dicotyledonous plants
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The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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Answer:

An acid is any hydrogen-containing substance that is capable of donating a proton (hydrogen ion) to another substance. A base is a molecule or ion able to accept a hydrogen ion from an acid.

Answer:

1.Sour in taste

2. Tum blue litmus into red

3. Acids change methyl orange to red

4.Phenolphthalein remains colourless

5. Acids do not give soapy touch

6. Give hydrogen ions in solution

Bitter in taste

The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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Answer:

pH = 1.05

Explanation:

A solution of sulfuric acid, H₂SO₄, dissociates in water as follows:

H₂SO₄ → 2H⁺ + SO₄²⁻

That means per mole of H₂SO₄ you will have 2 moles of H⁺

pH = -log [H⁺]

As [H₂SO₄] = 0.045M and [H⁺] = 2×[H₂SO₄]

[H⁺] = 0.090M

pH = -log [0.090M]

The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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Answer:

owa owa

Explanation:

owa owa owa owa owa ow

Answer:

Any molecule which has a hydrogen atom attached directly to an oxygen or a nitrogen is capable of hydrogen bonding. Hydrogen bonds also occur when hydrogen is bonded to fluorine, but the HF group does not appear in other molecules.

So, the HF no. c) is a right answer.

Answer:

A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.

Explanation:

Brainlist

The volume of glucose C6H12O6 that has a billion molecules \(1.00*10^{9}\) carbon atoms is 0.299 g, rounded to 3 significant digits.

Glucose (C6H12O6) has a molar mass of 180.156 g/mol

To calculate the mass of glucose containing a billion carbon atoms, we need to convert the number of carbon atoms to moles.

\(1.00*10^{9} carbon atoms = \frac{(1.00*10^{9})}{(6.022*10^{23}) }moles= 1.66*10^{-15} moles\)

Now, we need to multiply the number of moles of glucose by the molar mass of glucose to get the mass of glucose containing a billion carbon atoms.

Mass of glucose

\(= (1.66*10^{-15} moles) * (180.156 g/mol)\\= 0.299 g\)

Therefore, the mass of glucose C6H12O6 that contains a billion \(1.00*10^{9}\) carbon atoms is 0.299 g, rounded to 3 significant digits.

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The mass of the oxygen used during the reaction is 8.16 g

The chemical element with the atomic number 8 and symbol O is called oxygen. It belongs to the periodic table's chalcogen group, is a very reactive nonmetal, and an oxidizing agent that easily produces oxides with most elements as well as other compounds.

The reaction is as follows ,

4Fe + 3 ⇒ 2

The molar ratio of the reaction  

= 4:3

The four moles of  Fe react with 3 moles of oxygen molecule to produced Iron Oxide .

The mole of iron = mass ÷ molar mass

= 19.43 g ÷ 55.845 g/mole

= 0.34 mole

If four moles of  Fe react with 3 moles of oxygen molecule to produced  Iron Oxide .

The number of moles of oxygen

= 3 moles × 0.34 mole ÷ 4 moles

= 0.22 mole

The mass

= 0.22 × 32

= 8.16 g

Thus, The mass of the oxygen used during the reaction is 8.16 g

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Answer:

Theoretical Yield of SF₆ = 2.01 moles

Explanation: If you understand and can apply the methodology below, you will find it applies to ALL chemical reaction stoichiometry problems based on the balanced standard equation; i.e., balanced to smallest whole number coefficients.

Solution 1:

Rule => Convert given mass values to moles, solve problem using coefficient ratios. Finish by converting moles to the objective dimensions.

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

= 425g/256g/mol.      = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

Determining Limiting Reactant => Divide moles each reactant by their respective coefficient; the smaller value will always be the limiting reactant.

S₈ = 1.66/1 = 1.66

F₂ = 6.03/24 = 0.25 => F₂ is the limiting reactant

Determining Theoretical Yield:

Note: When working problem do not use the division ratio results for determining limiting reactant. Use the moles F₂ calculated from 229 grams F₂ => 6.03 moles F₂. The division procedure to define the smaller value and limiting reactant is just a quick way to find which reactant controls the extent of reaction.  

Given      S₈            +          24F₂            =>    8SF₆

             425g                    229g                      ?

   = 425g/256g/mol. = 226g/38g/mol.

