engine oil reduces friction between the moving parts in in a car energy by
a.) cooling the engine
b.) making the parts sticky so that they move more slowly.
c.) making the parts slippery
d.) two of the above

Explanation:

Starting position at x  = 16m

Ending position at x  = -25m

Time of flight  = 4s

Unknown:

Distance flown  = ?

Displacement  = ?

Speed  = ?

Velocity  = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;  

  So distance  = 16 + 25  = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

      Speed  = \(\frac{distance}{time}\)   = \(\frac{41}{4}\)   = 10.25m/s

Velocity is 10.25m/s along -x axis

Answer:

When current is reduces to 0.3 A resistance of the bulb would be 400 ohms.

Explanation:

We know Power (P)  = I(Current). V(Voltage)

Rearranging this equation we get,

I = P/ V

We have P = 75 W and V = 120 V

Thus, 75 W / 120 V

= 0.625 A

Using Ohm's law to find the resistance that would be needed to reduce the current to 0.3 A:

R = V / I

= 120 V / 0.3 A

= 400 ohms

Therefore, a resistance of 400 ohms will be needed to reduce the current to 0.3 A.

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Pption d. flow does not independently influence the speed of water in a stream. Instead, it is an outcome determined by the combined effects of gradient, discharge, and channel geometry.

The flow itself, or the rate at which water moves in a stream, is not an independent factor that influences the speed of water in a stream. Instead, it is a result of other factors such as gradient, discharge, and channel geometry.

a. Gradient: The gradient, or slope, of the stream affects the speed of water. Steeper gradients generally lead to faster-flowing water.

b. Discharge: The discharge of a stream, which refers to the volume of water passing through a given point in a specified amount of time, directly affects the speed of water. Higher discharge results in faster flow.

c. Channel geometry: The shape and dimensions of the stream channel also influence the speed of water. Wider and deeper channels tend to have slower flow, while narrower and shallower channels often lead to faster flow.

Therefore, option d. flow does not independently influence the speed of water in a stream. Instead, it is an outcome determined by the combined effects of gradient, discharge, and channel geometry.

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When the string breaks at point a, the ball will continue to move in a straight line tangent to the point on the circle where it broke free. The third curve most accurately represents the path the ball will take after the string breaks.

This means that the ball will continue moving in the direction it was moving at the moment the string broke. In the first curve, the ball appears to continue moving in a circle, which is not possible as it has lost its centripetal force.

The second curve shows the ball moving in a straight line in the direction of its velocity at point a, which is the correct direction. However, the curve appears to be too steep as the ball should continue moving in a straight line with constant velocity. The third curve shows the ball moving in a straight line with constant velocity, which is the correct behavior.

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The maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 v is 75 A.

To calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V, we need to use the equation: `V = E - Ir`, where `V` is the terminal voltage, `E` is the electromotive force, `I` is the current, and `r` is the internal resistance of the battery.Rearranging the equation, we get: `I = (E - V)/r`Substituting the given values, we get: `I = (9.00 V - 8.90 V)/0.012 Ω`I = 8.33 ΩΩ, or 75 A (rounded to the nearest whole number).Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

We know that the internal resistance of the battery is 0.012 Ω and the electromotive force is 9.00 V. The formula used to calculate the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is I = (E - V)/r.Here, E = 9.00 V, V = 8.90 V, and r = 0.012 Ω.I = (9.00 V - 8.90 V)/0.012 ΩI = 83.3 ΩΩRounding off to the nearest whole number gives the answer of 75 A. Therefore, the maximum current that can be drawn from the battery without the terminal voltage dropping below 8.90 V is 75 A.

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Answer:

Please find the answer in the explanation

Explanation:

Given that a scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of a mountain.

Since a weather map indicates that a warm front is approaching the mountain, according to the conventional current, the warm front is approaching because the weather must have been in higher relative humidity in cool air.

