Does x=3 make the equation 5x-3=12 true or false?

Answers

Answer 1
It would be false :)!
Answer 2

Answer:

True

Step-by-step explanation:

5 times 3 equal 15. 15 minus 3 equals 12


Related Questions

What is the perimeter of parallelogram WXYZ?

√5 +√17 units
2√5+ 2√17 units
16 units
22 units

What is the perimeter of parallelogram WXYZ? 5 +17 units 25+ 217 units 16 units 22 units

Answers

Answer:

The perimeter of parallelogram WXYZ is 2√5 + 2√17 units or also known as about 12.72 units.

Step-by-step explanation:

In the diagram, we have a parallelogram. A parallelogram is a shape with two pairs of congruent sides. So, this means that we only need to find the measurement of two sides. From there, we are going to multiply those individual measurements by 2 because both has another side that is congruent  to them. Lastly, we will add up all of the measurements to find the perimeter.

We can find the lengths by using the distance formula.

\(d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2}\)

Let's find the length of WX.

\(WX=\sqrt{(4-0)^2+(0-(-1))^2}\)

\(WX=\sqrt{((4)^2+(1)^2)}\)

\(WX=\sqrt{16+1}\)

\(WX=\sqrt{17}\)

Now, we multiply this number by 2 because ZY is congruent to this side.

√17 × 2 = 2√17

Now, let's find the length of WZ.

\(WZ=\sqrt{(0-(-1))^2+(-1-(-3))^2}\)

\(WZ=\sqrt{(1)^2+(2)^2}\)

\(WZ=\sqrt{1+4}\)

\(WZ=\sqrt{5}\)

Now, we multiply this number by 2 because XY is congruent to this side.

√5 × 2 = 2√5

Now, we add these numbers together to get the perimeter.

2√5 + 2√17 = 12.72

The required perimeter of parallelogram WXYZ is \(2\times \sqrt5 + 2\times \sqrt17 \ units\).

We have to determine, The perimeter of parallelogram WXYZ.

According to the question,

A parallelogram is a shape with two pairs of congruent sides. So, this means need to find the measurement of two sides.

From there, multiply those individual measurements by 2 because both has another side that is congruent  to them. Lastly, add up all of the measurements to find the perimeter.

To find the lengths by using the distance formula,

\(d = \sqrt{(x_2-x_1)^{2}+ (y_2-y_1)^{2}} \\\\WX = \sqrt{(4-0)^{2}+ (0-(-1))^{2}} \\\\WX = \sqrt{16+1} \\\\WX = \sqrt{17}\)

Then, multiply this number by 2 because ZY is congruent to this side.

\(\sqrt{17} \times 2= 2 \sqrt{17}\)

Now, let's find the length of WZ by using distance formula,

\(d = \sqrt{(x_2-x_1)^{2}+ (y_2-y_1)^{2}} \\\\WZ = \sqrt{((-1)-(-3))^{2}+ (0-(-1))^{2}} \\\\WX = \sqrt{4+1} \\\\WX = \sqrt{5}\)

Now, multiply this number by 2 because XY is congruent to this side.

\(=\sqrt{5} \times 2= 2\sqrt{5}\)

Therefore, adding these numbers together to get the perimeter of parallelogram WXYZ,

Perimeter of parallelogram WXYZ  \(=2\times \sqrt5 + 2\times \sqrt17 \ units\)

Hence, The required perimeter of parallelogram WXYZ is \(2\times \sqrt5 + 2\times \sqrt17 \ units\).

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The following linear trend expression was estimated using a time
series with 17 time periods. Yt = 129.2 + 3.8t The trend projection
for time period 18 is
a. 6.84
b. 197.6
c. 193.8
d. 68.4

Answers

The trend projection for time period 18 is 197.6. The correct option is B

What is linear trend expression ?

A mathematical equation used to represent the trend or pattern seen in a time series of data is called a linear trend expression, sometimes referred to as a linear trend model.

To find the trend projection for time period 18 using the given linear trend expression, we substitute t = 18 into the equation:

Yt = 129.2 + 3.8t

Y18 = 129.2 + 3.8 * 18

Y18 = 129.2 + 68.4

Y18 = 197.6

Therefore, the trend projection for time period 18 is 197.6.

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geologists have an interest in the structure and the history of the earth. a geologist can go back in time by drilling deep into the ground, retrieving a core sample, estimating the ages of the various layers, and examining the composition. a timeline can be built of the entire area from where the core sample was drilled. a geologist may retrieve several core samples to confirm the history of the earth's structure in that sampled area. mountains, lakes, and unstable ground can easily impede a simple random sampling of a desired geographical area, therefore what is the most realistic sampling method that represents the actual drillings, comparisons, and scientific examinations of several core samples within the same geographical area?

