draw the lewis structure (including resonance structures) for methyl azide (ch3n3) .

To select four species that can be identified as molecules from the given list, you should look for species that are composed of two or more atoms chemically bonded together. The correct options are:

1. CO (Carbon monoxide) - A molecule consisting of one carbon atom and one oxygen atom bonded together.
2. CO2 (Carbon dioxide) - A molecule consisting of one carbon atom and two oxygen atoms bonded together.
3. O2 (Oxygen) - A diatomic molecule consisting of two oxygen atoms bonded together.
4. CH3OH (Methanol) - A molecule consisting of one carbon, four hydrogen, and one oxygen atom bonded together.

Your answer: Four species that can be identified as molecules from the list are CO, CO2, O2, and CH3OH.

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To find the number of moles represented by a certain number of particles, you can use Avogadro's number and the concept of molar mass.

Avogadro's number (symbolized as N_A) is a fundamental constant that represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. It is approximately equal to 6.022 × 10²³ particles/mole.

Molar mass is the mass of one mole of a substance and is expressed in grams/mole. It represents the sum of the atomic masses or molecular masses of the constituent particles in a substance.

To calculate the number of moles, you can follow these steps;

Determine the number of particles you have (atoms, molecules, ions, etc.).

Identify the molar mass of the substance or the average molar mass if it's a mixture.

Divide the number of particles by Avogadro's number to convert them into moles. The formula is:

Moles = Number of Particles / Avogadro's number

Moles = Number of Particles / (6.022 ×10²³ particles/mole)

The result will give you the number of moles represented by the given number of particles.

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--The given question is incorrect, the correct question is

"Explain how you would find the number of moles that are represented by a certain number of representative particles."--

Answer:

14) The edge dislocation is more plastic than the screw dislocation

15) So as to form kinks that are fast moving

Explanation:

14) Edge and screw dislocations are the two main types of mobile dislocations

The three dimensional core of the screw dislocation prevents the slipping of the layers (one over the other) in a BCC metal such that kinks are required to be formed first  by thermal activation (heating) in order. The kinks are edge dislocation that move such that the screw dislocation moves forward

Hence, the edge dislocation is more plastic than the screw dislocation

15) The three dimensional structure of a screw dislocation acts like a wedge which resists the slipping of the layers in the BCC structure such that the screw dislocation needs to be highly thermally activated forming kinks before the surrounding layers can move.

Answer:

a

Explanation:

The element that has two electrons in its 4d sublevel is Ruthenium (Ru) with the atomic number of 44.

Ruthenium (Ru) is a rare transition metal from the platinum group of the periodic table. It is a hard, brittle, silvery-white metal with a slight bluish tint and an atomic number of 44. Ruthenium is one of the densest materials, and it has four stable isotopes. It is commonly found in ores containing other platinum metals.

Ruthenium is frequently used in electrical contacts due to its hardness, wear resistance, and low contact resistance. It is also utilized in some alloys with platinum and other platinum-group metals to make wear-resistant electrical contacts. Ruthenium can also be used as a catalyst in some chemical reactions. It can oxidize and reduce many molecules, making it useful in various oxidation-reduction reactions.

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1.  the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.  the final concentration of KOH after adding 550 mL of water to 125 mL of 3.01 M KOH solution is approximately 0.557 M.

1.) If 125 mL of water is added to 45.3 mL of a 0.71 M NaOH solution, the resulting solution will be a diluted NaOH solution. The addition of water will increase the total volume while reducing the concentration of NaOH. To determine the final concentration of NaOH, we need to consider the conservation of moles.

First, let's calculate the moles of NaOH in the initial solution:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.0453 L × 0.71 M = 0.0321433 moles

After adding 125 mL (0.125 L) of water, the total volume of the solution becomes 0.0453 L + 0.125 L = 0.1703 L.

To find the final concentration, we divide the moles of NaOH by the total volume:

final concentration of NaOH = moles of NaOH / total volume

final concentration of NaOH = 0.0321433 moles / 0.1703 L ≈ 0.189 M

Therefore, the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.) If 550 mL of water is added to 125 mL of a 3.01 M KOH solution, the resulting solution will also be a diluted solution. Again, we will apply the conservation of moles to determine the final concentration of KOH.

First, calculate the moles of KOH in the initial solution:

moles of KOH = volume (in L) × concentration (in M)

moles of KOH = 0.125 L × 3.01 M = 0.37625 moles

After adding 550 mL (0.55 L) of water, the total volume of the solution becomes 0.125 L + 0.55 L = 0.675 L.

