Drag and drop each word or phrase into the type of plate boundary it describes.
plates collide
Divergent Boundary Convergent Boundary
Transform Boundary
volcanoes and mountains
forms mid-ocean ridges
earthquakes
plates move apart
plates slide past each other

To find the mass percent composition of an element, divide the mass contribution of the element by the total mass then multiply by 100.

The total mass = 200.0 g

Phosphorus mass = 87.28 g

Oxygen mass = 112.72 g

%composition of P:

=> (87.28 g/200.0g)*100

=> 43.64 %

%composition of O:

=> (112.72g/200.0 g)*100

=> 56.36 %

Answer

c. Litmus Is red phenolphthalein is colorless

Explanation

A solution with a pH of 3 is acidic. The main use of litmus is to test whether a solution is acidic or basic, blue litmus turns red under acidic conditions, and red litmus turns blue under basic or alkaline conditions. Phenolphthalein is often used as an indicator in acid–base titrations. phenolphthalein, it turns colorless in acidic solutions and pink in basic solutions.

Therefore, the correct option for a solution with a pH of 3 is:

c. Litmus Is red phenolphthalein is colorless

Answer:

Hello How are you

Explanation: the answer might be Screenshot

Answer: Wire gauze is an essential piece of supporting equipment in a laboratory as glassware cannot be heated directly with the flame of a Bunsen burner, and requires the use of wire gauze to diffuse the heat, helping to protect the glassware.

Explanation:

The standard emf of the  voltaic cell based on Ag+(aq)/Ag(s) and Fe3+(aq)/Fe2+(aq) half-cells is 0.03 V.

To determine the reactions at the cathode and anode, we need to know the standard reduction potentials of the given half-cells. The standard reduction potentials are as follows:

Ag+(aq) + e- → Ag(s) E° = +0.80 V
Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V
Since the higher reduction potential will occur at the cathode and the lower one at the anode, we have:
Cathode reaction: Ag+(aq) + e- → Ag(s)
Anode reaction: Fe3+(aq) + e- → Fe2+(aq)
The cathode reaction involves the reduction of silver ions to silver metal, and the anode reaction involves the reduction of ferric ions to ferrous ions. And the standard emf of the cell is:

E°cell = E°cathode - E°anode

E°cell = +0.80 V - (+0.77 V)

E°cell = 0.03 V

In this voltaic cell, the cathode reaction is Ag+(aq) + e- → Ag(s), and the anode reaction is Fe3+(aq) + e- → Fe2+(aq). The standard emf of the cell is 0.03V.

To know more about half-cells visit:

brainly.com/question/17205920

#SPJ11

A voltaic cell is based on Ag+(aq)/Ag(s) and Fe3+(aq)/Fe2+(aq) half-cells. The cathode reaction is \(Ag^+(aq) + e^{-}\ - > Ag(s)\) and the anode reaction is \(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\).

Determine the cathode and anode reactions

To determine the cathode and anode reactions in the voltaic cell based on the \(Ag^+(aq)/Ag(s)\ and\ Fe^{3+}(aq)/Fe^{2+}(aq)\) half-cells, we need to compare the reduction potentials of each half-reaction. The reaction with the higher reduction potential will occur at the cathode (where reduction takes place), while the reaction with the lower reduction potential will occur at the anode (where oxidation takes place).

The standard reduction potentials for the half-reactions are as follows:

\(Ag^+(aq) + e^{-}\ - > Ag(s) \ \ \ \ \ \ \ \ E\° = +0.80 V\)

\(Fe^{3+}(aq) + e^{-} \ - > Fe^{2+}(aq) \ \ \ \ \ \ \ \ E\° = +0.77 V\)

Since the standard reduction potential for \(Ag^+(aq)/Ag(s)\) is higher than that of \(Fe^{3+}(aq)/Fe^{2+}(aq)\), the \(Ag^+(aq)/Ag(s)\) half-reaction will occur at the cathode (reduction) and the \(Fe^{3+}(aq)/Fe^{2+}(aq)\) half-reaction will occur at the anode (oxidation).