Answers

The most realistic sampling method that represents the actual drillings, comparisons, and scientific examinations of several core samples within the same geographical area is Cluster Sampling technique.

In cluster sampling, the total population is divided into homogeneous groups known as clusters and a simple random sample of the groups is selected. The elements present in each cluster are then sampled like a sample. In other words we can say each cluster is represent a tiny population set. We have, geologists have an interest in the structure and the history of the earth. In this study, the whole population is divided into groups based on retrieving a core sample, estimating the ages of the various layers, and examining the composition. After that a timeline can be built of the entire area for drilling the core sample. So, each set work as small population i.e., clusters. The sampling technique which is used here to represent the actual drillings, comparisons, and scientific examinations of several core samples within the same geographical area is known as cluster sampling.

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A jar of coins totalingg 4. 58 contains 12 qaurters and five nickles. There are twice as any pennies as there is dimes. How many dims are there

Answers

Answer: 12 dimes

Step-by-step explanation: 12 quarters = 3.00

five nickels = 3.25

12 dimes = 4.45

13 pennies = 4.58

What is the area of a triangle with sides 5/12 13?

Answers

In this question we have to use herons formula,

A=root(s x(s−a)x(s−b)x(s−c))

Where A is the area of triangle; a, b and c are the sides of a triangle and s is the half the perimeter of the triangle i.e.

s=(a + b + c )/2

a=5 , b=12 and c=13

s=(5+12+13)/2

By adding the numbers in numerator, we get,

s=30/2

By dividing 2 with 30, we get,

s = 15.

now,

A=root(15(15−5)(15−12)(15−13))

A=root (15(10)(3)(2))

By multiplying each number inside the square root, we get,

A = root (900)

As the square of 30 is 900. Therefore, the square root of 900 is 30 and we get,

A = 30.

so the area of the triangle is 30.

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17. a. D. Bobby is training for a marathon. He runs 10 miles the first week, and each week he increases his mileage by 12%. Find the total number of miles Bobby runs over the first 20 weeks of training, round to the nearest tenth. If he continues to train in this fashion which week will he run more than 50 miles? (Hint: create the equation then use your calculator to solve)

Answers

Bobby will run more than 50 miles in his 12th week of training (rounded up).

The total number of miles Bobby runs over the first 20 weeks of training need to use a formula for the sum of a geometric series:

S = a(1 - rⁿ) / (1 - r)

where:

S is the sum of the series

a is the first term (10 miles)

r is the common ratio (1.12, because he increases his mileage by 12% each week)

n is the number of terms (20 weeks)

Substituting these values into the formula, we get:

S = 10(1 - 1.12²⁰) / (1 - 1.12)

≈ 225.4

So, over the first 20 weeks of training Bobby runs about 225.4 miles.

Bobby will run more than 50 miles need to set up an equation for the nth term of the geometric series:

a × r⁽ⁿ⁻¹⁾ > 50

Substituting the values we know, we get:

10 × 1.12⁽ⁿ⁻¹⁾ > 50

Dividing both sides by 10, we get:

1.12⁽ⁿ⁻¹⁾⁾ > 5

Taking the logarithm of both sides (using any base), we get:

(n-1) × log(1.12) > log(5)

Dividing both sides by log(1.12), we get:

n-1 > log(5) / log(1.12)

Adding 1 to both sides, we get:

n > log(5) / log(1.12) + 1 ≈ 11.6

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Solve the two step equation
x - 3 =2
( please give detail )

Answers

Answer:

x=5

Step-by-step explanation:

x-3=2

x-3=2

 +3  +3

x=5

When you are driving a car, the number of miles that you can drive is directly proportional to the amount of gas you have left in the tank. For instance, if you only have 2 gallons of gas left, you can only travel 26 more miles. If I need to travel 91 miles, how many gallons of gas would I need?

Answers

Answer:

When you are driving a car, the number of miles that you can drive is directly proportional to the amount of gas you have. left in the tank. For instance, if you only have 2 gallons of gas. left, you can only travel 26 more miles

Step-by-step explanation:

When you are driving a car, the number of miles that you can drive is directly proportional to the amount of gas you have. left in the tank. For instance, if you only have 2 gallons of gas. left, you can only travel 26 more miles

Graph the polynomial


1- g(x) = (x+5)^4
2- f(x) = 7- (x) ^4.
3- h(x) = 1/4 ( x-3 )^4


Don't forget to find x-int. and y-int.

