Dr. Jackson is studying pharmacokinetics, which is the study of how drugs are absorbed, distributed, metabolized, and eliminated by the body. Option D is the correct answer.
Specifically, she is examining how the route of administration (oral vs rectal) affects the drug's effect. This is an important area of research, as different routes of administration can lead to different pharmacokinetic profiles and may affect the therapeutic efficacy and toxicity of a drug.
Understanding the pharmacokinetics of drugs is crucial for determining the appropriate dosage and administration method for a particular drug, as well as for developing new drugs with optimal pharmacokinetic properties.
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Based on the information provided, we can conclude that Dr. Jackson is doing a study involving neuropharmacology. This is because she is researching the effects of a drug on the nervous system and examining how it is absorbed and processed by the body, which falls under the field of neuropharmacology.
Specifically, she is investigating whether the method of administration (oral or rectal) affects the drug's effectiveness, which is a common area of study within neuropharmacology.
The study of how medicines alter brain processes and the neural pathways by which they affect behaviour is known as neuropharmacology. Behavioural and molecular pharmacology are the two primary subfields of this field. Neuropsychopharmacology, which includes the investigation of how drug abuse and dependence influence the brain, is the main emphasis of behavioural neuropharmacology. With the ultimate goal of creating medications that have positive impacts on neurological function, molecular neuropharmacology studies neurons and their neurochemical interactions. These two disciplines are intertwined because they both focus on the interplay of neurotransmitters, neuropeptides, neurohormones, neuromodulators, enzymes, second messengers, co-transporters, ion channels, and receptor proteins in the central and peripheral nervous systems.
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According to the chemiosmotic mechanism, what is the direct source of the energy used to synthesize ATP from ADP in chloroplasts and in mitochondria
Answer:
NADPH2
Explanation:
nicotinamide adenine nucleotide phosphate
4. The diagram above shows the repeating groups of atoms that make up two samples. Both samples are gases at room temperature. Will the other properties of the samples likely be the same or different? (Examples of properties are smell, color, and the temperature at which a substance melts.)
Answer:
Both samples will be different
Explanation:
Because having different amounts of atoms will make a big impact
What is a transform plate boundary? What happens as a result?
Answer:
Two plates sliding past each other forms a transform plate boundary. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions. Rocks that line the boundary are pulverized as the plates grind along, creating a linear fault valley or undersea canyon.
21. Which is a characteristic of aerobic respiration?
a. Only two ATP molecules are produced.
b. ATP, CO,, and alcohol are the end products.
C. Glucose is broken down in the absence of oxygen to release energy.
d. Glucose is converted to CO,, ATP, and H,O in the presence of oxygen
The stem of a plant is experiencing phototropism. Which statement correctly describes the plant's response? (1 point)
the stem moves away light for better photosynthesis
the stem moves towards the light for better photosynthesis
the stem bends to the sides because there are smaller cells on sides
the stem grows upward because Larger cells are growing
Answer:
The stem moves toward the light for better photosynthesis.
Explanation:
I also took this quiz and got this answer
what is the relationshp between tangible and intangible weight in the first chapter?
The relationship between tangible and intangible weight in the first chapter refers to the distinction between physical and emotional weight or burden.
In the first chapter, the author makes a distinction between tangible and intangible weight.
Tangible weight refers to physical weight, such as carrying a heavy backpack or a box of books.
Intangible weight, on the other hand, refers to emotional weight or burden. This type of weight is not physical, but it can still be felt and can impact a person's life just as much as physical weight.
Examples of intangible weight include stress, anxiety, and depression. The author is suggesting that both tangible and intangible weight can have a significant impact on a person's life and that it's important to recognize and manage both types of weight in order to live a healthy and balanced life.
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what must change in the ecosystem for trees to appear
Of course, we already have trees in our ecosystem. If we were to gain more trees, then we need everybody to stop cutting them down for their gain. Nevertheless, we still need to use some trees to have mandatory everyday items. Trees partially need sunlight to grow and gain energy. With global warming gradually increasing, we may already have what we need to see trees continue to thrive. It is also helpful to plant trees ourselves; it is not a big difference, but it still helps.
