Drying a siab of material at 6500 + lam with air at 24. humidity at a velocity of 1.5 m/s, Estimate the drying rate in the constant rate regime by determing the mass transfer coefficient (ky) for flow across a fiat plare. Tengen of : 2-0.5m Ai viscos 174 : M = 20,21-10-4epais Alv density: P-1.045 kg/m3 Diffusivery of waterinar: DAB = 0,288 (mysar M Wair=28,97 YBM = 1 420

Alloys were stronger and more durable

The call "print (mult(9, 15, 6, 7))" is not correct. The function definition specifies three parameters with default values. This means that when the function is called, the values of these parameters can be provided by the caller, but are not required.

If no value is provided for a parameter, the default value will be used. In the first call, only one argument is provided, so the function will use the default values for b and c. In the second call, two arguments are provided, so the function will use the provided values for a and b, and the default value for c. In the third call, four arguments are provided, which is more than the function definition allows, so the call is not correct. In the fourth call, three arguments are provided, which is within the allowed range, so the call is correct.

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Answer:

find the attenuation constant, the phase constant and the intrinsic impedance of a non magnetic medium has a frequency

Explanation:

find the attenuation constant, the phase constant and the intrinsic impedance of a non magnetic medium has a frequency

The dynamic viscosity of the oil in poise is 13.625 pois

The kinematic viscosity of the oil in strokes is 14.34

F viscous is given as n*  ΔFr / Δy

where n = F * Δy / A * ΔVn

We have to define the terms of the formula

Δy = 12.5 x 10⁻³

ΔVr = 2.5m /s

A = 60 x 60 cm² = 0.36m

F = 98.1 n

We have to put the values in the formula

98.1 n *  12.5 x 10⁻³ /  0.36m * 2.5m /s

n = 1.3625  ns / m²

The kinematic viscosity of the oil in strokes if the specific gravity of the oil is 0.95

y = n / e

n =  1.3625  

e = 0.95 x 10³

y = 1.3625  / 0.95 x 10³

= 1.434 x 10⁻³

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Wood is a composite type of CMC. What is Wood. Wood is a natural composite that is formed from cellulose fibers embedded in a matrix of lignin.

It is a natural material that has been used for thousands of years to make structures, furniture, and other useful items. What are Composites. Composite materials are made up of two or more materials with distinct and they can be made by combining any type of material. The goal of combining different materials is to create a new material with better overall properties than any of the individual components. Wood is made up of cellulose fibers embedded in a matrix of lignin. Wood, which is a natural composite, is an example of a composite made up of organic materials. CMC (Ceramic matrix composites) and MMC (Metal matrix composites) are the other two composite types.
Wood is a natural composite material and does not fall under the categories of (a) CMC (Ceramic Matrix Composite), (b) MMC (Metal Matrix Composite), or (c) PMC (Polymer Matrix Composite).

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Hey there ..

I think the answer is as they put brake ..

I am not sure .. just check the image also provided above .. ..

If u think this helped u ..plz mark me as brainliest ..

And follow me

Answer:

During starts and stops

Explanation:

"Many of the energy inefficiencies in vehicles occur during starts and stops."

found it in the text.

C = k eo A / d C = 7* 8.85* 10^

Answer:

a)  ≈ 11.7 watts

b)  ≈ 21.4 watts

Explanation:

Given data :

Oven door dimensions : 0.6m  by 0.7m

average surface temperature = 32°c

Temperature of ambient air = 22°c

emissivity of door = 0.4

surrounding temperature = 22°c

a) Calculate heat transfer by free convection

q = 3.34 ( 0.5 * 0.7 ) (32-22 ) ≈ 11.7 watts

attached below is the detailed solution

b) calculate heat transfer by radiation

q = ∈.As б ( Ts^4 - Tsun^4 )

   = 1( 0.5*0.7 ) * 5.67 * 10^-8 [( 273+32)^4 - ( 273+22)^4 ]

   ≈ 21.4 watts

Answer: yes because fish its like quick sand is will just fall apart into tiny pecies to now it want us to round to the nearst hundredth so what is 12 divide by 3 and time 1

12:3x1=4 because we are rounding to the nearst hundredth

=4

Explanation:

The torque M which must be applied to the crank at O when the crank angle = 30° is 0.5 Nm.

Taking moments about O, the torque is given byτ = (AB x BC) sin(θ) x a

Here θ is the angle between AB and the horizontal and a is the tangential acceleration of B.θ is 180° - 2α and sin(θ) = sin(2α), where α is the angle between the coupler and AB.