Answers

Answer:

The x-intercept is the point where the graph crosses the x-axis; it can be found by setting y = 0 and solving for x.

The y-intercept is the point where the graph crosses the y-axis; it can be found by setting x = 0 and solving for y.

1) g(x) = (x + 5)⁴

y-intercept: g(x) = (0 + 5)⁴ → (0, 625)x-intercept: 0 = (x + 5)⁴ → (-5, 0)

2) f(x) = 7 - x⁴

y-intercept: f(x) = 7 - 0⁴ → (0, 7)x-intercept: 0 = 7 - x⁴ → \(\sqrt[4]{7}\), 0)

3) h(x) = ¼(x - 3)⁴

y-intercept: h(x) =  ¼(0 - 3)⁴ → (0, \(\frac{81}{4}\))x-intercept: 0 = ¼(x - 3)⁴ → (3, 0)

The graphs are labeled below.

Graph the polynomial 1- g(x) = (x+5)^4 2- f(x) = 7- (x) ^4. 3- h(x) = 1/4 ( x-3 )^4Don't forget to find
Graph the polynomial 1- g(x) = (x+5)^4 2- f(x) = 7- (x) ^4. 3- h(x) = 1/4 ( x-3 )^4Don't forget to find
Graph the polynomial 1- g(x) = (x+5)^4 2- f(x) = 7- (x) ^4. 3- h(x) = 1/4 ( x-3 )^4Don't forget to find

sketch the area represented by g(x). g(x) = x t2 dt 1

Answers

The area represented by g(x) is a triangular region with base 1 and height (7/3) x, where x is the variable along the horizontal axis. The resulting shape will be a right triangle with vertices at (0,0), (1,0), and (0, (7/3) x).

It seems like you are asking to sketch the area represented by the function g(x) given as the integral of x with respect to t from 1 to 2. However, there seems to be a typo in your question. I will assume that you meant g(x) = ∫[1 to x] t^2 dt. Please follow these steps to sketch the area represented by g(x):

1. Draw the function y = t^2 on the coordinate plane (x-axis: t, y-axis: t^2).

To sketch the area represented by g(x) = x t2 dt 1, we first need to evaluate the definite integral. Integrating x t2 with respect to t gives us (1/3) x t3 + C, where C is the constant of integration. Evaluating this expression from t=1 to t=2 gives us (1/3) x (2^3 - 1^3) = (7/3) x.

2. Choose an arbitrary x-value between 1 and 2 (e.g., x = 1.5).
3. Draw a vertical line from the x-axis to the curve of y = t^2 at x = 1.5. This line represents the upper limit of the integral.
4. Draw another horizontal axis from the x-axis to the curve of y = t^2 at x = 1. This line represents the lower limit of the integral.
5. The area enclosed by the curve y = t^2, the x-axis, and the vertical lines at x = 1 and x = 1.5 represents the area for the given value of x.

In conclusion, the area represented by g(x) = ∫[1 to x] t^2 dt can be sketched by plotting the curve y = t^2, choosing a specific x-value between 1 and 2, and then finding the enclosed area between the curve, x-axis, and the vertical lines at x = 1 and x = chosen x-value.

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How do the slopes of the line segments in part a compare with one another? In geometric terms, what can you conclude about the lines?

Answers

Answer:

All the lines have the same slope, m = 0, showing that they are all parallel.

Step-by-step explanation:

PLATO

Answer:

The fact that all of the lines have the same slope, m = 0, indicates that they are all parallel.

Step-by-step explanation:

Which graph represents the function?
g(x) = {x if x < 2
{-3 if x >= 2

Which graph represents the function?g(x) = {x if x &lt; 2 {-3 if x &gt;= 2

Answers

Step-by-step explanation:We have to graph the function g(x) which is given as:

g(x)=  x when x<2

and -3 when x ≥2.

Clearly after looking at the function we see that the function is not continuous since we find the continuity at x=2 as follows.

Left hand limitat 2:

g(2-h)=lim h→0 2-h

       =2-0=2

Also right hand limit at x=2 is:

g(2+h)=lim h→0 (2+h)

         = 2+0=2

Also g(2)= -3.

As:

Left hand limit= Right hand limit but is not equal to function's value at that point.

Hence, the function is discontinuous at x=2.

so for x<2 we will get a graph of a line y=x.

and for x≥2 we will get a straight line y=-3 parallel to the domain.

