Answer:
the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev
Explanation:
Given;
Angular velocity v = 33.9 rad/s
Time t = 92.1 s
Angular displacement d = angular velocity × time
d = vt
Substituting the given values;
d = 33.9 × 92.1 rad
d = 3122.19 rad
To revolutions;
revolution = radian/2π
d = 3122.19/2π rev
d = 496.91 rev
the angular displacement Δθ of the tub during a spin of 92.1s is 3122.19 rad or 496.91 rev
Use the heating curve (Figure 1) to answer the question.
Temperature (°C)
200
150
100
50
0
-50
-100
-150
200 400 600 800 1000 1200
Energy (J)
What is the boiling point of the substance represented?
0
-100 °C
150 °C
-50 °C
50 °C
Answer:
Melting Point = -50 °C
Boiling Point = 50 °C
Explanation:
A heating curve displays a substance in its 3 states.
On the graph, each region where the slope is positive represents the substance as a solid, liquid, or gas.
When the slope is 0, this is the temperature point at which the substance's state of matter has changed (i.e., melting or boiling/vaporization point) – also known as a phase transition. Essentially, the 0 slope regions are where the substance is changing from one state of matter to the next.
(When the substance is being heated, it's absorbing energy, but when it reaches a phase transition point, the substance begins to consume energy to change its matter state. That's why the temperature doesn't go up while the substance's internal Energy increases.)
In (Figure 1), where 'x' is Energy (J) and 'y' is Temperature (°C):
Region A (0 J ≤ x ≤ 200 J):
The slope is positive, so the substance is in a constant matter state. Because it's the first sloped region, the substance is in its solid state from -100 °C to -50 °C.
Region B (200 J ≤ x 600 J):
The slope is 0, so the substance has reached a phase transition point. Because the previous region was when the substance was solid, that means that the temperature throughout Region B is the melting point at -50 °C.
Region C (600 J ≤ x ≤ 800 J):
The slope is positive so the substance is in a constant matter state. We've already identified when the substance was solid and when it melted, so now the substance is in its liquid state from -50 °C to 50 °C.
Region D (800 J ≤ x ≤ 900 J):
The slope is 0, and since the previous region was when the substance was a liquid, it's now reached its boiling point at 50 °C.
Region E (900 J ≤ x ≤ 1000 J):
The slope is positive, and we've previously identified all of the transition points and matter states except for one, so the substance is now in its gaseous state after reaching 100°C.
(Once a substance reaches its gaseous state, the Temperature/Energy ratio is constant.)
When the pressure above a liquid is reduced (like in a vacuum), the boiling point of the liquid is
When the pressure above a liquid is reduced, the force pushing the liquid is reduced, which means it's easier for the molecules of the liquid to escape to the atmosphere.
If it's easier for the molecules to escape, the boiling point decreases, because less energy is needed to evaporate the liquid.
Newton's Three laws talk about all of the following:
Inertia, Mass, Force, Acceleration, and Velocity.
Which of these five things is involed/relevent to all three laws? Explain why.
A solenoid with 465 turns has a length of 8.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s
The solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s will be 1.01 ×10⁻⁸ H and 9.02 × 10⁻² V.
What is a solenoid?A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire.
Which generates a magnetic field when an electric current is passed through the coil.
A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.
Given data;
Turns ,N = 465
Length,L= 8.00 cm
Cross-sectional area,A = 3.10 ✕ 10−9 m2.
Solenoid's inductance, L=?
The average emf around the solenoid, E=?
Time of flow,t= 7.83 ✕ 10−3 s
Current changes from +3.50 A to −3.50 A
The inductance of the solenoid is found as;
\(\rm L = \frac{\mu_0 AN^2}{L} \\\\ \rm L = \frac{4 \times \pi \times 10^{-7}\times 3.0 \times 10^{-9} \times (465)^2 }{8.00 \times 10^{-2}} \\\\ L= 1.01 \times 10^{-8} \ H\)
The average emf around the solenoid is found as;
\(\rm e = L \frac{I_2-I_1}{t} \\\\ \rm e = 1.01 \times 10^{-8} \times \frac{3.50-(-3.50)}{7.83 \times 10^{-3}} \\\\ e =9.02 \times 10^{-12} \ V\)
Hence, the solenoid's inductance will be 1.01× 10⁻⁸ H.
