(=8x^{2} y-x^{2} y+3xy^2-5xy^2-2xy+3xy\)
Add similar elements: \(8x^{2} y-x^2y=7x^2y\)
\(=7x^2y+3xy^2-5xy^2-2xy+3xy\)
Add similar elements: \(3xy^2-5xy^2=-2xy^2\)
\(=7x^{2} y-2xy^2-2xy+3xy\)
Add similar elements: \(-2xy+3xy=xy\)
\(=7x^2y-2xy^2+xy\)
\(7x^2y\) and \(-2xy^2\) and \(xy\) are the three different terms.
Only \(7x^2y\) and \(xy\) are positive terms, thus making two positive terms.
Expand. Your answer should be a polynomial in standard form. (x-4)(x-6)
Answer:
x2+10x+24
Step-by-step explanation:
The expanded expression in standard form is: \(x^2 - 10x + 24\)
To expand the expression (x - 4)(x - 6), you can use the distributive property to multiply each term in the first parentheses by each term in the second parentheses. Let's do that step by step:
(x - 4)(x - 6)
Step 1: Multiply x from the first parentheses by both terms in the second parentheses:
\(x * x = x^2\\x * -6 = -6x\)
Step 2: Multiply -4 from the first parentheses by both terms in the second parentheses:
-4 * x = -4x
-4 * -6 = 24
Now, put everything together: (x - 4)(x - 6) = \(x^2 - 6x - 4x + 24\)
Combine like terms: \(x^2 - 10x + 24\)
So, the expanded expression in standard form is:
\(x^2 - 10x + 24\)
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Please help me with question
Answer:
Yes, you are right.
Step-by-step explanation:
RS = 20
UT = 20
UT also = x + 10
x = 20 - 10
x = 10
So, yes, you are right.
Hope that helps!
A jeweler is creating a circular bracelet out of gold wire. If the radius of the bracelet is going to be 1.5inches, how much wire will the jeweler need for the bracelet?
The jeweler will need approximately 9.42 inches of gold wire to create the circular bracelet.
To solve the problem, you can use the formula for the circumference of a circle, which is given by:
C = 2πr,
where C is the circumference, π (pi) is a constant approximately equal to 3.14, and r is the radius of the circle. Here, we are given that a jeweler is creating a circular bracelet out of gold wire, and the radius of the bracelet is 1.5 inches. Therefore, to determine the amount of wire the jeweler will need for the bracelet, we can use the formula for the circumference of a circle as follows:C = 2πr = 2 × 3.14 × 1.5 inches= 9.42 inches
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x^4-6x-7-8y-y^2 help me to solve this question
A triangle has vertices of (-2, -1), (0, -5), and (3, 2). What are the vertices of the image after applying the translation
(x,y) → (x+3.y-4)?
A. (-5,3), (-3,-1), (0.6)
B. (1.-5), (3,-9), (6,-2)
C. (1, -1), (3,-5), (6,2)
D. (2.-4)(4, -8). (7.-1)
Answer:
B. (1, -5), (3, -9), (6, -2)
Step-by-step explanation:
First vertex: -2 + 3 = 1, -1 - 4 = -5, so (1, -5)
Second vertex: 0 + 3 = 3, -5 - 4 = -9, so (3, -9)
Third vertex: 3 + 3 = 6, 2 - 4 = -2, so (6, -2)
(1, -5), (3, -9), (6, -2)
I hope this helps :))
answer the next 3 questions using the following information: a project has three activities a, b, and c that must be carried out sequentially. the probability distributions of the times required to complete each of the activities a, b, and c are uniformly distributed in intervals [1,5], [2,3] and [3,6], respectively. find the total project completion time and run 1000 simulation trials in excel.
To find the total project completion time, we need to add the time required for each activity. Since the activities must be carried out sequentially, the total project completion time will be the sum of the times required for each activity.
The time required for activity a is uniformly distributed in the interval [1,5], so we can assume that the average time required for activity a is (1+5)/2 = 3.
The time required for activity b is uniformly distributed in the interval [2,3], so we can assume that the average time required for activity b is (2+3)/2 = 2.5.
The time required for activity c is uniformly distributed in the interval [3,6], so we can assume that the average time required for activity c is (3+6)/2 = 4.5.
Therefore, the total project completion time is:
Total project completion time = time for activity a + time for activity b + time for activity c
= 3 + 2.5 + 4.5
= 10
To run 1000 simulation trials in Excel, we can use the RAND function to generate random numbers between 0 and 1. We can then multiply these random numbers by the range of each activity to get a simulated completion time for each activity. We can then add up the simulated completion times for each trial to get a simulated total project completion time.
