Escribe a cuáles de las bolsas anteriores corresponde la notación decimal aproximada a tres cifras

The natural values of n for which the difference (2-2n) - (5n-27) is positive are 1, 2, 3, and 4.

To find the natural values of n for which the difference (2-2n) - (5n-27) is positive, we need to simplify the expression and then solve for n.

(2-2n) - (5n-27) = 2 - 2n - 5n + 27

= -7n + 29

So, we need to find the natural numbers n for which -7n + 29 > 0.

To do this, we can solve for n as follows

-7n + 29 > 0

-7n > -29

n < 29/7

Since n is a natural number, it must be an integer greater than or equal to 1. Therefore, the natural values of n for which the difference (2-2n) - (5n-27) is positive are 1, 2, 3, and 4.

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Answer:

n=-20

Step-by-step explanation:

Answer:

7.3%

Step-by-step explanation:

Let M = Maths

E = English

P(M ∪ E) = P(M) + P(E) - P( M ∩ E)

From the question:

P(M ∪ E) = 35.7%

P(M) = 18%

P(E) = 24%

P( M ∩ E) = unknown

35.7% = 18% + 24% - P( M ∩ E)

35.7% = 42% - P( M ∩ E)

P( M ∩ E) = 42% - 35.7%

P( M ∩ E) = 7.3%

Therefore, the probability that a student who receives an A in Math course will also receive an A in English course is 7.3%.

In order to find the values of the sides of the triangle you take into account the relation between sides and hypotenuse.

h: hypotenuse

c1: shorter leg

c2: longer leg

Longer leg c2 is 3 inches longer than c1:

c2 = c1 + 3

hypotenuse h is 6 inches longer than c1:

h = c1 + 6

The formula for the calculation of the hypotenuse is:

h² = c1² + c2²

you replace for h and c2 in terms of c1:

(c1 + 6)² = c1² + (c1 + 3)²

You solve the previous equation for c1:

c1² + 12c1 + 36 = c1² + c1² + 6c1 + 9

c1² - 6c1 - 27 = 0

the roots of the previous equation are:

(c1 - 9 )(c1 + 3) = 0

c1 = 9

c1 = -3

You take the positive number because there is no length of sides with negative values.

Then, c2 and h are:

c2 = c1 + 3 = 9 + 3 = 12

h = c1 + 6 = 9 + 6 = 15

Hence, shorter leg is 9 inches, longer leg 12 inches and hypotenuse 15 inches

Answer:

4.6 feet

Step-by-step explanation:

To create a 10" by 10" grid using 1" pieces of wire, you will need to increase a total of 110 pieces of wire. This includes 100 "place" wires to form the grid squares, and 10 additional "piece" wires on each side to complete the border.

To create a similar 10'' by 10'' grid, we would need to increase each side by a factor of 10/6 or 5/3. This means that each piece of wire in the original 6'' by 6'' grid would need to be extended by 5/3, making it 5/3 inches long.

The number of pieces of wire needed for the new grid can be calculated by using the formula:

Number of pieces of wire = (number of horizontal wires + number of vertical wires + diagonals) x length of each wire

For the original 6'' by 6'' grid, there are 7 horizontal wires, 7 vertical wires, and 10 diagonals (which can be counted by drawing lines from each corner to the opposite corner). So the total number of wires is:

(7 + 7 + 10) x 1 = 24

For the new 10'' by 10'' grid, there will be 11 horizontal wires, 11 vertical wires, and 16 diagonals. So the total number of wires needed is:

(11 + 11 + 16) x (5/3) = 64.44 (rounded up to the nearest whole number)

Therefore, we would need approximately 64 pieces of wire to create a similar 10'' by 10'' grid.

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The function has the value of its range decrease as the values in its domain increase is equals to \(f(x) = 0.3^ x \). So, option(B) is right one.

The domain of a function is defined as a set of all possible inputs for the function and range of the function is the set of all values that f takes. For example, the domain of f(x)=x² is all reals and range their corresponding values of f(x).