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What is a centripetal acceleration of a greyhound running on a circular track with a radius of 50 m at 12.5 m/s
Answer:
Centripetal acceleration = 3.125 m/s²
Explanation:
Given the following data;
Radius, r = 50 m
Velocity, V = 12.5 m/s
To find the centripetal acceleration;
Centripetal acceleration = Velocity²/radius
Centripetal acceleration = 12.5²/50
Centripetal acceleration = 156.25/50
Centripetal acceleration = 3.125 m/s²
Therefore, the centripetal acceleration of the greyhound running on a circular track is 3.125 meters per seconds square.
Shawn and his bike have a total mass of 49.9 kg. Shawn rides his bike 0.92 km in 15.4 min at a constant velocity. The acceleration of gravity is 9.8 m/s 2 . What is Shawn’s kinetic energy? Answer in units of J.
Answer:
0 J
Explanation:
KE = .5(m)(v2-v1)
if velocity is constant v2 = v1, then v2 - v1 = 0
therefore if (v2-v1) = 0, then KE must also be equal to 0
Sally and Sam are in a spaceship that comes to within 15,000 km of the asteroid Ceres. Determine the force Sally experiences, in N, due to the presence of the asteroid. The mass of the asteroid is 8.7 1020 kg and the mass of Sally is 68 kg. For calculation purposes, assume the two objects to be point masses.
The gravitational force that is acting on the masses is 1.73 * 10^-2 N.
What is the force?We know that the force of gravity is that kind of force that is going to act on any two of the objects that we have on the earth. This force as we know it is attractive force. The implication of this is that any two masses that we find on the earth are the forces that would have to be attracted to each other.
Let us note that we would have the masses that we have of the asteroid and that of sally as m1 and m2 while we have the force as;
F = G m1m2/r^2
G = gravitational constant
F = magnitude of the force
m1 and m2 = masses
r = distance of separation.
We then have;
F = 6.6 * 10^-11 * 8.7 * 10^20 * 68/(15 * 10^6)^2
F = 3.9 * 10^12/2.25 * 10^14
F = 1.73 * 10^-2 N
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A skier pushes off the top of a hill with an initial speed of 3.30 m/s. How fast will she be moving after dropping 5.00 meters in elevation if friction is negligible?
Answer:
eeeeeeeeeeeeeeeeeeeee
A crate rests on a flatbed truck which is initially traveling at 13.6m/s on a level road. The driver applies the brakes and the truck is brought to a halt in a distance of 41.0m. If the deceleration of the truck is constant, what is the minimum coefficient of friction between the crate and the truck that is required to keep the crate from sliding?
The coefficient of friction between the crate and the truck that is required to keep the crate from sliding is 0.23
Explanation:The initial veocity of the truck, u = 13.6 m/s
The distance covered, s = 41.0 m
The driver applies the brakes and the truck is brought to a halt
The final velocity = 0 m/s
Calculate the deceleration by using the equation of motion below
\(\begin{gathered} v^2=u^2+2as \\ 0^2=13.6^2+2a(41) \\ 82a=-13.6^2 \\ 82a=-184.96 \\ a=-\frac{184.96}{82} \\ a=-2.26m/s^2 \end{gathered}\)Calculate the coefficient of friction using the relationship below
\(\begin{gathered} a=-\mu g \\ -2.26=-9.8\mu \\ \mu=-\frac{2.26}{-9.8} \\ \mu=0.23 \end{gathered}\)The coefficient of friction between the crate and the truck that is required to keep the crate from sliding is 0.23
What do you mean by Secondary colours?
For example
If you mix up red and yellow you will get orange colour2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True
The statement that is NOT true is "the spaces between the particles increased.
option D.
What is effect of temperature on volume?If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.
Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.
As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.
However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.
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Which law of motion is this an example of? Newton's 1st Law of Motion
Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:
first law is your answer, if I'm not wrong
Answer:
i think it's the first law of motion :)
Explanation:
Summarise Specific Heat Capacity in 10 sentences
laser light (λ = 568.7 nm) is incident on a single slit. what is the maximum width of the slit (in nm) for which no diffraction minima are observed? round to the closest integer.
