In order to prepare amide bonds, dicyclohexylcarbodiimide (DCC) was first used as a coupling reagent by Sheehan and Hess in 1955.
Since then, DCC has been employed for peptide synthesis. An O-acylisourea active intermediate plays a role in the creation and propagation of an amide or peptide bond in this process. It would be difficult to overestimate the significance of the typical carboxylic acid reaction with dicyclohexylcarbodiimide (DCC) and amines to produce amides in the synthesis of peptides, especially in the solid phase (Scheme 1). Dicyclohexylcarbodiimide, sometimes known as DCC, is a dehydrating agent typically employed in the laboratory to manufacture proteins. It removes a water molecule from the amino acids involved in the creation of the peptide bond and forms a suitable leaving group.
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Which statement best explains how weather is related to the water
cycle?
Answer:
Increased evaporationof water vapour from sea or land will increase rainfall
Answer:
Explanation:
increased evaporation of water vapor from sea to land will increase rainfall
is Isoheptenes hazardous when wet
Answer:
yes it is dangerous
Explanation:
Water reactive substances are dangerous when wet because they undergo a chemical reaction with water.
Heart, 5 stars, and Brainiest to first right answer!
Which two types of air masses would likely form a subtropical jet stream?
Warm and cool air masses meeting near the North Pole
Cool and warm air masses meeting near the equator
Multiple warm air masses meeting near the equator
Two or more cool air masses meeting near the South Pole
Answer:
Give person above me brainliest
Explanation:
Select the correct answer.
Which state of matter is highly compressible, is made of particles moving independently of each other, and is present in large quantities near Earth’s surface?
A.
solid
B.
liquid
C.
gas
D.
plasma
Answer:
C. Gas
Explanation:
Unit 4.2 quiz chemistry
Answer:
H₂SO₄ is the correct answer sorry im late
What is the molarity of a solution that contains 4.53 moles of lithium nitrate (LiNO3) in 2.85 liters of solution
Answer:
M= ml - 45301 - 11.59M.
Explanation:
explain order of reaction and use the data below and the rate equation to show how it is calculated.
Using the data above determine
(a) order with respect to (A)
(b) order with respect to (B)
(c) rate equation
(d) overall order
The rate equation is Rate = k[A]²[B]³, and the reaction has an overall order of 5.
If the rate equation is correct, what is the reaction's order?A rate law illustrates how a chemical reaction's rate is influenced by the reactant's concentration. The rate law typically has the formula rate = k[A]n for reactions like aA products, where k is the proportionality constant also known as the rate constant. and The reaction's sequence in relation to A is indicated by n.
Rate = k[A]x[B]y
Rate = k[A]²[B]³
Overall order = 2 + 3 = 5
Therefore, the overall order of the reaction is 5, and the rate equation is Rate = k[A]²[B]³.
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What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?
we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.
To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.
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Copper metal has a face-centered cubic structure with all atoms at lattice points and a density of 8.93 g/cm^3. The edge length of the unit cell is 361.5 pm. Calculate the mass of 1 atom of copper.
The mass of 1 atom of copper metal in the given face-centered cubic structure is determined as 1.054 x 10⁻²² g.
Mass of 1 atom of copperThe mass of 1 atom of copper is calculated as follows;
mass of 1 atom of copper = molar mass of copper / Avogadro's number
substitute the value of molar mass of copper and Avogadro's number;
mass of 1 atom of copper = (63.5 g/mol) / (6.023 x 10²³)
mass of 1 atom of copper = 1.054 x 10⁻²² g
Thus, the mass of 1 atom of copper is determined as 1.054 x 10⁻²² g.
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35.0 ml. of a 0.250 M solution of /OH is titrated with 0.150 M HCI. After 35.0 mL of the HCl has been added, the resultant
Determine the amount of KOH present in the resulting solution. KOH was initially 0.00875 mol, then 0.00525 mol of it interacted with HCl. As a result, 0.00875 mole - 0.00525 mol (= 0.00350 mol of KOH is left. The resulting solution has a volume of 70.0 mL (35.0 mL plus 35.0 mL).
