Heat used by electric heater :
Q = m • c • ∆T
Q = (75 kg)(4200 J/kg°C)(43°C - 15°C)
Q = 8.82 × 10⁶ J
Cost of electrical energy :
Cost = (8.82 × 10⁶ J)/(3.6 × 10⁶ J) • ($ 0.15)
Cost = $ 0.3675
In this exercise we have to use the knowledge of heat to calculate how much this energy used will cost, so we have:
The cust to fill a bathtub will be \($ 0.3675\)
so organizing the information given in the statement we have that:
1 kWh = 3.6x106 J.costs $0.15 per kWh75 kg of water 15°C to 43°CThe heat formula is given by:
\(Q = m * c * \Delta T\)
Substituting the values already given in the statement we have:
\(Q = (75)(4200 )(43- 15)\\Q = 8.82* 10^6 J\)
So to calculate the cost we have to;
\(Cost = (8.82 *10^6 )/(3.6 *10^6) ( 0.15)\\Cost = $ 0.3675\)
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suppose you measure the recession velocity (the speed at which any object is moving away from us) of galaxy a to be 1000 km/s and the recession velocity of galaxy b to be 6000 km/s. what can you conclude about the relative distances of these two galaxies?
We can conclude that Galaxy B is farther away from us than Galaxy A. Galaxy B is about 6 times farther away than Galaxy A.
The recession velocity of a galaxy is proportional to its distance from us, according to Hubble's Law. Specifically, the recession velocity v is given by:
v = H*d
where,
H = Hubble constant, which represents the rate of expansion of the universe
d = distance of the galaxy.
Assuming a value of H = 70 km/s/Mpc (which is a commonly used value), we can use the recession velocities of galaxies A and B to compare their distances from us.
If galaxy A has a recession velocity of 1000 km/s, its distance from us can be calculated as:
dA = vA / H = 1000 km/s / 70 km/s/Mpc ≈ 14.3 Mpc
Similarly, if galaxy B has a recession velocity of 6000 km/s, its distance from us can be calculated as:
dB = vB / H = 6000 km/s / 70 km/s/Mpc ≈ 85.7 Mpc
Therefore, we can conclude that Galaxy B is farther away from us than Galaxy A. In fact, galaxy B is about 6 times farther away than galaxy A.
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A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will it go? Use -32 ft/s? forthe acceleration caused by gravity. Ignore air resistance.
Given,
The initial height of the soccer ball, h₁=6 ft
The initial velocity of the ball, u=96 ft/s
The acceleration due to gravity, g=-32 ft/s
When the ball reaches the maximum height, its velocity will reduce to zero.
Thus the velocity of the ball when it is at its maximum height is v=0 ft/s
From the equation of motion,
\(v^2-u^2=2gh_2\)Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.
On substituting the known values,
\(\begin{gathered} 0-96^2=2\times-32\times h_2 \\ \Rightarrow h_2=\frac{-96^2}{2\times-32} \\ =144\text{ ft} \end{gathered}\)Thus the maximum height reached by the ball is,
\(\begin{gathered} H=h_1+h_2 \\ =6+144 \\ =150\text{ ft} \end{gathered}\)Thus the maximum height reached by the ball is 150 ft.
the quantity with the same units as force times time, ft, with dimensions mlt−1 is what?
The quantity with the same units as force times time (ft) and dimensions of MLT^(-1) is momentum.
Momentum is defined as the product of an object's mass and its velocity. Its units in the SI system are kilogram meters per second (kg m/s).
To see why momentum has the same units as force times time, we can use the definition of force, which is the rate of change of momentum.
F = dp/dt
where F is force, p is momentum, and t is time. Rearranging this equation, we get:
F * t = dp
where F * t is force times time (ft) and dp is the change in momentum. Therefore, force times time has the same units as momentum, which is MLT^(-1).
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A space alien named Zorg is working hard. In fact, as time goes by, Zorg works harder and
harder: Zorg's power output depends on time as P= b3 where b is a constant coefficient.
How much work will Zorg be able to perform between t = 0 and t = T?
