disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.

Answer:

La transformación energética, transformación de la energía, conversión energética o conversión de la energía es el proceso de cambiar la energía de un tipo de energía a otro. En física, la energía es una cantidad que proporciona la capacidad de realizar un trabajo (por ejemplo, levantar un objeto) o proporciona calor. Además de ser convertible, de acuerdo con la ley de conservación de la energía, la energía es transferible a una ubicación u objeto diferente, pero no se puede crear ni destruir.

La energía en muchas de sus formas se puede utilizar en procesos naturales o para proporcionar algún servicio a la sociedad, como calefacción, refrigeración, iluminación o realizar trabajos mecánicos para operar máquinas. Por ejemplo, para calentar una casa, el horno quema combustible, cuya energía potencial química se convierte en energía térmica, que luego se transfiere al aire de la casa para elevar su temperatura.

Explanation:

Energy refers to the ability or capacity to do work. Energy can be of various types as follows:

Kinetic energy is energy possessed by an object because of its motion while potential energy is energy possessed by an object because of its position or its condition.

The law of conservation of energy states that energy cannot be created nor destroyed but can only be transformed i.e. converted from one form to another.

Friction is a force that resists the relative motion or tendency to such motion of two bodies in contact.

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Hi there!

We can use the conservation of momentum to solve.

\(m_1v_1 + m_2v_2 = m_1v_1' + m_2v_2'\)

m1 = mass of rocket (40,000 kg)

m2 = mass of gas (300 kg)

v1, v2 = INITIAL velocities of rocket and gas (0 m/s)

v1' = FINAL velocity of rocket (+220 m/s, assuming UP to be positive)

v2' = FINAL velocity of gas (- ? m/s, DOWNWARD so negative)

This is an example of a "recoil" collision, so:

\(0 = m_1v_1' + m_2(v_2')\)

Set the two equal:

\(m_2(-v_2') = m_1v_1'\)

Plug in the givens:

\(300(-v_2') = (40,000)(220)\\\\\)

\(\v_2 = \boxed{-29,333.33 m/s}\)\(v_2 = \boxed{-29,333.33 m/s}\)

We are given the following information about an inelastic collision.

Mass of 1st object = 4 kg

Mass of 2nd object = 10 kg

Initial velocity of 1st object = 25 m/s

Final velocity of both objects = 14 m/s

Initial velocity of 2nd object = ?

In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.

Recall that the total momentum is conserved and given by

Let us substitute the given values and solve for initial velocity of the body (u2)

Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s

Rolyna throws the rock horizontally with a velocity of 15.82m/s.

The height of the rock that rolyna throws is 200 m while the horizontal distance covered by the rock is 100 m.

As the stone is thrown from a top hill the path of the rock will be a horizontal projectile.

The time period of flight of horizontal projectile is given by,

T = √(2H/g)

H is the height of The Rock, g is the acceleration due to gravity.

Now, putting all the values,

T = √((2×200)/10))

T = 6.32 seconds.

We know that there is no acceleration in the horizontal direction of the rock,

So, we can write,

Speed = horizontal distance/time

Speed = 100/6.32

Speed = 15.82m/s.

So, the initial velocity of the rock is 15.82m/s.

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Direction of |a+b| is south east and that of |a-b| is north east.

Given

a = 3i - 2j

b = -i - 4j

To find,

a+b =?

a-b =?

|a+b| = |(3i - 2j - i - 4j)|

        = |2i - 6j|

        = \(\sqrt{2^{2} + (-6^{2}) }\)

        = \(\sqrt{4+36}\)

        = \(\sqrt{40}\)

        = \(2\sqrt{10}\)

|a-b| = |(3i - 2j) - (-i - 4j)|

       = |3i -2j + i + 4j|

       = |4i + 2j|

       = \(\sqrt{4^{2} + 2^{2} } \\\)

       = \(\sqrt{16+ 4}\)

       = \(\sqrt{20}\)

       = \(2\sqrt{5}\)

Direction of |a+b| is south east (|2i - 6j|, this shows 2 units to the right and 6 units down)

Direction of |a-b| is north east (|4i + 2j|, this shows 4 units right & 2 units up)

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Answer:

Regardless of how the steps are documented, the goal of scientific method is to gather data that will validate or invalidate a cause and effect relationship.

