During a review game, Mr. TooMuch's class correctly answered 68 questions on the first try. If there were 74 questions in the game, at what rate were questions answered correctly on the first try? Express your answer as a decimal in the form of 0.ABC.

If necessary, round to the nearest thousandth.

Answer:

Here is a example they gave these numbers 6.9 and they say find 2 ways to describe it you will have this 6.9 or 6 to9

The most appropriate choice for cone and total surface area of cone will be given by-

Total surface area of the cone is \(198235.71 cm^2\)

What is cone and total surface area of cone?

Cone is a 3 dimensional figure whose base is a circle and upper surface finally converge to a point.

Cone is obtained by revolving a right angled triangle about one of its legs.

Total surface area of the cone is the sum of curved surface area of the cone and the area of the base of the cone.

If r is the radius of the base of the cone and l is the slant height of the cone, then total surface area of the cone will be given by

\(\pi r(r+l)\)

Here

Ratio of the slant height and radius of base of the cone = 2:1

Radius = 145cm

Slant height = \(145 \times 2\)

                    = 290 cm

Total surface area of cone = \(\pi r(r+l)\\\)

                                              = \(\frac{22}{7} \times 145\times (145+290)\\\)

                                              = \(\frac{22}{7} \times 145 \times 435\)

                                               = \(198235.71 cm^2\)

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Complete Question

The slant height and the radius of  base of the cone are in the ratio 2:1. If the radius of the cone is 145cm. What is the total surface area of the cone?​

The dilation transformation of the triangle ABC by a scale factor of 3, with the point P as the center of dilation indicates;

Side A'B' will be parallel to side AB

Side A'C' will be parallel to side AC

Side BC will lie on the same line as side BC

A dilation transformation is one in which the dimensions of a geometric figure are changed but the shape of the figure is preserved.

The possible options, from a similar question on the internet are;

Be parallel to

Be perpendicular to
Lie on the same line as

The location of the point P, which is the center of dilation, and the lines PC and PA of dilation and the scale factor of dilation indicates that we get;

PB' = 3 × PB

PA' = 3 × PA

PC' = 3 × PC

Therefore; The side B'C' will be on the same line as the side BC

The Thales theorem, also known as the triangle proportionality theorem indicates that;

The side A'C' will be parallel to the side AC

The side A'B', will be parallel to the side AB

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Answer:

51.2 mi

Step-by-step explanation:

Proportions:

5 in ⇔ 16 mi

16 in ⇔ C mi

C = 16*16/5

C = 51.2 mi

Answer:

25 students are in the chess club

Step-by-step explanation:

100×5=500

500÷20=25

I hope it's correct:)

Answer:

25 students

and how?

its 2          5         S       T      U       D          E         N        T         S

The moment of inertia for rotation about the z axis is  \(I & =\frac{a^2 M}{3}\).

A triangular prism of mass m, whose two ends are equilateral triangles.

Two ends are equal.

The xy plane with side 2a, is centered on the origin with its axis along the z axis.

Find the moment of inertia for rotation the z-axis.

It is divide into 4 triangles with side 'a' k one side is 3cm.

\($$\begin{aligned}& I_{\text {BiG }}=16 I_{\text {small }} . \\& I_{\text {BIG }}=4 I_{\text {small }}+P_{A T}\end{aligned}$$\)

It is fact that the big triangle is made up from four small triangles. connected with parallel axis theorem.

Now, we have to find the distance from the center of mas of small outer triangles to the origin. so, that it is PAT.

\($$\therefore z=2 \sqrt{x^2-\frac{a}{2} ^2}$$\)

\($$\begin{aligned}& =2 \sqrt{\left(\frac{a}{\sqrt{3}}\right)^2-\frac{a^2}{4}} \\& =2 \sqrt{\frac{a^2}{3}-\frac{a^2}{4}} \\I_{\text {Big }} & =\frac{\sqrt{3}}{3} a \cdot \\& \left.=4 I_{\text {small }}+3 m \frac{\sqrt{3}}{3} a\right)^2 \\I_{\text {Big }} & =4 I_{\text {small }}+\frac{3 m}{4} \frac{1}{3} a^2 \\& =\frac{a^2}{4}\end{aligned}$$\)

⇒ Now, by using the \($I_{\text {Big }}=I$\)

⇒\(I & =4\left(\frac{\sqrt{2}}{16}\right)+\frac{a^2 M}{4} \\\)

⇒\(4 I & =I+a^2 m\)

⇒\(4 I-I & =a^2 m \\\)

⇒\(3 I & =a^2 M . \\\)

⇒\(I \quad & =\frac{a^2 M}{3}\)

Therefore, the moment of inertia is \(I & =\frac{a^2 M}{3}\).

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Answer:

can you submit the coordinet plane?