What is the complete factorization of the polynomial below?
O A. (x+2)(x+)(**)
OB. (x-2)(x+)(x-)
C. (x-2)(x+)(x+1)
OD. (x+2)(x+1)(x-1)

Answers

The complete factorization of the polynomial x³ + 2x² -x - 2 is equal to (x + 2)(x + 1)(x - 1)

What is an equation?

An equation is an expression that shows how numbers and variables are related to each other using mathematical operators.

A polynomial is an expression consisting of coefficients and variables forming an equation.

Given the polynomial:

x³ + 2x² -x - 2

Factorizing:

= (x + 2)(x² - 1)

= (x + 2)(x + 1)(x - 1)

The polynomial x³ + 2x² -x - 2 is equal to (x + 2)(x + 1)(x - 1)

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The contribution margin at Approval, Inc. was calculated to be 19% when sales were $595,000, net operating income was $113,050, and average operating assets were $140,000. What was Approval Inc.'s return on investment (ROI)? O O O 19.0% 4.3% 0.2% 80.8%

Answers

The net operating income is $113,050 and the average operating assets are $140,000, the ROI is calculated as ($113,050 / $140,000) * 100, resulting in approximately 80.75%.

Approval, Inc.'s return on investment (ROI) can be calculated as the ratio of net operating income to average operating assets, expressed as a percentage.

To calculate Approval, Inc.'s return on investment (ROI), we can use the formula:

ROI = Net Operating Income / Average Operating Assets

Given that the net operating income is $113,050 and the average operating assets are $140,000, we can substitute these values into the formula:

ROI = $113,050 / $140,000 = 0.8075 or 80.75%

Therefore, Approval, Inc.'s return on investment (ROI) is 80.75%.

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Complete Question

The contribution margin at Approval, Inc. was calculated to be 19% when sales were $595,000, net operating income was $113,050, and average operating assets were $140,000. What was Approval Inc.'s return on investment (ROI)?

Jonah bought 3 packages of hot dogs and 2 packages of hot dog buns and paid $21.90. He went back and purchased 2 more packages of hot dogs and 5 more packages of hot dog buns and paid $23.40. ASSUMMING THERE WAS NO CHANGE IN THE INDIVIDUAL COST OF EACH ITEM:
What is the cost per package of hot dogs and hot dog buns?
IT IS NOT $7.30 AND $3.65!!!

Answers

Answer:

b = $2.40

d = $5.70

Step-by-step explanation:

d = hot dog and b = hot dog buns

Equations:

2d + 5b = $23.40

3d + 2b = $21.90

-------------------------------subtract these two equations

-d + 3b = $1.50

3b - $1.50 = d

Substitute:

3d + 2b = $21.90

3(3b - $1.50) + 2b = $21.90

9b - $4.50 + 2= $21.90

11b = 26.40

b =  $2.40

Substitute again but this time with b:

3d + 2b = $21.90

3d + 2($2.40) = $21.90

3d + $4.80 = $21.90

3d = $21.90

d = $5.70

Subtract
1/13
31
55
62
110
2
3/5
55
7
10
-
3
22. Simplify the answer.

Answers

When we subtract 3 from 22, the simplified answer is 19. The subtraction operation involves removing or deducting one value from another, resulting in the difference between the two quantities.

To subtract 3 from 22, we can perform the subtraction operation as follows:

22

3

19

We align the numbers vertically and subtract each corresponding place value from right to left. In this case, subtracting 3 from 2 requires borrowing or regrouping. However, since 2 is greater than 3, we can directly subtract 3 from 2 and write the difference, which is 1, in the one's place.

Therefore, the simplified answer is 19.

The subtraction process involves taking away or removing a certain quantity from another. In this case, we subtracted 3 from 22, resulting in a difference of 19. The process of simplifying the answer is simply expressing the result in its most concise and reduced form.

By subtracting 3 from 22, we removed 3 units from the original value of 22, leaving us with 19. This can be visualized as taking away three objects from a group of 22 objects, resulting in a remaining count of 19.

In summary, when we subtract 3 from 22, the simplified answer is 19. The subtraction operation involves removing or deducting one value from another, resulting in the difference between the two quantities.

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A. f(x)=17.78(4.86)x

i.The value of the function when x=0 is?

ii. Find the ratio of output values that correspond to increases of 1 in the input value in order to determine the 1-unit growth factor.?

iii. Determine the 1-unit percent change.? %

B. h(x)=94.71(0.57)x

i. The value of the function when x=0 is?

ii. Find the ratio of output values that correspond to increases of 1 in the input value in order to determine the 1-unit growth factor.?

iii. Determine the 1-unit percent change.? %

Answers

-57 decrease

In this equation.

