The statemengt is false. Electromgnetic waves do not require a medium to transfer energy. They can transfer energy through vacuum (empty space with nothing in it). If electrimagnetic waves needed a medium to move through from place to place, then we could never see the sun, and also it would get very cold here.
a student in track and field is running a hurdles race. the hurdles are 91.4 cm tall. the student is running with a horizontal velocity of 4.00 m/s and leaps with a vertical velocity of 9.00 m/s. if the student makes this leap 0.400 m before the hurdle, will they clear the hurdle? if they clear the hurdle, how much do they clear the hurdle by? if they do not clear the hurdle, what could they do to have a higher jump?
No, they will not be able to clear the hurdle from the given distance of their leap.
What are the projectile motion?
Projectile motion includes vertical and horizontal velocity components. It's important to understand that the two are independent of each other. But what is a projectile and what is a good example. Well, a projectile is an object that is thrown by applying a force that falls under gravity and is subject to the resistance of the medium in which it travels. It can be thrown into the air and fall under the influence of gravity.
First of all the time required to reach the hurdle is:
by using horizontal velocity we have time =
t = 0.100s
Now for the vertical distance covered by student:
S = ut + gt²
S = 9 × 0.100 + 9.8 × 0.100²
S = 0.851m or 85.1cm
Since the distance calculated is less than the height of hurdles which is 91.4 cm so the student may not be able to clear the hurdle.
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I have a 10kg crate on top of a ramp that has a 30m long surface and rises 5m in the air. If the μk is .05, what is the speed at the bottom?
The speed at the bottom is 10 m/sec.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
I have a 10kg crate on top of a ramp that has a 30m long surface and rises 5m in the air. If the μk is .05,
work = change in kinetic energy
mgh = 0.5 mv²
10*10*5 = 0.5 * 10 * v²
v = 10 m/sec
The speed at the bottom is 10 m/sec
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Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
Answer:
Drinking water
Direct as we are achieving water directly by ourselvesOur foods
Indirect as foods contain water we are getting water indirectly from themWashing clothes
Direct as direct contact of water is here(b) Earth rotates on its axis in 1 day. At what velocity is a person standing at the equator in the figure above (Person 1) moving due to our planet's rotation
Earth rotates on its axis in 1 day. The velocity of a person standing at the equator due to Earth's rotation 463 meters per second.
The velocity of a person standing at the equator due to Earth's rotation can be calculated by considering the circumference of the Earth at the equator and the time it takes for Earth to complete one rotation (which is approximately 24 hours or 86,400 seconds).
The circumference of a circle can be calculated using the formula: C = 2πr, where C is the circumference and r is the radius. For the Earth, the radius at the equator is approximately 6,378 kilometers or 6,378,000 meters.
So, the circumference of the Earth at the equator is:
C = 2π(6,378,000 meters) = 40,075,880 meters (approximately)
Since the Earth completes one rotation in 24 hours or 86,400 seconds, the velocity of a person standing at the equator can be calculated by dividing the distance traveled (circumference) by the time taken:
Velocity = Distance / Time
Velocity = 40,075,880 meters / 86,400 seconds
Calculating this gives us a velocity of approximately 463 meters per second. Therefore, a person standing at the equator is moving with a velocity of approximately 463 meters per second due to Earth's rotation.
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What symbol would best represent an electric fan speed controller in an electric circuit?.
The letter M surrounded in a circle, which stands for a motor, would be the finest symbol to symbolize an electric fan speed controller in an electrical circuit.
A little motor, which is a simplified description of how a fan operates, causes the blades to rotate. Therefore, the motor sign in the circuit will be a M inside a circle, which stands for the motor.Any device that transforms energy from one form to another into mechanical energy, especially an internal combustion engine or a set of coils and magnets that transform electric current into power.Electric motors can be powered by alternating current (AC) sources like a power grid, inverters, or electrical generators or by direct current (DC) sources like batteries or rectifiers. Considerations including the type of power source, construction, application, and type of motion output can be used to categorize electric motors. They can be AC or DC powered, brushed or brushless, single-phase, two-phase, or three-phase, axial or radial flux, air-cooled or liquid-cooled, and can use any type of cooling system.For industrial application, standardized motors offer practical mechanical power. The largest have an output more than 100 megawatts and are used for pumped storage, pipeline compression, and ship propulsion.
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Hello I need help with this science problem
A= N=
Answer:
charge of the atom = -1
charge of the nucleus = 4
A fast Humvee drove from Desert A to Desert B. for the first 12 hours and traveled at an average speed of 185 km/h. For the next 13 hours, it travelled at an average speed of 160 km/h. What was the average speed of the whole journey?