Step-by-step explanation:

Answer:

12.56cm

Step-by-step explanation:

4π cm

4 x 3.14

12.56cm

Answer:

2+x^2=18 = 2+4^2=18

Step-by-step explanation:

Because when you have the ( ^2) then that means your going to multiply a number by the same number and then 4 times 4 equals 16 and you still have the +2 therefore you add that on the 16 and 16+2 equals 18.

Part I

Part II

Part III

This a term that represents the amount of how hot or cold a substance is the unit used to measure temperature as regards the question is degrees Celsius.

The range of the graph is temperature while the domain is the time

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"How many sticks of gum can you eat at one time?" is the finest and most right response. Then the correct option is A.

A statistical question is one that may be addressed by gathering data from several sources.

A statistical question is one that may be addressed by gathering data and in which the data is likely to vary. This is not the same as a question with a predetermined response.

The first choice or letter A, "How many sticks of gum can you eat at one time?" is the finest and most right response among the options supplied by your query.

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Answer:

A) 26 guests

Step-by-step explanation:

I just took the quiz on edge

Answer:

steps below

Step-by-step explanation:

((x²-2x-8)/(x²-3x-10)) - ((x²-2x-3)/(x²+7x+6))

= ((x+2)(x-4)/(x+2)(x-5)) - ((x+1)(x-3)/(x+1)(x+6))

= (x-4)/(x-5) - (x-3)/(x+6)

= (x-4)(x+6)/(x-5)(x+6) - (x-3)(x-5)/(x-5)(x+6)

= ((x-4)(x+6) - (x-3)(x-5))/(x-5)(x+6)

= ((x²+2x-24) - (x²-8x+15)) / (x-5)(x+6)

= (x²+2x-24-x²+8x-15) / (x-5)(x+6)

= (10x-39) / (x-5)(x+6)      ..... (10x-39) / (x²+x-30)

Step-by-step explanation:

We first need to simplify the quadratic numerators and denominators. We'll use the fact that any equation of form

\(ax^2 + bx + c = 0\)

where it has solutions \(x_1\) and \(x_2\) can be written as

\(a(x-x_1)(x-x_2)\)

Where \(b = -a(x_1 + x_2)\) and \(c = ax_1x_2\)

Fortunately, here a = 1 for all equations, so let's learn how to solve for a=1 because it's a bit simpler.

\(x^2 - 2x - 8 = 0\\x^2 - 2x + 1 - 9 = 0\\(x - 1)^2 - 9 = 0\\(x - 1)^2 = 9\\x - 1 = 3 \vee x - 1 = -3\\x = 4 \vee x = -2\\x^2 - 2x - 8 = (x - 4)(x + 2)\\~\\~\\x^2 - 3x - 10 = 0\\x^2 - 3x - 10 = 0\\\\x^2 - 3x + 2.25 - 12.25 = 0\\(x - 1.5)^2 - 12.25 = 0\\(x - 1.5)^2 = 12.25\\x - 1.5 = 3.5 \vee x - 1.5 = -3.5\\x = 5 \vee x = -2\\x^2 - 3x - 10 = (x - 5)(x + 2)\\~\\~\\\frac{x^2-2x-8}{x^2-3x-10} = \frac{(x-4)(x+2)}{(x-5)(x+2)} = \frac{x - 4}{x-5}\)

See, we've simplified the first term of the subtraction. Now let's do the same with the right side:

\(x^2 - 2x - 3 = 0\\x^2 - 2x + 1 - 4 = 0\\(x - 1)^2 = 4\\x - 1 = 2 \vee x - 1 = -2\\x = 3 \vee x = -1\\x^2 - 2x - 3 = (x - 3)(x + 1)\\~\\~\\x^2 + 7x + 6 = 0\\x^2 + 7x + 12.25 - 6.25 = 0\\(x + 3.5)^2 = 6.25\\x + 3.5 = 2.5 \vee x + 3.5 = -2.5\\x = -1 \vee x = -6\\x^2 + 7x + 6 = (x + 1)(x + 6)\\~\\~\\\frac{x^2 - 2x - 3}{x^2 + 7x + 6} = \frac{(x-3)(x+1)}{(x+1)(x+6)} = \frac{x-3}{x+6}\)

See, we've simplified the second term. Now we need to bring them to the common denominator:

\(\frac{x^2-2x-8}{x^2-3x-10} - \frac{x^2-2x-3}{x^2+7x+6} = \frac{x-4}{x-5} - \frac{x-3}{x+6} = \frac{(x-4)(x+6)}{(x-5)(x+6)} - \frac{(x-3)(x-5)}{(x+6)(x-5)} =\\~\\= \frac{(x-4)(x+6) - (x-3)(x-5)}{(x+6)(x-5)} = \frac{(x^2 + 2x - 24) - (x^2 - 8x + 15)}{(x+6)(x-5)} =\\~\\= \frac{10x-39}{(x+6)(x-5)}\)

We could simplify even further if we can find some a and b so that

\(10x - 39 = a(x+6) + b(x-5)\)

then

\(\frac{10x-39}{(x+6)(x-5)} = \frac{a}{x-5} + \frac{b}{x+6}\)

So let's try!