Here are the steps to run 1000 simulation trials in Excel:
1. In cell A1, enter "Trial" as the column header.
2. In cell B1, enter "Time for Activity A" as the column header.
3. In cell C1, enter "Time for Activity B" as the column header.
4. In cell D1, enter "Time for Activity C" as the column header.
5. In cell E1, enter "Total Project Completion Time" as the column header.
6. In cell A2, enter "1" as the first trial number.
7. In cell B2, enter the formula "=RAND()*(5-1)+1" to generate a random number between 1 and 5 for activity a.
8. In cell C2, enter the formula "=RAND()*(3-2)+2" to generate a random number between 2 and 3 for activity b.
9. In cell D2, enter the formula "=RAND()*(6-3)+3" to generate a random number between 3 and 6 for activity c.
10. In cell E2, enter the formula "=B2+C2+D2" to calculate the total project completion time for trial 1.
11. Select cells B2:E2 and drag the fill handle down to fill in the formulas for the remaining trials.
12. After filling in the formulas for 1000 trials, you can use Excel's AVERAGE function to find the average total project completion time across all trials.
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Help me please i reallly need it
Answer:
a) A = 64(2s - 1)
b) A = 1,856 cm²
Step-by-step explanation:
Given the side of the frame, 8s, and that the border that frames the picture is 4 on either side = 8:
a) Find an expression for the area of the frame, in factored form.A = area of the square frame
A₁ = Total area (including the picture inside the frame) = (8s)²
A₂ = Area of the picture inside the frame = 4 + 4 = (8s - 8)²
To find the area of the frame, subtract the area of the picture from the total area.
A = A₁ - A₂
A = (8s)² - (8s - 8)²
Perform the necessary exponential operations:
A = 64s²- (64s² - 64s - 64s + 64)
A = 64s²- (64s² - 128s + 64)
A = 64s²- (64s² - 128s + 64)
Distribute -1 into the parenthesis:
A = 64s²- 64s² + 128s - 64
Combine like terms:
A = 0 + 128s - 64
A = 128s - 64
Factor out 64:
A = 64(2s - 1)
The expression for the area of the frame in factored form is: A = 64(2s - 1).
b) Determine the area of the frame when s = 15cmUsing the same expression from part A:
A = 64(2s - 1)
Substitute s = 15 into the expression:
A = 64[2(15) - 1]
A = 64(30 - 1)
A = 64(29)
A = 1,856 cm²
Therefore, the area of the frame that has a side of 15 cm is: A = 1,856 cm²
Step-by-step explanation:
F=5000N</p><p>
\(F=5000N
\longrightarrow{\green{F=5000N}}
\)
A professor believes the students in a statistics class this term are more creative than most other students attending the university. A previous study found that students at the university had a mean score of 40 on a standard creativity test, and the current class has an average score of 47 on this scale with an estimated population standard deviation of 5. The standard deviation of the distribution of means is 1.30. If there were 16 students in the class, and the professor wanted to test the null hypothesis described in the scenario using the 5% level of significance, the cutoff t score would be:
Since our calculated t score of 14.4 is much larger than the cutoff t score of 2.131, we can reject the null hypothesis and conclude that the mean creativity score of the current statistics class is significantly different from the mean creativity score of the rest of the university students.
The null hypothesis in this scenario is that the mean creativity score of the current statistics class is not significantly different from the mean creativity score of the rest of the university students, which is 40.
We can use a one-sample t-test to test this hypothesis, where the test statistic is calculated as:
t = (sample mean - population mean) / (sample standard error)
where the sample standard error is calculated as:
standard error = population standard deviation / sqrt(sample size)
Plugging in the given values, we have:
t = (47 - 40) / (5 / sqrt(16)) = 14.4
To find the cutoff t score at the 5% level of significance with 15 degrees of freedom (16 students - 1), we can use a t-distribution table or a calculator. Using a table, we find that the cutoff t score is 2.131.
Therefore, since our calculated t score of 14.4 is much larger than the cutoff t score of 2.131, we can reject the null hypothesis and conclude that the mean creativity score of the current statistics class is significantly different from the mean creativity score of the rest of the university students.
