determine the value of the resultant and its location from O.
see attach image.​

Determine The Value Of The Resultant And Its Location From O.see Attach Image.

Answers

Answer 1

Answer:

Explanation:

In the x direction the force will be

½(-w₀)L/2 = -¼w₀L  

acting ⅔(L/2) = L/3 below the x axis.

In the y direction the force will be

½(-w₀)L + ½w₀L/2 = -¼w₀L  

the magnitude of the resultant will be

F = w₀L  √((-¼)² + (-¼)²) = w₀L√⅛

in the direction

θ = arctan(-¼w₀L / -¼w₀L) = 225°

to find the distance, we balance moments

(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]

     (√⅛)[d] = ½         [⅔L] + ¼      [⅔L/2] - ¼      [L - ⅓L/2]

     (√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]

     (√⅛)[d] =      ⅓L  +    ⅟₁₂L     -  ¼L + ⅟₂₄L  

     (√⅛)[d] = 5L/24

               d = 5L/24 / (√⅛)

               d = 5√⅛L/3

Determine The Value Of The Resultant And Its Location From O.see Attach Image.

Related Questions

two 200 pound lead balls are separated by a distance 1m. both balls have the same positive charge q. what charge will produce an electrostatic force.between the balls that is of the same order of magnitude as the weight of one ball?

Answers

Answer:

The  charge is  \(q = 3.14 *10^{-4} \ C\)

Explanation:

From the question we are told that

     The mass of each ball is  \(m = 200 \ lb = \frac{200}{2.205} = 90.70 \ kg\)

       The distance of separation is  \(d = 1 \ m\)

Generally the weight of the each ball is mathematically represented as  

      \(W = m * g\)

where g is the acceleration due to gravity with a value \(g = 9.8 m/s^2\)

substituting values

      \(W = 90.70 * 9.8\)

      \(W = 889 \ N\)

Generally  the electrostatic force between this balls is mathematically represented as

         \(F_e = \frac{k * q_1* q_2 }{d^2}\)

given that the the charges are equal we have

    \(q_1= q_2 = q\)

So

         \(F_e = \frac{k * q^2 }{d^2}\)

Now from the question we are told to find the charge when the weight of one  ball is equal to the electrostatic force

So  we have

       \(889 = \frac{9*10^9 * q^2}{1^2}\)

   =>   \(q = 3.14 *10^{-4} \ C\)

       

The magnitude of charge on the balls is \(3.14 \times 10^{-4} \;\rm C\).

Given data:

The masses of two lead balls are, m = 200 lb = 200/2.205 = 90.70 kg.

The distance of separation of two balls is, d = 1 m.

First of all we need to obtain the weight of ball. The weight of the ball is expressed as,

W = mg

Here,

g is the gravitational acceleration.

Solving as,

W = 90.70 × 9.8

W = 888.86 N

The expression for the electrostatic force between this balls is mathematically represented as,

\(F = \dfrac{k \times q_{1} \times q_{2}}{d^{2}}\)

Since, the charges are equal then,

\(q_{1} =q_{2}=q\)

Also, the magnitude of force between the balls is same as the weight of one ball. Then,

F = W

Solving as,

\(F =W= \dfrac{(9 \times 10^{9}) \times q^{2}}{1^{2}}\\\\889= \dfrac{(9 \times 10^{9}) \times q^{2}}{1^{2}}\\\\q = 3.14 \times 10^{-4} \;\rm C\)

Thus, we can conclude that the magnitude of charge on the balls is \(3.14 \times 10^{-4} \;\rm C\).

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Does heat and temperature depend on the other or are they totally separate ideas? Explain.

Answers

Answer:

What heat means in thermodynamics, and how we can calculate heat using the heat ... Scientists define heat as thermal energy transferred between two systems

Explanation:

thermal energy

Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?

Answers

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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If a force is applied, but the object does
not move, what can we say about the
amount of work that is done?
A. Some work is done.
B. No work is done.
C. The work equals the force.
D. A large amount of work is done.

Answers

Answer:

doesn't move, no work is done; if a force is applied and the object moves a distance d in a direction other than the direction of the force, less work is done than if the object moves a distance d in the direction of the applied.

