Different shapes are drawn on cards and then the cards are placed in a bag. The number of cards for each shape is shown in the table.
Shape octagon square circle
Number of cards 12 27 91
What is the probability that a randomly selected card has a circle drawn on it?

The estimated answer for the mathematical expression is 2.

An estimate is a rough amount that is representative of the original figure. In math, we can estimate decimals to the nearest tenths, hundredths, thousandths, and so forth.

For the expression above we have to estimate the different values. 2.06 can be estimated as 2 while 0.6 can be estimated as 1. When we multiply this, we get 2, a round figure. If we decide to Figures greater than 5 are usually rounded up to 1. So, estimates do not give the exact figure, rather they give an idea of the range.

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The equation of the line passing through A and B is y = (4/5)x - (2/5).

A straight line's general equation is y = mx + c, where m is the gradient and y = c is the value at which the line intersects the y-axis. The y-axis intercept is denoted by the number c. A straight line with gradient m and intercept c on the y-axis has the equation y = mx + c.

The point-slope form of a linear equation can be used to find the equation of the line passing through points A and B:

y - y1 = m(x - x1) (x - x1)

where m denotes the slope of the line, (x1, y1) denotes the coordinates of point A or B, and (x, y) denotes the coordinates of any other point on the line.

To calculate the slope, we can use points A (3, 2) and B (8, 6).

m = (y2 - y1) / (x2 - x1) = (6 - 2) / (8 - 3)\s= 4 / 5

So the equation for the line connecting A and B is:

y - 2 = (4/5)(x - 3) (x - 3)

This equation can be simplified by multiplying both sides by 5:

5y - 10 = 4x - 12

Then we can rearrange it to form the slope-intercept equation, y = mx + b:

5y = 4x - 2

y = (4/5)x - (2/5)

As a result, the equation for the line connecting A and B is y = (4/5)x - (2/5).

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Answer:

400

Step-by-step explanation:

Answer:

Step-by-step explanation:

Percent means per one hundred so

p/100=5/8

p=500/8

p=62.5%

So 62.5% have paid their yearly fees.

400(5/8)=250

250 members have paid their fees.

The quotient of - 3.32 / - 2.2 is 8 ÷5.

Given fraction:

-3.32 / -2.2

First step is to re-write the given fraction which is - 3.52 / - 2.2

3.52 / 2.2

Second step is to convert the decimal to fraction

352 ÷ 100 / 22 ÷10

Third step is to reduce the fraction

reducing 352/100

=(2^5 × 11)/(2^2 × 5^2)

= [(2^5 × 11) ÷ 2^2] / [(2^2 × 5^2) ÷ 2^2]

= (2^3 × 11)/5²

= 88/25

Reducing 22/10

Divide the numerator and denominator by the greatest common divisor

= 22 ÷ 2 / 10 ÷ 2

= 11 /5

Now let determine  or find the quotient

88 ÷ 25 × 11 ÷ 5

= 8 ÷ 5

Therefore we can conclude that 8 ÷ 5 is the quotient.

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Answer:

The rates are not equivalent since Maria saves $0.50 more per month than Ralph.

Step-by-step explanation:

We can determine if two rates are equivalent by comparing the rates at which they save per month.

Maria's savings per month:

Both 50 and 4 can be divided by 2, which gives us 25/2.  As a regular number, this becomes 12.5/1 which means Maria saves $12.5 per month.

Ralph's savings per month:

Both 60 and 5 can be divided by 5, which gives us 12.  Thus, Ralph saves $12 per month.

Thus, the rates are not equivalent as Maria saves $0.50 more per month than Ralph.

Answer:

ayah

Step-by-step explanation:

Car A is 2 times Faster than Car B during the first hour.

The graph of Car A is a straight line, indicating that it is traveling at a constant speed.

