Discuss the effect of β, on the order of centrality measures of connected graph? Suppose, for a given β, node A has more centrality then node B, Can we reverse the effect, by choosing different β i.e. node B, now will have more centrality then node A? [4 Marks]

Answer:

Wireless

Explanation:

A wireless remote control can be an advantage to an operator who is welding close to the power source. Hence, option A is correct.

An electrical device used to wirelessly and remotely operate another device is a remote control, often known as a remote or clicker. Consumer gadgets, such as television sets, DVD players, and other home appliances, can be controlled by a remote control.

In the current electronic market, remote control systems fall into three primary categories: IR-based systems, RD-based systems, and BT-based systems. the receiver and the remote must be lined up exactly for infrared, also known as IR.

IR, on the other hand, is unable to pass through a number of materials but can operate over a much wider spectrum. This allows the user far greater freedom and control in environments with challenging terrain and obstacles.

Thus, option A is correct.

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The power inside the ammeter is given by a multiple of E/R of 0.288E/R.

Each of these instruments are employed in electric circuits, but the main distinction between an ammeter and a voltmeter is that the voltmeter is useful for measuring the volts or emf between two points inside an electric circuit, whilst the ammeter is useful for measuring the current that flows.

In digital ammeter systems, a shunt resistor is employed to generate a calibrated voltage corresponding to the current flowing. The analog-to-digital converter (ADC) in a digital voltmeter is then used to measure this voltage; the digital showcase is calibrated to show the current flowing through the shunt.

3.88R, R in parallel so equivalent of both \(=\frac{3.88R}{4.88} =0.795R\)

R and in parallel so equivalent of both \(=0.5R\)

\(I=\frac{E}{R}=\frac{E}{1.295R}\)

\(I=0.772E/R\)

\(I_{1}=0.772*\frac{1}{4.88}E/R\)

\(I_{1}=0.158E/R\)

\(I_{2} =0.1614E/R\)

\(I_{2}=\frac{0.386E}{R}\)

\(I_{A}=I_{2} I_{r}\\\)

\(I_{A}=0.228\frac{E}{R}\)

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Answer:

The answer is below

Explanation:

Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.

It results in material forming a hard surface membrane, while the inner layer is soft.

It is mostly used for universal joints, construction cranes, machine tools, etc.

On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.

It increases the hardness and brittleness of the material.

It is often used for axles, blades, nuts and bolts, nails, etc.

a) The steps that Ms. Shell must take in this regards to solve the puzzle are listed from step 1 to step 11.

b) No, it can't be used to solve the same problem as we will keep getting measurement in multiples of 3.

a) We're told that she has 2 opaque cans. The capacity of each of the opaque cans are 8 liters and 5 liters.

The procedure to measure 1- liter, 2- liters, 3- liters, 4- liters, 6- liters and 7- liters are as follows;

Step 1; Fill the 5 liters opaque barrel with oil painting and also pour it into the 8 liters opaque barrel.

Step 2; Fill the 5 liters opaque barrel right again and also pour it into the 8 liters opaque barrel. This would mean that the 8 liters barrel will be full and we will have 2 liters left in the 5 liters opaque barrel which takes care of the 2 liters measure.

Step 3; Drain the 8 liters opaque barrel and also pour the 2 liters left from the 5 liters tap right into it.

Step 4; With the 5 liters opaque barrel now empty, fill it again and pour it right into the 8 liters tap to make 7 liters inside the 8 liters barrel. This takes care of the 7 liters measure.

Step 5; Now, drain the 5 liters opaque barrel and also refill it. When it gets full pour it into 8 liters that presently has 7 liters until it gets full

Step 6 Since the 8 liters barrel is now full, it means that 4 liters of oil painting are left in the 5 liters opaque barrel. This takes care of the 4 liters measure.

Step 7; Empty the 8 liters opaque barrel and pour the 4 liters left in the 5 liters tap into it.

