Planet Nemesis has a radius of 20,000 km and mass of 2 x 1026 kg. What is its average density in (g/cm3)? [Give the numerical answer, omitting the units of g/cm3.]
2.Planet Caprica follows a largely circular orbit around its host star. If Caprica is roughly 20 AU from its host star and takes 100 years to complete one revolution, how quickly is Caprica moving along its orbit (in km/s)? [Give the numerical answer with assumed units of km/s.]
The average density of Planet Nemesis is approximately [numerical answer] g/cm3.
What is the average density of Planet Nemesis in g/cm3?To calculate the average density of Planet Nemesis, we need to use the formula: density = mass / volume. By knowing the mass of the planet (2 x 1026 kg) and assuming it is a sphere with a radius of 20,000 km, we can determine its average density.
The average density of Planet Nemesis can be calculated by dividing its mass by its volume. The mass of the planet is given as 2 x 1026 kg, and assuming it to be a sphere, we can find its volume using the formula for the volume of a sphere: V = (4/3) * π * r³, where r is the radius of the planet (20,000 km).
Once we have the volume, we can calculate the average density by dividing the mass by the volume. By converting the units, we can express the density in g/cm3.
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The average density of Planet Nemesis is 5.22. The orbital speed of Caprica is 5.93 km/s.
1. To calculate the average density of Planet Nemesis, use the formula:
density = mass/volume.
The volume of a sphere can be calculated using the formula:
volume = (4/3)πr^3.
For Planet Nemesis, the volume is (4/3)π(20,000 km)^3. Convert the mass to grams by multiplying by 1000: 2 x 10^26 kg x 1000 = 2 x 10^29 g.
Then, calculate the density: (2 x 10^29 g)/volume. The numerical value of the average density is approximately 5.22.
2. To find the orbital speed of Planet Caprica, use the formula:
orbital speed = 2πa/T,
where a is the semi-major axis (distance from the host star) and T is the orbital period.
Convert the distance from AU to km: 20 AU x 1.496 x 10^8 km/AU = 2.992 x 10^9 km.
The orbital speed is then (2π(2.992 x 10^9 km))/100 years.
Convert the orbital period to seconds: 100 years x 3.1536 x 10^7 s/year = 3.1536 x 10^9 s.
Finally, calculate the orbital speed: (2π(2.992 x 10^9 km))/(3.1536 x 10^9 s). The numerical value of the orbital speed is approximately 5.93 km/s.
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g what is the approximate ratio between the powers emitted at 500 nm at 2000 degrees c to that at 2500 degrees c, that is, the power emitted at 500 nm at 2000 degrees c divided by the amount of power at 500 nm at degrees 2500 c?
The approximate ratio between the powers emitted at 500 nm at 2000 degrees Celsius to that at 2500 degrees Celsius is approximately 1/2 or 0.5.
The power emitted by an object at a given temperature and wavelength depends on the object's temperature and the wavelength being considered.
As the temperature of an object increases, the amount of power it emits at all wavelengths also increases.
In this problem, we are asked to find the ratio of the powers emitted at 500 nm by an object at two different temperatures, 2000 degrees Celsius and 2500 degrees Celsius.
We know that at higher temperatures, an object emits more power at all wavelengths.
Therefore, we can immediately conclude that the power emitted at 500 nm by an object at 2500 degrees Celsius is greater than the power emitted at 500 nm by an object at 2000 degrees Celsius.
To find the ratio between these two powers, we can think of it as a proportion.
Let P1 be the power emitted at 500 nm by an object at 2000 degrees Celsius and P2 be the power emitted at 500 nm by an object at 2500 degrees Celsius. We want to find P1/P2.
Since the power emitted at 500 nm by an object at 2500 degrees Celsius is greater than the power emitted at 500 nm by an object at 2000 degrees Celsius, we know that P1/P2 is less than 1.
However, we are asked to find an approximate value for this ratio. We can estimate this ratio by thinking about how much the power emitted at 500 nm changes as the temperature increases from 2000 degrees Celsius to 2500 degrees Celsius.
Typically, the power emitted by an object at a given wavelength increases exponentially with temperature.
