During elongation in the ribosome, the amino end of the amino acid at the P-site is connected to the carboxyl end of the amino acid attached to the tRNA at the A-site.
During protein synthesis, elongation is the stage where the polypeptide chain is formed. This process occurs at the ribosome, where the mRNA is translated into a protein sequence. During elongation, the ribosome reads the codons of the mRNA and matches them with complementary anticodons on the tRNA. The tRNA carries an amino acid that is added to the growing polypeptide chain.
At any given time during elongation, there are two tRNAs present at the ribosome: one carrying the amino acid at the A-site, and the other carrying the nascent polypeptide chain at the P-site. The amino acid at the A-site is then transferred to the end of the polypeptide chain at the P-site via peptide bond formation, and the ribosome moves to the next codon in the mRNA, creating a new A-site for the next incoming tRNA.
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During elongation in the ribosome, the amino end of the amino acid at the P-site is connected to the carboxyl end of the amino acid attached to the tRNA at the A-site.
What happens during Ribosome Elongation?The ribosome is a complex molecular machine responsible for protein synthesis. During elongation, the ribosome reads the mRNA (messenger RNA) and synthesizes a polypeptide chain by adding amino acids one by one to the growing chain. The connection between the amino end of the amino acid at the A-site of tRNA and the carboxyl end of the amino acid attached to the tRNA at the P-site during ribosome elongation is facilitated by the ribosome's peptidyl transferase activity, which is an enzyme found in the large ribosomal subunit.
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what is the weight of 5.3 x 1024 molecules of C6H₁₂O6?
The weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ is 9.5294 x 10²⁶ g
To calculate the weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ (glucose), we need to determine the molecular weight of glucose and then multiply it by the given number of molecules.
The molecular formula of glucose (C₆H₁₂O₆ ) indicates that it consists of 6 carbon (C) atoms, 12 hydrogens (H) atoms, and 6 oxygen (O) atoms.
Using the atomic weights of carbon (12.01 g/mol), hydrogen (1.01 g/mol), and oxygen (16.00 g/mol), we can calculate the molecular weight of glucose:
To find the molecular weight of glucose, we add up the atomic weights of all the constituent atoms:
(6 x atomic weight of carbon) + (12 x atomic weight of hydrogen) + (6 x atomic weight of oxygen)
(6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol
The molecular weight of glucose (C₆H₁₂O₆ ) is 180.18 g/mol.
To find the weight of 5.3 x 10²⁴ molecules of glucose, we can use the following equation:
Weight = Number of molecules x Molecular weight
Weight = (5.3 x 10²⁴ molecules) x (180.18 g/mol)
Calculating this expression:
Weight = 9.5294 x 10²⁶ g
Therefore, the weight of 5.3 x 10²⁴ molecules of C₆H₁₂O₆ (glucose) is approximately 9.5294 x 10²⁶ grams.
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We must first determine the molar mass of the compound to convert it to grams, which we use to calculate the molecular weight.
It is possible to determine the molar mass of \(C_6H_1_2O_6\) (glucose), by adding the atomic masses of its constituent parts:
C: 6 atoms x atomic mass of carbon (12.01 g/mol) = 72.06 g/mol
H: 12 atoms x atomic mass of hydrogen (1.01 g/mol) = 12.12 g/mol
O: 6 atoms x atomic mass of oxygen (16.00 g/mol) = 96.00 g/mol
Total molar mass of \(C_6H_1_2O_6\) = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol
Now we can find the weight of \(5.3 * 10^2^4\) C6H12O6 molecules using this molar mass:
(number of molecules) x (molar mass) = weight (in grams).
(5.3 x \(10^2^4\) molecules) x (180.18 g/mol) = weight
Weight = 9.00 x \(10^2^6\) grams
Therefore, the weight of 5.3 x \(10^2^4\) molecules of C6H12O6 is approximately 9.00 x\(10^2^6\) grams.
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Approximately how many elements are necessary to form all the solids, liquids and gases around us?
The number of elements necessary to form all the solids, liquids, and gases around us is approximately 90.
Elements are the building blocks of matter, and they cannot be broken down into simpler substances through chemical reactions. The periodic table is a chart that organizes all the known elements based on their atomic number, which represents the number of protons in the nucleus of an atom.
The periodic table currently consists of 118 elements, but not all of them are naturally occurring. Of these, around 90 elements are commonly found in nature and are responsible for the vast array of materials and substances we encounter every day.
