Enter the two inequalities in the box and select the proper word to join the inequalities

Enter The Two Inequalities In The Box And Select The Proper Word To Join The Inequalities

Answers

Answer 1

Solution

Given

|9x + 7| < 48

this can be rewritten as

\(-48<9x+7\text{ and }9x+7<48\)

Enter The Two Inequalities In The Box And Select The Proper Word To Join The Inequalities

Related Questions

convert (-2,2) into equivalent polar coordinates

Answers

(2rad2, 135) is the polar equivalent

Determine the quadrant in which the terminal side of the given angle lies.

115°

A. I

B. II

C. III

D. IV

Answers

Answer:

\( \frac{x}{115}= \frac{2\pi}{360}\)

And solving for x we got:

\( x= \frac{115}{160} 2\pi = \frac{23}{36}pi= 0.639 \pi\)

since the value obtained is higher than \(\pi/2\) and lower than \( \pi\) we can conclude that this angle would be in the second quadrant.

B. II

Step-by-step explanation:

In order to solve this problem we can write the angle in terms of pi using the following proportion rule:

\( \frac{x}{115}= \frac{2\pi}{360}\)

And solving for x we got:

\( x= \frac{115}{160} 2\pi = \frac{23}{36}pi= 0.639 \pi\)

since the value obtained is higher than \(\pi/2\) and lower than \( \pi\) we can conclude that this angle would be in the second quadrant.

B. II

Sarah can walk 3 miles in 1 hour at this pace how many miles will Sarah walk in 4 hours​

Answers

Answer:

12 miles

Step-by-step explanation:

3 miles per 1 hour pace

3 × 4 = 12 miles

Answer:

x = 12 miles

Step-by-step explanation:

Sarah can walk 3 miles in 1 hour.

At this pace how many miles will Sarah walk in 4 hours​?

Write and solve an equation of ratios:

 3 mi        1 hr

---------  =  --------

    x           4 hr

Cross-multiplying yields x = 12 miles.  

Sarah can walk 12 miles in 4 hours

A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mile inland (see figure). He can row at a rate of 1 mile per hour and walk at 3 miles per hour. Toward what point on the coast should he row in order to reach point Q in the least time? (Round your answer to two decimal places.) 0.84 mile(s) down the coast

Answers

Least time required to reach the point Q as per the distance and the speed rate is equal to 2 hours.

As given in the question,

Nearest point on the coast is 2 miles far away

rate of the row = 1mile per hour

Walk at the rate of 3 miles per hour

Let 'x' hours be the least time to reach point Q.

Time = distance / speed

Time taken to reach the point Q = [√ 1 + ( 3 - x)² ]/ 3

Time taken to reach the coast = (√ 4 + x² ) / 1

Total  time taken 't' = (√ 4 + x² ) / 1 + [√ 1 + ( 3 - x)² ]/ 3

To find least time dt/dx = 0

t  = (√ 4 + x² ) / 1 + [√ 1 + ( 3 - x)² ]/ 3

⇒dt/dx = [ x / √ 4 + x² ] + ( 3 - x) / √( 10 -6x + x² )

⇒x / √ 4 + x² = ( x - 3) / √( 10 -6x + x² )

Squaring both the side we get,

x² / (4 + x²) = ( x - 3)² / ( 10 -6x + x² )

⇒3x² -24x +36 =0

⇒ x² -8x + 12 = 0

⇒ x = 2 or 6 hours

Therefore , the least time taken to reach the point Q is equal to 2 hours.

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. Express this number in standard form:
?
4.39 х 10^-7

Answers

Answer:

4.39e-7

Step-by-step explanation:

What is the cos A?Will give 15 points.

What is the cos A?Will give 15 points.

Answers

Answer:

Step-by-step explanation:

cos A = \(\frac{\sqrt{8} }{3}\)

If a sweater costs $40.00 before the sale and $35.00 after the sale, what was the percent of decrease?

Answers

Answer:

%12.5

Step-by-step explanation:

Answer:

12%

Step-by-step explanation:

What is my perfect crime? I break into Tiffany's at midnight. Do I go for the vault? No, I go for the chandelier. It's priceless. As I'm taking it down, a woman catches me. She tells me to stop. It's her father's business. She's Tiffany. I say no. We make love all night. In the morning, the cops come and I escape in one of their uniforms. I tell her to meet me in Mexico, but I go to Canada. I don't trust her. Besides, I like the cold. Thirty years later, I get a postcard. I have a son and he's the chief of police. This is where the story gets interesting. I tell Tiffany to meet me in Paris by the Trocadero. She's been waiting for me all these years. She's never taken another lover. I don't care. I don't show up. I go to Berlin. That's where I stashed the chandelier.

