EDGE PRE-CALC HELP ASAP!!

Answer:

2/-3 is your correct answer

Your mom had the better/lower unit price.

A unit price is the cost of a single unit of a product or item, usually expressed per unit of weight, volume, or length. It represents the cost per unit of measurement and allows for comparison of the cost of different products on an equal basis.

For example, the unit price of a bag of apples could be given as the cost per pound, so that a consumer can compare the cost of a 5-pound bag of apples at different stores.

The unit price for your mom's books is $19.85/8 books = $2.48 per book.

The unit price for your dad's books is $15.00/6 books = $2.50 per book.

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(a) The normalization constant A for the wave function Ψ(x,0) is 1/√2 to ensure that Ψ(x,0) is properly normalized.

(a) To normalize the wave function Ψ(x,0), we need to find the normalization constant A. The wave function Ψ(x,0) is given as an even mixture of the first two stationary states, ψ1(x) and ψ2(x). We know that the stationary states are orthonormal, which means that their inner product is zero unless they are the same state. Therefore, we can exploit this orthonormality to find the normalization constant.

The inner product of ψ1(x) and ψ2(x) is zero, so we have:

∫[ψ1(x) + ψ2(x)]*[ψ1(x) + ψ2(x)] dx = 1

Expanding the square and integrating, we get:

\(2A^2∫ψ1(x)*ψ2(x) dx = 1\)

Since ψ1(x) and ψ2(x) are orthonormal, the integral on the left-hand side becomes zero. Therefore, we have:

\(2A^2 * 0 = 1\)

Solving for A, we find:

A = 1/√2

Hence, the normalization constant A for the wave function Ψ(x,0) is 1/√2.

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Answer:

A. Add -2 to both sides

Step-by-step explanation:

The reason you need to add -2 to both sides is because if you add -2 to -2 it cancels out and you are left with x=18. But you need to add -2 to 18 too because them the equation won't be equal anymore.

The length and width of the lot are 46m and 36m  respectively

Let the width of the lot be x,

therefore, length=x+10 (as the lot must be 10m longer than it's wide)

Now, according to the question:

Area of the lot= 1656 m²

Area of a rectangle is given by the product of it's length to width, that is:

⇒ Length × Width= 1656 m²

⇒ (10+x).x= 1656

⇒ 10x+x²= 1656

⇒ x²+10x-1656=0

⇒x²+46x-36x-1656=0

⇒x(x+46)-36(x+46)=0

⇒(x-36)(x+46)=0

⇒x=36 or x=-46(which can be ignored)

∴ x=36 and 10+x=46

So, the length of the lot is 46m and the width is 36m.

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Answer + Step-by-step explanation:

a) GE = r = GM

Then GEO is an isosceles triangle

b) since GEO is an isosceles triangle  then :

m∠SEG = m∠GOM = measure of the arc GM (mGM)  (result 1)

On the other hand :

m∠SEG = m∠SEG = (1/2)×(mAS - mGM)  (it’s a formula)   (result 2)

Now ,we equate  (result 1) and  (result 2) :

m∠SEG = mGM  

m∠SEG = (1/2)×(mAS - mGM)

Then

mGM = (1/2)×(mAS - mGM)

c) mGM = (1/2)×(mAS - mGM)

⇔ 2mGM = mAS - mGM

⇔ 3mGM = mAS

⇔ 3m∠SEA = m∠SOA

Remember:

mGM = m∠GOM = m∠SEA

Answer:

C. 36

There are 150 cups total, and 60 blue cups

\(150/60=0.4\)

Multiply that by the number of cups he picked up

\(0.4*90=36\)

The equation of the line that passes through (-4, 4) and is perpendicular to y = (1/2)x + 1 is y = -2x - 4.

What is slope formula?

The formula to find the slope between 2 coordinates of a line is given by;

m = (y₂ - y₁)/(x₂ - x₁)

The slope of a line perpendicular to y = (1/2)x + 1 will have a slope that is the negative reciprocal of (1/2).

Now we can use the point-slope form of a line to write the equation of the line:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is a point on the line.

Substituting m = -2 and (x1, y1) = (-4, 4), we get:

y - 4 = -2(x - (-4))

Simplifying:

y - 4 = -2(x + 4)

y - 4 = -2x - 8

y = -2x - 4

So, the equation of the line that passes through (-4, 4) and is perpendicular to y = (1/2)x + 1 is y = -2x - 4.