Angle α is given byα = cos⁻¹((BC² - AC² - AB²) / (-2AC x AB))

The tangential acceleration of B is given by

a = (BC x AB x ω²) / (2 x BD)

where BD is the perpendicular distance from O to AB.

Calculating angle α

α = cos⁻¹((BC² - AC² - AB²) / (-2AC x AB))

α = cos⁻¹((1.5² - 0.8² - 0.9²) / (-2x0.8x0.9))

α = cos⁻¹(-0.263)α = 104.33°

Calculating θ

θ = 180° - 2α

θ = 180° - 2(104.33°)

θ = - 16.67°

We can take sinθ = sin(-16.67°) = -0.29.

Using τ = (AB x BC) sin(θ) x aτ = (0.9 x 1.5) x -0.29 x ((1.5 x 0.9 x 2π / 60)² / 2 x 0.8)τ = - 0.5 Nm

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What is ratio?

A ratio indicates the number of times one number contains another. For example, if a dish of fruit contains eight oranges as well as six lemons, the orange-to-lemon ratio is eight to six. Similarly, the proportion of lemons to oranges is 6:8 (or 3:4), while the proportion of oranges to overall fruit is 8:14. (or 4:7). The numbers in a ratio can be any quantity, such as a count of people or things, or measurements of lengths, weights, time, and so on. Both numbers must be positive in most cases.

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To draw a free body diagram of the pint glass with liquid, we need to identify all of the forces acting on the object and draw them as vectors. The forces acting on the pint glass with liquid are.

Weight: The weight of the pint glass with liquid is 2 lb, acting downwards. We can represent this force as a vector pointing downwards from the center of mass of the glass, which is located 2 inches out from the end of the hand.

Reaction force from the hand: The hand is in contact with the glass and exerts an equal and opposite force on the glass, upwards. We can represent this force as a vector pointing upwards from the center of mass of the glass.

Distributed load: The forearm and hand are modeled as a rigid beam with a distributed load of 0.2 lb/in over 15 inches. The pint glass is rigidly connected to the end of the forearm, so it also experiences this distributed load. We can represent this load as a vector pointing downwards from the end of the forearm.

Tension in biceps tendon: The biceps tendon is modeled as a rope/wire pulling on the forearm. This tension force is transmitted to the pint glass, causing it to rotate about the elbow. We can represent this force as a vector pointing upwards from the end of the forearm.

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The gas phase reaction of the C6H6(g) + Cl2(g) = C6H5Cl(g) + HCl(g)  will get the chlorobenzene and hydrogen chloride.

Given data :

C6H6(g) + Cl2(g) = C6H5Cl(g) + HCl(g)

Change in Free Energy: ΔG(20C) = -125.7kJ (negative, so the reaction runs)

Change in Enthalpy: ΔH(20C) = -119.9kJ (negative, so the reaction is exothermic)

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We require further details about the circuit and its components in order to validate the calculated analytical matrix solutions for forces F1, F2, and F3.

According to KVL, all source voltages in a closed circuit must add up to the same amount as all voltage drops. When current moves from the higher potential terminal to the lower potential terminal, voltage drops happen.

| 1 2 1 | 4 |

| 3 -4 -2 | 2 |

| 5 3 5 |-1 |

| 1 2 1 | 4 |

| 0 -10 -5 | -10 |

| 0 -7 0 | -21 |

-7I2 = -21

Solving for I2, we get:

I2 = 3

Substituting this value into the second row, we get:

-10I2 - 5I3 = -10

Substituting I2 = 3, we get:

-10(3) - 5I3 = -10

Solving for I3, we get:

I3 = 2

Substituting the values of I2 and I3 into the first row, we get:

I1 + 2(3) + 2 = 4Solving for I1, we get:

I1 = -2

Therefore, the solution for the system of equations is:

I1 = -2 milliamperes

I2 = 3 milliamperes

I3 = 2 milliamperes

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Answer:

control loop unit

Explanation:

Edmentum/Plato

Answer:

  A. Oil changes

Explanation:

It depends on the car and its usage and environment. Usually oil is supposed to be changed every few months, more often if the car is driven a lot. Coolant changes may be indicated as seasons change, so will generally occur less frequently than oil changes.

Tire and brake replacement depend on usage and driving habits. Some owners may never have to replace either one, if they trade their car every year or two. Folks who drive with their foot on the brake pedal may have to replace brakes relatively often.

The most frequent task is generally oil changes.