PLEASEEE HELP ME!!!!!!!! (assume no variable equals 0) will give brainly

PLEASEEE HELP ME!!!!!!!! (assume no variable equals 0) will give brainly

Answers

SOLVING WITH THESE VALUES:

x=2

y=3

——————————————————

\(\frac{8(2)^9(3)^3-12(2)^8(3)^2+2(2)^3(3)}{2x^3y}\)      

The answer is 1,729 when x=2 and y=3

Work is in the pictures below :)

Picture 1: Solved where x=2 and y=3

Picture 2: Solved without plugging in values for x and y

PLEASEEE HELP ME!!!!!!!! (assume no variable equals 0) will give brainly

(2) An international call to a certain country costs Rs. 7
for the first minute, and Rs. 4 per minute thereafter.
Write down an expression in rupees for the cost of
a 10 minutes long international call. Simplify your
expression​

Answers

Answer:

\(y = 43\)

Step-by-step explanation:

Given

\(First\ Minute = 7\)

\(Additional\ Minutes = 4\) per minute

Required

Determine the cost of a 10 minutes call

First, we need to determine the expression for the call charges.

Let:

x = minutesy = charges

The relationship between x and y is:

\(y = First\ Minute + Additional\ Minutes(Number\ of\ minutes\ - 1)\)

i.e.

\(y = 7 + 4(x - 1)\)

1 is subtracted from the total minutes because the first minute has a fixed rate.

For a 10 minutes call

\(x = 10\)

\(y = 7 + 4(x - 1)\)

\(y = 7 + 4(10 - 1)\)

\(y = 7 + 4*9\)

\(y = 7 + 36\)

\(y = 43\)

Hence, the charges for a 10 minutes call is: Rs.43

The graph to the right is the uniform probability density function for a friend who is x minutes late. ​(a) Find the probability that the friend is between 10 and 30 minutes late. ​(b) It is 10 A.M. There is a 20​% probability the friend will arrive within how many​ minutes? part a) what is the probability that the friend is between 10 and 30 minutes late_?

The graph to the right is the uniform probability density function for a friend who is x minutes late.

Answers

The probability that the friend is between 10 and 30 minutes late is approximately 0.6667, or 66.67%.

Since the probability density function is uniform, the probability of the friend being between 10 and 30 minutes late is equal to the area of the rectangle that lies between x = 10 and x = 30, and below the curve of the probability density function.

The height of the rectangle is equal to the maximum value of the probability density function, which is 1/30 since the interval of possible values for x is [0, 30] minutes.

The width of the rectangle is equal to the difference between the upper and lower limits of the interval, which is 30 - 10 = 20 minutes.

Therefore, the probability of the friend being between 10 and 30 minutes late is:

P(10 < x < 30) = (height of rectangle) x (width of rectangle)

= (1/30) x 20

= 2/3

≈ 0.6667

So the probability that the friend is between 10 and 30 minutes late is approximately 0.6667, or 66.67%.

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Rational algebraic expression
x²-16/x²+8x+16

Answers

(x - 4)/(x + 4)

Step-by-step explanation:

\(\begin{aligned}\tt\frac{x^2-16}{x^2+8x+16}&=\tt\frac{x^2-4^2}{\left(x+4\right)^2}\\&=\tt\frac{\left(x+4\right)\left(x-4\right)}{\left(x+4\right)^2}\\&=\tt\frac{x-4}{x+4}\end{aligned}\)

Note :

a² - b² = (a + b)(a - b)(a + b)² = a² + 2ab + b²

5c + d = c+ 4d find the ratio c:d

Answers

Answer:3c + 18d brainless pls

Step-by-step explanation:First, eliminate the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

3

(

5

c

+

4

d

)

+

6

(

d

2

c

)

(

3

5

c

)

+

(

3

4

d

)

+

(

6

d

)

(

6

2

c

)

15

c

+

12

d

+

6

d

12

c

Next, group like terms:

15

c

12

c

+

12

d

+

6

d

Now, combine like terms:

(

15

12

)

c

+

(

12

+

6

)

d

3

c

+

18

d,

The answer is 3:4.