To find the final concentration, divide the moles of KOH by the total volume:

final concentration of KOH = moles of KOH / total volume

final concentration of KOH = 0.37625 moles / 0.675 L ≈ 0.557 M

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Answer:

It's D

Explanation:

Option 2) Bromoethane and methanol is correct

The major products obtained upon treatment of ethyl methyl ether with excess HBr are Bromoethane and methanol.

What is ethyl methyl ether?

Ethyl methyl ether is a colorless gas that is used as a solvent. The IUPAC name for this compound is methoxyethane. It is a member of the ether family of compounds. When ethyl methyl ether reacts with excess HBr, it undergoes a substitution reaction and forms Bromoethane and methanol. The mechanism for this reaction is given below: Methoxyethane reacts with hydrogen bromide to produce methanol and ethyl bromide (bromoethane). Here are the products that are formed in this reaction: Bromoethane (C2H5Br) and Methanol (CH3OH)

The chemical equation for this reaction can be written as: CH3OCH2CH3 + HBr → CH3OH + CH3CH2Br \(\boxed{Option\ 2)}\)

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The PESTLE and SWOT analyses provide a comprehensive assessment of the external and internal factors influencing the Harvard case "Clean Edge Razor: Splitting Hairs in Product Positioning."

The PESTLE analysis examines the external factors that may impact the case. Politically, regulations on product safety and environmental sustainability could affect the razor industry. Economically, consumer purchasing power and economic trends may impact the demand for high-end razors. Sociocultural factors, such as grooming habits and preferences, influence consumer behavior. Technological advancements, such as electric razors and online shopping, pose opportunities and challenges. Legal factors include intellectual property rights and advertising regulations. Environmental considerations involve sustainability and eco-friendly practices.

The SWOT analysis evaluates the internal strengths and weaknesses of the case. Strengths may include the Clean Edge brand reputation and innovative product features. Weaknesses could involve high manufacturing costs or limited market presence. Opportunities may arise from market growth and expanding into new segments. Threats may come from intense competition and changing consumer preferences.

By conducting both analyses, the case can gain insights into the broader industry landscape, identify potential risks and opportunities, and assess its own internal capabilities. This holistic understanding aids in making informed decisions and formulating effective strategies for positioning the Clean Edge Razor product.

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Answer:

I just did it home slice the first one's Ag+ and Zn2+ and the second one is A

Explanation:

I just did the assignment

Answer:

ag+ and zn2+

Explanation:

second question is A

The majority of the lead(II) iodide in the solution precipitates out as a yellow solid flag.

Define lead iodide?

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Answer:

solution of K3PO4?

1.31 m

2.

Concentration of Chloride Ions in a 0.193m solution of Potassium Chloride is _______.

0.193 m

3.

Concentration of Iodide ions in a 0.193 solution of Barium iodide is _________.

0.386 m

4.

In a Titration of 35.00 mL of 0.737 m H2So4, _______ mL of a 0.827 m KOH solution is required for neautralization.

62.4

5.

Consider the following reactions

AgNo3 ------>

Co(No3) ---->

AgNo3 ---->

Which is the correct order of increasing activity for these metals?

Ag < Co < Zn

6.

There are ______ Mol of bromide ions in 0.500 L of a 0.300M solution of AlBr3

0.450 m

7.

How many grams of Sodium Chloride are there in 550 mL of a 1.90 m aq solution of sodium CL?

6.11 g

8.

The total concentration of ions in a 0.250 M solution of HCL is _______?

0.500 m

9.

How many moles of Co 2+ are present in 0.200 L of a 0.400 M solution of Co I2

0.0800

10.

A Neautralization reaction between an acid and a metal hydroxide produces

Water and a salt

11.

7 Strong Acids

Claire HCl

Brian HBr

invented HI

nutrious HNo3

(3)candy HClO3

(2,4)sold H2So4

(4)profit HClO4

12.

8 strong bases

Lily LiOH Lithium Hydroxide

never NaOH Sodium Hydroxide

knew KOH PossasiumHydroxide

Robert RbOH

could ClOH

bake Ba(OH)2

strawberry Sr(OH)2

cake Ca(OH)2

13.

What are the spectators ions in the reaction between KOH(aq) and HNO(aq)

HF + OH ---> H2O + F-

14.

Combining Aq solution of BaI2 and Na2So4 affords a precipitate of BaSO4

Which Ions is/are spectator ions in the reaction?