Hope this helped!!!

Answer:

amino acids

Explanation:

protins made of amino acids

hope ur help

Answer:

AMINO ACIDS

Explanation:

Protein consists of carbon, hydrogen, oxygen, and nitrogen. The addition of nitrogen gives protein its unique distinction from carbohydrate and fat, along with establishing the signature name, amino acid.

Answer:

161,000 cm

Explanation:

1 mi × (1.61 km/mi) × (1000 m/km) × (100 cm/m) = 161,000 cm

Explanation:

the planet orbits slowly every night and different types of moon shine bright in the sky

Answer:

v = 4.79 10³ m / s

Explanation:

For this exercise we will use the universal law of gravitation and Newton's second law

          F = G M m / r²

where G is the gravitational constant, m the mass of the satellite, M the mass of the Earth, r the distance from the center of the planet to the satellite

           F = m a

since the satellite has a circular path, the acceleration is centripetal

          a = v² / r

we substitute

          G M m / r² = m v² / r

           G M / r = v²

We calculate

          v² = 6.67 10⁻¹¹ 5.98 10²⁴ / 6.96 10⁶

          v = √ (22.94 10⁶)

          v = 4.79 10³ m / s

Answer:

7570 m/s

Explanation:

take the square root of: 6.67E-11× 5.98E24/6.96E6

To find the output energy and output power of the sprinter, we can use the formulas for kinetic energy and power.

Output Energy:

The output energy is equal to the change in kinetic energy. The formula for kinetic energy is:

KE = 1/2 * mass * velocity^2

Given:

Mass (m) = 75 kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 8.0 m/s

Using the formula, we can calculate the change in kinetic energy:

ΔKE = 1/2 * m * (v^2 - u^2)

= 1/2 * 75 kg * (8.0 m/s)^2

Calculating the value:

ΔKE = 1/2 * 75 kg * 64 m^2/s^2

= 2400 J

Converting to kiloJoules (kJ):

Output Energy = 2400 J / 1000

= 2.4 kJ

Output Power:

The output power is the rate at which the work is done. The formula for power is:

Power = Work / Time

Given:

Time (t) = 5.0 s

Using the formula, we can calculate the output power:

Output Power = Output Energy / Time

= 2.4 kJ / 5.0 s

Calculating the value:

Output Power = 0.48 kW

Therefore, the output energy is 2.4 kJ and the output power is 0.48 kW.

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1. good morning mam going to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for

Most precipitation on the east coast and southeastern part of the United States is derived from moist air coming in from the Atlantic Ocean.

This is due to a combination of factors, including prevailing wind patterns, the proximity of the Gulf Stream, and the geography of the region. The prevailing winds in this part of the United States generally come from the southwest, which means that moist air from the Atlantic Ocean is carried over the region. As this moist air moves over the warm waters of the Gulf Stream, it picks up even more moisture, which can lead to increased precipitation.

In addition, the geography of the region also plays a role in precipitation patterns. The Appalachian Mountains run parallel to the east coast, and as moist air moves over these mountains, it is forced to rise, which can cause it to cool and condense, leading to precipitation.

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Answer:

the object's position.

Explanation: might help ion know

The integral in Ampere's law must be evaluated around a closed path, but the path itself can take on many different shapes and orientations.