Answer:

The number of paths in the network is six.

The paths are:
C - A - T - N - EndC - A - T - R - N - EndC - B - P - U - N - EndC - B - P - U - T - R - N - EndC - B - P - A - T - N - EndC - B - P - A - T - R - N - End
2. The critical path is C - A - T - N - End with a duration of 24 weeks.

3. The float on activity U is 1 week.

4. If activity B takes three weeks longer than planned, it will affect the duration of path 3 and the entire project. It will elongate the project duration to 29 weeks.

2. b) The critical path is A-C-E-G with a duration of 18 weeks.

(c) The normal expected project completion time is 18 weeks.

(d) The total project cost using normal time is RM 7600.

(e) To complete the project two weeks faster, activities C and E can be crashed for the minimum cost.

The additional cost incurred will be RM 600.

The total cost is RM 8200.

3 The inventory cost that will minimize the total cost of inventory is obtained using the formula,

TAC = IC + OC + HCS

Where TAC

= Total Annual CostIC = Inventory CostOC = Ordering CostHCS = Holding and Carrying Cost.

The probability distribution is shown below. Demand 0 1 2 3 4 5Probability 0.20 0.15 0.25 0.20 0.10 0.10

To determine the optimal order quantity and reorder policy that would minimize total cost,

the EOQ (Economic Order Quantity) model will be used.

The EOQ can be determined using the formula,

Q = √((2DCO)/CH')

Where Q = Economic Order Quantity

D = Demand'

C0 = Cost per order

H = Holding cost

C = IC per unit

Let’s assume the cost per unit, C = RM 500,

the holding cost, H = 0.2,

and demand, D = 3 units per day.

Hence,CO = RM 800 (C0 = Cost per order, which is the same as ordering cost)

Then,Q = √((2 x 3 x RM 800)/RM 100)Q = 24 units per order

Then, the reorder level can be determined using the formula,

ROL = d * LWhere L = Lead time

ROL = 3 x 5 = 15 units

The total annual cost can be determined by substituting the values into the formula,

TAC = IC + OC + HCS

where IC = 0.5 x RM 500

= RM 250OC

= (365/EOQ) x C0OC

= (365/24) x RM 800OC

= RM 12133.33HCS

= (Q/2) x H x dHCS

= (24/2) x 0.2 x 3HCS

= RM 7.20

TAC = RM 250 + RM 12133.33 + RM 7.20TAC = RM 12390.53

Hence, the order quantity that will minimize the total cost of inventory is 24 units.

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Answer:

The advantages of using a pure sine wave for your appliances and machinery are as follows: Reduces electrical noise in your machinery.

translates to no TV lines and no sound system hum.

Cooking in microwaves is quicker.

Explanation:

The smoothest signal is a sine wave, and sine waves are the basis of all functions.

Every other continuous periodic function is a basis function, which means that it can be described in terms of sines and cosines.

For instance, using the Fourier series, I can describe the fundamental Sinusoidal frequency and its multiples in terms of the triangle and square waves.

Based on the given options, the most suitable classification for women's yoga pants consisting of 93% cotton and 7% spandex knit fabric would be (d) 6104.62.2021

The correct classification of women's yoga pants consisting of 93% cotton and 7% spandex knit fabric would depend on the specific characteristics and properties of the pants. The classification is typically determined by the Harmonized System (HS), which is an international standard for classifying traded products.

To identify the correct classification, we need to analyze the different options provided:

(a) 9506.91.0030: This classification refers to "Articles and equipment for general physical exercise, gymnastics, or athletics." While yoga pants can be used for physical exercise and athletics, this classification seems more suitable for equipment or accessories used in sports activities, rather than clothing items.

(b) 6104.62.2006: This classification refers to "Women's or girls' trousers, breeches, and shorts of synthetic fibers." However, the composition of the fabric in the given description includes cotton and spandex, which are natural and synthetic fibers, respectively. Therefore, this classification does not accurately represent the fabric composition.

(c) 6104.62.2011: This classification refers to "Women's or girls' trousers, breeches, and shorts of cotton, not knitted or crocheted." Since the fabric in the given description is a knit fabric, this classification does not match the fabric construction.

(d) 6104.62.2021: This classification refers to "Women's or girls' trousers, breeches, and shorts of cotton, knitted or crocheted." This classification seems to be the most appropriate choice as it matches the fabric composition of the yoga pants, which consists of a knit fabric primarily made of cotton.