There is also primary succession, this is the process of how trees grow. See more below.
Hope this basic outline helped, let me know if you need more info.
ATGTCGCTGATACTG UAC
A matches with U, but T also matches A. I am confused? Does T still match with A as well?
The sequence 'ATGTCGCTGATACTGUACA is RNA because it contains uracil and therefore a single strand, but it may form secondary structures by matching U with A in the same way that for T and A.
What is an RNA sequence?An RNA sequence is a nucleotide sequence in a single strand generated through the process of transcription from a given DNA sequence, which is the genetic material of the cell.
Therefore, with this data, we can see that a RNA sequence is generated from DNA and this RNA contains uracil instead of thymine, which pair with adenine.
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Where is DNA found in your cheek cells? Name two locations in the cell.
Answer:
It is found in the nucleus of the cell.
Which of the following structures is responsible for providing energy for the cell? (1 point) Chloroplast Nucleus Mitochondria Cell membrane
Answer:
Mitochondria
Explanation:
The mitochondria is the power house of the cell!
how much time spent in vigorous activity is usually needed to deplete glycogen reserves?
It depends on the individual's glycogen storage and the intensity of the activity, but it usually takes 1-2 hours of continuous vigorous activity to deplete glycogen reserves.
Glycogen is the stored form of glucose in our muscles and liver, and it's the primary fuel source during exercise. The amount of glycogen stored in the body varies among individuals, depending on factors such as diet, fitness level, and training history. Generally, an average person can store 400-500 grams of glycogen in the muscles and 70-100 grams in the liver.
The rate of glycogen depletion also depends on the intensity and duration of the activity. Vigorous exercise, such as running or cycling at high intensity, can deplete glycogen reserves faster than moderate exercise. It usually takes 1-2 hours of continuous vigorous activity to exhaust the glycogen reserves completely. However, this time can be shorter or longer depending on the individual's glycogen storage capacity and the availability of other energy sources, such as fat and glucose from the bloodstream.
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Part 4 - Natural Selection and Adaptations
3 of 113 of 11 Items
Item 3
A scientist studied a snail population that had a variation of shell colors. The number of each differently colored snail shell was recorded. The graph shows the data the scientist collected.
Over time, the rocks on which the snails lived became covered with dark-colored seaweed.
Which graph best represents the range of colors in the snail population that resulted from natural selection after the dark-colored seaweed covered the rocks?
There are different types of natural selection. When one of the extremes phenotypes is being favored, directional selection is going on. Meanwhile, balancing selection increases the proportion of intermediate phenotype.
-----------------------------
Since I do not have the graphs, I will set different potential scenarios
Let us assume the snails shell has three phenotypes: light brown, brown, and dark brown.Light brown and dark brown are the extreme phenotypesLet us also assume that seaweed is brown-colored.Scenario 1: More light brown individuals than brown and dark brown
Probably after the dark-colored seaweed covered the rocks, snails needed to camouflage to avoid predation. So they must have suffered a change in color from light brown to dark brown.
Since this new trait is beneficial, natural selection favored it.
So animals change from being light brown to dark brown.
The type of natural selection acting here is directional selection.
A population that is under the effects of directional selection, experiences an increase in the proportion of individuals expressing an extreme phenotype, different from the original one.
In these cases, interactions between living organisms and the environment modify in the same direction.
So, the most abundant individuals turned from being light brown to being dark brown.
After dark-colored seaweed covered the rocks, the number of dark brown individuals increased, and the light brown individuals decreased.
**********************
Scenario 2: More brown individuals than light brown and dark brown
This is the same situation as before. In this case, there were more brown individuals than snails expressing extreme phenotypes.
**********************
Scenario 3:
Now let us assume three different phenotypes: Yellow, brown and greyYellow and Grey are the extreme phenotypesSeaweed is brown-colored.Let us suppose that the original number of individuals was higher for one of the extreme traits, either yellow or grey.
After the seaweed-covered rocks, snails needed to camouflage to avoid predation, so they changed their color from yellow or grey to brown.
In this scenario, the intermediate phenotype is being favored by natural selection over the extreme phenotypes.
