Angle D and angle B are congruent because they are corresponding angles. Angle E and C are also congruent because they are corresponding angles.
The diameters of ball bearings are distributed normally. The mean diameter is 138 millimeters and the variance is 9. Find the probability that the diameter of a selected bearing is between 143 and 144 millimeters. Round your answer to four decimal places.
The probability that the diameter of a selected ball bearing is between 143 and 144 millimeters, given a normal distribution with a mean diameter of 138 millimeters and a variance of 9. Therefore, the probability that the diameter of a selected ball bearing is between 143 and 144 millimeters is approximately 0.0247
To calculate the probability, we first need to standardize the values of 143 and 144 millimeters using the z-score formula:
z = (x - μ) / σ
where x is the value, μ is the mean, and σ is the standard deviation.
In this case, the mean (μ) is 138 millimeters and the variance (σ^2) is 9, so the standard deviation (σ) is the square root of the variance, which is √9 = 3.
For 143 millimeters:
z1 = (143 - 138) / 3 = 5 / 3 ≈ 1.6667
For 144 millimeters:
z2 = (144 - 138) / 3 = 6 / 3 = 2
Next, we need to use the standard normal distribution table or a calculator to find the probability associated with these z-scores. The probability between these two z-scores represents the probability of the diameter being between 143 and 144 millimeters.
Using the table or a calculator, we find that the cumulative probability corresponding to z1 = 1.6667 is approximately 0.9525, and the cumulative probability corresponding to z2 = 2 is approximately 0.9772.
To find the probability between 143 and 144 millimeters, we subtract the cumulative probability corresponding to z1 from the cumulative probability corresponding to z2:
P(143 < x < 144) = P(z1 < Z < z2) = P(z2) - P(z1) = 0.9772 - 0.9525 ≈ 0.0247
Therefore, the probability that the diameter of a selected ball bearing is between 143 and 144 millimeters is approximately 0.0247 (or 2.47% rounded to four decimal places).
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The initial and terminal points of RS are given below. Write the vector as a linear combination of standard unit vectors i and j.
R(11,-4) and S(10, 3)
The vector as a linear combination of standard unit vectors i and j is,
⇒ - i + 7j
We have to given that;
The initial and terminal points of RS are given below,
⇒ R(11, -4) and S(10, 3)
Hence, We can write as;
R = 11i - 4j
S = 10i + 3j
Hence, The vector as a linear combination of standard unit vectors i and j is,
⇒ RS = S - R
= (10i + 3j) - (11i - 4j)
= - i + 7j
Thus, The vector as a linear combination of standard unit vectors i and j is,
⇒ - i + 7j
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Please help me I will give you extra points and whoever the first one to answer I mark you with the brain thing. 6
Answer:
20 gallons per 10 mintues or 10 gallons per minute so c!
Step-by-step explanation:
We can see the time going up in incriments of 10 and gallons going down in incrimients of 20. This gives us the answer.
Find the greatest common factor of 14a and 11a^2
Answer:
a
Step-by-step explanation:
A hot air balloon traveled 2.5 hours at a speed of 450 km/hr. What distance did it travel?
Answer:
1,125 km
Step-by-step explanation:
So you want to find out how far the balloon went and we already know how fast and how long it's been traveling for. So now, all you have to do is come up with an equation which looks like:
2.5 x 450
Which equals 1,125 km.
The speed 450km/hour tells us that the balloon travels 450km in one hour. To find how much it traveled in 2.5 hours, we multiply 450 by 2.5.
450 x 2.5 = 1125 km
Therefore, the balloon traveled 1125 km in 2.5 hours
I don’t understand this at all
keeping in mind that Mt Everest is 8000 meters, or namely 8 Kilometers, Check the picture below.
15 columns of equal number of tiles are paved in a path. If the total number of tiles used are 1845, then how many rows of tiles are there in the path?
The total number of rows of tiles paved in a path 1845 total used tiles is equal to 15.
Total number of tiles used = 1845
Number of columns = 15
Let us assume that there are 'n' rows of tiles in the path.
Since there are 15 columns of equal number of tiles.