Therefore, we can estimate that the power emitted at 500 nm at 2500 degrees Celsius is roughly twice as much as the power emitted at 500 nm at 2000 degrees Celsius.
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The relationship between the equilibrant and the resultant vector is *
the equilibrant is equal in magnitude and in diredction
the equilibrant is equal in magnitude but opposite in direction
the equilibrant is different in magnitude and in direction
the equilibrant is different in magnitude but opposite in direction
Answer:
the equilibrant is equal in magnitude but opposite in direction.
Explanation:
In vector algebra, a resultant vector is a single vector that have the same effect as the effect of the net or algebraic sum of two or more vectors.
A resultant vector arises from finding the adding multiple vectors together.
When a group of vectors is replaced by a resultant vector, in order to keep the system of vectors at equilibrium, there is another vector which has the same magnitude as the resultant vector but acting in opposite direction to the resultant vector. This vector is called the equilibrant.
a man has amass of 70kg.calculate his weight on earth where gravitational strength is 10N/kg
a man has a mass of 70kg. then calculated weight on earth where Gravity strength is 10N/kg is 700N
Gravity, which derives from the Latin word gravitas, which means "weight"[1], is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.
Weight W = mg = 70*10 = 700 N
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By how much do the critical angles for red (660 nm) and violet (410 nm) light differ in a diamond surrounded by air?
the critical angle for red light in diamond is 24.51°
critical angle for violet light in diamond is 24.01°.
given:
wavelength of red light λr =660nm
wavelength of violet light λv =410nm
refractive index for air=1
as the refractive index of red and violet colour in diamond is
Refractive index of red color nr= 2.407
Refractive index of violet color nv= 2.451
as it is mentioned that angle is critical angle,thus θr =90°
so,from Snell's law
n1sinθc=n2 sin 90°
Here,
n1 is the refractive index for incident medium
n2 is the refractive index for refractive medium
θc is the critical angle after which light starts reflecting internally
The critical angle for red light is here,n1=2.407, n2=1
n1sinθc=n2 sin 90°
2.407×sin θc=1×1
sin θc =(1/2.407)
θc=sin-1 0.415
θc=24.51°
Thus,the critical angle for red light in diamond is 24.51°
The critical angle for violet light is,
here,n1=2.451,n2=1
n1sinθc=n2 sin 90°
2.407×sin θc=1×1
sin θc= (1/2.451)
θc=sin-1 0.407
=24.01°
Thus,the critical angle for violet light in diamond is 24.01°.
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the induced emf in the loop is measured to be v . what is the magnitude b of the magnetic field that the loop was in? express your answer in terms of some or all of the variables a , c , and v .
The magnitude of the magnetic field that the loop was in can be expressed as b = v/(a*c), where v is the induced EMF, and a and c are given variables.
According to Faraday's law, the induced emf in a loop is directly proportional to the rate of change of magnetic flux through the loop. The formula for the induced emf in a loop is given as v = -dΦ/dt, where v is the induced emf and Φ is the magnetic flux.
Assuming that the magnetic field passing through the loop is uniform and perpendicular to the plane of the loop, the magnetic flux can be expressed as Φ = b * A, where b is the magnetic field strength and A is the area of the loop.
Rearranging the formula for v and substituting the value of Φ, we get v = -d(b * A)/dt = -A * db/dt.
Since A is constant, we can simplify the formula to v = -A * db/dt.
Solving for b, we get b = v/(A * dt).
Substituting A = a*c (where a and c are the dimensions of the loop) and rearranging the formula, we get b = v/(a*c), which is the required answer.
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If the volume of the system is compressed at constant temperature, what change will occur in the position of the equilibrium?
If the volume of a system is compressed at constant temperature, the position of the equilibrium will shift in favor of the side with a lower number of gas molecules.
This observation is based on Le Chatelier's principle, which states that a system at equilibrium will respond to a stress or change by shifting in a direction that minimizes the effect of the stress.
When the volume of a gaseous system is reduced, the pressure increases. According to the ideal gas law (PV = nRT), at constant temperature, an increase in pressure (P) is directly proportional to a decrease in volume (V) if the number of moles of gas (n) and the gas constant (R) remain constant.
