Answer:
Explanation:
In 1785, Coulomb investigated quantitatively, the force exerted between point charges.
The Coulomb's Law states that: "The force of attraction or repulsion between two, point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them. "
If q₁ and q₂ are two, point charges and r is the distance between them, then the electric force of attraction or repulsion F between them, according to Coulomb’s law will be:
F ∝ q₁q₂ ________________________ eqn (1)
F ∝ 1/r² ________________________ eqn (2)
Combining eqn (1) and eqn (2), we get:
F ∝ (q₁ q₂)/r²
F = (kq₁q₂)/r²
where,
k = constant of proportionality = 9 x 10⁹ N.m² / C²
The water in a tank is pressurized by air,and the pressure is measured by a multifluid manometer as shown in the Fig. The tank is located on a mountain at an altitude of 1400 m where the atmospheric pressure is 85.6 kPa. Determine the air pressure in the tank if ℎ1 = 0.1 m, ℎ2 =0.2 m, and ℎ3 = 0.35 m. Take the densities of water, oil, and mercury to be1000 kg/m3, 850 kg/m3, and 13,600 kg/m3
, respectively?
Air is used to pressurize water in a tank, and the pressure is then measured. by a multifluid manometer so Consequently, the air pressure in the tank is 129.45KPa.
In the physical sciences, pressure is defined as either the stress at a place within a confined fluid or the perpendicular force per unit area. The weight of the atm is atmospheric pressure, which is approximately 15 pounds per square inch at sea level. Each square meter of the Earth's surface is under pressure from the atmosphere.
atmospheric pressure (\(P_{atm\))=85.6kPa
\(P_{atm\)=85600Pa
density of water=\(\rho =\)1000 kg/\(m^3\)
density of oil(\(\rho_0\))=850kg/\(m^3\)
density of mercury(\(\rho_{m\))=13600 kg/\(m^3\)
height of water column(\(h_1\))= 0.1m
height of oil column from water level(\(h_2\))=0.2m
height of mercury column (\(h_3\))=0.35m
pressure at point B
\(P_B=P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \: \rightarrow(1)\)
\(P_B=P_{atm} +\:\rho_mgh_3\: \rightarrow(2)\)
\(P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \:=P_{atm} +\:\rho_mgh_3\:\)
\(P_{air} =\:-\rho_0gh_1\: -\rho_wgh_2 \:+P_{atm} +\:\rho_mgh_3\:\rightarrow(3)\)
\(\rho _mgh_3\)=13600x9.8x0.35=46648 Pa
\(\rho _0gh_1\) =850x9.8x0.1=833 Pa
\(\rho _wgh_2\) =1000x9.8x0.2=1960 Pa
By putting the value in eq.3
\(P_{air\)=85600+46648−833−1960 = 129455Pa
therefore pressure of air in the tank is 129.45KPa
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what is the speed of electron having the same kinetic energy with photon speed 0.006c?
Answer:
if gossipy egg overriding successors spatial
The pressure of sea water increases by 1.0atm for each 10m increase in the depth, by what percentage is the density of water increased in the deepest ocean of water of 12km. Compressibility is 5.0×10^-5 atm
The percentage by which the water density increased is 4.1\(\mathbf{\overline 6}\) %
The known values are;
The increase in pressure per 10 meter increase in depth = 1.0 atm
The depth of the deepest ocean = 12 km = 12,000 m
The compressibility of the ocean = 5.0 × 10⁻⁵ 1/atm
The unknown
The percentage the density of water increased in the deepest ocean
Strategy;
Find the pressure at the deepest point of the deepest ocean and apply the compressibility
We have;
\(\mathbf{Compressibility = \dfrac{1}{V} \times \dfrac{\partial V}{\partial p}}\)
The change in pressure, \(\partial p\) = (12,000 m/(10 m)) × 1.0 atm = 1,200 atm
Therefore, we have for one cubic meter of water
\(\mathbf{5.0 \times 10^{-5} \ atm^{-1} = \dfrac{1}{1 \, m^3} \times \dfrac{\partial V}{1,200 \, atm}}\)
Therefore;
\(\mathbf{\partial}\)V = 5.0 × 10⁻⁵ atm⁻¹ × 1 m³ × 1,200 atm = 0.06 m³
The new volume = V - \(\mathbf{\partial}\)V
∴ The new volume = 1 m³ - 0.06 m³ = 0.94 m³
The initial density = mass/(1 m³)
The new density = mass/(0.96 m³)
The percentage increase in density, \(\partial\)ρ%, is given as follows;
\(\mathbf{\partial p \% = \dfrac{ \dfrac{Mass}{0.96 \ m^3} - \dfrac{Mass}{1 \ m^3} }{ \dfrac{Mass}{1 \ m^3}} \times 100 = \dfrac{25}{6} \% = 4.1 \overline 6 \%}\)
∴ \(\mathbf{\partial}\)ρ% = 4.1\(\mathbf {\overline 6}\) %
The percentage by which the water density increased, \(\partial\)ρ% = 4.1\(\mathbf{\overline 6}\) %
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Which of the following is NOT a characteristic of science?