Divide the total number of tiles used by the number of columns to get the number of tiles in each column.
⇒Number of tiles in each column = Total number of tiles / Number of columns
⇒Number of tiles in each column = 1845 / 15
⇒Number of tiles in each column = 123
So each column has 123 tiles.
The number of rows,
= Divide total number of tiles used by the number of tiles in each row same as number of tiles in each column.
⇒ Number of rows = Total number of tiles / Number of tiles in each row
⇒ Number of rows = 1845 / 123
⇒ Number of rows = 15
Therefore, there are 15 rows of tiles in the path.
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nth term of quadratic sequence 3,11,25.45
Answer:
it's formula is tn=a+(n-1)d
Step-by-step explanation:
if you have to solve it then you need to find the common difference and it's formula ist2-t1Given the points A(1,-3) and B(-4,7), find the slope of a line parallel to line AB.
m=2
m=-1/2
m =-2
m=1/2
======================================================
Explanation:
Let's find the slope of line AB
m = (y2-y1)/(x2-x1)
m = (7-(-3))/(-4-1)
m = (7+3)/(-4-1)
m = 10/(-5)
m = -2
The slope of line AB is -2
The slope of any line parallel to line AB will also have the same slope.
Parallel lines have equal slopes, but different y intercepts.
4/5 as an equivalent fraction in 3 different forms.
Answer:
Equivalent fraction of ⅘:
\( \frac{4}{5} = \frac{8}{10} = \frac{12}{15} = \frac{16}{20} \)
2.45 convert the following unsigned binary numbers to hexadecimal. a. 1101 0001 1010 1111 b. 001 1111 c. 1 d. 1110 1101 1011 0010
a. 1101 0001 1010 1111 --> D1AF, b. 001 1111 --> 1F, c. 1 --> 1, d. 1110 1101 1011 0010 --> EDB2.
What is the hexadecimal representation of the given binary numbers?
Converting binary numbers to hexadecimal involves grouping the binary digits into sets of four, starting from the rightmost digit. Each group is then converted to its corresponding hexadecimal digit.
In the first step, we convert the binary numbers to hexadecimal as follows:
a. 1101 0001 1010 1111 --> D1AF
b. 001 1111 --> 1F
c. 1 --> 1
d. 1110 1101 1011 0010 --> EDB2
In binary, each digit represents a power of 2, while in hexadecimal, each digit represents a power of 16.
The conversion simplifies the representation and allows for easier understanding and manipulation of binary numbers.
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find the area of the surface defined by z = xy and x2 + y2 ≤ 2.
Answer:i think the anwser is 6
Step-by-step explanation:
The area of the surface defined by z = xy and x2 + y2 ≤ 22 would be, Area = ∬ sqrt(1 + r^2) * r dr dθ, with limits 0 ≤ r ≤ sqrt(2) and 0 ≤ θ ≤ 2π.Evaluate the integral to get the area of the surface.
To find the area of the surface defined by z = xy and x^2 + y^2 ≤ 2, we need to use a double integral over the region bounded by the inequality x^2 + y^2 ≤ 2.
First, we should rewrite the inequality in polar coordinates: x^2 + y^2 ≤ 2 becomes r^2 ≤ 2, where r is the radial distance and θ is the angle. This means 0 ≤ r ≤ sqrt(2) and 0 ≤ θ ≤ 2π.
Next, we find the Jacobian for the polar coordinates, which is |J(r,θ)| = r.
Now, we need to compute the magnitude of the gradient of z = xy in terms of polar coordinates. The gradient of z is given by the partial derivatives:
∂z/∂x = y and ∂z/∂y = x
In polar coordinates, x = r*cos(θ) and y = r*sin(θ). So, we have:
∂z/∂r = cos(θ)*∂z/∂x + sin(θ)*∂z/∂y = r*cos^2(θ) + r*sin^2(θ) = r
Now, we use the double integral to find the surface area:
Area = ∬ sqrt(1 + (∂z/∂r)^2) * |J(r,θ)| dr dθ
Area = ∬ sqrt(1 + r^2) * r dr dθ, with limits 0 ≤ r ≤ sqrt(2) and 0 ≤ θ ≤ 2π.