Balancing selection -or Stabilizing selection-, decreases the number of individuals expressing the extreme phenotype and favors individuals that exhibit medium-range characteristics. These are the ones that get to survive. Selective pressure is against h0m0zyg0tes.
In this case, the number of individuals expressing yellow or grey shells decreases, while individuals with brown color increase.
In the attached files you will find graphs for the three scenarios.
--------------------------
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What are the two functions of the skeletal system? *
A. Provides stucture and protection
B. Sends and recièves signals throughout the body
C. Obtain nutrients and removes waste produced by the body
D. Regulates body temperature and protects the body from damage.
HELP PLEASE
Answer:
A. provide structure and protection
hope it helps
which of the following terms can be used interchangeably? which of the following terms can be used interchangeably? antigen and agglutinogen agglutinogen and agglutinin antigen and antibody antigen and agglutinin
Option B, Antigen is a molecule that causes an immunological reaction, hence the phrases antigen and agglutinogen can be used interchangeably.
The terms "antigen" and "agglutinogen" are interchangeable, but not "agglutinin" or "antibody." A molecule known as an antigen binds to an antibody or a T-cell receptor to initiate an immune response.
An agglutinin is an antibody that causes the clumping of antigens, whereas an agglutinogen is a kind of antigen that particularly stimulates the clumping of cells.
B-cells create antibodies, which are proteins that have a high degree of specificity in their ability to attach to antigens. The correct response is (b), which states that both antigen and agglutinogen can be used interchangeably.
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The question is -
Which of the following terms can be used interchangeably?
a. antigen and agglutinin
b. antigen and agglutinogen
c. agglutinogen and agglutinin
d. antigen and antibody
Researchers examined the ability of cultures of the bacterium Pseudomonas aeruginosa to adapt to the antibiotics ceftazidime and avibactam when they are administered together. The researchers grew four replicate cultures in growth medium with no antibiotics added (control) and four additional replicate cultures in the same growth medium with added ceftazidime and avibactam. At the conclusion of the experiment, samples of the replicates exposed to the antibiotics were removed and their genomes were sequenced. All of the antibiotic-resistant mutants were missing three genes (hmgA, galu, mexXY). It is known that one of these three genes makes wild-type P. aeruginosa susceptible to the two antibiotics. However, the researchers do not know which gene it is. Which of the following experiments would specifically determine which gene is responsible for ceftazidime- avibactam sensitivity in P. aeruginosa ?
A. Clone the three deleted genes from a wild-type P. aeruginosa strain, and insert these sequences into the mutant bacterial strains to restore sensitivity to ceftazidime-avibactam.
B. Delete genes that are homologous to the three deleted genes in other bacterial species, and determine if doing so also confers ceftazidime-avibactam resistance in those bacteria.
C. Perform qene knockout (targeted mutation) of either the hmgA, galu, or mexXY gene on separate cultures of the wild-type P. aeruginosa. For each individual mutant, determine whether or not ceftazidime-avibactam resistance has occurred.
D. Perform gene knockout (targeted mutation) of both the hmgA andgalu genes of the wild-type P. aeruginosa in a single culture, and then determine if ceftazidime-avibactam resistance has occurred in the mutant strain.
Answer:
The correct answer is - option C.
Explanation:
The researcher found that the three genes hmgA, galU, and mexXY were missing from antibiotic-resistant mutants. It is known now that one of these genes is responsible for the susceptibility to the two antibiotics of wild-type P. aeruginous.
Performing gene knockout (targeted mutation) of all three genes on separate cultures of the wild-type P. aeruginosa would help to know which gene is responsible by determining if ceftazidime-avibactam resistance has occurred for each gene or not.
ILL Give brainliest, Why is diabetes a serious disease?
Because you have to go to lots of doctor’s appointments
Because every cell in your body needs glucose to live
Because you have to give yourself insulin shots
Because you can’t eat what you want anymore
Answer:
When there isn't enough insulin or cells stop responding to insulin, too much blood sugar stays in your bloodstream. Over time, that can cause serious health problems, such as heart disease, vision loss, and kidney disease.