Is HCl directly titrated with NaOH?The titrant (NaOH), which is added gradually throughout the course of a titration, is added to the unknown substance. The equivalency point is the moment at which precisely the right quantity of titrant (NaOH) has indeed been added that react to the entire analyte (HCl).
What happens when you titrate NaOH to HCl?What took place during titration: One mole of NaOH interacts with one mole of HCl inside the reaction between the two substances. NaOH with HCl equals NaCl plus H2O. (NaOH and HCl have a mole ratio of 1:1.) • The NaOH concentration is 0.1 M, or 0.1 molecules per litre.
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What is the relationship between mass and gravity
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
Can you give me brainliest
Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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ygyugygygggygygg..................................................................................................................................................
please try to keep questions acedemic related
it does no good for questions like this to be on here when others need help, try to keep your questions..
- Partained to the particular subject
- presented in the correct language and maner
- understandable and with all the information needed
no hard feelings, though this question and answer will be deleted by moderators soon so just keep all that in mind ^^
The following are products in the chemical reaction shown below.
Answer:
C₆H₁₂O₆ and O₂
Explanation:
To know which option is correct, it important that we know the concepts of chemical equation .
A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.
The reactant is located on the left side and the product is located on the right side.
Reactant —> Product
With the above information, let us answer the question given above.
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
The products are located on the right side of the equation.
Thus, the products of the reaction is C₆H₁₂O₆ and O₂
As the diagram model the processo se reproduction lomon) formand change formation Sexual reproduction results in a child that is different from its parents because
A. the child receives all of is genetic information from its mother
B. the child produces its own genetic information once it is formed
C. the child receives half of is genetic information from each parent
D. the child receives all of it's genetic information from it's father there
Answer:
The answer is C. the child receives half of is genetic information from each parent
Explanation:
hope this helps enjoy
Magnesium hydroxide reacts with chlorine to form magnesium chloride,
magnesium chlorate and water. How many grams of magnesium hydroxide is
needed to yield 8.00 moles of magnesium chlorate?
77.8 g Mg(OH)2
9178.1 g Mg(OH)2
2799.6 g Mg(OH)2
.823 g Mg(OH)2
How many grams of sodium sulfato pro
The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.
To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.
The balanced equation is as follows:
2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O
From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.
Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.
To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.
Given:
Moles of Mg(ClO3)2 = 8.00 moles
Using the stoichiometric ratio, we have:
8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2
To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.
The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol
Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g
Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.
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Read the chemical equation.
N2 + 3H2 - 2NH3
Using the volume ratio, determine how many liters of NH3 is produced if 4.2 liters of H2 reacts with an excess of N2
if all measurements are taken at the same temperature and pressure?
A 2.8 liters
B 3.2 liters
C 5.4 liters
D 6.3 liters
Answer:
A 2.8 liters
Explanation:
Step 1: Write the balanced equation
N₂ + 3 H₂ ⇄ 2 NH₃
Step 2: Establish the appropriate volume ratio
At the same temperature and pressure, the volume ratio of H₂ to NH₃ is 3:2.
Step 3: Calculate the volume of ammonia produced from 4.2 L of hydrogen
4.2 L H₂ × 2 L NH₃/3 L H₂ = 2.8 L
which of the following cannot be a chemical symbol of an element
Cf cannot be a chemical symbol of an element. Therefore, option B is correct.
What is an element ?The term an element is defined as a substance that cannot be broken down into a simpler format. They are separate by a unequaled atomic number. The elements are formed by their atomic number in the periodic table, which highlights elements with similar properties.
Cf cannot be a chemical symbol of an element. CO is the symbol of element cobalt. B is the symbol of element boron and Cu is the symbol of an element copper.
Thus, option B is correct.
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Your question is incomplete, most probably your answer was
Which of the following cannot be the chemical symbol for an element
a. co
b. cf
c. b
d. cu
Balance the equations by putting the necessary coefficients in the blanks. Normally we do not write 1s when balancing, but for this particular question you need to include them for full credit. __Na3N___ Na +__ N2 ___H3PO4 + __ KOH __K3PO4 + __ H2O __ N2 +__ H2 __ NH3 __H2O2 __ O2 + __ H2O __ Zn + __ HCl __ ZnCl2 + __H2 __ C2H6 + __ O2 __ CO2 + __H2O __ CuCl2 + __H2S __ CuS + __HCl
Balancing a chemical equation is the process of ensuring that the number of atoms of each element in the reactants is equal to the number of atoms of that same element in the products.