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Answer:

Part A: \(\frac{3}{5}\)

Part B: \(\frac{1}{2}\)

Step-by-step explanation:

We know that Alinn flipped a coin 20 times, and that 12 of those times resulted in heads. The other 8 times resulted in tails.

Part A wants us to find the experimental probability of the coin landing on heads. Experimental probability is the probability determined based on the experiments performed.

Part B wants us to find the theoretical probability of the coin landing on heads. Theoretical probability is determined based on the number of favorable outcomes over the number of possible outcomes.

Experimental probability is determined as # of times something occurred experimentally / total number of times.  

Since 12 of the 20 times that Alinn flipped the coin resulted in heads, this means that the experimental probability of Alinn flipping heads is \(\frac{12}{20}\), which simplifies down to \(\frac{3}{5}\).

Theoretical probability, as stated above, is the number of favorable outcomes / possible outcomes.

Our favorable outcome is flipping heads, and on a coin, there are two sides that a coin can land on: heads and tails. This means that there are two possible outcomes, and only one of them is favorable.

This means that our theoretical probability is \(\frac{1}{2}\).

Answer:

does it want the degree????

Answer:

Step-by-step explanation:

B

Answer d

Step-by-step explanation:d

Answer:

c. 51

Step-by-step explanation:

Answer:

My earlier answer was deleted, so I'm reposting.  The only thing I can think happened is that I included a link to a free bar chart program, which I used for the attached chart.

Step-by-step explanation:

Make your own chart or find an online bar chart utility.  I was unable to properly label the title and axes on my chart, so modify these properties.

The conditional probability of X taking the value n+k given that X is greater than n is the same as the unconditional probability of X taking the value k, as the memoryless property ensures that the probability of the event happening is constant regardless of the number of previous trials.

To show analytically that P(X = n+k|X > n) = P(X = k) for a geometric random variable X, we can use the properties of geometric distributions.

First, let's define the probability mass function (PMF) of a geometric random variable X with parameter p as:

P(X = k) = \((1 - p)^{k-1}\) * p

Now, let's consider P(X = n+k|X > n), which represents the conditional probability that X takes the value n+k given that X is greater than n.

Using the definition of conditional probability, we have:

P(X = n+k|X > n) = P(X = n+k and X > n) / P(X > n)

The numerator represents the joint probability that X takes the value n+k and X is greater than n. Since X follows a geometric distribution, the event X > n implies that X takes a value greater than or equal to n+1.

Therefore, we can rewrite the numerator as:

P(X = n+k and X > n) = P(X = n+k and X ≥ n+1)

Since X is a geometric random variable, the probability of it taking a specific value k given that it is greater than or equal to n+1 is the same as the probability of it taking the value k. This is because the geometric distribution has the memoryless property, meaning that the outcome of future trials does not depend on the outcomes of past trials.

Therefore, we can simplify the numerator as:

P(X = n+k and X ≥ n+1) = P(X = n+k)

Finally, we divide this numerator by the denominator P(X > n) to get:

P(X = n+k|X > n) = P(X = n+k) / P(X > n)

Using the PMF of the geometric random variable, we substitute the expressions:

P(X = n+k) = \((1 - p)^{n+k-1}\) * p

P(X > n) = 1 - P(X ≤ n) = 1 - [(1 - p)ⁿ * p]

Substituting these values into the equation, we have:

P(X = n+k|X > n) = [\((1 - p)^{n+k-1}\) * p] / [1 - (1 - pⁿ) * p]

We can simplify this expression further, but at this point, we have shown analytically that P(X = n+k|X > n) = P(X = n+k). This means that the conditional probability of X taking the value n+k given that it is greater than n is equal to the probability of X taking the value k.

Verbal Argument:

The equation P(X = n+k|X > n) = P(X = k) holds true for geometric random variables because of the memoryless property of the geometric distribution. In a geometric distribution, each trial represents the occurrence of a specific event, and the probability of the event happening in each trial remains constant.

When we condition on X > n, it means that we have already observed n trials without the event occurring. At this point, the remaining trials are independent of the previous n trials. The geometric distribution does not "remember" or take into account the number of trials that have already occurred.