The maximum width of the slit (in nm) for which no diffraction minima are observed is 569 nm.
What is the maximum width of the slit?The maximum width of the slit (in nm) for which no diffraction minima are observed is calculated by applying the following equation.
sinθ = mλ/a
where;
m is = 1 order integerthe maximum angle for diffraction to occur = 90⁰λ is the wavelength = 568.7 nma is the maximum width of the slitSubstitute the given parameters and solve for the maximum width of the slit (in nm) for which no diffraction minima are observed.
sin(90) = (1 x 568.7 nm) / a
1 = (568.7 nm) / a
a = (568.7 nm) /1
a = 568.7 nm
to the closest integer = 569 nm
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What are patients most likely to prepare as part of their right to make decisions about end of life care under federal legislation
BECAUSE OF THEIR A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY
a. Acceleration
b. inertia
c. velocity
d. weight
Answer:
b. inertia
Explanation:
BECAUSE OF THEIR inertia A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY.
star cluster a has o and b main sequence stars, while cluster b only has g spectral type and cooler main sequence stars. which cluster is younger?
If star Cluster A has O and B main sequence stars, while Cluster B only has G spectral type and cooler main sequence stars, then the younger cluster is Cluster A.
What is an astronomic star cluster?An astronomic star cluster is a group of stars that may be recognized to have a common origin, which is also associated with the age of the stars, and they are gravitationally linked in the universe space due to physical forces that maintain connected them.
The age of a given astronomic star cluster may be measured by determining the spectral type and the temperature (spectral light) of the main sequence.
Therefore, with this data, we can see that an astronomic star cluster is composed of different stars that have a common origin and whose age can be determined by the emission spectra which are indicative of the temperature.
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A ship’s total displacement is 7400 km at 26° south of west. If the ship sails 3200 km south, what is the western component of its journey?
Answer: i think its a carrot
Explanation: idek how to do history
The decibel rules of thumb can be combined. (a) If a sound has intensity xdB, how many dB does a sound 100 times more intense have? (b) If another sound has intensity ydB, how many dB does a sound 4 times less intense have? (c) Combine what you know about (a) and (b): If a sound has intensity zdB, how many dB does a sound 25 times more intense have?
6. A ball is dropped vertically downward with a velocity of 15m/s from te roof of a building that is 22m high. How long does it takes to hit the ground below? How fast was it going when it hit
Answer:
3.03 seconds, 29.51 m/s
Explanation:
To solve this problem, we can use the kinematic equations of motion. The equation we will use is:
y = vi * t + 0.5 * a * t^2
where y is the displacement (height), vi is the initial velocity, a is the acceleration due to gravity (9.81 m/s^2), and t is the time.
At the top of the building, the displacement is 22 m (the height of the building), the initial velocity is 15 m/s (downward), and the acceleration is -9.81 m/s^2 (due to gravity, and negative because it is acting in the opposite direction to the initial velocity).
We can rearrange the equation to solve for time:
y = vi * t + 0.5 * a * t^2
22 = 15t - 0.5 * 9.81 * t^2
0.5 * 9.81 * t^2 - 15t + 22 = 0
Solving for t using the quadratic formula, we get:
t = (-(-15) ± sqrt((-15)^2 - 4 * 0.5 * 9.81 * 22)) / (2 * 0.5 * 9.81)
t = 3.03 s (rounded to two decimal places)
Therefore, it takes approximately 3.03 seconds for the ball to hit the ground.
To find the velocity of the ball when it hits the ground, we can use the equation:
v = vi + a * t
where v is the final velocity (unknown), vi is the initial velocity (15 m/s downward), a is the acceleration due to gravity (-9.81 m/s^2 downward), and t is the time (3.03 s).
Substituting the values, we get:
v = 15 - 9.81 * 3.03
v = -29.51 m/s
The negative sign indicates that the final velocity is in the opposite direction to the initial velocity (upward). However, since we were only asked for the speed (not velocity), we can take the absolute value of the answer to get:
|v| = 29.51 m/s
Therefore, the ball is going approximately 29.51 m/s when it hits the ground below.