A.) Cathode reaction:

\(Ag^+(aq) + e^{-}\ - > Ag(s)\)

B.) Anode reaction:

\(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\)

It's important to note that the oxidation half-reaction is typically written in the reverse direction (as an oxidation) to emphasize the loss of electrons.

Therefore, the cathode reaction is \(Ag^+(aq) + e^{-}\ - > Ag(s)\) and the anode reaction is \(Fe^{3+}(aq)\ - > Fe^{2+}(aq) + e^{-}\).

To know more about voltaic cell, refer here:

https://brainly.com/question/29186551

#SPJ4

We would need 14.535 mL of the 2.7 M glucose stock solution and 270.465 mL of water to prepare 285 mL of a 0.48 M glucose solution.

To calculate the volume of a 2.7 M glucose stock solution and the volume of water needed to prepare a 0.48 M glucose solution, we can use the equation:

\(C_{1} V_{1}\)= \(C_{2} V_{2}\)

where \(C_{1}\) is the initial concentration, \(V_{1}\) is the initial volume, \(C_{2}\) is the final concentration, and \(V_{2}\) is the final volume.

Given:

\(C_{1}\)= 2.7 M (concentration of the stock solution)

\(C_{2}\) = 0.48 M (desired final concentration)

\(V_{2}\) = 285 mL (desired final volume)

First, let's calculate the volume of the stock solution required (V1):

\(C_{1} V_{1}\)= \(C_{2} V_{2}\)

\(V_{1}\) = (\(C_{2} V_{2}\)) / \(C_{1}\)

\(V_{1}\) = (0.48 M * 285 mL) / 2.7 M

\(V_{1}\) = 0.051 M * 285 mL / M

\(V_{1}\) = 14.535 mL

So, you would need 14.535 mL of the 2.7 M glucose stock solution.

To calculate the volume of water (Vo) required, we can subtract the volume of the stock solution from the desired final volume:

Vo = V2 - \(V_{1}\)

Vo = 285 mL - 14.535 mL

Vo = 270.465 mL

Therefore, you would need 14.535 mL of the 2.7 M glucose stock solution and 270.465 mL of water to prepare 285 mL of a 0.48 M glucose solution.

Learn more about stock

https://brainly.com/question/3942978

#SPJ11

The factor identified as not associated with (and possibly causing) type 1 diabetes mellitus is option c) dysfunctional insulin receptors.

Insulin-producing cells in the pancreas are destroyed in type 1 diabetes mellitus, an autoimmune condition. Type 1 diabetes mellitus is thought to be caused by or be influenced by the following factors:

A hormone called insulin is produced by beta cells in the pancreas. It is essential for controlling blood sugar levels and making it easier for cells to absorb glucose for use as fuel. Insulin signals cells in the liver, muscle, and fat tissues to absorb glucose from the bloodstream, assisting in the maintenance of normal blood sugar levels.

To learn more about insulin, refer to:

https://brainly.com/question/786474

#SPJ4

Explanation :

A four-step synthesis of the product from the starting material involves the use of different reagents. The reagents used in this process include:

Step 1:

Reagent 1: The starting material is reacted with thionyl chloride (SOCl2) in the presence of anhydrous DMF or THF to form the corresponding acid chloride. (COCl).

Step 2:

Reagent 2: The acid chloride (COCl) formed in step 1 is reacted with NaN3 in DMF, forming the corresponding azide compound. (N3).

Step 3:

Reagent 3: The azide compound (N3) formed in step 2 is reacted with Raney nickel in ethanol, forming an amine compound (NH2).

Step 4:

Reagent 4: Finally, the amine compound (NH2) formed in step 3 is reacted with anhydrous acetic anhydride (CH3CO)2O in the presence of pyridine, forming the product.