Answer:

B. No work is done.

Explanation:

Work is only done when the object moves in the direction of the force.

A soldier is tasked with measuring the muzzle velocity of a new rifle. Knowing the principles of
projectile motion, he decides to perform a simple experiment at the indoor firing range. The soldier
hangs a target a distance of d = 109 m from the end of the barrel. The rifle is mounted so that the bullet?
exits moving horizontally at the same height as the bullseye. After six trials, the soldier tabulates the
values he measured for the vertical distance h from the bullseye to the bullet strike.
d
h
What is the most accurate muzzle velocity that the soldier can report to his sergeant?

Answers

Answer:

it could be that there is a big percentage

Explanation:

What is the acceleration of a 50 kg object pushed with a force of 325 newtons?​

Answers

Answer:

Acceleration(a) = 6.5m/s²

Explanation:

The formula for Force is

Force(F)= Mass of an object(m) × Acceleration (a)

F=325

m=50kg

a=?

insert figures into the formula (F=m×a)

325=50×a

use change of subject by dividing both sides of the equation by 50

(325/50)=50a/50

a = 325/50

therefore a= 6.5m/s², where a is Acceleration.


Please help this question

Please help this question

Answers

Answer:

Kantians would say that Sharkeisha acted immorally since she increased overall pain.

The answer would be d.

The moon has a mass of 7.35 E 22 kg and is located 3.84 E 8 meters from Earth. If a car on Earth has a mass of 3,450 kg, what is the gravitational force between this car and the moon?

Answers

F = 0.00156 N

Explanation:
F=G•m1•m2
_____
r2

Bailey wants to find out which frozen solid melts the fastest: soda, ice, or orange juice. She pours each of the three liquids into the empty cubes of an ice tray, and then places the ice tray in the freezer overnight. The next day, she pulls the ice tray out and sets each cube on its own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

Answers

Answer:

its 45 over 6

Explanation:the answer is in  the question

Answer: Only the melted cube's shape changed.

Explanation:

Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced human society as a whole.

Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced

Answers

Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.

Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.

Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.

Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.

Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.

Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.

Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.

Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.

Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.

Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.

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Ela A ball of mass 100gm is suspended by a string 40cm long. Keeping the string always taut, the ball describes a horizontal circle of radius 10cm. Find i. the angle made by the string with the vertical ii. the angular speed of the ball. [2+3] h If the hall in above problem was rotated in a vertical circle what would be​

Answers

Hi there! :)

In this situation, the tension in the string is responsible for two things:

- Its vertical component balances the weight of the ball

- Its horizontal component results in a centripetal force

Using the angle from the vertical, the tension's COSINE component would be its vertical component and its SINE component the horizontal component.

i.

We can use right-triangle trigonometry to solve.

We know that the string itself is 40 cm long, and the horizontal leg of the string (opposite side from the vertical angle) is 10 cm.

We can use sine to solve.

Recall:
\(sin\phi = \frac{O}{H}\)

Plug in the values and solve for the angle made by the string and the vertical.

\(sin\phi = \frac{10}{40} \\\\sin^{-1}(\frac{1}{4}) = \phi\\\\\phi = \boxed{14.478^o}\)

ii.

Begin by summing forces in the vertical direction to solve for tension.

\(\Sigma F = T_y - F_g\)

Since the forces are balanced (there no acceleration in the vertical direction), ∑F = 0.

\(0 = T_y - F_g\\\\T_y = F_g\)

The force of gravity (Fg) is equivalent to:
\(T_y = F_g = mg\)

Ty is the cosine component. We can now solve for the tension.

(Using g≈ 9.8 m/s²)

\(Tcos(14.478) = mg \\\\Tcos(14.478)= (0.1)(9.8) \\\\T = \frac{(0.1)(9.8)}{cos(14.478)} = 1.012 N\)
We can use this value of 'T' to solve for the net force in the horizontal direction, and subsequently, the ball's angular speed.

Let 'Tx' represent the horizontal component of tension (sine).

In the horizontal direction, we only have the force of tension acting on the ball that results in a net centripetal force.

\(F_{xnet} = T_x = m\omega^2 r\)

\(Tsin\phi = m\omega^2 r\)

Rearrange the equation to solve for ω.