Answer:
The value is \(v_t = 172 \ km/h\)
Explanation:
From the question we are told that
The average speed for the first 12 hours is \(u = 185 km/h\)
The average speed for the next 13 hours is \(v = 160 \ km/h\)
Generally the total time taken is mathematically represented as
\(t_t = 12 + 13\)
=> \(t_t = 25 \ h\)
The distance covered in the first movement is
\(D = u * 12\)
\(D = 185 * 12\)
\(D = 2220 \ km\)
The distance covered in the first movement is
\(d= v * 13\)
\(d = 160 * 13\)
\(d = 2080 \ km\)
The total distance traveled is
\(D_t = D + d\)
\(D_t = 2220 +2080\)
\(D_t = 4300 \ km\)
The average of the whole journey is
\(v_t = \frac{D_t}{t_t}\)
\(v_t = \frac{4300}{25}\)
\(v_t = \frac{4300}{25}\)
\(v_t = 172 \ km/h\)
Problem 3. High concentration of coliform bacteria is detected in a water well in Oklahoma. Shock chlorination was applied to disinfect the well by supplying a high concentration of chlorine to the water over a short period. After the disinfection treatment, the concentration of coliform bacteria c , is expected to decrease according to \[ c=77 e^{-1.5 t}+20 e^{-0.08 t} \] Where t is time in hours, and c is the bacteria concentration in ppm. Determine the time required for the bacteria concentration to be reduced to 15ppm using the Newton's method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). Check your result with fsolve function in Python's scioy library.
The time required for the bacteria concentration to be reduced to 15ppm using the Newton's method is 8.12 hours.
Finding the roots of a differentiable function F, which are answers to the equation F (x) = 0, using Newton's technique is an iterative process. To solve this problem, we can use Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). The formula for Newton’s method is:
xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
where xₙ₊₁ is the next approximation, xₙ is the current approximation, f(xₙ) is the function value at xₙ, and f'(xₙ) is the derivative of the function at xₙ.
For this problem, we have:
f(t) = 77 \(e^{-1.5 t}\) +20 \(e^{-0.08 t}\) - 15
f’(t) = -115.5 \(e^{-1.5 t}\) - 1.6 \(e^{-0.08 t}\)
After using the Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01), the results are as follows:
t = 4.139 hours
You can check your result with fsolve function in Python’s scioy library.
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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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The magnetic field 0.100 m from a
wire is 4.20 x 10-5 T. What is the field
0.200 m from the wire (twice as far)?
[?] *10^[?]T
Answer:
Your answer is given below:
Explanation:
Why is circular motion at constant speed not a natural state of motion?
The reason behind circular motion at constant speed is not a natural state of motion is centripetal acceleration acting on it.
What is centripetal acceleration?
Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
A natural state of motion is that motion where object moves with constant velocity and no acceleration. As in circular motion of an object at constant speed, a constant centripetal acceleration remains, this is not a natural state of motion.
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Most meteors burn up in the
Answer:
the Mesosphere
Most meteors burn up in the mesosphere. Unlike the stratosphere, temperatures once again grow colder as you rise up through the mesosphere.
Explanation:
Have a nice day
Answer:
The Mesosphere
Explanation:
It is the coldest layer.
A block of mass m slides from rest down an inclined plane of length s and height h. If F is the magnitude of the force of kinetic friction acting on the block as it slides, then the kinetic energy of the block when it reaches the bottom of the incline will be equal to (A) mgh (B) mgs−Fh (C) mgh−Fs (D) mgs−Fs
The question is about a block of mass m sliding down an inclined plane and its kinetic energy at the bottom. The correct answer is (C) mgh−Fs.
The following forces are at work on the block as it descends the slope:
1. The gravitational force (mg), which exerts downward pressure vertically.
2. Force that acts perpendicular to the inclination is called the normal force (N).
3. the resistance to the block's motion is caused by the force of kinetic friction (F), which acts perpendicular to the inclination.
As the block slides down the inclined plane, it gains kinetic energy due to the conversion of gravitational potential energy (mgh) into kinetic energy. However, the force of kinetic friction (F) opposes the motion, and therefore, some of the potential energy is lost as work is done against the friction force over the length s of the incline (Fs). So, the net kinetic energy of the block at the bottom of the incline is the initial potential energy minus the energy lost to friction: mgh−Fs.
