Distinguish between the two main types of mechanical waves

Answer:

These destructive frequencies entrain the thoughts towards disruption, disharmony, and disunity. Additionally, they also stimulate the controlling organ of the body — the brain — into disharmonious resonance, which ultimately creates disease and war.

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

In this case, we need to determine that specific heat for solid and liquid states of matter. By Heat Physics, we understand that specific heat is contained in the slopes of the two sensible phases in the following form:

\(\frac{\Delta T}{\Delta Q} = \frac{1}{m\cdot c}\) (1)

Where:

Solid phase

If we know that \(m = 9.80\,g\), \(T_{1} = 40\,^{\circ}C\), \(T_{2} = 235\,^{\circ}C\), \(Q_{1} = 183\,J\) and \(Q_{2} = 819\,J\), then the specific heat of the solid phase is:

\(c = \frac{\Delta Q}{m\cdot \Delta T}\)

\(c = \frac{819\,J-183\,J}{(9.80\,g)\cdot (235\,^{\circ}C - 40\,^{\circ}C)}\)

\(c = 0.333\,\frac{J}{g\cdot ^{\circ}C}\)

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

Liquid phase

If we know that \(m = 9.80\,g\), \(T_{3} = 230\,^{\circ}C\), \(T_{4} = 471\,^{\circ}C\), \(Q_{3} = 1470\,J\) and \(Q_{4} = 2870\,J\), then the specific heat of the liquid phase is:

\(c = \frac{\Delta Q}{m\cdot \Delta T}\)

\(c = \frac{2870\,J - 1470\,J}{(9.80\,g)\cdot (471\,^{\circ}C - 230\,^{\circ}C)}\)

\(c = 0.593\,\frac{J}{g\cdot ^{\circ}C}\)

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

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a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

The electric potential is the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field with negligible acceleration of the test charge to avoid producing kinetic energy or radiation by test charge.

SI unit: volt

Other units: statvolt

In SI base units: V = kg⋅m^2⋅A^−1⋅s^−3

Dimension: M L^2 T^−3 I^−1

Explanation:

Hope it is helpful....

Explanation:

common symbol - V

SI unit - volt

other unit - statvolt

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

When a charged particle moves through a magnetic field, it experiences a force known as the Lorentz force. The Lorentz force is given by the equation F = qvBsinθ, where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

In this scenario, an aluminum rod with a mass of 0.946 g is passed between the poles of a 0.41-T permanent magnet at a speed of 4.05 m/s at a 90o angle. Since aluminum is a conductor, it is expected that electrons in the metal will be free to move, allowing for a current to flow through the rod.

We can calculate the charge of the particle by using the equation F = ma, where F is the Lorentz force, m is the mass of the particle, and a is the acceleration of the particle.

The acceleration of the aluminum rod can be calculated using the equation a = F/m. Since the rod is moving at a constant velocity, the force due to air resistance can be ignored. Therefore, the force acting on the rod is solely due to the Lorentz force. Thus, we can write: a = F/m = qvBsinθ/m, Solving for q, we get: q = ma/vBsinθ = (0.946 x 10^-3 kg x 4.05 m/s)/(0.41 T x sin90o) = 9.26 x 10^-6 C.

Therefore, the charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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Answer:

C. Constant

Explanation:

The total energy of the cannonball remains constant as it travels through the air.

Answer:

Explanation:

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With a current shunt, the current is obtained by measuring voltage across the current shunt and calculating using Ohm's Law.

A current shunt is a device that is used to measure electric current. It is a small resistor placed in parallel with the load (or the element being measured), that creates a known small voltage drop proportional to the current flowing through it.

By measuring this voltage drop and using Ohm's law, the current flowing through the shunt (and the load) can be calculated. Current shunts are commonly used in high-current applications, such as in power plants, electrical distribution systems, and electric vehicles.

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With a current shunt, the current is obtained by measuring the voltage drop across the current shunt and calculating using Ohm’s Law. A current shunt is a device that creates a low-resistance path for electric current, to allow it to pass around another point in the circuit. In current measuring, shunts allow the measurement of high current values by placing a resistor of low, known resistance in parallel with a voltmeter.

Answer:

The time taken for the package to reach the ground is 20.6s

Explanation:

Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :

\(distance = speed \times time\)

\(let \: distance = 105 \\ let \: speed = 5.10\)

\(105 = 5.1 \times t\)

\(5.1t = 105\)

\(t = 105 \div 5.1\)

\(t = 20.6 \: second \: (3s.f)\)

Answer:

If the natural abundance of boron-11 is 80.1%, then the natural abundance of boron-10, the other stable isotope of boron, is 100% - 80.1% = 19.9%.