It's important to note that the final determination of the correct classification should be based on the specific regulations and guidelines provided by the relevant customs and trade authorities in the applicable country or region. The HS classification may vary slightly across different jurisdictions, and it is always recommended to consult the official classification resources for accurate and up-to-date information.

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Answer:

(b) Given the Weibull parameters of example 11-3, the factor by which the catalog rating must be increased if the reliability is to be increased from 0.9 to 0.99.

Equation 11-1: F*L^(1/3) = Constant

Weibull parameters of example 11-3: xo = 0.02 (theta-xo) = 4.439 b = 1.483

Explanation:

(a)The Catalog rating(C)

   Bearing life:\(L_1 = L , L_2 = 2L\)

   Catalog rating: \(C_1 = C , C_2 = ? ,\)

From given equation bearing life equation,

\(F\times\frac{1}{3} (L_1) = C_1 ...(1) \\\\ F\times\frac{1}{3} (L_2) =C_2...(2)\)

we Dividing eqn (2) with (1)

\(\frac{C_2}{C_1} =\frac{1}{3} (\frac{L_2}{L_1})\\\\ C_2 = C*(\frac{2L}{L})\frac{1}{3} \\\\ C_2 = 1.26 C\)

The Catalog rating increased by factor of 1.26

(b) Reliability Increase from 0.9 to 0.99

\(R_1 = 0.9 , R_2 = 0.99\)

Now calculating life adjustment factor for both value of reliability from Weibull parametres

\(a_1 = x_o + (\theta - x_o){ ln(\frac{1}{R_1} ) }^{\frac{1}{b}}\)

\(= 0.02 + 4.439{ ln(\frac{1}{0.9} ) }^{\frac{1}{1.483}} \\\\ = 0.02 + 4.439( 0.1044 )^{0.67}\\\\a_1 = 0.9968\)

Similarly

\(a_2 = x_o + (\theta - x_o){ ln(\frac{1}{R_2} ) }^{\frac{1}{b} }\\\\ = 0.02 + 4.439{ ln(1/0.99) }^{\frac{1}{1.483} }\\\\ = 0.02 + 4.439( 0.0099 )^{0.67}\\\\a_2 = 0.2215\)

Now calculating bearing life for each value

\(L_1 = a_1 * LL_1 = 0.9968LL_2 = a_2 * LL_2 = 0.2215L\)

Now using given ball bearing life equation and dividing each other similar to previous problem

\(\frac{C_2}{C_1} = (\frac{L_2}{L_1} )^{\frac{1}{3} }\\\\ C_2 = C* (\frac{0.2215L }{0.9968L} )^{1/3}\\\\ C_2 = 0.61 C\)

Catalog rating increased by factor of 0.61

One of the National Academy of Engineering's Grand Challenges for Engineering is to manage the nitrogen cycle.

This challenge aims to develop sustainable methods for efficiently using nitrogen in agricultural and industrial processes, while minimizing negative environmental impacts.

The nitrogen cycle is a natural process that involves the conversion of nitrogen between different forms in the environment. However, human activities, such as the excessive use of nitrogen-based fertilizers and the burning of fossil fuels, have disrupted this cycle and led to environmental problems.

Managing the nitrogen cycle requires finding solutions to reduce nitrogen pollution, improve nitrogen use efficiency in agriculture, develop sustainable practices for wastewater treatment, and minimize nitrogen emissions from industrial processes.

By addressing this grand challenge, engineers aim to develop innovative technologies, policies, and practices that can help restore balance to the nitrogen cycle, protect ecosystems, and ensure the sustainable use of nitrogen resources.

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Technician A is correct. Disc brake pads should be replaced when worn to the minimum allowable thickness as stated by the vehicle's manufacturer.

This is to ensure that the brakes are performing safely and efficiently. When there is a brake performance complaint, the pads should still be inspected for any signs of wear and tear. The pads may need to be replaced if they have reached the minimum allowable thickness, but it is important to inspect them to ensure that there is no other underlying cause for the performance complaint. It is important to always adhere to the manufacturer's recommended guidelines for replacing brake pads, as this will ensure that your vehicle's brakes remain safe and efficient. Failing to do so can lead to decreased brake performance, and increased stopping distances, and can even lead to brake failure in some cases.

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Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation:

RIs represents the voltage phasor across the resistor. Since the voltage across an inductor is just the inductance multiplied by the current's derivative, is (see "Key Concept", above, for explanation). Vout(t)=2.68·cos(1000·t+26.6°).

For a voltage given as v = sin t, take note that the phasor diagrams have been produced at a time of t = /2.