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The correct statements are:

b) Ordering costs decrease with respect to lot size,

c) It is good to have fixed interval ordering systems for products that have independent demand,

e) Taxes and insurance costs can be considered as carrying costs of inventory,

f) Costs incurred for defective products identified after the products are shipped are classified as internal failure costs,

h) Costs of repairing faulty products under warranty are limited to external failure costs, and j) Under EOQ inventory model, there is an assumption which states that there is no possibility of inventory stockout to occur.

b) Ordering costs decrease with respect to lot size: Ordering costs involve the expenses incurred when placing orders for inventory, such as administrative costs, processing fees, and transportation costs.

When the lot size increases, the frequency of placing orders decreases, resulting in lower ordering costs per unit. This is because the fixed costs associated with ordering are spread over a larger quantity of inventory.

c) It is good to have fixed interval ordering systems for products that have independent demand: Fixed interval ordering systems involve placing orders at regular intervals, regardless of the inventory level.

This approach is suitable for products with independent demand, where the demand is unpredictable or sporadic. By setting fixed intervals, the company can ensure a consistent replenishment schedule and avoid stockouts while optimizing inventory levels.

e) Taxes and insurance costs can be considered as carrying costs of inventory: Carrying costs are the expenses associated with holding and storing inventory.

They include costs such as storage fees, insurance premiums, taxes on inventory, and the opportunity cost of tying up capital in inventory. Taxes and insurance costs directly impact the financial burden of inventory holding and are considered as components of carrying costs.

f) Costs incurred for defective products identified after the products are shipped are classified as internal failure costs: Internal failure costs are expenses incurred due to quality issues discovered within the company's operations.

In the context of inventory, costs related to defective products identified after they are shipped, but before reaching the customer, fall under internal failure costs. These costs include rework, scrap, and any necessary corrective actions taken to address the quality problems.

h) Costs of repairing faulty products under warranty are limited to external failure costs: External failure costs are the expenses incurred due to quality issues discovered by customers after the products have been delivered.

When faulty products are repaired under warranty, the costs associated with the repairs are considered external failure costs. This includes the direct costs of repairing or replacing the faulty products and any associated customer service expenses.

j) Under EOQ inventory model, there is an assumption which states that there is no possibility of inventory stockout to occur: The Economic Order Quantity (EOQ) model is a widely used inventory management technique.

It assumes that demand for the product is constant and known with certainty, there are no quantity discounts or price variations, and there is no possibility of stockouts occurring.

The assumption of no stockouts simplifies the calculations and ensures that the optimal order quantity obtained from the model will meet the demand without interruptions.

However, in real-world scenarios, stockouts can occur due to unforeseen factors, variability in demand, or supply chain disruptions.

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Answer:

A.

2, 23, 51

Step-by-step explanation:

Substitute 2, 5, and 9 for n in the function and simplify in each case.

a2=−5+(2−1)(7)=2 a subscript 2 baseline equals negative 5 plus left parenthesis 2 minus 1 right parenthesis left parenthesis 7 right parenthesis equals 2

a5=−5+(5−1)(7)=23 a subscript 5 baseline equals negative 5 plus left parenthesis 5 minus 1 right parenthesis left parenthesis 7 right parenthesis equals 23

a9=−5+(9−1)(7)=51 a subscript 9 baseline equals negative 5 plus left parenthesis 9 minus 1 right parenthesis left parenthesis 7 right parenthesis equals 51

The action that would reduce the amount the person paid in taxes to 1,000 is option (D) Receiving a $49,000 tax credit

In this scenario, the person has $50,000 in taxable income and pays a 10% income tax rate, which amounts to $5,000 in taxes. To reduce the tax liability to $1,000, the person needs to receive a tax credit of $49,000. Tax credits directly reduce the amount of tax owed, whereas tax deductions reduce taxable income.

A tax deduction of $4,000 would lower the taxable income to $46,000, resulting in a lower tax liability of $4,600, which is not low enough to reach $1,000. Therefore, a tax credit of $49,000 is needed to reduce the tax liability to $1,000.

Therefore, the correct option is (D) Receiving a $49,000 tax credit

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The given question is incomplete, the complete question is:

A person has $50,000 in taxable income for a year and pays a 10 percent income tax rate, equal to $5,000. Which action would reduce the amount the person paid in taxes to $1,000?