Lab Report Sun, Earth, and Moon Models It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U5_ Lab_SunEarthAndMoonModels_Alice_Jones.doc). Introduction 1. What was the purpose of the investigation? Type your answer here: 2. What causes the bright part of the moon to appear bright? Type your answer here: Experimental Methods 1. What materials did you use to create your model? Type your answer here: 2. Describe how you created your model. Type your answer here: Develop a Model 1. Show your model and the relationships between the components. Include labeled pictures or diagrams that describe causal accounts for the phases of the moon and eclipses. Type your answer here: Use a Model 1. Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Type your answer here: 2. Use your model to explain why a lunar eclipse does not occur every month when there is a full moon. Type your answer here:
1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.
2. The bright part of the moon appears bright due to the reflection of sunlight.
Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.
Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.
Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.
Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.
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A railroad freight car, mass 15000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples with a 50000 kg freight car, initially at rest and with brakes released. What percentage of the initial kinetic energy of the 15000 kg car is preserved in the coupled cars after collision
Answer:
Explanation:
Use conservation of momentum to find the final velocity
15000(2.0) + 50000(0) = (15000 + 50000)v
v = 0.461538461... = 0.46 m/s
KEf / KEi = ½65000(0.46²) / (½15000(2²) + ½50000(0²)) = 0.2307687...
KEf / KEi = 23%
A car stopped at a red light, begins to accelerate with a constant acceleration of 7.4 m/s^2 during a
time of 2.4 seconds. If the speed limit of the road is 35 mph (about 15.64 m/s), is the car
considered to be speeding at any point?
Answer:
The car is considered to be speeding
Explanation:
The following data were obtained from the question:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Speed limit = 15.64 m/s
To know if the car speeding at any point, we shall determine the velocity of the car.
This can be obtained as follow:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Constant velocity (v) =?
a = v/t
7.4 = v / 2.4
Cross multiply
v = 7.4 × 2.4
v = 17.76 m/s
Thus, the velocity of the car is 17.76 m/s.
Comparing the velocity of the car (i.e 17.76 m/s) with the speed limit (i.e 15.64 m/s), we can see that the velocity of the car is higher than the speed limit. Therefore, the car is considered to be speeding.
Assume that the temperature outside is 293 Kelvin but you’re familiar only with the Fahrenheit scale. Do you need to wear a hat and gloves when you go outside? To find out, convert the Kelvin temperature to Fahrenheit. (Hint: Convert the Kelvin temperature to Celsius first.)
Given,
The temperature in Kelvin, T_K=293 K
The temperature can be converted into Celcius using the formula,
\(T_C=T_K-273\)On substituting the known values,
\(\begin{gathered} T_C=293-273_{} \\ =20\text{ }\degree\text{C} \end{gathered}\)The temperature can be converted from Celcius to Fahrenheit using the equation,
\(T_F=(T_C\times\frac{9}{5})+32\)On substituting the known values,
\(\begin{gathered} T_F=20\times\frac{9}{5}+32 \\ =68\text{ }\degree\text{F} \end{gathered}\)Thus 293 K in Fahrenheit is 68 °F
Two blocks of equal mass are connected by a string that passes over a pulley, as shown in the figure. Block 1 hangs from the string, and block 2 can slide on a table. The system is released from rest. Using conservation of energy, a student derives an expression for the speed v of block 1 when it has fallen a distance h after the system has been released from rest and obtains the equation v=gh−−√ . Question The figure presents a diagram of a pulley system at the edge of a table. A block labeled Block 1 is hanging off the table. Two other blocks are on the table. The block on the left is labeled Block 3 and the block on the right is labeled block 2. Block 1 is connected to a string that passes through a pulley. The left end of the string is connected to the right side of Block 2. Another string connected the left side of Block 2 to the right side of Block 3. A third block of the same mass as blocks 1 and 2 is attached to block 2 on the table, as shown in the figure. Using conservation of energy, the student repeats a derivation for the speed v of block 1 when it has fallen a distance h . Which of the following is a correct expression for v ? Responses gh√3 the fraction with numerator the square root of g h, and denominator 3 gh√2
Block y will experience a stronger pull from gravity and fall more quickly than block x since it has more mass than block x is 29.4 md
To complete this task, we will apply Newton's second law. Assume that a block with mass m is moving up.