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Out of 25 26 27 28 29 30 31 and 32 which one is a factor of 27
Answer:
27
Step-by-step explanation:
factors are numbers that divide exactly into a number , leaving no remainder.
then the only factor of 27 from the list is 27
PLEASE HELPPP‼️‼️‼️‼️I WILL MARK BRAINLYEST ‼️‼️SOMEONE PLEASE ANSWER ‼️‼️
What is the length of DE?
A. 2.24
B. 2.66
C. 5
D. 1.73
Answer:
B
Step by Step Explanation:
D = (1, 1)
E = (2, 3)
Take out C immediately, as the distance is 100% not more than 3 units.
I'm going to go with the premise that wherever the letters' points on the graphs are where the letters are located.
Take out D as well because the distance is around 2 - 2.66 units, and not under (Look at what I said previously).
Now if we get a ruler and rotate it exactly to the line from D to E, we will get the answer B (This is due to angles).
Hope this answered your question or at least helped, in which case you're welcome. :D
it would be 2.24 !!!
expert that helps you learn core concepts.
See Answer
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 23, 25, 16, 20, 13, 10, 28, 19. Use Table 2.
a. Calculate the sample mean and the sample standard deviation. (Round intermediate calculations to 4 decimal places. Round "Sample mean" to 3 decimal places and "Sample standard deviation" to 2 decimal places.)
Sample mean.
Sample standard deviation
b. Construct the 90% confidence interval for the population mean. (Round "t" value to 3 decimal places and final answers to 2 decimal places.)
Confidence interval to
c. Construct the 99% confidence interval for the population mean. (Round "t" value to 3 decimal places and final answers to 2 decimal places.)
Confidence interval to
The sample mean of the observations is 19.25 and the standard deviation is 2.15
Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.
Sample standard deviation is the square root of the variance
mean = (23 + 25 + 16 + 20 + 13 + 10 + 28 + 19)/8
mean = 19.25
variance = (x₁ - mean)²/n(n-1)
variance = ((23 - 19.25)² + (25 - 19.25)² + (16 - 19.25)² + (20 - 19.25)² + (13 - 19.25)² + (10 - 19.25)² + (28 - 19.25)² + (19 - 19.25)²)/(8(7))
variance = 259.5/56
variance = 4.63
Standard deviation = √variance = √4.63 = 2.15
Therefore, the sample mean of the observations is 19.25 and the standard deviation is 2.15
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help me w this pls thanks
Answer:
Perimeter: 4+\(\pi \\\) mm
Area: \(\pi\) mm^2
Step-by-step explanation:
Perimeter:
90/360 * 4\(\pi \\\) +2 + 2 = 4+ \(\pi \\\)
Area:
90/360 * 4\(\pi\) = \(\pi\)
Answer: 7.14 mm and 3.14 mm²
Step-by-step explanation:
The perimeter of a figure is the total length on the outside of the figure. A regular circle has a perimeter of \(2\pi r\), where r is the radius and \(\pi\) is an irrational constant, approximately 3.14.
Due to the right angle, we know that this is a quarter circle, as it is a quarter of 360°, or a full circle. Hence, the curved portion of the quarter circle is \(\frac{1}{4}* 2\pi r\) or \(\frac{1}{2} \pi r\). The radius is 2 mm, so this value is
\(\frac{1}{2} \pi*2=\pi\)
However, this isn't the total perimeter, as there are straight edges in the figure too. Both edges are radii of the whole circle, so both would be 2mm. Their total is
\(2+2=4\)
By adding \(\pi\) to 4 we get \(\pi +4\) or 7.14 mm.
The area is the total space enclosed by a figure. The total area of a whole circle is \(\pi r^2\), where r is still the radius. Since this is a quarter circle, it would take up a quarter of the area, or \(\frac{1}{4} \pi r^2\). We can plug in 2 for r and solve to get the area.
\(\frac{1}{4}\pi*2^2\\\frac{1}{4}\pi*4\\\pi\)
Hence, the area is \(\pi\), or around 3.14 mm².
A rectangle is a _____.
quadrilateral
square
parallelogram
rhombus
help me plssssssssssssssssssssssssssssssssssssssssss
and please give explanation
[1] H 2.4
Let us turn the pictures into equations, using the key given. Then, we will solve.
x + x + \(\frac{1}{4}\)x + 1 + 1 + 1 = x + x + x + \(\frac{1}{2}\)x
2x + \(\frac{1}{4}\)x + 3 = 3x + \(\frac{1}{2}\)x
\(\frac{9}{4}\)x + 3 = \(\frac{7}{2}\)x
3 = \(\frac{5}{4}\)x
x = 2.4
[2] J
We can tell the first two options are incorrect because there was a change in size, not position.
