Do I set up the modem or router first?

Answer:

yes

Explanation:

an idea could be a jack o lantern monster since it Halloween tomorrow  

a. The maximum thickness of the copper nozzle is 3.3 mm

b. The maximum thickness of the steel nozzle is 0.054 mm

The question has to do with heat transfer

Heat transfer is the movement of heat energy from one body to anotrher.

Since the rate of heat loss by the gas equal rate of heat gain by the metal.

The rate of heat loss by gas is P = -hA(T - T') where

The rate of heat gain by metal is given by P' = kA(T - T")/t where

Since P = P', we have that

-hA(T - T') =  kA(T - T")/t

Making t subject of the formula, we have

t = -k(T - T")/h(T - T')

Given that for copper

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -378 W/m-K(540°C - 150°C)/[2 × 10⁴ W/m²-K(540°C - 2750°C)]

t = -378 W/m-K(390°C)/[2 × 10⁴ W/m²-K(-2210°C)]

t = 147420 W/m/4420 × 10⁴ W/m²

t = 147420 W/m/44200000 W/m²

t = 0.0033 m

t = 3.3 mm

So, the maximum thickness of the copper nozzle is 10.71 cm

Given that for steel

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -23.2 W/m-K(980°C - 150°C)/[2 × 10⁴ W/m²-K(980°C - 2750°C)]

t = -23.2 W/m-K(830°C)/[2 × 10⁴ W/m²-K(-1770°C)]

t = 19256 W/m/3540 × 10⁴ W/m²

t = 19256 W/m/35400000 W/m²

t = 0.0000544 m

t = 0.0544 mm

t ≅ 0.054 mm

So, the maximum thickness of the steel nozzle is 0.054 mm

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Answer:

"192.3 watt" is the right answer.

Explanation:

Given:

Efficient amplifier,

= 65%

or,

= 0.65

Power,

\(P_c=250 \ watt\)

As we know,

⇒ \(P_t=P_c(1+\frac{\mu^2}{2} )\)

By putting the values, we get

        \(=P_c(1+\frac{1}{2} )\)

        \(=1.5 \ P_c\)

Now,

⇒ \(P_i=(P_t-P_c)\)

        \(=1.5 \ P_c-P_c\)

        \(=\frac{P_c}{2}\)

DC input (0.65) will be equal to "\((\frac{P_c}{2} )\)".

hence,

The DC input power will be:

= \(\frac{250}{2}\times \frac{1}{0.65}\)

= \(\frac{125}{0.65}\)

= \(192.3 \ watt\)

Answer:

Explanation:

For a job of applications engineer which require excellent technical skills, commitment  to working , ability to deal well and confidently with customers a willingness to travel and very intelligent and well-balanced personality.

The ten questions you should ask Maria to determine if she is qualified for the job are :

To calculate the total wellbore storage coefficient and the dimensionless wellbore storage coefficient,  it is necessary to obtain more details about the compressibility of the fluid and the fluctuations in fluid level observed during the drawdown experiment.

The wellbore's storage coefficient reflects the variation in fluid quantity resulting from a unit of pressure change in the same area. The subsequent equation can be utilized to compute it:

Wellbore Storage Coefficient (C) = (Change in Fluid Volume) / (Change in Pressure)

To estimate the wellbore storage coefficient without having the specific values of the oil formation volume factor (Bo) for a particular reservoir, we divide the wellbore storage coefficient by Bo.

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Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

Answer:

Inductive reactance is denoted by \(X_L\) where

\(X_L=2\pi fL\)

from looking at the equation, you can see that as frequency increases, so does the inductive reactance.

Answer:

1/6

Explanation:

A dice has 6 sides, the probability of 4 appearing is 1/6.

In the context of the National Electrical Code (NEC), "SI" stands for the International System of Units, also known as the metric system.

The NEC is a standard for electrical installations, adopted in the United States, and it includes provisions for electrical safety, wiring, and other aspects related to electrical systems.

The SI units are widely used in scientific, engineering, and technical fields globally, providing a standardized and coherent system of measurement.

The NEC references SI units for various electrical quantities, such as voltage (volts), current (amperes), resistance (ohms), power (watts), and others.