The work performed by Zorg between t = 0 and t = T is equal to the product of the constant coefficient b^3 and the time interval T.
How did we get the value?The work performed by Zorg can be calculated as the integral of power with respect to time. If Zorg's power output is given by P = b^3, then the work performed by Zorg between time t = 0 and t = T can be calculated as:
W = ∫_0^T P(t) dt = ∫_0^T b^3 dt = b^3 * t |_0^T = b^3 * T
So, the work performed by Zorg between t = 0 and t = T is equal to the product of the constant coefficient b^3 and the time interval T.
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A train whistle is 580 Hz when
stationary. It is moving away from
you at 18.8 m/s. What frequency
do you hear?
(Speed of sound = 343 m/s)
(Unit = Hz)
HELP PLS!!
Answer:
Did you find the answer for this?
Explanation:
Answer:
550Hz
Explanation:
Convert 400 mm to m using the method of dimensional analysis
Answer:
To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4
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what must the separation be between a 5.2 kg particle and a 2.4 kg particle for their gravitational attraction to have a magnitude of 2.3x10^-12 n
The separation between a 5.2 kg particle and a 2.4 kg particle for their gravitational attraction to have a magnitude of 2.3x10^-12 N is approximately 0.018 meters.
The gravitational force between two point masses can be calculated using the equation F = G(m1m2)/r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass. Solving for r in this equation, we get r = sqrt(G(m1m2)/F). Plugging in the given values, we get r = sqrt((6.67x10^-11 m^3/kg s^2)(5.2 kg)(2.4 kg)/(2.3x10^-12 N)) = 0.018 m.
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A box weighing 25 N is lifted to a height of 1.1 m by sliding it up a ramp 3.2 m long. The person pushing the box exerts a force of 9.9 N.
What is the mechanical advantage of the ramp?
b. What is the machine's efficiency?
5. What is the power of a crane that lifts a 120 N load 14 m in 3.6 s?
Answer:
a. The mechanical advantage of the ramp is:
Mechanical advantage = length of ramp / height
Mechanical advantage = 3.2 m / 1.1 m
Mechanical advantage = 2.91
b. The efficiency of the machine is the ratio of output work to input work, expressed as a percentage. In this case, the output work is the work done on the box (force x distance), which is:
Output work = force x distance
Output work = 25 N x 1.1 m
Output work = 27.5 J
The input work is the work done by the person pushing the box, which is:
Input work = force x distance
Input work = 9.9 N x 3.2 m
Input work = 31.68 J
The efficiency of the machine is:
Efficiency = (output work / input work) x 100%
Efficiency = (27.5 J / 31.68 J) x 100%
Efficiency = 86.8%
Therefore, the efficiency of the machine is 86.8%.
c. The power of the crane is given by the formula:
Power = work / time
where work is the product of force and distance, and time is the duration over which the work is done.
In this case, the work done by the crane is:
Work = force x distance
Work = 120 N x 14 m
Work = 1680 J
The time taken to lift the load is 3.6 s. Therefore, the power of the crane is:
Power = work / time
Power = 1680 J / 3.6 s
Power = 466.7 W
Therefore, the power of the crane is 466.7 watts.
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Explanation:
Restate Newton’s third law of motion.
Answer:
The force exerted by one source object on another target object always creates another force at the target object that pushes back on the source object with the same ... or His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
16.) A person walks 4 meters east, then walks 3 meters north. Determine distance and
displacement.
Answer:
Long question good luck:)
Explanation:
Answer:7
Explanation:
because its the right answer
what minimum volume must the slab have for a 45.0 kgkg woman to be able to stand on it without getting her feet wet?
The minimum volume of the slab required so that the feet of the woman do not get wet is 0.045m³.
The mass of the woman is 45 Kg and the woman is standing on the slab which is in water.
Now, let us say the minimum volume of the slab is V.
Now, we know, in order to float, the weight of the woman should be equal to the buoyancy on the slab.
Now, we can write,
W = B
W = Vpg
Where,
V is the minimum volume of the slab,
p is the density of the water,
g is the acceleration due to gravity,
W is the weight of the woman.