Na + and I -

15.

The Spectator ions in the react between aq Hydrochloric acid and Aq Ammonia

Are ________

B. Cl - only

16.

Spectator ions of aq hydrofluoric acid and aq barium hydroxide are _________

D. Ba 2+ only

17.

Spectator ions in reactions

Aq perchloric acid and Aq barium hydroxide are >>>>>>>

ClO 4- and Ba 2+

To solve this we must be knowing each and every concept related to concentration and its calculation.  Therefore,  the concentration that of chloride ions in a 0.193 m solution of potassium chloride is 0.193 m.

There are two components in an aqueous solution: the solute and the solvent. You must be familiar with these two fundamental terminology for solution concentration. The quantity of solute present in the solution must always be recorded.

A solution's concentration can be expressed in a variety of ways. Chemists frequently work with moles when doing their tasks. In place of the number of moles, pharmacists will utilize percentage concentrations. 

KCl\(\rightarrow\) K⁺ + Cl⁻

concentration of KCl= concentration of K⁺= concentration of  Cl⁻ = 0.193 m

Therefore,  the concentration that of chloride ions in a 0.193 m solution of potassium chloride is 0.193 m.

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Answer:

Electrons have a negative charge and are found in the area of an atom called Outer Shell

Electrons have a negative charge and are found in the area of an atom called electron shells.

Answer:

grams NH3 is equal to 0.058718113128665 mole.

Explanation:

Answer:

3 moles

Explanation:

Use the mole = mass/mr equation

so, mole = 51/17 = 3 moles

At 46.40 degrees Celsius and 897.00 mmHg, 6.20 liters of oxygen gas will contain a mass of 26.37 grams.

Oxygen is an element that is essential to life as we know it. It is a colorless, odorless, tasteless gas that makes up about 21% of the Earth's atmosphere. In its natural form, oxygen is made up of molecules of two oxygen atoms bonded together. Oxygen is vital to all living organisms, including humans, and is necessary for respiration and combustion. Oxygen plays a major role in many chemical processes, such as the burning of fuel, the corrosion of metals, and the formation of acids and bases. It is also an important component of environmental cycles, such as the water cycle and the carbon cycle.

897.00 mmHg = 897.00 mmHg × (1 atm / 760 mmHg) ≈ 1.17934 atm

46.40 °C + 273.15 = 319.55 K

Now, let's rearrange the ideal gas law equation to solve for the number of moles (n):

n = PV / RT

Plugging in the given values:

n = (1.17934 atm × 6.20 L) / (0.0821 Latm/molK × 319.55 K)

Simplifying the equation, we find:

n ≈ 0.2839 moles

To calculate the mass of O₂ gas, we need to multiply the number of moles by the molar mass of O₂:

Molar mass of O₂ = 32.00 g/mol

Mass of O₂ = 0.2839 moles × 32.00 g/mol ≈ 9.0928 g

Therefore, there are approximately 9.0928 grams of O₂ gas in the 6.20 L container at a pressure of 897.00 mmHg and a temperature of 46.40°C.

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Answer:

All of these stoichiometry problems are worked alike. Here is the 4 step process.

4Na + O2 → 2Na2O

Step 1. Write and balance the equation. You have that.

Step 2. Convert whatever you have to mols. If a solid then mols = grams/molar mass = ?. If a solution then mols = M x L = ? In this case, the molar mass of Na2O is approx 62 so mols = 2/62 = approx 0.03 but that's just a close guess. You should do it more accurately.

Step 3. Using the coefficients in the balanced equation, convert mols of what you have to mols of what you want. You have mols Na2O and you want to convert that to mols Na.

0.03 mols Na2O x (4 mols Na/2 mols Na2O) = about 0.06. Note that mols Na2O in the numeratorof the first term cancels with mols Na2O in the denominator of the second term which leaves mols Na which is what you want. In practice you ALWAYS know that the coefficient of the unit you are converting to goes on top and the coefficient of mols you have goes on the bottom.

4. Now convert mols of what you want to grams. grams = molsl x molar mass - about 0.06 x 23 = about ?

Copy this. It can come in handy for every chemistry course you take.

Explanation:

According to the stoichiometry of the given chemical equation, 1.703 g of sodium is needed to make 2 g sodium oxide.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.It is used in balancing chemical equations and preparation of solutions.From the given chemical equation, 92 g sodium gives 108 g sodium oxide, thus, 2 g is prepared by 92×2/108=1.703 g of sodium.