To counteract this increase in pressure caused by compression, the system will shift in the direction that reduces the number of gas molecules. This shift occurs because a decrease in the number of gas molecules reduces the pressure, thereby partially offsetting the pressure increase caused by compression.
It's important to note that the specific equilibrium shift depends on the balanced equation and stoichiometry of the reaction involved. In general, however, when the volume is compressed at constant temperature, the equilibrium will shift in the direction that results in a decrease in the total number of gas molecules.
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A hot blackbody is surrounded by a cool low-density cloud of material. If we look directly at the blackbody through the low-density cloud we will see a(n) _____ spectrum.
The term that fills the gap in the statement "A hot blackbody is surrounded by a cool low-density cloud of material. If we look directly at the blackbody through the low-density cloud we will see a(n) "absorption spectrum.
When a hot blackbody is surrounded by a cool low-density cloud of material, if we look directly at the blackbody through the low-density cloud, we will see an absorption spectrum. Absorption spectra refer to spectra that have missing colors (wavelengths) as a result of selective absorption of particular frequencies.
Absorption lines in a spectrum are generated when radiation is absorbed by atoms or molecules in the sample. When photons of specific energy pass through a low-density cloud of gas, the gas molecules in the cloud can absorb some of that energy, resulting in a spectrum that has a number of dark lines therefore, an "absorption spectrum.
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The si unit of average speed is m.s. True or False. anyone who is right I will give him brainlist if you are sure
True
Explanation:
Average speed is a scalar magnitude as opposed to average velocity which is a vector. The unit of measurement in the International System (S.I.) of the average speed is the meter per second (m/s).
A crate with a mass of 50
kg sits at rest on a inclined plane at a 30 degree angle. Calculate: a) the
normal force, b) the force of friction, c) the coefficient of friction, and d)
the weight (in newtons) of the box
Answer:
First at all normal force
Explanation:
F= MG ( 50kg)(9.8m/s)= 490 N
Why don't animals that use electricity electrocute themselves.
Answer:
Electric eels DO endanger themselves by generating electricity. They frequently shock themselves.
That is one animal but I hope it helps!!!
3. When a person is outside of the system and they add energy to the
system, we show this energy as
Answer:
We show added energy to a system as +Q or -W
Explanation:
The first law of thermodynamics states that, in an isolated system, energy can neither be created nor be destroyed;
Energy is added to the internal energy of a system as either work energy or heat energy as follows;
ΔU = Q - W
Therefore, when energy is added as heat energy to a system, we show the energy as positive Q (+Q), when energy is added to the system in the form of work, we show the energy as minus W (-W).
The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the value mathematically, and check it using the number line.
Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is -0.50 meter/second.
The change in velocity for ball 1 is -0.50 – 1.00 = -1.50 meters/second.
Explanation:
yee hope it helps
A toy car with a mass of 2. 0-kg moves with a constant velocity of 20. 0 m/s. A net force of 6. 00 n is applied to the toy car in the direction of its motion for 4. 00 seconds. What is the final momentum of the toy car?.
the final momentum of the toy car is 64.0 kg m/s.
Given parameters:
Mass of the toy car, m = 2.0 kg
Velocity of the toy car, v = 20.0 m/s
Net force, F = 6.00 N
Time for which force is applied, t = 4.00 s
We can find the change in momentum of the toy car using the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied on it.
The impulse is given by the product of force and time. Therefore,
Δp = Ft
The final momentum of the toy car will be the sum of its initial momentum and the change in momentum. Since the toy car is initially moving with a constant velocity, its initial momentum is given by p = mv.
Therefore,
Final momentum of the toy car, p' = p + Δp
= mv + Ft
Substituting the given values, we get:
p' = (2.0 kg) (20.0 m/s) + (6.00 N) (4.00 s)p'
= 40.0 kg m/s + 24.0 kg m/sp'
= 64.0 kg m/s
Therefore, the final momentum of the toy car is 64.0 kg m/s.
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What might be some explanations for Earth's apparent
"luck" in not being hit by more space debris?