Balance the chemical eqations given in the problem?
Na3N → 3 Na + ½ N2H3PO4 + 3 KOH → K3PO4 + 3 H2ON2 + 3 H2 → 2 NH3H2O2 → O2 + 2 H2OZn + 2 HCl → ZnCl2 + H2C2H6 + 7/2 O2 → 2 CO2 + 3 H2OCuCl2 + H2S → CuS + 2 HClChemical equations are used to describe the reactants and products in a chemical reaction. These equations are written using chemical formulas and symbols, indicating the types and numbers of atoms or molecules involved in the reaction. However, these equations must be balanced to obey the law of conservation of mass, which states that the total mass of the reactants must equal the total mass.
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base and? The carbonate buffer is responsible for the pH regulation of the extracellular environment. A carbonic acid-hydrogencarbonate is prepared in a ratio 1.25:1. The Ka is 4.5 x 10^-7 what is the concentration of t hydrogen carbonate ion if the physiological pH = 7.35 what is the concentration of H₂CO₂ lon
The concentration of the hydrogen carbonate ion ([HCO₃⁻]) is approximately 3.15 x 10⁷ and the concentration of the carbonic acid ([H₂CO₃]) is approximately 2.52 x 10⁷.
The carbonate buffer system plays a crucial role in maintaining the pH balance of the extracellular environment. In this system, carbonic acid (H₂CO₃) and hydrogen carbonate (HCO₃⁻) act as a conjugate acid-base pair. Given that the ratio of carbonic acid to hydrogen carbonate is 1.25:1, we can assume that the initial concentration of carbonic acid is higher. Let's denote the initial concentration of carbonic acid as [H₂CO₃] and the concentration of hydrogen carbonate as [HCO₃⁻]. The dissociation of carbonic acid can be represented by the equation: H₂CO₃ ⇌ H⁺ + HCO₃⁻. The equilibrium constant (Ka) for this reaction is given as 4.5 x 10⁻⁷. At physiological pH (7.35), the concentration of H⁺ is determined by the dissociation of carbonic acid and is tightly regulated. To calculate the concentration of hydrogen carbonate ion ([HCO₃⁻]), we need to make use of the Henderson-Hasselbalch equation:
pH = pKa + log([HCO₃⁻]/[H₂CO₃])
Substituting the given values, we have:
7.35 = -log(4.5 x 10⁻⁷) + log([HCO₃⁻]/[H₂CO₃])
Rearranging the equation, we find:
log([HCO₃⁻]/[H₂CO₃]) = 7.35 + log(4.5 x 10⁻⁷)
Taking antilog of both sides, we get:
[HCO₃⁻]/[H₂CO₃] = 10^(7.35 + log(4.5 x 10⁻⁷))
Simplifying the right-hand side, we have:
[HCO₃⁻]/[H₂CO₃] ≈ 3.15 x 10⁷
Since the initial ratio of H₂CO₃ to HCO₃⁻ is 1.25:1, we can set up the equation:
[HCO₃⁻] = 1.25 x [H₂CO₃]
Substituting the value of [HCO₃⁻]/[H₂CO₃] from above, we find:
1.25 x [H₂CO₃] = 3.15 x 10⁷
Solving for [H₂CO₃], we get:
[H₂CO₃] ≈ 2.52 x 10⁷
Therefore, the concentration of the hydrogen carbonate ion ([HCO₃⁻]) is approximately 3.15 x 10⁷ and the concentration of the carbonic acid ([H₂CO₃]) is approximately 2.52 x 10⁷.
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A student conducted three trails to determine the concentration of an unknown concentration of HCI. In the first trail the calculated concentration was 0.104 M, the second was 0.113 M and the third trail was 0.108 M. What is the percent difference between the first two trials and based on the lab procedures procedures guidelines what would the average molarity be?