Evaluate the integral to get the area of the surface.
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A manufacturer of cable wire periodically selects samples to monitor the process. A sample of ten wires is selected and the diameters (in cm.) are 0.493, 0.534, 0.527, 0.511, 0.565, 0.559, 0.519, 0.562, 0.551, and 0.530. The standard deviation is a. 0.099 cm. b. 0.045 cm. c. 0.024 cm d. 0.005 cm. e. 0.455 cm.
The standard deviation for the given data is c. 0.024 cm.
Let's calculate the standard deviation using the given data:
Diameters: 0.493, 0.534, 0.527, 0.511, 0.565, 0.559, 0.519, 0.562, 0.551, and 0.530.
Find the mean:
Mean = (0.493 + 0.534 + 0.527 + 0.511 + 0.565 + 0.559 + 0.519 + 0.562 + 0.551 + 0.530) / 10
Mean ≈ 0.5411 cm
Calculate the squared differences:
\((0.493 - 0.5411)^2, (0.534 - 0.5411)^2, (0.527 - 0.5411)^2, (0.511 - 0.5411)^2, (0.565 - 0.5411)^2, (0.559 - 0.5411)^2, (0.519 - 0.5411)^2, (0.562 - 0.5411)^2, (0.551 - 0.5411)^2, (0.530 - 0.5411)^2\)
Find the average of the squared differences:
Average = (sum of squared differences) / 10
Take the square root of the average to get the standard deviation.
By calculating the above steps, the standard deviation of the given data set is approximately 0.024 cm.
Therefore, the correct answer is c. 0.024 cm.
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the population of all standardized exam scores has a mean of 500 and a standard deviation of 100. twenty-five students in a professor's class take the exam, and their average score is 525. what is the z statistic that is associated with the class's average?
The z statistic that is associated with the class's average is 1.25.
In the given question the population of all standardized ex scores has a mean of 500 and a standard deviation of 100 . Twenty-five students in a professor's class take the ex , and their average score is 525.
We have to find z statistic that is associated with the class's average.
n = 25
μ = 500
σ = 100
\(\bar X\) = 525
Then ,
z statistic = \(\frac{\bar{X} - \mu}{\frac{\sigma}{\sqrt n} }\)
putting the value in the formula:
z statistic = (525-500)/(100/\sqrt 25)
z statistic = (25)/(100/5)
z statistic = (25)/(20)
z statistic = 1.25
Therefore,
The z statistic that is associated with the class's average is 1.25.
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PLS HELP! I WILL MAKE U BRAINLIST! LATE WORK
Step-by-step explanation:
to graph a line always find 2 points out has to go through. that means the points' coordinates make the equation true.
I usually start with x = 0.
point 1 of equation 1 is then
y = -2×0 + 6 = 6
(0, 6)
point 1 of equation 2 is then
y = (3/2)×0 - 1 = -1
(0, -1)
then I pick a value for x that makes the handling of any fractions easier. like in our case x = 2.
point 2 of equation 1 is then
y = -2×2 + 6 = -4 + 6 = 2
(2, 2)
point 2 of equation 2 is then
y = (3/2)×2 - 1 = 3 - 1 = 2
(2, 2)
oh, so I have found the intersection point right away (point 2 of both equations).
so, let's pick a different point 2 for equation 1, like x = 4
y = -2×4 + 6 = -8 + 6 = -2
(4, -2)
with these 4 points you define the 2 lines, and you have the intersection point at (2, 2).
Find the sum of the following series. Round to the nearest hundredth if
necessary
5 + 10 + 20 + ... + 163840
Sum of a finite geometric series:
ai
Sn
di — airon
1 - 1
Answer:
327675
Step-by-step explanation:
the formula of the series is:
16
∑5*2^(n-1)
n=1
the formula for the sum of a geometric series is:
Sn=a(1-r^n)/(1-r)
plug in the values from above
n=16 a=5 and r=2 (values from the geometric function) so
Sn=5(1-2^16)/(1-2)
Sn=327675
an economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in california. he believes that the mean income is $21.2, and the standard deviation is known to be $9.3. how large of a sample would be required in order to estimate the mean per capita income at the 95% level of confidence with an error of at most $0.68? round your answer up to the next integer.