Each element has its own unique properties, including its atomic structure and the way it interacts with other elements. These properties determine the characteristics of the substances formed when elements combine.
So, approximately 90 elements are necessary to form all the solids, liquids, and gases around us. It is important to note that this number may vary slightly depending on the specific context and the types of materials being considered.
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What is a plain?
A.A vast area of relatively flat land that has only small changes in elevation.
B.A type of land form where the land and sea overlap and directly interact.
C.The mouth of a river where it meets another body of water
D.An area of land that is a mound or ridge of sand.
Answer:
A. A vast area of relatively flat land that has only small changes in elevation
you find a piece of cloth painted with organic dye. by analyzing the dye, you find that only 71 % of the carbon-14 originally in the dye remains. when was the cloth painted? express your answer in years to two significant figures.
The cloth was painted with organic dye approximately 2,300 years ago ( rounded to two significant figures ).
To determine when the cloth was painted with organic dye, we can use the half-life of carbon-14 and the given information that 71% of the carbon-14 remains. The half-life of carbon-14 is 5,730 years.
Step 1: Calculate the decay factor.
Decay factor = remaining percentage / 100
Decay factor = 71% / 100 = 0.71
Step 2: Use the decay formula.
N(t) = N0 * (1/2)^(t / half-life)
0.71 = (1/2)^(t / 5730)
Step 3: Solve for t (time in years).
t / 5730 = log(0.71) / log(1/2)
t = 5730 * (log(0.71) / log(1/2))
t ≈ 2349.27 years
Expressing the answer to two significant figures, the cloth was painted approximately 2,300 years ago.
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Explain the ways that carbon dioxide is added to the atmosphere. How is it removed? Does most carbon enter the atmosphere as carbon dioxide or is it in another form? How do increased levels of carbon dioxide in the atmosphere affect the earth?
Answer:
Carbon dioxide is added to the atmosphere by human activities. When hydrocarbon fuels (i.e. wood, coal, natural gas, gasoline, and oil) are burned, carbon dioxide is released. During combustion or burning, carbon from fossil fuels combine with oxygen in the air to form carbon dioxide and water vapor.Carbon moves from fossil fuels to the atmosphere when fuels are burned. When humans burn fossil fuels to power factories, power plants, cars and trucks, most of the carbon quickly enters the atmosphere as carbon dioxide gas. Each year, five and a half billion tons of carbon is released by burning fossil fuels.Carbon dioxide causes about 20 percent of Earth's greenhouse effect; water vapor accounts for about 50 percent; and clouds account for 25 percent.Likewise, when carbon dioxide concentrations rise, air temperatures go up, and more water vapor evaporates into the atmosphere—which then amplifies greenhouse heating
A certain chemical reaction releases 25.7 kJ/g of heat for each gram of reactant consumed. How can you calculate the heat produced by the consumption of 3.4 kg of reactant? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
The heat produced by the consumption of 3.4kg of reactant if the chemical reaction releases 25.7kJ of heat for each gram of consumed reactant is 87,380KJ.
How to calculate heat consumed?According to this question, a certain chemical reaction releases 25.7 kJ/g of heat for each gram of reactant consumed.
However, when given 3.4kg of reactant, we need to convert this mass unit to grams by multiplying by 1000 as follows:
3.4kg × 1000 = 3400g
If the reaction releases 25.7 kJ/g of heat for each gram of reactant consumed, this means that for 3400g, the amount of heat energy that will be released is as follows:
3400g × 25.7Kj/g
= 87,380KJ
Therefore, the heat produced by the consumption of 3.4kg of reactant if the chemical reaction releases 25.7kJ of heat for each gram of consumed reactant is 87,380KJ.
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Which would you expect to increase the rate of photosynthesis?
As you rise from low light intensity to higher light intensity, the rate of photosynthesis will increase because there is more light available to drive the reactions of photosynthesis.
Which scenario best exemplifies the way a signal is passed down an axon coated with myelin sheath?
The scenario that best exemplifies the way a signal is passed down an axon coated with myelin sheath is saltatory conduction, where the signal jumps from one node of Ranvier to the next, allowing for faster transmission.
Saltatory conduction is the process by which a signal travels down an axon that is coated with a myelin sheath. The myelin sheath acts as an insulator, preventing the signal from dissipating and allowing it to travel faster and more efficiently. When the signal reaches a node of Ranvier, it depolarizes the membrane and triggers the opening of voltage-gated ion channels.