Putting values,
45 x 10 = V x 1000 x 10
V = 0.045 m³
So, the minimum volume of the slab should be 0.045m³.
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what is meant by input and output work
Answer:
the x and y values
Explanation:
because on the table the x is the input and y is the output
A horizontal force of magnitude 47.3 N pushes a block of mass 3.95 kg across a floor where the coefficient of kinetic friction is 0.643. (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of 4.89 m across the floor?
The work done by the applied force is -117.42 J.
Force applied on the block = 47.3 N
Mass of the block = 3.95 kg
Coefficient of kinetic friction = 0.643
Displacement = 4.89 m
(a) It is represented by the formula,
W = Fd cos θ
Where,
W = work done by the force,
F = magnitude of the applied force,
d = distance covered by the object,
θ = angle between the applied force and the displacement of the object.
W = Fd cos θ
For a horizontal force, θ = 0
Therefore, W = Fd cos 0 = Fd
Since the block is moving with a constant velocity, the net force on the block must be zero. Thus, the force of friction acting on the block is equal in magnitude and opposite in direction to the applied force.
The force of friction on the block,
f = μkN
where,
μk is the coefficient of kinetic friction,
N is the normal force exerted on the block by the floor
Since the block is on a horizontal floor, the normal force is equal in magnitude and opposite in direction to the weight of the block.
Therefore,
N = mg
where,
g is the acceleration due to gravity
Substituting the value of N in the formula of force of friction:
f = μkN= μkmg
The force of friction acting on the block is 0.643 × 3.95 × 9.8 = 24.005 N
Since the net force on the block is zero, the applied force is equal in magnitude to the force of friction acting on the block and is opposite in direction.
Therefore,
F = - 24.005 N
The work done by the external force on the block-floor system is given by,
W = Fd
W = (-24.005 N) × 4.89 m = -117.42 J
Therefore, the work done by the applied force is -117.42 J.
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Pushing or pulling an object that is not already moving can make that object start to move?
TRUE
OR
FALSE ?
According to the research, the correct option is true. The statement "Pushing or pulling an object that is not already moving can make that object start to move" is true.
What is motion?It is about the change of position starting from a reference system from which it is observed that an object experiences.
In this sense, it is related to the displacement of a body and is produced by an imbalance between the forces that act on it, that is, the application of a force modifies the state of rest or the direction of movement.
Therefore, we can conclude that motion is the state of bodies when they change position caused by an effect acting on the bodies called force.
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What is the number of oxygen atom(s) on which the negative charge will resonate following relevant resonance structures?
Two oxygen atoms would share the negative charge.
What are resonance structures?There are some compounds in which a single structure is insufficient to explain the properties of the compound. In that case, we have to involve a number of other structures which contributes to the overall structure of the molecule to different extents.
The arrows are used to show the transformation of the structures of the compounds. Looking at the structures as it has been shown here, we know that the oxygen atoms that would be involved in the resonance are the oxygen atoms that are in the conjugated system.
There are two oxygen atoms in the conjugated system hence they will share the negative charge.
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The Enterprise goes into orbit around a mysterious planet. The ship moves at 4200 m/s in a circle of radius 4.91 x 10^7 m. What is the mass of the
planet?
Answer:
M = 1.3*10^25 Kg
Explanation:
Answer:
Explanation:
im not saying this bc of the person on top but its 1.3 and then 10^25 i done physics on acellus and i passed with an 90% and i have all of my notes and so the person on top of me was right :)
Two magnets are placed near each other on a space station orbiting Earth.
Their north poles are facing each other. Which statement explains what will
happen to the magnets?
O A. They will be repelled because they are in each other's magnetic
field.
B. They will not move because they have only half of a magnetic
field.
C. They will not move because they have very small gravitational
fields.
D. They will be attracted because their electric fields will add
together
Answer: A. They will be repelled because they are in each other's magnetic
field.
Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.
The statement that described the happening to the magnets should be that they will be attracted because they are in each other's magnetic.
What is a magnet?Magnet refers to the piece of iron or other material that comprise of the atoms also it inbuilt the magnetism properties like attraction of other type of iron objects. In the case when the two magnets shoud be placed near to each other also their north poles should be faced each other so it should be attracted since it is considered as the each other magnetic.