\(\omega^2 = \frac{Tsin\phi}{mr}\\\\\omega = \sqrt{\frac{Tsin\phi}{mr}} = \sqrt{\frac{1.012sin(14.478)}{(0.1)(0.1)} }= \boxed{5.03 \frac{rad}{s}}\)

**The last question is unfinished, so I am unable to answer it at this time.

Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.

Answers

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

How do we explain?

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and

An acetate rods rubs against a cloth. What type of charge will the rod end up with?
A. Positive
B. Negative
C. Not enough info
D. Neutral

Answers

Answer:

I believe it's A

Explanation:

........

two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object

Answers

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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A 74.1 kg high jumper leaves the ground with
a vertical velocity of 9.7 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m

Answers

Answer:

4.80 m

Explanation:

We are given the mass of the high jumper, its initial velocity, and the acceleration of gravity. We are trying to find the vertical displacement of the high jumper.

Let's set the upwards direction to be positive and the downwards direction to be negative.

List out the relevant known variables.

v₀ = 9.7 m/s a = -9.8 m/s² Δx = ?

We still need one more variable in order to use the constant acceleration equations. Since we are trying to find the max height of the jumper, we can use the fact that at the top of its trajectory, its final velocity will be 0 m/s.

    4. v = 0 m/s

Using these four variables, let's find the constant acceleration equation that contains these variables:

v² = v₀² + 2aΔx

Substitute the known values into the equation and solve for Δx.

(0)² = (9.7)² + 2(-9.8)Δx 0 = 94.09 + (-19.6)Δx -94.09 = -19.6Δx Δx = 4.80

The high jumper can jump to a max height of 4.80 m.

Just look at the picture and sort

Just look at the picture and sort

Answers

Each example can be classified as absolute dating or relative dating as follows:

A geologist puts a series of events in chronological order after studying a sequence of rock layers. (Relative Dating)A geologists inferes that a volcano erupted after sedments were deposited. (Relative Dating)A geologists determines the geological period that a dinosaur lived in based on the llayer of sediment it was found in. (Relative Dating)A geologist measures the ratio of isotopus in a sample to calculate how many half-lives have passed since the sample formed (Absolute Dating)A geologists determine how many years ago a event ocurred.  (Absolute Dating)A geologists calculates that a volcano erupted 52 million years after some sedments were deposited. (Absolute Dating)What is Absolute Dating and Relative Dating?

Absolute dating and relative dating are two methods used by geologists and archaeologists to determine the age of rocks, fossils, and other geological and archaeological materials.

Therefore, Relative dating involves determining the order of past events without determining their specific age. This is done by studying the sequence of rock layers and the fossils they contain. Absolute dating corresponds to determining the specific age of an object or event using methods such as radiometric dating or dendrochronology.

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In which direction does the magnetic field in the center of the coil point?

In which direction does the magnetic field in the center of the coil point?

Answers

Each segment of circular loop carrying current produces magnetic field lines in the same direction with in the loop. The direction of magnetic field at the centre of circular coil is perpendicular to the place of the coil. i.e. along the axis of the coil. Please mark brainiest!!!

Answer:

Right

Explanation:

Coil move right yes

Why do people do drugs?

Answers

People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”

List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.

Answers

Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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Which standing wave has exactly three antinodes?
A.
B.
C.
D.

Which standing wave has exactly three antinodes?A.B.C.D.

Answers

Answer:

Explanation:

C looks good,  b/c antinodes are where the waves is at a max displament.

The wave has exactly three antinodes is option C.

What number of antinodes are in 3 status waves?

As in all status wave styles, each node is separated through an antinode. This sample with 3 nodes and two antinodes is known as the second one harmonic and is depicted within the animation.

Where are the antinodes?

The other of a node is an anti-node, a factor where the amplitude of the status wave is at most. those occur midway among the nodes. In a full wavelength of a status wave, there are two loops. So, there should be  nodes midway of every of the two loops.

What's a wave in technology?

Wave, propagation of disturbances from location to vicinity in a ordinary and prepared manner. maximum acquainted are floor waves that journey on water, however sound, mild, and the movement of subatomic particles all exhibit wavelike residences.