Given:

\(\to 5c + d = c+ 4d\)

To find:

c:d=?

Solution:

\to 5c + d = c+ 4d

simulating the identical terms:

\(\to 5c -c = 4d-d\\\\\to 4c = 3d\\\\\to \frac{c}{d} = \frac{3}{4}\\\\\therefore\\\to c:d= 3:4\)

so, the ratio is 3:4

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find the distance between (5,2) and (−1,9)

Answers

Answer:

\(d=9.21954\)

Step-by-step explanation:

Distance Formula: \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Simply plug in the 2 coordinates into the distance formula to find distance d:

\(d=\sqrt{(-1-5)^2+(9-2)^2}\)

\(d=\sqrt{(-6)^2+(7)^2}\)

\(d=\sqrt{36+49}\)

\(d=\sqrt{85}\)

\(d=9.21954\)

At a nursery, you pay $6 for 2 plants. At this price, how much would you pay for 11 plants?

Answers

Answer:

You will need to pay 33 dollars for 11 plants.

Step-by-step explanation:

We can use ratios to solve this problem.

$6                 x dollars

------------  = ------------

2 plants           11 plants

Using cross products:

6*11 = 2 *x

66 =2x

Divide each side by 2.

66/2 = 2x/2

33 = x

You will need to pay 33 dollars for 11 plants.

Answer:

$ 33

Step-by-step explanation:

2 plants ⇒ cost $6

Therefore, 1 plant would cost

$6/2 = $3.

To find the cost for 11 plants, we multiply the cost per plant by the number of plants:

Cost for 11 plants = $ 3 × 11 = $ 33.

So, you would pay $ 33 for 11 plants at the given price.

if a1 = 6 and an = na(n-1) + 2 then find the value of a3

Answers

The value of a3 is 30.

What is arithmetic sequence?

An arithmetic sequence is sequence of integers with its adjacent terms differing with one common difference.

If the initial term of a sequence is 'a' and the common difference is of 'd', then we have the arithmetic sequence as:

We are given that a_1 = 6 and \(a_n = n_a(n-1) + 2\)

Then Substitute as needed and do the arithmetic;

a_1 = 6

\(a_n = n_a(n-1) + 2\)

\(a_2 = -5a_1 +2 \\a_2= -5(6) +2 =-28\)

 \(a_ 3 = -5a_2 +2 = -(-28) +2 = 30\)

The value of a3 is 30.

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write inequality shown y=-11/7x-4

Answers

Answer:The inequality represented by the equation y = -11/7x - 4 can be written as:

y ≤ -11/7x - 4

This represents a less than or equal to inequality, indicating that the values of y are less than or equal to the expression -11/7x - 4.

Step-by-step explanation: .

Find the value of x, 6,4, 3x, 4x+1

Find the value of x, 6,4, 3x, 4x+1

Answers

Answer:

If two chords intersect in a circle, then the product of the segments of one chord equals the product of the segments of the other chord.

6(3x) = 4(4x + 1)

18x = 16x + 4

2x = 4

x = 2

how much would it cost to buy 100 shares in ODX group Inc and 300 shares

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The cost to buy 100 shares in ODX group Inc and 300 shares   peer Comms Lts is  

         \(C = \$ 775\)

Step-by-step explanation:

   From the chat we that the cost of 100  ODX shares is  \(\$175\)

    The cost of 100 peer Comms Lts  is  \(\$ 200\)

Hence the cost 300 peer Comms Lts  is  \(k = 3 * 200 = \$ 600\)

Now  the cost of  100 shares in ODX group Inc and 300 shares of  peer Comms Lts  is mathematically evaluated as

           \(C = 175 + 600\)

           \(C = \$ 775\)

 

 

how much would it cost to buy 100 shares in ODX group Inc and 300 shares

The cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

Given in question the graph here is missing.

We have to calculate the total cost of 100 shares in ODX group Inc and 300 shares in peer comms limited in year 5.

From the graph it is clear that, the x axis shows the no. of year and y axis shows the cost of 100 shares for each type.

From graph, the cost of 100 shares of ODX group in year 5 is $175.

And the cost of 100 shares of peer comm Ltd in year 5 is $ 200.

So the total cost of 300 shares of  peer comm Ltd in 5 year is $(\(200\times3\)) or $600.