The warm front is approaching to replace it so that the cool air can conventionally replace the warmth air too.

The condition the scientists will most likely observe at the top of the mountain will be high relative humidity.

Answer:

D. The overall enthalpy change for a reaction is independent of the route the reaction takes.

Answer: Hess's law states that the overall enthalpy change for a reaction is independent of the route the reaction takes. Option D is correct.

It is given Hess's law.

It is required to state the Hess's law.

Thermochemical equations can be manipulated to give the data chemical reactions. We find exactly how much energy will be absorbed or released by the reaction because we may face various explosions.

There are mainly two ways to calculate ΔH of any reaction. First If the reaction has ΔH then the reverse of the reaction will have opposite ΔH and the second is if double the ΔH of the substances, double the ΔH.

Therefore Hess's law states that the overall enthalpy change for a reaction is independent of the route the reaction takes.

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The solar system is the planetary system that includes the Sun and all of the objects that orbit around it. These objects include planets, dwarf planets, moons, asteroids, comets, and other space debris.

The eight planets in the solar system, in order of their distance from the Sun, are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. Pluto was previously classified as the ninth planet but has since been reclassified as a dwarf planet.

The largest planet in the solar system is Jupiter, which is also the fifth planet from the Sun. Jupiter is a gas giant, meaning that it is primarily composed of hydrogen and helium, and has numerous moons, including the four largest known as the Galilean moons.

The inner planets, including Mercury, Venus, Earth, and Mars, are known as the terrestrial planets because they are primarily composed of rock and metal. They are also relatively small in size compared to the gas giants.

The solar system is constantly in motion, with each object following its own unique orbit around the Sun. These orbits are affected by the gravitational pull of other objects in the solar system, which can cause objects to change their paths or collide with one another.

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The distance of separation between the wires so that the top wire will be held in place by magnetic repulsion is 0.00428 m or approximately 4.28 mm.

To find the distance of separation between the wires, we can use the formula for the magnetic force between two parallel wires carrying currents. The force per unit length between two parallel wires carrying currents I1 and I2, separated by a distance d is given by:

F = μ0/2π × I1 × I2 / d

where μ0 is the permeability of free space, which has a value of 4π x \(10^{-7}\) N/A².

In this problem, the top wire is carrying a current of I1 = 29.1 A and the bottom wire is carrying a current of I2 = 59.5 A. The force per unit length on the top wire due to the magnetic repulsion from the bottom wire is equal to its weight per unit length, which is given as 0.081 N/m. So we have:

F = 0.081 N/m

I1 = 29.1 A

I2 = 59.5 A

μ0 = 4π x \(10^{-7}\) N/A²

Substituting these values in the formula above, we can solve for the distance d:

d = μ0/2π × I1 × I2 / F

d = (4π x \(10^{-7}\) N/A²)/(2π) × 29.1 A × 59.5 A / 0.081 N/m

d = 0.00428 m

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Answer:

P = 4707.692 watts

Explanation:

To find work:

Work = Force * Displacement

W= 255 N * 48 m

W = 12240 J

now we can find power:

Power = Work / Time

P = 12240 J / 2.6 s

P = 4707.692 watts

Historically, photographs taken by American spy planes at high altitudes have been used for various purposes such as reconnaissance and intelligence gathering.

Depending on the specific photograph in question, it could potentially show a wide range of information such as military installations, troop movements, or other sensitive information. The altitudes at which a photo is taken can affect the level of detail that can be seen in the image. However, it is important to note that the use of such technology can also raise privacy and security concerns, particularly if it is used to gather information on individuals or groups without their consent or knowledge.

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let the bowling ball initially is moving along the x-axis,

The whole process can be represented as,

Before the collision the net kinetic energy of the balls is,

where the values of the variables are given as,

As the value of cos(90) is zero.

Substituting the known values,

The value of the net kinetic energy with the velocity along the y-axis before the collision is,

The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.

