during fusion, a force must be overcome to bring reacting nuclei together. the nature of this force is a force. is called
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The force that must be overcome to bring reacting nuclei together during fusion is the Coulomb force, which is the electrostatic force of repulsion between positively charged atomic nuclei.
In the case of fusion, the positively charged nuclei must overcome this force of repulsion in order to get close enough together for the strong nuclear force to come into play and bind them together. This requires an immense amount of energy, which is typically provided by high temperatures and pressures in a fusion reactor.
The challenge of harnessing fusion as a viable energy source lies in being able to sustain the high temperatures and pressures required to overcome the Coulomb force and initiate fusion reactions, while also effectively managing the resulting energy output.
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During fusion, a force must be overcome to bring reacting nuclei together. This force is called the electrostatic force, also known as the Coulomb force.
During fusion, the force that must be overcome to bring reacting nuclei together is known as the Coulomb force, which is an electrostatic force of repulsion between positively charged nuclei. This force arises due to the fact that both nuclei have a positive charge, and like charges repel each other.
The Coulomb force is a fundamental force of nature, and it is one of the four fundamental forces that govern the behavior of matter. It is responsible for many phenomena in our everyday lives, such as the repulsion between two magnets with the same polarity and the interaction between charged particles in electric circuits.
In the context of fusion, the Coulomb force must be overcome by the high temperature and pressure in the fusion plasma in order to bring the reacting nuclei close enough together for the strong nuclear force to take over and bind them into a new, heavier nucleus. This process releases a tremendous amount of energy and is the fundamental source of energy in the sun and other stars.
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Related Questions
What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
Answers
Answer:
5 m/s²
Explanation:
Acceleration = change in speed/time taken
20-5=15
15/3= 5 m/s²
If a balloon is charged with static electricity and you rip small pieces of tissue paper. Will it stick to the balloon?
Answers
Answer:
Yes
Explanation:
Rubbing a balloon with wool cloth will create static electricity charges. If you place small pieces of tissue paper near the balloon in Picture 2, they would probably stick to the balloon.
the bold type sa matanda
Answers
Complete the following hypothesis the pressure lncrease as
Answers
Temperature is increased the pressure also increases due to fast movement of molecules because of more energy.
How temperature is related to pressure?The temperature of the gas is directly proportional to the pressure. Faster moving particles will collide with the walls of the container that put force on the wall which leads to increase in pressure.
So we can conclude that temperature is increased the pressure also increases due to fast movement of molecules because of more energy.
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One forecasting model was used to forecast demand for a product. The forecasts and the demand are shown in the table below. B Actual Forecast 11 40 41 35 38 3 38 35 33 30 IX Calculate Moan Absolute Deviation (MAD) and Mean Squared Error (MSE). Show all details and use 1 decimal in your answer For the toolbar, press ALT+F10 (PC) or ALT+FN-F10 (Mac). BI V S Paragraph Arial 14px V QUESTION 1 The department manager is using a combination of methods to forecast sales of tonsters at a local department store. The demanders shown in the be Week Actu Demand 11 24 bo 2 bas x III A Using trend projection, calculate foresting values for week and week & Show details of your answer For the toolbar, pro ALT.F10 PC) O ALT.FN.F10 Mac BIS Paragraph Arial 14 Focus Chile we state
Answers
The estimated demand for Week 4 is 36.3
MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:
MAD= Sum of| Actual demand - Forecast demand | / number of periods
In the given table, the Actual demand is shown as B and the forecast demand is shown as F.
B Actual Forecast 11 40 41 35 38 3 38 35 33 30
Calculation of MAD:
Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0
The number of periods is 9 as shown in the table.
MAD= 103/9MAD= 11.44
Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:
MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.
Calculation of MSE:
Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854
The number of periods is 9 as shown in the table.
MSE= 2854/9MSE= 317.1
Therefore, the calculated MAD is 11.44 and MSE is 317.1.