The percent difference between the first two trials is 8.3% and final outcome would be an average molarity of 0.108 M.
How to calculate percent difference and average molarity?To calculate the percent difference between the first two trials, use the formula:
% Difference = |(Value 1 - Value 2) / ((Value 1 + Value 2) / 2)| x 100%
% Difference = |(0.104 M - 0.113 M) / ((0.104 M + 0.113 M) / 2)| x 100%
% Difference = |-0.009 M / 0.1085 M| x 100%
% Difference = 8.3%
The percent difference between the first two trials is 8.3%.
To find the average molarity, add the three calculated concentrations together and divide by the number of trials:
Average Molarity = (0.104 M + 0.113 M + 0.108 M) / 3
Average Molarity = 0.108 M
Based on the lab procedures guidelines, the average molarity would be the most accurate representation of the unknown concentration of HCI. Therefore, the average molarity of 0.108 M would be the final result.
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In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.
Since the number of atoms which are reacting are equal to the number of to the number of atoms in the product, this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.
What is the principle of matter conservation?Any system that is closed to all exchanges of matter and energy is subject to the law of conservation of matter, which is a general law of physics and chemistry. This law states that regardless of how the components rearrange themselves, the mass of an object or group of things remains constant over time.
A chemical reaction is what?A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that solely affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei.
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If 3.90 g of CuNO3 is dissolved in water to make a 0.840 M solution, what is the volume of the solution in milliliters?
Volume:
The volume of the solution is 24.8 milliliters (mL).
To solve this problem, we can use the formula:
Molarity (M) = moles of solute / liters of solution
We are given the mass of CuNO3 and the molarity of the solution, so we can first calculate the number of moles of CuNO3:
moles of CuNO3 = mass / molar mass
molar mass of CuNO3 = 63.55 + 14.01 + 3(16.00) = 187.56 g/mol (using atomic weights from the periodic table)
moles of CuNO3 = 3.90 g / 187.56 g/mol = 0.0208 mol
Next, we can rearrange the formula for molarity to solve for the volume of the solution:
liters of solution = moles of solute / Molarity
liters of solution = 0.0208 mol / 0.840 M = 0.0248 L
Finally, we can convert liters to milliliters:
volume of solution = 0.0248 L x 1000 mL/L = 24.8 mL
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According to statistics from the Centers for Disease Control, the number of deaths by
AIDS has dropped; however, the slowing decline concerns experts. Considering the data
about new AIDS cases provided in the circle graph, what conclusion can be drawn about
the AIDS epidemic in 2000?
A. AIDS medications are powerful and extremely successful.
B. Most people are not concerned about AIDS.
C. All races are equally affected by the AIDS epidemic.
OD. Many people are still misinformed about the severity of AIDS.
E. More children and teenagers are affected by AIDS than adults.
Answer:
E. More people from African American ethnic group is affected by AIDS than other groups.
Explanation:
because it is supported by the data provided in the circle graph. The graph shows that 48% of new AIDS cases in 2000 were in the African American population, while only 31% were in the white population and 20% were in the Hispanic population. This indicates that a disproportionate number of African Americans were affected by the AIDS epidemic in 2000. While option D "Many people are still misinformed about the severity of AIDS" is a possible conclusion, but it is not directly stated or implied by the data provided in the graph.
Reaction Data ReactantsProductsAl(NO3)3NaClNaNO3AlCl3Starting Amount in Reaction4 moles9 moles??Determine the maximum amount of NaNO3 that was produced during the experiment. Explain how you determined this amount. I've had help on this before but im still struggling.
Step 1: Write and balance the equation:
3 NaCl + Al(NO3)3 → AlCl3 + 3 NaNO3
Step 2: We need to find the limiting and excess reactant. For this, we need to look at the stoichiometric ratio between the reactants:
3 moles of NaCl reacts with 1 mole of Al(NO3)3.
Now we do a rule of 3 for both.