After the collision of the balls, the net kinetic energy is,

Negative sign here indicating the direction of the final balls motion will be opposite to the each other.

The values of the variables are given as,

Substituting the known values,

The value final kinetic enegry of the balls with velocity along the y-axis is,

Here 360 degree is used because the pin ball direction is downward of the positive x-axis.

Then by the law of conservation of energy along the y-axis,

Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.

The natural length of the spring is approximately 3.67 meters, rounded to the nearest hundredth.

Using the given information, we can apply Hooke's Law, which states that the force required to stretch or compress a spring is proportional to the displacement from its natural length. Mathematically, this is represented as:

F = k * x

where F is the force applied, k is the spring constant, and x is the displacement from the natural length.

Let L be the natural length of the spring. When the spring is stretched from 4m to 5m, the displacement is 5 - L, and the work done is 4J. Similarly, when the spring is stretched from 5m to 9m, the displacement is 9 - L, and the work done is an additional 4J.

Using the work-energy theorem, the work done on the spring is equal to the change in potential energy, which can be represented as:

W = (1/2) * k * (x2^2 - x1^2)

We can set up two equations based on the given information:

4 = (1/2) * k * ((5 - L)^2 - (4 - L)^2)
4 = (1/2) * k * ((9 - L)^2 - (5 - L)^2)

We can solve these equations simultaneously to find the spring constant, k, and the natural length, L. Upon solving, we get:

L ≈ 3.67 meters

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Explanation:

tan ● = opposite / adjacent

tan 31.5 = 19 / F

0.613 = 19 / F

0.613F = 19

F = 31

sin ● = opposite / hypotenuse

sin 31.5 = 19 / a

0.52 = 19 / a

0.52a = 19

a = 36. 36

Using trigonometry, the base of the triangle is approximately 33.476, and the hypotenuse of the triangle is approximately 38.118.

To find the base and hypotenuse of a right triangle with one angle of 31.5 degrees and a given height of 19:

Here,

Opposite side = height = 19 (given)

Adjacent side = base (unknown)

Hypotenuse = hypotenuse (unknown)

First, let's find the base (adjacent side):

tan(θ) = opposite ÷ adjacent

tan(31.5 degrees) = 19/base

To find the base, we can rearrange the equation:

base = opposite ÷ tan(θ)

base = 19 ÷ tan(31.5 degrees)

Calculating the value:

base ≈ 33.476

So, the base of the triangle is approximately 33.476.

Now, using the Pythagorean theorem, we can write:

hypotenuse² = base² + opposite²

hypotenuse² = (33.476)² + 19²

hypotenuse ≈ 38.118

Therefore, the hypotenuse of the triangle is approximately 38.118.

Thus, base is 33.476, and hypotenuse is 38.118.

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The controversial psychological study of prison life that took place in 1971 is known as the Stanford Prison Experiment. It was conducted by psychologist Philip Zimbardo and his team at Stanford University to examine how individuals adapt to the roles of prisoners and prison guards in a simulated prison environment.

The study involved 24 male college students who were randomly assigned to either the role of prisoner or guard. The experiment quickly spiraled out of control as the guards began to abuse their power, and the prisoners became increasingly submissive and depressed. The guards used psychological tactics such as humiliation, sleep deprivation, and even physical punishment to maintain their authority over the prisoners.

The study was meant to last for two weeks, but it was terminated after just six days due to the extreme and abusive behavior of the guards. The Stanford Prison Experiment remains controversial due to ethical concerns about the mistreatment of the participants and the potential long-term psychological effects on those who took part.

The study has had a significant impact on the field of psychology and has raised important questions about the ethics of conducting psychological research. It has also shed light on the dangers of group dynamics and how individuals can be easily influenced by social roles and situations.

