Answer:
where is the question
Step-by-step explanation:
Evaluate the expression when a=3
2a=
Answer:
6 is ur answer hope it help u
lol :)
☃️✌
Merry christmas~
activity b has a duration of 12 days and an earliest finish (ef) of 22 days. if b's latest start (ls) is 15 days, this must mean that b's slack (in days) is
The slack of activity B, given its duration of 12 days, earliest finish of 22 days, and latest start of 15 days, is -7 days.
Now, let's calculate the slack of activity B. Slack represents the amount of time an activity can be delayed without affecting the overall project schedule. Mathematically, slack can be calculated as the difference between the latest start (LS) and the earliest finish (EF) of an activity:
Slack = LS - EF
In our case, the latest start (LS) of activity B is 15 days, and the earliest finish (EF) is 22 days. Therefore, the slack of activity B can be calculated as follows:
Slack = LS - EF
Slack = 15 - 22
Slack = -7
The slack value of -7 indicates that activity B is already delayed by 7 days, considering the project schedule. Negative slack values imply that the activity is behind schedule, and any further delay will directly impact the project completion date.
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what is the common difference of the arithmetic sequence below? 0.5,0.25,0,-0.25
A 10. 0-kg bowling ball sliding across a frictionless surface, with a velocity of 3. 00 m/s, collides head-on with a stationary 9. 00-kg bowling ball. the collision is perfectly elastic, sending the 9. 00-kg ball sliding away and leaving the 10. 0-kg ball with a velocity of 0. 156 m/s. what is the speed of the 9. 00-kg ball after the collision
Initially travelling away from it at a speed of +0.156 m/s, a M = 9.00 kilogram ball collides head-on with a M = 10.0 kg ball that is moving at +3.00 m/s.
What is the formula after collision?\($v_{1, \mathrm{f}}=\left(\frac{m_1-m_2}{m_1+m_2}\right) v_{1, \mathrm{i}}+\left(\frac{2 m_2}{m_1+m_2}\right) v_{2, \mathrm{i}}$$v_{2, \mathrm{f}}=\left(\frac{2 m_1}{m_1+m_2}\right) v_{1, \mathrm{i}}+\left(\frac{m_2-m_1}{m_1+m_2}\right) v_{2, \mathrm{i}}$\)
If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p = m•v.
When momentum, p, and kinetic energy, KE, are conserved during a collision, the collision is said to be elastic. KE0 = KEf and po = pf are the results, respectively. KE = 1/2 mv2, thus we will write 1/2 m1 when we remember that (v1i) 2 + 1/2 m2(vi)2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) When the cue ball and the 2 ball collide with velocities of 0.0m/s before and after, 100% of the momentum of the cue ball is transmitted to the "8." It follows that the "8" ball is moving at a speed of 2.0 m/s. The masses' initial kinetic energy is given by K.E1 = 1/2 m1u21 + 1/2 m2u22.
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Suppose A is a non-empty bounded set of real numbers and c < 0. Define CA = ={c⋅a:a∈A}. (a) If A = (-3, 4] and c=-2, write -2A out in interval notation. (b) Prove that sup CA = cinf A.
Xis the smallest upper bound for -2A (sup CA) and y is the greatest lower bound for A (inf A), we can conclude that sup CA = cinf A.
(a) If A = (-3, 4] and c = -2, then -2A can be written as an interval using interval notation.
To obtain -2A, we multiply each element of A by -2. Since c = -2, we have -2A = {-2a : a ∈ A}.
For A = (-3, 4], the elements of A are greater than -3 and less than or equal to 4. When we multiply each element by -2, the inequalities are reversed because we are multiplying by a negative number.
So, -2A = {x : x ≤ -2a, a ∈ A}.
Since A = (-3, 4], we have -2A = {x : x ≥ 6, x < -8}.
In interval notation, -2A can be written as (-∞, -8) ∪ [6, ∞).
(b) To prove that sup CA = cinf A, we need to show that the supremum of -2A is equal to the infimum of A.