Option H would make the shape bigger, but it becomes larger. This means the answer is option J.
Calcula la suma de las longitudes de los catetos, si la hipotenusa mide 15 u y la altura relativa a ella mide 6 u.
UwU
Answer:
9 sqrt(5)
Step-by-step explanation:
La altura relativa a la hipotenusa corta la hipotenusa en dos segmentos.
Defina x como
x = la longitud de uno de esos segmentos
Entonces, la longitud del otro segmento = 15 - x.
Entonces, por el teorema, tenemos que (15-x) (x) = 36, de modo que
15x - x ^ 2 = 36
x ^ 2 - 15x + 36 = 0
(x-3) (x-12) = 0
Entonces, x = 3 o x = 12.
Sin pérdida de generalidad. sea x = 3.
Entonces, la suma de las dos piernas es
raíz cuadrada (6 ^ 2 + 3 ^ 2) + raíz cuadrada (12 ^ 2 + 6 ^ 2) =
raíz cuadrada (36 + 9) + raíz cuadrada (144 + 36) =
raíz cuadrada (45) + raíz cuadrada (180) =
raíz cuadrada (9 * 5) + raíz cuadrada (36 * 5) =
3 raíz cuadrada (5) + 6 raíz cuadrada (5) =
9 cuadrados (5)
Pavi has a credit line of $8,000 on his credit card. Review the summary of his credit card statement. How much credit does Pavi currently have available on this card?
Summary Previous Balance Payments/Credits New Purchases Finance Charge New Balance
$2,500. 00 $1,500. 00 $3,000. 00 $7. 50 $4,007. 50
A.
$3,992. 50
B.
$5,000. 00
C.
$5,500. 00
D.
$6,500. 50
The correct option is option (a) $3,992.50. Pavi currently has a $3,992.50 credit on her current card.
The calculation of the provided data, according to the question, is as follows:
$8000 is the credit limit on the card.
Paid in Full = $2,500
$1,500 has been credited to the account.
The value of recent purchases made by Pavi is $3,000
Applied finance charges equal $7.50
The card's current balance is equal to $4,007.50.
Using the formula below, we can now determine the amount of credit that is now available on the card:
The credit line on the card = Available Credit - New Balance
By entering values into the formula provided, we obtain
Credit available on the current card: $8,000 - $4,007.50= $3,992.50.
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suppose that the probability of engine malfunction during any one-hour period is p = 0.03p=0.03. find the probability that a given engine will survive two hours.
The probability that the engine will survive for more than 2 hours is 94.09%.
To find the probability that a given engine will survive two hours, we need to use the concept of independent events. This means that the probability of an event happening in one hour does not affect the probability of it happening in the next hour.
The probability of the engine surviving for one hour is 1 - p = 1 - 0.03 = 0.97 (since the probability of malfunction is 0.03, the probability of survival is the complement of that, which is 1 - 0.03).
To find the probability of the engine surviving for two hours, we need to multiply the probability of survival for each hour:
P(survive for 2 hours) = P(survive for 1 hour) * P(survive for 1 hour)
= 0.97 * 0.97
= 0.9409
Therefore, the probability that a given engine will survive two hours is 0.9409 or 94.09%.
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Find m∠EDC.....................
Answer:
m<EDC=110
Step-by-step explanation:
angle c is 35 degrees too, because this is isoceles
using the sum of the triangle's angles which are always 180
70+x=180
x=110
can someone please help me graph this ? not rlly sure
The graph of the given equation is attached below.
Plotting a line graphThe equation of a line in slope-intercept form is expressed as y = mx + b.
Given an xy plane, we are to plot the graph of the given equation
y = -2/3 x + 1
The given equation has a slope of -2/3 and a y-intercept of 1. This shows that the constructed line must cut the y-axis at the point (0, 1).
The graph of the equation is attached below.
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find the multiplier for the rate of exponential growth or decay.
1) 1% growth
1% growth has a multiplier 1+0.01=1.01
What is exponential growth function ?
A process called exponential growth sees a rise in quantity over time. When a quantity's derivative, or instantaneous rate of change with respect to time, is proportionate to the quantity itself, this phenomenon takes place.
The exponential function which models the exponential growth has a form
\(y= C(1+r)^x\)
where C is initial amount, y is final amount, x is time, r is rate (the percent written as a decimal) and 1+r is a multiplier.
The exponential function which models the exponential decay has a form
\(y= C(1-r)^x\)
where C is initial amount, y is final amount, x is time, r is rate (the percent written as a decimal) and 1-r is a multiplier.