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jordan is a big fan of space, space travel, and rockets, so he's super excited to be attending the launch of spacex's new startship rocket. jordan's friend malik is also attending the launch, but they're at different locations. if jordan is 40% closer to the launch site than malik, how much louder (in decibels) will the rocket launch sound be than for malik? you may assume that the sound produced by the rocket as it launches is emitted uniformly in all directions.
Answer:4.43 decibels louder for Jordan compared to Malik
Explanation:
To determine how much louder the rocket launch sound will be for Jordan compared to Malik, we need to use the inverse square law. This law states that as you move away from a sound source, the intensity of the sound decreases by the square of the distance. In other words, if you double the distance from a sound source, the intensity decreases to one-fourth of its original level.
Let's assume that the sound produced by SpaceX's new Starship rocket is at a constant intensity and emitted uniformly in all directions. If Jordan is 40% closer to the launch site than Malik, then we can assume that Jordan is at a distance of 0.6x from the launch site, where x is the distance from Malik to the launch site.
Using the inverse square law, we can calculate how much louder the rocket launch sound will be for Jordan compared to Malik:
(intensity at Jordan's location) / (intensity at Malik's location) = (distance from Malik's location)^2 / (distance from Jordan's location)^2
(intensity at Jordan's location) / (intensity at Malik's location) = (x)^2 / (0.6x)^2
(intensity at Jordan's location) / (intensity at Malik's location) = 1 / 0.36
(intensity at Jordan's location) = 2.78 x (intensity at Malik's location)
To convert this ratio of intensities into decibels, we can use the formula:
L = 10 log10 (I/I0)
where L is the sound level in decibels, I is the intensity of the sound, and I0 is a reference intensity of 10^-12 W/m^2.
Assuming that the reference intensity I0 is constant for both locations, we can simplify this formula to:
L = 10 log10 (intensity)
Therefore, the sound level for Jordan compared to Malik can be calculated as:
L = 10 log10 (2.78 x intensity) - 10 log10 (intensity)
L = 10 log10 (2.78)
L = 4.43 dB
Therefore, the rocket launch sound will be approximately 4.43 decibels louder for Jordan compared to Malik.
three collinear forces,F1=45N west,F2=63N east and an unknown force F3 are applied to an object.The resultant force of the three forces is 12N west.
Show by means of a tail to head method of vector addition how the magnitude of F3 could be found?
Take east to be the positive direction. Then the resultant force from adding F₁ and F₂ is
F₁ + F₂ = (-45 N) + 63 N = 18 N
which is positive, so it's directed east.
To this we add a third force F₃ such that the resultant is 12 N pointing west, making it negative, so that
18 N + F₃ = -12 N
F₃ = -30 N
So F₃ has a magnitude of 30 N and points west.
What would be the mass of the same object on the moon, where gravity is one sixth of Earth gravity?
Magmas have a variety of chemical compositions because of all of the following EXCEPT
A. different magmas formed in different locations are isolated and don't mix.
B. the magmas' heat can melt rock from the walls of the magma chamber.
C. they come from a variety of source rocks.
D. the rocks that melt to make magma are composed of many minerals, not all of which melt under the same conditions
A. Different magmas generated in various places are isolated from one another. This assertion is untrue since magmas can interact with one another and mix.
Magma is composed of what?Under the surface of the Earth, molten and semi-molten rock mixtures are known as magma. This mixture typically consists of four components: a base heated liquid substance known as the melt; minerals that the melt crystallized; solid rocks that the melt mixed with from the surrounding constraints; and dissolved gases.What three varieties of magma are there?Moreover, it has trace levels of dissolved gases like sulfur, carbon dioxide, and water vapor. Magma is kept in a fluid state by the tremendous pressure and temperatures under the crust of the Earth. Each of the three fundamental forms of magma—basaltic, andesitic, and rhyolitic—has a unique mineral makeup.learn more about Magmas here
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What is friction? A. f net= ma B. the normal force C. the wearing down of surfaces D. forces opposing the motion of surfaces in contact with each other
Answer:
D. Forces opposing the motion of surfaces in contact with each other
Explanation:
Friction moves in the opposite direction of the object.
A ball is thrown straight up from the ground. Where will the ball have its lowest velocity
Explanation:
i think it will be on the ground
If D equals the maximum amount of new demand-deposit money that can be created by the banking system on the basis of any given amount of excess reserves; E equals the amount of excess reserves; and m is the monetary multiplier, then
Multiple Choice
m = E/D.
D = E × m.