Now final cost of 100 shares in ODX group Inc and 300 share in peer comm Ltd is \(($600+$175)\) dollars.

Hence the cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

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A college football team plays 10 games during which the season. In how many ways can it
end the season with 5 wins, 4 loses, and 1 tie?

Answers

Answer:

14

Step-by-step explanation:

A 97% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. A preliminary sample standard deviation is 1.4. The smallest sample size n that provides the desired accuracy is

Answers

Answer:

The sample size will be "\(102.5494 \sim 102\)". A further explanation is given below.

Step-by-step explanation:

Let the sample size will be:

= n

The given values are:

Standard deviation,

= 1.4

ME,

= 0.3

As we know,

⇒ \(n=(Z \frac{a}{2}\times \frac{SD}{E})^2\)

On putting the estimated values, we get

⇒    \(=(2.17\times \frac{1.4}{0 .3})^2\)

⇒    \(=(\frac{3.038}{0.3})^2\)

⇒    \(=102.5494 \sim 102\)

5.2: Bowling for Triangles (Part 2)
Here is a visual pattern of dots. The number of dots D(n) is a function of the step number n.

1. What values make sense for n in this situation? What values don't make sense for n?

5.2: Bowling for Triangles (Part 2)Here is a visual pattern of dots. The number of dots D(n) is a function

Answers

Using the pattern, n can represent the the increase of dots according to step.

In the given question we have to find what values make sense for n in this situation.

n is representing the number.

As we can see that there is a pattern given.

In the step 1 have 1 dot, in step 2 have 3 dots, in step 3 have 6 dots and in step 4 have 10 dots.

So if we see the pattern then according to number of step the dots increasing accordingly.

As In step 1 have 1 dot, in step 2, 2 dots increase, in step 3, 3 dots increase and in step 4, 4 dots increase.

So, n can represent the the increase of dots according to step.

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Solve for x
4( 3x - 5) = -2(-x + 8) - 6x

Answers

Answer:

Step-by-step explanation:

12x - 20 = 2x  -16 - 6x

12x - 20 = -4x - 16

16x - 20 = -4x

20x = 20

x = 1

How do you evaluate -98 - 13

Answers

Evaluations can only be done with algebraic equations

Answer:

-111

Step-by-step explanation:

Subtract 13 from -98  

A company is going to make an oil container in the shape of a cylinder. As shown below, the container will have a height of 6m and a diameter of 6m. The container will be made from steel (including its top and bottom). If the steel costs $27 for each square meter, how much will the steel cost in total? If necessary, refer to the list of geometry formulas. For your calculations, do not round any intermediate steps, and use the π button on the ALEKS calculator. Round your answer to the nearest cent

Answers

Answer:

The cost of required steel is \(169.56 *27 = 4578.12\) dollars

Step-by-step explanation:

The surface area of cylinder will be equivalent to the area of the steel sheet.

Surface area of cylinder \(= 2\pi rh+2\pi r^2\)

Substituting the given values we get

Surface area of cylinder

\(= 2*3.14*3*6 + 2*3.14 *3^2\\= 169.56\)square meter

Cost of 1 square meter of steel is  $27

Then, the cost of required steel is

\(169.56 *27 = 4578.12\) dollars








A rectangle has vertices on a coordinate plane at points E(-2,-2), F(-2,5), G(4,5), and H(4,-2). What is the length of side EF

Answers

Answer:

7 cm

Step-by-step explanation:

1+1+90+1000+=
YOu will get 70 points

Answers

Answer:

THe answer is 1092.

Step-by-step explanation:

1 + 1 + 90 + 1000

2 + 90 + 1000

92 + 1000

1092

Answer:

YEA!! THX

Step-by-step explanation:

Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure. Suppose the target tire pressure of a certain car is 28 psi (pounds per square inch.)



(a) At what psi will the TPMS trigger a warning for this car? (Round your answer to 2 decimal place.)



When the tire pressure is
below

20.16
psi.



(b) Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 3 psi. If the car’s average tire pressure is on target, what is the probability that the TPMS will trigger a warning? (Round your answer to 4 decimal places.)



Probability



(c) The manufacturer’s recommended correct inflation range is 26 psi to 30 psi. Assume the tires’ average psi is on target. If a tire on the car is inspected at random, what is the probability that the tire’s inflation is within the recommended range? (Round your intermediate calculations and final answer to 4 decimal places.)