For 9 moles of NaCl:
3 moles of NaCl --- 1 mole of Al(NO3)3
9 moles of NaCl --- x mole of Al(NO3)3
3x = 9
x = 3 moles of Al(NO3)3
For 4 moles of Al(NO3)3:
3 moles of NaCl --- 1 mole of Al(NO3)3
x moles of NaCl --- 4 moles of Al(NO3)3
x = 12 moles of NaCl
As we can see, to react with 4 moles of Al(NO3)3 we should have 12 moles of NaCl, but we have just 9. So the NaCl is the limiting reactant and the excess reactant is Al(NO3)3.
Step 3: We need to look at the stoichiometric ratio between the limiting reactant (NaCl) and NaNO3:
3 moles of NaCl --- 3 moles of NaNO3
9 moles of NaCl --- x moles of NaNO3
x = 9 moles of NaNO3
Answer: The maximum amount of NaNO3 that was produced during the experiment is 9 moles.
Identify the substance that has formula mass of 133.5amu.
(a) MgCI
b)SCI
c)BCI
D) AICI
The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.
To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.
(a) MgCl2:
The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).
Mg: atomic mass = 24.31 amu
Cl: atomic mass = 35.45 amu
Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu
(b) SCl:
The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).
S: atomic mass = 32.07 amu
Cl: atomic mass = 35.45 amu
Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu
(c) BCl:
The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).
B: atomic mass = 10.81 amu
Cl: atomic mass = 35.45 amu
Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu
(d) AlCl3:
The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).
Al: atomic mass = 26.98 amu
Cl: atomic mass = 35.45 amu
Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D
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Heeellllpppp ASAP ......
Answer:
I saw B, he vented SUS
Explanation:
Iodoethane Is the answer.
Mg(s) + Ni2+(ag) -> Mg2+ (aq) + Ni(s) What is the total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag)? * 10 ( 1.0 mol ,20 mol ,3.0 mol, 4.0 mol
The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.
How to find the number of moles?This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).
In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).
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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.
What is the number of the electrons gained?We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.
In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.
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Sodium sulfate forms several hydrates. A sample of one of these hydrates is heated until all the water is removed. What is the formula of the original hydrate if it loses 43% of its mass when heated?
Answer:
Na₂SO₄•(H₂O)₆.
Explanation:
The mass that is lost when the sample is heated is water.
Let's assume we have 100 g of the hydrate:
43 grams would be water (H₂O), while the rest (100-43=57) would be sodium sulfate anhydrous (Na₂SO₄).
We convert both those masses to moles, using their respective molar masses:
H₂O ⇒ 43 g ÷ 18 g/mol = 2.39 molNa₂SO₄ ⇒ 57 g ÷ 142.04 g/mol = 0.40 molWe can write those results as (Na₂SO₄)₀.₄₀•(H₂O)₂.₃₉. Now we just need to multiply those numbers so that they become integers.
If we multiply both coefficients by 5 we're left with (Na₂SO₄)₂•(H₂O)₁₂.
Simplify and thus the final answer is Na₂SO₄•(H₂O)₆.
In the reaction below what is the molar enthalpy if 1.73 mol A reacts with unlimited B and releases 4567 kJ of heat.
2 A+ 3 B - 2C
The standard enthalpy change for the reaction 2A+B⇌2C+2D is 664 kJ/mol and The heat that is absorbed when 3.70 mol of A reacts is 2456.8 J
The heat changes that take place as reactants combine to generate a product are measured by the enthalpy of a reaction.
The following formula can be used to determine the enthalpy change of a reaction:
Hess's law states that
Enthalpy of reaction = product's enthalpy - the reactant's enthalpy.
Considering the given reaction: 2A + B ⇌ 2C + 2D
Enthalpy of reaction = product's enthalpy - the reactant's enthalpy.
Enthalpy of reaction (ΔH°f) = (2 C + 2 D) - (2 * A + B)
Enthalpy of reaction (ΔH°f) = {[2(223) + 2(-523)] - [2(-245) + 2(-387)]}
Enthalpy of reaction (ΔH°f) = 664 kJ/mol
ΔH = q ÷ n
ΔH = molar enthalpy (heat) of solution
q = amount of energy (heat) released or absorbed
n = moles of solute
so. q = ΔH xn
q = ΔH xn
q = 664 kJ/mol x 3.70 mol
Q= 2456.8 J
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