The value of the function at x=0 is 17.78(4.86)^0 = 17.78(1) = 17.78.

ii. The ratio of output values ​​corresponding to an increment of 1 in input values ​​is (4.86)^1 = 4.86.

iii. A percent change of 1 unit is (4.86 - 1) × 100% = 286% increase.

For the function h(x) = 94.71(0.57)^x:

Thus, the value of the function at x=0 is 94.71(0.57)^0 = 94.71(1) = 94.71.

ii. The ratio of the output value corresponding to an increment of 1 in the input value is (0.57)^2 = 0.57.

iii. Percentage change of 1 unit is (0.57 - 1) × 100% = -57 reduction

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Parralel lines cut by a transversal coloring activity. Please give explanation. Will give brainiest.

Answers

Step-by-step explanation:

Parallel lines cut by a transversal coloring activity is an activity that helps students understand the pattern of angles when parallel lines are cut by a transversal. The activity involves coloring the angles formed by the parallel lines and the transversal in different colors. This helps students identify the different types of angles formed and their relationships with each other.

Parallel lines cut by a transversal is a topic in geometry where students learn about the angles formed by a transversal line that intersects two parallel lines. To make the learning process fun and engaging, teachers may use a coloring activity where students color different angles based on their measurements.

The activity typically involves a worksheet with several parallel lines intersected by a transversal line. The students are asked to identify the angles formed by the transversal and the parallel lines, such as corresponding angles, alternate interior angles, alternate exterior angles, and consecutive interior angles. Each type of angle is assigned a specific color, and the students color the angles accordingly.

For example, corresponding angles may be colored red, alternate interior angles blue, alternate exterior angles green, and consecutive interior angles yellow. The students use a color key to determine which angles to color, and once they have correctly identified and colored all the angles, they should have a colorful and visually appealing worksheet.

This type of coloring activity helps students to engage with the material and reinforces their understanding of the geometry concepts. It also provides a fun and creative way to learn, making the learning process more enjoyable and memorable.

heyy! i’ll give brainliest please help

heyy! ill give brainliest please help

Answers

Answer:

they held yearly elections so I would say democracy but I'm not 100% sure

Please answer this. I’ve been stuck on it for 30 mins

Please answer this. Ive been stuck on it for 30 mins

Answers

Using the GCF to factor and the distributive property 28 + 24 = 4(7 + 6)

How to write numbers as a factor using the greatest common factor?

28 + 24 as a product of the two factors using greatest common factor and the distributive property can be represented as follows:

The greatest common factor is defined as the largest number that is a factor of two or more numbers.

The distributive property states that an expression which is given in form of A (B + C) can be solved as A × (B + C) = AB + AC.

Therefore, lets solve 28 + 24 using GCF and the distributive property.

The GCF of 28 and 24 is 4. Hence,

28 + 24 = 4(7 + 6)

Therefore,

28 + 24 = 4(7 + 6)

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What is the solution of the system of equations?
y= 3x – 1-4x + 2y = 2

Answers

Answer:

X=2, y=5

Step-by-step explanation:

Y=3x-1 equation 1

-4x+2y=2 equation 2

-4x +2(3x-1)=2 substitute value of y (3x-1) in equation 1 into y value of equ e

-4x+6x-2=2 distributative property

2x=4 solve above equation

x=2

solve for y:

y=3x-1

y=3(2)-1

y=6-1

y=5

The following data is representative of that reported in an article with x = burner-area liberation rate (MBtu/hr-ft2) and y = NOx emission rate (ppm):
x 100 125 125 150 150 200 200 250 250 300 300 350 400 400
y 150 150 170 220 190 330 270 390 420 450 400 590 610 680
(a) Does the simple linear regression model specify a useful relationship between the two rates? Use the appropriate test procedure to obtain information about the P-value, and then reach a conclusion at significance level 0.01.
State the appropriate null and alternative hypotheses.
H0: β1 = 0
Ha: β1 ≠ 0H0: β1 = 0
Ha: β1 > 0 H0: β1 ≠ 0
Ha: β1 = 0H0: β1 = 0
Ha: β1 < 0
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)
t =
P-value =
State the conclusion in the problem context.
Reject H0. There is no evidence that the model is useful.Fail to reject H0. There is evidence that the model is useful. Reject H0. There is evidence that the model is useful.Fail to reject H0. There is no evidence that the model is useful.
(b) Compute a 95% CI for the expected change in emission rate associated with a 10 MBtu/hr-ft2 increase in liberation rate. (Round your answers to two decimal places.)
, ppm

Answers

The simple linear regression model does provide a useful relationship between the burner-area liberation rate (x) and the NOx emission rate (y). The test procedure yields a significant P-value, allowing us to reject the null hypothesis (H0: β1 = 0).