A sinusoidally varying quantity, like an alternating current or voltage, is represented by a rotating vector called a phasor. It is easy to simplify the challenges of managing single frequency circuits by using a phasor model.

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The given statement "Fortunately, individual irrigation systems (valve-in-head) and block irrigation systems have the exact same order of operation making troubleshooting an irrigation system a singular linear process" is FALSE because individual irrigation systems and block irrigation systems have different orders of operation.

In an individual irrigation system, each sprinkler head has its own valve, while in a block irrigation system, a group of sprinkler heads share a common valve.

Therefore, troubleshooting an irrigation system is not a singular linear process as it requires a different approach for each type of system.

For example, when troubleshooting an individual irrigation system, one needs to check each valve separately, whereas in a block irrigation system, one needs to check the common valve and its components. Understanding the differences between these systems is important for effective irrigation system maintenance and repair.

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The little dots that move between the fuel rods represent steam.

What are fuel rods?

A long, thin zirconium metal tube that holds pellets of fuel for nuclear reactors made of fissionable material. The fuel rods are bundled together into fuel assemblies, which are then put one at a time into the reactor core. The fuel rod's main functions are to maintain the fuel in a precise geometry and to act as the first line of defense between the fission products and the outside world. Therefore, maintaining its integrity is the main objective of fuel design and operating procedures for reactors. Small ceramic pellets of low-enriched uranium oxide are the fuel used in today's commercial reactors. These fuel rods are bundled into tall fuel assemblies, which are then put inside the reactor.

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gyucucugbyguhg8yiuhj7uuh/Answer:

The practice of extracting more gas from reserves by pumping water at high pressure is called hydraulic fracturing or fracking.

Hydraulic fracturing, commonly known as fracking, is a technique used in the oil and gas industry to extract natural gas from underground reserves that are trapped in tight rock formations, such as shale.

The process involves drilling a well deep into the rock formation and injecting a mixture of water, sand, and chemicals at high pressure. This high-pressure fluid creates fractures in the rock, allowing the trapped gas to flow more freely and be extracted.

The water acts as a carrier for the sand, which helps to hold the fractures open and create pathways for the gas to flow to the wellbore.

The injected chemicals serve various purposes, such as reducing friction, preventing bacterial growth, and enhancing the efficiency of the fracking process.

Once the fracturing is complete, the pressure is released, and a portion of the injected fluid flows back to the surface, along with the extracted gas. This mixture of fluid and gas is then separated, and the gas is further processed for commercial use.

Hydraulic fracturing has significantly increased the production of natural gas in many regions, providing access to previously inaccessible reserves. However, it is a controversial practice due to concerns about its potential environmental impacts, such as water contamination, seismic activity, and greenhouse gas emissions.

Overall, hydraulic fracturing, or fracking, has been instrumental in unlocking vast gas reserves and has reshaped the energy landscape. However, it is essential to carefully manage its implementation to mitigate potential environmental risks.

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Answer:

43.2%

Explanation:

Given that,

Heat absorbed by a carnot heat engine, \(Q_1=235\ kW\)

Heat rejected to the atmosphere, \(Q_2=164\ kW\)

We need ti find the thermal efficiency of the heat engine. It is equal to the ratio of output work to the energy supplied. Its mathematical form is given by :

\(\eta=1-\dfrac{Q_1}{Q_2}\\\\\eta=1-\dfrac{235}{164}\\\\\eta=-0.432\)

or

\(\eta=-43.2\%\)

The egative value of efficiency shows work is done by the engine.

Answer:

a) Here, Total No. of subscribers=N

So, the total number of lines in the network, L = \(\frac{N(N-1)}{2}\)

b) If N=2, then L=1;

If N=10, then L=45;

If N=100, then L= 4950;

If N=1000, then L= 499500.

c) In a mesh topology network with N subscribers, (N–1) lines must be built to each subscriber.

d) No it is not suitable for a public telecommunications network.

Because it is costly and complex to implement. Needs more power to active all nodes. The nodes will face redundant connection problem etc.

Explanation:

a) Because each subscriber is directly connected to all other subscribers, the network follows a mesh topology.

b) If N=2,

L=\(\frac{2*(2-1)}{2}\) = 1.

If N=10,

L= \(\frac{10*(10-1)}{2}\) = 45.

If N=100,

L= \(\frac{100*(100-1)}{2}\) = 4950

If N=1000,  

L= \(\frac{1000*(1000-1)}{2}\) = 499500.