Trend Projection formula is given by:
Y = a + bx
where Y is the estimated demand for a particular period.
a is the Y-intercept
b is the slope of the regression line x is the period number
In the given table, the Week number is shown as X and the Actual demand is shown as Y.
Week number Actual Demand 11 24 22 29
Using trend projection for Week 3, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4
Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35
Therefore, the estimated demand for Week 3 is 35.
Using trend projection for Week 4, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78
Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3
Therefore, the estimated demand for Week 4 is 36.3.
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The small lens in a telescope that magnifies an image is called the:.
Answers
You only need an eyepiece if the image is to be examined by a human eye. But for prime focus photography or spectroscopy, it's not needed.
Nobody ever looked through an eyepiece on the Hubble Space scope, and I doubt that the Webb has one either.
imagine that you lived in a dot on the surface of an expanding balloon, and as you looked to more distant dots, you observed the following
a.A dot at a distance of 5 centimeters from you is moving away from you at a speed of 1 centimeter per hour (1 cm/hr). •
b. A dot at a distance of 10 centimeters from you moving away from you at a speed of 2 centimeters per hour (2 cm/hr). c.A dot at a distance of 15 centimeters from you moving away from you at a speed of 3 centimeters per hour (3 cm/hr)
Answers
This phenomenon is similar to what astronomers observe in our actual universe, where distant galaxies are moving away from us at increasing speeds, indicating the expansion of space on a cosmic scale.
If I lived on a dot on the surface of an expanding balloon and observed the following:
a. A dot at a distance of 5 centimeters from me is moving away at a speed of 1 centimeter per hour (1 cm/hr).
b. A dot at a distance of 10 centimeters from me is moving away at a
speed of 2 centimeters per hour (2 cm/hr).
c. A dot at a distance of 15 centimeters from me is moving away at a speed of 3 centimeters per hour (3 cm/hr).
This observation suggests that the dots on the balloon's surface are undergoing a phenomenon known as cosmological expansion. In cosmology, this expansion refers to the stretching of space itself, which causes objects to move away from each other.
In this case, the dots on the balloon's surface represent distant objects in the universe, and the increasing distances between the dots indicate that the space between them is expanding. The increasing speeds at greater distances imply that the expansion is accelerating, which aligns with the observations of an expanding universe.
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Which statement accurately describes the atmospheres of the inner planets?
Mars has no atmosphere.
Mercury has a thick atmosphere.
Mars and Venus have similar atmospheres.
Earth and Venus have similar atmospheres.
Answers
Answer:
The option your looking for is C- Mars and Venus have similar atmospheres
Answer:
C: Mars and Venus have similar atmospheres.
A resume is usually read for less than ____ seconds by an employer.
a. 10
b. 20
c. 30.
d. 40
Answers
A resume is usually read for less than C. 30 seconds by an employer.
A resume is a document that presents your educational qualifications, experiences, and achievements that have taken place throughout your academic career and professional life. This document is crucial in a job application process, and it plays a key role in determining whether an employer is interested in interviewing you or not. Thus, it is necessary to write a well-written and a concise resume that catches the employer's attention in less than 30 seconds. This is because most employers go through many job applications and they do not have much time to read every resume thoroughly.
Therefore, it is essential to organize and format the resume in such a way that the key information and skills stand out. In addition, it is necessary to customize the resume to fit the job requirements of each job application, this can be done by researching the company and the job position to determine what skills and qualifications the employer is looking for. In conclusion, it is crucial to ensure that the resume is well-written, organized, and customized to fit the employer's requirements. So the correct answer is C. 30.
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Martin mixed sulfur (a yellow solid) with iron filings (a black solid) in a ceramic dish called a crucible. Then he separated them using a magnet. What kind of a change is this?
A.
change in state
B.
mixing and separation
C.
replacement
D.
synthesi
Answers
The kind of change that occurred when Martin mixed sulfur and iron filings in a crucible and then separated them using a magnet is option B, "mixing and separation."
