Drag the tiles to the correct boxes to complete the pairs.
Match each solution to the equation it solves.

Answer:

30 cards

Step-by-step explanation:

12 is 36% of 30. we round the 36% to 40% since one card is wroth more than 4%.

Answer: 35 times 50% is 17.5 so she got a 40% discount because 35 times 40% equals 14

Step-by-step explanation:

You have to do first 35•50% and get your answer and if it’s not the right number then go up or down and I went down 10 and got 14 when I did 35•40%

In this problem the diagonal of the Tv is 19 and the hight is 11 so we can use the pythagorical theorem to find the width (w) so:

and we solve for w so

Yes, triangle inequality theorem apply to all equilateral triangles.

The triangle inequality theorem explains the relation between a triangle's three sides. This theorem states that for any triangle, the sum of the lengths of the first two sides is always greater than the length of the third side. In other terms, this theorem states that a straight line is always the shortest distance between any two places.

So Triangle inequality theorem is not only valid for all equilateral traingles but it is valid for all traingles.

A Triangle is only formed is if follows Triangle inequality theorem so every equilateral triangle needs to follow this theorem.

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Answer:

70

Step-by-step explanation:

solution

total balls: 100

red balls:70

blue balls: 30

balls picked:5

Now,

probability of all picked balls being red: 70

Answer: 70



Step-by-step explanation:

The probability of picking a red ball on a single draw is 70/100 = 0.7 since there are 70 red balls out of 100 total balls.

With replacement means that after each draw, the ball is placed back into the pool, so the total number of balls remains the same.

Therefore, the probability of picking all five red balls can be calculated as follows:

P(5 red balls) = (0.7)^5 = 0.16807

So the probability of picking all five red balls with replacement is approximately 0.16807 or 16.807%.

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With a dilation factor of 1 / 4, Polygon ABCD with vertices at A(−4, 6), B(−2, 2), C(4, −2), D(4, 4) would be: A(-1, 1.5), B(-0.5 , 0.5), C(1, -0.5), D(1 , 1). Second option

The solution to the problem would be the solution that is gotten when we divide these points by 1/4. This is the dilation factor

we would have:

A(−4, 6), B(−2, 2), C(4, −2), D(4, 4)

= (-4 * 1/4, 6 * 1/4) , B(-2 * 1/4, 2 * 1/4), C(4 * 1/4, -2 * 1/4), D(4 * 1/4, 4 * 1/4)

= A(-1, 1.5), B(-0.5 , 0.5), C(1, -0.5), D(1 , 1)

Hence the second option is correct.

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Answer:A′(−1, 1.5), B′(−0.5, 0.5), C′(1, −0.5), D′(1, 1).

Step-by-step explanation:

To dilate a point using a scale factor, you multiply both the x-coordinate and the y-coordinate of the original point by the scale factor.

Given the original vertices of the polygon ABCD and a scale factor of one fourth (1/4), we can find the coordinates of the dilated vertices A', B', C', and D':

Original vertex A(-4, 6):

x-coordinate of A': -4 * 1/4 = -1

y-coordinate of A': 6 * 1/4 = 1.5

So, vertex A' is (-1, 1.5).

Original vertex B(-2, 2):

x-coordinate of B': -2 * 1/4 = -0.5

y-coordinate of B': 2 * 1/4 = 0.5

So, vertex B' is (-0.5, 0.5).

Original vertex C(4, -2):

x-coordinate of C': 4 * 1/4 = 1

y-coordinate of C': -2 * 1/4 = -0.5

So, vertex C' is (1, -0.5).

Original vertex D(4, 4):

x-coordinate of D': 4 * 1/4 = 1

y-coordinate of D': 4 * 1/4 = 1

So, vertex D' is (1, 1).

Comparing the calculated coordinates with the options given:

A′(−1, 1.5), B′(−0.5, 0.5), C′(1, −0.5), D′(1, 1)

Among the given options, the correct vertices of polygon A′B′C′D′ are A′(−1, 1.5), B′(−0.5, 0.5), C′(1, −0.5), D′(1, 1).

(a) \($P(\text{drives or public transportation}) = P(\text{drives})\) + \(P(\text{public transportation}) = 0.796 + 0.069 = 0.865$\)

(b)\($P(\text{neither drives nor takes public transportation})\) = 1 - \(P(\text{drives or public transportation}) = 1 - 0.865 = 0.135$\)

(c) The probability that a randomly selected worker primarily does not drive a bicycle to work is the complement of the probability that they do drive:

\($P(\text{does not drive}) = 1 - P(\text{drives}) = 1 - 0.796 = 0.204$\)

(d) No, the probability that a randomly selected worker primarily walks to work cannot equal 0.25. The only given probabilities are for driving and taking public transportation, and no information is provided about the probability of walking.