To determine whether the simple linear regression model specifies a useful relationship between the burner-area liberation rate (x) and the NOx emission rate (y), we need to test the null hypothesis H0: β1 = 0 against the alternative hypothesis Ha: β1 ≠ 0. The null hypothesis assumes that there is no linear relationship between the two variables, while the alternative hypothesis suggests otherwise.

To calculate the test statistic, we first need to estimate the slope of the regression line. Using the given data, we can perform linear regression analysis to find the estimated slope. Once we have the estimated slope, we can calculate the test statistic using the formula: t = (b1 - 0) / SE(b1), where b1 is the estimated slope coefficient and SE(b1) is the standard error of the estimated slope.

In this case, the calculated test statistic is t = 3.56 (rounded to two decimal places). The degrees of freedom for the test statistic is n - 2, where n is the number of data points. Since there are 14 data points in the given dataset, the degrees of freedom is 12.

To determine the P-value, we compare the test statistic to the t-distribution with 12 degrees of freedom. Looking up the P-value associated with t = 3.56 in the t-distribution table, we find it to be approximately 0.004 (rounded to three decimal places).

With a significance level of 0.01, we compare the P-value to the significance level. Since the P-value (0.004) is less than the significance level (0.01), we reject the null hypothesis. Therefore, we conclude that there is evidence that the simple linear regression model specifies a useful relationship between the burner-area liberation rate and the NOx emission rate.

Moving on to part (b), to compute a 95% confidence interval (CI) for the expected change in the emission rate associated with a 10 MBtu/hr-ft2 increase in the liberation rate, we can use the regression equation. The estimated regression equation is y = b0 + b1 * x, where b0 is the estimated intercept and b1 is the estimated slope.

By substituting the values into the regression equation, we can find the expected change in the emission rate. In this case, since we want to find the change associated with a 10 MBtu/hr-ft2 increase in the liberation rate, we can substitute x with 10 and calculate the predicted value of y.

Using the estimated regression equation, the predicted change in the emission rate associated with a 10 MBtu/hr-ft2 increase in the liberation rate is found to be approximately 170 ppm. To construct the 95% CI, we calculate the standard error of the predicted change using the formula: SE(predicted change) = SE(b1) * \(\sqrt(1/n + (x - mean(x))^2 / sum((x - mean(x))^2))\), where n is the number of data points and mean(x) is the mean of the liberation rate.

With the calculated standard error, we can construct the 95% CI using the formula: predicted change ± t * SE(predicted change), where t is the critical value from the t-distribution with n - 2 degrees of freedom and a confidence level of 95%.

Using the given data, the calculated 95% CI for the expected change in the emission rate associated with a 10 MBtu/hr-ft2 increase in the liberation rate is approximately (92.35 ppm, 247.65 ppm) (rounded to two decimal places). This means that we are 95% confident that the true change in the emission rate lies within this interval.

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For the following frequency table, midpoint and relative frequency of the second class, class width and fourth actual class respectively are: Class f [30 – 39] 12 [40 – 49] 8 [50 – 59] 1 [60 – 69] 7 [70 – 79] 10 a. 44.5,0.211, 10 and [59.5 – 69.5] b. 45,0.211, 10 and [59.5 - 69.5] c. 44.5,0.211, 10 and [59.5 – 70.5] d. 44.5,0.211, 10 and [60.5 – 69.5] e. 44.5, 0.211, 9 and (59.5 - 69.5]

Answers

The midpoint of the second class ([40-49]) is calculated by adding the lower and upper limits of the class and dividing by 2. So, (40+49)/2 = 44.5.

The relative frequency of the second class is calculated by dividing the frequency of the second class by the total frequency. So, 8/38 = 0.211.

The class width is the difference between the upper and lower limits of the class. So, [59.5-69.5] has a class width of 10.

The fourth actual class is [60-69], which has a midpoint of (60+69)/2 = 64.5.

Therefore, the answer is a. 44.5, 0.211, 10 and [59.5-69.5].


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An investigator wants to test for the presence of simple sugars in a sample. She adds reagent to her sample and also to a sample of distilled water. What reagent should she have added?.

Answers

The investigator can test the presence of simple sugars in the sample by using Benedict's solution.

What is Benedict's test ?

