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Diego made a graph of two quantities that he measured and said,

“The points all lie on a line except one, which is a little bit above the line. This means that the quantities can’t be proportional.”

Do you agree with Diego?

Answer:

its c

Step-by-step explanation:

The expression cos (125°) - cos 55° cos 35° cos 55° can be written as cos (55°) + cos (55°) cos (35°) cos (55°).

cos (125°) can be rewritten as cos (180° - 125°). Similarly, cos (35°) can be rewritten as cos (180° - 35°). Therefore, the expression can be written as:

cos (180° - 125°) - cos (55°) cos (180° - 35°) cos (55°)

Simplifying further, we have:

cos (55°) - cos (55°) cos (145°) cos (55°)

Since 145° is the supplement of 35°, we can rewrite it as:

cos (55°) - cos (55°) cos (180° - 35°) cos (55°)

Now, cos (180° - 35°) is equal to -cos (35°). Therefore, the expression becomes:

cos (55°) + cos (55°) cos (35°) cos (55°)

Hence, the expression as a function of an acute angle is:

cos (55°) + cos (55°) cos (35°) cos (55°)

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The correct statement regarding the variation of the two measures is given as follows:

C. Yes, they vary directly. When one quantity increases, the other quantity also increases.

For this problem, we have that when the number of correct answers on the test increases, the score also does, hence the two quantities vary directly, and option c is the correct option for this problem.

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Answer:

it is D if I am not mistkin

Answer:

one pen costs 0.5 euros

one rubber costs 0.75 euros

Step-by-step explanation:

4p+5r=5.75

p+4r=3.5

  -4r.   -4r

p=3.5-4r

4(3.5-4r)+5r=5.75

14-16r+5r=5.75

14-11r=5.75

-14.     -14

-11r=-8.25

r=0.75

One rubber cost 0.75 euros

Now to find cost of one pen we just fill in what we know

p+4(0.75)=3.5

p+3=3.5

 -3.  -3

p=0.5

1 pen cost 0.5 euros

Hopes this helps please mark brainliest

Answer:

x= 1

Step-by-step explanation:

Answer:

The odds for are 50% and the odds against are 50%.

Step-by-step explanation:

On a die, there is 6 possibilities 2, 3, and 5, are 3 of them.

This means there is a 3/6 chance that it will land on one of those numbers, and there is also a 3/6 chance it will land on 1, 4, or 6.

3/6 is equivalent to 50% and 1/2.

Answer:

Any value between 3 and 19 may be the measure of third side.

Step-by-step explanation:

If three sides of a triangle are a, b, and c, possible measures of the sides of a triangle will be.

1). a + b > c

2). b + c > a

3). a + c > b

If a = 8, b = 11,

1). 8 + 11 > c

   c < 19

2). 11 + c > 8

    c > 8 - 11

    c > (-3)

3). 8 + c > 11

    c > 11 - 8

    c > 3

Therefore, by combining the given inequalities,

3 < c < 19

Any value between 3 and 19 may be the measure of third side.

The generating function for the sequence {an} is given by a(x) = (1 + 2x) / (1 - x - 6x^2). It captures the terms of the sequence {an} as coefficients of the powers of x.

To find the generating function of the sequence {an}, we can use the properties of generating functions and solve the given recurrence relation.

The given recurrence relation is: an = an-1 + 6an-2

We are also given the initial conditions: a0 = 1 and a1 = 3.

To find the generating function, we define the generating function A(x) as:

a(x) = a0 + a1x + a2x² + a3x³ + ...

Multiplying the recurrence relation by x^n and summing over all values of n, we get:

∑(an × xⁿ) = ∑(an-1 × xⁿ) + 6∑(an-2 × xⁿ)

Now, let's express each summation in terms of the generating function a(x):

a(x) - a0 - a1x = x(A(x) - a0) + 6x²ᵃ⁽ˣ⁾

Simplifying and rearranging the terms, we have:

a(x)(1 - x - 6x²) = a0 + (a1 - a0)x

Using the given initial conditions, we have:

a(x)(1 - x - 6x²) = 1 + 2x

Now, we can solve for A(x) by dividing both sides by (1 - x - 6x^2²):

a(x) = (1 + 2x) / (1 - x - 6x²)

Therefore, the generating function for the given sequence is a(x) = (1 + 2x) / (1 - x - 6x²).

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Answer:

  x ≈ 29.076 ≈ 29.1

Step-by-step explanation:

Given BA=22.2, AD=11.3, DC=14.8, and BC =x in triangle ABC with angle bisector BD, you want to find the value of x.

The angle bisector divides the sides proportionally. This means ...

  BC/BA = CD/AD

  x/22.2 = 14.8/11.3 . . . . substitute given values

  x = 22.2(148/113) ≈ 29.076 ≈ 29.1

The value of x is about 29.1.

__

Additional comment

We have rounded x to 1 dp to match the other dimensions in the figure. Its exact value is 29 43/565.