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Write the laws of refraction.(It should be Snell's law)​

Answers

Explanation:

Snell's Law of refraction:

Refraction of light obeys the following its two laws which's snell's law.

The incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane. For a given pair of media and given colour of light, the ratio of the sine of angle of incidence i to the sine of angle of refraction r is a constant i.e.

\( \rm \cfrac{sin \: i}{sin \: r } = \mu\)

This is known as the refractive index of the second medium with respect to the first medium. Mu is given as:

\( \rm\mu = \cfrac{Speed \; of \; light \; in\; the\; first \; medium}{Speed \; of \; light \; in\; the\; second \; medium}\)

Let's take an example.

If a ray light travels from air to water,then mu = sin i/sin r is the refractive index of water with air.

\(\rm \cfrac{sin \: i}{sin \: r } = \mu\)

Ex.1:Ray light from air to water

sin i = 3*10^6 m/s^1sin r = 2.25*10^8 m s^-1

\( \rm \mu \: = \cfrac{3 \times {10}^{8} \: m \: s {}^{1} }{2.25 \times 10 {}^{8} \: m \: s {}^{ - 1} } = \cfrac{4}{3} = \boxed{ 1.33}\)

Ex.2: Ray light from Air to glass:

sin i = 3*10^8 m s ^-1sin r = 2*10^8 m s^-1

\( \rm \mu \: = \cfrac{3 \times {10}^{8} m \: s {}^{ - 1} }{2 \times {10}^{8 \: } m \: s {}^{ - 1} } = \cfrac{3}{2} = \boxed {1.5}\)

\( \rule{225pt}{2pt}\)

A roller coaster car accelerates uniformly covers a distance of 50 m while increasing its speed
from 5.0 m/s to 25 m/s. How long does it take for this to occur? What is its average velocity over
this distance? (3.3 s. 15 m/s)
Proof please

Answers

Answer:

Explanation:

Given parameters:

Distance covered  = 50m

Initial velocity  = 5m/s

Final velocity  = 25m/s

Unknown:

Time taken to cover the distance  = ?

Average velocity   = ?

Solution:

To solve this problem, we use the expression below:

   x  = \((\frac{v + u}{2}) t\)  

x is the distance

v is the final velocity

u is the initial velocity

t is the time

   50 = \(\frac{5 + 25}{2}\)  x t

   50  = 15 x t

   t  = 3.3s

Average velocity  = \(\frac{v + u}{2}\)   = \(\frac{5+25}{2}\)   = 15m/s

D
5. Mariam driving at a speed of 20.0 m/s applies
brakes close to a signal and travels a distance of
200 m before coming to rest. What was her
acceleration?
A. -0.50 m/s2
B. -0.70 m/s2
C. -1.00 m/s2
D. -2.00 m/s2
6. A trollen at rest is nushed to accelerate at a

Answers

Answer:

maibi.... D

Explanation:

I think is D

Which of these would be a part of a force diagram for this image? Check all that apply.

Answers

The options that would be a part of a force diagram for the attached image are:

A; A dot that represents the box

B; A vector labeled Fg, pointing straight down

E; A vector labeled Fs, pointing parallel to and up the ramp.

What are the qualities of a force diagram?

This is a simple force diagram of an item lying on an inclined plane.

The first step is to draw a dot in the center of the box, as here is where we will draw the other forces operating on the box.

Second, we must recognize the force of gravity (F_g), which is a vertical vector line drawn from that dot and whose perpendicular component assures that the box is pressing against the inclined plane.

Third, we can see that the box is moving down the slope, but it will face some friction in the other direction. As a result, we will draw a vector line parallel to the inclined plane from the dot to the left of the box. Frictional force (F_fs) will be shown by this line.

Fourth, there would be a normal force attempting to counteract the perpendicular component of gravity (F_g). This normal force is perpendicular to the perpendicular component of F_g. This is referred to as F_g•sin. We will draw a vector line perpendicular to the inclined plane starting from the dot to represent this normal force. F_n represents this normal force.

Looking at the possibilities, only Options A, B, and E correlate to the forces stated above.