Let x be the supremum of -2A, denoted as sup CA. This means that x is an upper bound for -2A, and there is no smaller upper bound. Therefore, for any element y in -2A, we have y ≤ x.
Since -2A = {-2a : a ∈ A}, we can rewrite the inequality as -2a ≤ x for all a in A.
Dividing both sides by -2 (remembering that c = -2), we get a ≥ x/(-2) or a ≤ -x/2.
This shows that x/(-2) is a lower bound for A. Let y be the infimum of A, denoted as inf A. This means that y is a lower bound for A, and there is no greater lower bound. Therefore, for any element a in A, we have a ≥ y.
Multiplying both sides by -2, we get -2a ≤ -2y.
This shows that -2y is an upper bound for -2A.
Combining the results, we have -2y is an upper bound for -2A and x is a lower bound for A.
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A popular pizza parlor charges $12 for a large cheese pizza plus $1.50 for each additional topp
total cost, C, of a pizza with T toppings can be represented by C = 1.50T + 12. What is the dom
the context of the problem situation?
The domain of the total cost function C = 1.50T + 12 is the set of non-negative integers.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The domain of the function is all non-negative integers, since the number of toppings on a pizza cannot be negative or a fraction of a topping.
Therefore, the domain is {0, 1, 2, 3, ...}
This means that the function is defined for any non-negative integer value of T.
If the customer orders a pizza with 3 toppings, then the total cost would be C = 1.50(3) + 12 = $16.50.
If the customer orders a plain cheese pizza with no toppings, then the total cost would be C = 1.50(0) + 12 = $12.
Therefore, the domain of the total cost function C = 1.50T + 12 is the set of non-negative integers.
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PLS HELP ME I DON'T GOT MUCH TIME!!!! I ONLY GOT 1 MIN!!!!
Two sixth grade science classes are making salt water solutions. The first class (Class A) is using a ratio of three parts salt to five parts water. The other class (Class B) is using a ratio of two parts salt to four parts water. Using the amount of water as the independent variable and the amount of salt as the dependent variable, write a function equation for each class to represent its solution. Make sure to indicate which equation belongs to which class.
Answer:
The graph in the attached figure
Step-by-step explanation:
Let
x ----> parts of water
y ----> parts of salt
we know that
Class A
y/x = 3/5
y=3/5x
Class B
y/x=2/4=1/2
y=1/2x
using a graphing tool
The graph in the attached figure
I REALLY REALLY NEED HELP
Answer:
answer all?
Step-by-step explanation:
Answer:
1- SF: 2; X:7
2- SF:2.5; X:10.5
3- SF:1.5; X:7.5
4- SF:3; X:9.4
Step-by-step explanation:
You multiply a length in centimetres by a certain percent, then multiply the new length by a different percent. The result is 4 times the length you started with. What could the two percents be?
Answer:
The two percent could be 100% and 400%.
Step-by-step explanation:
This would result in the length being multiplied by 4.
Match the numbers to their equivalent alternate form.
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What are the first 10 digits after the decimal point when the fraction $\frac17$ is written in base 16?
Answer:
The amswer is "2,4,9....."
Step-by-step explanation:
\(x=\frac{1}{7}\\\\x_d=0.\overline{142857}\\\\x_h=0.\overline{249}\\\\\)
by leave you to work out the other 7 digits:
\(\to \frac{1}{7}\approx \frac{a}{16}\\\\a= \text{first hex digit}\\\\a=floor(\frac{16}{7})=2\\\\\)
\(\to \frac{1}{7}- \frac{a}{16}\approx \frac{b}{16^2}\\\\b= \text{second hex digit}\\\\b=floor(\frac{16^2}{7} -16a)=4\\\\\)
\(\to \frac{1}{7}- \frac{a}{16}-\frac{b}{16^2} \approx \frac{c}{16^3}\\\\c= \text{third hex digit}\\\\c=floor(\frac{16^3}{7} -16^2a-16b)=9\\\\\)
could someone help me with my recent asked questions? I really do need the help, but a lot of people don't take it seriously. Thank you :)
what do you need help with
Answer:
Sure
Step-by-step explanation:
Mientras que en variables discretas se utiliza la función de probabilidad, en distribuciones continuas se utiliza la función de densidad., verdadero o falso?