Therefore, the dot products u · x and u · y must be 0, which means that u is orthogonal to B.

Show that u is orthogonal to C, which means that the dot product of every vector in A with every vector in C is 0.

We can also show that every vector in B is orthogonal to every vector in C by following a similar process.

Therefore, we have proven that A ⊥ B, A ⊥ C, and B ⊥ C.

Yes, there exist subspaces A, B, and C of R3 such that A ⊥ B, A ⊥ C, and B ⊥ C.

Here is an example of subspaces A, B, and C of R3:

A = span{(1,0,1), (0,1,0)}

B = span{(0,1,1), (1,0,1)}

C = span{(1,1,0), (0,1,1)}

The first step to proving that A ⊥ B, A ⊥ C, and B ⊥ C is to show that A is orthogonal to both B and C, which means that the dot product of every vector in A with every vector in B and every vector in C is 0.

Let u and v be two vectors in A, and let x and y be two vectors in B.

Then we can represent them as follows: \(u = c1(1,0,1) + c2(0,1,0)\)

\(v = d1(1,0,1) + d2(0,1,0)x = e1(0,1,1) + e2(1,0,1)y = f1(0,1,1) + f2(1,0,1)\)

Now we can calculate the dot product of u with x and y:

\(u · x = (c1(1,0,1) + c2(0,1,0)) · (e1(0,1,1) + e2(1,0,1))\)

\(= c2e1u · y = (c1(1,0,1) + c2(0,1,0)) · (f1(0,1,1) + f2(1,0,1))= c2f2\)

Since we know that x and y are linear combinations of vectors in B, which is a subspace of R3, we know that x and y are themselves vectors in R3.

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Answer:

Step-by-step explanation

Claire experiences apprehension and fear during the anticipatory socialization phase of socialization when her boss proposes putting her on a task force at work, due to her negative group experiences in college.

Anticipatory socialization is the phase in the socialization process where individuals anticipate and prepare for their future roles and experiences in a particular social group or setting.

It involves forming expectations, attitudes, and behaviors based on past experiences and knowledge.

In Claire's case, her negative group experiences in college, where she often ended up doing most of the work and faced poor communication within the group, have shaped her expectations and attitudes towards group work.

As a result, when her boss proposes putting her on a task force at work, Claire immediately feels apprehensive and fearful.

She anticipates that she may face similar challenges, such as an uneven distribution of workload and ineffective communication, which could negatively impact her experience in the task force.

During the anticipatory socialization phase, individuals rely on their past experiences and perceptions to anticipate what they may encounter in a new social setting.

Claire's negative group experiences in college have influenced her apprehension and fear, as she expects the same difficulties to arise in the task force at work.

These emotions and concerns may impact her willingness to fully engage in the new group and could influence her interactions and behavior within the task force.

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The first step is to describe the method to take

To solve the system of equations 4x + 2y = 11 and 3x - y = 9, the first step would be to choose a method to solve the system.

There are several methods for solving systems of equations, including:

One common method is the substitution method, which involves solving one equation for one variable and then substituting the expression for that variable into the other equation.

For example, we could solve the second equation 3x - y = 9 for y to get:

y = 3x + 9

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Answer: 7 and 8

Step-by-step explanation:

Square root and squared cancel out

Answer:

a=7

b=32

Step-by-step explanation:

The first one (a) is 7 because if you square a square root, you get the number inside the root. Also, technically a square root has an exponent of (1/2) so when you have a power-to-a-power (power rule of exponents) you multiply the exponents. So (\(7^{1/2}\))^2 is 7.

For (b) you have to take it in two parts. Square the square root and you get 2. Square the 4 in front, you get 16. Multiply those two numbers (16 and 2) together and you get 32.

Edit: Check on your calculator, you get the same answers I got! :)

Answer:

he is not

Step-by-step explanation:

a whole number has no decimal and it is not a fraction and NO NEGATIVES 3/2is a fraction/decimal so it is not a whole number

To find the z-score for a sales associate who earns $37,500, we can use the formula:

z = (x - μ) / σ

Where:

x is the value we want to convert to a z-score (in this case, $37,500),

μ is the mean of the distribution (in this case, $32,500), and

σ is the standard deviation of the distribution (in this case, $2,500).

Substituting the given values into the formula, we have:

z = (37,500 - 32,500) / 2,500

z = 5,000 / 2,500

z = 2

Therefore, the z-score for a sales associate who earns $37,500 is 2.

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The z-score for a sales associate earning $37,500 in a system where the mean salary is $32,500 and the standard deviation is $2,500 has a z-score of 2. This score indicates that the associate's salary is two standard deviations above the mean.

The z-score represents how many standard deviations a value is from the mean. In this case, the value is the salary of a sales associate, the mean is the average salary, and the standard deviation is the average variation in salaries.

We calculate the z-score by subtracting the mean from the value and dividing by the standard deviation, like so:

Z = (Value - Mean) / Standard Deviation

So, the z-score for an associate earning $37,500 would be:

Z = ($37,500 - $32,500) / $2,500

This gives us a z-score of +2, indicating that a salary of $37,500 is two standard deviations above mean.