We have a number of functions and we have to check its range decrease as the values in its domain increase.

A) The function is defined as \(f(x) = 3^ x \), As we put values x from reals, x = 0,1,2,3,

=> f(x) = 3⁰, 3¹,3² ,...

so that with increase of input value of x ( domain) the value of range also increase.

B) function is defined, \(g(x) = 3.5^ x \)

As we put values x from reals, x = 0,1,2,3,

=> f(x) = 3.5⁰, 3.5,3.5² ,...

so that with increase of input value of x (domain) the value of range also increase.

C) The function is \(h(x) =0.3^{x}\)

As we put values x from reals, x = 0,1,2,3,

=> f(x) = 0.3⁰, 0.3,0.3² ,...

=> f(x) = 1, 0.3, 0.09,...

so that with increase of input value of x ( domain) the value of range decrease.

D) The function is \(k(x) = \frac{3 ^{x}}{2 } \)

As we put values x from reals, x = 0,1,2,3,

=>\( f(x) = \frac{ {3}^{0}}{2} , \frac{3^{1}}{2}....\)

= 0.5, 1.5,...

so that with increase of input value of x ( domain) the value of range is also increases. Hence, required value is

\(f(x) = 0.3^ x \)

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The function that has the values of its range decrease as the values in its domain increase is the function (C) h(x) = 0.3^x.

To see why, let's take a look at the

other functions:

(A) f(x) = 3^x: As x increases, 3^x also increases, so the range of f(x) increases as the values in its domain increase.

(B) g(x) = 3.5^x: Similarly to (A), as x increases, 3.5^x also increases, so the range of g(x) increases as the values in its domain increase.(D) k(x) = 1/2(3^x): As x increases, 3^x increases, so 1/2(3^x) also increases, although at a slower rate. Therefore, the range of k(x) increases as the values in its domain increase.

However, for (C) h(x) = 0.3^x: As x increases, 0.3^x decreases, approaching zero. Therefore, the range of h(x) decreases as the values in its domain increase.

Thus, the answer is (C) h(x) = 0.3^x.

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Answer:

Press the kinda paper clip thing it says attach file then press that

Step-by-step explanation:

The results generated in the map phase are combined in the _reduce_ phase.

In maps, the "reduced phase" refers to a technique used to remove the phase ambiguity present in interferometric synthetic aperture radar (InSAR) data. InSAR uses radar to measure the distance between a satellite or aircraft and the ground and can be used to create detailed maps of changes in the surface of the earth over time.

However, because InSAR data is collected using radar waves, which are sensitive to the phase of the signal, the data can be affected by phase ambiguities. The reduced phase technique is used to remove these ambiguities and create more accurate maps.

Therefore, The results generated in the map phase are combined in the _reduce_ phase.

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If the boy is riding a bicycle and gets stuck or got accident by a car, 440ml of IV fluid will be administered.

To avoid further injury, place the victim on the ground very gently and slowly without handling vigorously. In one direction, tilt the sufferer. Dress loosely around the waist, chest, and neck. So that the tongue can fall forward and allow blood and vomit to drain out, tilt your head back and slightly downward. When you come across an accident victim, the first thing you need to determine is whether the victim's body has sustained any physical wounds. Depending on how severe the collision was, you might not be able to see any inside injuries, but you will see a few exterior ones.

In a car accident, spine injuries and head trauma are common. Therefore, be aware that rough handling of the sufferer will result in additional injuries while opting to assist the victim in moving to a safer location on the road. Therefore, request any onlookers to carefully assist in moving the sufferer to a location near the road where it will be safer.

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The equation of Straight line, perpendicular to line [k]would be y = - x + 5

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of straight line also represents the directly proportional relation as -

y = mx + c

y = mx         {c = 0}

m = y/x    

or

m = Δy/Δx  

where [m] is constant of proportionality.