The graph shows that Car A is traveling 100 miles in 2 hour .The table of Car B shows that it travels 50 miles in 1 hour, 100 miles in 2 hours, and 150 miles in 3 hours. Thus, the rate of Car B is increasing, as it travels at a faster speed during each hour compared to the previous hour.To find the rate of each car, we need to divide the distance by the time. For Car A, rate = distance ÷ time = 100 miles ÷ 2 hours = 50 miles per hour.

For Car B, we can find the average rate for each hour by dividing the distance traveled during that hour by the time. Thus, the rates are: First hour: 50 miles per hour Second hour: 50 miles ÷ 1 hour = 50 miles per hour Third hour: 50 miles ÷ 1 hour = 50 miles per hour By comparing the rates, we see that both cars are traveling at the same speed during the second and third hours. However, during the first hour, Car A is traveling faster than Car B.

Thus, Car A has the greatest speed.To determine how many times faster Car A is compared to Car B during the first hour, we can divide their rates. The rate of Car A is 50 miles per hour, while the rate of Car B is 50 miles per hour. Therefore, Car A is traveling at the same speed as Car B during the second and third hours. During the first hour, Car A is traveling twice as fast as Car B. Thus, Car A is 2 times faster than Car B during the first hour.

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Answer:

It would be a lot of bavgeria

Answer:

450000

Step-by-step explanation:

125×(60×60)

=125×3600

=450000

Answer:

y, -2,3

w, 3,2

L, 0

k,-2/1 or just (-2)

m=0

Step-by-step explanation:

not sure but love the pfp

Step-by-step explanation:

7x - 3 = 6x + 17

7x - 6x = 17 + 3

x = 20

Solution → x = 20°

Answer:

A)  A coordinate grid is shown from negative 10 to positive 10 on the x axis and also on the y axis. Two lines are shown intersecting on the ordered pair (3, 8)

Step-by-step explanation:

Given equations:

\(\textsf{Equation 1}: \quad y=-2x+14\)

\(\textsf{Equation 2}: \quad y=2x+2\)

Substitute Equation 2 into Equation 1 and solve for \(x\):

\(\implies 2x+2=-2x+14\)

\(\implies 4x=12\)

\(\implies x=3\)

Substitute found value of \(x\) into Equation 2 and solve for \(y\):

\(\implies y=2(3)+2=8\)

Therefore, the solution to the system is (3, 8).  

This is the point of intersection of the two lines.

The proof for the statement given in question is as follows,

By analogy, if V is the set-theoretic union of n proper subspaces Wi (1in), then |F|n1.

Proof:

We can assume that the union of the other subspaces contains no Wi

Then (v + Fu)Wi= and (v + Fu) Wj (ji) ,

can only contain one vector because else Wj would contain u.

Hence

| v + Fu |=|F|≤n−1.

Corollary: Avoidance lemma for vector spaces.

Assume E is a vector space spanning an infinite field. If a subspace is contained in a finite union of subspaces, it is contained in one of them.

It should be noted that there is a similar Avoidance lemma for prime ideals in commutative rings.

A vector space (also known as a linear space) is a set whose members, known as vectors, can be added together and multiplied ("scaled") by integers known as scalars. Scalars are frequently real numbers, but they can also be complex numbers or, more broadly, members of any field.

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Step-by-step explanation:

well, you have to make sure that the answer you enter is right.

so, pay attention and follow the lead here, so that you then can decide, if it is right or needs some adaptation.

every probability is always the ratio of desired cases to totally possible cases.

in our case here we have 10 balls in the back, one is pulled randomly.

so, there are 10 possible outcome cases.

(a)

the desired event X is to pull a white ball.

well, how many of the 10 possible balls are white ? this is the desired outcome.

3, 4, 5, 7, 8, 9, 10 : 7 balls are white.

so, in the line X you have to mark these 7 balls.

and the probability is : 7/10

"not X" : since we have only 2 types of balls, "not white" means "grey".

how many of the 10 possible balls are grey ?

1, 2, 6 : 3 balls are grey (not white).

so, in the line "not X" you have to mark these 3 balls.

and the probability is : 3/10

(b)

"1" always stands for the totally sure, always true event.

