Equipotential Surfaces: A region of space contains a uniform electric field directed in the positive x direction as shown. Among the following the correct statements about the electric potential is: Select one: VYYc b. V₁ V₂ Ve d. We can't judge ​

Answer:

Informal education is important because it can help individual to learn how to react and control situations.

It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.

Explanation:

Informal education is a type of education that is learned from different life experiences, happenings outside a structured curriculum.

Informal education is important because it can help individual to learn how to react and control situations.

It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.

The normal force on the block of steel of mass 11.1Kg at constant speed is 108.8 N.

Mass of steel block = 11.1 Kg

Normal force on the block = Force exerted by the surface on the block

= mass × acceleration due to gravity

= m × g

Taking the value of g as 9.8 m/s

= 11.1 × 9.8

= 108.78 N

By converting the answer to one decimal place, round the value to

= 108.8 N

Thus, the normal force on the block of steel by the Teflon surface round to one decimal place is 108.8 N.

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By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

The first involves a salesman who, even though he is aware of the customer's inexperience, does not overcharge them because he does not want to risk damaging his reputation by being found out.

Because the salesman was not driven by a sense of obligation to treat the consumer fairly, Kant claims that this is not a moral issue.

The second claim is that "an action performed out of obligation has its moral significance not in the goal that it is intended to achieve.

Therefore, By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

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The difference in its Kinetic energy of the mass is 3 (¹/₂mV₁² ).

The difference in the kinetic energy of the mass is calculated by applying the following formula as shown below.

ΔK.E = K.Ef - K.Ei

where;

The difference in its Kinetic energy of the mass is calculated as;

ΔK.E = ¹/₂m [ (2V₁²) - ( V₁²) ]

ΔK.E = ¹/₂m[ (4V₁²) - ( V₁²) ]

ΔK.E =  ¹/₂mV₁²[4  - 1]

ΔK.E =  3 (¹/₂mV₁² )

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Answer:

7.407 recurring m/s^2

Explanation:

Initial velocity= 0 m/s [as it starts from rest]

Final velocity= 10 m/s

Time taken= 1.35 s

Hence,

Acceleration = Final velocity - Initial velocity

                                 Time taken

a=10

   1.35

a=7.407 recurring m/s^2

Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

The power needed to boil the water is divided by the element's power output, and the result is multiplied by 100 to get the efficiency of the kettle as a percentage. The answer is 79 %.

We are informed that

Electric kettle power is 1 kW.

Electric kettle voltage is 230 V.

The time it takes the kettle to bring the water to boiling point is 7.5 minutes.

1 kg = mass of water.

Heat generated equals V x I x t + Pt.

generated heat = 1000 W x 7.5 x 60

Heat absorbed equals (100 - 15) x 1 x 4200 = 4200 x 85

Efficiency is determined by multiplying the heat produced by the heat absorbed by 100.

= 4.2 x 85 x 10^3 / 4.5 x 10^5 x 100

= 357 / 4.5 = 79 %

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Answer:

21.73 kg

Explanation:

Applying,

T = 2π√(m/k)............... Equation 1

Where T = period, m = mass on the spring, k = spring constant, π = pie.

make m the subject of the equation

m = T²k/4π²................. Equation 2

From the question,

Given: T = 3.45 s, k = 72.0 N/m, π = 3.14

Substitute these values into equation 2

m = (3.45²×72)/(4×3.14²)

m = 21.73 kg.

Hence the mass should be 21.73 kg

Answer:

b)    pressure increases with depth because of the weight of the fluid  above

P = ρ g H        density * gravity * fluid depth

(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)

Answer:

a) ΔS = 14.46 J/k

b) ΔS = 70.76 J/k

Explanation:

The general formula to calculate the entropy change accompanied with a process is:

ΔS = ΔQ/T

where,

ΔS = entropy change for the process

ΔQ = Heat Transfer during the process

T = Absolute Temperature during the process

a)

In this case the heat transfer will be given as:

ΔQ = (ΔHfus)(N)

where,

ΔHfus = Molar Heat of Fusion of Tin = 7.029 KJ/mol

N = No. of moles of tin = 1 mol

Therefore,

ΔQ = (7.029 KJ/mol)(1 mol)

ΔQ = 7.029 KJ = 7029 J

and the absolute temperature is:

T = 213°C +273 = 486 k

using these values in the entropy formula, we get:

ΔS = 7029 J/486 k

ΔS = 14.46 J/k

b)

In this case the heat transfer will be given as:

ΔQ = (ΔHvap)(N)

where,

ΔHvap = Molar Heat of Vaporization of Carbon Dioxide = 15.326 KJ/mol

N = No. of moles of Carbon Dioxide = 1 mol

Therefore,

ΔQ = (15.326 KJ/mol)(1 mol)

ΔQ = 15.326 KJ = 15326 J

and the absolute temperature is:

T = 216.6 k

using these values in the entropy formula, we get:

ΔS = 15326 J/216.6 k

ΔS = 70.76 J/k

Answer:

Suppose the cable was vertical.

Vertical forces have to cancel to zero.

If you added weight to the beam the vertical force (supposed down)

the cable has to support the added weight as well as the weight added to the cable.

One could create a perpetual motion machine by using the additional downward force on the wall from weight applied to the beam. That is because

2 forces must be offset by the force Fv. That is, both the cable and the additional weight would contribute to the downward force at Fv.