Thus, according to the stoichiometry of the given chemical equation, 1.703 g of sodium is needed to make 2 g sodium oxide.

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The reaction of the hydrogen and the chlorine atoms would lead to the formation of HCl

In this reaction, each chlorine molecule (Cl2) breaks apart into two chlorine atoms (Cl), and each hydrogen molecule (H2) breaks apart into two hydrogen atoms (H). These reactive atoms then combine to form hydrogen chloride molecules (HCl).

It's worth noting that the reaction between hydrogen gas and chlorine gas is highly exothermic and releases a significant amount of energy.

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Answer: C: Sodium donates an electron to chlorine.

Explanation:

Sodium wants to lose an electron and chlorine wants to gain an electron to become stable. This is because of their place in the periodic table, sodium being on the very left edge and chlorine on the very right (noble gasses dont count as they are stable to begin with)

Therefore sodium will donate to chlorine so they both become stable with an ionic bond. (another way to tell its ionic is the very large difference in electronegativity)

When table salt forms, sodium donates an electron to chlorine resulting in the formation of bond which is formed when the electronic configurations become stable.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Plants produce glucose and oxygen in an endothermic reaction called photosynthesis. The mass of glucose, C6H12O6, made when 1.0g of water reacts with carbon dioxide is 60gm.

Photosynthesis is a process used by plants and other organisms to change light energy into chemical energy that, through cellular respiration, can later be passed to fuel the organism's activities.

6H₂O + 6CO₂ CH12O6 + 602

We must convert the water to moles. We know that the molar mass of

Water 18

= 1 / 18

= 0.055

Now we look at our chemical equation's mole ratios. We can see that

6 moles of water produce 1 mole of glucose.

therefore, we will have 1/3 mol of glucose

The molar mass of glucose is 180

= 60gm of glucose will produce.

Thus, the mass of glucose, C6H12O6, made when 1.0g of water reacts with carbon dioxide is 60gm.

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The standard entropy change for the reaction at 25 °C is -101.6 J/(mol·K).To calculate the standard entropy change for the reaction at 25 °C, we need to use the standard molar entropy values from the table and apply them to the stoichiometry of the reaction.

The equation for the reaction is:

MgCl2(s) + H2O(l) ⟶ MgO(s) + 2HCl(g)

The standard molar entropy values for the substances involved in the reaction are:

MgCl2(s): 95.2 J/(mol·K)
H2O(l): 69.9 J/(mol·K)
MgO(s): 26.9 J/(mol·K)
HCl(g): 186.9 J/(mol·K)

The entropy change (ΔS) for the reaction can be calculated using the formula:

ΔS = ΣnSf - ΣnSi

where ΣnSf is the sum of the standard molar entropy values of the products and ΣnSi is the sum of the standard molar entropy values of the, each multiplied by their stoichiometric coefficients (n).

ΔS = [1(26.9 J/(mol·K)) + 2(186.9 J/(mol·K))] - [1(95.2 J/(mol·K)) + 1(69.9 J/(mol·K))]

ΔS = -101.6 J/(mol·K)

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Answer:

C12H22O11

Explanation:

The correct option is (a) 1,000,000ºK.

The temperature of the Sun's corona is most nearly equal to option (a) 1,000,000ºK. The corona is the outermost layer of the Sun's atmosphere and is composed of highly ionized gas. The temperature of the corona is much higher than the temperature of the Sun's visible surface (the photosphere), which has a temperature of about 5,500 ºC (or 5,800 ºK). The reason for the high temperature of the corona is still not fully understood, but it is thought to be related to the Sun's magnetic field and the transfer of energy from the Sun's interior to its outer atmosphere.

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There are approximately 7.5 grams of potassium chloride (KCl) present in the 500.0 mL sports drink.

To determine the amount of potassium chloride (KCl) present in the 500.0 mL sports drink, we need to calculate the mass of KCl based on the given percentage composition. Given:

Volume of sports drink = 500.0 mL

Percentage of KCl by mass = 1.5%

To find the mass of KCl, we can use the formula:

Mass of KCl = Percentage composition x Total mass of the solution

First, we convert the volume of the sports drink from millilitres to grams assuming the density of the solution is 1 g/mL:

Mass of the solution = Volume of the solution x Density

Mass of the solution = 500.0 mL x 1 g/mL

Mass of the solution = 500.0 g

Next, we calculate the mass of KCl using the percentage composition:

Mass of KCl = (Percentage of KCl / 100) x Mass of the solution

Mass of KCl = (1.5 / 100) x 500.0 g

Mass of KCl = 0.015 x 500.0 g

Mass of KCl = 7.5 g

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Explanation:

An environmentally sustainable society is one that seeks to minimize the impacts of using natural capital to generate natural income through the economy.