By adopting SI units, the NEC aligns with international standards and promotes consistency and compatibility in electrical installations.

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Answer:

false

Explanation:

(a) Factor of safety: Fs = 350 / 28.87 = 12.11. (b) Factor of safety: Fs = 350 / 23.84 = 14.68. (c) Factor of safety: Fs = 350 / 49.56 = 7.06. (d) Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(53.76 / 0.577, 88

The factor of safety against yielding is given by the ratio of the yield strength to the maximum allowable stress. For plane stress, the maximum allowable stress is determined by the distortion energy and maximum shear stress theories. Using these theories, we can calculate the maximum allowable stress for each plane stress state and then calculate the factor of safety.

(a) For σₓ = σy = 100 MPa,

Maximum shear stress theory: τmax = σ/2 = 100/2 = 50 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 100 + √0 + 0 = 100 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(50 / 0.577, 100 / 1.732) = 28.87 MPa

Factor of safety: Fs = 350 / 28.87 = 12.11

(b) For σₓ = 100 MPa and σy = 50 MPa,

Maximum shear stress theory: τmax = (σₓ - σy)/2 = 25 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 75 + √562.5 = 88.96 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(25 / 0.577, 88.96 / 1.732) = 23.84 MPa

Factor of safety: Fs = 350 / 23.84 = 14.68

(c) For σₓ = 100 MPa and Tₓy = -75 MPa,

Maximum shear stress theory: τmax = (σₓ + |Tₓy|)/2 = 87.5 MPa

Distortion energy theory: σmax = (σₓ + σy)/2 + √[(σₓ - σy)/2]^2 + τxy^2 = 100 + √(1875 + 5625) = 182.32 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(87.5 / 0.577, 182.32 / 1.732) = 49.56 MPa

Factor of safety: Fs = 350 / 49.56 = 7.06

(d) For σₓ = -50 MPa, σy = -75 MPa, and Txy = -50 MPa,

Maximum shear stress theory: τmax = √[(σₓ - σy)/2]^2 + Txy^2 = √[(25/2)^2 + 50^2] = 53.76 MPa

Distortion energy theory: σmax = √[(σₓ - σy)/2]^2 + Txy^2 + √[(σₓ + σy)/2]^2 = √[(25/2)^2 + 50^2] + √(625 + 5625)/2 = 88.96 MPa

Allowable stress: σallow = min(τmax / 0.577, σmax / 1.732) = min(53.76 / 0.577, 88

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The missing option is attached below

Turn the ignition to the on position after inserting the key. Just the electronics, leave the engine off.

After 10 minutes and 30 seconds, switch off the light by turning the key. Restart the key, then wait another 10 minutes and 30 seconds before turning it off once more. Low batteries are the primary culprit, but shock can also make the fob forget its pairing. Check your car's user manual for the correct steps to reset most remote controls. The fob needs to be reprogrammed if resetting does not fix the issue. The ignition is the component of an automobile engine where fuel is ignited. The ignition is immediately disconnected by the gadget. single-word noun. The ignition is the area inside an automobile where you turn the key to start the engine.

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Among the types of reversible hydrocolloid materials used in dentistry, the most viscous one is typically the agar hydrocolloid.

Agar hydrocolloid is a reversible hydrocolloid material that exhibits a high viscosity when heated and gels upon cooling. It is commonly used in the technique called "agar impression" or "agar-agar impression."

Agar hydrocolloid has a higher viscosity compared to other reversible hydrocolloid materials such as alginate. Its higher viscosity allows for better control and accuracy in capturing fine details of dental impressions. However, it also requires specific equipment and temperature control during the impression-taking process.

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The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

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Answer:

C - oil filters.

Explanation:

You must crush or drain oil filters for a minimum of 12 hours for recycling because used motor oil is hazardous waste and can affect the environment if disposed of properly so the government has created strict rules for proper disposal.

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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A wrench used to measure resistance while applying a twisting force using a common socket, and whose values are stated in inch-pounds or foot-pounds, is called a; Torque wrench.

The features of the wrench are given as;

The correct answer is Torque wrench because a torque wrench is simply a tool that is used to apply a particular torque to a fastener such as a bolt.