Step 8; Fill the 5 liters again and pour into the formerly being 4 liters inside the 8 liters opaque barrel to get the 8 liters full and 1 liter remaining in the 5 liters opaque barrel. This takes care of the 1 liter measure.

Step 9; Empty both of the opaque cans, also fill the 8 liters opaque barrel and also pour it right into the 5 liters opaque barrel till it gets full. There would now be 3 liters left in the 8 liters barrel and this takes care of the 3 liters measure.

Step 10; Drain the 5 liters opaque barrel and pour the 3 liters oil painting from 8 liters tap into it.

Step 11; Fill the 8 liters opaque barrel again and pour it into the 5 liters barrel which presently has 3 liters outside. Upon filling the 5 liters tap from the 8 liters barrel, we will get 6 liters oil painting.

b) We're told that you now have 9- liters and 6- liters opaque cans as against 8- liters and 5- liters.

Due to the fact that 9 and 6 share the same multiple of 3, it means that we can not use this to get an odd number of liters and neither can we use it to find the other number of liters because it'll keep us giving us dimension in multiple of 3.

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probably in it's chromosomes

Technicians A and B both make partially truthful claims, but neither is entirely true. A certain class of crystal called a piezoelectric material can transform mechanical pressure or vibrational energy into electrical energy.

Piezoelectric crystals have a balanced charge and an asymmetric atomic structure. When mechanical pressure is applied, the structure deforms, forcing the positive charge and the negative charge apart. This refers to the direct piezoelectric effect.

In crystalline materials without inversion symmetry, the linear electromechanical connection between the mechanical and electrical states leads to the piezoelectric effect.

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The statement "the enormous gains in crop yields brought about by green revolution technologies may soon stop" is definitely true.

The green revolution may be defined as a type of revolution in which there would be a great increase in the production of food grains (such as rice and wheat) due to the introduction of high-yielding varieties, the use of pesticides, and better management techniques.

It started around the 1960s and helped in increasing food production in the country. The green revolution's primary aim was to introduce high-yielding varieties (HYVs) of cereals to alleviate poverty and malnutrition. They soon stop because they are not much efficient as pear present needs and conditions.

Therefore, the statement "the enormous gains in crop yields brought about by green revolution technologies may soon stop" is definitely true.

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Answer:

take your foot off of the accelorator. do not brake and let the vehicle coast until it stops. put on your hazard lights as well

Explanation:

During a 12-volt charging system voltmeter test, it is recommended to turn off all electrical accessories to get an accurate reading of the system's voltage.

A charging system voltmeter test is a diagnostic procedure performed to assess the voltage output of the charging system in a vehicle. The charging system is responsible for maintaining the battery's charge and providing electrical power to the vehicle's electrical components while the engine is running.

To conduct a charging system voltmeter test, a voltmeter is connected to the battery terminals or the charging system's output terminal. The engine is then started, and the voltmeter measures the voltage output of the charging system.

By turning off the electrical accessories, you can eliminate any potential load on the system, allowing you to measure the actual voltage output. This will provide a more reliable assessment of the charging system's performance.

Therefore, during a 12-volt charging system voltmeter test, it is recommended to turn off all electrical accessories to get an accurate reading of the system's voltage.

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Because it is an excellent conductor, copper is used for the majority of electrical wiring, and shorter cables reduce the resistance of wires carrying an electric current.

1)smaller wires

2)NOT X: Electron flow

Y: Lots of potential energy

Z: Minimal potential energy

3)Volts

4) It has strong conductivity.

5) The charges move more slowly in current Y because of the larger potential difference.

6)NOT

insulator,

semiconductor,

conductor,

superconductor

7)Differences in electric potential  

8) a cold slice of lead metal

9) Electrons flow between regions with high and low electric potential.