Answer:
Answer: FIRST OPTION
Step-by-step explanation:
The missing picture is attached.
By definition, given a Quadratic equation in the form:
Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.
The Quadratic Formula is the following:
In this case, the exercise gives you this Quadratic equation:
You can identify that the numerical coefficients are:
Therefore, you can substitute values into the Quadratic formula shown above:
You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.
25
An expression is shown below.
2/3
3a + 3b + 8
Place a check mark next to each equivalent expression.
A. O 3a + 3b + (8 + 4) − 4
B. O −(−¾a + ½¾⁄b + 8)
c.
(a + b + 8)
(3a + 3b + 8) × ²1/1
E.O a + b + 0 × c + 8
D. 6 x
Answer: To determine which expressions are equivalent to the given expression, we need to simplify the given expression first:
2/3 (3a + 3b + 8) = 2a + 2b + 16/3
Now we can check which expressions are equivalent to this simplified expression:
A. 3a + 3b + (8 + 4) − 4 = 3a + 3b + 8, not equivalent
B. −(−¾a + ½¾⁄b + 8) = 3/4 a - 3/2 b - 8, not equivalent
C. (a + b + 8) (3a + 3b + 8) × ²1/1 = (3a^2 + 9ab + 24a + 3b^2 + 24b + 64)/1, not equivalent
D. 6x = 6x, not equivalent
E. a + b + 0 × c + 8 = a + b + 8, not equivalent
None of the expressions is equivalent to the given expression 2/3 (3a + 3b + 8).
Step-by-step explanation:
Which statement shows how two polynomials 3x + 6 and 5x2 - 4x demonstrate the closure property when multiplied?
O 15x3 + 18x? - 24x may or may not be a polynomial
O 15x3 + 18x2 - 24x is a polynomial
O 15x + 42x2 – 24x may or may not be a polynomial
15x3 + 42x2 - 24x is a polynomial
Here you go, rockstar
B) 15x3 + 18x2 − 24x is a polynomial
✨keep going!✨
If you were required to survey Fresno City College students regarding their employment status, which sampling technique would you use? Explain.
If I were required to survey Fresno City College students regarding their employment status, I would use a stratified random sampling technique.
Stratified random sampling involves dividing the population into subgroups, or strata, based on certain characteristics that are relevant to the survey. In this case, the relevant characteristic is employment status. The population consists of all Fresno City College students, and the two strata are employed and unemployed students.
Once the population has been divided into strata, a random sample is taken from each stratum. The sample size for each stratum is proportional to the size of the stratum in the population. For example, if 60% of Fresno City College students are employed, then 60% of the sample should consist of employed students.
Using a stratified random sampling technique ensures that the sample is representative of the population and that each subgroup is represented in the sample. It also reduces sampling error and increases the precision of the estimates.
PLEASE HELP I NEED ANSWER
Answer:
The area of the figure is 61.24 cm
Step-by-step explanation:
The area for the parallelogram is determined by base x height, so 7 x 6 = 42.
The area of a circle is \(\pi\)r², with r being the radius, so that means the circle area is 38.48, but because its a semicircle, its half of that, so the area is 19.24.
42 + 19.24 = 61.24
Can someone help me please
it's sideways take a better pic
(1 point) Use the linear approximation to estimate (1.02)³(-3.02)³ ≈ Compare with the value given by a calculator and compute the percentage error: Error = %
To estimate (1.02)³(-3.02)³ using linear approximation, we can start by considering the function f(x) = x³. We will approximate the values (1.02)³ and (-3.02)³ by using the linear approximation around a known value.
Let's choose the known value to be 1. Using the linear approximation, we have:
f(x) ≈ f(a) + f'(a) * (x - a)
where a = 1 is our chosen known value, and f'(x) is the derivative of f(x) with respect to x.