In conclusion, the four-step synthesis of the product from the starting material requires the use of the following reagents:

To know more about the reagent https://brainly.com/question/28463799

#SPJ11

Answer:

here you go

Explanation:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11

Answer:

Athlete will run \(\[34.272Km\]\)

Explanation:

One mile equals to \(\[1.609Km\]\)  

 \(& \therefore 21.3\text{ mile = 1}\text{.603}\times \text{21}\text{.3}Km \\ & 21.3\text{ mile = 34}\text{.2717}Km \\\)  

Thus, the athlete will run \(\[34.2717Km\]\).

Learn more about unit conversion here:

https://brainly.com/question/19730577

https://brainly.com/question/17187413

Answer:

i think it's D

Because O is added to Na

and

H is added to Cl

Answer:

d. NaCl + H2So4 --> Na2 SO4 + 2HCl

Explanation:

The reaction between sodium chloride (NaCl) and sulfuric acid (H2SO4) is a redox reaction.
In a redox reaction, one reactant loses electrons and is oxidized, while the other reactant gains electrons and is reduced. In this reaction, sodium chloride is oxidized and sulfuric acid is reduced.

Sodium chloride is oxidized because it loses an electron to sulfuric acid. The oxidation state of sodium in sodium chloride is +1, and the oxidation state of sodium in sodium sulfate is +2. This means that sodium has lost an electron.

Sulfuric acid is reduced because it gains an electron from sodium chloride. The oxidation state of sulfur in sulfuric acid is +6, and the oxidation state of sulfur in sodium sulfate is +4. This means that sulfur has gained an electron.

The overall reaction can be written as follows:

NaCl + H2SO4 → Na2SO4 + HCl

This reaction is a redox reaction because it involves the transfer of electrons between sodium chloride and sulfuric acid.

The name of the organic compound is 2-methyl pentane. The given organic compound is a five-carbon system with a substitution at the C-2 carbon. The naming of an organic compound is done according to the rules given by IUPAC.

The given organic compound has 5 carbon in its main chain. So It has the root word Pent. Since, all the bonds are single bonds, the organic compound is saturated, hence it has the suffix -ane. Hence the unsubstituted straight chain is pentane.

Numbering is done from right to left, because when the numbering is from right to left, the substituted carbon gets C-2, when it is numbered from left to right, the substituted carbon gets C-4. So the numbering is from the right and the substituted carbon is C-2. The substituent is a single carbon system, a methyl substituent. So the organic compound is named 2-methyl pentane .

Learn more about naming of organic compounds here,

https://brainly.com/question/27843604?

Answer:

I'm sorry, but I cannot see the observations or the data table you mentioned in your question. However, I can still provide you with some general guidance on how to approach the calculations and answer the questions based on the given information.

4. To calculate the concentration of the NaOH solution, you need to know the mass of NaOH used and the volume of the solution. The formula to calculate concentration is:

Concentration (in mol/L) = (Mass of NaOH (in grams) / molar mass of NaOH) / Volume of solution (in L)

Make sure to convert the mass of NaOH to moles by dividing it by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).

5. The balanced equation for the neutralization reaction between NaOH and HCl is:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

(aq) represents an aqueous solution, and (l) represents a liquid.

6a. To calculate the average concentration of HCl in the sample from site B, you need to know the volumes and concentrations of the NaOH and HCl solutions used in the titration. Use the formula:

Concentration of HCl (in mol/L) = (Volume of NaOH solution (in L) * Concentration of NaOH (in mol/L)) / Volume of HCl solution (in L)

Multiply the volume of NaOH solution used by its concentration to find the amount of NaOH used. Then, divide this amount by the volume of HCl solution used to find the concentration of HCl.

6b. To determine the pH of the water at site B, you need to know the concentration of HCl from the previous calculation. The pH can be calculated using the formula:

pH = -log10[H+]

Since HCl is a strong acid, it dissociates completely into H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl. Take the negative logarithm (base 10) of the H+ concentration to find the pH.

To check if the water is safe, compare the calculated pH value to the range provided (pH 4.5-7.5). If the pH falls within this range, the water is considered safe for plant and animal reproduction in an aquatic environment.