In using Ampere's law, the integral must be evaluated around a closed path. Ampere's law is a fundamental principle in electromagnetism that relates the magnetic field around a closed loop to the electric current passing through the loop. The integral form of Ampere's law states that the line integral of the magnetic field around a closed loop is equal to the current passing through the loop multiplied by a constant known as the permeability of free space. This law is useful for calculating the magnetic field around various current-carrying structures such as wires, solenoids, and transformers.
The integral around the closed path can be evaluated in any direction, clockwise or counter-clockwise, as long as it follows the right-hand rule for magnetic field direction. The path can be any shape, as long as it is closed and the current passes through the loop. The integral can also be evaluated in multiple segments if the path is not continuous. In summary, the integral in Ampere's law must be evaluated around a closed path, but the path itself can take on many different shapes and orientations.

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The only claim that is supported by the interval is claim E: The mean number of porcupine teeth marks on all wooden blocks treated with the repellent is less than 6.

The 95% confidence interval (4.9, 5.8) means that if we were to repeat the experiment multiple times, the true mean number of porcupine teeth marks on all wooden blocks treated with the repellent would be expected to fall within the interval 95% of the time.

Since the interval does not contain the value 5, we can conclude that claim B is not supported by the interval. We cannot conclude whether claim A is supported or not since the interval includes values both below and above 5.

Similarly, claim C is not supported since the interval does not include the value 6. Claim D is also not supported since the interval does not extend above 5.8.

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the complete question is :

Porcupines can cause damage to wood structures by chewing them. Researchers studied a liquid repellent

designed to reduce such damage. A sample of 20 wooden blocks of the same size were treated with the

repellent and left outside in an area where porcupines are known to live. After a certain amount of time, the

blocks were inspected for the number of porcupine teeth marks visible. The data were used to create the

95 percent confidence interval (4.9,5.8).

Which of the following claims is supported by the interval?

A

The expected number of porcupine teeth marks on a wooden block treated with the repellent is less than 5.

B- The expected number of porcupine teeth marks on a wooden block treated with the

repellent is 5.

с- The mean number of porcupine teeth marks on all wooden blocks treated with the

repellent is 6.

D- The mean number of porcupine teeth marks on all wooden blocks treated with the repellent is greater than 6.

E- The mean number of porcupine teeth marks on all wooden blocks treated with the repellent is less than 6.

Answer:

a. normal

Explanation:

In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.

Answer:

The term "scientific methods" are more accurate than "scientific method" because "s" used in "scientific methods" makes the word plural and science experiments use several observations to get a result and not only based on single observation.

So, "scientific methods" is a plural term that is more accurate than "scientific method".

To derive an expression for the coefficient of kinetic friction (µ) between the wreckage and the road, we can start by considering the conservation of momentum in the x-direction.

Before the collision, the car has momentum mv in the positive y-direction, while the pickup truck has momentum Mvcos(θ) in the positive x-direction. After the collision, the fused wreckage comes to a stop, so the final momentum is zero.

By applying the principle of conservation of momentum, we can write the equation: mv + Mvcos(θ) = 0. Rearranging the equation, we get µ = -mv / (Mvcos(θ)). Since we are interested in the coefficient of kinetic friction, which is a positive value, we can take the absolute value of the expression.

In this problem, a car and a pickup truck collide and stick together, forming a fused wreckage that skids along the road until it comes to a stop. The coefficient of kinetic friction (µ) between the wreckage and the road is the parameter of interest.

To derive an expression for µ, we apply the principle of conservation of momentum in the x-direction. Before the collision, the car has momentum in the positive y-direction, while the pickup truck has momentum in the positive x-direction. After the collision, the fused wreckage comes to a stop, resulting in zero final momentum. By setting up and solving the conservation of momentum equation, we can derive an expression for µ in terms of the given parameters m, M, v, θ, and the distance D.

The expression µ = -mv / (Mvcos(θ)) represents the coefficient of kinetic friction between the wreckage and the road. The negative sign arises because the friction force acts in the opposite direction to the motion. The expression demonstrates the relationship between the masses, velocities, angle of collision, and the coefficient of kinetic friction in determining the skidding distance D of the wreckage along the road.