Mixing and separation involve physical changes rather than chemical changes. Let's break down the steps involved to understand the nature of the change:Martin mixed sulfur (a yellow solid) with iron filings (a black solid) in a crucible.This step represents the physical process of combining two substances together. It does not involve any chemical reactions or the formation of new substances.Martin separated the mixture using a magnet.By using a magnet, Martin was able to selectively attract and separate the iron filings from the mixture. This separation process is also a physical change, as it does not alter the chemical composition of the sulfur or iron filings.Based on these steps, it is evident that the change involved in mixing sulfur and iron filings in a crucible and then separating them using a magnet is a physical change known as "mixing and separation." The original substances (sulfur and iron filings) remain chemically unchanged throughout the process.It is important to note that if a chemical reaction occurred between the sulfur and iron filings, resulting in the formation of a new substance, the change would be classified as a chemical change, such as synthesis or replacement. However, in this case, there is no evidence of a chemical reaction taking place, making the change a physical one.For more such questions on sulfur and iron filings, click on:
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Which is an electronic tool that can be used to improve science?
Answers
Answer:
Telescope, Probware, etc,..
Answer: probeware
Explanation:
the answer is probeware
if you mean by the options,
A. a ruler
B. a thermometer
C. a beaker
D. probeware
Please do it to me thank alot
Answers
Answer:
See explanations below
Explanation:
For resistors in series, the will be added for those in parallel, we will take the sum of their reciprocal
A) 3 2ohms resistors in series
Equivalent resistance = 2 + 2 + 2
Equivalent resistance = 6ohms
B) 2 4 ohms resisstors in parallal
1/R = 1/4 + 1/4
1/R = 2/4
R = 4/2
R = 4ohms
Equivalent resistance is 2ohms
C) 4 ohms with in series with 8ohms = 4 + 8
Equivalent resistance = 4 + 8
Equivalent resistance = 12ohms
D) 4 ohms and 2 ohms in parallel is expressed as;
1/R = 1/4 + 1/2
1/R = 1+2/4
1/R = 3/4
R = 4/3
4/3 ohms in series with 6ohms
Equivalent resistance = 4/3 + 6
Equivalent resistance =4+18/3
Equivalent resistance = 22/3 ohms
Select the correct location on the image.
The red arrow shows the direction that wind from the South Pole would travel if Earth were not spinning. The wind’s destination is at point A. Because Earth is spinning in the direction shown by the blue arrow, the Coriolis effect will cause the wind to terminate closest to which point?
Answers
The graphic shows that whereas southern winds would be redirected to the right, northern wind will be redirected to the left.
How would the Coriolis effect change if the Earth's rotation ceased?The Earth wouldn't appear much like it currently does if it ceased rotating on its axis.The absence of the Coriolis Effect would prevent the spiraling of winds, the enlargement of the equatorial area, and the oceanification of the continents.
Why are the arrows pointing in the different directions for each hemisphere's wind direction?The Coriolis effect is what appears to be a deflection.Fluids that move over wide areas, like air currents, are comparable to the trajectory of a ball.The Northern Hemisphere gives them the appearance of bending to the right.In the Southern Horizon, where currents seem to bend to a left, the Coriolis force behaves in the opposite direction.
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an electron moving in a uniform magnetic field experiences the maximum magnetic force when the angle between the direction of the electron's motion and the direction of the magnetic field is A) 0 B) 45°C ) 90° D) 180°
Answers
An electron moving in a uniform magnetic field experiences the maximum magnetic force when the angle between the direction of the electron's motion and the direction of the magnetic field is 90°. So, option C) is correct.
The correct answer is C) 90°. This is because the magnetic force on a charged particle, say, an electron, moving in a magnetic field is given by F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
When θ = 90°, sinθ = 1, and therefore the magnetic force is at its maximum value. When θ = 0° or 180°, sinθ = 0, and the magnetic force is zero.