\(a + b = 10\\6a - 5b = -39\\b = 10 - a\\6a - 5(10 - a) = -39\\6a - 50 + 5a = -39\\11a = 11\\a = 1\\b = 10 - 1 = 9\\~\\\frac{10x-39}{(x+6)(x-5)} = \frac{1}{x-5} + \frac{9}{x + 6}\)

And that's the simplest form.

Answer:

33

Step-by-step explanation:

Add 165 and 80 to get 245. 80 times 3 = 240.

So 80 is around 1/3 of 240. In other words it is around 33%

Answer:

5

Step-by-step explanation:

The formula for this linear function is f(x) = mx + b, where m is the slope (in this example, -350), and b is indeed the y-intercept (750,000 in this case).

An equation expressing the connection between the expressions on either side of a sign. Normally, it has an equal sign and just one variable. such as: 2x - 4 is equal to 2. The variable x is present in the example above.

Workers who complete the computer security course will each receive a reimbursement of $350.

We deduct $350x from of the initial $750,000 to determine how much money will remain inside the education fund once x employee gets the reimbursement.

Thus, f(x) = 750,000 - 350x is the equation again for function that describes that amount of money still in the fund when x employees receive the refund.  

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The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

t=\(\sqrt{\frac{38}{g} }\)

Step-by-step explanation:

19=(1/2)gt²

(multiply both sides by 2)

38=gt²

(divide both sides by g)

t²=(38/g)

(square root both sides)

t=\(\sqrt{\frac{38}{g} }\)

if we call the price of citrons c and the price of fragrant wood apples f, then the first statement of the question gives us the equation

and the second statement gives

Hence, we have a system of equations with two unknowns and 2 equations which we need to solve in order to answer our question.

Let us solve for c in the first equation. Doing this gives

putting that into the second equation gives

With the value of f in hand, we put it into the first equation and solve for c:

Hence, the price of citron is 8 units and the price of the fragrant wood apples is 5 units.

Answer:

The area of this circle is \((\frac{\pi}{2} )\)  the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is \((\frac{2}{\pi} )\) ϕcircle

Step-by-step explanation:

Area of the circle is given by;

\(A_c = \frac{\pi d^2}{4}\)

Area of the square is given by;

\(A_s = L^2\)

relationship between the edge length of the square, d, and length of its side, L,

\(d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}\)

But area of the square , \(A_s = L^2\)

\(d = \sqrt{2A_s}\)

Then, the area of the square in terms of the edge length is given by;

\(A_s = \frac{d^2}{2}\)

Area of the circle in terms of area of the square is given by;

\(A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )\)

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

\(\phi _{circle} = E.(\frac{\pi d^2}{4})\)

Flux through the surface of the square is given by;

\(\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )\)

Therefore, Φsquare is \((\frac{2}{\pi} )\) ϕcircle

If the circle has the same diameter as the edge length of the square, then the area of this circle is \(\rm \dfrac{\pi }{2}\) the area of the square

The uniform electric field is normal to the surface, the flux through the surface is the electric field multiplied by the area of this surface.

Φsquare is \(\dfrac{2}{\pi}\)  ϕcircle

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the square

For the uniform electric field normal to the surface, the flux through the surface is____________the area of this surface.

Therefore, Φsquare is ________ ϕcircle .

1. If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the square.

The area of the circle is;

\(\rm Area \ of \ circle = \dfrac{\pi d^2}{4}\)

The area of the square is;

\(\rm Area \ of \ square = a^2\)

The relationship between the edge length of the square, d, and length of its side a is;

\(\rm d = \sqrt{a^2+a^2}\\\\d = \sqrt{2a^2}\\\\d = \sqrt{2} a\)
The area of the circle in terms of the area of the square is;

\(\rm Area \ of \ circle = \dfrac{\pi }{2} \ Area \ of \ square\)

If the circle has the same diameter as the edge length of the square, then the area of this circle is \(\rm \dfrac{\pi }{2}\) the area of the square.

2. The uniform electric field is normal to the surface, the flux through the surface is the electric field multiplied by the area of this surface.