Therefore, it is not possible to determine the probability of walking to work based on the given information.

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To determine the t-statistic for determining the significance of the relationship between the midterm score and grade on the final exam, we need information as the sample size (n) and the degrees of freedom (df).

Without these values, we cannot calculate the exact t-statistic.

However, the t-statistic is typically calculated using the formula t = r * sqrt((n-2)/(1-r^2)), where r is the correlation coefficient and n is the sample size. In this case, the correlation coefficient is 0.30.

The t-statistic measures the strength and significance of the relationship between the variables. A larger t-value indicates a stronger relationship and a higher likelihood of statistical significance.

To determine whether the relationship is significant, we compare the calculated t-value to the critical value from the t-distribution for the given degrees of freedom.Without the specific values for sample size and degrees of freedom, we cannot provide the exact t-statistic in this case.

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Answer:

answer below

Step-by-step explanation:

1) mean: divide the total value of numbers by the number of variables.

12 + 46 + 32 + 18 + 26 + 41 + 46 = 221 / 7 = 31.5714285714 = 32 or 31.6

2) mode: most frequent #

So in this case you can just look at what number is repeated the most, which is 46 since it’s repeated twice.

3) median: the middle # in the list of #’s when ordered lowest to highest.

Lowest — highest

12  18  26  32  41  46  46

4) range: the difference between the lowest and highest # in the list

Lowest - 12

Highest - 46

46 - 12 = 34

Answer:

5

Step-by-step explanation:

The expected value of a continuous random variable is a measure of its central tendency or average value, while the variance is a measure of its variability or spread around the mean.

The expected value or mean of a continuous random variable X is defined as:

E[X] = ∫ xf(x) dx

where f(x) is the probability density function (pdf) of X, and the integral is taken over all possible values of X.

The variance of a continuous random variable X is defined as:

Var(X) = E[(X - μ)²]

where μ is the mean of X (i.e., E[X]), and the expectation is taken over all possible values of X. Alternatively, the variance can also be calculated as:

Var(X) = ∫ (x - μ)² f(x) dx

where f(x) is the probability density function (pdf) of X, and the integral is taken over all possible values of X.

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Answer:

A right triangle is a triangle that has 90 degrees angle in one of its parts. You are given two points that have coordinate:

x1,y1= (-2, 4)

x2,y2= (-1,1)

To make the angle 90 degrees, there is two possible third point coordinate:

1. x1, y2 = (-2,1)

2. x2, y1= (-1,4)

The right triangle would be option C: (-2,1)

Option A and B is not a right triangle

Step-by-step explanation:

Answer:

the coordinates of vertex E is (6,0)

C(2,0),compare this to(2,4)

same x.but y=0

(6,0)comparing to (6,12)

we get it

The perimeter of square ABCD is 28 units.

The perimeter of a square is the sum of all its sides. In this case, we need to find the perimeter of square ABCD.

The question provides two possible answers: 28 units and 37 units. However, we can only choose one correct answer. To determine the correct answer, let's think step by step.

A square has all four sides equal in length. Therefore, if we know the length of one side, we can find the perimeter.

If the perimeter of the square is 28 units, that would mean each side is 28/4 = 7 units long. However, if the perimeter is 37 units, that would mean each side is 37/4 = 9.25 units long.

Since a side length of 9.25 units is not a whole number, it is unlikely to be the correct answer. Hence, the perimeter of square ABCD is most likely 28 units.

In conclusion, the perimeter of square ABCD is 28 units.

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Answer:

???

Step-by-step explanation:

Answer:

\( m\angle XYZ = 70\degree \)

Step-by-step explanation:

By exterior angle theorem:

4x° = 2x° + 70°

4x° - 2x° = 70°

2 x° = 70°

2x = 70

x = 70/2

x = 35

\( m\angle XYZ = 2x\degree \)

\( m\angle XYZ = 2\times 35\degree \)

\( m\angle XYZ = 70\degree \)

Answer:

A little less than 320

Step-by-step explanation:

Round the miles to 168 and 150

Add together 168 + 150 = 318

Answer: a. a little less than 320

Answer:

1.11 and the tip is 2.78

Step-by-step explanation:

imagine having the whole like 19 the half is 9.5 and 1/4 is 4.75 you work your way down until you reach the 6 percent and get 1.11.