This causes the signal to quickly jump to the next node of Ranvier, bypassing the areas covered by the myelin sheath. This process continues along the length of the axon until the signal reaches the end. Saltatory conduction reduces the energy consumption of the neuron and speeds up signal transmission. It is particularly important for long axons, where it allows for rapid communication in the nervous system.
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Is the distribution of electrons in the sodium-chlorine bond and the carbon- chlorine bond the same? For each case, describe how the electrons that make up the bond are distributed between the two atoms.
The distribution of electrons is not the same in sodium-chlorine bonds and carbon-chlorine bonds (electronic configuration)
The electronic configuration of sodium chlorine
sodium atom is 2, 8, 1
chlorine atom is 2, 8, 7
Carbon chlorine
Carbon - 2,8,2
Chlorine - 2,8,7
Electronic Configuration refers to how the electrons are the distribution of electrons within an atom. The greatest number of electrons that can be found in an orbit can be calculated using the formula 2n2, where n is the orbit number. The formula also referred to as "Bohr Bury Schemes," aids in figuring out how electrons are arranged in the distribution of electrons.
In order to determine the distribution of electrons by the electrical configuration of cations, electrons are first removed from the outermost p orbital, then from the s orbital, and finally from the d orbitals (if any more electrons need to be removed)
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How many moles are there in 100g of helium
Explanation:
so for this one u need to remember this equation and use it to find out moles= mass /mr . Mr of helium is 4
so moles= mass /mr
=100/4
=25 moles
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describe the general trend in electronegativity as metals in group 2 on the periodic table are concidered in order of increasing atomic number
Answer:
Electronegativity decrease in group from top to bottom
Explanation:
A force of 20N acts on an object. It causes a displacement of 500 cm in the direction of force. What would be the work done in Nm on the object?
Answer:
500/100=5m
W=F*D
W=20*5=100Nm
Explanation:
The work done in Nm on the object is 100 Nm
Calculation of the work done:
Since A force of 20N acts on an object. It causes a displacement of 500 cm in the direction of the force.
Since the displacement is in cm
So, in meters, it should be like
= 500 / 100
= 5 m
Now we know that
Work done = force * displacement
= 20N * 5
= 100 Nm
hence, The work done in Nm on the object is 100 Nm
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with cobalt-60, the half-life is 5.27 years. assuming we started with 1000 g of isotope recovered in a sample, how much would remain after 6 half-lives?
After 6 half-lives, only 15.625 g of the initial 1000 g of cobalt-60 would remain in the sample.
The half-life of cobalt-60 is 5.27 years, which means that after every 5.27 years, half of the initial amount of the isotope would decay. So after 1 half-life, we would have 500 g remaining. After 2 half-lives, we would have 250 g remaining, after 3 half-lives we would have 125 g remaining, after 4 half-lives we would have 62.5 g remaining, and after 5 half-lives we would have 31.25 g remaining.
Now, we need to calculate how much would remain after 6 half-lives. So after 5 half-lives, we had 31.25 g remaining. After another half-life, we would have half of 31.25 g, which is 15.625 g remaining.
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how wide is the typical melting point range for a pure compound?
The typical melting point range for a pure compound can vary depending on the specific compound and its purity. However, in general, the melting point range for a pure compound is relatively narrow. It is typically within a few degrees Celsius or even less.
The melting point of a compound is a characteristic physical property that reflects the temperature at which a solid substance changes into a liquid state. The melting point range is defined as the temperature range over which the compound transitions from a solid to a liquid. It is influenced by factors such as the strength of intermolecular forces, molecular structure, and purity of the compound.
Impurities or variations in the compound's composition can widen the melting point range. A pure compound will have a more precise and narrow melting point range compared to a sample containing impurities or mixtures of compounds. The presence of impurities can introduce additional phases or alter the melting behavior, resulting in a broader range of temperatures over which the compound transitions from solid to liquid.
In summary, the typical melting point range for a pure compound is relatively narrow, usually within a few degrees Celsius, but the presence of impurities can widen the range.
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how many moles of copper are equivalent to 3.44x10^23 atoms of copper?
Answer:
0.571moles
Explanation:
The Avogrado's number or constant denoted by NA will be used for this question.
The Avogrado's number = 6.022 × 10^23 particles, is contained in 1 mole of a substance.
To get the number of atom/particles in a substance, the formula: N= n × NA is used.