D = E − 1/m.
D = m/E.
The correct equation is D = E × m, where D represents the maximum amount of new demand-deposit money, E represents the number of excess reserves, and m is the monetary multiplier.
Let's break it down step by step:
1. D represents the maximum amount of new demand-deposit money that can be created by the banking system based on a given amount of excess reserves.
2. E represents the number of excess reserves.
3. m is the monetary multiplier, which represents the multiple by which the money supply can expand through the creation of new demand-deposit money.
The equation D = E × m shows that the maximum amount of new demand-deposit money that can be created (D) is equal to the number of excess reserves (E) multiplied by the monetary multiplier (m).
To understand this better, let's consider an example:
Suppose a bank has $100 million in excess reserves (E) and the money multiplier (m) is 5. Using the equation D = E × m, we can calculate the maximum amount of new demand-deposit money that can be created (D):
D = $100 million × 5 = $500 million
So, in this example, the maximum amount of new demand-deposit money that can be created is $500 million. The correct equation relating D, E, and m is D = E × m.
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The correct statement is D = E × m, If D equals the maximum amount of new demand-deposit money that can be created by the banking system on the basis of any given amount of excess reserves.
The equation D = E × m represents the relationship between the maximum amount of new demand-deposit money (D), the amount of excess reserves (E), and the monetary multiplier (m).
The monetary multiplier is a measure of the potential expansion of the money supply through the lending and deposit creation process in the banking system. It is calculated by dividing the total money supply by the amount of excess reserves held by banks.
By multiplying the amount of excess reserves (E) by the monetary multiplier (m), we can determine the maximum amount of new demand-deposit money that can be created by the banking system (D).
Therefore, D = E × m is the correct expression that represents the relationship between D, E, and m in the context of the maximum expansion of the money supply.
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9. [-/1 Points] DETAILS OSCOLPHYS1 26.2.022. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A mother sees that her child's contact lens prescription is +2.50 D. What is the child's near point, assuming the contact lens is designed to enable the child to see objects 25.0 cm away clearly? cm Additional Materials Reading
The diopter for the contact lens is +2.50D, which can be converted to a focal length as follows:f = 1/2.50 = 0.40 meters Substitute the given values in the equation to find the distance of the near point.p = 100/0.40 = 250 cm Therefore, the child's near point is 250 cm away from the child's eyes when wearing a +2.50 D contact lens.
According to the thin lens equation, the lens equation can be used to calculate the distance from an object to its image using the focal length and object distance, as well as the image distance.A mother sees that her child's contact lens prescription is +2.50 D. What is the child's near point, assuming the contact lens is designed to enable the child to see objects 25.0 cm away clearly.The image distance, u', is equal to the near point distance when the object distance is equal to the near point distance. So, we can use the following equation to calculate the distance of the near point:p
= 100/f Where p is the distance to the near point, and f is the lens's power, which is calculated as follows:f
= 1/d Where d is the diopter. The following equation can be used to calculate the diopter of a lens:D
= 1/f.The diopter for the contact lens is +2.50D, which can be converted to a focal length as follows:f
= 1/2.50
= 0.40 meters Substitute the given values in the equation to find the distance of the near point.p
= 100/0.40
= 250 cm Therefore, the child's near point is 250 cm away from the child's eyes when wearing a +2.50 D contact lens.
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A body of mass 250g is release from the top of a building. If the body hits the ground with a velocity of 4m/s, calculate th height of the building [g=10m/s²]
The height of the building is 8 meters. to calculate the height, we can use the equation for free fall:
\(v^2 = u^2 + 2as,\)
where v is the final velocity (4 m/s), u is the initial velocity (0 m/s), a is the acceleration due to gravity (-10 m/s^2), and s is the distance or height.
Rearranging the equation, we get:
\(s = (v^2 - u^2) / (2a)\)
Substituting the given values, we have:
\(s = (4^2 - 0^2) / (2 * -10) = 16 / -20 = -0.8 meters.\)
Since the height cannot be negative, we take the absolute value:
|\(s| = 0.8 meters.\)
Therefore, the height of the building is approximately 0.8 meters or 8 meters.
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A bat hasa mads of 2kg at the velocity of 45 m/s what is the kinectic energy could he give to a ball
Answer:
the kinetic energy the bat can give to a ball is 2,025 J.
Explanation:
Given;
mass of the bat, m = 2kg
velocity of the bat, v = 45 m/s
The kinetic energy the bat can give to a ball is calculated as;
\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 2 \ \times \ 45^2\\\\K.E = 2,025 \ J\)
Therefore, the kinetic energy the bat can give to a ball is 2,025 J.