The International Space Station moves about once a year to get out of the way of dangerous debris. Critical parts of the station can withstand impact of objects as large as 1 cm, according to NASA. The agency didn't specify the size of the Cosmos 1408 fragment that posed a danger.
A doubly charged helium atom whose mass is 6.6x10^-27 kg is accelerated by a voltage V=1971.4 V and enters the area of magnetic field perpendicular to its velocity B=0.46 T. What is its period of revolution?
The period of revolution of the doubly charged helium atom in the magnetic field is approximately 7.28 × 10^-8 seconds.
To find the period of revolution of a doubly charged helium atom in a magnetic field, we can use the following formula:
T = (2πm) / (qB)
where T is the period of revolution, m is the mass of the helium atom, q is the charge of the atom, and B is the magnetic field strength.
Given:
m = 6.6 × 10^-27 kg (mass of helium atom)
V = 1971.4 V (voltage)
B = 0.46 T (magnetic field strength)
q = 2 × e (doubly charged, so two times the elementary charge)
First, let's find the charge of the helium atom (q):
e = 1.6 × 10^-19 C (elementary charge)
q = 2 × e = 2 × 1.6 × 10^-19 C = 3.2 × 10^-19 C
Now, we can find the period of revolution (T) using the formula:
T = (2πm) / (qB)
T = (2 × π × 6.6 × 10^-27 kg) / (3.2 × 10^-19 C × 0.46 T)
T ≈ 7.28 × 10^-8 s
The period of revolution of the doubly charged helium atom in the magnetic field is approximately 7.28 × 10^-8 seconds.
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what is the relationship between frequency and wavelenghts of an EM wave?
A.as wavelengths decreases, the frequency of the waves increases.
B.as wavelengths decreases,the frequency also decreases
C.the wavelength and the frequency has a direct relationship
D.there is no relationship existing between wavelength and frequency
Answer:
a...as wavelengths decreases ,the frequency of the waves increases.Steam (18kg/kmol) at 1600psi and 1000°F enters a turbine operating at steady state as shown. P. = 1600 psi Turbine 22% of the entering mass flow is extracted by duct T = 1000° F 2 at 160psi and 450°F. The rest of the steam exits 2 3 Pz = 1 psi at duct 3 at 1psi and 102°F. The turbine develops a power output of 9x108 Btu/hr. Heat transfer to T, = 102°F P2 = 160 psi the surroundings accounts for 7% of the power T, = 450°F output. Neglecting kinetic and potential energy effects and assuming that steam behaves as ideal gas at constant y=1.35, a) Determine the fluid's specific gas constant in Btu/lb/°R. b) Determine the mass flow rate of the steam entering the turbine in lb/hr (Answer: 2.738x10 lb/hr) c) How would your result in part b) change if the inlet pressure is 1700psi and WHY?
The fluid specific gas constant of the steam from the turbine is 0.1103 But/lb/°R, the mass flow rate is 2.7380 lb/ hr and the enthalpy and mass flow rate remain constant and volume changes if there is change in inlet pressure.
(a) Power output = 9 × 10⁸ Btu/hr
Heat transfer to the surrounding accounts = 7% of heat transfer of the output
Gas constant = y = 1.35
Temperature T₁ = 1000° F
Temperature T₂ = 450° F
Temperature T₃ = 120° F
Mass of steam = 18 Kg/Kmol
The fluid specific gas constant = R =
= R = Rₙ / m
= R = 1.986 / 18
= R = 0.1103 But/lb/°R
(b) Mass flow rate of the turbine during entry = Q =
= Q = 7% of the power output
= Q = ( 7 × 9 × 10 ⁸ )/ 100
= Q = 63 × 10 ⁶ Btu/hr
Now power developed by the turbine before steam = m×(h₁ - h₂)
= m × (h₁ - 0.22m)
Power developed by the turbine after steam = m×(h₂ - h₃)
= 0.78m × (h₂ - h₃)
Total Power = m×(h₁ - h₂) + 0.78m × (h₂ - h₃)
Applying the thermodynamics formula,
= [m×(h₁ - h₂) + 0.78m × (h₂ - h₃)] - Q = W
= [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] - Q = W
And we know that , R = Cₐ - Cₙ
and, γ = Cₐ / Cₙ
= Cₐ = (R × γ) / (γ - 1)
= Cₐ = 0.4228 Btu/lb°F
Substituting this in [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] - Q = W
= [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] = W + Q
= m = 963000000 / 347.30
= m = 2.7380 lb/hr
(c)If there is change in the inlet pressure then the volume changes but the enthalpy and mass flow rate remain constant.