For f(x) = x³, we have f'(x) = 3x².
Approximating (1.02)³:
f(1.02) ≈ f(1) + f'(1) * (1.02 - 1)
= 1³ + 3(1²) * (1.02 - 1)
= 1 + 3 * 1 * (0.02)
= 1 + 0.06
= 1.06
Approximating (-3.02)³:
f(-3.02) ≈ f(1) + f'(1) * (-3.02 - 1)
= 1³ + 3(1²) * (-3.02 - 1)
= 1 - 3 * 1 * (4.02)
= 1 - 12.06
= -11.06
Now, we can multiply these approximations:
(1.02)³(-3.02)³ ≈ 1.06 * (-11.06)
≈ -11.7576
To compare this with the value given by a calculator, let's calculate it accurately:
(1.02)³(-3.02)³ ≈ 1.02³ * (-3.02)³
≈ 1.06120808 * (-10.8998408)
≈ -11.55208091
The percentage error can be computed using the formula:
Error = (Approximated Value - Actual Value) / Actual Value * 100%
Error =(−11.7576−(−11.55208091))/(−11.55208091)∗100
= −0.20551909/(−11.55208091)∗100
≈ 1.7784%
Therefore, the percentage error is approximately 1.7784%.
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how am i supposed to know help
The two triangles are similar, solve for x.
Answer:9
Step-by-step explanation:
Do the proportion:
60/54 = 110/(10x+9)
Simply solve for x
PLZZZ HELP FAST
what is the value of y
\(y ^3 = 5\)
Answer: y= \(\sqrt[3]{5}\)
Step-by-step explanation:
name the plane represented by the points in the box
A.fbcg C.fecb
B.bade D.fkgi
need now please help
Answer:
The plane represented in the box is: fbcg
Step-by-step explanation:
Given
The attached box
Required
Which of the given points is a plane in the box
To do this, we simply check if the points are connected i.e. if there is a directed between each of the points of the plane.
A. FBCG
Point F links to B, (by drawing a vertical line from F)
Point B links to C, (by drawing a right horizontal line from B to C)
Point C links to G, (by drawing a vertical line from C down to G)
Point G links to F, (by drawing a left horizontal line from G to F)
Hence, FBCG is a plane on the box.
This is not so for other options
is there a real number whose square root is-1?
Answer:
No.
The square root of any number can never be negative/ -1
9. - Pamela quiere calcular la altura de una torre de PEMEX, observa que el ángulo de elevación a la
parte alta de una torre es de 30°, camina hacia la torre 500m y encuentra que el ángulo es ahora
de 60°, que altura tiene la torre.
The height of the PEMEX tower is 287.6 meters if She walks towards the tower 500m and finds that the angle is 60 degrees.
The angle of elevation = 30 degrees
Walking distance = 500m
The angle of elevation after walking = 60 degrees
When Pamela is 500 meters away from the tower, the tangent of the angle of elevation is calculated as:
tan(30°) = h / 500
h = 500 * tan(30°)
h = 500 * 0.5774
h = 288.7 meters
After walking 500m,
tan(60°) = h / d
h = d * tan(60°) ---------equation 1
The new distance between her and the tower is:
d = 500 - x
Using the tangent function with an angle of 60 degrees, the equation can be written as:
h = (500 - x) * tan(60°)
500 * tan(30°) = (500 - x) * tan(60°)
288.7 = (500 - x) * 1.732
166.5 = 500 - x
x = 333.5 meters
Substituting this value of x in equation 1:
h = (500 - 333.5) * tan(60°)
h = 166.5 * 1.732
h = 287.6 meters
Therefore, we can conclude that the height of the tower is 287.6 meters.
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The complete question is-
Pamela wants to calculate the height of a PEMEX tower. She observes that the angle of elevation to the top of the tower is 30 degrees. She walks towards the tower 500m and finds that the angle is now 60 degrees.