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Which is carried by waves?
x disturbance
• energy
• matter
• space
Hinata throws a 0.3-kg volleyball at the wall. With a velocity of 3.2 m/s, the volleyball hits the wall perpendicularly, then bounces back straight to Hinata at a velocity of 2.1 m/s. What is the change in momentum of the volleyball? (A) 1.6 kg-m/s B) 1.0 kg-m/s 0.3 kg-m/s D) 2.5 kg-m/s
The change in momentum of the volleyball is 1.6 kg-m/s. The change in momentum of an object can be calculated by subtracting the initial momentum from the final momentum. In this case, the initial momentum is the product of the mass and initial velocity of the volleyball, and the final momentum is the product of the mass and final velocity of the volleyball.
Given:
Mass of the volleyball (m) = 0.3 kg
Initial velocity of the volleyball (\(v_1\)) = 3.2 m/s
Final velocity of the volleyball (\(v_2\)) = -2.1 m/s (since it bounces back in the opposite direction)
Initial momentum (\(p_1\)) = m * \(v_1\) = 0.3 kg * 3.2 m/s = 0.96 kg-m/s
Final momentum (\(p_1\)) = m * \(v_2\) = 0.3 kg * (-2.1 m/s) = -0.63 kg-m/s
Change in momentum (Δp) = \(p_2\) - \(p_1\) = (-0.63 kg-m/s) - (0.96 kg-m/s) = -1.59 kg-m/s
The change in momentum is negative because the volleyball changes direction. However, we are interested in the magnitude of the change, so we take the absolute value:
|Δp| = |-1.59 kg-m/s| = 1.59 kg-m/s ≈ 1.6 kg-m/s
Therefore, the change in momentum of the volleyball is approximately 1.6 kg-m/s.
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A motorist is speeding along at 33m/s when he sees a squirrel on the road 200 meters in
front of him. He tries to stop, but it takes 12 seconds for his car to stop
(a) What is the acceleration of the car? (assume acceleration was constant)
(b) Does the squirrel survive?
(c) How fast was the car moving at 100 meters?
a) the acceleration of the car = -2.75 m/s
b) d = 198 meters. Therefore, the squirrel would survive.
c) the car moving at 100 meters with a speed of 23.22m/s
What is acceleration ?
acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Use the kinematic equation to solve for the acceleration:
v = u +at
v = final velocity
u = initial velocity
a = acceleration
t = time
In this instance, the final velocity is 0 because he comes to a stop. We can solve for the acceleration by plugging in the given values:
0 = 33 + (12)a
0 = 33 + 12a
-33 = 12a
-33 / 12 = a --> a = -2.75 m/s²
b) Find the amount of distance necessary to stop. Use the formula:
v^2 = u^2 + 2ad
d = distance
Plug in the values:
0² = 33² + 2(-2.75 · d)
0 = 1089 - 5.5d
-1089 = -5.5d
d = 198 meters. Therefore, the squirrel would survive.
c)
Find the velocity at 100 meters by using the same formula as before:
v^2 = u^2 + 2ad
However, in this instance, we are solving for the final velocity. Plug in the given points to solve:
vf² = 33² + 2(-2.75 · 100)
vf² = 1089 + (-550)
vf² = 539
vf = √539
vf ≈ 23.22 m/s.
the car moving at 100 meters with a speed of 23.22m/s
a) the acceleration of the car = -2.75 m/s
b) d = 198 meters. Therefore, the squirrel would survive.
c) the car moving at 100 meters with a speed of 23.22m/s
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Where do you find energy
Answer: nuclear energy, fossil energy -- like oil, coal and natural gas -- and renewable sources like wind, solar, geothermal and hydro power
Explanation:
Energy can be in many forms like the ones I stated but the sun is probably the biggest source also and play's a big part.
A star of apparent magnitude 5 appears _____ than a star of apparent magnitude 3.
A star of apparent magnitude 5 appears dimmer than a star of apparent magnitude 3.