What happens to distance and velocity if the time to fall increases or decreases?
In free-fall motion the velocity is given by the following equation of motion:
\(v=v_0-gt\)Where:
\(\begin{gathered} v=\text{ velocity} \\ g=\text{ acceleration of gravity} \\ t=\text{ time} \end{gathered}\)Therefore, the velocity increases linearly with time. This happens if the object encounters no air resistance. In the case that there is air resistance the object will reach a terminal velocity.
In the case of distance, this is given by the following equation:
\(s=v_0t-\frac{1}{2}gt^2_{}\)This means that the distance increases with time following a parabolic function.
prepare for the module exam,
Question 1
1 pts
If a 6 ohm wire is connected to a 10 volt battery, what will the current be?
O 6 amperes
O ,67 amperes
O 1.67 amperes
60 amperes
Answer:
1.67 amperes
Explanation:
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
\( V = IR \) ......equation 1
Where;
V represents voltage measured in voltage.I represents current measured in amperes.R represents resistance measured in ohms.Making I the subject of formula, we have;
\( I = \frac {V}{R} \) .....equation 2
Given the following data;
Voltage = 10 VoltsResistance = 6 OhmsTo find the current flowing through the battery, we would use eqn 2;
\( I = \frac {10}{6} \)
Current, I = 1.67 amperes
a 0.500 kg copper cup is at 280 o k. if 2.5 x 104 j of energy is added to it, what is the final temperature in o k? the specific heat of copper is 387 j kg-1 oc-1 .
The final temperature of the copper cup is found to be 409.19° K.
The mass of the copper cup is 0.500 Kg and it is at a temperature of 280°K.
A total of 2.5 x 10⁴ J of energy is added to the system.
The final temperature of the system is let us say T.
Now, the change in energy will be given by,
∆Q = mC∆T
Where,
C is the specific capacity of copper.
Putting values,
2.5 x 10⁴ = 0.5 x 387 x(T - 280°)
T = 409.19°K.
So, the final temperature of the copper cup is 409.19°K.
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2. A 6 kg object is initially at rest. A 300 N force acts on the object, moving it forward 4 meters in
2 seconds.
a) How much work does the force do on the object?
b) How much power is exerted on the object?
c) What is the final velocity of the object?
Answer: a. 1200J b. 600W c. 20m/s
Explanation: W = Fxcos
F = 300, x=4, direction of force is = to direction of object so cos(0) = 1
a) 300*4 = 1200
b) P = W/t
1200/2 = 600W
c) vf^2 = vi^2 + 2ax
vi = 0, x = 4, a= 300/6
vf^2 = 2(50)(4)
vf^2 = 400
vf= 20m/s
How do you calculate displacement on a graph
Explanation:
On a position vs time graph (x vs t), displacement is the difference in positions (Δx = x₂ − x₁).
On a velocity vs time graph (v vs t), displacement is the area under the graph (Δx = ∫ v dt).
HELP PLEASE
Find the net force necessary for a 15 kg object to accelerate at 20 m/s/s.
Answer:
The answer is 300 NExplanation:
The force acting on an object given the mass and acceleration we use the formula
force = mass × accelerationWe have
force = 15 × 20
We have the final answer as
300 NHope this helps you
if the cannonball was thrown straight upwards at this velocity (the y-component of velocity found in part one), how long would it be in the air.
The distance traveled in the x-direction in the time found in part two is given by:50.5m
1. Find the time the cannonball is in the air when thrown straight upwards.
2. Find the x-component of the velocity.
3. Determine how far the cannonball will travel using the x-component of the velocity and the time found in part one.
When the cannonball is thrown straight upwards, it will eventually come to a stop and then fall back down. To find how long it's in the air, we can use the following equation:
time = (initial_velocity_y) / g
where g is the acceleration due to gravity (approximately 9.81 m/s²).
Using the y-component of velocity found in part one, plug it into the equation to find the time.
where t is the time, vy is the y-component of the velocity and g is the acceleration due to gravity, which is 9.81 m/s2.
Therefore, t = 32.2/9.81 = 3.27 s
The x-component of the velocity is the same as the given initial velocity, 15.5 m/s. Therefore, the distance traveled in the x-direction in the time found in part two is given by:
d = vx * t
where d is the distance and vx is the x-component of the velocity.
Therefore, d = 15.5 * 3.27 = 50.5 m
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