6c. Use a similar calculation as in 6a to determine the average concentration of HCl in the sample from site C.

6d. Use the concentration of HCl from 6c to calculate the pH using the formula in 6b. Follow the same procedure to check if the water is safe based on the pH range.

7. To find the most current pH value for the Grand River, you can search for the latest data from reliable sources such as environmental agencies, research institutions, or government websites. Compare this pH value to the pH values obtained in the experiment to assess the difference between them.

Remember, without the specific data and observations, the calculations and comparisons provided here are only general guidelines. It's important to use the actual data from your experiment to obtain accurate results and conclusions.

Please mark as Brainliest

The given Ksp for Mn(OH)2 is 2.0 x 10-13. To calculate the pH at which Mn(OH)2 will begin to precipitate from a solution, we will use the following steps:

Step 1: Write the chemical equation for Mn(OH)2 dissociating in water

Mn(OH)2 ⇌ Mn2+ + 2OH-

Step 2: Write the Ksp expression for Mn(OH)2Ksp = [Mn2+][OH-]^2 = 2.0 x 10^-13

Step 3: Write the expression for the equilibrium concentration of OH-2[OH-] = √(Ksp / [Mn2+])

We know that the initial concentration of Mn2+ is 0.10 M[OH-] = √(2.0 x 10^-13 / 0.10) = 6.32 x 10^-7 M

Step 4: Calculate the pOH of the solution pOH = -log[OH-] = -log(6.32 x 10^-7) = 6.20pH = 14.00 - pOH = 14.00 - 6.20 = 7.80

Therefore, Mn(OH)2 will begin to precipitate from a solution at pH 7.80.

To know more about precipitate visit:

https://brainly.com/question/30904755

#SPJ11

Diffusion and Evaporation are the two procedures required for the perfume's odor to get to the lab's back area.

Diffusion is the movement of molecules from a region where they are more concentrated to one where they are less concentrated.

Diffusion, then, is the process by which matter moves net from an area of high concentration to a region of low concentration as a result of the random motion of molecules. In this instance, the fragrance is permeating the space's air.

A liquid converting to vapour through the process of evaporation takes place at the substance's surface. In this instance, the liquid perfume is evaporating into the gaseous air in order to transform into a vapour and subsequently spread into the air.

To  know more about diffusion visit;

https://brainly.com/question/13513898

#SPJ4

Answer:

The materials would be best to us for the core to make the strongest electromagnetic to pick up the most nails is described below in detail.

Explanation:

Use a couple of wire strip-pers to exclude some centimeters of insulation from every end of the cable. Skillfully cover the cable around the nail. The more cable you enclose around the nail, the more effective your electromagnet will be. Compose certain that you leave sufficient of the cable unwrapped so that you can connect the battery.

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in litres.
Therefore, the molarity of the H₂CO solution is 13.30 mol/L.

In this case, we have 5.50 L of a 13.3 M H₂CO solution. To find the molarity, we need to calculate the number of moles of H₂CO and divide it by the volume of the solution.

The formula weight of H₂CO is 30.03 g/mol. To convert from molarity to moles, we multiply the molarity by the volume in liters:

13.3 mol/L × 5.50 L = 73.15 mol

So we have 73.15 moles of H₂CO in 5.50 L of solution.

Finally, to find the molarity, we divide the number of moles by the volume of the solution:

73.15 mol ÷ 5.50 L = 13.30 mol/L

To know more about solute refer to this:

https://brainly.com/question/8851236

#SPJ11

a. When a strong acid is added to an acetate buffer, excess acetic acid is generated as a result of the reaction of the strong acid with the acetate ions.

b) When a strong base is added to the acetate buffer, the amount of acetate ions decreases because the strong base reacts with acetic acid to form acetate ions.

a) Acetic acid \((HC_2H_3O_2)\)concentration increases when a strong acid is introduced into the acetate buffer. This is due to the fact that the extra strong acid will react with the acetate ion \((C_2H_3O_2)\)of the buffer to generate more acetic acid. The following shows the reaction:

\(H^+\) (from the strong acid) + \(C_2H_3O^2^-\)(from the buffer) → \(HC_2H_3O_2\) (acetic acid)

B. On the other hand, the concentration of acetate ion \((C_2H_3O_2_-)\)decreases when a strong base is added to the acetate buffer. This is due to the fact that the extra strong base will allow the acetic acid \((HC_2H_3O_2)\) of the buffer to react and become acetate ion. The following diagram shows the reaction:

\(HC_2H_3O_2\) (acetic acid) + \(OH^-\) (from strong base) \(C_2H_3O^2^-\)(acetate ion) + \(H_2O\)

Therefore, when a strong acid is added to an acetate buffer, excess acetic acid is generated as a result of the reaction of the strong acid with the acetate ions while when a strong base is added to the acetate buffer, the amount of acetate ions decreases because the strong base reacts with acetic acid to form acetate ions.

Learn more about buffer, here:

https://brainly.com/question/31847096

#SPJ4

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

So we have

\(volume = \frac{220}{11} \\ \)

We have the final answer as

Hope this helps you

Answer:

Moon

Explanation:

The potential of a standard hydrogen (S.H.E.) electrode under the given conditions is -0.126V.

A standard hydrogen electrode (SHE) is a reference electrode used to estimate the standard electrode potentials (E°) of half-reactions. It is made up of a platinum electrode coated in platinum black (Pt) and a hydrogen (H2) electrode dipping into an acidic solution of HCl. The pressure of H2 is measured at 1.0 atm, and the concentration of H+ is maintained at 1.0 mol/L. The potential of the SHE is set to 0.000 V at all temperatures, and other electrode potentials are compared to it to determine their standard reduction potentials.

Using the Nernst equation, we can compute the potential of the SHE : E = E° - (RT/nF)lnQ, where E is the cell potential, E° is the standard cell potential, R is the gas constant, T is the temperature, n is the number of moles of electrons transferred in the redox reaction, F is the Faraday constant, and Q is the reaction quotient.

The given conditions[H+] = 0.77 MPH2 = 1.4 atm T = 298 K

We can use the Nernst equation to calculate the potential of the SHE under these conditions as follows:

E = E° - (RT/nF)lnQ,

where  E° = 0.000 VR = 8.314 J/(mol*K)n = 2 F = 96,485 J/V*KpH2 = 1.4 atm

Q = [H+]2/[H2]E = E° - (RT/nF)lnQ= 0.000 - (8.314*298/2*96,485)*ln (0.77/1.4^2)= 0.000 - 0.000688= -0.126 V

Therefore, the potential of the standard hydrogen electrode (SHE) under the given conditions would be -0.126 V.

To know more about standard hydrogen (S.H.E.) electrode please visit :

https://brainly.com/question/12588341

#SPJ11

Answer:

its is true because i think its true???

When each alkene is treated with NBS and hv, the products formed are the corresponding vicinal dibromides.

Alkenes are hydrocarbons that have a carbon-carbon double bond. Alkenes are unsaturated, which means they have one or more double bonds. They can be categorized based on the number of carbon atoms they have, such as ethene (\(C_{2} H_{4}\)), propene, butene, and so on.

N-bromosuccinimide (NBS) is a useful reagent for introducing a bromine atom in the allylic or benzylic positions of alkenes. When NBS is used in conjunction with light or heat, the HBr that is produced as a byproduct reacts with NBS to create a source of bromine radicals.

This reaction is called allylic/benzylic bromination. When the allylic/benzylic bromination of alkenes is carried out, the corresponding vicinal dibromides are formed.

Learn more about bromination here:

https://brainly.com/question/31033378

#SPJ11

Compared to an atom as a whole, an atomic nucleus Is very tiny but has most of the mass. Correct answer: letter A.

Because atoms are composed of protons, neutrons and electrons. The protons and neutrons are found in the nucleus, which is very small compared to the atom as a whole. However, the protons and neutrons have much more mass than the electrons, so the nucleus has most of the mass of the atom.