10) long and lean

The copper produced by electrolysis is known as pure copper or electrolytic copper. Numerous types of electrical wiring use copper as its electrical conductor. Electricity is produced, transmitted, and distributed via copper wire in telecommunications, electronic circuits, and a variety of other electrical devices.

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Answer:

False

Explanation:

Answer:

a.)

US Sieve no.                         % finer (C₅ )

4                                                  100

10                                                95.61

20                                               82.98

40                                               61.50

60                                               42.08

100                                              20.19

200                                              6.3

Pan                                               0

b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4

c.) Cu = 3.33

d.) Cc = 1

Explanation:

As given ,

US Sieve no.             Mass of soil retained (C₂ )

4                                            0

10                                          18.5

20                                         53.2

40                                         90.5

60                                         81.8

100                                        92.2

200                                       58.5

Pan                                        26.5

Now,

Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g

⇒ w = 421.2 g

As we know that ,

% Retained = C₃ = C₂×\(\frac{100}{w}\)

∴ we get

US Sieve no.               % retained (C₃ )               Cummulative % retained (C₄)

4                                            0                                           0

10                                          4.39                                      4.39

20                                         12.63                                     17.02

40                                         21.48                                     38.50

60                                         19.42                                     57.92

100                                        21.89                                     79.81

200                                       13.89                                     93.70

Pan                                        6.30                                      100

Now,

% finer = C₅ = 100 - C₄

∴ we get

US Sieve no.               Cummulative % retained (C₄)          % finer (C₅ )

4                                                     0                                          100

10                                                  4.39                                      95.61

20                                                 17.02                                     82.98

40                                                 38.50                                    61.50

60                                                 57.92                                    42.08

100                                                79.81                                     20.19

200                                                93.70                                   6.3

Pan                                                 100                                        0

The grain-size distribution is :

b.)

From the diagram , we can see that

D10 = 0.12

D30 = 0.22

D60 = 0.12

c.)

Uniformity Coefficient = Cu = \(\frac{D60}{D10}\)

⇒ Cu = \(\frac{0.4}{0.12} = 3.33\)

d.)

Coefficient of Graduation = Cc = \(\frac{D30^{2}}{D10 . D60}\)

⇒ Cc = \(\frac{0.22^{2}}{(0.4) . (0.12)}\) = 1

Answer:

no

Explanation:

How many trees would it take to reverse climate change?

1.2 trillion trees

Crowther says planting 1.2 trillion trees would give a reduction "way above" that figure. To put that in context, global CO2 emissions are around 37 billion tons per year.Apr 17, 2019

Answer:

Use cases are known to be a set of instruction  or processes between a User/Actor with the system to produce a desired input.

With the aid of a diagram, the set of use cases that are carried out in this ATM are given below:

Insert PIN

(1)Perform required transaction

(2)Withdrawal

(3)Deposit

(4)Transfer

(5)Change PIN

(6)Exit

Note: Kindly find an attached diagram of the Use case as part of the solution to process carried out at the ATM

Sources: The diagram of the Use case for ATM was researched and taken from Quizlet.

Explanation:

Solution

Use cases are normally a set of instruction  or processes between a User/Actor with the system to produce a desired input.

A use case diagram or image is a graphical representation of all the use case or processes that connects or interact with the system

The use case diagram is a part of Unified Modelling Language also called the UML.

The set of use cases that are carried out in this ATM use case diagram to know the requirements of the ATM is shown below:

Now both the customer/client and Bank are seen as Actors.

Actors are the ones or people that interface with the system.

The ATM is often used to withdraw money and it also have some requirement.

Some of the use-cases that could serve as a basis for understanding the requirements for an ATM system are;

Customer (actor)  often uses bank ATM to know or see the Balances of his/her bank accounts. They use it also to Deposit Funds and Withdraw Cash.

They can also use it to Transfer Funds (use cases). ATM Technician are known to give a form of Maintenance and Repairs. All these used cases is one that involve Bank as the actor  when it is liked to customer transactions or to the ATM servicing.