Answer:

letter P

Step-by-step explanation:

From among the five answer choices shown, select the letter that comes next in the series in the question.

24Y, 20E, 16A, 12U, 8

From the 5 options given, the letter that comes next is P because from U to letter P is 5 points away,

Answer:

44 <= x

Step-by-step explanation:

Bristol is the cheapest city and Paul can drop from his plans to stay under budget.

To determine which city Paul can drop and still stay under budget, we need to find the total cost of visiting all four cities and compare it to Paul's budget of £300.

We do not have information about the cost of sightseeing in each city, so we will assume that the cost is the same for each city. In that case, the cost of visiting all four cities is:

Cost of visiting all cities = Cost of visiting one city x 4

Let's call the cost of visiting one city "x". Then:

Cost of visiting all cities = x * 4

To stay under budget, the cost of visiting all cities must be less than or equal to £300. So we can write the following inequality:

Simplifying this inequality, we get:

x ≤ £75

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The answer is (c) Bristol, as it has the highest cost among the remaining cities and dropping it would leave Paul with 224 pounds, which is still within his budget.

A budget is whenever one plans on how to spend an estimated income. All the income should be considered as well as all the expenses. In other words, it is an expending plan.

The total cost of visiting all cities is:

76 + 66 + 91 + 60 + 72 = 365

To stay under budget, Paul must drop at least one city. To determine the cheapest city to drop, we can calculate the cost of the trip to each city if visited individually and compare it to the remaining budget:

- Bristol: 76 pounds

 Remaining budget: 300 - 76 = 224 pounds

- Leicester: 66 pounds

 Remaining budget: 300 - 66 = 234 pounds

- Glasgow: 91 pounds

 Remaining budget: 300 - 91 = 209 pounds

- Leeds: 60 pounds

 Remaining budget: 300 - 60 = 240 pounds

- Belfast: 72 pounds

 Remaining budget: 300 - 72 = 228 pounds

The city that Paul can drop while staying under budget is the one with the lowest cost.

Therefore, the answer is (c) Bristol, as it has the highest cost among the remaining cities and dropping it would leave Paul with 224 pounds, which is still within his budget.

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Answer:

x=23 miles

Step-by-step explanation:

Using the formal 62.55 = 4.25 + 2.65x

62.55 - 4.25 = 58.3

58.30=2.65x

58.30/2.65=x

22=x

Dont forget to add in the 1st mile

23 total miles

The mean exam score of student 2 for all four exams is 87.5.  Based on the information provided, you have a spreadsheet containing the scores of 50 students on 4 different exams. To calculate the mean exam score for Student 2 across all four exams, you need to follow these steps:

1. Locate the scores for Student 2 on all four exams. They should be on the first sheet of the spreadsheet and likely in a row or column corresponding to Student 2.

2. Add the scores of Student 2 for all four exams together. For example, if their scores were 80, 85, 90, and 95, the total would be 80 + 85 + 90 + 95 = 350.

3. To calculate the mean, divide the total score (from step 2) by the number of exams (which is 4 in this case). Using the example scores above, the mean would be 350 / 4 = 87.5.

So, the mean exam score for Student 2 for all four exams is 87.5. Keep in mind that this example assumes hypothetical exam scores; you will need to replace them with the actual scores found in the spreadsheet to obtain the correct mean score for Student 2.

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The length of the diagonal should be 17 ft.

To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the diagonal of a right triangle is equal to the sum of the squares of the lengths of the other two sides.

Let's call the length of one wall 8 ft and the length of the other wall 15 ft. If the corner of the room is square, then the diagonal forms the hypotenuse of a right triangle.

So, using the Pythagorean theorem:

diagonal^2 = 8^2 + 15^2

diagonal^2 = 64 + 225

diagonal^2 = 289

Taking the square root of both sides:

diagonal = √289

diagonal = 17 feet

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Answer:

the answer is 2

Step-by-step explanation:

The equation which represent the three squares which is divided into the 5 fifths is,

\(15 \times \dfrac{1}{5} = 3\)

A fraction number is the number which is a part of a whole number. It is written with a numerator and denominator. Fraction number are written as,

\(\dfrac{a}{b}\)

Here (a) is the numerator and (b) is the denominator.

A multiple of a fraction is the number which is n times of the original function.

The model represents,

\(3 \div 1/5\)

Here, the total number of square are given is 3. These three square are then divided into the one fifth.

Thus, we get total 3 times of 5 one fifth which is equal to the entire 3 squares

.

Thus, the equation can be written for this condition as,

\(15 \times \dfrac{1}{5} = 3\)

Hence, the equation which represent the three squares which is divided into the 5 fifths is,

\(15 \times \dfrac{1}{5} = 3\)

Option B is the correct option.