Diabetes is a serious disease because you have to give yourself insulin shots.
What is insulin?The INS gene in humans encodes insulin, a peptide hormone generated mostly via beta cells within the pancreas.
What is Diabetes?When the blood glucose, commonly known as blood sugar, would be too high, then develop diabetes.
Diabetes develops when the pancreatic, a gland located behind the stomach, either produces insufficient amounts of the hormone insulin or even when the body has trouble utilizing it. Insulin aids in the movement of circulation sugar towards cells. Sugar becomes transformed into energy once within the cells, either for now or for later.
Therefore, the correct answer will be an option (C).
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why are plants eukaryotic
Plants, like most multicellular organisms, are eukaryotic. Eukaryotic cells are characterized by having a true nucleus, which contains the organism's genetic material, in the form of DNA, enclosed within a membrane.
Additionally, eukaryotic cells are typically larger and more complex than prokaryotic cells, which lack a true nucleus and other membrane-bound organelles. Plants, like other eukaryotes, have many different types of organelles within their cells, including mitochondria, ribosomes, and chloroplasts. Chloroplasts are unique to plant cells and are responsible for photosynthesis, the process by which plants convert light energy into organic compounds, such as glucose. Additionally, plant cells have a rigid cell wall made of cellulose that provides structural support and protection.
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Put the steps of the carbon cycle in order using Step 1 as your starting point. Step 1: Carbon dioxide is
taken in by plants during photosynthesis.
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is
taken in
The animal releases the carbon dioxide back into the atmosphere during respiration.
The animal eats a plant and uses its carbohydrates for energy.
DONE
Answer:
step four
step three
step two
Explanation:
What particles can move through the dialysis
tubing, do you think?
Answer:
Glucose, starch and iodine (potassium iodide) will pass through the membrane of the dialysis tubing.
donker m, straver me, wesseling j, loo ce, schot m, drukker ca, et al. marking axillary lymph nodes with radioactive io- dine seeds fo
The purpose of marking axillary lymph nodes with radioactive iodine seeds is to aid in their localization and identification during surgical procedures, particularly in the context of breast cancer.
During breast cancer surgery, it is important to identify and remove the affected axillary lymph nodes for accurate staging and proper treatment planning. To facilitate this process, radioactive iodine seeds can be implanted in the axillary lymph nodes prior to surgery.
The radioactive iodine seeds emit radiation that can be detected using specialized equipment, such as a gamma probe, during the surgical procedure. This allows the surgeon to precisely locate and remove the marked lymph nodes, ensuring that all potentially cancerous nodes are appropriately excised.
By marking the axillary lymph nodes with radioactive iodine seeds, the procedure becomes more efficient and targeted. It helps reduce the risk of unnecessary lymph node removal while maximizing the likelihood of detecting and treating cancerous nodes.
Overall, marking axillary lymph nodes with radioactive iodine seeds improves the accuracy and success of axillary lymph node dissection in breast cancer surgery.
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The complete question is:
What is the purpose of marking axillary lymph nodes with radioactive iodine seeds?
PLS NO LINKS OR FAKE ANSWERS. What does the atmosphere protect us from? Which layer?
Answer:
The atmosphere protects us from ultraviolet (UV) radiation. The layer that does this is the stratospheric ozone layer. I hope this helps you! ;)
why does the lb/amp/ara plate fluoresce when the lb/amp plate does not
The lb/amp/ara plate fluoresces because it contains the ara gene whereas the lb/amp plate does not fluoresce due to the absence of the ara gene.
The ara or arabinose gene must be added to turn on the operon and make the E. coli glow. Green fluorescent protein (GFP) is a protein that glows with a bright green fluorescence and was first isolated from the marine jellyfish Aequorea victoria. Ara gene encodes the regulatory protein that binds to the pBAD promoter; the pBAD promoter binds arabinose and encourages RNA polymerase binding. When arabinose binds to the Ara gene, the production of GFP is switched on.
Because the second plate is the lb/amp plate there is no ara gene or arabinose, this hinders the binding of the RNA polymerase. As the RNA polymerase is not bound the green fluorescent protein or GFP will not be expressed. Thus the lb/amp plate also will not be showing any sort of fluorescence.
