Energy from the Sun is transferred from the Earth’s surface to the atmosphere, resulting in
atmospheric convection currents that produce winds. How do physical properties of the air
contribute to convection currents?

a -The warmer air sinks because it is more dense than cooler air.
b -The warmer air rises because it is more dense than cooler air.
c- The warmer air sinks because it is less dense than cooler air.
d -The warmer air rises because it is less dense than cooler air.

ANSWERS

(a) 650 N

(b) 650 N

(c) 7150 J

(d) An example would be "what is the coefficient of kinetic friction between the dummy and the ground?"

EXPLANATION

Given:

• The constant velocity of the football player and dummy, v = 0.85 m/s

• The distance the player pushes the dummy for, d = 11 m

• The energy used by the player to push the dummy, E = 7150 J

• The mass of the tackling dummy, m = 120 kg

First, we have to draw a free-body diagram of this situation,

(a) The energy that the player uses to push the dummy is the work done,

So the force is,

Hence, the football player exerts a force of 650 N on the dummy.

(b) We know that the football player and the dummy are moving at a constant velocity. This means that the acceleration is 0, so, by Newton's second law of motion,

So the force of friction the dummy exerts is equal to the force exerted by the football player,

Hence, the frictional force the dummy exerts is 650 N.

(c) Since the frictional force the dummy exerts is equal to the force that the football player exerts, and the distance it is applied for is the same, then the work done is the same as well.

Hence, the work done by friction as the dummy is slid along the field for 11 m is 7150 J.

(d) No, mass is not necessary for this question. A force question that would involve the mass of the dummy would be a question involving the weight of the dummy and, therefore, its mass.

A question like this may be "what is the coefficient of kinetic friction between the dummy and the ground?". In this case, we would need to use the frictional force, found in part (b), and the normal force of the dummy, which is equal to its weight - this is because it is not moving in the vertical direction.

Answer and Explanation:

A.

There would be a net force of 50 N going to the right.

Since both forces are going right, they add onto the force amount.

#teamtrees #PAW (Plant And Water)

Answer:

I think it's light year but there shouldn't be also km/s but km/h

Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .

Heat lost by iron  = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam  = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:

Q3m x c x ΔT1 = m x c x ΔT2 + ms x L

Let's calculate the value of Q1 first.

Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)

We know that

c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg

°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg

Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J

Now, let's calculate the value of Q2

.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)

We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =

(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg

Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.

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Answer:

B. Motion

Explanation:

I took the test and got 100%, the person who answered before me is correct, please mark me brainliest

Surface tension is the energy required to increase the surface area of a liquid.  Option (b)

Surface tension is the propensity of liquid surfaces at rest to shrink to the smallest feasible surface area. Surface tension permits items with a higher density than water, such as razor blades and insects (such as water striders), to float on the water's surface without being immersed.

Surface tension at liquid-air contacts is caused by the higher attraction of liquid molecules to each other (owing to cohesion) than to air molecules (due to adhesion).There are two main systems at work. The first is an inward strain on the surface molecules, which causes the liquid to constrict.

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According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.

1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.

E = (1/4πϵ0) (Q/r^2)

where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.

The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:

Φ = ∫E⋅dA = E ∫dA = E(2πR)L

Substituting the expression for the electric field, we have:

Φ = (Q/2ϵ0r^2)(2πRL)

Therefore, the outward electric flux through the rounded "side" of the cylinder is:

Φ = (Q/ϵ0)(R/Lr^2)

2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:

E = (1/4πϵ0) (Q/R^2)

The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:

Φ = ∫E⋅dA = E ∫dA = EπR^2

Substituting the expression for the electric field, we have:

Φ = (Q/ϵ0)(R/r^2)

3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:

Φ = (Q/ϵ0)(R/r^2)

4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:

Φ_total = Φ_side + Φ_top + Φ_bottom

= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)

Simplifying this expression, we have:

Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]

5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:

Φ_total = Q/

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The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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The distance from O to S is 64.5 m.