P(X) means the probability to get the event X as outcome.

again, in our case, X means pulling a white ball.

1 - P(X)

from (a) we know the probability to pull a white ball : 7/10.

so,

1 - P(X) = 1 - 7/10 = 10/10 - 7/10 = 3/10

and that stands for "probability for NOT pulling a white ball" in the sense of the "opposite of the probability to pull a white ball".

(c)

I don't know what options you can select, but it has to be something like

1 - P(X) is the same as P(not X).

simply because both mean the same :

the probabilty of the opposite of pulling a white ball is the probability of not pulling a white ball.

Answer:

cost when 400 miles is driven is $143.

Step-by-step explanation:

Model for cost calculation: C=0.32m + 15

We have to find cost when no. of miles driven is 400.

To find that cost we need to plug 400 in place of m.

C=0.32m + 15

=> c = 0.32*400 + 15

=> c = 128 + 15 = 143

Thus, cost when 400 miles is driven is $143.

Answer:

The C-intercept, 15, means that if Janelle drove 0 miles on a particular day it would cost her 15 dollars to rent the car for that day.

I'm not sure of what your trying to find... but the slope is (10/3). The equation in  slope form is y=(10/3)x-10. The Standard form is 10x-3y=30.

Does this help?

Answer: The equation of that line is \(Y = 3 \frac{1}{3}x -10\)

Step-by-step explanation:

The expression in the form (x +a)² + b is shown below.

We have to expression given expression in the form (x +a)² + b.

1. x² + 12x

x² + 12x + 36 - 36

= (x +6)² - 36

2. x² + 3x - 2

x² + 2 . 3x /2 - 9/4 + 9/4 -2

(x+ 3/2)² - 17/4

3. x²+ 1/2 x

x² + 2 . 1/4 x + (1/2)² - (1/2)²

= (x+ 1/2)² - 1/4

4. x² - 2/9 x

=  x² + 2 . 2/20 x + 4/400 - 4/400

= (x+ 2/200)² - 1/100

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This question is Incomplete

Complete Question

Recall the hurricane relief fund context from the previous investigation. Bob set up a hurricane relief donation fund and started it off by donating $ 35 . Instead of tripling in value each day, suppose it doubled in value each day

Complete the following table showing the account values at the end of each day.

Number of days since the initial investment, n Amount (in dollars) in the relief account, A

0 1 2 3 4

Answer:

Number of days(n) = Amount (in dollars) in the relief account(A)

0 = $35

1 = $70

2 = $140

3 = $280

4 = $560

Step-by-step explanation:

The formula for doubling time

P(t) = Po(2)^t/k

Where P = Amount after time t

Po = Initial Amount

t = number of days

k = Frequency at which it doubles

For 0 days

t = 0, k = 1, P(o) = $35

P(t) = Po(2)^t/k

P(0) = $35(2)^0/1

= $35(2)⁰

= $35 × 1

= $35

For 1 day

t = 1, k = 1 , P(0) = $35

P(t) = Po(2)^t/k

P(0) = $35(2)^1/1

= $35(2)¹

= $35 × 2

= $70

For 2 days

P(t) = Po(2)^t/k

t = 2, k = 1, P(0) = $35

P(0) = $35(2)^2/1

= $35(2)²

= $35 × 4

= $140

For 3 days

P(t) = Po(2)^t/k

t = 3, k = 1

P(0) = $35(2)^3/1

= $35(2)³

= $35 × 8

= $280

For 4 days

P(t) = Po(2)^t/k

t = 3, k = 1, P(0) = $35

P(0) = $35(2)^5/1

= $35(2)⁴

= $35 × 16

= $560

Answer:

60+1b

Step-by-step explanation:

Multiply the numbers without variables:

3x4=12

12x5=60

Next put the equations together:

60+1b

Hence, the correct answer is 60+1b

Answer:

60+1b

Step-by-step explanation:

3x4=12

12x5=60

So, your final equation is 60+1b

Answer:

143 should be correct

Step-by-step explanation:

hope this helps

Step-by-step explanation:

the area of a parallelogram is

baseline × height = 5 × 3.2 = 16 m²

Sphenathi and the other matriculants must travel at an average speed of approximately 107 km/h to reach Uptington by 09:45.