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An amoeba divides into two amoebas every hour. The number N of amoebas after t hours can be represented by t = log2 N. How many hours will it take for a single amoeba to divide into 2048 amoebas?
The number N of amoebas after t hours can be represented by the formula, t = log2 N. Given, an amoeba divides into two amoebas every hour.
Therefore, a single amoeba will divide into two amoebas in the first hour. So, the number of amoebas after the first hour will be
2.The formula t = log2 N can be written in exponential form as N = 2tWe need to find how many hours will it take for a single amoeba to divide into 2048 amoebas. Therefore, the equation will be written as 2048 = 2t.Now, we will convert this equation in logarithmic form as t = log2 2048.t = log2 \(2^11t\) = 11Therefore, it will take 11 hours for a single amoeba to divide into 2048 amoebas.
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ANSWER QUICK ILL MAKE U BRAINLIEST!!!
Answer:
1. 3.8 x 10¹⁸
2. 4 x 10¹²
3. 3.4 x 10^ -20
4. 523000000000 atoms
5. 0.00000000000000000000000000167 kg
If a mutation rendered the signal recognition particle nonfunctional, what would be the most obvious effect on the cell?.
If a mutation rendered the signal recognition particle nonfunctional, All proteins normally secreted by the cell would remain in the cytosol.
A mutation is a modification to the DNA sequence of an organism. Mutations can result through viral infection, errors in DNA replication during cell division, and exposure to mutagens.
Our cells are constantly undergoing mutations, yet very few of these have any negative effects on our health. There are numerous explanations for why mutations typically don't have significant effects. One explanation is that our cells have highly advanced machinery for quickly correcting mutations. Therefore, they won't have enough time to cause issues.
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If a transmembrane domain of protein contains beta-sheet structure, the overall structure of the transmembrane portion is likely a________. a) beta-barrel. b) beta-tube. c) beta-turn. d) beta-helix.
If a transmembrane domain of protein contains beta-sheet structure, the overall structure of the transmembrane portion is likely a beta-barrel.
The transmembrane domain of membrane proteins is a crucial domain that crosses the hydrophobic phospholipid bilayer of the membrane. The transmembrane domain is hydrophobic because it's composed of nonpolar amino acid residues, which are essential for crossing the membrane.
There are two forms of transmembrane domains: alpha-helical transmembrane domains and beta-barrel transmembrane domains, depending on their structural features. The transmembrane domain of alpha-helical proteins is an alpha-helix that runs through the membrane.The transmembrane domains of beta-barrel proteins, on the other hand, are beta-sheet structures that create a barrel-like shape by interacting with one another.
Therefore, if a transmembrane domain of protein contains beta-sheet structure, the overall structure of the transmembrane portion is likely to be a beta-barrel.
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What would the diet
include for an animal
that is coming into a
time of providing
offspring?
A. Higher protein, minerals, and vitamins
B. Carbohydrates and fats
C. Protein, calcium, and phosphorus
D. Concentrates and fats
Option C. The diet of an animal that is coming into a time of providing offspring should be rich in nutrients that are necessary for growth and development of the offspring.
These nutrients include protein, calcium, and phosphorus. Protein is required for the synthesis of enzymes and hormones, as well as for the development of muscle and other tissues in the growing offspring. Calcium and phosphorus are essential minerals required for bone development and other physiological processes.
Therefore, option C, which includes protein, calcium, and phosphorus, is the most appropriate answer. A diet that is high in these nutrients will help ensure that the offspring have a healthy start in life and will also support the health of the mother during this critical time.
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Explain the relationship between the loss of Arctic Ice and the sustainability of
human populations.
The loss of Artic ice is negative between human population. It will cause human population who live in coastal areas in the artic circle will have to deal with erosion on the coast lines.