Group of answer choices
Predictions must be testable through observations or experiments.
The results of repeated observations or experiment are more or less the same.
Science is subject to revision and correction based on new observations
It appeals to authority to establish its validity.
Answer:
C
Explanation:
it is C because science is an acquiring and defining of knowledge.
A 0.125 kg mass is placed on a vertically oriented spring that is stretched 0.32 meters from its equilibrium position. If the spring constant is 250 N/m, how fast will the mass be moving when it reaches the equilibrium position? Hint: you cannot ignore the change in gravitational potential energy in this problem. Please give your answer in units of m/s.
The mass will be moving at 14.3 m/s when it reaches the equilibrium position.
To determine the speed of the mass when it reaches the equilibrium position, we need to consider the conservation of mechanical energy, which includes both the spring potential energy and the gravitational potential energy.
The total mechanical energy (E) of the system is the sum of the potential energy and the kinetic energy:
E = PE (potential energy) + KE (kinetic energy)
At the equilibrium position, all the potential energy is converted into kinetic energy, so the total mechanical energy is entirely in the form of kinetic energy.
The potential energy stored in the spring (PE_spring) is given by Hooke's Law:
PE_spring = (1/2) * k * \(x^{2}\)
Where k is the spring constant (250 N/m) and x is the displacement from the equilibrium position (0.32 m).
PE_spring = (1/2) * 250 N/m *\((0.32 m)^2\)
PE_spring = 12.8 J
The change in gravitational potential energy (ΔPE_gravity) is given by:
ΔPE_gravity = m * g * h
Where m is the mass (0.125 kg), g is the acceleration due to gravity (9.8 m/\(s^2\)), and h is the change in height (which is zero in this case since the height doesn't change).
ΔPE_gravity = 0 J
Therefore, the total mechanical energy (E) is equal to the potential energy stored in the spring:
E = PE_spring
E = 12.8 J
Since the total mechanical energy is entirely in the form of kinetic energy at the equilibrium position, we can calculate the speed (v) using the equation:
E = (1/2) * m * \(v^2\)
Rearranging the equation, we get:
\(v^2\) = (2 * E) / m
\(v^2\) = (2 * 12.8 J) / 0.125 kg
\(v^2\) = 204.8 \(m^2\)/\(s^2\)
Taking the square root of both sides:
v = √ 204.8 \(m^2\)/\(s^2\)
v ≈ 14.3 m/s
Therefore, the mass will be moving at approximately 14.3 m/s when it reaches the equilibrium position.
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PLEASE HELP ITS DUE TODAY
A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.
-Find the hang time for the projectile.
-Find the initial speed of a projectile.
-What are the x and y components of the projectile’s velocity the moment before it strikes the ground?
-At what speed will the projectile strike the ground?
Answer:
30.9 m
Explanation:
x = 129.9 m y = 30.9 m First of all, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m
5. What are 3 ways you can alter pH for the benefit of you and
your family?
A 7.9 kg block initially at rest is pulled to the
right along a horizontal, frictionless surface
by a constant, horizontal force of 12.4 N.
Find the speed of the block after it has
moved 3.7 m.
Answer in units of m/s.
Answer:
\(v=3.4081\frac{m}{s}\)
Explanation:
\(F=ma\\F=12.4N\\m=7.9kg\\a=\frac{12.4N}{7.9kg}\\a=1.5696\frac{m}{s^2}\)
\(v^2=v_0^2+2a\Delta x\\v_0=0\frac{m}{s}\\a=1.5696\frac{m}{s^2}\\\Delta x=3.7m\\v^2=(0\frac{m}{s})^2+2(1.5696\frac{m}{s^2})(3.7m)\\v^2=11.6152\frac{m^2}{s^2}\\v=\sqrt(11.6152\frac{m^2}{s^2})\\v=3.4081\frac{m}{s}\)
the answer for this pls
The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.
How to explain the relationshipThere are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:
For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.
In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.
In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.
Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.