We have a line [k] that has an equation of y = x - 7

We have the given equation of line -

y = x - 7

Slope of line will be 1.

Slope of the line perpendicular to line [k] will be -

m[p] = -1

Then, the general equation would become -

y = - x + c

For point (7, - 2), we can write -

- 2 = - 7 + c

c = - 2 + 7

c = 5

Therefore, the equation of Straight line, perpendicular to line [k]would be y = - x + 5

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According to Thales theorem :

\( \frac{AB}{AE} = \frac{BC}{ED} \\ \)

\( \frac{2}{2 + 5.2} = \frac{s}{6} \\ \)

\( \frac{2}{7.2} = \frac{s}{6} \\ \)

\( \frac{1}{3.6} = \frac{s}{6} \\ \)

\( \frac{s}{6} = \frac{1}{3.6} \\ \)

Multiply sides by 6

\(6 \times \frac{s}{6} = 6 \times \frac{1}{3.6} \\ \)

Simplification

\(s = \frac{6}{3.6} \\ \)

\(s = \frac{6}{36 \times {10}^{ - 1} } \\ \)

\(s = \frac{6 \times {10}^{1} }{36} \\ \)

\(s = \frac{6 \times 2 \times 5}{6 \times 2 \times 3} \\ \)

6 s and 2 s are simplify

\(s = \frac{5}{3} \\ \)

\(s≈1.67\)

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Answer:

x+y=4+8=12

$12 for one of each

or if you mean indivually (the wording confused me)

$4 for child, $8 for adult

Step-by-step explanation:

x=adult

y=child

2x+10y=56

4x+5y=52

iin order to be able to subtract values and find x and y im going to multiply 4x+5y=52 by two and get 8x+10y=104

8x+10y=104

-2x+10y=56

6x=48 divide each side by 6

x=8

plug 8 back into an equation to find cost of y

2(8)+10y=56

-16            -16

10y=40

y=4

In both the Vendor Compliance at Geoffrey Ryans (A) and Operational Execution at Arrows Electronics cases, there are common problems and challenges. These include issues related to vendor management.

One of the key problems faced by both companies is vendor compliance. This refers to the ability of vendors to meet the requirements and standards set by the company. Both cases highlight instances where vendors fail to meet compliance standards, leading to disruptions in the supply chain and operational inefficiencies. This problem affects the overall performance and profitability of the companies.

Another challenge faced by both companies is operational execution. This encompasses various aspects of operations, including inventory management, order fulfillment, and delivery. In both cases, there are instances where operational execution falls short, leading to delays, errors, and customer dissatisfaction. This challenge requires the companies to streamline their processes, improve communication and coordination, and enhance overall operational efficiency.

Overall, the problems and challenges in both cases revolve around effective vendor management, supply chain optimization, and operational excellence. Addressing these issues is crucial for both companies to improve their performance, meet customer demands, and maintain a competitive edge in the market.

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Answer:

Hope this helps you........

The percentage of songs that have lengths within 31 seconds of the mean is 68%

The graph that completes the question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

Area = within 31 seconds

From the graph, we have

Mean = 227 seconds

So, we have

Range = 227 - 31 to 227 + 31

Evaluate

Range = 196 to 258

As a percentage, we have

The range 196 to 258 is about 68% of the distribution

Hence, the percentage is 68%

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The area of triangle ADC is 32√3.

What is area of triangle ?

The area of a triangle is the amount of space that is enclosed within its boundaries. It is measured in square units. The formula for finding the area of a triangle depends on the known dimensions of the triangle.

If the base and height of the triangle are known, then the area can be calculated using the formula:

Area = (base × height) / 2

If the lengths of all three sides of the triangle are known, then the area can be calculated using Heron's formula:

Area = √(s(s-a)(s-b)(s-c))

where "a", "b", and "c" are the lengths of the sides of the triangle, and "s" is the semi-perimeter, which is half the perimeter of the triangle.

To find the area of triangle ADC, we need to first determine the length of AD, the height of the triangle.