By taking the help of the standard deviation, the answer obtained is
n = 719
What is Standard Deviation?
At first it is important to know about Variance.
Variance is the sum of the square of deviation from the mean of the data.
On taking the square root of variance, Standard deviation is obtained.
The formula used for calculating the number of samples required is
\(n=\frac{Z^{2}_{\alpha /2}\times \sigma ^{2}}{e^{2}}\), \(\sigma\) is the standard deviation , e is the error,
Here,
\(\alpha\) = 1 - \(\frac{95}{100}\)
= 1 - 0.95
= 0.05
Critical values of Z = \(\pm\)1.96 [ From the table]
Standard deviation (\(\sigma\)) = 9.3
error (e) = $0.68
On putting the value,
n = \(\frac{1.96^2 \times 9.3^2}{0.68^2}\)
n = 718.5
n = 719
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An automatic machine in a manufacturing process is operating groperly if the iengths of an important subcomponent are normally distributed with a mean of izal cri and a otandard deviation of 5.6 cm. A. Find the probability that one selected subcomponent is longer than 122 cm, Probability = B3. Find the probability that if 3 subcomponents are randomly selected, their mean length exceeds 122 cm. Probability win C. Find the probabilify that if 3 are randomly selected, ail 3 have lengths that exceed 122 cm. Probability =
A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.
z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)
Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.
B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.
The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.
Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm
Now we can calculate the z-score for a mean length of 122 cm:
z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)
Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.
C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.
Probability = (0.9999)^3 ≈ 0.9997
Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.
Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.
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Monte todo página 108 quiero las respuestas porfa
Answer:
no abla espanol
Step-by-step explanation:
A square has an area of 49 cm squared what is the length of each side
Answer:
7
Step-by-step explanation:
\(s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7\)
10
Select the correct answer
Mike launches a stone using a catapult from a height of 160 feet. The stone reaches its maximum height of 250 feet after 3 seconds, and it hits the ground after 8 seconds.
Which of the following graphs represents the trajectory of the stone?
Answer: W
Step-by-step explanation:
i took the test
if m = 2 and n = 5 then find the value of 6m+5n
Answer:
37
Step-by-step explanation:
6m+5n
plug in your given values
6(2) + 5(5)
12+25
=37
Answer:
37
Step-by-step explanation:
6m + 5n
6*2 + 5*5 = 12 + 25
= 37
Write an equation of a line in slope-intercept form with the given slope and y-intercept.
slope: 8, y-intercept: -3
usain bolt ran the 2012 olympic 100-meter race in 9.63 seconds. if he runs at this rate on a road wait a speed limit of 25 miles per hour, how will his speed compare to the speed limit? justify your answer.(25 mi/hr=40,234 meter/hr)
Answer:
Usain Bolt runs about 37,383 meters an hour so he will not exceed the speed limit but will run at about 23 miles per hour.
Step-by-step explanation:
Usain Bolt runs about 37,383 meters an hour so he will not exceed the speed limit but will run at about 23 miles per hour. We get this from 3600 seconds in an hour, 3600÷9.63×100≈37383 meters an hour. 1609.344 meters in a mile. 37383÷1609.344≈23 mph
Answer:Sample Response: The speed limit is about 11.2 meters per second. Usain is running 10.38 meters per second. So he is running slower than the speed limit.
Step-by-step explanation:Need brainliest award
The altitude of a right circular cylinder is twice the radius of the base. Find the height. If the volume is 300 m^3
a. 12
b.18
c. 8
if the surface area is 400 m^2
a. 12
b. 18
c. 8
if the lateral area is 350 m2
a. 11
b. 17
c. 18
The height of the cylinder given the volume of 300 m³ is approximately 8.788 m. Therefore, the answer is c. 8.
The height of the cylinder given the surface area of 400 m² is approximately 15.954 m. Therefore, the answer is b. 18.
The height of the cylinder given the lateral area of 350 m² is approximately 12.536 m.