When θ = 45°, sinθ is less than 1, so the magnetic force is less than its maximum value.
The magnetic force acting on a moving charged particle is given by F = q(v × B), where F is the magnetic force, q is the charge of the particle, v is its velocity, and B is the magnetic field.
The cross product (v × B) in the formula implies that the magnetic force is at its maximum when the angle between the velocity and the magnetic field is 90 degrees.
So, option C) is correct.
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A flat-bottom river barge is 14.0 m long, 9.0 m wide, and 4.0 m deep.
(a) How many m3 of water will it displace while the top stays 2.00 m above the water? Vdisp = m3.
(b) What load in Newtons will the barge contain under these conditions if the empty barge weighs 132710 Newtons in dry dock? Weightload = Newtons
Answers
The barge will Motion 252 m³ of water while maintaining a 2.00 m top height above the water.
What precisely are Newton's Laws of Motion?An object in motion maintains a straight course and a steady speed until it is affected by an unbalanced force. An object at rest maintains its state of rest. The mass of an item and the force acting on it define the acceleration of that thing.
The barge's displacement of water is proportional to its volume below the waterline.
The following formula may be used to determine the barge's volume:
Volume of barge = length × width × depth
Volume of barge = 14.0 m × 9.0 m × 4.0 m
Volume of barge = 504 m³
The top section of the barge is 2.00 m deep, so its volume can be calculated as follows:
Volume of top section = length × width × depth
Volume of top section = 14.0 m × 9.0 m × 2.0 m
Volume of top section = 252 m³
Now, the barge's displacement of water may be computed as follows:
Volume of water displaced = Volume of barge - Volume of top section
Volume of water displaced = 504 m³ - 252 m³
Volume of water displaced = 252 m³.
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At what cold-reservoir temperature C would a Carnot engine with a hot-reservoir temperature of 360 C have an efficiency of 70%?
Answers
The cold-reservoir temperature (C) at which a Carnot engine with a hot-reservoir temperature of 360°C has an efficiency of 70% is 108°C.
To find the cold-reservoir temperature (C) at which a Carnot engine with a hot-reservoir temperature of 360°C has an efficiency of 70%, we can use the Carnot efficiency formula: Efficiency = 1 - (Tc/Th)
Where Tc is the cold-reservoir temperature and Th is the hot-reservoir temperature.
Given:
Hot-reservoir temperature (Th) = 360°C
Efficiency = 70% = 0.70
To find the cold-reservoir temperature (Tc), we rearrange the equation:
0.70 = 1 - (Tc/360)
Solving for Tc: Tc/360 = 1 - 0.70
Tc/360 = 0.30
Tc = 0.30 × 360
Tc = 108°C
Therefore, the cold-reservoir temperature (C) at which a Carnot engine with a hot-reservoir temperature of 360°C has an efficiency of 70% is 108°C.
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propane vapor is expanded adiabatic ally with a volume change of 0.275 ft 3 and final temperature of 85 0°r. what is the amount of heat transfer for this process?
Answers
Propane vapor is expanded adiabatically with a volume of V4 = 10.0 m³ , which corresponds to the quantity of heat transfer for this procedure.
The gas first begins to grow adiabatically from state 1 to state 2, where V2 is 7.1 m3, then continues on to state 3 isothermally, where V3 is 23 m3, before being compressed adiabatically to reach state 4.
P1V'1 = P2V'2 for the adiabatic process in stages 1 to 2
We know that P2V2 = P3V3 for the stage 2 to stage 3 isothermal process.
We know that P3V'3 = P4V'4 for the stage 3 to stage 4 adiabatic process.
Beginning with the conclusion, we can deduce that P4 = P3 * (V3/V4).
Reversing the equation, we find that P4 = P2 * (V2/V3) * (V3/V4).
Backtracking even further, we find that P4 = P1 * (V1/V2)' * (V2/V3) * (V3/V4)'
P4 = P1*(V1/V2)*(V2/V3)*(V3/V4)'
We obtain V1V3 = V2V4 by substituting expression heat transfer for P4 into the equation P1V1 = P4V4 with T being a constant.
V4 = V1V3/V2
V4 = (0.275* 3) / 85
V4 = 85 / 10
V4 = 10.0 m³
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Which objects would sink in honey, which has a density of 1.4 g/cm³? Check all that apply.
Answers
Answer:
any object that has density more than 1.4
Explanation:
The object that has density more than 1.4 is denser than the honey
The beat frequency produced when a 240-hertz tuning fork and a 246-hertz tuning fork are sounded together is
Answers
The beat frequency produced when a 240-hertz tuning fork and a 246-hertz tuning fork are sounded together is 6 Hz.
The beat frequency produced when a 240-hertz tuning fork and a 246-hertz tuning fork are sounded together can be calculated using the formula f_beat = |f_1 - f_2|, where f_1 and f_2 are the frequencies of the tuning forks. In this case, we have f_1 = 240 Hz and f_2 = 246 Hz.
Substituting these values into the formula, we get f_beat = |240 Hz - 246 Hz| = 6 Hz. Therefore, the beat frequency produced when a 240-hertz tuning fork and a 246-hertz tuning fork are sounded together is 6 Hz.
Beat frequencies are created when two sound waves of slightly different frequencies interfere with each other. This interference causes the amplitude of the resulting wave to oscillate at a frequency equal to the difference between the two original frequencies. In the case of tuning forks, the beat frequency can be heard as a fluctuation in the volume of the sound.
The beat frequency produced when a 240-hertz tuning fork and a 246-hertz tuning fork are sounded together is 6 Hz.
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A 2500kg automobile develops 30kW of power to drive with a constant velocity of 90km/h on a level ground. What power must it develop to drive up a 15 degree hill with the same velocity.
Answers
Answer:
the power developed by the automobile is 7,764.57 W.
Explanation:
Given;
mass of the automobile, m = 2500 kg
initial power developed by the automobile, P₁ = 30 kW = 30,000 W
initial speed of the automobile, v₁ = 90 km/h = 25 m/s
inclination of the hill, θ = 15⁰
second speed of the automobile, v₂ = v₁Sinθ
The power developed by the automobile is calculated as;
P = Fv
\(F = \frac{P_1}{V_1} = \frac{P_2}{V_2} \\\\P_2 = \frac{P_1V_2}{V_1} \\\\P_2 = \frac{30,000 \ W \ \times 25Sin(15^0)}{25} \\\\P_2 = 30,000 \ \times sin(15^0)\\\\P_2 = 7,764.57 \ W\\\\\)
Therefore, the power developed by the automobile is 7,764.57 W.
if space has a hyperbolic geometry, what will happen to two initially parallel flashlight beams as they traverse billions of light-years of space?
Answers
In a space with hyperbolic geometry, the behavior of parallel lines differs from that of Euclidean geometry.
In hyperbolic space, parallel lines diverge from each other as they extend further.If two initially parallel flashlight beams traverse billions of light-years of space in a hyperbolic geometry, they will gradually diverge from each other. The divergence between the beams will increase as they travel a greater distance.
This phenomenon is a consequence of the non-Euclidean geometry of space. In hyperbolic space, the curvature causes parallel lines to "spread out" or diverge. The extent of the divergence will depend on the specific curvature of the space and the distance traveled.
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According to Newton's 2nd law of motion, if you hit a baseball with a bat it will
-hurt your hand from the reaction force
-accelerate according to the applied force
-fly in a straight line unless an outside force changes its course
-fall to the ground because of gravitational pull
Answers
Answer:
Newton's second law states that force is directly proportional to the product of mass and acceleration.
so if you hit a baseball with a bat it will accelerate according to the applied force.