= 1.66 moles S₈          = 6.03 moles F₂ <= Limiting Reactant

Max #moles SF₆ produced from 6.03 moles F₂ and an excess S₈

Since coefficient values represent moles, the reaction ratio for the above reaction is 24 moles F₂ to 8 moles SF₆. Such implies that the moles of SF₆ (theoretical) calculated from 6.03 moles of F₂ must be a number less than the 6.03 moles F₂ given. This can be calculated by using a ratio of equation coefficients between 24F₂ and 8SF₆  to make the outcome smaller than 6.03. That is,

moles SF₆ = 8/24 x 6.03 moles = 2.01 moles SF₆ (=> theoretical yield)  

S₈ + 24F₂ => 8SF₆

moles SF₆ = 8/24(6.03) moles = 2.01 moles

You would NOT want to use 24/8(6.03) = 18.1 moles which is a value >> 6.03.        

This analysis works for all reaction stoichiometry problems.

Convert to moles => divide by coefficients for LR => solve by mole mole ratios from balanced reaction and moles of given.    

____________________

Here's another example just for grins ...

             C₂H₆O   +   3O₂     =>     2CO₂    + 3H₂O

Given:    253g          307g               ?               ?

a. Determine Limiting Reactant

b. Determine mass in grams of CO₂ & H₂O produced        

Limiting Reactant

moles  C₂H₆O = 253g/46g/mol = 5.5 moles  => 5.5/1 = 5.5

moles  O₂ = 307g/32g/mol = 9.6 moles         =>  9.6/24 = 0.4 ∴ O₂ is L.R.

But the problem is worked using the mole values; NOT the number results used to ID the limiting reactant.  

 C₂H₆O   +       3O₂          =>     2CO₂    + 3H₂O

------------ 9.6 mole (L.R.)              ?               ?

mole yield CO₂ = 2/3(9.6)mole = 6.4 mole  (CO₂ coefficient < O₂ coefficient)

mole yield H₂O = 9.6mole  = 9.6mole (coefficients O₂ & CO₂ are same.)

mole used C₂H₆O = 1/3(9.6)mole = 3.2 mole (coefficient  C₂H₆O < coefficient O₂)

For grams => moles x formula weight (g/mole)

The chemical formula for the molecule you provided is C2H5Cl.

In the molecule, the central atom is carbon (C), which is bonded to two hydrogen atoms (H) and one chlorine atom (Cl). The carbon atom forms single bonds with each of the hydrogen and chlorine atoms, resulting in a linear structure.

To write the chemical formula, we start by indicating the number of atoms of each element present in the molecule. In this case, there are two carbon atoms (C2), five hydrogen atoms (H5), and one chlorine atom (Cl1).

Next, we write the symbols for the elements in the order of their appearance. The formula is typically written with the carbon atom first, followed by hydrogen, and then any other elements in alphabetical order. Therefore, the chemical formula for the molecule is C2H5Cl.

The subscripts in the formula indicate the number of atoms of each element in the molecule. In this case, there are two carbon atoms, five hydrogen atoms, and one chlorine atom.

It's important to note that the formula represents the simplest ratio of atoms in the molecule. It does not provide information about the spatial arrangement or bonding pattern of the atoms. Additional structural information, such as the arrangement of atoms in space, would require a more detailed representation, such as a Lewis structure or a three-dimensional model.

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Answer:

B. a covalent bond.

150 grams of NaOH is approximately equal to 2.256 x 10^24 particles of NaOH.

To convert grams of NaOH to particles of NaOH, we need to use the concept of molar mass and Avogadro's number. The molar mass of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) together. It can be determined as follows:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can use the molar mass to convert grams of NaOH to moles. Since 1 mole contains Avogadro's number (approximately 6.022 x 10^23) particles, we can determine the number of particles as follows:

150 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (6.022 x 10^23 particles / 1 mol NaOH) ≈ 2.256 x 10^24 particles

It's important to note that this calculation assumes the substance is pure NaOH and that the molar mass and Avogadro's number are accurate.

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strontium sulfate (s) + lithium iodide (aq)  →  strontium iodide (aq) and lithium sulfate (aq).