We live in an increasingly industrialized and globalized society, where there is great competition between competitors to generate profitability, and several of the resources used in industrial activities are the planet's natural resources, which are scarce and can generate a series of losses for nature. and for the quality of life of future generations.

Therefore, it is important that society increasingly covers companies with environmentally responsible attitudes, where there is a minimization of impacts on nature and the development of sustainable technologies, in order to preserve the environment and the quality of life of humanity.

It is also important to note that environmentally sustainable attitudes help in the global positioning of companies and transmit much more value to their stakeholders, which translates into the achievement of strategic advantages for companies.

Answer:

The correct answer would be

B. silver chloride

Explanation:

I hope this helps, have a great day!

The precipitate would be silver chloride.

These are reactions that lead to the formation of insoluble salts.

According to the law of solubility, all chloride salts are soluble except those of lead and silver.

Thus, the silver chloride formed from the reaction between silver nitrate and sodium chloride would be the precipitate.

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Since the solubility of NaNO3 in water at 30 ∘C as 94.9⋅g per 100 g, the solution is unsaturated.

At a specific temperature and pressure, an unsaturated solution is one in which the maximum amount of solute has not yet completely dissolved in the solvent. In other words, more solute can dissolve in the solution.

There is no net change in the amount of dissolved solute when the rate of precipitation and the rate of solute dissolution are equal at equilibrium.

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Answer:

Fnet = 13920 Newtons

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

\( Fnet = Fapp + Fg\)

Where;

Given the following data;

Mass, m = 800 kg

Acceleration, a = 7.6m/s²

To find the applied force;

\( Fapp = ma\)

Substituting into the equation, we have;

\( Fapp = 800 * 7.6\)

Fapp = 6080N

To find the gravitational force;

We know that acceleration due to gravity, g = 9.8m/s²

\( Fg = mg\)

Substituting into the equation;

\( Fg = 800 * 9.8\)

Fg = 7840N

To find the net force;

\( Fnet = Fapp + Fg\)

Substituting into the equation, we have;

\( Fnet = 6080N + 7840N\)

Fnet = 13920 Newton.

Therefore, the net force experienced is 13920 Newton.

Answer:

It would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate

Explanation:

Using the balanced chemical equation and the molar mass of aluminum nitrate provided, we can calculate the amount of aluminum nitrate produced from the given mass:

1 mole of aluminum nitrate (Al(NO3)3) has a mass of 213.01 g.

So, 5.4 g of Al(NO3)3 is equivalent to (5.4 g) / (213.01 g/mol) = 0.0254 mol.

From the balanced chemical equation, we can see that 3 moles of beryllium nitrate (Be(NO3)2) produce 2 moles of aluminum nitrate. So, the amount of beryllium nitrate needed to produce 0.0254 mol of aluminum nitrate is:

(0.0254 mol Al(NO3)3) x (3 mol Be(NO3)2 / 2 mol Al(NO3)3) = 0.0381 mol Be(NO3)2

Now we can use the concentration and the amount of beryllium nitrate to calculate the volume of the solution required:

0.0381 mol of Be(NO3)2 is present in (0.0381 mol) / (1.75 mol/L) = 0.0218 L = 21.8 mL of 1.75 M beryllium nitrate solution.

Therefore, it would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate, assuming the reaction proceeds to completion.

The density of an object is its mass divided by its volume. To find the volume of the object, we can use the formula for the volume of a rectangular prism:

V = l * w * h

Where:

V = Volume

l = length

w = width

h = height

In this case:

V = 2.2cm * 0.8cm * 1.7cm = 2.976 cm^3

To convert the mass from grams to grams per cubic centimeter, we need to convert the volume from cubic centimeters to cubic meters.

1cm^3 =10^-6 m^3. so 2.976cm^3 = 2.976*10^-6 m^3

So the density of the object is:

density = mass/volume = 5.4g / 2.976*10^-6 m^3 = 1817.5 kg/m^3

Now we can compare the density of the object to the density of water which is 1000 kg/m^3.

Since the density of the object is greater than the density of water, the object will not float on water.