Emily and Rachel had lunch at the mall. Emily ordered two slices of pizza and three cookies and her bill was $8. Rachel ordered one slice of pizza and four cookies and her bill was $9. What was the price of one slice of pizza? What was the price of one cookie?

The sequence of natural numbers that leaves a remainder of 3 when divided by 10 is:

3, 13, 23, 33, 43, 53, 63, 73, 83, 93, 103, 113, ...

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♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The prοbability οf chοοsing a negative number frοm bοth Set A and Set B is 1/10 οr 0.1.

There are 2 negative numbers in Set A οut οf a tοtal οf 4 numbers. Therefοre, the prοbability οf chοοsing a negative number frοm Set A is 2/4 = 1/2.

There is 1 negative number in Set B οut οf a tοtal οf 5 numbers. Therefοre, the prοbability οf chοοsing a negative number frοm Set B is 1/5.

Tο find the prοbability οf chοοsing a negative number frοm bοth sets, we need tο multiply the individual prοbabilities:

P(negative frοm Set A and negative frοm Set B) = P(negative frοm Set A) * P(negative frοm Set B)

P(negative frοm Set A and negative frοm Set B) = (1/2) * (1/5) = 1/10

Therefοre, the prοbability οf chοοsing a negative number frοm bοth sets is 1/10 οr 0.1.

Cοunt the number οf negative numbers in Set A. There are 2 negative numbers.

Cοunt the number οf negative numbers in Set B. There is 1 negative number.

Find the tοtal number οf numbers in Set A. There are 4 numbers.

Find the tοtal number οf numbers in Set B. There are 5 numbers.

Use the fοrmula:

P(negative frοm Set A and negative frοm Set B) = P(negative frοm Set A) * P(negative frοm Set B)

Plug in the values:

P(negative frοm Set A and negative frοm Set B) = (2/4) * (1/5)

P(negative frοm Set A and negative frοm Set B) = 1/10

Therefοre, the prοbability οf chοοsing a negative number frοm bοth Set A and Set B is 1/10 οr 0.1.

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The functions and their transformations are

From the question, we have the following parameters that can be used in our computation:

f(x) = 2(x + 1)² - 3

A translation down by 5 units is represented as

f(x) - 5

So, we have

f(x) - 5 = 2(x + 1)² - 3 - 5

f(x) - 5 = 2(x + 1)² - 8

Rewrite as

h(x) = 2(x + 1)² - 8

A translation left by 5 units is represented as

f(x + 5)

So, we have

f(x + 5) = 2(x + 1 + 5)² - 3

f(x + 5) = 2(x + 6)² - 3

Rewrite as

k(x) = 2(x + 6)² - 3

A translation right by 5 units is represented as

f(x - 5)

So, we have

f(x - 5) = 2(x + 1 - 5)² - 3

f(x - 5) = 2(x - 4)² - 3

Rewrite as

g(x) = 2(x - 4)² - 3

A translation up by 5 units is represented as

f(x) + 5

So, we have

f(x) + 5 = 2(x + 1)² - 3 + 5

f(x) + 5 = 2(x + 1)² + 2

Rewrite as

j(x) = 2(x + 1)² + 2

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Option (A) Names of TV shows taped in New York are an example of qualitative data. Qualitative data is descriptive in nature and does not involve numerical values or measurements.

It deals with qualities or attributes that cannot be expressed numerically. In this case, the names of TV shows are characteristics that describe the nature of the data. Quantitative data, on the other hand, is numerical data that can be measured and expressed in numbers. A parameter is a measurable factor or variable that can be used to define a system, while statistics is a branch of mathematics that deals with data collection, analysis, and interpretation. In conclusion, since the names of TV shows are descriptive in nature and do not involve numerical values, they are an example of qualitative data.

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The 20 in. by 20 in. cardboard used make the box by cutting out squares of length x from the corners gives;

The dimensions that will yield maximum volume are;

Length =

The dimensions of the cut square that gives the maximum volume is approximately 3.3 feet, while the dimensions of the box are;

Length; 13.3 feet

Width; 13.3 feet

Height; 3 feet

The maximum volume of the box is approximately 592.6 ft³

The maximum value of a function is the peak or highest point on the graph of the function.

The volume, V, of a box of Length, L, Width, W and Height, H, is given by the formula;

V = L×W×H

The length, width, and height of the box obtained by cutting a square of side length, x from the corners are;

Height of the box formed = x

Length of the cardboard box = 20 - 2•x

Width of the cardboard box = 20 - 2•x

The volume of the box is therefore;

V(x) = (20 - 2•x)•(20 - 2•x)•x = 4•x³ - 80•x² + 400•x

At the maximum point, we have;

V'(x) = (3×4)•x² - (2×80)•x + 400 = 0

V'(x) = 12•x² - 160•x + 400 = 0

Which gives;

3•x² - 40•x + 100 = 0

(3•x - 10)•(x - 10) = 0

Therefore;

\( \displaystyle{x = \frac{10}{3} }\) and x = 10

When x = 10, we have;

V(10) = 4×10³ - 80×10² + 400×10 = 0

When x = 10/3, we have;

V(10) = 4×(10/3)³ - 80×(10/3)² + 400×(10/3) ≈ 592.6

Therefore, the dimensions of the box that gives the maximum volume is \( \displaystyle{x = \frac{10}{3} \approx 3.3}

The dimensions that yield maximum volume are therefore;

The maximum of the box is 592.6 ft³

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Using right endpoints: The estimated area under the graph of \(\(f(x) = \frac{1}{x+1}\)\) is approximately 0.7413. Using left endpoints:  The estimated area under the graph of \(\(f(x) = \frac{1}{x+1}\)\)  is approximately 0.6063.

The estimation of the area under the graph of \(\(f(x) = \frac{1}{x+1}\)\) over the interval [1, 3]  using four approximating rectangles with right endpoints:

1. Calculate the width of each rectangle: \(\(\Delta x = \frac{b - a}{n} = \frac{3 - 1}{4} = \frac{1}{2}\)\), where (a = 1) is the lower bound of the interval, b = 3 is the upper bound, and n = 4 is the number of rectangles.

2. Determine the x-coordinates of the right endpoints of the rectangles:

  - For the first rectangle: \(\(x_1 = a + \Delta x = 1 + \frac{1}{2} = \frac{3}{2}\)\)

  - For the second rectangle: \(\(x_2 = x_1 + \Delta x = \frac{3}{2} + \frac{1}{2} = 2\)\)

  - For the third rectangle: \(\(x_3 = x_2 + \Delta x = 2 + \frac{1}{2} = \frac{5}{2}\)\)

  - For the fourth rectangle: \(\(x_4 = x_3 + \Delta x = \frac{5}{2} + \frac{1}{2} = 3\)\)

3. Evaluate the function at the right endpoints to get the heights of the rectangles:

  - For the first rectangle: \(\(f(x_1) = f(\frac{3}{2}) = \frac{1}{\frac{3}{2} + 1} = \frac{2}{5}\)\)

  - For the second rectangle: \(\(f(x_2) = f(2) = \frac{1}{2 + 1} = \frac{1}{3}\)\)

  - For the third rectangle: \(\(f(x_3) = f(\frac{5}{2}) = \frac{1}{\frac{5}{2} + 1} = \frac{2}{7}\)\)

  - For the fourth rectangle: \(\(f(x_4) = f(3) = \frac{1}{3 + 1} = \frac{1}{4}\)\)

4. Calculate the area of each rectangle: \(\(A_i = \Delta x \cdot f(x_i)\)\)

  - For the first rectangle: \(\(A_1 = \frac{1}{2} \cdot \frac{2}{5} = \frac{1}{5}\)\)

  - For the second rectangle: \(\(A_2 = \frac{1}{2} \cdot \frac{1}{3} = \frac{1}{6}\)\)

  - For the third rectangle:\(\(A_3 = \frac{1}{2} \cdot \frac{2}{7} = \frac{1}{7}\)\)

  - For the fourth rectangle: \(\(A_4 = \frac{1}{2} \cdot \frac{1}{4} = \frac{1}{8}\)\)

5. Sum up the areas of all the rectangles to get the estimated area under the graph: \(\(A_R = A_1 + A_2 + A_3 + A_4 = \frac{1}{5} + \frac{1}{6} + \frac{1}{7} + \frac{1}{8}\)\)

Now, if you'd like to repeat the approximation using left endpoints, we can follow a similar process with slight modifications.

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Answer:

0.125

Step-by-step explanation:

Hope it helps

Answer:

(5/4) / 10

= (5×10)/4

= 50 / 4

= 25/ 2

= 12.5

Step-by-step explanation:

brainliest plz

Answer:

60%

Step-by-step explanation:

Answer:

Your answer is 3/25

Step-by-step explanation:

Answer:

The answer  is 12/100 or 6/50

Answer:

Around 82-81% aren't yellow.

Step-by-step explanation:

Add together the number of marbles that aren't yellow and divide the total of NON YELLOW with the total (32) to get around 82-81%.

Answer:

932

Step-by-step explanation:

If they have 4 every hour, and there's 233 hours, you multiply 233 by 4.

Hi there!  

»»————-　★　————-««

I believe your answer is:  

\(x - 6 = 5\)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

I am assuming that '3=x divided by 3' is supposed to be \(3 = \frac{x}{3}\).

⸻⸻⸻⸻

The first, second, and fourth equations have x divided by a number. To isolate x, we would have to use the multiplication property of equality.

⸻⸻⸻⸻

For the third one (\(x-6=5\)), the variable 'x' is being subtracted by 6. We would have to use the addition property of equality to isolate x.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

The estimate of the mean length of the insects Ciara found is 17 millimeters (mm).

To calculate an estimate of the mean length of the insects Ciara found, we need to find the weighted average of the lengths using the given frequencies.

Let's denote the lower limits of the length intervals as L1 = 0, L2 = 10, and L3 = 20.

Similarly, denote the upper limits as U1 = 10, U2 = 20, and U3 = 30.

Next, we calculate the midpoints of each interval by taking the average of the lower and upper limits.

The midpoints are M1 = (L1 + U1) / 2 = 5, M2 = (L2 + U2) / 2 = 15, and M3 = (L3 + U3) / 2 = 25.

Now, we can calculate the sum of the products of the frequencies and the corresponding midpoints.

This gives us (5 \(\times\) 5) + (6 \(\times\) 15) + (9 \(\times\) 25) = 25 + 90 + 225 = 340.

Next, we calculate the sum of the frequencies, which is 5 + 6 + 9 = 20.

Finally, we divide the sum of the products by the sum of the frequencies to find the weighted average, which is 340 / 20 = 17.

Therefore, the estimate of the mean length of the insects Ciara found is 17 millimeters (mm).

Thus, the mean length of the insects Ciara found is approximately 17 millimeters (mm).

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Answer:

17.2 cm²

Step-by-step explanation:

Alr let me try

The angle is 1.2 you got it right. The rest is in the pics

Answer: A(shaded)=17.15 cm²

Step-by-step explanation:

What you did so far is correct.

Given:

r=5

s=6

Solve for Ф  angle:

s=\(\frac{part circle}{wholecircle} 2\pi r\)         This way help you find the portion/percent you want

6=(Ф/360) (2\(\pi\)5)       >solve for Ф  Divide by (2\(\pi\)5) and multiply by 360

Ф=68.75

Solve for pie/sector

Now that you have the angle,  you can use the same concept for area

Area of sector = \(\frac{part circle}{wholecircle} \pi r^{2}\)

Area of sector = \(\frac{68.75}{360} \pi 5^{2}\)

Area of sector = 15.0 cm²

Now let find y so we can plug into area of triangle

use tan Ф = opposite/adjacent

tan 68.75 = y/5

y=5 * tan 68.75

y=12.86 cm

Area of triangle = 1/2 b h          b=y=12.86     h =5

Area of triangle = 1/2* 12.86*5

Area of triangle = 32.15 cm²

Now subtract area of sector from triangle

A(shaded)=A(triangle)-A(sector)

A(shaded)=32.15- 15.0

A(shaded)=17.15 cm²

Answer:

\(\frac{18}{19}\)

Step-by-step explanation:

The absolute value of a number is how far away it is from 0 on the number line. Even though \(\frac{-18}{19}\) is a negative number, the absolute value wouldn't be \(\frac{-18}{19}\), because distance can't be negative. Hence the absolute value of \(\frac{-18}{19}\) is \(\frac{18}{19}\).

The minimum is 29 cm and it represents the sensor's minimum height above the ground.

In Mathematics and Geometry, the standard form of a cosine function can be represented or modeled by the following mathematical equation (formula):

y = Acos(Bx - C) + D

Where:

By critically observing the graph which models the sensor's height above the ground (in centimeters) shown in the image attached below, we can reasonably infer and logically deduce that it has a minimum height of 29 centimeters.

In conclusion, the sensor's minimum height above the ground cannot exceed 29 centimeters.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

n = -1.25

Step-by-step explanation:

S(ABCD) = AB × AD

S(ABCD) = 2n × (4n + 5)

S(ABCD) = CD × AD

2n × (4n + 5) = CD × (4n + 5)

n = -1.25

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Answer:

14 minutes

Step-by-step explanation:

We take

63 / 6 = 10.5 words per minute

So, Nachelle can text 10.5 words per minute.

At this rate, how many minutes would it take her to text 147 words?

We take

147 / 10.5 = 14 minutes

So, at this rate, it would take her 14 minutes to text 147 words.

Answer:

You can buy 12 gallons of gas.

Step-by-step explanation:

I took 40 and 3.25, then divided them.

I got a very large ugly decimal. When simplified it is 12.

We have been given the expression 2^5/8=2^2  was used to simplify this expression. 2 to the fifth power, over 8 = 22.

8 can be rewritten as 2^3

Hence, the given expression becomes

2^5/2^3=2^2

After subtracting the exponents on left hand side of the equation we get:

2^2=2^2

we can do it by simplifying 8 to 2^3 to make both powers base two, and subtracting the exponents.

Linear expressions or equations are expressions in which the highest power of the variable is one.