Apparent magnitude is a measure of the brightness of celestial objects as observed from Earth. The magnitude scale is logarithmic, meaning that each whole number increase or decrease represents a difference in brightness by a factor of approximately 2.512. Therefore, a star with a higher magnitude appears dimmer than a star with a lower magnitude.
In this case, a star with an apparent magnitude of 3 is brighter than a star with an apparent magnitude of 5. The difference in magnitude of 2 corresponds to a brightness ratio of approximately 6.31. This means that the star of magnitude 3 is about 6.31 times brighter than the star of magnitude 5. The human eye perceives this difference as a noticeable decrease in brightness. The magnitude scale is reversed, so smaller numbers indicate brighter objects, with negative magnitudes representing the brightest objects visible in the sky.
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What beat frequencies are possible with tuning forks of frequencies 255, 258, and 260 hz ?
Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.
The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.
A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.
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A car accelerates from 15 m/s to 25 m/s for 6 seconds. What is the car's displacement? (use: d=>(); + v) )
Answer:
hope this helps : )
Explanation:
brainliest plz
A wave with a wavelength of 2m has a frequency of 10Hz. What is its speed?
Answer:
Below
Explanation:
To find the wave speed of a wave you can use this formula :
wavespeed (v) = (frequency) x (wavelength λ)
Plug in our values :
v = (10Hz) x (2m)
v = 20 m/s
Hope this helps!
Now, seriously !
There's a stream of objects flowing past you.
Ten of them pass you every second.
Each one is 2m long.
Don't you think you can figure out how fast they're flowing ?
In a compound microscope, the focal lengths of the objective and eyepiece are +0.50 cm and +2.0 cm respectively. The instrument is focused on an object 0.52 cm from the objective lens. Compute the magnify- ing power of the microscope if the virtual image is viewed by the eye at a distance of 25 cm. Ans. 3.4 x 10²
please I need the solution asap
Magnification of the compound microscope with given values is 3.4 x 10², which means it can magnify 340 times.
The enhancing power of a compound amplifying focal point is given by the recipe:
Enhancement = (1 + (f0/fe)) x (do/de)
Where f0 is the focal length of the objective point of convergence, fe is the focal length of the eyepiece, do is the distance between the article and the objective point of convergence, and de is the distance between the eyepiece and the virtual picture.
Subbing the given characteristics into the situation, we get:
Enhancement = (1 + (0.50 cm/2.0 cm)) x (0.52 cm/(25 cm - 0.50 cm))
Enhancement = 3.4 x 10²
The given condition for the strengthening force of a compound magnifying lens is utilized with the given qualities to compute the amplification of the magnifying instrument. The subsequent worth of 3.4 x 10² implies that the magnifying lens can amplify an item multiple times its unique size when seen a ways off of 25 cm.
Consequently, the intensifying power of the amplifying instrument is 3.4 x 10², and that suggests that the amplifying focal point can enhance a thing on numerous occasions its one of a kind size when seen a distance away of 25 cm.
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If you throw a 0.3kg ball straight up with an initial speed of 39m/s, how fast will it be moving when it’s 21m above the release point?
The question relies on conservation of energy
2 Energy equations:
Kinetic Energy = 1/2mv^2
Gravitational potential energy = mgh
Initial energy = final energy
1/2m(v0)^2 = mgh + 1/2m(vf)^2
Divide mass out to save time
1/2(v0)^2 = gh + 1/2(vf)^2
PLug in what we know:
v0 = 39 m/s
h = 21 meters
1/2(39)^2 = 9.8(21) + 1/2(vf)^2
1/2(39)^2 - 9.8(21) = 1/2(vf)^2
554.7 = 1/2(vf)^2
1109.4 = (vf)^2
vf = 33.3076 m/s
What will happen if the two plungers are pressed together firmly? Explain your answer.
Answer:
This air being forced out causing the air pressure inside to be much lower than that on the outside. As higher air pressure always pushes, it keeps the two plungers together.
Hope that helps. x
Chuyển động thẳng đều là gì?
Lời giải:
Answer:
very easy question like its exam
Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.
How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
From edge
Answer:
like 23 or something
Explanation: