Equilibrium: In the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 480 N and makes an angle 0 of 80° with the floor. A man weighing 800 N climbs slowly up the ladder When he has climbed to a point that is 7.8 m from the base of the ladder, the ladder starts to slip. What is the coefficient of static friction between the floor and the ladder? 7.8 m​

Answer:

5.634004 × 10^7

Explanation:

the number 7 is for the numbers before the number 5

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes.

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

h = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

Answer:

No

Explanation: It is the only country that does not. Hope this helped :)

Answer:

Ribosomes are organelles the make protein for the cell.

Given:

The rate of decay,

The initial mass, M=150 g

To find:

The expression for the mass at any time t.

Explanation:

On rearranging the given equation,

On integrating the above equation,

Final answer:

Thus the expression for the mass at any time t is

Therefore the correct answer is option A.

Answer:

T = 3.14 10⁻²  s

Explanation:

The general equation for a traveling transverse wave is

           y = A sin (k x - wt +Ф)

where w is the angular velocity that is related to the period and Ф is the phase of the oscillation

           w = 2π / T          (1)

In this case they indicate that the expression of the wave

         y = 0.003 cos (20 x + 200t)

if we use the relationship of the double angles

          a = kx - wt

          b = Ф

          sin (a + b) = sin a cos b + sin b cos a

for the case Ф = 90 we have

          sin (a + b) = cos b

we substitute

          y = A cos (kx -wt)

with an initial phase of fi = 90º

if we compare the terms of the two expressions

         A = 0.003 m  

         k = 20 m⁻¹

         w = -200  rad/s

the negative sign indicates that the wave goes to the left

if we clear from equation 1

          T = 2π / w

          T = 2π / 200

          T = 3.14 10⁻²  s

Answer:

The force exerted by the rope is FT = 225.06 [N]

Explanation:

In order to solve this problem we must use a static analysis, since Globe does not move. For a better understanding in solving this problem, a free body diagram with the forces acting on the globe is attached.

The buoyant force acts upward as it causes the balloon to tend to float, the weight of the balloon tends to lower the balloon and the downward tension force does not allow the balloon to float

The buoyant force is defined by the following equation:

FB = Ro*V*g

where:

FB = Buoyant force [N]

Ro = density of the air = 1.3 [kg/m^3]

V = volume of the balloon = 20 [m^3]

g = gravity acceleration = 9.81 [m/s^2]

FB = 1.3*20*9.81 = 255.06 [N]

Now we do a sum of forces equal to zero in the y-axis

FB - 30 - FT = 0

255.06 -30 = FT

FT = 225.06 [N]

Answer:Calculate the work done using:

work done (in joules) = force (in newtons) x distance moved (in metres)

To practice calculations involving force, distance and work done.

Explanation: I hope this helps srry if I'm wrong

The electric heater draws a current of 4.5 amps.

Using Ohm's Law, we can calculate the current drawn by the electric heater. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) applied to the conductor divided by its resistance (R):

In this case, the voltage (V) is 120 V and the power (P) of the electric heater is 540 W. We can use the formula P = VI, where P is the power in watts, V is the voltage in volts, and I is the current in amperes. Solving for I, we get:

Therefore, the electric heater draws a current of 4.5 amperes (A) when operated at 120 volts (V).

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In hydrogen atom the electronic transition from n= ∞ to n=1 corresponds to largest energy emission.

Electronic transition is the jump of an electron from one energy level to another energy level .

E = hc/λ

h= plank constant =6.62*10^(-34)

c=speed of light

λ= wavelength of emited electron .

Thus , we can conclude that the electronic transition from infinity to n=1 (ground state) corresponds to largest energy emission .

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Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.

Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:

Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.

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Answer:

Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.

Explanation:

Answer: read this hope this helped

Explanation: A hypothesis is a possible explanation for a set of observations or an answer to a scientific question. ... The next step in the scientific method is to test the hypothesis by designing an experiment. This includes creating a list of materials and a procedure— a step-by-step explanation of how to conduct the experiment.

Answer:

When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.

Explanation:

Answer: When a bell is pounded, the metal vibrates. The vibrations travel through the air as sound waves. When these waves reach our ears, they make our eardrums vibrate.

Explanation:

We hear the sound of the bell ringing. Sound always needs to travel through some kind of medium, such as air, water, or metal.