Answers

Answer:

Step-by-step explanation:

Hello!

The monitoring system warn the driver when the tire pressure of the vehicle is 28% below target pressure.

Be X: target tire pressure of a certain car (pounds per square inch)

a)

X= 28 psi

If the monitoring system will warn the driver when the pressure is 28% below the target pressure: X-0.28X

First step, you have to calculate the 28% of 28psi

28*0.28= 7.84

Second step, is to subtract the calculated 28% to the target pressure:

28 - 7.84= 20.16

The TPMS will trigger a warning at 20.16 psi.

b)

If X~N(μ;σ²)

μ= 28psi (since the average is on target, then the target pressure for the car will be the average value of the distribution)

σ= 3psi

P(X≤20.16)

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now you have to look for the corresponding value of probability using the Z-table. Since the value is negative you have to the use the left entry of the Z-table, in the first column you'll find the integer and first decimal of the value -2.6- and in the first row you'll find the second decimal value -.-1

The value of probability that corresponds to -2.61 is:

P(Z≤-2.61)= 0.005

c)

You have to calculate the probability of inspecting a tire at random and it being inflated within recommended range, symbolically this is:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Calculate both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

The probability of the tire being inflated within recommended inflation range is 0.498.

I hope this helps!

Using the normal distribution, it is found that:

a) The warnings triggers at 20.16 psi.

b) 0.0045 = 0.45% probability that the TPMS will trigger a warning.

c) 0.4972 = 49.72% probability that the tire’s inflation is within the recommended range.

------------------------

Normal Probability Distribution

We use the z-score formula, given by:

\(Z = \frac{X - \mu}{\sigma}\)

\(\mu\) is the mean.\(\sigma\) is the standard deviation. It measures how many standard deviations the measure is from the mean. Each z-score has a p-value, which is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

------------------------

Item a:

28% below 28 psi is 100 - 28 = 72% of 28 psi, that is:

\(0.72(28) = 20.16\)

The warnings triggers at 20.16 psi.

------------------------

Item b:

Mean of 28 psi, thus, \(\mu = 28\)Standard deviation of 3 psi, which means that \(\sigma = 3\)The probability of a warning is the p-value of Z when X = 20.16.

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{20.16 - 28}{3}\)

\(Z = -2.61\)

\(Z = -2.61\) has a p-value of 0.0045.

0.0045 = 0.45% probability that the TPMS will trigger a warning.

------------------------

Item c:

Between 26 and 30 psi, which is the p-value of Z when X = 30 subtracted by the p-value of Z when X = 26. Thus:

X = 30

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{30 - 28}{3}\)

\(Z = 0.67\)

\(Z = 0.67\) has a p-value of 0.7486.

X = 26

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{26 - 28}{3}\)

\(Z = -0.67\)

\(Z = -0.67\) has a p-value of 0.2514.

0.7486 - 0.2514 = 0.4972.

0.4972 = 49.72% probability that the tire’s inflation is within the recommended range.

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5m+ 4 -m + 3/5 - 15m​

Answers

Final \(-11m + \frac{23}{5}\)

Steps/Reasons/Explanation:

Question: Solve \(5m + 4 - m + \frac{3}{5} - 15\).

Step 1: Collect like terms.

\((5m - m - 15m) + (4 + \frac{3}{5})\)

Step 2: Simplify.

\(-11m + \frac{23}{5}\)

~I hope I helped you :)~

A comet travels at an average speed of 273,000 km/h.
It takes 8 days for the comet to reach Earth.
Find the distance, in km, the comet travelled

Answers

Answer: 52,416,000 km

Step-by-step explanation:

If a comet travels 273,000 km/hr

1) Multiply 273,000 km by 24 hours to find how far the comet travels in one day

2) multiply the answer from 1 by 8 to determine how far it travels in 8 days

1) \(\frac{273,000 km}{hr}\)*\(\frac{24 hr}{1 day}\) = \(\frac{6,552,000km}{day}\) (hours cancel out)

2)\(\frac{6,552,000km}{day}\)*8 day= 52,416,000 km in 8 days

The comet approximately travelled 52,416,000km from when it began to travel to when it reached Earth. Hope this helped :)

Please help I’ll mark u <3

Please help Ill mark u &lt;3

Answers

Answer:

x>-4

Step-by-step explanation:

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