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This is the formula for the equilibrium number density of particles with net weight mnetg as a function of the height r. The constant prefactor is given by: N/(A(kBT/mg)(1 - exp[-mgh/(kBT)]))

Starting with Equation 5.1 for the particle density in equilibrium:

c(r) = c(0) * exp[-mg(r-z)/(kBT)]

here c(r) is the number density of particles at height r, c(0) is the number density of particles at height z=0 (the bottom of the test tube), m is the mass of a particle, g is the acceleration due to gravity, kB is the Boltzmann constant, T is the temperature, and z is the height of the bottom of the test tube.

To find the constant prefactor, we need to use the fact that the total number of particles is N, and the test tube cross-section is A. We can integrate the number density over the entire height of the test tube to find the total number of particles:

N = ∫c(r) A dr

We can substitute the expression for c(r) into this equation:

N = A c(0) ∫exp[-mg(r-z)/(kBT)] dr

To evaluate this integral, we make the substitution u = mg(r-z)/(kBT):

du/dr = mg/(kBT)

dr = kBT/(mg) du

The limits of integration also change:

when r = z, u = 0

when r = z+h, u = mgh/(kBT)

Substituting these into the integral:

N = A c(0) ∫exp[-u] (kBT/mg) du from 0 to mgh/(kBT)

N = A c(0) (kBT/mg) [-exp(-u)] from 0 to mgh/(kBT)

N = A c(0) (kBT/mg) (1 - exp[-mgh/(kBT)])

Solving for c(0), we get:

c(0) = N/(A(kBT/mg)(1 - exp[-mgh/(kBT)]))

Substituting this expression for c(0) into the original equation for c(r), we get:

c(r) = N/(A(kBT/mg)(1 - exp[-mgh/(kBT)])) * exp[-mg(r-z)/(kBT)]

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Acid rain is the result of pollutants being released into the air

Acid rain is defined as rain or any other type of precipitation that is unusually acidic, which means it contains a lot of hydrogen ions. Acid rain has a pH level that is lower than this and typically ranges from 4-5. Most water, including drinking water, has a neutral pH that exists between 6.5 and 8.5.

When gases like sulphur dioxide and nitrogen oxides are released into the atmosphere, a chemical reaction takes place that eventually results in acid rain. These substances have the capacity to ascend to extremely high altitudes in the atmosphere, where they combine and interact with oxygen, water, and other chemicals to create acid rain, a type of ozone-depleting haze.

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For Machine 1  ideal mechanical advantage is 4, for machine 2 the IMA is 8 and for the machine 3 the IMA is 4. The load the machines can lift is 400N, 800N and 200N respectively.

The ideal mechanical advantage of a machine is an important factor in determining its efficiency and usefulness. The higher the IMA, the easier it is to lift heavy loads with less effort. However, it is important to note that the actual mechanical advantage (AMA) may differ from the ideal due to various factors such as friction and other mechanical losses. Therefore, it is essential to consider both IMA and AMA when evaluating the performance of a machine.

Machine 1:

Ideal Mechanical Advantage (IMA) = Load / Effort

IMA = 400 N / 100 N

= 4

Machine 2:

IMA = Load / Effort

IMA = 800 N / 100 N

= 8

Machine 3:

IMA = Load / Effort

IMA = 200 N / 50 N

= 4

In simple terms, the ideal mechanical advantage (IMA) of a machine is the ratio of the load it can lift to the effort or force needed to lift it. In other words, it is the number of times a machine multiplies the force or effort applied to it.

For Machine 1, the IMA is 4, which means that the machine can lift a load that is four times heavier than the applied force. Therefore, if you apply 100 N of force to the machine, it can lift a load of up to 400 N.

For Machine 2, the IMA is 8, which means that it can lift a load that is eight times heavier than the applied force. If you apply 100 N of force to this machine, it can lift a load of up to 800 N.

For Machine 3, the IMA is 4, which means that it can lift a load that is four times heavier than the applied force. If you apply 50 N of force to this machine, it can lift a load of up to 200 N.

