During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive force of 115 N to the tire's rim. The mass of the wheel is 1.80 kg and, for the purpose of this problem, assume that all of this mass is concentrated on the outside radius of the wheel. The diameter of the wheel is 50.0 cm. A chain passes over a sprocket that has a diameter of 8.50 cm. In order for the wheel to have an angular acceleration of 4.30 rad/s2, what force, in Newtons, must be applied to the chain
Answers
Answer:
The force is \( F_c = 789.03 \ N \)
Explanation:
From the question we are told that
The tangential resistive force is \(F_t = 115 \ N\)
The mass of the wheel is m = 1.80 kg
The diameter of the wheel is \(d = 50.0 cm = 0.5 \ m\)
The diameter of the sprocket is \(d_c = 8.50 \ cm =0.085 \ m\)
The angular acceleration considered is \(\alpha = 4.30\ rad/s^2\)
Generally the radius of the wheel is
\(r = \frac{d}{2}\)
=> \(r = \frac{0.5}{2}\)
=> \(r = 0.25 \ m \)
Generally the radius of the sprocket is
\(r_c = \frac{d_c}{2}\)
=> \(r_c = \frac{0.085}{2}\)
=> \(r_c = 0.0425 \ m \)
Generally the moment of inertia of the wheel is mathematically represented as
\(I = m * r^2\)
=> \(I = 1.80 * 0.25^2\)
=> \(I = 1.1125 \ kg \cdot m^2\)
Generally the torque experienced by the wheel due to the forces acting on it is mathematically represented as
\(\tau = F_c * r_c - F_t * r \)
Here \(F_c\) is the force acting on the sprocket
So
\(\tau = F_c * 0.0425 - 115 * 0.25 \)
\(\tau = 0.0425F_c - 28.75 \)
Generally the torques that will cause the wheel to move with \(\alpha = 4.30\ rad/s^2\) is mathematically represented as
\(\tau = I * \alpha\)
So
\( 0.0425F_c - 28.75 = I * \alpha \)
\( 0.0425F_c - 28.75 = 1.1125 *4.30 \)
\( 0.0425F_c - 28.75 = 1.1125 *4.30 \)
\( F_c = 789.03 \ N \)
Related Questions
A high-diver of mass 59.8 kg jumps off a board 10.0 m above the water. If, 1.00 s after entering the water his downward motion is stopped, what average upward force did the water exert?
a. 108 N.
b. 4.27 N.
c. 840 N.
d. 598 N.
e. None of the other answers is correct.
Answers
la respuesta correcta es la "E"
The diagrams show four bodies moving in the directions shown. The only forces acting on the bodies are shown in each diagram.
Which body gains the most kinetic energy when moving a distance of 1.0m ?
Answers
Answer:
C - the greatest net force is on c with 25N - 10N = 15N
a = F / M
a = (v2 - v1) / t so C has the greatest acceleration and will reach the greatest velocity
KE = 1/2 M v^2
The diagrams show four bodies moving in the directions shown. The only forces acting on the bodies are shown in each diagram. The option C body gains the most kinetic energy when moving a distance of 1.0m.
What is kinetic energy?When some amount of force is applied on a object it can store a energy in that object. That is the kinetic energy. Mathematically the mass of the object and its change in acceleration in that object makes the kinetic energy. It is a vector quantity.
How can we calculate the kinetic energy?
To calculate the kinetic energy we are using the formula,
U= (1/2)mv²
U = (1/2) ma²t²
Or, U= (1/2)ma × at²
Or, U= F × (1/2)at²
From this calculation we can see that if there is more force applied on a body that generates more kinetic energy on that object.
According to the question ,
Force of the object of Option A has (F) = f₂ - f₁
= (20 - 10)
= 10N
Force of the object of Option B has (F) = 10N
Force of the object of Option C has (F) = f₂ - f₁
=(25-10)= 15N
Force of the object of Option D has (F) = f₂ - f₁
= (30-30)
= 0N
According to the question, option C has the most amount of force and we know the more force generate the more kinetic energy. So it has the more kinetic energy.
We can easily say that, The option C body gains the most kinetic energy when moving a distance of 1.0m
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In blacksmithing, quenching is when you heat steel to 600°C, then dipping it into a pool of oil to quickly lower its temperature. Steel has a specific heat capacity of 470 J/kgK, and quenching oil has a specific heat capacity of 510 J/kgK. A 7kg sword was quenched in 20°C oil, reaching a final temperature of 75°C. What was the total mass of oil in that quenching pool?