We can use the Pythagorean theorem to find AD:

AD² = AC² - CD²

AD² = 16²- 8²

AD²= 192

AD = √192

AD = 8√3

Now that we know the height of the triangle, we can find its area using the formula:

Area = (base × height) / 2

In this case, the base is DC, which is 8. So, we have:

Area = (8 × 8√3) / 2

Area = 32√3

Therefore, the area of triangle ADC is 32√3.

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Answer:

4.5

Step-by-step explanation:

your question isn't very clear but I believe this is what youre asking:

step 1: using the order of operations we subtract 8-5 which gives us 3

step 2: we multiply 3x2 which gives us 6

step 3: If we divide 27/6, we get 4.5 If they are asking you to round the number, we get 5.

If this isn't the way they are asking you to solve, please clarify in the comments so I can help you!

The derivative of F(x) with respect to\(\( x \) is \( F'(x) = 5x^4 \sin(x^{10}) \).\)

To find F'(x) we can apply the Fundamental Theorem of Calculus, which states that if a function  F(x) is defined as the integral of another function f(t), then the derivative of \( F(x) \) with respect to  x is given by F'(x) = f(x)  In this case, we have:

\(\[ F(x) = \int_{0}^{x^{5}} \sin(t^2) dt \]\)

To differentiate  F(x)  with respect to x, we'll use the chain rule. Let's define the upper limit of the integral as a new function of ( x ) :

\(\[ g(x) = x^5 \]\)

Now we can rewrite the integral as:

\(\[ F(x) = \int_{0}^{g(x)} \sin(t^2) dt \]\)

Applying the chain rule, we have:

\(\[ F'(x) = \frac{d}{dx} \left[ \int_{0}^{g(x)} \sin(t^2) dt \right] \]\)

By the Fundamental Theorem of Calculus, the derivative of the integral with respect to ( x ) is just the integrand evaluated at the upper limit, multiplied by the derivative of the upper limit. Therefore:

\(\[ F'(x) = \sin(g(x)^2) \cdot \frac{d}{dx}(g(x)) \]\)

To find\(\( \frac{d}{dx}(g(x)) \),\) we differentiate \(\( g(x) = x^5 \)\) with respect to\(\( x \):\)

\(\[ \frac{d}{dx}(g(x)) = \frac{d}{dx}(x^5) = 5x^4 \]\)

Substituting this back into the expression for  F'(x), we get:

\(\[ F'(x) = \sin((x^5)^2) \cdot 5x^4 \]\)

Simplifying further:

\(\[ F'(x) = 5x^4 \sin(x^{10}) \]\)

Complete question:

Find  \(\(F'(x)\) for \(F(x) = \int_{0}^{x^{5}} \sin(t^{2}) dt\).\)

Therefore, the derivative of F(x) with respect to\(\( x \) is \( F'(x) = 5x^4 \sin(x^{10}) \).\)

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Using the condition for a relation to be a function, we have that items b and c are not functions.

A relation represents a function when each value of the input is mapped to only one value of the output.

In this problem, we have that:

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Step-by-step explanation:

Simply graph the two equations....the intersection of the two graphs is the solution

Answer:

3/4

Step-by-step explanation:

15/20 is 3/4. therefore, according to the previous data, it is 3/4.

P.S. I looked at your answers and you cannot just spam random answers. thats rude and it violated the honor code. how would you feel if you posted a question and the answer was just random letters. and then you failed your test. thats not nice. and you are on canvas, because i use it too, and i know what it looks like. you cannot cheat on a test, as this is not what Brainly is for. im just so dissapointed because you disrespect others.

Answer:

5) 96.506 revolutions ≅ 97 revolution

6) circumference (c) = 83.1355

Step-by-step explanation:

5) A bicycle wheel has a radius of 33 cm. How many revolutions of the wheel are needed to cover a distance of 200 m?