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The vertical reinforcing steel requirement for an 8" thick masonry foundation wall that is 7'6" high, supporting 6'6" of unbalanced backfill with a lateral load of 60 psf is #5 at 48" o.c. The correct option is 3.

The minimum vertical reinforcing steel requirement for a foundation wall is determined by the height of the wall, the thickness of the wall, the load on the wall, and the unbalanced backfill. The minimum size and spacing of vertical reinforcing bars in a masonry wall are specified in ACI 530-11/ASCE 5-11/TMS 402-11. The vertical reinforcing steel requirement for a masonry foundation wall is determined by the formula:

A = (0.0025hd) / s where A is the area of vertical reinforcement (\(in^{2} /ft\)), h is the height of the wall (ft), d is the effective thickness of the wall (ft), and s is the spacing of the bars (in).

The minimum area of vertical reinforcement should not be less than 0.0025 times the product of the height and effective thickness of the wall. The minimum spacing of vertical bars is 48 inches or the thickness of the wall, whichever is less.

For an 8" thick wall with a height of 7'6" and a lateral load of 60 psf, the minimum area of vertical reinforcement is:

0.0025 × 7.5 × 0.67 = 0.0126 (\(in^{2} /ft\)).

The minimum size of the vertical bar is #5 (0.162 in2).

Therefore, the minimum number of bars required is:

0.0126 / 0.162 = 0.0777, which is rounded up to 0.08.

Thus, the minimum spacing of vertical bars is 12 / 0.08 = 48 inches. Therefore, the minimum vertical reinforcing steel requirement is #5 at 48 inches o.c., which is option 3.

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A minimum set of requirements for plumbing installations in a municipality, city, county, or state is a plumbing code.

A plumbing code is a set of minimum standards and regulations that dictate the design, installation, and maintenance of plumbing systems. The code is typically enforced by local or state authorities and serves to protect public health and safety by ensuring that plumbing systems are safe, functional, and sanitary. Plumbing codes cover a wide range of requirements, including the size and type of pipes and fittings, fixture installation and location, drainage and venting, water supply, and backflow prevention. Plumbing codes are updated periodically to reflect advances in technology, changes in building materials, and new safety and environmental concerns. Compliance with the plumbing code is mandatory, and failure to meet the code requirements can result in fines, penalties, or legal action.

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75743366

Explanation:

Answer:

14 cents

Explanation:

1 trillion US dollar

To retrieve information from an articles' database using the HTTP GET method, we can use a URL with a query string that specifies the parameters of the search. The URL will typically begin with the base API endpoint followed by the resource we are interested in, in this case, the articles.

We can also include pagination information in the query string if the results are paginated. The basic format of the URL will be "http://example.com/api/articles?param1=value1&param2=value2&page=2".

To retrieve the first page of articles from the database, we can use the following URL:

```

http://example.com/api/articles?page=1

```

This will retrieve the first page of articles, assuming that the default number of results per page is 10. If we want to retrieve the second page, we can append `&page=2` to the URL, and so on for subsequent pages. We can also specify additional parameters in the query string to filter the results, such as by author or by date.

Once we have retrieved the data, we can parse it and display it to the user. If the results are paginated, we can provide links or buttons to allow the user to navigate between pages of results. We can also provide additional options to the user to sort or filter the results, depending on the capabilities of the API.

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Answer:

Hello There!!

Explanation:

The answer is territorial.

hope this helps,have a great day!!

~Pinky~

\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)

The county is normally the state's largest political and Territorial unit.