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Which of these would be a part of a force diagram for this image? Check all that apply.

In a class experiment to determine information about free-fall acceleration, a watermelon and a pumpkin are each set to fall from the back of the stands at your football stadium.

a. If the watermelon and the pumpkin are both dropped at the same time, which one will hit the ground first?

b. If the watermelon is thrown downward with an initial speed of 10 m/s and the pumpkin is dropped, which one will hit the ground first? Show calculation to support your answer.

c. If it takes the watermelon 1 second to reach the ground when it is thrown downward at 10 m/s, how tall are the stands?

d. How long does it take the pumpkin to reach the ground if it is dropped from this height you calculated in part c?

Answers

Answer:

a) They both hit the ground at the same time

b) Watermelon will hit first, since its speed is faster than the pumpkin speed

c) h = 29,6 m

d)t = 3,02 sec

Explanation:

Equations for fall free movement are:

vf = v₀ + g*t       when   v₀ = 0   (dropped case)  vf = g*t

h = v₀*t + 1/2*g*t²

a) For both ( watermelon and pumpkin) the equation of speed is the same:

vf = g*t²    Both will have the same speed second through second

They both hit the ground at the same time

b) Now is watermelon is thrown with v₀ = 10 m/s

Watermelon will hit first since its speed is faster than the pumpkin speed

vf(watermelon) =  10 + g*t

vf₂ (pumpkin)   =  g*t

c) h = v₀*t + (1/2)*g*t²

h = (10)*1 + (1/2)*9,8*1

h = 10 + 19,6

h = 29,6 m

d)  h = g*t

t = 29,6/9,8

t = 3,02 sec

The product of an object's mass and velocity is it's

A) acceleration
B) inertia
C) momentum
D) weight

Answers

Answer:

C) Momentum

Explanation:

Refers to an objects mass in motion.

A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 45000 m/s.
What will be the final speed of an electron released from rest at the negative plate?
Express your answer to two significant figures and include the appropriate units
V=_________

Answers

Answer:

2.1x10^6m/s

Explanation:

One electron has a charge of –1.602e-19 C

mass of electron is 9.1e-31 kg

mass of proton is 1.6726e−27 kg

mass ratio is 1.6726e−27 / 9.1e-31 = 1838

The force is constant, F

distance is constant, d

a = F/m

a increases by a factor 1838, as m decreases by that factor

a = a₀1838

v₀² = 2a₀d

v² = 2a₀d1838

v²/v₀² = 2a₀d1838 / 2a₀d = 1838

v² = 1838v₀² = 1838(45000)²

v = 45000√1838 = 2.1e6 m/s

A high speed rail train is approaching a crossing in South Florida. Because the train is approaching, a Doppler shift will cause

the sound of the train's horn to be louder
the sound of the train's horn to be louder and appear to be at a lower pitch
the sound of the train's horn to appear to be at a lower pitch
the sound of the train's horn to appear to be at a higher pitch

Answers

Answer:

Explanation: The correct answer is: the sound of the train's horn to appear to be at a higher pitch.

As the high speed rail train approaches the crossing, it moves towards the sound waves it creates. This causes the frequency of the sound waves to be compressed, which results in an apparent increase in frequency or pitch of the train's horn. This effect is known as the Doppler shift. Therefore, the sound of the train's horn will appear to be at a higher pitch.

The length of your eye decreases slightly as you age, making the lens a bit closer to the retina. Suppose a man had his vision surgically corrected at age 30. At age 70, once his eyes had decreased slightly in length, what condition would he have?
A. Nearsightedness
B. Farsightedness
C. Neither nearsightedness nor farsightedness

Answers

Answer:

A. Nearsightedness

Explanation:

A nearsightedness is an eye defect that occurs when someone is only able to see close ranged object but not far distance object. According to the question, if the length of my eye decreases slightly as I age, this means there is a possibility that I will find it difficult to view a far distance object as I age.

At 70, once my eyes had decreased slightly in length, this means I will only be able to see close ranged object but not far distant object, showing that I am now suffering from nearsightedness according to its definition above.

How do I find the mass in kg

How do I find the mass in kg

Answers

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.

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