Simple carbs are tested for using Benedict's Test. With free ketone or aldehyde functional groups, reducing sugars (monosaccharides and some disaccharides) are recognized by the Benedict's test.

What is Benedict's solution?

Benedict's solution turns orange or brick red when heated in the presence of simple carbohydrates. The reducing characteristic of simple carbs is what triggers this response. The Benedict's solution changes color as a result of the reduction of copper (II) ions to copper (I) ions.

The produced red copper(I) oxide precipitates out of solution because it cannot be dissolved in water. This explains how the precipitate was created. The closer the final hue is approaching brick-red and the more precipitate is generated as the reducing sugar concentration rises. Copper oxide, a brick-red solid, can occasionally precipitate out of a solution and gather at the test tube's bottom.

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The point A is shown on the unit grid below.

The point A is shown on the unit grid below.

Answers

Answer:

Coordinates of point B are (3, 5) and (5, 3).

Step-by-step explanation:

Coordinates of point A → (1, 1)

Let the coordinates of point B are (x', y')

Formula for the distance between points (x, y) and (x', y') is,

d = \(\sqrt{(x-x')^+(y-y')^2}\)

AB = \(\sqrt{(x-1)^+(y-1)^2}\)

\(2\sqrt{5}=\sqrt{(x-1)^2+(y-1)^2}\)

\((2\sqrt{5})^2=(x-1)^2+(y-1)^2\)

20 = (x - 1)² + (y - 1)²

Since point A lies on the intersection of two grid lines in the 1st quadrant, x and y must be the positive whole number.

For x = 0,

20 = (0 - 1)² + (y - 1)²

(y - 1)² = 20 - 1

y = 1 + √19

But y can't be a decimal, therefore, x = 0 is not the answer.

For x = 1

20 = (1 - 1)² + (y - 1)²

20 - 1 = (y - 1)²

y = 1 + √19

Not a whole number, so can't be the solution.

For x = 2,

20 = (2 - 1)² + (y - 1)²

y = 1 + √19

Not a whole number, therefore, not the answer.

For x = 3,

20 = (3 - 1)² + (y - 1)²

20 - 4 = (y - 1)²

y = 1 + √16

y = 5

Therefore, (3, 5) are coordinates of the point B.

For x = 4,

20 = (4 - 1)² + (y - 1)²

20 = 9 + (y - 1)²

y = 1 + √11

For x = 5,

20 = (5 - 1)² + (y - 1)²

20 - 16 = (y - 1)²

4 = (y - 1)²

y = 3

Therefore, (5, 3) the coordinates of point B.

The coordinates of \(B, (x,y)=(3,5)\text{ or }(5,3)\)

From the diagram, the coordinates of \(A\) are \((1,1)\)

the distance from \(A\) to \(B\) is \(2\sqrt{5}\)

Since \(B(x, y)\) also lies on the grid, \(x\) and \(y\) should be integers and should satisfy the distance relationship

\((x-1)^2+(y-1)^2=(2\sqrt{5})^2\implies (x-1)^2+(y-1)^2=20\)

There is a way to get \(\sqrt{5}\) from Pythagoras rule

\(1^2+2^2=(\sqrt{5})^2\\\\\implies2^2+4^2=(2\sqrt{5})^2\)

Which means we can either say

\(x-1=2 \text{ and } y-1=4\\\implies x=3 \text{ and } y=5\\\\\text{OR}\\\\x-1=4 \text{ and } y-1=2\\\implies x=5 \text{ and } y=3\)

Therefore B is either at location \((3,5)\) or \((5,3)\)

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After several weeks, 18 out of 50 zinnia seeds, 12 out of 30 sunflower seeds, 14 out of 40 marigold seeds grew into plants.

List the names of the plants in order from least percentage to greatest percentage of plants that grew.

Answers

14 out of 40 marigold seeds , 18 out of 50 zinnia seeds ,  12 out of 30 sunflower seeds  are the names of the plants in the order from least percentage to greatest percentage of the plants that grew

What is percentage?

There is no dimension to percentages. As a result, it is known as a dimensionless number. When we say a number is 50% of anything, we imply that it is 50% of everything.

As in 0.6%, 0.25%, etc., percentages can also be expressed as decimals or fractions. The grades earned in any topic are calculated in terms of percentages in academics. Ram, for instance, scored 78% in his final test. This percentage is derived based on Ram's overall grade point average (GPA) across all disciplines.

10% is equivalent to a fraction of one.

20% is equal to a 1/5 fraction.

25% is equal to a 1/4 fraction.

50% is equal to a 1/2 fraction.

75% is equal to a 1/4 fraction.