To determine how many of the 7,000 boron atoms are the boron-11 isotope, we can use the following steps:

Calculate the number of boron-10 atoms:

19.9% x 7,000 = 1,393

Calculate the number of boron-11 atoms:

80.1% x 7,000 = 5,607

Therefore, out of 7,000 boron atoms, 5,607 are the boron-11 isotope.

Explanation:

Answer:

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Explanation:

Answer:

  h’ = 1/9 h

Explanation:

This exercise must be solved in parts:

* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy

starting point. Higher

         Em₀ = U = m g h

final point. Lower, just before the crash

         Em_f = K = ½ m \(v_{b}^2\)

energy is conserved

         Em₀ = Em_f

         m g h = ½ m v²

         v_b = \(\sqrt{2gh}\)

* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved

initial instant. Just before the crash

         p₀ = 2m 0 + m v_b

final instant. Right after the crash

         p_f = (2m + m) v

the moment is preserved

         p₀ = p_f

         m v_b = 3m v

         v = v_b / 3

          v = ⅓ \(\sqrt{2gh}\)

* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together

Starting point. Lower

          Em₀ = K = ½ 3m v²

Final point. Higher

          Em_f = U = (3m) g h'

          Em₀ = Em_f

          ½ 3m v² = 3m g h’

we substitute

         h’=  \(\frac{v^2}{2g}\)

         h’ =  \(\frac{1}{3^2} \ \frac{ 2gh}{2g}\)

         h’ = 1/9 h

Answer: A.

tracking training through a leaming records store LRS.

Explanation:

An LRS uses xAPI to collect learner data, or experiences, from both online and offline sources. These experiences are reported back to the LRS in the form of xAPI statements, where they are stored. These statements can then be retrieved for reporting and interpretation of the learner data.

Given

The voltage of the battery, V=20.0 V

The resistance of the two resistors are 40 ohm each.

The two resistance are connected in parallel

To find

The current through the circuit.

Explanation

The resistors are connected in parallel

Thus the equivalent resistance is

By Ohm's law,

where I is the current through the battery

Putting the values

Conclusion

The current through the battery is 1.00 A

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer: Parallel

Explanation: Parallel because you don’t want all the lights to go out because of one light.

The electrical wiring and safety devices applied have to be perfect for non complainable circuit system  in houses. One thing have to ensure that all the electrical components needs to follow the requirements set by national electrical code.

Circuits are way for the passage of electrical current which consists of electrical wires and devices such as bulbs, fan etc. The circuit system have to be properly designed so that no overload or short circuit can be occured.

Proper thermal insulations for cables and wires have to be chosen. Moreover, all the electrical components should follow the standard requirements set by local bodies or national electrical code.

Safety devices such as circuit breaker or switches like fuse of standard quality must be applied to protect the devices. Circuit breakers are more better than fuses because they don't need replacements.

Similarly, the selection of wires of cables have to careful and need to check the quality of plastic sheaths on them.

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Answer:

The range of the projectile is 60 m

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

\(v_x=v_o\)

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

\(v_y=g.t\)

The horizontal distance is calculated as a constant speed motion:

\(x = v_x.t\)

Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:

x = 15*4 = 60

The range of the projectile is 60 m

According to the given statement  then the current in the secondary coil is 5A.

The correct option is B.

Transformers have at least two windings or coils, as seen in the experiment above. The primary is referred to as such, and the secondary as such. AC electricity enters the primary coil here. Where the current is induced to carry out any sort of energy transfer is in the secondary coil.

According to the question,

Current in primary coil, I\(_i_n\) = 10A

Power  = V\(_i_n\)I\(_i_n\) = V\(_o_u_t\)I\(_o_u_t\)

Then

By substituting the values,

V\(_i_n\)* 10 =V\(_i_n\)I\(_o_u_t\)

By applying cross-multiplication,

10 = 2I\(_o_u_t\)

I\(_o_u_t\) = 10/2

= 5A

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The complete question is -

A certain transformer doubles input voltage. If the primary coil has 10 A of current, then the current in the secondary coil is

A- 25 A.

B- 5 A.

C- none of the above

D- 2A.

E- 10 A.

The radio waves travels between the two boxes and they were travelling through air,

In that way, the radio waves from box A to B through air, the box A will gets the signal, and then modulates, amplifies and then it send out radio waves. Through the air, Box B will captures, amplifies and demodulates radio waves.

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12 Step 3

13 Step 2

14 Step 4

15 Step 4

16 Step 5

Answer:

-76

Explanation:

f(-6) = -3*-6^2-4*-6+8

= -3*36+24+8

= -108+32

= -76

Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

Answer:

Where's the question?

Explanation:

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Answer:

D.all of the above

Explanation:

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Answer:

0.95g/cm3

Explanation:

sorry I did it in a rough paper.

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