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please help very easy 5th grade work giving brainliest
Answer:
the answer is option B because opposit sides of the magnets attract each other
1. At which point is potential energy the greatest?
1. At which point is kinetic energy the greatest?
Answer:
A ,C
Explanation:
Shows
Find the ratio of the diameter of aluminum to silver wire, if they have the same resistance per unit length (as they might in household wiring).dAl/dAg =
Given:
The resistance per unit length of aluminum is equal to the resistance per unit length of silver i.e.,
\(\frac{R_{Al}}{l_{Al}}=\frac{R_{Ag}}{l_{Ag}}\)Required: The ratio
\(\frac{d_{Al}}{d_{Ag}}\)Explanation:
The resistance of aluminum is given by the formula
\(\begin{gathered} R_{Al}=\rho_{Al}\frac{l_{Al}}{A_{Al}} \\ \frac{R_{Al}}{l_{Al}}=\frac{\rho_{Al}}{\pi(r_{Al})^2} \\ \frac{R_{Al}}{l_{Al}}=\frac{\rho_{Al}}{\pi(\frac{d_{Al}}{2})^2} \end{gathered}\)The resistance of silver is given by the formula
\(\begin{gathered} R_{Ag}=\rho_{Ag}\frac{l_{Ag}}{A_{Ag}} \\ \frac{R_{Ag}}{l_{Ag}}=\frac{\rho_{Ag}}{\pi(r_{Ag})^2} \\ \frac{R_{Ag}}{l_{Ag}}=\frac{\rho_{Ag}}{\pi((d_{Ag})\/2)^2} \end{gathered}\)Since,
\(\frac{R_{Al}}{l_{Al}}=\frac{R_{Ag}}{l_{Ag}}\)On substituting the values, the ratio can be calculated as
\(\begin{gathered} \frac{\rho_{Al}}{\pi(\frac{d_{Al}}{2})^{2}}=\frac{\rho_{Ag}}{\pi(\frac{(d_{Ag})}{2})^{2}} \\ \frac{\rho_{Al}}{(d_{Al})^2}=\frac{\rho_{Ag}}{(d_{Ag})^2} \\ \frac{(d_{Al})^2}{(d_{Ag})^2}=\frac{\rho_{Al}}{\rho_{Ag}} \\ \frac{d_{Al}}{d_{Ag}}=\sqrt{\frac{\rho_{Al}}{\rho_{Ag}}} \end{gathered}\)Thus, the ratio is
\(\frac{d_{Al}}{d_{Ag}}=\sqrt{\frac{\rho_{Al}}{\rho_{Ag}}}\)Final Answer: The ratio of the diameter of aluminum to silver is the square root of the ratio of resistivity of aluminum to silver.
How long will it take a person walking at 3.2 m/s to travel 16 m? *
Answer:
5.0 s
Explanation:
The equation for time is:
\(t = \frac{d}{s} \)
We plug in the given values into the equation
\(t=\frac{16\ m}{3.2\ m/s^}\)
\(t=5.0 \ s\)
if we sketch a pressure vs. volume graph of a gas at a given temperature, what changes on the graph are seen as the volume decreases?
Answer:
The pressure will show inverse relation - it will start to increase along with the decrease in volume.
Explanation:
The volume of a gas is inversely proportional to the pressure exerted upon it; hence for a given temperature, if you observe a decrease in the volume on the graph, you can be certain that the pressure must have increased.
To elucidate it even more just think of how the molecules of gas will behave in a closed container at a given temperature. The more you compress or put pressure upon the gas the more the volume of it will decrease.
The electricity received at an electric substation has a potential difference of 2.80 x 105 V. If the required output is 440 V, what should be the ratio of the turns of the step-down transformer?
A
Explanation: sorry sir but its required step up transformer for high voltage not step
Pure sodium metal explodes when it makes contact with water, and chlorine, in its natural state, is a deadly, poisonous gas. When these two chemicals combine, they form a harmless, white powder known as sodium chloride or table salt. Which of the following statements does this information support?
A.The properties of substances change during chemical reactions but then later go back to their original condition.
B.Heat must be added in order to change the chemical properties of substances.
C.When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
D.When substances are chemically combined, the properties of the new substances that are formed are the same as the properties of the original substances.
Answer: When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
Explanation:
Which of objects above is the furthest away from earth?
Group of answer choices
The Andromeda Galaxy.
The cluster of galaxies.
Saturn.
the Voyager spacecraft.
The object that is furthest away from earth is the cluster of galaxies. Option B
What is the solar system?The solar system is arrangement of arrangement of the sun and the planets. The sun lies at the center of the solar system. This is known as the heliocentric model. The planets surround the sun in orbits.
Now as we move across the earth going far deeper into the outer space, we would find out that the object that is furthest away from earth is the cluster of galaxies. Option B
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If an 8m long string is in its twelfth harmonic, what is the wavelength of standing waves on the string?