Answers
Q = mcΔT
where Q is the heat transferred, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
The heat lost by the sword is:
Q_sword = mcΔT = (7 kg)(470 J/kgK)(600°C - 75°C) = 2,835,000 J
The heat gained by the oil is:
Q_oil = mcΔT = (m_oil)(510 J/kgK)(75°C - 20°C)
We can solve for m_oil:
Q_oil = Q_sword
(m_oil)(510 J/kgK)(55°C) = 2,835,000 J
m_oil = 104,706 kg
Therefore, the total mass of oil in the quenching pool was 104,706 kg.
Plants use sunlight as energy to convert carbon dioxide and water into glucose and oxygen. Which best describes the reaction? The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products. The law of conservation of energy indicates the same amount of carbon will be found in the reactants as in the products. The law of conservation of mass indicates the same amount of glucose will be found in the reactants as in the products. The law of conservation of energy indicates the same amount of glucose will be found in the reactants as in the products.
Answers
Answer:
the correct statement is the first
The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products.
Explanation:
The law of conservation of energy establishes that the masses are not destroyed, they can only be transformed.
Therefore the mass of carbon in the reactants (CO2 and H2O) must be in the products (glucose and oxygen)
so the correct statement is the first
The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products.
Answer:
The answer is the first statement
Explanation:
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answers
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Which statement describes a primary difference between an electromagnetic wave and a mechanical wave
Answers
The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.
Difference between an Electromagnet and Mechanical WaveA primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.
Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.
Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.
On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.
Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.
In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.
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The coefficient of linear expansion of steel is 11 x 10 perc . A steel ball has a volume of
exactly 100 cm at 0 C. When heated to 100 C, its volume becomes:
Answers
Question: The coefficient of linear expansion of steel is 11 x 10⁻⁶ per °c . A steel ball has a volume of
exactly 100 cm³ at 0 C. When heated to 100 C, its volume becomes:
Answer:
100.11 cm³
Explanation:
From the question,
γ = (v₂-v₁)/(v₁Δt)...................... Equation 1
Where γ = coefficient of volume expansion, v₂ = final volume, v₁ = initial volume, Δt = change in temperature.
make v₂ the subject of the equation
v₂ = v₁+γv₁Δt..................... Equation 2
Given: v₁ = 100 cm³, γ = 11×10⁻⁶/°C, Δt = 100 °C.
Substitute into equation 2
v₂ = 100+100(11×10⁻⁶)(100)
v₂ = 100+0.11
v₂ = 100.11 cm³
car accelerates at a rate of 4.00 m/s?. How long will it take the car to speed up from 20 m/s to 50 m/s?
Answers
The distance that will take the car to speed yup from 20m/s to 50m/s is 262.5 meters
The first step is to write out the parameters given in the question are
acceleration= 4
initial velocity= 20
final velocity= 50
The distance can be calculated as follows
V²= U² + 2as
50²= 20² + 2(4)(s)
2500= 400= 8s
2500-400= 8s
2100= 8s
s= 2100/8
s= 262.5 meters
Hence the distance is 262.5 meters
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From the definition of acceleration, the time it will take the car to speed up is 7.5 seconds
Given that a car accelerates at a rate of 4.00 m/s^2. To calculate how long it will take the car to speed up from 20 m/s to 50 m/s, let us first mark out the needful parameters.
Acceleration a = 4 m/\(s^{2}\)
Initial velocity U = 20 m/s
Final Velocity V = 50 m/s
Time t = ?
From the definition of acceleration, acceleration is the rate of change of velocity. That is,
a = (V - U)/ t
Substitute all the parameters into the formula above.
4 = ( 50 - 20) / t
Cross multiply
4t = 30
Make t the subject of formula
t = 30/4
t = 7.5 t
Therefore, the time it will take the car to speed up is 7.5 seconds
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what planet has 1/10 of earth's gravity Show all work
Answers
The planet that has ⅒ of the earth's gravity is the moon.
What is gravity?Gravity is the force exerted by any object with mass on any other object with mass.
Gravity is the force on Earth's surface, of the attraction by the Earth's masses, and the centrifugal pseudo-force caused by the Earth's rotation, resulting from gravitation.
The gravity on the planet Earth is 1 with a acceleration due to gravity of 9.8m/s². One-tenth of this is 0.1 (0.98m/s²).
The planet with the above gravity is the moon with a gravity of 0.166.
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How many resistors are found in this circuit?
A) 0
B) 1
C) 2
D) 3
Answers
what are the four things that affect the resistance of a wire? A. length, diameter, material, and temperature B. weight, diameter, material, and temperature C. length, height, material, temperature D. length, weight, material, and temperature
Answers
Answer:
A. length, diameter, material, temperature
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answers
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.
A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. Determine the magnitude of the angular acceleration of the wheel. Give your answer in units of radians per second squared.
Answers
A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. The magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².
To determine the magnitude of the angular acceleration of the wheel, we need to first calculate the change in angular velocity and the time taken to come to rest. Then we can use these values to find the angular acceleration.