Sorry if this is not the answer you are looking for

Answer:

118 m/s

Explanation:

Given :

We know that

\(f\ =\ \frac{1}{2l} \sqrt{\frac{T}{U} }\)......Eq(1)

Where \(\sqrt{\frac{T}{u} }\) =v

l=length

f=frequency

l= 98.0 cm= 0.98 m

f=60.0 Hz

Now from the Eq(1)

\(f\ =\ \frac{v}{2l}\)

This equation can be written as

v=2fl.............Eq(2)

Putting the value f and l in Eq(2)

v=2*60*0.98

v=117.6 m/s ~ 118 m/s

There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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B. The difference between total nuclear mass before and after the reaction.

This is because you can see how much nuclear matter had actually been used in the reaction by finding the difference between the initial mass and final mass.

The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.

The assertion that ocean waves move on the water's surface is accurate. Therefore, choice A is right.

A wind wave, water wave, or tornado water wave is a surface wave that develops on a body of water's free surface as a result of the air flowing over the ocean's surface. The fetch is the distance at which two objects come into touch when facing the wind.

The wind is the most frequent source of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.

The statements about ocean waves a true will be they travel on the surface of the water.

Thus, option A is correct.

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Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is  the objects have opposite charges.

An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.

In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.

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If the wave slows down with no change in frequency, the wavelength decreases.

A wave is defined as the disturbance that has the ability to transfer energy from one point to another in a medium.

The properties of a wave include the following:

When there is a change in the speed of the wave with no change in frequency, the length of the wave would decrease.

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The statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

This law describes the nature of a force as the result of a mutual and simultaneous interaction between an object 1 and a second object 2.

According to Newton's third law of motion, whenever two objects A and B interact with each other, they both exert equal but opposite forces upon each other.

Therefore, the statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.

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Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

No

Explanation:

Answer:

The mount saved is $ 0.105.

Explanation:

Concerned about the increase in the electricity bill, a person decides to save by reducing bathing time from 20 to 15 minutes. Your shower has the following specifications: 4200 W and 220V. Knowing that the kWh costs R$0.30, the savings made in 10 days were approximately​.

The electrical energy is given by

E = P x t

where, P is the electrical power and t is the time.

When he is using the shower for 20 minutes, the energy consumed is

E = 4200 x 20 x 60 = 5040,000 J = 1.4 kWh

When he is using the shower for 15 minutes, the energy consumed is

E' = 4200 x 15 x 60 = 3780000 J = 1.05 kWh

The difference in energy is

E'' = E - E' = 1.4 - 1.05 = 0.35 kWh

The money saved is

= 4 0.3 x 0.35 = $ 0.105

The compressive stress in the steel column is found to be approximately 397.6 MPa.

The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),

A = π*(d/2)², diameter of the column is d,

A = π*(0.4/2)²

A = 0.1257m²

The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.

σ = 50 MN/0.1257m²

σ = 397.6 MPa

Therefore, the compressive stress in the steel column is approximately 397.6 MPa.

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Answer:

So it floats

Explanation:

m =3893.40 /10 = 389.340kg (if i use g= 10 not 9.81 -use 9.81 if your syllabus says so)

v = 4.60 m cube

389.340/4.60 =84.64

as density less than that of water 90

so it floats

Answer:

\(B=1.61\times 10^{-4}\ T\)

Explanation:

The attached figure shows the path followed by an electron in the semicircular path from A to B.

Velocity of the electron is, \(v=1.42\times 10^6\ m/s\)

It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

\(Bqv=\dfrac{mv^2}{r}\)

B is the magnitude of the magnetic field

\(B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T\)

So, the magnitude of the magnetic field is \(1.61\times 10^{-4}\ T\).

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be  \(B=1.61\times 10^-{4]\ T\)

The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.

The attached figure shows the path followed by an electron in the semicircular path from A to B.

The velocity of the electron is, \(v=1.42\times 10^6\ \frac{m}{s}\)

It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

\(Bqv=\dfrac{mv^2}{r}\)

B is the magnitude of the magnetic field

\(B=\dfrac{mv}{rq}\)

\(B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\)

\(B=1.61\times 10^{-4}\ T\)

So, the magnitude of the magnetic field is  \(B=1.61\times 10^-{4]\ T\)

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Net work done  on student B by the Ferris wheel in moving from the top to the bottom  is mathematically given as

net work done on A =0.

Generally the equation for the work energy theorem is mathematically given as

net work done on A = change in kinetic energy of A.

Where, angular velocity is constant.

change in kinetic energy = 0.

Hence, from work energy theorem,

net work done on A =0.

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