Thus,
1. 1% growth has a multiplier 1+0.01=1.01;
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Which statement best describes "willing suspension of disbelief"? A technique used by actors in which they defer their own reality to accept that of the play A dynamic in which the audience agrees to accept the fictional world of the play on an imaginative level while knowing it to be untrue. A psychological dynamic in which one group of audience members can affect the responses of others to an event, particularly if they share the same cultural background.
The statement that best describes "willing suspension of disbelief" is: A dynamic in which the audience agrees to accept the fictional world of the play on an imaginative level while knowing it to be untrue.
The concept of "willing suspension of disbelief" is an essential element in experiencing and appreciating works of fiction, particularly in theater, literature, and film. It refers to the voluntary act of temporarily setting aside one's skepticism or disbelief in order to engage with the fictional narrative or performance. It involves consciously accepting the imaginative world presented by the creator, even though it may contain unrealistic or fantastical elements. By willingly suspending disbelief, the audience allows themselves to become emotionally invested in the story and characters, making the experience more enjoyable and meaningful. This dynamic acknowledges the inherent fictional nature of the work while acknowledging that the audience is aware of its fictional status. It creates a mutual understanding between the audience and the creators, enabling the audience to fully immerse themselves in the narrative and connect with the intended emotions and themes of the work.
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plss helpppppppppp w,jvkwsvkjbw,vj effvdefv
Answer:180
Step-by-step explanation:
4) Find the surface area of the regular pyramid
The surface area of the regular pyramid is 131.15 cm.
Define surface area.The surface area is the area occupied by a two-dimensional flat surface. It has a square unit of measurement. The surface area of a three-dimensional object is the space taken up by its outer surface. The whole area of the surface of the specified solid item is referred to as surface area. We should add the areas of the surfaces to determine the object's surface area because the faces of three-dimensional objects are essentially 2D shapes.
Given,
Surface area = 1/2(a× b) + 3/2(b ×s)
Where b is a pyramid's side, a is a triangle's base height, and s is a pyramid's slant height.
Side = 6.1
Base = 7
Slant height = 12
Equating in formula:
1/2(6.1 × 7) + 3/2(6.1 × 12)
1/2(42.7) + 3/2(73.2)
21.35 + 109.8
131.15
The surface area of the regular pyramid is 131.15 cm.
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How can you find the length of ⎯⎯⎯⎯⎯⎯⎯⎯⎯
Answer:
about 1 inch
Step-by-step explanation:
What is 0.24
as a fraction in simplest form?
Answer:
6/25
Step-by-step explanation:
Hope this helps!
A brainlist would be appreciated! I'm almost an expert!
One important use of the regression line is to do which of the following? Choose the correct answer below. A. To make predictions about the values of y for a given x-value B. To determine the strength of a linear association between two variables
C. To determine if a distribution is unimodal or multimodal D. Both A and B are correct
The correct answer is D. Both A and B are correct, to make predictions about values of y for given x value and to determine the strength of linear association between variables.
The regression line is a statistical tool that allows us to model the relationship between two variables, usually called X (the independent variable) and Y (the dependent variable), assuming a linear relationship between them. Once the regression line has been fitted to the data, it can be used for two main purposes:
A. To make predictions about the values of Y for a given X-value: Once the regression line has been fitted, we can use it to predict the value of Y for any given X-value. This is done by plugging in the X-value into the equation of the regression line, which will give us an estimated value of Y.
B. To determine the strength of a linear association between two variables: The regression line is also a measure of the strength of the linear relationship between X and Y. Specifically, the slope of the regression line (which represents the change in Y for a unit change in X) is a measure of how much Y changes for a given change in X. The closer the slope is to zero, the weaker the linear relationship between X and Y; the farther the slope is from zero, the stronger the linear relationship between X and Y.
Therefore, both A and B are correct uses of the regression line.
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Is the least squares line the same as the regression line?
The least squares line and the regression line are the same thing. They both refer to the line of best fit in a scatterplot.
The least squares line and the regression line are two terms used to describe the same concept in statistics. The line of best fit is a line that is used to describe the relationship between two variables in a scatterplot. The line is created by finding the line that minimizes the sum of the squared differences between the observed values and the predicted values for each data point.
This method is known as the least squares method, which is why the line is often referred to as the least squares line. The term regression line is used because the line is often used to perform regression analysis, which is a statistical method for estimating the relationship between two variables. In conclusion, the least squares line and the regression line are the same thing, and they both refer to the line of best fit in a scatterplot.