Pythagorean theorem
How far from the wall should Zachary position the bottom of the ladder so that the top reaches the window ledge?
(PHOTO)
As the question suggests, we need to use Pythagorean Theorem!
\(a^{2}\ +\ b^{2}\ = c^{2}\)
You are given the hypotenuse and one of the sides therefore you need to rearrange your formula like so:
\(a^{2}=c^{2}-b^{2}\)
Substitute your values and solve.
\(a^{2}=17^{2}-15^{2}\\a^{2}=289-225 \\a^{2}=64\\\sqrt{a^{2}} =\sqrt{64} \\\)
a = 8 meters
3. A linear quadrupole is a series of three charges in a line, in this case, along the z-axis. Consider charges +Q at z=±D and charge −2Q at z=0. Find an exact expressoin for the electrostatic potential at a point P in the x,y-plane at a distance r from the center of the quadrupole. (Hint: it may be easier to find V(x) on the x axis and then use symmetry to argue that you can switch from x to r.)
The exact expression for the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole is given by V(r) = k [Q/(r2 + D2)1/2 – Q/[(r2 + 2d + D2)1/2]] + k [-2Q/D].
Let's consider that three charges are placed in a straight line along the z-axis, and the charges are +Q on z=+D, -Q on z=-D, and -2Q at z=0.
To find the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole, let's proceed with the following steps:
To find the electrostatic potential at a point P in the x-axis, we need to consider that the distance from the charges that are on the axis is r, and the distance from the charges that are on the axis and are at +D and -D is d.
The distance from the charges on the axis and at 0 is x. Now we can write,
V(x) = k [Q/(x2 + D2)1/2 – Q/[(x + d)2 + D2]1/2] + k [-2Q/D].
Now, we can substitute the values in the above expression and obtain,
V(x) = k [Q/(x2 + D2)1/2 – Q/[(x + d)2 + D2]1/2] + k [-2Q/D] .
Now, we need to use symmetry to argue that we can switch from x to r, which is given by r2 = x2 + y2.
Thus, the exact expression for the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole is given by V(r) = k [Q/(r2 + D2)1/2 – Q/[(r2 + 2d + D2)1/2]] + k [-2Q/D].
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2x + 3y = 13
Step 2 of 2: Determine the missing coordinate in the ordered pair (?, 3/2) so that it will satisfy the given equation
Answer:
\(\frac{17}{4}\)
Step-by-step explanation:
Replace y with 3/2 and solve for x
2x + 3(3/2) = 13
2x + 9/2 = 13 Subtract 9/2 from both sides
2x = \(\frac{13}{1}\) - \(\frac{9}{2}\)
2x = \(\frac{26}{2}\) - \(\frac{9}{2}\)
2x = \(\frac{17}{2}\) Divide both sides by 2
x = \(\frac{17}{2}\) ÷ \(\frac{2}{1}\)
x = \(\frac{17}{2}\) x \(\frac{1}{2}\)
x = \(\frac{17}{4}\) o r4 \(\frac{1}{4}\) or 4.25
if josie missed 8 questions how many of them did she get correct
Answer:
Step-by-step explanation:
how many questions was it out of ?
but you must take away the 8 for the total amount of questions
which statistical method could a scientist use to estimate the strength of evidence that a particular node in a phylogeny exists?
A scientist can use bootstrap analysis to estimate the strength of evidence that a particular node in a phylogeny exists.
Bootstrap analysis is a statistical method used to determine the reliability and robustness of phylogenetic trees' topologies. In bootstrap analysis, a series of random resampling with replacement is used to assess how well the observed data fit the phylogenetic hypothesis.
Bootstrap values range from 0 to 100 and reflect the proportion of times that a particular node or branch occurs in the bootstrap replicate trees. Bootstrap values greater than 70% are usually considered strong evidence that a particular node or branch exists in the phylogenetic tree.
Bootstrap analysis is an important tool for understanding the reliability of phylogenetic trees and the evolutionary relationships among organisms.
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