An atom is the smallest unit of matter that can exist. Atoms are made up of three particles:

Atoms are the building blocks of all matter in the universe.

Learn more about the atom:

https://brainly.com/question/6258301

#SPJ4

Answer:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

3 moles of H2 = 2 moles of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Thus, we can say that:

1 mole of N2 = 3 moles of H2

1 mole of N2 = 2 moles of NH3

3 moles of H2 = 2 moles of NH3

Thus, considering the options given above, the right answers to the question are:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

3 moles of H2 = 2 moles of NH3

Answer:

3 h2=2nh3

2nh3=1n2

3h2=1n2

Explanation:

Answer:

The water absorbs the thermal energy of the fire.

Explanation:

Thermal energy a form of energy that is produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. It is a form of energy which involves the transfer of energy from regions of higher heat content to regions of lower heat content.

A burning wood fire has a higher heat content than water. Therefore, when water is thrown on a wood fire, the water will absorb the heat from the burning wood fire in order to raise its own heat content. since the wood fire has lost heat to water, it would eventually stop burning, whereas the water whose heat content has been raised may have some of its molecules absorbing so much heat that a change of phase occurs to the liquid phase.

Diels-Alder response is a response of diene and dienophile , when dienophile contains a pi bond adjoining to the pi bond reacting with diene a method called secondary orbital overlap which leads to selectivity of the response.

In endo arrangement the adjacent pi bond creates opportunity for extra frontier orbital interaction. This more interplay stabilizes the transition state.

When the reactants are arranged in an exo configuration no such interaction is feasible that is why endo product is more solid than exo product.

The transition state in chemical reactions is a fleeting and high-energy intermediate state that marks the point of maximum progression towards the products. It represents the point of highest potential energy during a reaction, when the bonds between the reactant molecules are breaking and new bonds between the product molecules are forming.

The transition state is crucial to understanding the rate and mechanism of a reaction. It is characterized by a unique arrangement of atoms and bonding, and its stability determines the energy required for the reaction to proceed. Understanding the transition state is essential for controlling the rate and outcome of chemical reactions, and can be used in the development of catalysts to improve reaction efficiency and specificity. In summary, the transition state is a fleeting and high-energy stage in a chemical reaction, where the bonds between reactants break and new bonds between products form.

To learn more about Transition state visit here:

brainly.com/question/22472755

#SPJ4

Complete Question: -

Because the exo form is more stable than the endo form, why is the endo product formed almost exclusively at low temperatures (or with short reaction times at high temperatures)

The reaction is the preparation of cis-norbornene-5,6-endo-dicarboxylic anhydride from cyclopentadiene, maleic acid, ethyl acetate, and ligroin. In addition to the main product

In addition to the main products, what is an important side reaction that could occur in this experiment? Why is it not a problem for our reaction method?

Answer:

The correct answer is b

Explanation:

Answer:

Correct Answer is (B)

Explanation:

Got it right on plato Chemistry Post test

Hope I helped you out :)

Carbon forms four covalent bonds in neutral compounds.

Carbon is an element located in Group 14 of the periodic table and has four valence electrons in its outermost energy level. To achieve a stable electron configuration, carbon can share these valence electrons with other atoms by forming covalent bonds. In a covalent bond, two atoms share a pair of electrons, resulting in a shared electron pair between the atoms.

Since carbon has four valence electrons, it can form up to four covalent bonds. Each covalent bond involves the sharing of one electron pair. By sharing electrons, carbon can complete its octet (or duet in the case of hydrogen) and achieve a more stable configuration. This ability to form four covalent bonds allows carbon to exhibit diverse bonding patterns and form a wide range of compounds, including organic compounds that serve as the building blocks of life.

In summary, carbon forms four covalent bonds in neutral compounds, allowing it to participate in various chemical reactions and form complex molecular structures.

Learn more about covalent bond from the given link:

https://brainly.com/question/19382448

#SPJ11