(a) The force acting on the particle P can be found using Newton's second law, which states that the net force on an object is equal to its mass times its acceleration. In this case, the acceleration is the time derivative of the velocity:

−→a = d−→v/dt = 6−→i + (2t+3)−→j (m/s^2)

The net force is therefore:

−→F = m−→a = 0.4(6−→i + (2t+3)−→j) = 2.4−→i + (0.8t+1.2)−→j (N)

At t = 4 s, we have:

−→F = 2.4−→i + (0.8(4)+1.2)−→j = 2.4−→i + 4.8−→j

The magnitude of the force is:

|−→F| = √(2.4^2 + 4.8^2) = 5.34 N (rounded to two decimal places)

Therefore, the magnitude of the force when t = 4 s is approximately 5.34 N.

(b) The displacement vector from O to S is:

−→OS = −→OP + −→PS

where −→OP = −3−→i + 4−→j (given) and −→PS is the displacement vector from P to S. We can find −→PS by integrating the velocity vector from t = 0 to t = 4:

−→PS = ∫(6t+4)−→i + (t^2+3t)−→j dt = [(3t^2+4t)−→i + (1/3)t^3+(3/2)t^2] from 0 to 4

−→PS = 44−→i + 46.67−→j (m)

Therefore,

−→OS = −3−→i + 4−→j + 44−→i + 46.67−→j = 41−→i + 50.67−→j (m)

The distance |−→OS| is:

|−→OS| = √(41^2 + 50.67^2) = 64.5 m (rounded to one decimal place)

Therefore, the distance from O to S is approximately 64.5 m.

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Answer:

hope it helps

Explanation:

1. flowing water

2.wind

3. hydroelectric power station

4. dam

5. lake

6. gravitational

7. renewable

8. fuel

9. pollution

10. expensive

11. flood

Answer:

the most common way to measure mass is using a balance.

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

An argument about the likely kinetic energy of the ball before and after the collision with the can is can remain the same, halved and completely transferred.

In physics, we understand as a collision process the interaction between two or more bodies, initially free (that is, there is no interaction between them). Collision is usually divided into three categories: elastic collision, partially elastic collision and inelastic collision.

Analyzing for each of these cases we have that the kinetic energy before and after the collision will be:

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One parameter of the system that is held constant that can be considered is the mass of the water.

In science, the constant is a type of unmodified variable that remains equal along with the experimental procedure.

The constants of a particular system must be considered and they cannot change in experiments or observations.

In conclusion, one parameter of the system that is held constant that can be considered is the mass of the water.

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Answer: The magnetic field at a point 1.0 cm from the central axis of the solenoid is 0.0276 T.

Explanation:

Given: Length = 0.50 m

No. of turns = 500

Current = 22 A

Formula used to calculate magnetic field is as follows.

\(B = \mu_{o}(\frac{N}{L})I\)

where,

B = magnetic field

\(\mu_{o}\) = permeability constant = \(4\pi \times 10^{-7} Tm/A\)

N = no. of turns

L = length

I = current

Substitute the values into above formula as follows.

\(B = \mu_{o}(\frac{N}{L})I\\= 4 \pi \times 10^{-7} Tm/A \times (\frac{500}{0.5 m}) \times 22\\= 0.0276 T\)

Thus, we can conclude that magnetic field at a point 1.0 cm from the central axis of the solenoid is 0.0276 T.

a) The average force with which the woman pushed the man is 210 N.

b.  the woman's recoil speed is still 3.68 m/s

c.  If  she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.

We first calculate  the Momentum  = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)

v = 3.68 m/s

Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s

The average force exerted on the man by the woman is:

Average force =   Δp / Δt

Average force  = 105 kg·m/s / 0.500 s

Average force  = 210 N

b) The woman's recoil speed is :

0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

v = 3.68 m/s

c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.

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Figure B5.1 is a diagram showing a wave travelling along a string. The wave is propagating in the rightward direction, as indicated by the curved arrows.

Direction is a type of guidance that provides the recipient with specific instructions on how to proceed. Direction can involve information on where to go, what to do, or what to avoid. It could be used to provide instructions on a task, a journey, or an event. Direction could also be used to provide motivation and help someone stay focused on their goals. Direction can be provided verbally, through writing, or through body language. It can come from a supervisor, a teacher, or a parent. Direction is important in helping someone follow their path and achieve their goals.