To determine the average speed at which Sphenathi and the other matriculants must travel to reach Uptington by 09:45, we need to calculate the time available for the journey and the distance between the two locations.

The time available is from 07:25 to 09:45, which is a total of 2 hours and 20 minutes. We need to convert this time to hours by dividing by 60:

2 hours + 20 minutes / 60 = 2.33 hours

Now, let's calculate the distance between Bloemfontein and Uptington. Suppose the distance is 'd' kilometers.

We can use the formula for average speed: average speed = distance / time

In this case, the average speed should be such that the distance divided by the time is equal to the average speed.

d / 2.33 = average speed

Now, let's assume that Sphenathi and the other matriculants must travel a distance of 250 kilometers to reach Uptington. We'll substitute this value into the equation:

250 / 2.33 = average speed

To find the average speed to the nearest km/h, we'll calculate the result:

average speed ≈ 107.3 km/h

Therefore, Sphenathi and the other matriculants must travel at an average speed of approximately 107 km/h to reach Uptington by 09:45.

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Answer:

The median for the first plot is 3

The median for the second plot is 7

The largest value for the first plot is 6

So the difference for the first plot is 6 - 3 = 3

The largest value for the second plot is 10

So the difference for the second plot is 10 - 7 = 3

This means the variation quadrial  is bigger for the red plot, but the difference beetween the points is equal.

Answer:

not 75 points

Step-by-step explanation:

Answer:

1. 4

2. 20

3. 80

Step-by-step explanation:

To start, we need write the polynomials:

Now we gonna find the difference between first polynomial and second, like this:

tip: Special care with operate signs.

That is the final solution, you can solve that polynomial if you need.

Answer:

12 boys

Step-by-step explanation:

i took the 7 that represents the girls and multiplied by 3 to get 21 (how many girls are there)

So then i took 4 multiplied 3 and thats how i got the answer 12 (brainllist Plz!)

On solving the providewd question we can say that, public static double solve(double a, double b, double c, boolean flag )

A quadratic equation is a quadratic polynomial in one variable that looks like this: x = ax2 + bx + c. a 0. This polynomial has at least one solution since it is a second-order polynomial, according to the Fundamental Theorem of Algebra. The answer can actually work or be difficult.

public static double solve(double a, double b, double c, boolean flag)

{     double d = Math.sqrt(b*b - 4*a*c);     if(flag)

{         return (-b + d) / (2*a);     }

else {         return (-b - d) / (2*a);     } }

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The Binomial probability of x = 3 for the given parameters is 0.2048

The Binomial probability relation can expressed as :

\(P(x) = nCx * p^{n} * q^{n-x}\)

where :

for x = 3

We substitute x into the equation thus :

P(x = 3) = 17C3 * (1/8)³ * (1 - 1/8)¹⁴

P(x = 3) = 0.2048

Therefore, the probability of x = 3 in the scenario given is 0.2048

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Answer:

it may be 3

Step-by-step explanation:

it may be bcz am not much good but still just trying

Answer:

0.48

Step-by-step explanation:

By the law of sines, the ratio of the sides of a triangle to the sine of the angles opposite the side must be the same

Therefore
\(\dfrac{EG}{\sin90} =\dfrac{ FG}{\sin E}\\\\\\\dfrac{\sqrt{69}}{\sin 90} = \dfrac{4}{\sin E}}\\\\\\\sin 90 = 1\\\\\dfrac{\sqrt{69}}{1} = \dfrac{4}{\sin E}\\\\\sqrt{69} = \dfrac{4}{\sin E}\\\\\sin E = \dfrac{4}{\sqrt{69}}\\\\\\= 0.481543\\\\= 0.48 \text{ rounded to the nearest hundredth}\)