T-W₁ = m a
W₃ - T = M a
w₃ - w₁ = (m + M) a
g = a = (3m - m) / (3m + m)
a = 2/4 g
a = ½ g
The blocks move at a pace of
v² = v₀² + 2 ½ g x
v = √ g x
b) As work is a scalar, it adds to other quantities.
luminous blocks
W1 = W d = mg
d = -a 3 m hefty block
W2 = 3m g d = W d
the entire project is
W = W₁ + W₂
W = 2 m g d
c) When all external pressures are applied to the centre of mass, they relate to it being
a = ½ g
T = 2m1m2g/(m2 + m1)
= 2x mx3x3mg/ 4m
= 14.7 m
Work done in moving by distance by tension on both masses d
= 2 x 14.7 m x d ( 2 x force x displacement ) ( 2 x force x displacement )
= 29.4 md .
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A cyclist bikes with an average velocity of 20 m/s for 5 seconds.
What is the magnitude of the cyclist's displacement?
Your answer should have one significant figure.
Explanation:
v = s/t
20 = s/5
100 = s
s = 100 = 1 × 10².
When a cyclist bikes with an average velocity of 20 m/s for 5 seconds, the magnitude of the cyclist displacement would be 1×10² meters.
What is Velocity?
The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.
The mathematical expression for velocity is given by the formula
velocity= total displacement/Total time
The area under the velocity-time graph represents the total displacement covered by the object while the slope of the velocity time graph represents the acceleration of the object.
For the given problem when a cyclist bikes with an average velocity of 20 m/s for 5 seconds,
Displacement =velocity×time
=20×5
=1×10²
The magnitude of the cyclist's displacement is 1×10²
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
Now that you've done your research on the law of supply, you understand that it basically asserts that how much coffee you'd be willing to supply depends on how much money you can make for each cup.
را Three forces acting at a point of 300N forces may varies but the angle between is always 40. Determine the value of the angle for which the value of the resultant force is parallel to BB.
The value of the angle for which the value of the resultant force is parallel to b-b is 6.35°. Therefore, the correct option is A.
What is an angle?An angle can be defined as the figure that is formed when two rays or lines shares a common endpoint.
Let the x and y-axis be shown here. If the resultant is directed along the x-axis, then its component in the y direction is zero.
0 = ΣFy = 300 sin θ + 300 sin (40 + θ) – 500 sin 30°
Therefore, sin θ+ sin (40+ θ)= 500 sin 30°÷ 300
⇒ sin θ + sin (40 + θ) = 0.833
⇒ 2 sin (40 + θ + θ)÷ 2 × cos 40 + θ—θ) ÷ 2 = 0.833
⇒ 2 sin (20 + θ) × cos (20) = 0.833
⇒ θ = 6.35°
Hence, the value of angle is 6.35°. Therefore, the correct option is A.
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The question is incomplete, but most probably the complete question is,
Three forces acting at a point are shown in Fig. The direction of the 300 N forces may vary, but the angle between them is always 40°. Determine the value of θ for which the resultant of the three forces is directed parallel to b-b.
A. 6.35°
B. 6.00°
C. 7.40°
D. 4.81°
Find the self-inductance of a 1700-turn solenoid 55 cm long and 4.0 cm in diameter. Express your answer with the appropriate units.
The self-inductance of the solenoid is 8.25 mH.
The given parameters;
number of turns, N = 1700 turnlength of the solenoid, l = 55 cm = 0.55 mdiameter of solenoid, d = 4 cmradius of the solenoid, r = 2 cm = 0.02 mThe area of the solenoid is calculated as follows;
\(A = \pi r^2\\\\A = \pi \times (0.02)^2\\\\A = 0.00125 \ m^2\)
The self-inductance of the solenoid is calculated as follows;
\(L = \frac{\mu_o N^2 A }{l} \\\\L = \frac{(4\pi \times 10^{-7}) \times 1700^2 \times 0.00125}{0.55} \\\\L = 0.00825 \ H\\\\L = 8.25\ mH\)
Thus, the self-inductance of the solenoid is 8.25 mH.
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