The reaction between strontium sulfate (SrSO4) and lithium iodide (LiI) can be represented by the following balanced chemical equation:

SrSO4 (s) + 2 LiI (aq) → SrI2 (aq) + Li2SO4 (aq)

In this reaction, strontium sulfate (SrSO4) in its solid state reacts with lithium iodide (LiI) in its aqueous state to produce strontium iodide (SrI2) and lithium sulfate (Li2SO4), both in their aqueous forms. The reaction can be understood by examining the ionic compounds involved. Strontium sulfate dissociates into strontium ions (Sr2+) and sulfate ions (SO4^2-), while lithium iodide dissociates into lithium ions (Li+) and iodide ions (I^-). The ions then rearrange to form the products, with strontium combining with iodide to form strontium iodide, and lithium combining with sulfate to form lithium sulfate. It's important to note that this reaction occurs in an aqueous solution, indicating that lithium iodide is dissolved in water. The solid strontium sulfate reacts with the aqueous lithium iodide to produce the aqueous products. This reaction demonstrates the chemical combination of the ions present in strontium sulfate and lithium iodide to form different ionic compounds.

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The volume of the base NaOH in the reaction is determined as 28.5 mL.

The balanced equation for the reaction between NaOH and H₂SO₄ is given as;

2NaOH + H₂SO₄ ----> Na₂SO₄ + 2H₂O

From the balanced chemical equation, the number of moles of acid in the reaction is calculated as follows;

n = 0.012 L x 0.132

n = 0.00158

The equivalent number of moles of the base is calculated as follows;

n_b = 2 x 0.00158

n_b = 0.00316

The volume of the base in the reaction is calculated as follows;

V_b = 0.00316 moles / 0.111 M

V_b = 28.5 mL.

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Answer: 55.5 oC is 0.014 atm (3rd decimal point)

Explanation:

The Clausius-Clapeyron equation is given as:

ln(P2/P1) = -(ΔH_vap/R) * (1/T2 - 1/T1)

where:

P1 = vapor pressure at temperature T1

P2 = vapor pressure at temperature T2

ΔH_vap = enthalpy of vaporization

R = gas constant = 8.314 J/(mol*K)

Converting the enthalpy of vaporization to J/mol:

ΔH_vap = 35.2 kJ/mol = 35,200 J/mol

Converting temperatures to Kelvin:

T1 = 64.7 + 273.15 = 337.85 K

T2 = 55.5 + 273.15 = 328.65 K

Substituting the values into the equation and solving for P2:

ln(P2/1 atm) = -(35,200 J/mol / 8.314 J/(mol*K)) * (1/328.65 K - 1/337.85 K)

ln(P2/1 atm) = -4.231

P2/1 atm = e^(-4.231)

P2 = 0.014 atm

Therefore, the vapor pressure for methanol at 55.5 oC is 0.014 atm, to the third decimal point.

The exit gas stream has an average molecular weight of 29.0 g/mol and the amount of leftover Phenanthrene in the reactor is 5377 g.

Start by calculating the stoichiometric amount of air required to burn 10 kg of Phenanthrene. The balanced chemical equation for the combustion of Phenanthrene is:

C₁₄H₁₀ + 19O₂ → 14CO2 + 5H₂O

Therefore, to burn 10 kg (10000 g) of Phenanthrene:

nO₂ = 19 x (10000 g / 178.24 g/mol) = 1065.5 mol

So the actual amount of oxygen supplied will be:

nO₂, supplied = 0.7 x nO₂ = 745.9 mol

The amount of air required to supply this much oxygen can be calculated using the ideal gas law:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Assuming standard temperature and pressure (STP):

P = 1 atm = 101.3 kPa

T = 273 K

R = 8.314 J/mol.K

The volume of air required is then:

Vair = nair × RT/P = (nO₂,supplied + nN₂,supplied) × RT/P

where nN₂,supplied = number of moles of nitrogen in the supplied air.

Since air is about 79% nitrogen by volume, assume that the number of moles of nitrogen is proportional to the number of moles of oxygen:

nN₂,supplied = (0.79/0.21) x nO₂,supplied = 2807.2 mol

Therefore,

Vair = (nO₂,supplied + nN₂,supplied) × RT/P

= (745.9 + 2807.2) × 8.314 × 273 / 101.3

= 63106 L

Calculate the average molecular weight of the exit gas stream using the ideal gas law again:

n = PV/RT

where n = number of moles of gas, P = pressure, V = volume, R = gas constant, and T = temperature.