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Steam flows through a nozzle at mass flow rate of
m =0.1 kg/s with a heat loss of 5 kW. The enthalpies at inlet and exit are 2500 kJ/kg and 2350 kJ/kg, respectively. Assuming negligible velocity at inlet (C 1 ≈0), the velocity (C2 ) of steam (in m/s) at the nozzle exit is (correct to two decimal places)
If negligible velocity at inlet (C 1 ≈0), the velocity (C2) of steam (in m/s) at the nozzle exit is 447.21 m/s.
According to question:
The steady flow energy equation for steady flow devices
m (h1 + ((c1)2/2) + z1g) + Q = m (h2 + ((c2)2/2) + z2g) + Wcv
C1 = 0
Wcv = 0
z1 = z2
mh1 + Q = mh2 + m((C2)2/2)
m((C2)2/2) = m(h1-h2) + Q
0.1 × ((C2)2/2) × 10-3 = 0.1(2500-2350) -5
C2 = 447.21 m/s
Thus, the negligible velocity at inlet (C 1 ≈0), the velocity (C2) of steam (in m/s) at the nozzle exit is 447.21 m/s.
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The mass of 0.0345 moles of a hypothetical molecule, ZY3, is correctly expressed as (where Z = 47.501 g/mol and Y= 12.608 g/mol)
A. 8.38 x 10-23 g
B. 85.3 g
C. 2.94 g
D. 3.04 x 1025 g
E. 247 g
The given mass of 0.0345 moles of a hypothetical molecule, ZY3 can be calculated by using the formula given below.
Mass = Number of moles × Molecular weight Molecular weight of ZY3 = (3 × Molecular weight of Y) + (1 × Molecular weight of Z)ZY3 molecule = ZY3Molecular weight of Z = 47.501 g/mol Molecular weight of Y = 12.608 g/mol Let's substitute these values in the above formula and calculate the mass of 0.0345 moles of ZY3.Mass = 0.0345 × [(3 × 12.608) + 47.501] g Mass = 0.0345 × 96.33 g Mass = 3.319185 g
Since the mass of 0.0345 moles of ZY3 is 3.319185 g, which is approximately equal to 3.04 × 1025 g. So, the correct option is D. 3.04 x 1025 g.
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difference between basic units and derived unit
Answer:
Basic units=those units of measurement which do not depend upon any other units are called basic units. Example length, mass, time, current etc.
Derived units=those units which are expressed in terms of fundamental units are called derived units. Example area, volume, density etc.
How are the smallest ocean waves produced?
A. Weak winds that blow for a long time over a great distance.
B. Weak winds that blow for short periods of time over great distances.
C. Weak winds that blow for long periods of time over small distances.
D. Weak winds that blow for short periods of time over small distances.
PLS HELP I WILL GIVE BRAINLYIST!!!
Answer:
A. (Most likely, sorry if im wrong.)
All waves change speed when they enter a new medium, but they don't always bend. When does bending occur?
consider two spheres of equal mass m, in contact with each other. if one sphere has twice the radius of the other sphere, determine the magnitude of the gravitational force of attraction between them.
The magnitude of the gravitational force of attraction between two spheres can be calculated using Newton's law of universal gravitation, which states:
F = G * (m₁ * m₂) / r²
Where:
F is the gravitational force of attraction between the spheres,
G is the gravitational constant (approximately 6.67430 × 10^(-11) N m²/kg²),
m₁ and m₂ are the masses of the spheres, and
r is the distance between the centers of the spheres.
Given that the two spheres have equal masses (m) and one sphere has twice the radius of the other, we can denote the radius of the smaller sphere as r and the radius of the larger sphere as 2r.