Calculate the initial angular velocity:
The initial linear velocity of the bicycle wheel is given by the formula v = ω * r, where v is the linear velocity, ω is the angular velocity, and r is the radius of the wheel.
The radius of the wheel is half the diameter, so r = 0.68 m / 2 = 0.34 m.
Given the initial linear velocity vi = 8.40 m/s, we can calculate the initial angular velocity ωi:
vi = ωi * r
ωi = vi / r
Calculate the final angular velocity:
The final angular velocity of the wheel is 0 rad/s since it comes to rest.
ωf = 0 rad/s
Calculate the change in angular velocity:
The change in angular velocity (Δω) is given by the formula Δω = ωf - ωi.
Δω = 0 - ωi
Calculate the time taken to come to rest:
To calculate the time taken to come to rest, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given the initial velocity vi = 8.40 m/s, final velocity vf = 0 m/s, and distance d = 115 m, we can calculate the acceleration a:
vf = vi + at
0 = 8.40 + a * t
We also know that the distance traveled d is related to the initial and final velocities and the time by the formula d = (vi + vf) / 2 * t:
d = (vi + vf) / 2 * t
115 = (8.40 + 0) / 2 * t
From the two equations above, we can solve for the acceleration a and the time t.
Calculate the angular acceleration:
The angular acceleration (α) is given by the formula α = Δω / t.
α = Δω / t
Substitute the values for Δω and t and calculate the angular acceleration.
Therefore, the magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².
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Determine the coefficient of kinetic friction when the frictional force is 65 N and the normal force is 120 N
Answers
Answer:
0.5417
Explanation:
The frictional force is equal to the coefficient of kinetic friction times the normal force, so
\(F_f=\mu_kF_n\)Then, solving for the coefficient of kinetic friction, we get:
\(\mu_k=\frac{F_f}{F_n}\)Now, we can replace the frictional force Ff by 65 N and the normal force Fn by 120 N
\(\mu_k=\frac{65N}{120N}=0.5417\)Therefore, the coefficient of kinetic friction is 0.5417
Airplane flight recorders must be able to survive catastrophic crashes. Therefore, they are typically encased in crash-resistant steel or titanium boxes that are subjected to rigorous testing. One of the tests is an impact shock test, in which the box must survive being thrown at high speeds against a barrier. A 52-kg box is thrown at a speed of 400 m/s and is brought to a halt in a collision that lasts for a time of 6.5 ms. What is the magnitude of the average net force that acts on the box during the collision
Answers
Answer:
3.2 MN
Explanation:
Given that
Mass of the box, m = 52 kg
Initial velocity of the box, u = 400 m/s
Final velocity of the box, v = 0 m/s
Time taken for the collision, t = 0.0065 s
Using the equation of motion
V = u + at, we turn around and make acceleration, a the subject of the formula. Now we have,
a = (v - u) / t
a = (0 - 400) / 0.0065
a = 61538.5 m/s²
The acceleration(which is negative acceleration or retar.dation actually) is 61538.5 m/s². We then proceed to is this acceleration in the basic Force equation, to get the magnitude of force needed.
Remember,
Force = mass * acceleration
F = ma, we already have our mass and acceleration, all we do is multiply
F = 52 * 61538.5
F = 3200002 N or 3.2 MN
Therefore, the magnitude of the force that acts on the box during collision is 3.2 MN
How do you determine: how many significant figures should you to round to when doing addition and subtraction?
Answers
2. Gerard is riding his bicycle directly east. His maximum
instantaneous velocity was 8 meters per second and his
minimum instantaneous velocity was 0 meters per second. He
covered 7.20 kilometers in 20.0 minutes. What is his average
velocity for the ride?
Answers
Gerard's average velocity for the ride is 6 meters per second.
To find Gerard's average velocity for the ride, we can use the formula:
Average velocity = Total displacement / Total time
First, we need to convert the distance traveled from kilometers to meters:
7.20 kilometers * 1000 = 7200 meters
Next, we convert the time from minutes to seconds:
20.0 minutes * 60 = 1200 seconds
Now, we can calculate the total displacement by subtracting the initial position from the final position. Since Gerard is riding directly east, there is no change in the east-west direction, so the displacement is equal to the distance traveled:
Total displacement = 7200 meters
Finally, we substitute the values into the average velocity formula:
Average velocity = 7200 meters / 1200 seconds
Average velocity = 6 meters per second
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What does the lines
between atoms represent?and howThe lines between molecules?