The wave is depicted by a series of oscillations along the string, represented by the vertical lines. The amplitude of the wave is represented by the distance between the highest and lowest points of the oscillations. As the wave travels in the rightward direction, the oscillations move along the string, and the amplitude remains unchanged.

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Tension in the left cable is 4395.9 N.

Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.

Here,

The total mass of the riders is given, m = 330 kg

Let the tension in the left cable be T₁ and that in the right cable be T₂.

From the figure,

T₁ cos 15 = T₂ cos 26

T₁ = T₂ cos 26/cos 15

Also,

T₁ sin15 + T₂ sin 26 = mg

Substituting values,

(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8

0.241 T₂ + 0.438 T₂ = 3234

0.679 T₂ = 3234

T₂ = 4762.8 N

Therefore, Tension in the left cable, T₁ = 0.930x 4762.8

         T₁ = 4395.9 N

Hence, The tension in the left cable is 4395.9 N

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Your question was incomplete. Attaching the image here.

Answer:

I hope this helps

Answer:

A. reduce the amount of soil by one-half and apply the same amount of force

Explanation:

Answer:

Explanation:

The speed of the cat can be found by using the formula

\(v = \frac{d}{t} \\ \)

d is the distance

t is the time taken

From the question we have

\(v = \frac{9}{16} = \\ = 0.5625\)

We have the final answer as

Hope this helps you

Answer: 490

Explanation:

The rise in temperature of the body as determined from the specific heat capacity, mass, and heat change of the body is 12.24 °C.

The rise in temperature of the body is determined from the specific heat capacity, mass, and heat change of the body.

The formula relating the temperature rise of the body, the specific heat capacity, mass, and heat change of the body is given below:

Heat change = mass * specific heat capacity * temperature rise

Temperature rise = Heat change / mass * specific heat capacity

Temperature rise = 3.6 * 10⁶ J / 84 kg * 3,500 J/kg/°C

Temepartaure rise = 12.24 °C

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Answer:

Newton's theory because he suggested that the greater the distance between objects, the weaker the pull of gravity.

Answer: The answer is Newton’s theory because he suggested that the greater the distance between objects, the weaker the pull of gravity

Explanation: Just took the test i hope this help you enjoy :D

The mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. The number that was removed is 75.

To solve this problem, we can use the concept of the mean (average) and apply it to the given information. Let's go through the steps to determine the number that was removed.

Step 1: Find the sum of the 6 numbers.

Since the mean of the 6 numbers is 25, we can multiply the mean by the total number of values to find the sum. In this case, 25 * 6 = 150.

Step 2: Find the sum of the remaining numbers.

To find the sum of the remaining numbers, we need to subtract the number that was removed from the original sum. Let's denote the number that was removed as "x". Therefore, the sum of the remaining numbers is 150 - x.

Step 3: Determine the number of remaining numbers.

Since one number was removed, the total number of remaining numbers is 6 - 1 = 5.

Step 4: Calculate the average of the remaining numbers.

We are given that the average of the remaining numbers is 15. To find the sum of the remaining numbers, we can multiply the average by the number of remaining numbers. Therefore, 15 * 5 = 75.

Step 5: Set up the equation and solve for the removed number.

Now we can set up the equation using the information from Steps 2 and 4. We have the equation: 150 - x = 75.

Step 6: Solve the equation.

To find the value of x, we can solve the equation. Subtracting 75 from both sides gives us 150 - 75 = x, which simplifies to x = 75.

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The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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None of the statements are true of all proteins. Here is a correct statement about proteins:

Proteins are large, complex molecules that perform a wide variety of functions in the body, such as catalyzing metabolic reactions, replicating DNA, responding to stimuli, and transporting molecules from one location to another. They are made up of chains of amino acids, which are linked together in a specific sequence determined by the genetic code. Protein structure and function is highly dependent on the specific sequence of amino acids in the protein, and proteins can take on a wide variety of shapes and sizes, ranging from small, globular proteins to large, fibrous proteins.

Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.