The distance between the centers of the spheres will be the sum of the radii:
r + 2r = 3r
Now, we can calculate the magnitude of the gravitational force of attraction between the spheres:
F = G * (m * m) / (3r)²
Simplifying further:
F = G * m² / (9r²)
Therefore, the magnitude of the gravitational force of attraction between the spheres is given by G * m² / (9r²).
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For the following state of a particle in a three-dimensional box, at how many points is the probability distribution function a maximum: nX= 2, nY= 2, nZ = 1? At what points is the probability distribution function a maximum for the following state: nX = 1, nY = 1, nZ = 1?
The number of points where the probability distribution function is a maximum and their location depend on the number of nodes and the symmetry of the wave function for a given state in a three-dimensional box.
For the state with nX= 2, nY= 2, nZ= 1, the probability distribution function will have a maximum at 8 points. This is because the wave function for this state has a total of 8 nodes, which are points where the probability density goes to zero. The probability distribution function is proportional to the square of the wave function, so it will be at a maximum at the points between nodes where the wave function has a maximum.
For the state with nX= 1, nY= 1, nZ= 1, the probability distribution function will have a maximum at the center of the box. This is because the wave function for this state is symmetric about the center of the box, and the probability density will be highest at the points where the wave function has a maximum.
The number of points where the probability distribution function is a maximum depends on the number of nodes in the wave function for a given state. For the state with nX= 2, nY= 2, nZ= 1, the probability distribution function will have a maximum at 8 points because there are 8 nodes in the wave function. For the state with nX= 1, nY= 1, nZ= 1, the probability distribution function will have a maximum at the center of the box because the wave function is symmetric about the center of the box.
In conclusion, the number of points where the probability distribution function is a maximum and their location depend on the number of nodes and the symmetry of the wave function for a given state in a three-dimensional box.
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The velocity of a bus increases by 20 m/s in 80 seconds. What is the
acceleration of the bus?
A. 0.25 m/s2
B. 4 m/s2
C. 60 m/s2
D. 100 m/s2
Answer:
A
Explanation:
velocity is measured in m/s
acceleration has units m/s^2
so divide the velocity change by the time change:
20 m/s / 80 s = 20 / 80 = .25 m/s^2
You are looking straight down on a magnetic compass that is lying flat on a table. A wire is stretched horizontally under the table, parallel to and a short distance below the compass needle. The wire is then connected to a battery so that a current I flows through the wire. This current causes the north pole of the compass needle to deflect to the left. The questions that follow ask you to compare the effects of different actions on this initial deflection. If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection? You did not open hints for this part. It is larger. It is smaller. It is unchanged.
The new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.
The new angle of deflection north pole becomes smaller
The angle of deflection is the angle formed when an object changes course from its original course of direction or target.
The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.
As the wire is continuously being lowered farther from the compass, the angle of deflection of the north pole continues to become smaller when compared to its initial deflection.
Therefore, the new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.
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A snap together cube has a protruding snap on one side and receptacle holes on the other 55 sides. What is the smallest number of these cubes that can be snapped together so that only receptacle holes are showing
The smallest number of cubes needed is 28. This forms a 3x3x3 cube with one central cube missing.
To minimize the number of protruding snaps while maximizing the number of receptacle holes, the cubes should be arranged in a 3x3x3 cube formation.
This structure would have 27 cubes, but one central cube must be removed to eliminate all protruding snaps.
Each of the remaining 26 cubes will have at least one side with receptacle holes facing outward.
The missing central cube ensures no protruding snaps are exposed.
Therefore, the smallest number of snap-together cubes needed to have only receptacle holes showing is 28.
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Which of the following statements describes one of the key decisions for personal safety while exercising?
A.
wearing dark and heavy clothes when exercising in hot climates
B.
keeping your shoes loosely tied or untied so you can easily put them on or take them off
C.
making sure clothing matches current fashion guidelines
D.
choosing clothing that is appropriate for the environment and type of exercise
Please select the best answer from the choices provided.
Answer:
D
Explanation:
Wearing the appropriate clothing in certain temperatures or environments are important to our safety while exercising because not bearing caution to that can result in injury
Answer:
The answer would be D
Explanation:
List the six zones or layers of the sun in order from the centermost to the outermost layer.