Assuming that the combustion products are at the same temperature and pressure as the supplied air (STP):

nCO₂ = nH₂O = nO₂,supplied = 745.9 mol

nN₂ = nN₂,supplied = 2807.2 mol

The total number of moles of gas in the exit stream is then:

ntotal = nCO₂ + nH₂O + nN₂ = 745.9 + 745.9 + 2807.2 = 4298.0 mol

The volume of the exit stream can be calculated using the ideal gas law:

Vexit = ntotal × RT/P = 4298.0 × 8.314 × 273 / 101.3 = 36534 L

The average molecular weight of the exit gas stream is then:

M = mtotal/ntotal

where mtotal = total mass of gas in the exit stream.

Calculate mtotal by adding up the mass of each component in the exit stream:

mtotal = mCO₂ + mH₂O + mN₂

where mCO₂, mH₂O, and mN₂ = masses of carbon dioxide, water vapor, and nitrogen, respectively.

Calculate these masses using the molecular weights of the compounds and the number of moles:

mCO₂ = nCO₂ × MCO₂ = 745.9 × 44.01 g/mol = 32804 g

mH₂O = nH₂O × MH₂O = 745.9 × 18.02 g/mol = 13419 g

mN₂ = nN₂ × MN₂ = 2807.2 × 28.01 g/mol = 78617 g

Therefore,

mtotal = mCO₂ + mH₂O + mN₂ = 32804 + 13419 + 78617 = 124840 g

Substituting into the equation:

M = mtotal/ntotal = 124840 g/4298.0 mol = 29.0 g/mol

So the exit gas stream has an average molecular weight of 29.0 g/mol.

The leftover Phenanthrene amount can be calculated as follows:

mPhenanthrene,leftover = mPhenanthrene,initial - mCO₂ - mH₂O

where mPhenanthrene,initial = initial mass of Phenanthrene, which is 10 kg (10000 g).

Substitute these values into the equation:

mPhenanthrene,leftover = 10000 - 32804 - 13419 = 5377 g

Therefore, the amount of leftover Phenanthrene in the reactor is 5377 g.

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Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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The mass percent of iron in the mixture is 29.43%.

What is mass percent?

Mass percent, also known as percent by mass, is a way of expressing the concentration of a solute in a solution, or the composition of a mixture, in terms of the mass of the solute or component relative to the total mass of the solution or mixture, multiplied by 100%.

To determine the mass percent of iron in the mixture, we need to use the formula:

mass percent = (mass of iron / total mass of mixture) x 100%

We are given that the mass of the iron is 1.213 g, and the total mass of the mixture is 4.123 g.

So, substituting these values into the formula:

mass percent = (1.213 g / 4.123 g) x 100%

mass percent = 29.43%

Therefore, the mass percent of iron in the mixture is 29.43%.

What is concentration of solution?

Concentration of a solution is the amount of solute dissolved in a given amount of solvent, and is usually expressed as a unit of measure per volume or mass of the solution. The most commonly used units of concentration include molarity, molality, mass percent, volume percent, and parts per million.

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Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

We can see here that the best fuel is the one that produces the most heat per unit mass. In this case, the fuel that produces the most heat per unit mass is methanol.

Fuel is a substance that is used to produce energy through combustion or other chemical reactions. It is commonly utilized to power various forms of transportation, generate heat or electricity, and operate machinery and appliances.

The results of the experiment are shown below:

Fuel            Mass (g)      Heat produced (J)       Heat per gram (J/g)

Methanol 1.0                          350                   350

Ethanol         1.0                          250                   250

Propane         1.0                          200                   200

Butane         1.0                          150                            150

Pentane         1.0                          100                            100

It is important to note that the results of this experiment are only a measure of the heat produced by the fuels.

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The partial pressure of the Helium gas is  0.9 atm.

The pressure that a gas exerts on its own when it is collected over water, independent of the pressure that the water vapor in the collecting vessel also produces, is known as its partial pressure.

When gas is collected over water, some of the water vapor will dissolve in it and change the overall pressure in the collecting vessel. Water vapor has its own partial pressure, which is affected by the relative humidity and temperature of the air around it. This is why it behaves in this way.