Where; N= Number of atoms in
substance
n= number of moles
NA= Avogadro's constant
Hence, to find the number of moles of copper equivalent to 3.44 × 10^23, we say: n= N / NA
That is, n = 3.44 × 10^23 / 6.022 × 10^23
= 0.5712
Therefore, 0.571 moles of Copper (Cu) is equivalent to 3.44 × 10^23 atoms of Copper.
Calculate the reaction energy Q for the reaction p + H2H+H. Express your answer in megaelectron volts. IVO AED t ? Q 11 MeV
The reaction energy Q for the reaction p + H2H+H is calculated to be 2.22 MeV.
The reaction energy Q for the reaction p + H2H+H is calculated to be 2.22 MeV.What is the reaction energy Q?The reaction energy Q is the energy released or absorbed during a nuclear reaction. The equation for calculating reaction energy Q is given below:Q = (m1 + m2 - m3 - m4) c^2where m1 and m2 are the masses of the initial particles, m3 and m4 are the masses of the final particles, and c is the speed of light.The masses of protons and hydrogen atoms are given below:mp = 1.00728 u (1 u = 1.6605 × 10^-27 kg)mH = 1.00783 uUsing these values, the masses of the particles involved in the reaction can be calculated as follows:Initial particles:mp + 2mH = 1.00728 u + 2 × 1.00783 u = 3.02394 uFinal particles:2mH = 2 × 1.00783 u = 2.01566 uSubstituting these values in the equation for reaction energy Q, we get:Q = (m1 + m2 - m3 - m4) c^2= (mp + 2mH - 2mH - mp) c^2= 2mp c^2= 2 × 1.00728 u × (1.6605 × 10^-27 kg/u) × (2.998 × 10^8 m/s)^2= 2.22 MeV (1 MeV = 1.6 × 10^-13 J).
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How does the valence electron configuration (entire last energy level configuration) relate to the group number on the Periodic Table? Use the shorthand notation in your discussion.
Answer:
The valence electron configuration determines the group to which an element belongs to.
Explanation:
The valence electron configuration of an atom of an element refers to the number of electrons in that atoms outermost shell.
The valence electron configuration is related to the group number of an element in that the number of electrons in the valence shell of an atom of an element determines the group to which an element belongs to. For example, all elements having one valence electron belong to group IA of the periodic table. Similarly, all elements having seven valence electrons belong to group VIIA of the periodic table.
This is because, since the reactivity of an element is related to its ability to either gain or lose a certain number of electrons in its valence shell, elements having same number of valence electrons have similar chemical properties.
If you write the balanced reaction for the neutralization of sodium hydroxide and hydrochloric acid, you will see that the reaction proceeds in a 2:1 fashion True or False
False. The neutralization reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) proceeds in a 1:1 fashion.
The balanced equation for this reaction is:
NaOH + HCl → NaCl + H2O
In this equation, one molecule of sodium hydroxide (NaOH) reacts with one molecule of hydrochloric acid (HCl) to form one molecule of sodium chloride (NaCl) and one molecule of water (H2O). The stoichiometric coefficients in the balanced equation represent the relative numbers of moles involved in the reaction.
Therefore, the reaction proceeds in a 1:1 fashion, where one mole of NaOH reacts with one mole of HCl.
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The Law of Conservation of Energy states that energy cannot be created or destroyed. It can only change forms.
True
or
False
Answer:
True
Explanation:
The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system remains constant or is conserved within a given frame of reference.
Brainliest?
Matter and your body-how are they
interrelated?
Answer:
Matter has mass and takes up space, everything has matte, your body takes up space. Matter refuels the body. You can also so your body produces matter as well
nh4no3, whose heat of solution is 25.7kj/mol, is one substance that can be used in cold pack. if the goal is to decrease the temperature from 25.0 c to 5.0 c, how many grams of nh4no3 should we use for every 100.0 g of water in the cold pack? assume no heat was lost outside of cold pack, and the specific heat of the resulted solution was the same as water
Mass of NH4NO3 use for every 100 g of water is 32.56g.
Calculation:-
m = 100.0 g
dT = 50 -25 = 25 oC
Cp = 4.184 J / oc g
Q = m Cp dT
Q = 100 x 4.184 x 25
Q = 10460 J
Q = 10.46 kJ
delta H = Q / n
25.7 = 10.46 / n
n = 10.46 /25.7
n = 0.407
moles of NH4NO3 = 0.407
mass of NH4NO3 = moles x molar mass
= 0.407 x 80
= 32.56 g
mass of NH4NO3 needed = 32.56 g
If you are using an already-used instant cold pack strain the liquid and evaporate until dry. The crystals are ammonium nitrate. Dissolve 80 grams of ammonium nitrate in 70 milliliters of hot water. This will take some time, so please be patient. Adding ammonium nitrate to water cools the mixture, a good example of an endothermic chemical reaction. An endothermic reaction occurs at the moment the substances come into contact with each other.
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Based on the article "Will the real atomic model please stand up?,” describe what Dalton’s theory states about a molecule of water.
Answer:
According to the Dalton's theory, the description of water molecule is that;
-Water molecules are made of two different kinds of atoms (hydrogen and oxygen atoms).
-All water molecules have twice as many hydrogen atoms as oxygen atoms.
-All water molecules have one oxygen atom for every two hydrogen atoms.
Explanation:
got a 100% on edge
Which species do you think is most vulnerable to overexploitation?
A. Red ferns
B. Lions
C. Tuna
D. Potatoes
The most vulnerable species to overexploitation among the given options is option c Tuna.
Overexploitation is the act of exploiting natural resources faster and more than they can be replenished. The process leads to the depletion of the natural resources, and the species becomes vulnerable to extinction.Explanation:Tuna is the species that is most vulnerable to overexploitation among the given options. Tuna is one of the most valuable fish globally and is among the most consumed fish species.
As a result, the tuna population has decreased rapidly due to overfishing.Overfishing is the main reason behind the depletion of tuna populations in many parts of the world. Moreover, tuna is among the species that are on the verge of extinction. Therefore, overexploitation can lead to a drastic decline in the population of tuna and, as a result, making the species vulnerable to overexploitation.The correct answer is c.
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HURRY PLS IT'S TIMED
When discussing Newton's law's of motion which terms do people most likely use when talking about Newton's third law of motion.
Answer:
Action and Reaction.
Explanation:
Newton has given three laws. When discussing Newton's laws of motion, the most likely used terms when talking about Newton's third law of motion are action and reaction. According to this law, for every action there is an equal and opposite reaction.
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
Explanation:
Current is applied to an aqueous solution of sodium sulfide. What is produced at the cathode? What is produced at the anode? 02(g) Hz(g) H2(g) S(s) Na(s) Na(s) S(s) Q2(g)The voltage generated by the zinc concentration cell described by. Zn(s)|Zn^2+(aq,0.100 M)|| Zn^2+ (aq,? M)|Zn(s) is 13.0 mV at 25 Degree C. Calculate the concentration of the Zn^2+(aq) ion at the cathode.
Therefore, the concentration of \(Zn^2+\)(aq) ion at the cathode is 0.050 M.
When a current is applied to an aqueous solution of sodium sulfide, hydrogen gas (\(H_2\)) will be produced at the cathode, while sodium metal (Na) and sulfur (S) will be produced at the anode. The half-reactions occurring are:
Cathode: 2H+(aq) + 2e- → (\(H_2\)(g)
Anode: 2OH-(aq) → \(1/2O_2(g) + H_2O(l)\) + 2e- ; \(2S_2-(aq) + 2H_2O\)(l) → \(SO_4^2-\)(aq) + 4H+(aq) + 2e- ; 4OH-(aq) → O2(g) +\(2H_2O\)(l) + 4e-
The voltage generated by the zinc concentration cell described by Zn(s)|\(Zn^2+(aq,0.100 M)|| Zn^2+\)(aq,? M)|Zn(s) is 13.0 mV at 25°C. Using the Nernst equation, we can calculate the concentration of \(Zn^2+\)(aq) ion at the cathode:
Ecell = E°cell - (RT/nF)lnQ
where E°cell = 0.00 V, R = 8.314 J/(mol*K), T = 298 K, n = 2, F = 96485 C/mol, Q =\([Zn^2+(aq,0.100 M)]/[Zn^2+(aq, M)]\)
Solving for \([Zn^2+(aq,? M)], we get [Zn^2+(aq, M)]\) = 0.050 M.
So. Therefore, the concentration of \(Zn^2+\)(aq) ion at the cathode is 0.050 M.