A.Receiving a $4,000 tax deduction

B.Receiving a $4,000 tax credit

C. Receiving a $49,000 tax deduction

D. Receiving a $49,000 tax credit

According to Weber's law, two items must differ in weight by "5 percent"of weight in order to detect a difference.

We are given that Weber's law

For weight discrimination, Weber’s law states that the JND is proportional to the weight of the stimulus.

The JND is defined as the smallest difference between two weights that can be detected by an observer.

The proportionality constant is known as Weber’s fraction and varies depending on the type of stimulus and the sensory modality involved.

For weight discrimination, Weber’s fraction is typically around 2-3%.

This means that two items must differ in weight by approximately 2-3% of their weight in order to detect a difference.

The difference of weight in percent is 5%, the correct option is A.

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Answer:

C

Step-by-step explanation:

the general equation is y=mx+b where m is the slope

if the slope of the line are the same the lines are parallel

y=2/3x+5 has the slope 2/3

C. y=2/3x-7 has the same slope 2/3

Answer:

I hope this helps.

Step-by-step explanation:

Step-by-step explanation:

just use step by step process so dum

Answer:c

Step-by-step explanation:

Answer:

D(last answer choice)

Step-by-step explanation:

(5x-6)(3x+4)

Foil it out to get:

\(15x^2+20x-18x-24\)

This simplifies to:

\(15x^2+2x-24\)

Answer:

46°

Step-by-step explanation:

from large triangle:

let the third unknown angle be 'a'

then,

a+x+7+85=180

a=88-x

now,from small triangle,

let the third unknown angle be 'b'

then,

b+x+2x=180

b=180-3x

b=a (vertically opposite angles)

then,

180-3x=88-x

2x=92

x=46

The solution is :

There are 240 students in the school.

Here, we have,

Givens

55% of the total number of students in a school are girls.

Equation

55/100 * x = 132

Solution

Multiply both sides of the equation  by 100

55/100x * 100  = 132 * 100

55x = 13200                        [  Divide by 55  ]

55x/55  = 13200/55

x = 240

Hence, The solution is :

There are 240 students in the school.

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complete question:

Of the students at milton middle school, 132 are girls. if 55% of the students are girls, how many total students are there at milton middle school?

Answer:

7 and 8: these are both proportional relationships because they grow at a constant rate of change

9: for every 40 miles that the car travels, it uses 2 gallons of gas.

10:  y= 20x

11: the graph would be steeper and have a greater rate of change. This car would be able to go farther on less fuel.

\(\pi r^{2} =\\3,14*4^{2} \\3,14*16\\=50.24\)

log 30+ log 6 is not equivalent to log 36

Equivalent expressions are expressions that perform the same function not with standing their appearance. If two algebraic expressions are equivalent, they have the same value when the same value(s) for the variable are used (s).

The original phrase is as follows

Log 36

Following that, we write the alternatives (a) log 2+ log 18

Apply the logarithmic rule log 2+ log 18 log (218)

Log 2 plus log 18 log (36)

Remove the bracket

Log 2 plus log 18 log36

(a) Log 2+ Log 18 is the same as log 36.

(b) Log 30 plus log 6

Use the logarithms’ law. 30 logs or more 6 logs (30 x 6)

Log 30 plus log 6 Equals log (180)

Remove the bracket

Log 30-plus log 6-log180

Hence,

(c) Log 30+log 6 does not equal log 36.

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Answer:

\(P(A < 84)=\frac{4}{7}\)

Step-by-step explanation:

\(Total\ numbers:\ 7\\Numbers\ less\ than\ 84:\ 4\\\\P(A < 84)=\frac{4}{7}\)

Answer:

13122

Step-by-step explanation:

6 x 3 = 18; 18 x 3 = 54; continue to do this 8 times and you get 13122!

Answer:

a(8) = 6*3^7 = 13122

Step-by-step explanation:

Each new term is equal to the previous one times the common ratio, r, which in this case is 3.

The general formula for a geometric sequence is a(n) = a(1)*r^(n - 1).

In this particular case, we have a(n) = 6*(3)^(n -1).

The 8th term of this sequence is a(8) = 6(3)^(8 - 1), which works out to:

a(8) = 6*3^7 = 13122

√48 = 4√3

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