About how long does it take earth to make a make 1 revolution around the sun a a day be a week see a month d a year
Answers
A block has an initial speed of 7. 0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal
Answers
A block has an initial speed of 7. 0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal. The block's speed after it has traveled 2.0 m up the inclined plane (ignoring friction) is approximately 8.52 m/s.
To determine the block's speed after it has traveled 2.0 m up an inclined plane, we can use the principles of linear motion.
Given:
Initial speed (v₀) = 7.0 m/s (upward)
Distance traveled (d) = 2.0 m
Angle of the inclined plane (θ) = 37°
We need to determine the final speed (v) of the block.
Using the equation of motion:
v² = v₀² + 2ad
Where:
v is the final speed
v₀ is the initial speed
a is the acceleration
d is the distance traveled
Since the inclined plane is frictionless, the only force acting on the block along the incline is its weight component parallel to the incline. This force can be calculated as:
F = mg * sin(θ)
The acceleration along the incline can be obtained using Newton's second law:
F = ma
Rearranging the equation, we have:
a = F/m
Substituting the expression for F:
a = (mg * sin(θ))/m
Simplifying:
a = g * sin(θ)
Substituting the known values:
θ = 37°
g = 9.8 m/s² (acceleration due to gravity)
a = 9.8 m/s² * sin(37°)
Calculating the value of a:
a =5.9 m/s²
Now, substituting the values of v₀, a, and d into the equation of motion:
v² = v₀² + 2ad
v² = (7.0 m/s)² + 2 * (5.9 m/s²) * (2.0 m)
Calculating the value of v:
v² = 49.0 m²/s² + 23.6 m²/s²
v² = 72.6 m²/s²
Taking the square root of both sides:
v = √(72.6 m²/s²)
v = 8.52 m/s
Therefore, the block's speed after it has traveled 2.0 m up the inclined plane (ignoring friction) is approximately 8.52 m/s.
The given question is incomplete and the complete question is '' A block has an initial speed of 7.0 m/s up an inclined plane that makes an angle of 37 ∘ with the horizontal. Ignoring friction, what is the block's speed after it has traveled 2.0 m? ''.
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Is alpha an particle?
Answers
A car with a velocity of 22.4 m/s accelerates at a rate of 3.7 m/s2 for 15
seconds. What is the car's displacement during this time period?
A 199.1 m
B 563.4 m
C 752.3 m
D 433.9 m
Answers
The displacement of the car during the time period when moving with a velocity of 22.4 m/s is 752.25 m.
What is displacement?Displacement can be defined as distance in a specified direction.
To calculate the displacement during the time period, we use the formula below.
Formula:
s = ut+at²/2........... Equation 1Where:
s = Displacementu = Initial velocitya = Acceleration t = Time.From the question,
Given:
u = 22.4 m/sa = 3.7 m/s²t = 15 secondsSubstitute these values into equation 1
s = (22.4×15)+(3.7×15²)/2s = 336+416.25s = 752.25 mHence, the displacement of the car is 752.25 m.
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Write an algorithm that calculate the time a train need to arrive at a detination given peed and ditance
Answers
An algorithm that calculates the time a train needs to arrive at a destination given speed and distance \(Time=\frac{Distance}{Speed}\).
What is Speed?The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.
The maximum speed that can be maintained when a period grows closer to zero is the starting speed.
By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period is calculated. Speed and velocity are not always the same thing.
The algorithm to calculate the time required will be,
Let the distance covered by the train is D and the speed of the train be S.
Then, the time taken by the train will be,
T = D/S
Here, D is the distance and S is the speed.
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Jared lifts a 35.0 kg of box from the floor to a table that is 1.75 meters above the floor. How much gravitational potential energy does the box gain?
Answers
Given,
The mass of the box, m=35.0 kg
The height to which the box was lifted, h=1.75 m
Potential energy is the energy possessed by an object due to its position.