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Step-by-step explanation:

Let's see. f(4) makes the divisor x-4

4|-2 9 -6 7

| 8 -68 296

-2 17 -74 2072

The quotient is -2x²+17x-74 with a remainder of 2072

Answer:

The triangles are similar by the Side Angle Side postulate (SAS).

Step-by-step explanation:

Sides 2 and 3 are proportional to sides 4 and 6 by a scale factor of 2. Angles O are congruent to each other by the vertical angles theorem.

Answer:

I need some more detail on character can you remember?

Step-by-step explanation:

Answer:

i think it is The Goldfinch

Step-by-step explanation:

pretty sure that is right...

The upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

To determine the upper and lower control limits for the sample means, we can use the formula:

Upper Control Limit (UCL) = Mean + (Z * Standard Deviation / sqrt(n))

Lower Control Limit (LCL) = Mean - (Z * Standard Deviation / sqrt(n))

In this case, we want to include roughly 95.5 percent of the sample means, which corresponds to a two-sided confidence level of 0.955. To find the appropriate Z-value for this confidence level, we can refer to the standard normal distribution table or use a calculator.

For a two-sided confidence level of 0.955, the Z-value is approximately 1.96.

Given:

Mean = 2.0 litres

Standard Deviation = 0.01 litres

Sample size (n) = 5

Using the formula, we can calculate the upper and lower control limits:

UCL = 2.0 + (1.96 * 0.01 / sqrt(5))

LCL = 2.0 - (1.96 * 0.01 / sqrt(5))

Calculating the values:

UCL ≈ 2.0018 litres

LCL ≈ 1.9982 litres

Therefore, the upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

Mean of the sample means = (2.005 + 2.001 + 1.998 + 2.002 + 1.995 + 1.999) / 6 ≈ 1.9997

Since the mean of the sample means falls within the control limits (between UCL and LCL), we can conclude that the process is in control.

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Answer:

21300

Step-by-step explanation:

120∑n=13n−4

Split the summation into smaller summations that fit the summation rules.

120∑n=1 3n−4=3120∑n=1 n+120∑n=1 −4

Evaluate

3120∑n=1 n.

21780

Evaluate  

120∑n=1 −4 −480

Add the results of the summations.

21780−480

Subtract 480 from 21780.

21300

The statement suggests that there is likely to be an interaction between nitrogen (N) and phosphorus (P), which are two fertilizer ingredients used to achieve optimum levels in plant growth. However, without further context or specific details, it is uncertain to determine the nature and extent of this interaction.

In agriculture and plant nutrition, both nitrogen and phosphorus are essential elements for plant growth and development. They play crucial roles in various physiological processes and are often supplied through fertilizers to optimize crop yields. The interaction between nitrogen and phosphorus can have significant implications for plant growth and nutrient utilization.

The ratio of nitrogen to phosphorus in the soil can affect nutrient uptake, plant growth, and overall productivity. Different plant species and soil conditions may exhibit varying responses to the interaction between these two fertilizer ingredients. Factors such as soil type, pH, organic matter content, and crop-specific nutrient requirements further contribute to the complexity of this interaction. To fully understand and assess the interaction between nitrogen and phosphorus, detailed research and experimentation specific to the particular context are necessary.

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Answer:

As per the moment I cannot answer this due to know screenshot and lack of informatio

Step-by-step explanation:

The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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Step-by-step explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)

Answer:

I would go with Lower

Step-by-step explanation:

For me this answer is mostly from common sense. let's give (teacher) a name (Paul) when Paul is organising his students he would rather have too many seats rather than not enough.

Answer: Ethan can fill the bowl(s) 15 times.

Step-by-step explanation:

Given information:v.magnitude = 3v makes an angle with positive x-axis.The angle made by v with the positive x-axis is 150°.v is in the direction 4i + 3j.Solution: We have to find the component form of v.

Let's represent the given information on a graph:From the above graph, we can say that v makes an angle of 30° with negative y-axis.The angle between v and the negative y-axis = 180° - 30° = 150°Let's find the magnitude of v:Let v be (x,y).v = x i + y j

Magnitude of v, |v| = √(x² + y²) = 3 Therefore, x² + y² = 3² = 9 ...(1)Angle made by v with negative y-axis, θ = 30°∴ The angle made by v with positive x-axis, α = 150° - 90° = 60°sinθ = y/|v|y = 3 sinθ = 3 sin(30°) = 1.5From equation (1),x² + 1.5² = 9x² = 9 - 2.25 = 6.75x = ± √6.75Since v makes an angle of 150° with the positive x-axis, the vector v lies in the second quadrant. Therefore, x is negative.So, x = - √6.75 and y = 1.5Hence, the component form of v is:(- √6.75, 1.5).Thus, the component form of v is (- √6.75, 1.5).

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