Ф = E.A

3. Flux through the surface of the circle is given by;

\(= \rm E\dfrac{\pi d^2}{4}\\\\=\dfrac{2}{\pi }\)

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Answer:

the answer is 126 cm

sana makatulong

Note that the measure of the listed angles is given as follows:

Where the above figure is a regular quadrilateral, the properties are given as follows:

1) Since ∠LKM represents one of the Right Angles, therefore, it is correct to state that m∠KLM is 90°

2) Since ∠LKJ is another Right Angle, and \(\overline{KL}\) ||\(\overline{JM}\),  and  \(\overline{MK}\) is a diagonal cutting across  \(\overline{KL}\) ||\(\overline{JM}\), ∠JKM ≅ ∠LMK

Since ∠JKM = 68°

Thus, ∠LMK = 68°

3) If opposite sides are equal; and

opposite sides are parallel, then the diagonals must bisect each other equally creating triangles that are congruent. Thus, ΔMNL ≅ ΔKNJ.

Given the above, ∠LMK ≅ ∠LJM

since ∠LMK = 68°

m∠LJM = 68°

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Answer:

60mph

Step-by-step explanation:

Answer:

Manny drove 45 miles in 0.75 hours.What was the average rate that he drove in miles per hour?

60 mph

Step-by-step explanation:

Answer:

the answer is

Step-by-step explanation:

the answer

The length of the fence around the enclosure not including the gates is:2l + 2w + 8 m

To find the length of the fence around the enclosure, we need to first find the perimeter of the rectangle and then subtract the combined length of the two gates from it.

Let's assume the length of the rectangle is 'l' and the width is 'w'.

From the given data, we know that each gate is 4 m wide.

Therefore, the width of the rectangle is:

Width = w + (4 m + 4 m) = w + 8 m

The perimeter of the rectangle is:

P = 2l + 2(w + 8 m) = 2l + 2w + 16 m

Now, we need to subtract the combined length of the two gates from the perimeter:

P - 2 × 4 m = 2l + 2w + 16 m - 8 m = 2l + 2w + 8 m

So, the length of the fence around the enclosure not including the gates is:2l + 2w + 8 m

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Answer:

C            Mark me as brainliest!!!

Step-by-step explanation:

For the additive opposites x+4y=28 and -x+y=12, yes, y is equal to 8.

In order to solve the given system of equations, we would apply the substitution method. Based on the information provided above, we have the following system of equations:

x + 4y = 28      .......equation 1.

-x + y = 12         .......equation 2.

By making x the subject of formula in equation 2, we have the following:

x = y - 12           .......equation 3.

By using the substitution method to substitute equation 3 into equation 1, we have the following:

y - 12 + 4y = 28

5y = 28 + 12

5y = 40

y = 40/5

y = 8

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Answer:

x=5

Step-by-step explanation:

4x+2=2x+12

4x-2x=12-2

2x=10

x=10/2

x=5

Probability for the following events will be :-

The probability of an event E,P(E)=

 Number of favourable outcomes / Total number of outcomes

​ =  n(E) / n(S)

​

Applying the concept of probability as shown above, let's calculate all the probabilities one by one.

(i) Probability of getting a king of red colour:

We know that, there are 26 red cards, 13 each of hearts and diamonds. Hence, there will be 1 king each in hearts and diamonds.

∴  Number of kings of red colour, n(E)=2

Also, total number of cards, n(S)=52

∴  Probability of getting a king of red colour

= n(E) / n(S)

= 2 / 52

⇒ 1 / 26

Hence, the required probability is  1 / 26

​(ii) Probability of getting a face card:

We know that, each suit has 3 face cards (Jack, Queen and King). Hence, there will be 12 face cards in total.

∴  Number of face cards, n(E)=12

Also, total number of cards, n(S)=52

∴  Probability of getting a face card

= n(E) / n(S)

= 12 / 52

⇒ 3 / 13

Hence, the required probability is  3 / 13

(iii) Probability of getting the jack of hearts:

We know that, there is only one jack in hearts.

∴  Number of jack of hearts, n(E)=1

Also, total number of cards, n(S)=52

∴  Probability of getting the jack of hearts =

n(E) / n(S)= 1 / 52

Hence, the required probability is  1 / 52

(iv) Probability of getting a red face card:

We know that, there are 26 red cards, 13 each of hearts and diamonds. Both hearts and diamonds have 3 face cards each.

∴  Number of red face cards, n(E)=6

Also, total number of cards, n(S)=52

∴  Probability of getting a red face card =

n(E) / n(S) = 6 / 52

⇒ 3 / 26

Hence, the required probability is  3 / 26

​(v) Probability of getting a spade:

We know that, there are 13 cards of spades.

∴  Number of spades, n(E)=13

Also, total number of cards, n(S)=52

∴  Probability of getting a spade =

n(E) / n(S) = 13 / 52

⇒ 1 / 4

Hence, the required probability is  1 / 4

(vi) Probability of getting the queen of diamonds:

We know that, there are 13 cards of diamonds. There is 1 queen of diamonds.

∴  Number of queens in diamonds, n(E)=1

Also, total number of cards, n(S)=52

∴  Probability of getting the queen of diamonds =

n(E) / n(S) = 1 / 52

​Hence, the required probability is  1/52

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