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The stress needed to obtain a dislocation velocity that is 5 times greater is approximately 372.98 MPa.

According to Johnston and Gilman, the relationship between dislocation velocity (V) and stress (σ) follows a power law equation: V = kσ^m, where k is a constant and m is the dislocation velocity exponent. In this case, m is given as 16.5. To find the stress needed to obtain a velocity 5 times greater than 1 cm/s, we can set up the following equation:

V_2 = 5V_1,

where V_1 is the initial velocity of 1 cm/s and V_2 is the desired velocity. Substituting the power law equation for both velocities, we get:

kσ_2^m = 5(kσ_1^m),

where σ_1 is the initial stress of 5.30 MPa. Since σ_1 is known, we can solve for σ_2:

σ_2^m = 5^m * σ_1^m,

σ_2 = (5^m * σ_1^m)^(1/m),

Substituting the given values, we have:

σ_2 = (5^16.5 * 5.30^16.5)^(1/16.5) ≈ 372.98 MPa.

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A line drawn from the leading edge to the trailing edge of an airfoil and equidistant at all points from the upper and lower contours is called the mean camber line.

The mean camber line is a very important concept in aerodynamics as it defines the overall shape of an airfoil and plays a key role in determining its aerodynamic characteristics, such as lift and drag. It is used to calculate the maximum thickness, maximum camber, and location of the maximum camber of an airfoil.

The mean camber line is typically used as a reference line when designing airfoils, and different shapes can be created by modifying it with specific curves and angles.

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Answer:

The most common and well known of these documents are memos and emails, which are used in every type of business. In addition to this, technical communicators also create instructions, product guides and documentation, graphs, charts, images, videos, and other forms of content.

There are many ways to communicate

technical information,

1. Planning sheet- describe the process - this

shows steps on how to make your drill drift-

telling us how us how to make it.

2.Drawings- this tells you the dimensions, size

of component/workpiece

Inspection sheets- check the measurements

are within given tolerances, this shows us

you've made it within those tolerances.

Instructions/ images of how to make your.

Technician A claims that a high-pressure small spare tyre may be used to operate a vehicle indefinitely. According to Technician B, the ABS system may set a code while utilizing a space-saving spare tyre. Because using a space-saving spare tyre can result in the ABS system setting a code, Technician B is correct.

A space saver spare tire is designed to be used in an emergency and temporarily.It can only be used to drive a limited distance at a slower speed and is lighter and smaller than a conventional tyre.It is true what Technician B says about utilising a space-saving spare tire—due to the variable tyre size, the ABS system may set a code. By utilizing sensors to keep an eye on each wheel, the ABS system keeps track of wheel speed. The technique uses the circumference of each tyre to determine wheel speed. The ABS system may set a code if the tyre size is different from what the system anticipates. Because a car shouldn't be driven for an extended period of time on a high-pressure tiny spare tyre, technician A is mistaken. Additionally, a high-pressure tiny spare tyre is made to be It can only be used to drive a limited distance at a slower speed and is lighter and smaller than a conventional tyre.It is true what Technician B says about utilising a space-saving spare tire—due to the variable tyre size, the ABS system may set a code.

By utilizing sensors to keep an eye on each wheel, the ABS system keeps track of wheel speed. The technique uses the circumference of each tyre to determine wheel speed. The ABS system may set a code if the tyre size is different from what the system anticipates. Because a car shouldn't be driven for an extended period of time on a high-pressure tiny spare tyre, technician A is mistaken. Additionally, a high-pressure tiny spare tyre is made to be

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Answer:

i have no idea

Explanation:

Answer:

it is okay depending on how u drive

The option that is not associated with the given term called urban sprawl is; Option A: Blocking high views

What is Urban Sprawl?

Urban sprawl is defined as the rapid expansion of the geographic boundaries of towns and cities which is often accompanied by low-density residential housing and increased reliance on the private automobilefor movement.

Looking at the given options, "blocking high views" is the option that is not typically a problem associated with urban sprawl because urbanization usually takes place on relatively flat levels.

The missing options are;

a. blocking high views

b. destroying animal habitats

c. overrunning farmland

d. reducing green space

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.