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a) Approximately 29.50% of brake pads will contain less than 32.5% copper. b)  The approximate distribution of the sample mean copper percentage is a normal distribution with mean 34 and standard error 0.7.

a)To solve this problem, we can use the z-score formula to standardize the value of 32.5 using the mean and standard deviation given:

z = (x - μ) / σ

where x is the value we are interested in (32.5), μ is the mean (34), and σ is the standard deviation (2.8).

Substituting these values, we get:

z = (32.5 - 34) / 2.8 = -0.536

Using a standard normal distribution table or calculator, we can find the probability of a z-score less than -0.536, which is approximately 0.2950 or 29.50%. Therefore, approximately 29.50% of brake pads will contain less than 32.5% copper.

b) The sample mean copper percentage of 16 pads will also follow an approximate normal distribution with mean μ = 34 and standard deviation σ/√n = 2.8/√16 = 0.7, where n is the sample size.

Therefore, the approximate distribution of the sample mean copper percentage can be expressed as:

X ~ N(34, 0.7)

where X is the sample mean copper percentage.

The mean of this distribution is equal to the population mean μ, which is 34. The standard error of the mean (also known as the standard deviation of the sampling distribution) is given by σ/√n, which is 0.7 in this case.

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Your question is incomplete, but probably the complete question is :

Assume the distribution of copper content (%) in sintered brake pads follows an approximate normal distribution with a mean of 34 and a standard deviation of 2.8

a.) What percentage of brake pads will contain less than 32.5% copper?

b.) What is the approximate distribution of the sample mean copper percentage if we sample 16 pads? Include the mean and standard error of this distribution

Answer:

0=0 1=1   6<8

Since 6 < 8  0.16 < 0.18

so, the hummingbird weighs more than a nickel

Step-by-step explanation:

6 is less than 8 so therefore .16 is less than .18. The nickel weighs .18 and .16 is less than that.

Answer: The 90% confidence interval for the population mean of the length of text messages is a range of values that is likely to contain the true population mean with a probability of 0.90 (or 90%). Based on the given information, we can calculate the confidence interval as follows:

Standard error of the mean (SE) = σ / sqrt(n)

where σ is the population standard deviation, n is the sample size, and sqrt denotes the square root.

SE = 3 / sqrt(22) ≈ 0.639

Margin of error (ME) = t(α/2, df) × SE

where t(α/2, df) is the critical value from the t-distribution with df degrees of freedom, and α is the level of significance (1 - confidence level).

For a 90% confidence level and 21 degrees of freedom (df = n - 1), the critical value is approximately 1.717.

ME = 1.717 × 0.639 ≈ 1.098

The confidence interval can be calculated as:

CI = sample mean ± ME

= 31 ± 1.098

= (29.902, 32.098)

Therefore, we can say that we are 90% confident that the true population mean of the length of text messages falls between 29.902 and 32.098 characters. In other words, if we were to repeat the sampling process many times and construct a 90% confidence interval for each sample, we would expect 90% of the intervals to contain the true population mean. Additionally, we can interpret the margin of error as the maximum amount that the sample mean is expected to differ from the true population mean, with a probability of 90%.

Step-by-step explanation:

The remainder when x³ - 1 is divided by (x + 3) is  -28

The functions are given as

x 3 1 is divided by x 3

Rewrite them as

f(x) = x³ - 1 is divided by (x + 3)

Set the divisor to 0

So, we have

x + 3 = 0

Determine the value of x

This gives

x = -3

By the remainder theorem

Substitute x = -3 in the function f(x)

So, we have

f(-3) = (-3)³ - 1

Evaluate the expression

f(-3) = -28

By the remainder theorem, this represents the remainder

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The given statement When inserting a value into a partially-filled array in descending order, the insertion position is indeed the index of the first value smaller than the value being inserted is true.

What is partially filled array?

A partially filled array, also known as a sparse array, is an array data structure where not all elements are populated with values. In other words, it is an array that contains empty or uninitialized elements.

When inserting a new value into this sorted array, we start from the beginning and compare the value with each existing element until we find the first element that is smaller. The insertion position for the new value is the index of this first smaller element.

For example, if we have a partially-filled array [10, 8, 5, 3] and we want to insert the value 6 into the array in descending order, we compare 6 with each element from left to right. The first element smaller than 6 is 5, and its index is 2. Therefore, the insertion position for the value 6 would be index 2, resulting in the updated array [10, 8, 6, 5, 3].

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