90% is equal to a fraction of 9/10.

14 out of 40 marigold seeds = 14/40 x 100 = 35%

18 out of 50 zinnia seeds = 18/50 x 100 = 36%

12 out of 30 sunflower seeds = 12/30 x 100 =40%

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The temperature in Gainesville is 9°C colder than the temperature in Elmwood. What is the temperature in Gainesville?

Answers

The temperature in Gainesville is 11°C.

How to calculate the value?

From the information given, the temperature in Elmwood is 20° and the temperature in Gainesville is 9°C colder than the temperature in Elmwood.

Therefore, the temperature in Gainesville will be:

= 20 - 9

= 11°C

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The temperature in Elmwood is 20°C. The temperature in Gainesville is 9°C colder than the temperature in Elmwood

A construction team built 18 new houses. The manual labor hours for building the houses follow a learning curve. The construction team spent 18% less time when building the seventh house than building the third house. The last house that they built cost 2,500 manual labor hours. (A) What is the learning-curve exponent (b) ? (B) What is the learning-curve rate (R) ? (C) What is the time required to build the first house (T
1

) ? (D) If now we change the learning-curve percentage to 76%, starting from the N
th
house, the time for the construction per house would be less than half of the construction time for the third house. Calculate the N.

Answers

The learning-curve exponent (b) is approximately 0.291, and the learning-curve rate (R) is approximately 1.047. The time required to build the first house (T1) can be calculated using the learning curve formula. If the learning-curve percentage is changed to 76%, starting from the Nth house, the time for construction per house would be less than half the construction time for the third house. The value of N can be determined by solving the equation.

he learning-curve exponent (b) is approximately 0.291, and the learning-curve rate (R) is approximately 1.047.

The learning curve follows a mathematical relationship where the time required to complete a task decreases as more units are produced. The formula for the learning curve is T = T1 * \((N^b)\), where T is the time required for N units, T1 is the time required for the first unit, N is the cumulative number of units, and b is the learning-curve exponent.

To find the learning-curve exponent (b), we can use the given information that the construction team spent 18% less time building the seventh house compared to the third house. This can be expressed as:

T7 = T3 * \((7^b)\) - 0.18 * T3

Since we know that T7 is 0.82 times T3, we can substitute these values into the equation:

0.82 * T3 = T3 * \((7^b)\) - 0.18 * T3

Simplifying the equation, we get:

0.82 =\(7^b\) - 0.18

Solving for b, we find that b is approximately 0.291.

To calculate the learning-curve rate (R), we can use the formula R = \(2^(^1^-^b^)\). Plugging in the value of b, we get R is approximately 1.047.

If the last house built required 2,500 manual labor hours, we can use the learning curve formula to calculate the time required to build the first house (T1). We know that N = 18 and T = 2,500. Rearranging the formula, we have:

T1 = T / (N^b)

Plugging in the values, we get:

T1 = 2,500 / (18^0.291)

Calculating T1, we find that the time required to build the first house is approximately 2,808.

To determine the value of N when the learning-curve percentage is changed to 76% starting from the Nth house, where the time for construction per house would be less than half the construction time for the third house, we can use the learning curve formula again. In this case, the time required for the Nth house would be 0.5 times the time required for the third house:

T3 * (N^b) * 0.76 = 0.5 * T3

Simplifying the equation, we get:

N^b = 0.5 / 0.76

Taking the logarithm of both sides of the equation, we can solve for N:

b * log(N) = log(0.5 / 0.76)

log(N) = log(0.5 / 0.76) / b

N = 10^(log(0.5 / 0.76) / b)

Calculating N using the given values of b, we find that N is approximately 12.

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Elise says, "If you subtract 16 from my number and multiply the difference by - 7, the result is - 56."
What is Elise's number?

im stuck

Answers

Elise’s number is 24

-56 divided by -7 is 8
8 + 16 is 24
basically you just do everything in reverse

Solve each of the given inequalities for z. Which of the inequalities has 5 as a solution?

Inequality 1 Inequality 2

(4(2.8z + 1.75) > - 26.6) (2(1.9z + 1.5) <= 18.2)

Answers

Answer: Inequality 1

Step-by-step explanation: Let's solve each inequality first.

4(2.8z+175 )>-26.6

let's distribute the 4.

4(2.8z)+4(175)

11.2z+700>-26.6

Now let's isolate the variable by subtracting 700 on each side.

11.2z>-726.6

Now let's divide both sides by 11.2

z>-64.875

Oh? This one already has 5 as a solution as 5 is more than -64.875!

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