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Tin metal can be prepared by electrolysis of its aqueous saltsCobalt metal can be prepared by electrolysis of its aqueous saltsCadmium metal can be prepared by electrolysis of its aqueous saltsHydrogen can be prepared by suitable electrolysis of aqueous magnesium saltsHydrogen CANNOT be prepared by suitable electrolysis of aqueous zinc saltsHydrogen can be prepared by suitable electrolysis of aqueous aluminum saltsHydrogen CANNOT be prepared by suitable electrolysis of aqueous silver saltsBarium metal CANNOT be prepared by electrolysis of its aqueous saltsLead metal can be prepared by electrolysis of its aqueous saltsNitrogen CANNOT be prepared by electrolysis of an aqueous nitrate solutionOxygen can be prepared by suitable electrolysis of aqueous perchlorate saltsOxygen can be prepared by suitable electrolysis of aqueous nitrate saltsOxygen can be prepared by suitable electrolysis of aqueous oxide salts
Tin, cobalt, and cadmium metals can be prepared by electrolysis of their aqueous salts, while barium metal cannot be prepared by electrolysis of its aqueous salts.
Tin, cobalt, and cadmium can be prepared by electrolysis of their aqueous salts, hydrogen can be prepared by suitable electrolysis of aqueous magnesium and aluminum salts, but not by electrolysis of aqueous zinc and silver salts, barium metal cannot be prepared by electrolysis of its aqueous salts, lead metal can be prepared by electrolysis of its aqueous salts, nitrogen cannot be prepared by electrolysis of an aqueous nitrate solution, and oxygen can be prepared by suitable electrolysis of aqueous perchlorate, nitrate, and oxide salts.
Electrolysis is a process that uses an electric current to drive a chemical reaction. The electrolysis of aqueous salts of certain metals can produce those metals in their elemental form. However, not all aqueous salts can be electrolyzed to produce their corresponding metals. Similarly, electrolysis can be used to produce hydrogen and oxygen from certain aqueous salts, but not all of them. The ability to electrolyze certain compounds depends on their chemical properties and the conditions under which the electrolysis is performed.
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• What will happen if there were no cilia in the respiratory tract? <||:>
Explanation:
Damaged cilia can't do their job of sweeping dirt and mucus out of your lungs. With bronchiectasis, your airways widen and stretch out. In some places, the airways are so stretched out they form little pockets. Germs, dust and mucus collect in these pockets and get stuck.
How did mitochondria
become part of the cell?
Answer: The mitochondria, as bacteria, only wanted to rob the host cells of their energy and then leave them to die. But the bacteria soon realized the benefit of working together with simple cells. The simple cells provide them with antioxidants to protect them from free radicals and toxic reactive oxygen species that the mitochondria generate as a byproduct of energy production.
Hope dis helps!
:)
Neutral atoms of all isotopes of a given element have the same
A) number of protons and neutrons
B) number of neutrons
C) number of electrons
D) mass numbers
E) masses
Neutral atoms of all isotopes of a given element have the same number of protons and neutrons.
All the isotopes of the same element consists of the same number of protons, which defines the element.
Depending on the neutron count, different isotopes can exist . This is because electrons are negatively charged and they can counterbalance the positive charge of protons. Also, they are present in equal numbers in neutral atoms of the same element.
Mass number is formed from the addition of protons and neutrons, which varies between isotopes. An isotope's mass can differ between different isotopes since it depends on its mass number and the masses of the particles that it is formed from.
However, the masses of various isotopes of the same element are extremely close. Hence, this can be challenging to distinguish without the help of specialized tools.
Thus, option (a) is correct.
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How much dextrose is contained in 250 mL D10W?
Select one:
25 g
25 mg
250 g
250 mg
The amount of dextrose contained in 250 mL of D10W is 25 g .
To determine the amount of dextrose contained in 250 mL of D10W, you can follow these steps:
Step 1: Understand the meaning of D10W.
D10W stands for a 10% dextrose solution in water, meaning that there is 10 grams of dextrose per 100 mL of solution.
D10W is a common solution used in healthcare settings, and it is important for healthcare providers to understand the concentration of dextrose in this solution in order to provide appropriate care to their patients. It is worth noting that the amount of dextrose in D10W can vary depending on the specific formulation used.
Step 2: Calculate the amount of dextrose in 250 mL.
To find the amount of dextrose in 250 mL, use the proportion:
(\frac{10 g dextrose }{ 100 mL solution}) = (\frac{x g dextrose }{ 250 mL solution})
Step 3: Solve for x.
Cross-multiply and solve for x:
10 g * 250 mL = 100 mL * x g
2500 g = 100x
x = 25 g
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