Lesson 02. 01 Properties of Water
Identify that water is a compound common to living things
Recognize the importance of hydrogen bonding to the properties of water
Explain why many compounds dissolve in water
Lesson 02. 02 Microscopes
Explain how modern technology affects the study of biology
Compare the structure and function of various types of microscopes
Lesson 02. 03 Early Cells
Describe the developments that led to the cell theory
Differentiate between eukaryotic and prokaryotic cells
Describe the structure of the cell membrane
Distinguish between active and passive transport
Lesson 02. 03A Early Cells (Honors)
Describe the theory of the origin of eukaryotic cells (endosymbiosis)
Explain the evidence that supports the theory of endosymbiosis
Lesson 02. 04 Cell Structure and Function
Describe the internal structures of eukaryotic cells
Summarize the functions of the organelles found in plant and animal cells
Lesson 02. 05 Cellular Energy
Recognize the importance of ATP as an energy-carrying molecule
Identify energy sources used by organisms
Lesson 02. 06 Cellular Respiration
Describe the process of cellular respiration
Compare aerobic respiration to anaerobic respiration
Lesson 02. 07 Photosynthesis
Describe the process of photosynthesis
Compare cellular respiration to photosynthesis
Answer:
Lesson 02.01: Properties of Water
Water is a compound common to living things because it is essential for life. It is a major component of cells and plays a crucial role in many biological processes.
Hydrogen bonding is important to the properties of water. Water molecules are polar, meaning they have a slight positive charge on one end and a slight negative charge on the other. This polarity allows water molecules to form hydrogen bonds with each other. Hydrogen bonding gives water its high boiling point, high specific heat capacity, cohesion, and adhesion properties.
Many compounds dissolve in water due to its polarity. Water's polar nature allows it to form interactions with other polar molecules, such as salts and sugars, as well as with charged ions. The positive and negative ends of water molecules surround and separate the ions or polar molecules, effectively dissolving them in the water.
Lesson 02.02: Microscopes
Modern technology has greatly impacted the study of biology. Advanced microscopes, such as electron microscopes, have allowed scientists to observe structures at a much higher resolution and magnification than was previously possible. Techniques like fluorescence microscopy and confocal microscopy enable the visualization of specific molecules and cellular processes in living organisms.
There are various types of microscopes with different structures and functions:
Light microscopes: Use visible light to illuminate the specimen and produce an image. They are commonly used in educational and research settings and can magnify up to 1000x.
Electron microscopes: Use a beam of electrons instead of light to visualize specimens. They offer much higher magnification and resolution than light microscopes. There are two types: transmission electron microscopes (TEM) and scanning electron microscopes (SEM).
Scanning probe microscopes: Use a physical probe to scan the surface of a specimen. They can provide atomic-level resolution and are used in nanotechnology and materials science.
Lesson 02.03: Early Cells
The developments that led to the cell theory include:
Robert Hooke's discovery of cells in cork in 1665.
Anton van Leeuwenhoek's observations of microscopic organisms in pond water in the late 17th century.
Matthias Schleiden's and Theodor Schwann's formulation of the cell theory in the 19th century, stating that all living organisms are composed of cells, and cells are the basic units of life.
Eukaryotic cells have a nucleus and membrane-bound organelles, while prokaryotic cells lack a nucleus and membrane-bound organelles. Eukaryotic cells are generally larger and more complex than prokaryotic cells.
The cell membrane, also known as the plasma membrane, is a selectively permeable barrier that surrounds the cell. It consists of a phospholipid bilayer with embedded proteins. The cell membrane regulates the movement of substances in and out of the cell and plays a vital role in maintaining cell homeostasis.
Active transport requires energy to move substances against their concentration gradient, from an area of lower concentration to an area of higher concentration. Passive transport, on the other hand, does not require energy and involves the movement of substances along their concentration gradient, from an area of higher concentration to an area of lower concentration.
Lesson 02.03A: Early Cells (Honors)
The theory of the origin of eukaryotic cells is called endosymbiosis. It proposes that eukaryotic cells evolved from the symbiotic relationship between different types of prokaryotic cells.
The evidence supporting the theory of endosymbiosis includes:
Mitochondria and chloroplasts have their own DNA and ribosomes, similar to prok
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It was suggested that 360 000 trees should be planted in the first year.How many trees would still need to be planted in the remaining 24 years?
Answer:
2 640 000
or
2.64 × 106
Explanation: