Elena is going to a farmer's market for fresh produce. She hastwo markets to choose from and hopes to buy both cherriesand asparagus. The table shows the probability that each typeof produce will be available at the markets.
Answers
INFORMATION:
We know that:
- Elena is going to a farmer's market for fresh produce.
- She has two markets to choose from and hopes to buy both cherries and asparagus.
The following table is given and shows the probability that each type of produce will be available at the market:
And we must select in which market she has the higher chance of buying both, assuming that the availability of cherries and the availability of asparagus are independent of each other
STEP BY STEP EXPLANATION:
To select the correct one, we need to use that the availability of cherries and the availability of asparagus are independent of each other, and for independent events we can calculate their combined probability as
\(P(A\cap B)=P(A)\times P(B)\)Now, using the formula, we can calculate the probabilities for North market and South market
Let P(A) represents the probability of cherries available at market and P(B) represents the probability of asparagus available at market.
- North Market:
\(P(A\cap B)=0.6\times0.85=0.51\)So, the probability of buying cherries as well as asparagus from the North market would be 0.51
- South Market:
\(P(A\cap B)=0.5\times0.84=0.42\)So, the probability of buying cherries as well as asparagus from the South market would be 0.42
Finally, from the two probabilities we can state that to maximize the chances of buying cherries as well as asparagus, Elena should choose the North market. There is 0.51 probability of both cherries and asparagus.
ANSWER:
D. North market. There is a 0.51 probability of both cherries and asparagus being available.
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=log (4)
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O A.
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Answer:
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Answer:
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Given:
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\(\begin{gathered} \text{Cost of a token=}\frac{4.40}{8} \\ \text{Cost of a token= \$0.55} \end{gathered}\)\(\begin{gathered} \text{Cost of 19 tokens=19}\times0.55 \\ \text{Cost of 19 tokens= \$10.45} \end{gathered}\)Which division expression is equivalent to 4 1/3 divided -5/6
Answers
Answer:
-78/15
Step-by-step explanation:
To divide fractions, we first need to convert the mixed number 4 1/3 to an improper fraction. To do this, we can multiply the denominator of the fraction (3) by the whole number (4) and add the numerator (1) to get the new numerator. The denominator remains the same:
4 1/3 = (4*3 + 1) / 3
= 13 / 3
We can then divide the two fractions by multiplying the numerator of the first fraction by the reciprocal of the second fraction:
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Answer:
y=9
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(a) The probability that both marbles are white is \((30/85) * (30/85) = (\frac{1}{17})^2.\)
(b) The probability that the first is red and the second is white is (10/85) * (30/85) = \((\frac{2}{17})^2\)=0.013
(c) The probability that neither is orange is (1 - 15/85) * (1 - 15/85) = (70/85) * (70/85)=0.67
(d) The probability that they are either red or white or both is (10/85) + (30/85) + (10/85 * 30/85) = (12/17) + (36/289)=0.83
(e) The probability that the second is not blue is 1 - (20/85) = 65/85=0.76
(f) The probability that the first is orange is 15/85=0.17
(g) The probability that at least one is blue is 1 - (65/85 * 64/84) = 51/85=0.6
(h) The probability that at most one is red is (10/85) + (74/85 * 73/84) = (10/85) + (54/289)=0.30
(i) The probability that the first is white but the second is not is (30/85) * (55/84)=0.23
(j) The probability that only one is red is (10/85 * 74/84) + (75/85 * 10/84) = (7/17) + (5/17)=0.70
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Answer:
8Step-by-step explanation:
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Answer:
x = 5q - 15
Step-by-step explanation:
\(\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15\)
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it should be 5×3