Answer:

\(KE_{new}=186300 J\)

Explanation:

Given:

\(KE=2300J\)   \(n=9\)

\(v_{new}=n*v_{old}\)

\(\frac{KE_{new}}{KE_{old}}=\frac{v^2_{new}}{v^2_{old}}=\frac{(n*v_{old})^2}{v^2_{old}}=n^2\)

\(KE_{new}=n^2KE_{old}\)

\(KE_{new}=(9)^2(2300)\)

\(KE_{new}=186300 J\)

Scientific notation

\(KE_{new}= 1.863*10^5 J\)

Hope it helps

The rock cycle is the process where minerals are converted into different forms by processes such as melting, cooling, eroding, o compacting. In this cycle, the matter that makes up the rocks is never destroyed or created it simply changes into different forms, therefore, this is an example of the law of conservation of matter. A similar cycle is the cycle of water, where the water of the earth is warm by the sun and evaporates then when it elevates to the atmosphere it cools and is condensed again into a liquid and falls back to the earth to begin the cycle. In this case, the water is not created or destroyed in simply changes into different states.

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Answer:

one has a k and one has a s

Explanation:

Answer:

the uk refers to the indians and the us refers to the state, (i think srry if its wrong)

Answer:

I think the answer is B.

Explanation:

Answer:

tough

ques

Explanation:

Answer:

b. the electromagnetic spectrum

Explanation:

the electromagnetic spectrum contains all the forms of light, including gamma rays, x-rays, ultraviolet radiation, visible light, infrared, radio waves, microwaves, etc

The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum horizontal velocity required for an object to orbit the earth just above the surface is calculated as follows;

V(min) = √GMR

where;

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

The supplied problem informs us that a ball was dropped and is supposed to be falling freely. Since the problem does not specify whether any other forces were present to influence the ball's motion, we must assume that the initial speed is v0=0 m/s.

Free-falling accelerates at a rate of 9.8 m/s2, which is referred to as the acceleration owing to gravity because it is being drawn towards the center of the earth. This indicates that a=9.8m/s2 is the value of the initial and final accelerations.

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180kg is mass of metal .

The definition of specific heat capacity

The amount of heat per unit mass needed to raise the temperature by one degree Celsius is known as the heat capacity or specific heat. The ability to distinguish between two polymeric composites using specific heat can be useful in calculating the processing temperatures and volume of heat required.

The heat capacity per unit mass of a material is known as the specific heat capacity (or simply the specific heat). The results of experiments indicate that three variables affect the amount of heat that is transferred: (1) the temperature change, (2) the mass of the system, and (3) the substance and phase of the material.

Eo is 9.9*10^6 J

ΔT is 55K

c is 1*10^3 J/kg.K

Eo = Mo. c. ΔT

Mo = Eo/ c. ΔT

Mo = 9.9*10^6/ 5 5*1*10^3

Mo = 180kg

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Answer:

 t = 14.53 s

Explanation:

The speed of a wave is constant and is given by

         v = \(\sqrt{ \frac{B}{ \rho} }\)

in this exercise they indicate that we assume the constant velocity, therefore we can use the uniform motion relations

          v = x / t

           t = x / v

in this case the sound pulse leaves the ship and must return so the distance is

          x = 2d

where d is the ocean depth d = 10900m and the speed of sound in seawater is v = 1500 m / s

let's calculate

           t = 2 10900/1500

           t = 14.53 s

Answer:  A. He developed the world's first star catalogue.

Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.

Answer:

f=156.25Hz

Explanation:

v=fT

500=fx3.2

500=3.2f

divide both sides by 3.2

f=156.25Hz

Answer:

True!

Explanation:

Answer:

It was not fired from the client's gun because the chair slid only 3 centimeters . If it had been fired from the client's gun the chair would slid 25.82 centimeters.

Explanation:

According to the law of conservation of momentum the momentum of the system before collision must be equal to the momentum of the system after the collision.

M1u1= m2u2

Let M1 = mass of the chair = 20kg

     m2= mass of the bullet= 10g= 0.001kg

      u1= velocity of the chair before collision = zero m/s

      u2 =  velocity of the bullet before collision = zero m/s

         v1= velocity of the chair after collision = ?  m/s  

        v2 =  velocity of the bullet after collision = 450 m/s

After collision their velocities change from u1 to v1 and u2 to v2 so

M1v1= m2v2

v1= m2v2/M1

v1= 0.01 *450/ 20=  0.225 m/s

Now according to the law of conservation of energy the energy of the system before collision must be equal to the energy of the system after the collision.

The energy of the chair after the bullet is hit is

KE of the chair + KE of the bullet=  1/2 (M)(v1)²+ 1/2 m(v2)²=

1/2 ( 20) (0.225 )² + 1/2 (0.01) (450)²

= 0.50625 + 1012.5=  1013.00625 Joules

Frictional force = Coefficient of kinetic force of wood on wood ( M+m) g

                           = 0.2* ( 20.01) 9.8=   39.2196 N

Work done by friction = frictional force * distance

If law of conservation of energy is applied  the KE  must be equal to the work done

KE = W

W= f*d

KE= F*d

d = KE/f= 1013.00625/ 39.2196= 25.82 cm

The chair did not move 25.82 cm .

It only moved 3 centimeter.

Hence the bullet fired was not from the client's gun.

The maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %

η = ( \(T_{H}\) - \(T_{C}\) ) / \(T_{H}\) * 100

η = Efficiency

\(T_{H}\) = Hottest temperature

\(T_{C}\) = Coldest temperature

Hottest temperature = Boiling point

Coldest temperature = Freezing point

\(T_{H}\) = 100 °C = 373 K

\(T_{C}\) = 0 °C = 272 K

η = ( 373 - 273 ) / 373 * 100

η = 100 / 373 * 100

η = 26.8 %

In a heat engine, the heat energy is converted into mechanical energy which will be used to do mechanical work like pushing a piston out from the cylinder.

Therefore, the maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %

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