Quadratic expressions or equations are expressions in which the highest power of the variable is two.

Cubic expressions or equations are expressions in which the highest power of the variable is three.

Quartic expressions or equations are expressions in which the highest power of the variable is four.

From the expression, 5x + 2 given,

the highest power of x is one. So it is a linear expression.

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The result is 4

A number's exponent indicates how many times the number has been multiplied by itself. Example: Since 2 is multiplied by itself 4 times, 2222 can be expressed as 24. Here, 4 is referred to as the "exponent" or "power," while 2 is referred to as the "base." Generally speaking, xn denotes that x has been multiplied by itself n times.

The quotient of powers property states that if you have an expression in the form (a^m)/(a^n) where 'a' is the base and 'm' and 'n' are integers, it can be simplified to (a^(m-n)).

In the given expression, 2 to the fifth power (2^5) can be divided by 8 (which is equal to 2^3), using the quotient of powers property. The result is 2^(5-3) = 2^2 = 4

So 2^5 / 8 = 4

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Step-by-step explanation:

to find this angle you can use the sin ratio seeing that the opposite has been given which is 35 and the hypotenuse which is 48.so the solution will be

sin?=opposite/hypotenuse

sin?=35/48

sin?=0.729

?=sin inverse of 0.729

?=46.8 rounded off to 47°

I hope this helps

Hi

in application of sinus formula : ( must learn your trigonimetric formulas by heart !)

value of ? is sin^(-1) = (35/48) = 46,8. so 47 when rounded to the nearest degree

Answer: 1.5 bananas per sundae

Step-by-step explanation:

There was a total of 6 bananas used in making 4 sundaes.

To find the number of bananas used per sundae, you should divide the number of bananas by the number of sundaes.

= No. of bananas / No. of sundaes

= 6 / 4

= 1.5 bananas per sundae

Answer:

Step-by-step explanation:

-4.32193257293

Answer:

371 students

Step-by-step explanation:

100% = 530

10% = 53

30% = 53 x 3 = 159

159 students are footballers.

Now we subtract.

530 - 159 = 371

371 students are not footballers.

Hope this helps!

Answer:

Step-by-step explanation:

- Hint: In this question we asked to find the Simple interest. Here, we will calculate simple interest for 4 years at 8% per annum by using the formula of simple interest (SI) =PRN100 .

Complete step-by-step solution -

To find the simple interest first we will know about simple interest.

Simple interest is based on principal amount for a fixed period of time. The amount which we deposit or take loan from the bank is known as principal amount. The period of time for which the money is lent is known as time on interest.

Now, we will calculate here simple interest,

SI =PRN100

Where P (principal amount) = Rs. 3000

R (Rate of interest) = 8%

N (number of period) = 4 years

So, finding simple interest by putting all the value, we get

=3000×8×4100

=30×8×4

=960 Rs.

The radius of each circle are:

1. 8 units

2. 15 units

3. 18 units

4. 19 units

5. 5 units

The correct five letter word is “HORSE”.

Given: 1. Area of Circle, A = 64π units²

          2. Diameter of the circle, d = 30 units

          3. Circumference of the circle, C = 36π units

          4. Diameter of the circle, d = 38 units

          5. Circumference of the circle, C = 31.4 units

Since the area of a circle is (πr²) units and the circumference of a circle is (2πr) units,

where r is the radius of the circle.

1. We are given that Area of Circle, A = 64π units²

πr² = 64π

r² = 64

r = √64

r = 8 units

Since, r = 8

Thus, the letter in the alphabet that will substitute this number is ‘H’.

2. We are given that Diameter of the circle, d = 30 units

2r = 30     (∵ d = 2r)

r = 30/2

r = 15 units

Since, r = 15

Thus, the letter in the alphabet that will substitute this number is ‘O’.

3. We are given that Circumference of the circle, C = 36π units

2πr = 36π

2r = 36

r = 36/2

r = 18 units

Since, r = 18

Thus, the letter in the alphabet that will substitute this number is ‘R’.

4. We are given that Diameter of the circle, d = 38 units

2r = 38     (∵ d = 2r)

r = 38/2

r = 19 units

Since, r = 19

Thus, the letter in the alphabet that will substitute this number is ‘S’.

5. We are given that Circumference of the circle, C = 31.4 units

2πr = 31.4

2 × 3.14 × r = 31.4   [let π = 3.14 (approx)]

2r = 10

r = 10/2

r = 5 units

Since, r = 5

Thus, the letter in the alphabet that will substitute this number is ‘E’.

As the required values of the radius of the circles are 8, 15, 18, 19, and 5 respectively.

Thus, the substitutes of these five numbers for five letters are H, O, R, S, and E respectively.

Therefore, the required five letter word is "HORSE".

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Complete Question

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