If you read it twice through, you realize that the answer needs to be in meters, not centimeters. Therefore, convert the

33 cm to meters. 100 cm = 1 meter

33 cm= 0.33 meter

1 revolution= one complete time around the wheel The distance around the wheel or circle= Circumference

Use the circumference formula: C=2πr

2(3.14)(0.33) ≅ approximately equal to 2.0724M= 1 Revolution

At this point you can divide 200 by 2.0724 to find out how many revolutions it would take for 200 meters, or you can set

up a proportion as follows: 2.0724 meters/ 1 revolution ≅ 200 Meters/ X revolutions .

Cross multiply, and you get 88 ≅2.198X 200/2.0724 ≅ 96.506 revolutions. Answer

6) Radius (r) = 13.23142

Diameter = 26.46284

circumference (c) = 83.1355

Area = 550m²

Answer:

6c^4 - 2c^3 + 4

Step-by-step explanation:

Answer: 6\(c^{4}\) - 2\(c^{3}\) + 4

Step-by-step explanation:

\((4c^{4} +1)- (7c^{3} -3)+(2c^{4} + 5c^{3} )\)

\(= 4c^{4} +1-7c^{3} +3+2c^{4} +5c^{3}\)

Combine like terms

\(= 6c^{4} -2c^{3} + 4\)

The conjecture that describes the pattern in the sequence is current term is 2 added to the previous term and the next term is 10

The sequence is given as:

0, 2, 4, 6, 8

In the above sequence, we can see that each current term is 2 added to the previous term

i.e.

Tn = 2 + Tn-1

Using the above conjecture, we have

Next term = 8 + 2

Evaluate

Next term = 10

Hence, the conjecture that describes the pattern in the sequence is current term is 2 added to the previous term and the next term is 10

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The maximum profit is achieved when approximately 312.5 units of lab equipment are sold.

The revenue function R(x) represents the amount of money the company earns from selling x units of lab equipment. It is given by the equation:

R(x) = -0.32x^2 + 270x

The costs function C(x) represents the expenses incurred by the company for producing and selling x units of lab equipment. It is given by the equation:

C(x) = 70x + 52

To determine the company's profit, we subtract the costs from the revenue:

Profit = Revenue - Costs

P(x) = R(x) - C(x)

Substituting the given revenue and costs functions:

P(x) = (\(-0.32x^2 + 270x)\) - (70x + 52)

Simplifying the equation:

P(x) = -0.32x^2 + 270x - 70x - 52

P(x) = -\(0.32x^2\)+ 200x - 52

The profit function P(x) represents the amount of money the company makes from selling x units of lab equipment after deducting the costs. It is a quadratic function with a negative coefficient for the x^2 term, indicating a downward-opening parabola. The vertex of the parabola represents the maximum profit the company can achieve.

To find the maximum profit and the corresponding number of units sold, we can use the vertex formula:

x = -b / (2a)

For the profit function P(x) = -\(0.32x^2 + 200x\)- 52, a = -0.32 and b = 200.

x = -200 / (2 * -0.32)

x = 312.5

Therefore, the maximum profit is achieved when approximately 312.5 units of lab equipment are sold.

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The solutions to the equation |15+x|=9 are x = -24 and x = -6, with the smallest value being -24.

The given equation |15+x|=9 can be solved by considering two cases based on the value of 15+x being either positive or negative.

In the first case, where 15+x is positive, we can simplify the equation by removing the absolute value bars, so we get 15+x=9. We can then solve for x by subtracting 15 from both sides, which gives x=-6.

To solve this equation, we need to consider two cases:

Case 1: 15 + x ≥ 0, i.e., x ≥ -15

In this case, the equation simplifies to:

15 + x = 9

x = -6

Case 2: 15 + x < 0, i.e., x < -15

In this case, the equation becomes:

-(15 + x) = 9

-15 - x = 9

x = -24

Therefore, the answers to the equation |15+x|=9 are x = -24 and x = -6, with -24 being the smallest value.

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