To help Lewis with his request, we can create a style rule for data cells with the attribute data date containing the text "Sep". Here's the code for it:

td[data-date*="Sep"] {
 background-color: rgba(232, 214, 148, 0.6);
 box-shadow: inset 0 0 20px gray;
}

For the table caption, we can create another style rule with the following code:

caption {
 caption-side: top;
 text-align: center;
 padding-bottom: 10px;
 font-size: 1.2em;
 letter-spacing: 3px;
}

To style the heading cells within the table header, we can add this code:

th {
 background-color: rgb(154, 64, 3);
 color: white;
}

Moving on to the "Column Styles" section, we can create a style rule for the article element as requested. Here's the code:

article {
 column-width: 260px;
 column-gap: 20px;
 border-right: 1px solid rgb(154, 64, 31);
 orphans: 2;
 widows: 2;
}

Lastly, to extend the h1 heading across all columns, we can add this code:

article h1 {
 column-span: all;
}

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The area of the cross-section is reduced by a factor of four when the tube's diameter is cut in half, connections  which results in a two-fold reduction in the volume flow rate.

The volume flow rate through a tube with a uniform cross sectional area and a fluid moving at a constant rate is equal to the cross-sectional area times the fluid's velocity. As a result, when the tube's diameter is cut in half, the cross-sectional area is decreased by a factor of four, which lowers the volume flow rate by a factor of two. All fluids, including an ideal fluid like water, have this effect. The principle of continuity, which stipulates that a fluid's volume flow rate must remain constant along a conduit provided that the fluid is incompressible and there are no sources or sinks, provides an explanation for this behavior.

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The answer is analyze

Answer:

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The horizontal forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

Answer:

\(\mathbf{\Delta_{max}=0.78 \ mm}\)

Explanation:

From the given information;

A simply supported beam (E = 12 GPa)

load q = 125 N/m

point load P = 200 N

the rectangular cross section

b = 75 mm

h = 200 mm

length = 3.6 m

The objective is to  calculate the maximum deflection of the beam;

Using the formula;

\(I = \dfrac{1}{E}*bh^3\)    about the z-axis that goes through the central

\(I = \dfrac{1}{12}*(75 \ mm)*(200 \ mm)^3\)

\(I = 5*10^7 \ mm^4\)

The length L = 3.6 m = 3600 mm

The maximum deflection of the beam can be calculated by using the formula:

\(\Delta _{max} = \dfrac{5}{384}* \dfrac{qL^4}{EI}+\dfrac{PL^3}{48EI}\)

\(\Delta _{max} = \dfrac{1}{12*10^3 \frac{N}{mm^2}*5*10^7 \ mm^4 }[ \dfrac{5*\frac{125 \ N}{100 \ mm}*3600 \ mm^4}{384}+\dfrac{200*(3600 \ mm )^3}{48}]\)

Thus; the maximum deflection of the beam is \(\mathbf{\Delta_{max}=0.78 \ mm}\)

Flexural strength, also known as modulus of rupture, is a measure of a material's ability to resist bending or breaking under a flexural load. It indicates the maximum stress experienced by the material at the moment of failure during a flexural test. It is calculated by dividing the maximum load applied to the material by the cross-sectional area of the material.

The flexural strength for a round specimen of MgO with a radius of 4mm, tested in a three-point bend test with a separation between load points of 50mm and an applied load at failure of 425N, can be calculated using the formula:

Flexural Strength = (3 * Load * Span) / (2 * Pi * Radius^2)

Substituting the given values:

Load = 425N

Span = 50mm = 0.05m

Radius = 4mm = 0.004m

Flexural Strength = (3 * 425N * 0.05m) / (2 * Pi * (0.004m)^2)

Calculating this expression yields a value of approximately 105.7 MPa.

Therefore, the flexural strength for the given specimen is approximately 105.7 MPa.

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Answer:

1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS

Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).

2. SLOW DOWN AND PULL OFF THE ROAD

Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.

3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE

The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.

4. STAY IN YOUR VEHICLE

If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.

5. BE VISIBLE

Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.

6. SET UP FLARES OR TRIANGLES

Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.

7. CALL FOR HELP

Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.

Hope this helps :)

I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.