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The mechanism that causes the air to rise and cool on the windward side of the mountain range is convection, which plays a significant part in creating the rain shadow effect.

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Answer:

उव्ग्वुव ह्व्झ एउएइहे एइएइएइएएइ सिसुब्स्सी बीस सिस इस्ब एइब

Explanation:

?उग्व्ब्वु विब्सिए इसिग्व विद्बिअब्द सिह्व्व इस्ब्व दिव्ब्स विह्द ऐद्जिइ सुउगव्दी सिइगैगे क्ज्गैइव अजिव्व्ज्व्स कैह्द अजि ह्ज्फ्ज इअह इकुगै ईग इअबे अजिव्ब जैइअब इऐहे ऐइहे ऐइग्गे अत्व्ब ओप्झब रोज दिधिए ऊइफ्ब इसुहद ईउहे सिउउअ दिइब्द स्सिउए ऐइहे सिएय्व एउविये एइव्वे

The resultant array is v = [10; 13; 82; 91; 92; 64].

To perform an insertion sort, we start with the first element of the array and iterate through the remaining elements. For each element, we compare it with the elements before it and insert it in the correct position.

Given the array v = [82; 91; 13; 92; 64; 10], let's perform two full insert processes:

1. First insert process:
- v = [82; 91; 13; 92; 64; 10]
- Compare 91 with 82. Since 91 is greater, no change is needed.
- Compare 13 with 91 and 82. Move 13 to the beginning of the array.
- v = [13; 82; 91; 92; 64; 10]

2. Second insert process:
- v = [13; 82; 91; 92; 64; 10]
- Compare 82 with 13. Since 82 is greater, no change is needed.
- Compare 91 with 82 and 13. Since 91 is greater, no change is needed.
- Compare 92 with 91, 82, and 13. Move 92 to the end of the array.
- Compare 64 with 92, 91, 82, and 13. Move 64 to the correct position between 13 and 82.
- Compare 10 with 64, 92, 91, 82, and 13. Move 10 to the beginning of the array.
- v = [10; 13; 82; 91; 92; 64]

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Explanation:

Dissolve 2 -naphthol in ethanol in a round bottom flask.

Add sodium hydroxide pellets and boiling chips. Attach a condenser.

Heat under reflux for 20 minutes, until all the base dissolves.

Add 1 -bromobutane and reflux for an additional hour.

Pour the contents fo the round bottom flask into a beaker of ice

Collect the precipitate by vacuum filtration on a Bachner funnel

Rinse the product with cold water and dry it on the filter.

Answer:

A) Sue is lifting the bucket by a force of 49.035 newtons.

B) The bucket has an acceleration of 8.207 meters per square second on the Moon.

Explanation:

A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:

\(\Sigma F = F - m\cdot g = 0\) (1)

Where:

\(F\) - Lifting force, measured in newtons.

\(m\) - Mass of the bucket, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:

\(F = m\cdot g\)

\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(F = 49.035\,N\)

Sue is lifting the bucket by a force of 49.035 newtons.

B) By the Second Newton's Law, we have the following model:

\(\Sigma F = F-m\cdot g = m\cdot a\) (2)

Where \(a\) is the net acceleration of the bucket, measured in meters per square second.

If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:

\(a = \frac{F}{m} -g\)

\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)

\(a = 8.207\,\frac{m}{s^{2}}\)

The bucket has an acceleration of 8.207 meters per square second on the Moon.

(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.

(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².

The given parameters;

The force applied by Sue in lifting the bucket at a constant velocity is calculated as;

\(F = m(a + g)\)

\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)

The acceleration of the bucket when lifted on the moon with the calculated force is;

\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)

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Answer:

the current is 5.2 Amps

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + \(v_{oy}\) t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        \(v_{y}\) = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero (\(v_{oy}\) = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s