If an 8m long string is in its twelfth harmonic, the wavelength of standing waves on the string will be 1.33cm approximately.
What is a Twelfth Harmonic?The harmonics on the 12th fret are one octave above the open strings, while the harmonics on the 5th fret are two octaves above the open strings.
To arrive at the above answer, we deploy the "harmonic" wavelength principle which states that the "nth" wavelength is equal to the fundamental wavelength divided by n. That is:
λn = λ1/n
Where:
λn = wavelength of standing wavesλ1 = 2L (Wavelength of the first harmonic)n = harmonic being determined which in this case is 12Hence,
λn = (2 x 8)/12
λn = 1.33333333333
λn \(\approx\) 1.33cm.
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help me get the answer in Physical Science.
Answer:
lithium
Explanation:
I took physical science 2 years ago and passed with an A
what is complex machine please explain
Answer:
Two or more simple machines work together to form a complex machine. Compound machines can do more difficult jobs than simple machines alone. Examples of complex machines are bicycle, wheel barrow, crane, car jack, lawn mover
Explanation:
A complex machine is device consisting of two more simple machine working together. for example a wedge is driven forced between objects to split lift or make them stronger.
8. According to the passage, in order for LeBron James to score a slam-dunk, what must he
exert?
Answer:
Kenetic Energy?
Explanation:
I need more context of what you are studying here...
A car drove 200 km east on an interstate highway, then was finally able to make an
exit and drove for another 70 km to the north before reaching their destination.
What was the direction of car's resultant displacement?
Answer:
70.66°Explanation:
To find the direction of the displacement vector, we have to solve for the ratio of both displacements, and furthermore the inverse tangent of the ratio.
Given data
200km east represents the x axis
70 km north represents y axis
the direction of the resultant is given as
∅= tan-1x/y
∅=tan-1 200/70
∅= tan-120/7
∅= tan-12.85
∅= 70.66°
hence the direction of the resultant is 70.66°
The five general principles from the APA are meant to __________. A. be enforceable rules B. be posted in every office C. guide and inspire good conduct D. stand up in court Please select the best answer from the choices provided
The five general principles from the APA are meant to: C. Guide and inspire good conduct.
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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015
10.0 points
A car traveling in a straight line has a velocity
of 5.25 m/s at some instant. After 4.27 s, its
velocity is 9.38 m/s.
What is its average acceleration in this time
interval?
Answer in units of m/s.
Divide the change in speed by the given time:
a = (9.38 m/s - 5.25 m/s) / (4.27 s) ≈ 0.967 m/s²
Which of the following is NOT an observation? a.The apple tastes sour b.The apple weighs about 38 g c.The apple is light green in color d.Apples are the best fruit
Answer:
d apple's are the best fruit
what effect does density have on transverse waves
Question 15 of 25
What is the period of a wave that has a frequency of 30 Hz?
Answer:
0.033 seconds
Explanation:
Period = 1/30 = 0.033 seconds
Answer:
The answer is 0.03 s
Explanation:
A.P.E.X.
a man of mass 60kg jumps onto a boat B which has mass 80kg. If he has a horizontal component of velocity 3m/s relative to the boat, just before he enters the boat, and the boat is travelling at speed 2m/s away from the pier when he makes the jump, find the resulting velocity of the man and boat
The velocity of the man and boat after the jump is 2.57 m/s.
What is velocity?The rate at which the position of an item changes with respect to time is expressed as a vector quantity called velocity. It is a way to gauge how fast and which way an object is moving. In other terms, velocity is the rate at which an object is moving in a particular direction.
How do you determine it?The concept of conservation of momentum, which asserts that the overall momentum of a closed system stays constant in the absence of external forces, must be used to solve this issue.
The system's overall momentum is initially: before the man gets onto the boat.
p1 = m1v1 + m2v2
where m1 is the man's mass, v1 is his starting speed (3 m/s horizontally), m2 is the boat's mass, and v2 is the boat's speed (2 m/s away from the pier).
p1 = (60 kg)(3 m/s) + (80 kg)(2 m/s)= 360 kg m/s
The two objects merge into a single system when the man jumps onto the boat, and their combined motion is:
p2 = (m1 + m2) v
where v represents the speed of the boat and guy after the jump.
We can equate the two expressions and find v since p1 = p2 follows the law of conservation of momentum:
P1 equals P2 (60 kg)(3 m/s) + (80 kg)(2 m/s) = (60 kg + 80 kg) v
360 kg m/s = 140 kg v
v = 2.57 m/s
As a result, the man's and boat's final speed after the jump is 2.57 m/s.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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