estimate the velocity with which you would contact the ground if you jumped from an airplane at an altitude of 5000 ft and (a) air resistance is negligible, (b) air resistance is important, but you forgot your parachute, or (c) you use a 25 ft diameter parachute.

Answer:

Since the KE is proportional to velocity squared, if you increase the KE by a factor of

2

, you increase

v

by a factor of

2

2

=

4

Detailed explanation :

25

=

0.5

⋅

m

⋅

(

5

2

)

Find

m

:

25

=

25

m

2

m

=

2

Hence the new KE:

KE

=

0.5

⋅

2

⋅

10

2

KE

=

100

J

The correct match of the descriptions to the below people are 23 - F, 24 - H, 25 - D, 26 - I, 27 - A, 28 - B.

23 - F Galileo: Galileo Galilei is credited with discovering the phases of Venus using a telescope. Through his observations, he observed that Venus went through a series of phases similar to those of the Moon, which supported the heliocentric model of the solar system.

24 - H Kepler: Johannes Kepler was the first to consider ellipses as orbits. He formulated the laws of planetary motion, known as Kepler's laws, which stated that planets move in elliptical paths with the Sun at one of the foci. Kepler's work revolutionized our understanding of celestial mechanics.

25 - D Aristotle: Aristotle, the ancient Greek philosopher, is considered one of the foremost thinkers in history. While his contributions span various fields, including philosophy and natural sciences, his views on astronomy were geocentric. He believed that the Earth was the center of the universe and that celestial bodies moved in perfect circles around it.

26 - I Nicolaus Copernicus: Nicolaus Copernicus was an astronomer who proposed the heliocentric model of the solar system, in which the Sun, rather than the Earth, was at the center. Copernicus's revolutionary idea challenged the prevailing geocentric view and laid the foundation for modern astronomy.

27 - A Eratosthenes: Eratosthenes was an ancient Greek mathematician and astronomer who made significant contributions to geography and astronomy. He is known for his accurate measurement of the Earth's circumference. By measuring the angle of the Sun's rays at two different locations, he estimated the Earth's circumference with remarkable accuracy.

28 - B Aristarchus: Aristarchus of Samos is credited with developing the first predictive model of the solar system. He proposed a heliocentric model centuries before Copernicus, suggesting that the Sun was at the center of the universe, with the Earth and other planets orbiting it. Aristarchus's model was a significant departure from the prevalent geocentric view of the time.

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From steam table,

(a).

The final temperature is 180°C.

At 10 bar, saturated liquid,

Temperature = 180°C

(b).

Heat removed from the steam is  2065.6 kJ/kg.

At 10 bar - 200°C, h1 = 2828.27 kJ/kg

At 10 bar, saturated liquid, h2 = 762.68 kJ/kg

Heat removed = h1 - h2 = 2065.6 kJ/kg

(c).

Work done is 204.9 kJ/kg.

Work done = heat removed - change in internal energy = 2065.6 - (2622.26 - 761.55) = 204.9 kJ/kg

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The word that signals a descriptive example is "including."  Including often introduces a descriptive example, providing additional information or clarification in a sentence.

This word is often used to introduce a list of examples or items that are being described in detail. For example, "I love all types of pizza, including pepperoni, Hawaiian, and vegetarian." In this sentence, the word "including" is used to introduce a list of specific types of pizza that the speaker enjoys. The correct answer is therefore "including".

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The speed with which the train reaches the rock slide is 19.36 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The initial velocity of the train can be obtained as illustrated below:

–1.6 = (0 – u) / 12.1

Cross multiply

0 – u = –1.6 × 12.1

– u = –19.36

Divide both sides by –1

u = –19.36 / –1

u = 19.36 m/s

Thus, the train uses 19.36 m/s to reach the rock slide

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Answer:

Time and velocity

Explanation:

The time taken for the velocity to double is very important to find the amount of acceleration the car acquires.

Acceleration is the rate of change of velocity with time.

  Acceleration  = \(\frac{v -u}{t}\)

v is the initial velocity

u is the final velocity

t is the time taken

 So, the velocity and time is needed to calculate the value of the acceleration the car undergoes.

The correct answer is $243

Explanation:

The hole in the fence is 3 meters, this means it is necessary to buy wood that covers this distance. Now, each meter is equal to 100 centimeters, this means 3 meters is equivalent to 300 centimeters ( 100 cm in each meter x 3). Besides this, it is known each plank covers 20cm and costs $16.20. In this context, the next step is to find how many planks are needed. The process is shown below:

300 cm (total width) ÷ 20 cm (width of 1 plank) = 15 planks

This means 15 planks are needed. Finally, fin the total cost

15 planks x $16.20 (cost of 1 plan) = $243

Answer:

Weather situations can be prepared for in many cases,

Explanation:

Answer: The pressure at the bottom : 19600 N/m²

Answer:

acceleration = v-u/ t

= 15-10/5

= 5/5

= 1 m/s2

Explanation:

hope this helped you.

Answer:

\(\boxed {\boxed {\sf 1 \ m/s^2}}\)

Explanation:

Acceleration is the change in velocity over the change in time. Therefore, the formula for calculating acceleration is:

\(a= \frac{v_f-v_i}{t}\)

Since the body's velocity increased from 10 meters per second to 15 meters per second 15 m/s is the final velocity and 10 m/s is the initial velocity. The time is 5 seconds.

\(a= \frac{ 15 \ m/s - 10 \ m/s}{5 \ s}\)

Solve the numerator.

\(a= \frac{ 5 \ m/s }{5 \ s}\)

Divide.

\(a= 1 \ m/s/s\)

\(a= 1 m/s^2\)

The acceleration is 1 meter per second squared.

The linear speed of a swimming whale is 50 km/h. and it will have traveled approximately 138.9 km after 2 and a half hours.

First, we need to convert the linear speed into m/s:

1 km/h = 1000/3600 m/s= 5/18 m/s

Therefore,50 km/h = 50 × 5/18 m/s = 125/9 m/s

Now, the distance traveled by the whale can be found using the formula:

Distance = speed × time

Since the time is 2.5 hours, we have that convert it to seconds:

2.5 hours = 2.5 × 60 × 60 seconds = 9000 seconds

Therefore, the distance traveled is:

Distance = (125/9) m/s × 9000 s= 1250000/9 m ≈ 138888.89 m≈ 138.9 km

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Answer: C.

Explanation:  Abrasion is where two things rub together causing friction, which in turn wears the rock down.

Answer:

I can't understand your language

Explanation:

I know that vietnamese is written...but unfortunately I can't understand....I have many vietnamese friends online....lol

Radii is a vital feature of the elements, and it can be useful in determining the characteristics of elements in various chemical and physical processes. The radii of atoms and ions of the same element differ due to their various charge and mass characteristics.

Atomic and ionic radii increase as you move down a group on the periodic table, and decrease as you move across a period from left to right due to increased nuclear charge, making the electrons closer to the nucleus. The size of an atom and ion also changes due to the number of electrons charge, and electronic configuration.In order of increasing radius, the arrangement of \(Ne, F-, O2-, Br-, Rb\) is given as follows:

\(Ne < F- < O2- < Br- < Rb+\)

Rb+ has the smallest radius due to its large nuclear charge and fewer electrons in the valence shell.

As a result, they are larger than Rb+. O2- has more electrons than Ne and is the largest among the given ions and atoms. It is important to note that in certain conditions, the trends in radii may not be valid because of hybridization and other factors. Nonetheless, this arrangement is valid for the given ions and atoms.

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If you add a vector with a magnitude of 1 to a vector of magnitude 2, the possible magnitudes for the vector sum range from 1 to 3.

This is because of the triangle inequality theorem.The triangle inequality theorem states that the magnitude of the sum of two vectors is less than or equal to the sum of their magnitudes. In other words, if we have two vectors A and B, then the magnitude of their sum C is given by:

|C| ≤ |A| + |B|

If we have a vector of magnitude 1, we can call it vector A. If we have a vector of magnitude 2, we can call it vector B.

Then the magnitude of their sum, vector C, is given by:|C| = |A| + |B|.

Since |A| = 1 and |B| = 2, we can substitute those values into the equation: |C| = 1 + 2

|C| = 3

Therefore, the maximum magnitude of the vector sum is 3.

However, the minimum magnitude of the vector sum is found when the vectors are pointing in opposite directions.

In this case, the magnitude of the sum would be:

|C| = |B| - |A|

|C| = 2 - 1

|C| = 1.

Therefore, the possible magnitudes for the vector sum range from 1 to 3.

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The velocity vector is r'(t) = (4, -3 sin t, 3 cos t), the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t), the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.

Space Curves: Arc lengthArc length formula is given by \(L = ∫a b |r'(t)|dt\)

, where r(t) is the vector function for the given curve.

Let's find the arc length of the given space curve:

r(t) = (2t, t^2 - 2, 5 - t^2) for 0 ≤ t ≤ 4.

The speed of r(t) is |r'(t)|.r'(t) = (2, 2t, -2t) and

||r'(t)|| = √(2^2 + (2t)^2 + (-2t)^2)

= 2√2t.So,

the arc length of the space curve is

L = ∫0 4 2√2t dt

= (4/3)√2 [t^(3/2)] from 0 to 4

= (4/3)√2 (4√2 - 0)= (16/3) * 2

= 32/3.

Therefore, the length of the given space curve with vector equation is 32/3. Vector Functions for the intersection of two surfaces

The equation for the given surface is \(F(x)=(2,x²-30).\)

Let's find the vector functions for the intersection of two surfaces.

To find the intersection, we equate the two given equations:2 = y = x².

We get y = x² = 2. So, x = ±√2.

The vector functions for the intersection of two surfaces are:

r1(t) = (t, 2, t^2 - 30)

for x = √2 and r2(t)

= (-t, 2, t^2 - 30)

for x = -√2.

Given TNB for a space curveLet's find the unit tangent vector to the space curve r(t) = (cos t, sin t, t).

The velocity vector is r'(t) = (-sin t, cos t, 1).

The speed of the curve is |r'(t)| = √(sin² t + cos² t + 1) = √2.

The unit tangent vector is T = r'(t) / |r'(t)| = (-sin t/√2, cos t/√2, 1/√2).

Now, let's find a unit normal vector to the space curve.The acceleration vector is r''(t) = (-cos t, -sin t, 0).

The magnitude of acceleration is |r''(t)| = 1.

The unit normal vector is N = r''(t) / |r''(t)| = (-cos t, -sin t, 0).The binormal vector is given by B = T × N.

Therefore, the unit tangent vector to the space curve r(t) = (cos t, sin t, t) is T = (-sin t/√2, cos t/√2, 1/√2),

the unit normal vector is N = (-cos t, -sin t, 0),

and the unit binormal vector is

B = (cos t/√2, -sin t/√2, 1/√2) × (-cos t, -sin t, 0)

= (sin t/√2, -cos t/√2, 1/√2).

Velocity, acceleration and curvature

Let's find the velocity vector, the acceleration vector, and the curvature of the space curve r(t) = (4t, 3 cos t, 3 sin t) for 0 ≤ t ≤ 27.

The velocity vector is r'(t) = (4, -3 sin t, 3 cos t).

The speed of the curve is |r'(t)| = √(16 + 9 sin² t + 9 cos² t) = 5.

The unit tangent vector is T = r'(t) / |r'(t)| = (4/5, -3 sin t/5, 3 cos t/5).

The acceleration vector is r''(t) = (0, -3 cos t, -3 sin t).

The magnitude of acceleration is |r''(t)| = 3.

The tangential component of acceleration is aT = T · r''(t) = 0.

The normal component of acceleration is aN = |r''(t)| · |N| = 3.

The unit normal vector is N = (-cos t, -sin t, 0).

The curvature is κ = |r''(t)| / |r'(t)|² = 3 / (25 + 9 sin² t + 9 cos² t)^(3/2) = 3 / (25 + 9)^(3/2) = 3 / 14^(3/2).

Therefore, the velocity vector is r'(t) = (4, -3 sin t, 3 cos t),

the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t),

the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.

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Answer:

nice, kind, and listens to the golden rule.

Explanation:

thats a person with good qualities.

If interstellar dust makes an rr Lyrae then the distance to the rr Lyrae variable star by a factor of 10, and its true distance will be 100 parsecs.

If interstellar dust makes an rr Lyrae variable star look 5 magnitudes fainter than it should, then we can use the magnitude-distance formula to determine how much we will over- or underestimate its distance. The magnitude-distance formula is:

m - M = 5log(d/10)
where m is the apparent magnitude of the star, M is its absolute magnitude, and d is its distance in parsecs.

If the star looks 5 magnitudes fainter than it should, then we can write:
m - M = 5 + 5log(d/10)

Since we are underestimating the distance, we can assume that the distance we calculate using this formula will be smaller than the actual distance. Therefore, we need to solve for d when the left-hand side of the equation is 5 magnitudes greater than it should be. In other words:
m - M = 10

Substituting this into the formula, we get:

10 = 5 + 5log(d/10)
5 = 5log(d/10)
1 = log(d/10)
d/10 = 10
d = 100 parsecs

Therefore, we will underestimate the distance to the rr lyrae variable star by a factor of 10, and its true distance will be 100 parsecs.

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Answer:

Oblique

Explanation:

I think that's the answer I was told this but forgot if this is the right answer if not then sorry

The charge on the individual ring is dq = σ * 2πr * dr.

A thin-walled hollow circular glass tube, open at both ends and centered on the origin along the z-axis, is negatively charged uniformly on its outer surface.

To determine the electric field it produces at a location a distance 'r' away from the tube, we can divide the tube into rings of thickness 'dr'. Each individual ring possesses charge 'dq'.

To find the charge on a single ring, we can consider an elemental ring with radius 'r' and thickness 'dr'. The charge on this ring can be calculated by multiplying the charge density (σ), which is the charge per unit area, by the area of the ring (dA).

The area of the ring is given by dA = 2πr * dr. Multiplying this by the charge density, we obtain dq = σ * dA = σ * 2πr * dr.

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The motion is defined as the change in position with respect to time. Force is defined as the product of the mass and acceleration of the object. Power is defined as the work per unit of time.

From the given,

The first image shows the ball is at rest. By using, Newton's first law of motion is defined as the object continuing to be at rest or in uniform motion unless an external force acted on it. If the ball is kicked, the ball which is initially at rest starts to move depending on the applied external force.

The ball moves in a particular direction and hence force is the vector quantity. When the force acts on the ball, work is done, and is equal force and displacement.

The second image shows the car in motion. The car moves in a particular direction, speed of the car gives velocity. Velocity is the vector quantity and the momentum is defined as the product of mass and velocity. When there is a change in velocity, gives rise to acceleration. Acceleration gives force by using Newton's second law of motion.

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\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

Let's solve ~

Given terms :

The formula to find kinetic Energy is ~

\( \boxed{ \boxed{ \sf{ \frac{1}{2} m{v}^{2} }}} \)

Now, apply the formula according to given situation

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2} \times 7 \times ( {4)}^{2} \)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2} \times 7 \times 16\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \times 8\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:56 \: \: joules\)

Therefore, the kinetic Energy of the car is 56 joules

Answer:

56 J

Explanation:

Formula to find the kinetic energy is :

\(E_k\) = \(\frac{1}{2} \)  × m × v²

Here ,

m ⇒ mass

v ⇒  velocity

Let us solve now

 \(E_k\) = \(\frac{1}{2} \) × m × v²

     = \(\frac{1}{2} \) × 7 kg × ( 4 ms⁻¹ )²

     = \(\frac{1}{2} \) × 7 × 16

     = \(\frac{1}{2} \) × 112

     = 56 J

Hope this helps you :-)

Let me know if you have any other questions :-)

Answer:

C. Mantle

Explanation:

The Mantle is a thick layer of solid and partially melted rock

The time in which the car reaches it maximum Haight is ≈1.8 seconds.

We know that when the car leaves the ramp , it will move in upward direction and forward direction .

velocity of moving forward=  v cos(a).......(initial velocity of moving front)

velocity of moving  upward = v sin(a).......(initial velocity of moving up)

v is the  initial velocity of car(30m/s), a is the angle of ramp(37°).

velocity of moving up for car at Max. hight = 0m/s

We know that,

final velocity=initial velocity - gt (g is acceleration due to gravity, t is time)

when something moves upward .

so,

0=v sin(a)-9.8t

t≈1.8 seconds

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