We have that;

Vapor pressure of the gas = 19.8 mmHg or 0.026 atm

Partial pressure of the Helium gas = 0.926 atm - 0.026 atm

= 0.9 atm

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Answer:

A. 9.83g

B. 13.06

Explanation:

A) To calculate the mass of BaSO4 formed, you need to first write the balanced equation for the reaction:

Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O

Then, you need to find the limiting reactant, which is the one that runs out first and determines how much product is formed. You can do this by converting the volumes and concentrations of the solutions to moles and comparing them with the stoichiometric coefficients.

50 mL of 1.00 M Ba(OH)2 = 0.050 L x 1.00 mol/L = 0.050 mol Ba(OH)2 88.7 mL of 0.475 M H2SO4 = 0.0887 L x 0.475 mol/L = 0.0421 mol H2SO4

According to the equation, 1 mol of Ba(OH)2 reacts with 1 mol of H2SO4, so Ba(OH)2 is in excess and H2SO4 is the limiting reactant.

Next, you need to use the mole ratio between the limiting reactant and the product to find how many moles of BaSO4 are formed:

0.0421 mol H2SO4 x (1 mol BaSO4 / 1 mol H2SO4) = 0.0421 mol BaSO4

Finally, you need to multiply the moles of BaSO4 by its molar mass to get its mass:

0.0421 mol BaSO4 x 233.39 g/mol = 9.83 g BaSO4

So, the mass of BaSO4 formed is 9.83 g.

B) To calculate the pH of the mixed solution, you need to first find the concentration of OH- ions that remain after the reaction. You can do this by subtracting the moles of OH- that reacted with H+ from the initial moles of OH- and dividing by the total volume of the solution.

The initial moles of OH- are equal to the moles of Ba(OH)2:

0.050 mol Ba(OH)2 x (2 mol OH- / 1 mol Ba(OH)2) = 0.100 mol OH-

The moles of OH- that reacted with H+ are equal to the moles of H2SO4:

0.0421 mol H2SO4 x (2 mol H+ / 1 mol H2SO4) = 0.0842 mol H+

The remaining moles of OH- are:

0.100 mol OH- - 0.0842 mol H+ = 0.0158 mol OH-

The total volume of the solution is:

50 mL + 88.7 mL = 138.7 mL = 0.1387 L

The concentration of OH- is:

0.0158 mol OH- / 0.1387 L = 0.114 M

Next, you need to use the relationship between pH and pOH to find the pH:

pOH = -log[OH-] = -log(0.114) = 0.94 pH + pOH = 14 pH = 14 - pOH = 14 - 0.94 = 13.06

So, the pH of the mixed solution is 13.06.

The name given to the group delimited in the image is ethyl.

It is a hydrocarbon from the alkyl functional group.

Ethyl is a substituent derived from ethane. The formula for ethane is \(C_2H_6\), whereas, ethyl has one H less than ethane.

Thus, the formula for ethyl  is \(C_2H_5\).

Looking at the delimited portion of the image, 2 C atoms in C-C bond are bonded by 5 H atoms.

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An insulated container is used to hold 44.1 g of water at 23.9 °C. A sample of copper weighing 10.1 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.0°C.  25 °C is the maximum temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales.

Which historically defined distinct reference points or thermometric substances. The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C.

Q꜀ = Qᵥᵥ

M꜀C꜀(M꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ– Mᵥᵥ)

10.1 × 0.385 (100 – Tₑ) =44.1 × 4.184 (Tₑ – 23.9)

396.55 + 4621.228 = 196.648Tₑ + 3.9655Tₑ

Tₑ = 5017.778 / 200.613

Tₑ = 25 °C

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The complete rate law should be like: Rate = k[NO][H2]^2

Rate = k[NO]^x[H2]^y, where x and y are the exponents for the concentration of nitric oxide (NO) and hydrogen (H2) respectively.

The rate law can be determined by performing experiments with different initial concentrations of NO and H2 and observing how the initial rate changes.

From the data provided,

It can be seen that increasing the concentration of NO by a factor of 2 results in an increase in the initial rate by a factor of 2^(x).

Similarly, increasing the concentration of H2 by a factor of 2 results in an increase in the initial rate by a factor of 2^(y).

Based on this information, x = 1 and y = 2 can be determined, giving us the rate law:

Rate = k[NO][H2]^2

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