Let's solve each problem step by step.
Finding the height given the volume:
The formula for the volume of a right circular cylinder is V = πr²h, where V is the volume, r is the radius of the base, and h is the height.
We are given that the volume is 300 m³. We also know that the height is twice the radius, which means h = 2r.
Substituting the value of h in terms of r into the volume formula, we get:
300 = πr²(2r)
300 = 2πr³
r³ = 150/π
r = (150/π)^(1/3)
To find the height, we substitute the value of r back into h = 2r:
h = 2((150/π)^(1/3))
Now, let's calculate the approximate value for h:
h ≈ 2(4.394) ≈ 8.788
So, the height of the cylinder is approximately 8.788 m.
Finding the height given the surface area:
The formula for the surface area of a right circular cylinder is A = 2πrh + 2πr², where A is the surface area, r is the radius of the base, and h is the height.
We are given that the surface area is 400 m². We also know that the height is twice the radius, which means h = 2r.
Substituting the value of h in terms of r into the surface area formula, we get:
400 = 2πr(2r) + 2πr²
400 = 4πr² + 2πr²
400 = 6πr²
r² = 400/(6π)
r = √(400/(6π))
To find the height, we substitute the value of r back into h = 2r:
h = 2√(400/(6π))
Now, let's calculate the approximate value for h:
h ≈ 2(7.977) ≈ 15.954
So, the height of the cylinder is approximately 15.954 m.
Finding the height given the lateral area:
The lateral area of a right circular cylinder is given by A = 2πrh, where A is the lateral area, r is the radius of the base, and h is the height.
We are given that the lateral area is 350 m². We also know that the height is twice the radius, which means h = 2r.
Substituting the value of h in terms of r into the lateral area formula, we get:
350 = 2πr(2r)
350 = 4πr²
r² = 350/(4π)
r = √(350/(4π))
To find the height, we substitute the value of r back into h = 2r:
h = 2√(350/(4π))
Now, let's calculate the approximate value for h:
h ≈ 2(6.268) ≈ 12.536
So, the height of the cylinder is approximately 12.536 m.
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Define the nonprobability sampling methods and give examples of each.
Sampling is the use of a subset of the population to represent the whole population or to inform about processes that are meaningful beyond the particular cases, individuals or sites studied.
In non-probability sampling, the sample is selected based on non-random criteria, and not every member of the population has a chance of being included. Common non-probability sampling methods include convenience sampling, voluntary response sampling, purposive sampling, snowball sampling, and quota sampling.
can you explain how to get the length of either leg of the triangle?
The area of the parallelogram is 281.91 m²
How to find the area of a parallelogram?A parallelogram is a quadrilateral with opposite sides equal to each other and opposite sides parallel to each other.
Therefore, the area of the parallelogram can be found as follows:
area of the parallelogram = bh
where
b = base of the parallelogramh = height of the parallelogramTherefore, let's find the height of the parallelogram using trigonometric ratios,
sin 70° = opposite / hypotenuse
sin 70° = h / 15
h = 15 sin 70°
h = 15 × 0.9396
h = 14.0953893118
h = 14.1 metres
Therefore,
area of the parallelogram = 14.1 × 20
area of the parallelogram = 281.907786236
area of the parallelogram = 281.91 m²
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I have a photo up could someone answer two?
Rewrite 5 square root 3^4 as an expression with a rational exponent. Then mark this number on the graph of f (x) = 3^x. Explain how you know where to place it.
Step-by-step explanation:
the nth root of something can be expressed as 1/n as exponent.
e.g. sqrt(2) = 2^(1/2).
so, the 5th root of 3⁴ = 3^(4/5)
for f(x) = 3^x
that means that x = 4/5 = 0.8.
so, I go on the x-axis to the right to 0.8, and from there straight up to the actual curve.
that is the desired point.
Eight families live on abbie's street. she asks each family how many pets they have. abbie's data set is: 0, 0, 1, 1, 2, 2, 2, 5. the modal number of family pets on abbie's street is:__________
Answer:
Step-by-step explanation:
It is asking for the "mode" which is the data element you see the most, therefore it is 2.