The gravitational potential energy gained by the box is,
\(E=\text{mgh}\)Where g is the acceleration due to gravity.
On substituting the known values,
\(\begin{gathered} E=35.0\times9.8\times1.75 \\ =600.25\text{ J} \end{gathered}\)Thus the gravitational potential energy gained by the box is 600.25 J
For the PE formula, why is the height required for calculations? Why do we need to know the height in order to determine PE? *
Answers
Answer:
Answer in Explanation
Explanation:
Whenever we talk about the gravitational potential energy, it means the energy stored in a body due to its position in the gravitational field. Now, we know that in the gravitational field the work is only done when the body moves vertically. If the body moves horizontally on the same surface in the Earth's Gravitational Field, then the work done on the body is considered to be zero. Hence, the work done or the energy stored in the object while in the gravitational field is only possible if it moves vertically. This vertical distance is referred to as height. This is the main reason why we require height in the P.E formula and calculations.
The derivation of this formula is as follows:
Work = Force * Displacement
For gravitational potential energy:
Work = P.E
Force = Weight = mg
Displacement = Vertical Displacement = Height = h
Therefore,
P.E = mgh
Urgent solve please book is introduction to nuclear
Physics by Kenneth s krane chapter 8 problem 1
PROBLEMS Find the (a) 247 Bk 243 Am + a; (b) 25¹ Cf → 2. For each decay given in Problem 1, calculate the kinetic energy and velocity 1. values of the following decays: 247 Cm + a; (c) 230 Th 226 R
Answers
The decay of 247 Bk to 243 Am by emitting an alpha particle results (a) in the formation of 243 Am. (b) results in the formation of 247 Cm. (c) Does not involve emission of any particles, so the resulting nucleus is 226 Ra.
(a) In the decay of 247 Bk to 243 Am, an alpha particle (consisting of two protons and two neutrons) is emitted. To calculate the kinetic energy and velocity, we need to know the masses of the particles involved. The kinetic energy can be determined using the equation: KE = (1/2)mv², where m is the mass and v is the velocity.
The velocity can be found using the relationship between kinetic energy and momentum, KE = p² / (2m), where p is the momentum. By knowing the masses of the alpha particle, 247 Bk, and 243 Am, we can calculate the kinetic energy and velocity.
(b) Similar to the previous case, the decay of 251 Cf to 247 Cm involves the emission of an alpha particle. By considering the masses of the alpha particle, 251 Cf, and 247 Cm, we can calculate the kinetic energy and velocity.
(c) The decay of 230 Th to 226 Ra does not involve any particle emission. Therefore, there is no kinetic energy or velocity associated with this decay process. It is simply a nuclear transformation where the nucleus of the atom changes from 230 Th to 226 Ra.
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The decay of 247 Bk to 243 Am by emitting an alpha particle results (a) in the formation of 243 Am. (b) results in the formation of 247 Cm. (c) Does not involve emission of any particles, so the resulting nucleus is 226 Ra.
(a) In the decay of 247 Bk to 243 Am, an alpha particle (consisting of two protons and two neutrons) is emitted. To calculate the kinetic energy and velocity, we need to know the masses of the particles involved. The kinetic energy can be determined using the equation: KE = (1/2)mv², where m is the mass and v is the velocity.
The velocity can be found using the relationship between kinetic energy and momentum, KE = p² / (2m), where p is the momentum. By knowing the masses of the alpha particle, 247 Bk, and 243 Am, we can calculate the kinetic energy and velocity.
(b) Similar to the previous case, the decay of 251 Cf to 247 Cm involves the emission of an alpha particle. By considering the masses of the alpha particle, 251 Cf, and 247 Cm, we can calculate the kinetic energy and velocity.
(c) The decay of 230 Th to 226 Ra does not involve any particle emission. Therefore, there is no kinetic energy or velocity associated with this decay process. It is simply a nuclear transformation where the nucleus of the atom changes from 230 Th to 226 Ra.
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