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Answer

True; Destructive occurs for two interfering waves that are 180 degrees out of phase

The net effect of the sodium-potassium pump is to create a transmembrane electrical potential.

Sodium-potassium pump is a process in which sodium ions (Na+) are transported out of the cell while potassium ions (K+) are transported into the cell. The net effect of this process is that there is a greater concentration of K+ ions inside the cell and a greater concentration of Na+ ions outside the cell.

This creates an electrochemical gradient across the cell membrane. This gradient is what allows cells to carry out a variety of functions such as transmitting signals and carrying out metabolic processes. The electrochemical gradient is also what drives the movement of other molecules across the cell membrane.

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Answer:

the new resister is 11 ohms.

Explanation:

Set it  up like this.

1/x + 1/1.1 = 1                    Subtract 1/1.1 from both sides

1/x = 1 - 1/1.1

1 - 1/1.1 = 1/11

1/x = 1/11                          Cross multiply

11 = x

If 1/11 bothers you, you could do it it another way.

1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1  Multiply top and bottom by 10

0.1*10/(1.1 * 10 ) = 1 / 11

Answer:

162,500

Explanation:

P=F(t)

32500=F(2)

162,500

The force exerted by the fuel on the shutter will be "162500 N". To understand the calculation, check below.

According to the question,

Change in momentum, ΔP = 325,000 kg.m/s

Time, Δt = 2 sec

Mass = 13,000 kg

We know the relation,

→ Force, F = \(\frac{dP}{dt}\) or,

                 = \(\frac{\Delta P}{\Delta t}\)

                 = \(\frac{Change \ in \ momentum}{Time}\)

By substituting the values,

                 = \(\frac{325000}{2}\)

                 = 162500 N

Thus the above answer is correct.

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Answer:

A

Explanation:

There is a mechanical advantage in this system....

    she only needed 100 N to lift 500 N

        1:5      she lifted it 2 meters, so if there WAS NO friction, she would have to pull in 5 x 2 = 10 meters

   but there IS friction so she must have pulled in MORE than 10 m  

Answer:

A 4.0 kg box is pressed into a spring. The spring constant is k = 220 N/m. The box is released at the bottom of a frictionless ramp and rises to a height of y = 0.75 m as shown below.

How far was the spring compressed?

Answer: 0.52 m

There would be no change as the wave speed would be 1. Option B

According to the wave equation for a string, the wave speed (v) is given by the equation:

v = √(T/μ)

Tripling both the tension in a guitar string and its mass per unit length;

T₂ = 3T₁ (tripling the tension)

μ₂ = 3μ₁ (tripling the mass per unit length)

We have for  the wave speed

v₂ = √(T₂/μ₂)

= √((3T₁)/(3μ₁))

= √(T₁/μ₁)

= v₁

We can see that based on the calculations that we have done in the problems. It is plane that there is no change in the wave speed.

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Answer:

The mobile electric energy gets converted into chemical energy while charging.

Explanation:

According to the law of conservation of energy, no energy is destroyed when one form of energy is transformed to another in the process as energy cannot be created or destroyed. As a result, total amount of energy remains same before and after any kind of transformation.

Generally, lithium ion batteries are used in mobile phones. In such batteries, the electricity is stored in the ionic structure by the chemical changes.

The mobile electric energy gets converted into chemical energy while charging.

When 70 Newton dog ran across the yard. we know The dog's weight. Hence option B is correct.

Force(F) applied on the body is mass(m) times its acceleration(a). i.e. F=ma according to this equation we get acceleration as a = this equation says that when we apply more force to the body, more acceleration it gets. When more is the mass of the body, greater force is needed to accelerate with same amount to that less mass.

70N dog means it is his weight, from which we can calculate its mass, by relation F = mg where g is acceleration due to gravity.

Hence for objective option B is correct, and for MSQ Both B and C is correct.

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