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Solve for all missing variables
Answer:
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Version G RMIT UNIVERSITY School of Science (Mathematical Sciences) ENGINEERING MATHEMATICS AUTHENTIC PRACTICAL ASSESSMENT 2 - QUESTION 2 2. (a) Find the derivative y', given: (i) y = (x²+1) log x - x; (ii) y = cosh (x arctan r). (b) Using logarithmic differentiation, find y' if y=e³ 5² tanh7 4r. The printable question file (pdf) is here Upload Choose a file G (3 marks) (3 marks) (5 marks)
According to the question Finally, on solving for \(\(y'\)\):
\(\[y' = 3 \cdot 5^2 \cdot 28 \sech^2(7 \cdot 4r) \cdot y\]\) and the derivative \(\(y'\)\) is
\(\[y' = \sinh(x \arctan r) \cdot \arctan r\]\)
(a) To find the derivative y', given:
(i) \(\(y = (x^2 + 1) \log x - x\)\)
We can apply the product and chain rule to find the derivative. Let's start with the product rule:
\(\[\frac{d}{dx}(uv) = u'v + uv'\]\)
where \(\(u = (x^2 + 1)\) and \(v = \log x - x\).\)
Taking the derivatives of \(\(u\)\) and \(\(v\)\) with respect to \(\(x\)\), we have:
\(\[u' = 2x \quad \text{and} \quad v' = \frac{1}{x} - 1\]\)
Now, applying the product rule:
\(\[\y' &= (x^2 + 1)(\frac{1}{x} - 1) + 2x(\log x - x) \\&= \frac{x^2 + 1}{x} - (x^2 + 1) + 2x \log x - 2x^2\]\)
\((ii) \(y = \cosh(x \arctan r)\)\)
We can again use the chain rule to find the derivative. Let \(\(u = \cosh(x \arctan r)\).\) Taking the derivative of \(\(u\)\) with respect to \(\(x\)\), we have:
\(\[\frac{du}{dx} = \frac{du}{du} \cdot \frac{du}{dx} = \sinh(x \arctan r) \cdot \frac{d}{dx}(x \arctan r)\]\)
Now, we need to find \(\(\frac{d}{dx}(x \arctan r)\). Let \(v = x \arctan r\).\) Taking the derivative of \(\(v\)\) with respect to \(\(x\)\), we have:
\(\[\frac{dv}{dx} = \arctan r\]\)
Substituting the values back into the chain rule, we get:
\(\[\frac{du}{dx} = \sinh(x \arctan r) \cdot \arctan r\]\)
Therefore, the derivative \(\(y'\)\) is:
\(\[y' = \sinh(x \arctan r) \cdot \arctan r\]\)
(b) To find \(\(y'\)\) using logarithmic differentiation, given \(\(y = e^{3 \cdot 5^2 \tanh(7 \cdot 4r)}\):\)
We can use logarithmic differentiation to find the derivative. Taking the natural logarithm of both sides:
\(\[\ln(y) = \ln\left(e^{3 \cdot 5^2 \tanh(7 \cdot 4r)}\right)\]\)
Using the logarithmic identity \(\(\ln(e^x) = x\)\), we simplify the equation:
\(\[\ln(y) = 3 \cdot 5^2 \tanh(7 \cdot 4r)\]\)
Now, taking the derivative of both sides with respect to \(\(r\):\)
\(\[\frac{1}{y} \cdot y' = 3 \cdot 5^2 \cdot \frac{d}{dr}(\tanh(7 \cdot 4r))\]\)
To find \(\(\frac{d}{dr}(\tanh(7 \cdot 4r))\), we can use the chain rule. Let \(u = \tanh(7 \cdot 4r)\).\) Taking the
derivative of \(\(u\)\) with respect to \(\(r\)\), we have:
\(\[\frac{du}{dr} = \frac{du}{du} \cdot \frac{du}{dr} = \sech^2(7 \cdot 4r) \cdot \frac{d}{dr}(7 \cdot 4r) = 28 \sech^2(7 \cdot 4r)\]\)
Substituting the values back into the derivative equation, we get:
\(\[\frac{1}{y} \cdot y' = 3 \cdot 5^2 \cdot 28 \sech^2(7 \cdot 4r)\]\)
Finally, solving for \(\(y'\)\):
\(\[y' = 3 \cdot 5^2 \cdot 28 \sech^2(7 \cdot 4r) \cdot y\]\)
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