Answers
a fixed mass of gas occupies a volume of 1000 CM3 at 0 degree celsius if it is heated at constant pressure of 100 degree celsius calculate the new volume
Answers
Answer:
P V = N R T ideal gas equation
V1 = k * T1 if P is constant and also N and R will be constant
V2 = k * T2 where k is some constant
Or V2 = (T2 / T1) * V1 also known as "Charles Law" for expansion at
constant pressure
V2 = (373 / 273) * 1000 cm^3 = 1366 cm^3 where T is absolute temperature
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
Answers
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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Please answer in complete sentences and answer all parts. Thank you very much
Part 2 of the problem will be out next.
Answers
The externally applied force is directly proportional to the distance of elongation. F ∝ x, where x is the elongation of materials. F=-kx, where k is the force constant of spring.
From the given,
block 1 is attached to the spring. When there is no force applied, block 1 remains at rest. When the force is applied externally to the spring attached to block 1, it begins to oscillate. While oscillating, block 1 gets displaced to point C.
The net force acts on block 1, and applied force F is acted towards the left and pushes block 1 to move towards the right. The frictional force Ff restricts the motion of block 1, which acts towards the left.
The Normal force Fn acted normally or perpendicular to block 1 and the normal force is acted upwards. The gravitational force Fg, acts downwards to attract block 1. Therefore, the net force acted on block 1 involves applied Force, Frictional force, Normal force, and Gravitational force.
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Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.
A.
69.58 newtons
B.
45.05 newtons
C.
25 newtons
D.
98.26 newtons
Answers
Answer:
Option A (69.56 newtons) is the appropriate solution.
Explanation:
According to the question,
On the X-axis,
⇒ \(T_1Cos30^{\circ}-T_2Cos60^{\circ}=0\)
or,
\(T_1Cos 30^{\circ}=T_2Cos60^{\circ}\)
On substituting the values, we get
\(T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}\)
\(T_1\times \sqrt{3} =T_2\)....(equation 1)
On the Y-axis,
⇒ \(T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N\)
\(\frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N\)
\(T_1+\sqrt{3}T_2=139.2\times 2\)
From equation 1, we get
\(T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N\)
\(T_1+3T_1=278.4 \ N\)
\(4T_1=278.4 \ N\)
\(T_1=\frac{278.4}{4}\)
\(=69.6 \ N\)
Answer:
69.58
Explanation:
Need help for this Asap please
Answers
The coefficient of static friction between the block of wood and the table is 0.449.
How to calculate the frictionThe weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.
The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.
Since the block is not accelerating vertically, we know that N = Mg, so we have:
μs = fs/N = 17.64 N / 39.24 N = 0.449
Therefore, the coefficient of static friction between the block of wood and the table is 0.449.
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The most effective way to reduce waste is to not create it in the first place.
True
False
Answers
Answer:
True
Explanation:
If there isnt any waste it would reduce the quantity however the waste that is present needs to be dealt with so......
why does a person at the depth of the lake doesn't burst
Answers
Answer:
Because the body regulates water pressure well because we are mostly composed of water
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s.A violinist is tuning her instrument to concert A (440 Hz). She plays the note while listening to an electronically generated tone of exactly that frequency and hears a beat of frequency 6.00 Hz, which increases to 7.00 Hz when she tightens her violin string slightly.
(a) What was the frequency of the note played by her violin when she heard the 3-Hz beats?
(b) To get her violin perfectly tuned to concert A, should she tighten or loosen her string from what it was when she heard the 3-Hz beats?
Answers
Answer:
A) 443 Hz
B) She has to loosen the string
Explanation:
A) Given;
Beat frequency;f_beat = 3 Hz
Frequency of electronically generated tone; f_e = 440 Hz
We know that formula for beat frequency is given by;
f_beat = |f1 - f2|
Now, applying it to this question, we have;
f_beat = f_v - f_e
Where f_v is frequency of the note played by the violinist
Thus, plugging in the relevant values;
3 = f_v - 440
f_v = 3 + 440
f_v = 443 Hz
B) In the concept of wave travelling in a string, the frequency is directly proportional to the square root of the force acting on the string.
Now, for the violinist to get her violin perfectly tuned to concert A from what it was when she heard the 3-Hz beats, the beat frequency will have to be zero. Which means it has to decrease by 3 Hz. For it to decrease, it means that the force applied has to decrease as we have seen that frequency is directly proportional to the square root of the force acting on the string.
Thus, she would have to loosen the string.
which image shows an example of kinetic energy
Answers
Answer:
Hello there seems to be no Images in this question but Kinetic energy is a push or a pull force which has to do with motion if you just need to know what t is. Next time be sure to add the pictures for it.
Explanation:
Thank you!
Hello the other person (#Sonichj123), was indeed correct there appears to be no picture in your question. Although there is no picture in your question, If you have another question I will be gladly to help you!
Explanation:
Thank you so much! (≥ФωФ≤)
What is environmental?
Answers
Answer:
Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.
Explanation:
I HOPE IT HELPS!!
THANX!!!
STAY SAFE!!!!
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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